The volumes of N₂ gas and H₂ gas required to form 28.5 grams of N₂H₄ at 30oC and 1.50 atm are 14.3 L and 28.6 L, respectively.
To determine the volumes of N₂ gas and H₂ gas required to form 28.5 grams of N₂H₄ at 30oC and 1.50 atm, we need to use the ideal gas law to calculate the number of moles of each gas needed, and then use the balanced chemical equation to determine the volume of each gas.
Calculate the number of moles of N₂H₄
The molar mass of N₂H₄ is:
Molar mass N₂H₄ = 2 x molar mass N + 4 x molar mass H
Molar mass N₂H₄ = 2 x 14.01 g/mol + 4 x 1.01 g/mol
Molar mass N₂H₄ = 32.05 g/mol
The number of moles of N₂H₄ can be calculated as follows:
n(N₂H₄) = mass / molar mass
n(N₂H₄) = 28.5 g / 32.05 g/mol
n(N₂H₄) = 0.890 mol
Determine the number of moles of N₂ and H₂ required
From the balanced chemical equation, we see that 1 mole of N₂ reacts with 2 moles of H₂ to produce 1 mole of N₂H₄. Therefore, the number of moles of N₂ and H₂ required can be calculated as follows:
n(N₂) = n(N₂H₄) = 0.890 mol
n(H₂) = 2 x n(N₂H₄) = 1.780 mol
Use the ideal gas law to calculate the volumes of N2 and H2
The ideal gas law is given by:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.0821 L atm/mol K), and T is the temperature in Kelvin.
We are given P = 1.50 atm and T = 30oC = 303 K.
For N₂ gas:
n(N₂) = 0.890 mol
R = 0.0821 L atm/mol K
T = 303 K
P = 1.50 atm
Solving for V, we get:
V(N₂) = n(N₂)RT/P
V(N₂) = 0.890 mol x 0.0821 L atm/mol K x 303 K / 1.50 atm
V(N₂) = 14.3 L
For H₂ gas:
n(H₂) = 1.780 mol
R = 0.0821 L atm/mol K
T = 303 K
P = 1.50 atm
Solving for V, we get:
V(H₂) = n(H₂)RT/P
V(H₂) = 1.780 mol x 0.0821 L atm/mol K x 303 K / 1.50 atm
V(H₂) = 28.6 L
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Draw resonance structures to show in which position nitrobenzene will nitrate to form dinitrobenzene
In order to create 2,4-dinitrobenzene and 2,6-dinitrobenzene, respectively, nitrobenzene can be nitrated in either the ortho or para positions.
Draw resonance structures to show in which position nitrobenzene will nitrate to form dinitrobenzeneA nitro group (-NO2) is substituted for a hydrogen atom (-H) on the benzene ring during the nitration process. The nitrobenzene resonance structures demonstrate that the electrons are distributed between the nitro group and the benzene ring. Due to the partial negative charge they have as a result of the nitro group's electron-withdrawing effect, the ortho and para positions are more vulnerable to electrophilic attack as a result of this delocalization.
The following diagram depicts the resonance structures for the ortho and para nitration products:
Ortho nitrification
H H
| |
H---C---NO2 H---C---NO2
| |
H NO2
Para nitration:
H H
| |
H---C---NO2 NO2---C---H
| |
NO2 H
The nitro group is situated on the 2 and 4 positions of the benzene ring in the ortho nitration product, whereas it is situated on the 2 and 6 positions in the para nitration product.
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Calculate the heat change associated
with cooling a 350.0 g aluminum bar
from 70.0/C to 25.0/C. Is the change
endothermic or exothermic? Why? How to change -14,175J to -14.2kj
(-14.2 kJ)
The aluminum bar is cooling through an exothermic process, which means that heat is being released from the bar and being transported to the surroundings. This is indicated by the negative sign of the heat change.
Exothermic or endothermic change?The aluminum bar is cooling through an exothermic process, which means that heat is being released from the bar and being transported to the surroundings. This is indicated by the negative sign of the heat change (-14.2 kJ). This is due to the metal bar losing heat as it cooled down because the ultimate temperature (25.0°C) is lower than the initial temperature (70.0°C).
we can use the formula:
Q = m * c * ΔT
where Q = heat change, m = mass of the aluminum bar, c = specific heat capacity of aluminum, and ΔT = change in temperature.
