Answer:
A
Explanation:
Force of gravity can be expressed as:
F = GMM/R^2
Where
F = gravitational force
M = mass
R = distance
Also, W = mg
From the above equation, we can deduce that force of gravity actually depends on mass and not volume.
The correct answer is therefore A.
Had twice as much mass
Therefore, the force of gravity pulls down on your school with a total force of 400,000 newtons. The force of gravity pulling down on your school would be exactly twice as much if your school Had twice as much mass
A train travels due north in a straight line with a constant speed of 100 m/s. Another train leaves a station 2,881 m away traveling on the same track, but traveling due south with a constant speed of 136 m/s. At what position will the trains collide? Round to the nearest whole number.
Answer:
The trains will collide at a distance 1660 m from the station
Explanation:
Let the train traveling due north with a constant speed of 100 m/s be Train A.
Let the train traveling due south with a constant speed of 136 m/s be Train B.
From the question, Train B leaves a station 2,881 m away (that is 2,881 m away from Train A position).
Hence, the two trains would have traveled a total distance of 2,881 m by the time they collide.
∴ If train A has covered a distance [tex]x[/tex] m by the time of collision, then train B would have traveled [tex](2881 - x)[/tex] m.
Also,
At the position where the trains will collide, the two trains must have traveled for equal time, t.
That is, At the point of collision,
[tex]t_{A} = t_{B}[/tex]
[tex]t_{A}[/tex] is the time spent by train A
[tex]t_{B}[/tex] is the time spent by train B
From,
[tex]Velocity = \frac{Distance }{Time }\\[/tex]
[tex]Time = \frac{Distance}{Velocity}[/tex]
Since the time spent by the two trains is equal,
Then,
[tex]\frac{Distance_{A} }{Velocity_{A} } = \frac{Distance_{B} }{Velocity_{B} }[/tex]
[tex]{Distance_{A} = x[/tex] m
[tex]{Distance_{B} = 2881 - x[/tex] m
[tex]{Velocity_{A} = 100[/tex] m/s
[tex]{Velocity_{B} = 136[/tex] m/s
Hence,
[tex]\frac{x}{100} = \frac{2881 - x}{136}[/tex]
[tex]136(x) = 100(2881 - x)\\136x = 288100 - 100x\\136x + 100x = 288100\\236x = 288100\\x = \frac{288100}{236} \\x = 1220.76m\\[/tex]
[tex]x[/tex]≅ 1,221 m
This is the distance covered by train A by the time of collision.
Hence, Train B would have covered (2881 - 1221)m = 1660 m
Train B would have covered 1660 m by the time of collision
Since it is train B that leaves a station,
∴ The trains will collide at a distance 1660 m from the station.
To dazzle his students, Mr. Turner collected volumes of ammonia gas and carbon dioxide gas. As the two colorless gases were combined in a closed two-liter bottle with a small amount of ammonium hydroxide, the chemistry students watched in amazement at the growth of white crystals inside the bottle. What happened inside the bottle as the gases were mixed? A) a physical change B) a chemical change C) the solution process D) a mixture was formed
Answer:
B) a chemical change .
Explanation:
There will be no chemical reaction when the gases ammonia and carbon dioxide are mixed together . But when there is presence of ammonium hydroxide , chemical reaction takes place between carbon dioxide and ammonium hydroxide resulting into the formation of ammonium carbonate as follows
2NH₄OH + CO₂ =( NH₄)₂CO₃ + H₂O.
The growth of white crystals inside the bottle indicates the presence of ammonium carbonate .
So it is a chemical change .
1/2mv^2+Fd=mgh solve for F
Answer:
[tex]F=\frac{mgh-\frac{1}{2} mv^2}{d}[/tex]
Explanation:
Step 1: Write out equation
[tex]\frac{1}{2} mv^2+Fd=mgh[/tex]
Step 2: Subtract FD on both sides
[tex]\frac{1}{2} mv^2=mgh-Fd[/tex]
Step 3: Subtract mgh on both sides
[tex]\frac{1}{2} mv^2-mgh=-Fd[/tex]
Step 4: Divide both sides by -d
[tex]\frac{\frac{1}{2} mv^2-mgh}{-d} =F[/tex]
Step 5: Rewrite
[tex]F=\frac{mgh-\frac{1}{2} mv^2}{d}[/tex]
Sort the length measurements in increasing order of magnitude from smallest to largest Drag each tile to the correct box Tiles Sequence micrometer Kilometer decimeter centimeter nanometer dekameter
Answer:
Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer
Explanation:
Given the following length measurement :
micrometer Kilometer decimeter centimeter nanometer dekameter.