The specific heat capacity of aluminum is 0.903 J/g·°C.
So, plugging in the values, we get:
Q = (350.0 g) * (0.903 J/g·°C) * (25.0°C - 70.0°C)
Q = -14,175 J
The negative sign indicates that heat is being lost by the aluminum bar,
To convert -14,175 J to kJ, we divide by 1000:
-14,175 J = -14.175 kJ
Rounding to one decimal place, we get:
-14.175 J ≈ -14.2 kJ
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What should an investigator do when they discover a mysterious substance at a crime scene?
OA. Immediately taste it to try to identify it.
О в.
O C.
O D. Smell it to determine whether it is legal or illegal.
Conduct a presumptive drug test immediately.
Put it in a bag and properly label it with the chain of custody information.
Answer:
c) Put it in a bag and properly label it with the chain of custody information.
Step by step explanation:-
Tasting it might kill the investigator.
Drug test would not be appropriate during the crime scene.
Having the knowledge to identify the drug by smelling is quite rare in people.
Universal indicator is added to water and then nitric acid is added to the mixture.Give the colour change when nitric acid is added to the mixture of universal indicator and water.
The colour change when nitric acid is added to the mixture of universal indicator and water can range from yellow/orange to red/dark red.
Universal indicator explained.
When nitric acid is added to a mixture of water and universal indicator, the color change depends on the concentration of the acid.
At low concentrations of nitric acid, the universal indicator will turn yellow or orange, indicating a slightly acidic solution. As the concentration of nitric acid increases, the color will shift towards red, indicating a more acidic solution. At very high concentrations, the solution may turn dark red, indicating a strongly acidic solution.
The reason for this color change is that universal indicator is a pH indicator that contains a mixture of dyes that change color depending on the pH of the solution. Nitric acid is a strong acid that dissociates completely in water, producing H+ ions that lower the pH of the solution. As the pH decreases, the color of the universal indicator changes from green to yellow to orange to red.
Therefore, the color change when nitric acid is added to a mixture of water and universal indicator depends on the concentration of the acid and can range from yellow/orange to red/dark red.
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Remember when you calculated the amount of water from Hurricane Isabel? Using the numbers you calculated, determine the total amount of heat released by the condensing water. You need to know that the energy released in the condensation of 1 kg of water vapor into 1 kg of liquid water is 2,260 kJ.
The energy released when 1 kg of water vapor condenses into 1 kg of liquid water is known as the heat of condensation, and it has a value of 2,260 kJ/kg. This means that for every kilogram of water vapor that condenses, 2,260 kJ of energy is released as heat.
How to calcalculate total amount of heat?
To calculate the total amount of heat released by the condensing water from Hurricane Isabel, we first need to know the total amount of water that was present in the hurricane. Once we have this value, we can multiply it by the heat of condensation (2,260 kJ/kg) to find the total amount of heat released.
For example, if the total amount of water from Hurricane Isabel was 1,000 kg, then the total amount of heat released would be:
Total heat released = 2,260 kJ/kg x 1,000 kg = 2,260,000 kJ
Therefore, the total amount of heat released by the condensing water from Hurricane Isabel depends on the amount of water that was present in the hurricane, and we need this information to make a specific calculation.
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what concentration of iodide is needed for the reaction to change color at 12 minutes? (rate: 0.028 mM/12 min)
According to a first-order rate law with a rate constant of 0.0058 min1, the reaction requires a concentration of iodide of about 4.83 mM before the color changes after 12 minutes.
How does the rate of the reaction change as the concentration of iodide ions rises?The demonstration in the movie shows that larger iodide ion concentrations accelerate the first reaction, hastening the depletion of thiosulfate. Because of this, the reaction's end-signaling color shift happens faster.
rate = k[I-]
[I-] = rate / k
Plugging in the given rate (0.028 mM/12 min), we get:
[I-] = (0.028 mM/12 min) / k
[I-] = (0.028 mM/12 min) / (0.0058 min⁻¹)
[I-] ≈ 4.83 mM
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PLEASE HELPPPP I WILL GIVE BRAINLIST
The possible values of the quantum numbers are:
Orbital shape quantum number l: 0, 1, 2, 3, 4, or 5.
Magnetic quantum number m: -l to +l.
Spin quantum number, s: +1/2 or -1/2.
What are the azimuthal, magnetic, and spin quantum numbers of the valence electrons in an atom with principal quantum number, n = 6?For the principal quantum number n = 6, the possible values of the azimuthal (orbital shape) quantum number l are 0, 1, 2, 3, 4, and 5.
The magnetic quantum number m can have values ranging from -l to +l, inclusive.
The spin quantum number, s can be either +1/2 or -1/2.
So, the valence electrons in an atom with principal quantum number n = 6 can have the following quantum numbers:
Azimuthal quantum number, l can be 0, 1, 2, 3, 4, or 5.
Magnetic quantum number, m can range from -l to +l, inclusive.
Spin quantum number, s can be either +1/2 or -1/2.
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If you had 9. 65 x 1026 atoms of Ag, how many moles would you have?
If you had [tex]9.65 * 10^{26[/tex] atoms of Ag, you would have [tex]1.603 * 10^3[/tex] moles of Ag.
To find the number of moles of Ag atoms you have, you need to use Avogadro's number, which is 6.022 x 10^23. This number represents the number of atoms in one mole of any substance.
To find the number of moles, you need to divide the number of atoms you have by Avogadro's number:
Number of moles = Number of atoms / Avogadro's number
Plug in the given values:
Number of moles = 9.65 x 10^26 atoms / 6.022 x 10^23 atoms/mole
Simplify:
Number of moles = 1.603 x 10^3 moles
So, if you had 9.65 x 10^26 atoms of Ag, you would have 1.603 x 10^3 moles of Ag.
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a 10.0 ml sample of vinegar, which contains acetic acid, is titrated with 0.50 m naoh, and 15.6 ml is required to reach the equivalence point. what is the molarity of the acetic acid?
The molarity of the acetic acid, when it is titrated with 0.50M NaOH, and 15.6 ml of it is required to reach the equivalence point, is 0.78 M.
The molarity of the acetic acid can be calculated using the following formula:
Molarity (M) = (Moles of Acid) / (Volume of Acid)
First, the moles of acetic acid must be determined. To do this, the moles of sodium hydroxide (NaOH) used to titrate the acetic acid must be determined.
Moles of NaOH = (Molarity of NaOH) x (Volume of NaOH)
Moles of NaOH = (0.50 mol/L) x (0.0156 L)
Moles of NaOH = 0.0078 mol
Since one mole of NaOH is needed to neutralize one mole of acetic acid, the moles of acetic acid are equal to the moles of NaOH, or 0.0078 mol.
Next, the volume of the acetic acid must be determined. Since 10.0 mL of vinegar was used, the volume of acetic acid is also 10.0 mL.
Now that the moles of acetic acid and the volume of acetic acid have been determined, the molarity of the acetic acid can be calculated.
Molarity (M) = (Moles of Acid) / (Volume of Acid)
Molarity (M) = (0.0078 mol) / (0.010 L)
Molarity (M) = 0.78 mol/L
Therefore, the molarity of the acetic acid is 0.78 mol/L.
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0. 450 kg of gasoline is spilled. If the density of gasoline is 0. 665 g/mL, what volume of gasoline is spilled?
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A 0.545L solution of KOH has a molarity of 2.84M. How many grams of KOH were used to make this aqueous solution?
Answer: 86.68 grams KOH or 86.7 g KOH to correct sig figs
Explanation:
M= moles/L
moles = MXL
moles = 2.84 X 0.545 = 1.55 moles now multiply by the molar mass of KOH
which is 56 (from the periodic table) =
Provide the products and balance the reaction below for the complete combustion of the fatty acid octanoic acid, C8H16O2
C8 H16 O2 (s) + O2(g) →?
A hydrocarbon comprises 92.3% carbon by mass and 7.7% hydrogen by mass. The compound's empirical formula will be oose answer: CH CH5, CH CH3, CH CH4.