Sorting in increasing order of magnitude from Smallest to Largest.
Expressing in terms of meters :
1 meter = 0.1 decameter
1 meter = 1 × 10^9 nanometer
1 meter = 1 × 10^2 centimeter
1 meter = 1 × 10^1 decimeter
1 meter = 0.001 kilometer
1 meter = 1 × 10^6 micrometers
Hence, arranging from Smallest to Largest :
Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer
could you guys help me with homework it's due tommorow
Answer:
d students show that stress can make people sick
One half of a balanced chemical equation is shown. 3Mg(OH)2 + 2H3PO4
Answer:
3 Mg, 2 P, 14 O, 12 H
Explanation:
A hiker is at the bottom of a canyon facing the canyon wall closest to her. She is 790.5 meters from the wall and the sound of her voice travels at 329.2 m/s at that location. How long after she shouts will she hear her echo? Round to two decimals. (Be careful to consider why echoes happen)
Answer:
4.80 seconds
Explanation:
The velocity of sound is obtained from;
V= 2d/t
Where;
V= velocity of sound = 329.2 ms-1
d= distance from the wall = 790.5 m
t= time = the unknown
t= 2d/V
t= 2 × 790.5/ 329.2
t= 4.80 seconds
Iron (II) hydroxide, whose chemical formula is shown here, is soluble in different solutions. In which solution would the Iron (III) hydroxide be LEAST soluble? A) OM (distilled water) B) 0.2M Fe3+ 0.5M Fe3- D) 1.0M Fe3-
Answer:
Explanation:
b 0.2m
Answer:
D. 1.0M Fe3+
Explanation:
I just took a took a test on this exact question.
Car A is travelling with a constant speed of 30 m/s and Car B is travelling with a constant speed of 110 km/h. Which car is travelling at a faster speed?
Answer:
Car B is travelling at a faster speed
Explanation:
We are given;
Speed of car A; V_a = 30 m/s
Speed of car B; V_b = 110 km/h
Now, V_a is already in m/s, so let's convert V_b to m/s too.
From conversions, 36 km/h = 10 m/s, therefore, 110 km/h would give;
(110 × 10)/36 = 30.56 m/s
Thus, V_b = 30.56 m/s
Comparing both speeds in m/s, we can see that 30.56 m/s > 30 m/s.
Thus, Car B is travelling at a faster speed.
The slowest moving animal is a crab found in the Red Sea. It travels with an average speed of 5.7 Km/year How long will it take this animal to travel 100 km?
Time = distance / speed
Time = (100 km) / (5.7 km/yr)
Time = 17.5 years
If this is true, then it's not likely that any member of the species has ever traveled 100 km in its lifetime. Weird !
how does an atom charge if all the electrons are removed
Answer: its does not have any charge but it still might have nuetrons.
Explanation:
Answer:
it will change to become a positively charged ion called a cation.
Explanation:
Ions are formed when an atom gains or loses electrons from its valence shell. This process causes an imbalance between the number of positively charged protons and negatively charged electrons, so the overall ion will carry a net positive or negative charge (I got this explanation from google)
What is the formula for finding the perimeter of a space?
Answer:
What shape is it? the formula is different depending on the shaping
Explanation:
Square P=4s
Rectangle P=2L+2W
Triangle a+b+c
Circle P=C=2πr=πd
and so on
Which of the following characteristics did John Dalton include in his description of the atom?
A. In any element, all the atoms are the same
B. Atoms only exist on Earth
C. Atoms are smaller than quirks
D. All matter is made up of atoms
E. Elements in a compound are always in constant action
Please just type the letters.
Answer:
The answer is "In any element ,all the atoms are the same".
A bus is mobing with aspped of 72km/hr .convert this speed in m/s.
Answer
ANSWER WITH FULL EXPLANATION
If a speed is given km/h, then the formula to convert the speed from km/h to m/s is
km/h = m/s
In other words, if you want to convert the given speed from km/h to m/s, then multiply the given number by and put "m/s" after it.
The speed of a car is 72 km/h.
Converting the speed into m/s
72 km/h = m/s = 20 m/s
∴ The speed of the car (expressed in m/s) is 20 m/s.
SHORT ANSWER
1km/h=5/18m/s
72km/h=72×5/18m/s
=4×5m/s
=20m/s.
HOPE THIS HELPS YOU PLEASE MARK ME AS BRAINLIEST
4. If a person runs at 4 m/s for 2 minutes, how far will they run?
Answer:
48 metresExplanation:
[tex]Speed = 4m/s\\Time = 2m = 120 secods\\\\Distance = ?\\Distance = Speed \times time \\\\Distance = 4 \times 12\\= 48\: meters[/tex]
The distance covered by the person is 480 meters.
We have a a person who runs at 4 m/s for 2 minutes.
We have to determine how far he had run.
What is the formula to calculate the distance travelled by the moving body?The distance travelled by the body can be given by -
d = v x t
where -
v - velocity of body
t - time for which the body travelled
According to question, we have -
v = 4 m/s
t = 2 minutes = 120 seconds
Therefore, the distance travelled will be -
d = v x t
d = 4 x 120
d = 480 meters
Hence, the distance covered by the person is 480 meters.
To solve more questions on Kinematics, visit the link below -
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Where is the Oort cloud located?
O between the orbit of Mars and the orbit of Jupiter
O in the different orbits between the sun and Neptune
O beyond the Kuiper belt, at the farthest end of the solar system
O all over the solar system and between the orbits of the planets
Answer: C
Explanation: just did it
Answer:
C
Explanation:
edg 2021 AP Physc
pls pls pls answer fast
Answer:
a) The maximum speed of the bus is 10 m/s
b) The bus was stationary for 3 seconds
c) The total distance travelled is about 126 m
d) The average velocity of the bus is approximately 5.04 m/s
From a rifle of mass 4 kg, a bullet of mass 50 g is fired with an initial velocity of 35 m/s. Calculate the initial recoil velocity of the rifle.
[tex]\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}[/tex]
Mass of rifle = 4kg
Mass of bullet = 50g = 0.05kg
Initial velocity of bullet = 35m/s
[tex]\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}[/tex]
Recoil velocity of rifle.
[tex]\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}[/tex]
Recoil velocity of rifle is given by
[tex]\dag\:\boxed{\bf{\purple{V=-\dfrac{mv}{M}}}}[/tex]
M denotes mass of riflem denotes mass of bulletv denotes velocity of bullet[tex]:\implies\sf\:V=-\dfrac{mv}{M}[/tex]
[tex]:\implies\sf\:V=-\dfrac{0.05\times 35}{4}[/tex]
[tex]:\implies\sf\:V=-\dfrac{1.75}{4}[/tex]
[tex]:\implies\bf\:V=-0.437\:ms^{-1}[/tex]
[Note : -ve sign shows opposite direction]
Answer:
MgVg=MbVb.
4×Vg=0.05×35.
4Vg=1.75.
Vg=1.75/4
=0.4375 ~ 0.4m/s.
A roller coaster is traveling at 13 m/s when it approaches a hill that is 400 m long. Heading down the hill, it accelerates at 4.0 m/s2. What is the final velocity of the roller coaster?
Answer:
The value is [tex]v = 47 \ m/s[/tex]
Explanation:
From the question we are told that
The initial speed of the roller coaster is [tex]u = 13 \ m/s[/tex]
The length of the hill is [tex]l = 400 \ m[/tex]
The acceleration of the roller coaster is [tex]a=4.0 \ m/s^2[/tex]
Generally the acceleration is mathematically represented as
[tex]a = \frac{ v - u}{ t_f - t_i }[/tex]
Here [tex]t_i[/tex] is the initial time which is equal to zero
[tex]v_f[/tex] is the final velocity which is mathematically represented as
[tex]v_f = \frac{d}{ t_f}[/tex]
So
[tex]a = \frac{ \frac{d}{d_f} - u }{ t_f - t_i}[/tex]
[tex]4 = \frac{\frac{400}{ t_f} - 13}{t_f - 0}[/tex]
[tex]4 = \frac{400 - 13t_f}{ t_f} * \frac{1}{t_f}[/tex]
[tex]4t_f ^2 +13f + 400 =[/tex]
Solving this using quadratic formula we obtain
[tex]t_f = 8.5 \ s[/tex]
[tex]t_f = -11.8 \ s[/tex]
Generally time cannot be negative so
[tex]t_f = 8.5 \ s[/tex]
Generally the final velocity is mathematically represented as
[tex]v = \frac{400}{8.5}[/tex]
[tex]v = 47 \ m/s[/tex]
Answer:58 m/s
Explanation:
That’s what it says
Referring to the image below (based on vectors physics), how does he get F2X = F2Cosθ. I don't understand how he got the equation so that he knows there are equal. I circled it in orange.