What is octanoic acid's fatty acid?Octanoic acid is a straight-chain saturated fatty acid derived from heptane in which one of the terminal methyl group's hydrogens has been replaced by a carboxy group. Caprylic acid is another name for octanoic acid. It functions as an antibiotic agent, a human metabolite, and an E. coli metabolite.
Along the chain of saturated fatty acids, there are no double bonds or any functional groups. In the sense that all carbons are "saturated," the term "saturated" refers to hydrogen (apart from the carboxylic acid [-COOH] group)
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The equation below represents a chemical reaction that occurs in living cells.
C6H12O6 + 6O2 ------> 6CO2 + 6H2O + energy
The reactants contain a total of _____?
atoms.
Answer:
Explanation:
The total number of atoms in the reactants can be determined by counting the atoms on each side of the equation.
On the left side, there are:
6 carbon atoms (C)
12 hydrogen atoms (H)
6 oxygen atoms (O)
On the right side, there are:
6 carbon atoms (C)
12 hydrogen atoms (H)
18 oxygen atoms (O)
Therefore, the reactants contain a total of:
6 + 12 + 6 = 24 atoms (of carbon, hydrogen, and oxygen)
Answer: 24 atoms
Which method would you use to separate sand and salt and water?
Answer:
Filtration
Explanation:
Sand can be separated by filtration. Then, salt can be separated by evaporating the salt solution in water. Water can be recovered by condensation.
pls mrk me brainliest
Answer:
decantation and evaporation
Explanation:
can someone help me answer this please.
with solution and answer. thanm you so much!!
Momentum-
[tex] \:\:\:\:\:\:\:\:\:\:\:\:\star\sf \underline {P = mv}\\[/tex]
Where-
P = Momentum m = Mass of Object v = Velocity of objectAs per question, we are given -
Distance travelled by car= 12 kmTime taken = 20 minutesConvert 20 minutes to hour-
1 minute = 1/60 hourTherefore, 20 minutes = 20/60 = 1/3 hour
[tex] \:\:\:\:\:\:\longrightarrow \sf\underline{Speed _{(car)} = \dfrac{Distance }{ time}}\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)} = \dfrac{12}{\dfrac{1}{3}}\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)}=12 \times 3 \\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)}= 36 km/h \\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)}= \dfrac{36 \times 1000}{3600}\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)}= \dfrac{\cancel{36} \times 10\cancel{0}\cancel{0}}{\cancel{36}\:\cancel{0}\cancel{0}}\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{Speed_{(car)} = 10 m/s }\\[/tex]
Mass = 30,000 gmMass = 30,000/1000 kg =30kgNo that we have obtained the velocity of the car is 10 m/s and the mass of the car is 30 kg,so we can put all the values and find for momentum of car -
[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{Momentum_{(car)} = mv}\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf Momentum_{(car)} = 30 \times 10\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf\underline{ Momentum_{(car)} =300 kgms^{-1}}\\[/tex]
Therefore, the momentum of car is 300 kgm/s.The rock in a particular iron ore deposit contains 80 %; Fe2O3 by mass. How many kilograms of the rock must be processed to obtain 2800 kg of iron? Express your answer using two significant figures
Mass of rock = 5004.16kg. The mass of the elements present in the compound determines the percentage composition.
Given that the [tex]Fe_{2} O_{3}[/tex] is 80 % by mass.
It means that 80 kg of is present in 100 kg of rock
To find the mass of rock which contains 2800 kg of iron
2800 kg = 2800*1000 g
2 moles of iron are present in 1 mole of
Molar mass of iron = 55.845 g/mol
Mass of 2 moles = 55.845 * 2 = 111.69 g/mol
159.69 g/mol Molar mass of [tex]Fe_{2} O_{3}[/tex]
It implies,
In 159.69 g of iron, there are 111.69 g.
The amount of iron in 159.69/111.69 g of
There are 2800*1000 g in (159.69/111.69) *2800*1000 g of material.
Mass of [tex]Fe_{2} O_{3}[/tex] = 4003.33kg
Thus,
100 kg of rock contains 80 kg.
One kilogram of rock makes up 100/80 kg.