Answer:
Please see explanation below
Explanation:
Recall that trigonometric functions like cosine (cos) and sine (sin) of an angle are defined based on the relationships between the sides and hypotenuse of a right angle triangle:
[tex]sin(\theta)=\frac{opposite}{hypotenuse} \\cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]
where the terms "opposite" and "adjacent" refer to the sides opposite and adjacent to the angle in question.
Based on such, one can solve for example for the "adjacent" side (the horizontal component of the 200 N vector you need to find) to the known angle ([tex]\theta[/tex]) in the following way:
[tex]cos(\theta)=\frac{adjacent}{hypotenuse}\\cos(\theta)=\frac{adjacent}{hypotenuse}\\cos(30^o)=\frac{adjacent}{200}\\adjacent=200\,\,cos(30^o)[/tex]
A man dropped a dime in a wishing well, he heard it 10 sec later Find velocity on impact
Answer:
Vf = 98 m/s
Explanation:
The dime is in a free fall motion under the influence of gravity. For the final velocity of the dime, we use 1st equation of motion here:
Vf = Vi + gt
where,
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s (Since, the initially the dime was at rest)
g = acceleration due to gravity = 9.8 m/s²
t = time taken = 10 s
Therefore, using these values, we get:
Vf = 0 m/s + (9.8 m/s²)(10 s)
Vf = 98 m/s
88 L + 120 dL = _____________ L?
Answer:
100 L
Explanation:
10 dL = 1 L
Mary is bouncing her basketball down the court and wants to find out how much mechanical energy she has. What is the formula that she should use?
Answer:
Mary is practicing kinetic energy so she can use 1/2mv^2.
Mary is bouncing her basketball down the court and wants to find out how much mechanical energy she has, then she has to use the formula
Mechanical energy = 1/2mv² + mgh
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.
As total mechanical energy is the sum of all the kinetic as well as potential energy stored in the system.
ME = KE + PE
As Mary is bouncing the basketball this means it would have some kinetic energy because of the movement along with the potential energy which is due to the height of the bouncing basketball
The total kinetic energy of the basketball
KE = 1/2mv²
Similarly, the total potential energy of the basketball
PE = mgh
Thus, when Mary is bouncing her basketball down the court and has to use the formula to calculate how much mechanical energy she has.
1/2mv² + mgh = mechanical energy.
Learn more about mechanical energy from here
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The unit of force,newton is a derived unit.why?
Answer: Newton, the unit of force, is defined based on Newton's Second Law (F=ma), as the force required to give a mass of one kilogram an acceleration of 1 meter/second2. Thus, it is derived from these other units.
Explanation:
Answer:
The unit of force is a derived unit.
Why because it isn't part of the fundamental units which is MLT which stands for mass,length and time.....MLT are the units that brings out the derived units that's why it is called derived units because it is derived from fundamental units so Newton/force is not part of the fundamental unit and if we find the dimension of force you will see that it will be L^2T^-2.....which means it is derived from fundamental unit which makes it a derived unit....Thank you for the question
A ball is dropped off a roof. The ball falls for 4 seconds. Just before the ball hits the ground what is its velocity?
Show work
Answer:
The velocity is 39.24 m/s
Explanation:
The time of fall t = 4 seconds
The initial velocity u = 0 m/s (since the ball is dropped, meaning it starts from rest)
Final velocity v = ?
Using
v = u + gt
where g is the acceleration due to gravity = 9.81 m/s^2
substituting, we'll have
v = 0 + (9.81 x 4)
v = 39.24 m/s
A NASA spacecraft measures the rate of at which atmospheric pressure on Mars decreases with altitude. The result at a certain altitude is: Convert to .
Answer:
[tex]= 4.21\times 10^{-10}J/cm^4[/tex]
Explanation:
According to the given situation, the computation is shown below:-
[tex]1kPa=10^3Pa[/tex]
So,
[tex]1Km = 10^5cm[/tex]
[tex]1kPa=0.01Pa/Cm[/tex]
[tex]1kPa=10^{-8}J/cm^4[/tex]
Now as per the question it is given that
r = 0.0421KPa/Km
= [tex]0.0421KPa/Km \times \frac{10^{-8}J/cm^4}{1KPa/Km}[/tex]
after solving the above equation we will get
= [tex]0.0421\times 10^{-8}J/cm^4[/tex]
or we can write the above equation in this manner, that is
[tex]= 4.21\times 10^{-10}J/cm^4[/tex]
Therefore we have solved the equation to reach the right answer.
A car travels 30.0 km to the south and then turns around and travels 20.0 km to the north in 1.5 hours time. What is the car's total displacement? What is the car's average velocity?