(100/80) *4003.33 kg of rock contains 4003.33 kg.
Mass of rock = 5004.16kg
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Can someone please help with this chemistry question?
If you have 3.45 mol sample of iron, how many grams of Fe₂O₃ will there be after the iron has rusted completely is 193.2 g Fe₂O₃.
Rust is a multi-paradigm, general-purpose programming language developed by Mozilla Research. It is designed to be a safe, concurrent, practical language that supports functional and procedural programming. Rust is syntactically similar to C++, but its memory safety features make it safer and more secure. It also provides better performance than many other languages. Rust provides memory safety by using a type system and a borrowing system to ensure that memory is only accessed when it is valid.
The balanced equation for the rusting of iron is:
Fe + O₂ -> Fe₂O₃
To calculate the grams of Fe2O₃ produced, we must first convert 3.45 mol Fe to grams.
Molar mass of Fe = 56.0 g/mol
Therefore, 3.45 mol Fe x 56.0 g/mol = 193.2 g Fe
Now, according to the balanced equation, 1 mol Fe produces 1 mol Fe₂O₃.
So, 193.2 g Fe will produce 193.2 g Fe₂O₃.
Therefore, the answer is 193.2 g Fe₂O₃.
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need answer asap!! will give brainliest!
The mistake is made in step 1.
Stoichiometric problem2C4H10 + 13 O2 → 8 CO2 + 10 H2O
From the equation, we see that 2 mole of butane reacts with 13 moles of oxygen to produce 10 moles of water.
First, we need to convert the given mass of water to moles:
1500 g H2O ÷ 18.015 g/mol H2O = 83.284 mol H2O
Next, we can use stoichiometry to calculate the moles of butane required to produce this amount of water:
83.284 mol H2O × 2 mol C4H10 ÷ 10 mol H2O = 16.657 mol C4H10
Finally, we can convert moles of butane to grams:
16.657 mol C4H10 × 58.12 g/mol C4H10 = 967.79 g C4H10
Thus, the mistake in the calculation was made in the first step where the given mass of water is to be converted to moles.
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Rewrite the following procedure using improved scientific language and in proper format: First I broke 2 eggs into a bowl and mixed them up really good. Then I added some oil and water. After that I mixed the cake mix until everything looked the same, then it went in the oven for a bit.
The batter was then transferred to a baking dish and placed in the oven for the required baking time.
What is Carbon dioxide?
Carbon dioxide (CO2) is a colorless, odorless gas that is naturally present in the Earth's atmosphere. It is composed of one carbon atom bonded to two oxygen atoms, and is a byproduct of respiration, combustion, and other chemical reactions. CO2 is important for plant growth and is also a greenhouse gas, contributing to the warming of the Earth's atmosphere.
To prepare the cake batter, two eggs were cracked into a mixing bowl and beaten thoroughly. Next, a suitable amount of oil and water were added to the mixture. The cake mix was then slowly added and stirred until it formed a homogeneous mixture.
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Show that you understand energy and its forms, including potential, chemical, and thermal energies by describing how gasoline can have potential, chemical, and thermal energy.
Gasoline can have potential energy because it is stored in a container, chemical energy because of the energy stored in its molecular bonds, and thermal energy because of the heat produced when it is burned.
How can gasoline have potential, chemical, and thermal energy?Gasoline is a fuel that contains potential, chemical, and thermal energy.
Potential energy is the energy that an object has due to its position or configuration. In the case of gasoline, it has potential energy because it is stored in a tank or container and has the potential to be used as fuel for a car or other combustion engine.
Chemical energy is the energy that is stored in the bonds between atoms and molecules. Gasoline has chemical energy because it is made up of molecules that contain stored energy in the form of chemical bonds. When gasoline is burned in an engine, the chemical energy is released and converted into thermal energy.
Thermal energy is the energy that is related to the temperature of a substance. When gasoline is burned in an engine, it produces thermal energy as a result of the chemical reactions that take place. This thermal energy is then converted into mechanical energy that powers the car's engine.
In summary, gasoline can have potential energy because it is stored in a container, chemical energy because of the energy stored in its molecular bonds, and thermal energy because of the heat produced when it is burned. These three forms of energy are all interrelated and can be converted from one form to another.
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E
C
A
Making Esters
1. Name the following esters and give the name of the alcohol + carboxylic reacted to make each one.
нн
но
||
Hнн
H-C-ë-o-С-С-Н
II
нн
Н
н н
H-c-c-c
11
нн
H-C - c- c-c
| | |
Hнн
=0
нн
I Т
O
Н
O-C-H
Н
B
нннн
|
|
0 — 0 — c - C - C -H
| | |
НННН
D
H-C-C-
| |
нн
F
Н
H-c-
Н
C
<=0
O
Н
H
нн
НН Н
H-c-c
Кт жи
11
H- C-C — с
11
11
- C — C — C —H
нн
H
| | |
HHH
H
H
|
- C-H
нннн
H
C-C C-C-H
=0
нннн
H-C
ннн
0 - ć - c - C-H
ннн
н н
0-c - C -н
HH
Answer:
Here are the names of the esters and the corresponding alcohols and carboxylic acids that were used to make them:
1. Ethyl acetate, made from ethanol and acetic acid
2. Methyl propanoate, made from methanol and propanoic acid
3. Butyl butyrate, made from butanol and butyric acid
4. Octyl formate, made from octanol and formic acid
5. Ethyl benzoate, made from ethanol and benzoic acid
6. Ethyl propionate, made from ethanol and propanoic acid
7. Methyl butyrate, made from methanol and butyric acid
8. Ethyl butyrate, made from ethanol and butyric acid
9. Propyl formate, made from propanol and formic acid
10. Butyl propionate, made from butanol and propanoic acid.
N₂(g) + 3 H₂(g) 2 NH3(g)
What mass in grams of ammonia (NH3) would the experiment produce if Brett uses
3 moles of nitrogen gas (N₂) and an excess of hydrogen?
5.7 g NH3
O 102 g NH3
17 g NH3
51 g NH3
The experiment would produce 102.18 g of ammonia. The answer is closest to 102 g NH₃.
Steps
The balanced chemical equation for the reaction is:
N₂(g) + 3H₂(g) → 2NH₃(g)
In this equation, the stoichiometric ratio of nitrogen gas to ammonia gas is 1:2. Accordingly, 2 moles of ammonia gas are created for every 1 mole of nitrogen gas that reacts.
As a result of using 3 moles of nitrogen gas, Brett will generate 2 x 3 = 6 moles of ammonia gas.
From the equation, we can see that for every 1 mole of nitrogen gas (N₂) used, 2 moles of ammonia (NH₃) will be produced. Therefore, if 3 moles of N₂ is used, the number of moles of NH₃ produced will be:
moles of NH₃ = (3 moles N₂) x (2 moles NH₃ / 1 mole N₂) = 6 moles NH₃
To calculate the mass of NH₃ produced, we need to use its molar mass, which is 17.03 g/mol. Therefore:
mass of NH₃ = (6 moles NH₃) x (17.03 g/mol) = 102.18 g NH₃
So, the experiment would produce 102.18 g of ammonia. The answer is closest to 102 g NH₃.
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[see photo] please help!!
option a is the answer
10
PLEASE HELPPPP
How many grams of HCl will make a solution with 100g of water saturated at 60 degrees C?
(please be quick!!!!)
110g HCl
55g of HCl
27.5g of HCl
If you want a solution that is less than saturated, the amount of HCl needed is less - in this case, 27.5g.
What is saturated?Saturated refers to a state of being filled to capacity or having reached its maximum level. In chemistry, it is used to describe a molecule or compound that has all its available bonds filled with either single or multiple bonds. It is a state of maximum solubility, meaning that no more of a substance can dissolve in a given solvent. In physical science, it can also refer to the highest temperature where a substance can exist in the liquid state without boiling.
The amount of HCl required to make a solution with 100g of water saturated at 60 degrees C depends on the concentration of the HCl solution you are trying to make. If you want to make a saturated solution, the maximum amount of HCl that can be dissolved in 100g of water at 60 degrees C is 55g. If you want a solution that is less than saturated, the amount of HCl needed is less - in this case, 27.5g.