Total displacement = ______ km S
Average velocity = ________ km/h S
Explanation:
Total displacement =30+20=50 Km
Average velocity =displacement /time
V=50/1.5=33.33km/hr
Answer:
Total Displacement: 10
Average velocity, closest option is 10.
Explanation:
30-20=10
state position nature and size of an image when an object placed at an distance equal to its focal length of rear view in vehicles
Answer:
The position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be
1) Position: Behind the mirror
2) Nature: Virtual
3) Size: Smaller than the object
Explanation:
Due to the nature and use of rear view mirrors, which are meant to enable the front facing driver visualize a wide area of the back portion of the vehicle, such that the images of the object will always remain smaller than the object, require a convex image
The image size, location, nature and orientation of an object placed in front of a convex mirror is diminished, behind the mirror of the upright, virtual, and upright
Therefore, the position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be
Position: Behind the mirror
Nature: Virtual
Size: Smaller than the object.
What is the difference between virtual images produced by concave, plane and convex mirrors? What does the negative sign in the value of magnification produced by a mirror indicates about an image?
Two charged particles, q1 and q2, are located on the x-axis, with q1 at the origin and q2 initially atx1 = 14.7 mm.In this configuration, q1 exerts a repulsive force of 2.62 µN on q2. Particle q2 is then moved tox2 = 18.0 mm.What is the force (magnitude and direction) that q2 exerts on q1 at this new location? (Give the magnitude in µN.)
Answer:
The force magnitude is 1.75 μN acting outward from the origin towards x₂
Explanation:
The given parameters, are;
The location of q₁ = The origin
The location of q₂ = 14.7 mm from q₁
The repulsive force exerted on q₂ by q₁ = 2.62 μN
The location the particle q₂ is located to = 18.0 mm from q₁
By Coulomb's law, we have;
[tex]F = k\dfrac{q_1 \times q_2 }{r^2}[/tex]
Where;
k = Coulomb constant ≈ 8.99 × 10⁹ kg·m³/(s²·C²)
r = The distance between the particles
F = The force acting between the particles
When r = 14.7 mm F = 2.62 μN
∴ q₂ × q₁ = r² × F/k = (14.7×10^(-3))²×2.62×10^(-6)/(8.9875517923^9) ≈ 1.48 × 10⁻¹⁸
q₂ × q₁ = 1.48 × 10⁻¹⁸ C²
When the distance is increased to 18.0 mm, we have;
F = (8.9875517923^9) × 1.4796647 × 10^(-18)/((18×10^(-3))²) = 1.75 × 10⁻⁶ N
∴ F = 1.75 μN.
Therefore;
The force magnitude is 1.75 μN outward from the origin towards x₂.
To magnitude of the force that [tex]q_2[/tex] exerts on [tex]q_1[/tex] at this new location is 1.75 µN.
Given the following data:
Initial distance of [tex]q_2[/tex] = 14.7 mm to m = 0.0147 meter.Repulsive force = 2.62 µNFinal distance of [tex]q_2[/tex] = 18.0 mm to m = 0.018 meter.Scientific data:
Coulomb's constant = [tex]8.99 \times 10^9\; Nm^2/C^2[/tex]To calculate the force (magnitude and direction) that [tex]q_2[/tex] exerts on [tex]q_1[/tex] at this new location, we would apply Coulomb's law:
The force in an electric field.Mathematically, the force in an electric field is given by this formula:
[tex]F=\frac{kq_1q_2}{r^2}[/tex]
Where:
k is Coulomb's constant.q is the charge.r is the distance.[tex]q_1q_2 =\frac{F}{k} \times r^2\\\\q_1q_2 =\frac{2.62 \times 10^{-6}}{8.99 \times 10^9} \times 0.0147^2\\\\q_1q_2 = 2.914 \times 10^{-16} \times 0.00021609\\\\q_1q_2 = 6.30 \times 10^{-20}\;C^2[/tex]
For the force, when r = 0.018:
[tex]F =\frac{8.99 \times 10^9 \times 6.30 \times 10^{-20}}{0.018^2} \\\\F =\frac{5.66 \times 10^{-10}}{0.000324} \\\\F = 1.75 \times 10^{-6}[/tex]
Note: 1 µN = [tex]1 \times 10^{-6}\;N[/tex]
Force, F = 1.75 µN.
In conclusion, the direction of the force at the new location is outward from the origin along [tex]X_2[/tex].
Read more on electric field here: https://brainly.com/question/14372859