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A student set up a titration apparatus that involved using 25. 9 mL of 1. 57 M acetic acid. The acetic acid was titrated with 0. 154 M NaOH.
What is the pH of the titration solution after 2. 19 mL of the NaOH was added if the Ka of acetic acid is 1. 8 x 10-5?
Answer:
The PH is 2.66 of the titration solution after 2.19 ml of the naoh was added if the ka of acetic acid is 1.8 x 10-5
Explanation:
What is meant by an organism’s body functions
Penelope's friend Joe gives her a ring for Valentine's Day, which he said is 14k white gold. Penelope's friend Daksha thinks it's actually composed of nickel. Describe a process/experiment that Penelope could conduct to find out for sure.
Dimethylglyoxime is a chemical that is present in this kit (in solution). KIT The solution will turn pink when used to clean a metal object with such a cotton swab when nickel is present in the Penelope's 14k white gold ring.
Check for the presence of nickel in white gold:White gold was first created to mimic platinum (a white metal). White gold is typically an alloy containing around 75% gold or around 25% nickel and zinc. It would be approximately 75% pure gold if it had an 18 karat stamp.
The question:
Joe, a friend of Penelope's, presents her with a 14k white gold ring on Valentine's Day. Daksha, a friend of Penelope's, believes it is truly made of nickel. Penelope may use the following procedure or experiment to determine this for sure:
You can get a nickel test kit if you're buying jewelry and are unsure if it includes nickel. Dimethylglyoxime is a chemical that is present in this kit (in solution). This chemical is used without harming the thing being evaluated.The solution turns pink when used to clean a metal object with such a cotton swab when nickel is present. This test may not detect trace levels of nickel, but it is typically a reliable jewelry detector.Know more about white gold
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A buffer solution contains 0. 337 M hydrocyanic acid and 0. 344 M sodium cyanide. If 0. 0359 moles of hydroiodic acid are added to 150 mL of this buffer, what is the pH of the resulting solution ?
The pH of the resulting solution is 8.57. In terms of moles/liter, pH is the negative logarithm of the concentration of hydrogen ions. pH expresses the nature of the solution (acidic, alkaline or neutral).
Number of HCN moles equals molarity * volume in L.
= 0.337(0.15) = 0.05055 moles
Number of NaCN moles = molarity * volume in L.
= 0.344(0.15) =0.0516 moles
HCN's Pka is 9.31.
PH = Pka + log [NaCN]/[HCN]
= 9.31 + log0.0516/0.05055
= 9.31 + 0.00893 = 9.319
After adding 0.0359 moles of HCL, the number of moles of HCN is equal to 0.05055 + 0.0359, = 0.08645 moles.
After adding 0.0359 moles of HCl, the number of moles of NaCN is equal to 0.0516-0.0359 moles, = 0.0157 moles.
PH = PKa + log [NaCN]/[HCN] = 9.31 + log [0.0157/0.08645] = 9.31 -0.74086 = 8.57
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Use the exponential notation to express the physical quantities
a. V= 15. 50 ml to L
b. M= 5. 00mg to g
c. M= 2000 to g
d. Λ= 256. 4nm to m
To begin today’s experiment you wash a 125 ml erlenmeyer flask and set up the experiment as show in figure 1. After allowing your water to boil for 10 minutes you remove the flask, clamp it and immerse it in water. After performing your calculations you see that your data is a little higher than everyone else’s. What is the probable source of the error?
One potential source of error could be a measurement error, either in the volume of water added or in the temperature of the water. Another potential source of error could be a problem with the calibration of the thermometer used to measure the temperature of the water.
However, one of the most likely sources of error in this case is the presence of air bubbles in the erlenmeyer flask during the experiment. Air bubbles can act as an insulator, trapping heat and preventing the water from reaching the same temperature as the rest of the water in the flask. This can result in an inaccurate measurement of the water's temperature and ultimately affect the calculation of the experimental data.
To reduce the impact of air bubbles in future experiments, it is recommended to ensure that the erlenmeyer flask is thoroughly cleaned and free of any debris or contaminants that may trap air bubbles. Additionally, carefully swirling the flask during the heating process can help to dislodge any trapped air bubbles and ensure that the water is evenly heated.
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