The force experienced by an electron in a field between parallel plates is proportional to which of the following? Select all that apply.

the potential difference between the plates

the current in the circuit

the inverse of the potential between the plates

the distance between the plates

the inverse of the distance between the plates

Answer:

160 watts.

Explanation:

Remark

Power = Work / Time

Work = F * d

Note: Since he is running up stairs he is doing work against gravity.

Givens

Formula

Solution

Answer:

Ns/Np = 0.171

Explanation:

First, we will find the ratio of lengths of each wire:

[tex]R_{p} = \frac{\rho L_{p}}{A}\\\\R_{s} = \frac{\rho L_{s}}{A}\\[/tex]

where,

Rs = Resistance of secondary coil

Rp = Resistance of Primary Coil

ρ = resistivity of copper

Ls = Length of the secondary coil

Lp = Length of theprimary coil

A = Area of cross-section of wie

Since the material and wire are the same. Therefore, dividing both equations, we get:

[tex]\frac{R_{s}}{R_{p}} = \frac{L_{s}}{L_{p}} \\\\\frac{L_{s}}{L_{p}} = \frac{13}{76}\\\\\frac{L_{s}}{L_{p}} = 0.171\\[/tex]

The number of turns are given as:

[tex]N_{s} = \pi DL_{s}\\N_{p} = \pi DL_{p}\\[/tex]

where,

Ns = No. of turns in the secondary coil

Np = No. of turns in the primary coil

D = Diameter of circular turns

D is the same for both coils. Therefore, dividing both equaions:

[tex]\frac{N_{s}}{N_{p}} = \frac{L_{s}}{L_{p}}\\\\[/tex]

Ns/Np = 0.171

Answer:

A mass of 10 kilograms lifted 10 meters in 5 seconds.

Explanation:

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

[tex] Power = \frac {Energy}{time} [/tex]

But Energy = mgh

Substituting into the equation, we have

[tex] Power = \frac {mgh}{time} [/tex]

Given the following data;

Mass = 10kg

Height = 10m

Time = 5 seconds

We know that acceleration due to gravity is equal to 9.8 m/s²

[tex] Power = \frac {10*9.8*10}{5} = 490 Watts [/tex]

Hence, a mass of 10 kilograms lifted 10 meters in 5 seconds would produce the most power.

Answer:

Sledgehammer A has more momentum

Explanation:

Given:

Mass of Sledgehammer A = 3 Kg

Swing speed = 1.5 m/s

Mass of Sledgehammer B = 4 Kg

Swing speed = 0.9 m/s

Find:

More momentum

Computation:

Momentum = mv

Momentum sledgehammer A = 3 x 1.5

Momentum sledgehammer A = 4.5 kg⋅m/s

Momentum sledgehammer B = 4 x 0.9

Momentum sledgehammer B = 3.6 kg⋅m/s

Sledgehammer A has more momentum

Answer:

I believe its a and c but my notes are all kinds of messed up so im sorry if its wrong

Explanation:

None of the  regions can the gravitational field strength due to the two planets be zero.

What is gravitational field?

A gravitational field is a model used in physics to explain the effects that a large thing has on the area surrounding it, exerting a force on smaller, less massive bodies. Consequently, a gravitational field, which is measured in newtons per kilogram, is employed to describe gravitational processes.

Field due to given masses can not be zero in the given region they do not cancel each other.

None of the  regions can the gravitational field strength due to the two planets be zero.

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Answer:

C?

Explanation:

Yep,It's C all right.

Answer:

Yep,It's C all right.

Explanation:

31kg

Explanation:

F = ma

m = F/a

m = 744N/24m/s^2

m = 31kg

(*Newton's Second Law*)

Explanation:

The diameter of a record, d = 0.3 cm

Radius, r = 0.15 cm

It rotates 33.5 times per minute.

(a) Frequency, f = 33.5 rotation/minute

= (33.5/60) rotation/second

= 0.55 rotation/second

(b) Time period,

T = 1/f

So,

[tex]T=\dfrac{1}{0.55}\\\\T=1.81\ s[/tex]

(c) Linear speed of a point on its rim,

[tex]v=r\omega\\\\v=0.15\times 10^{-2}\times 2\pi \times 0.55\\\\v=5.18\times 10^{-3}\ m/s[/tex]

(d) Centripetal acceleration,

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(5.18\times 10^{-3})^2}{0.15\times 10^{-2}}\\\\a=0.017\ m/s^2[/tex]

Hence, this is the required solution.

Answer:

B = 5.23 T

Explanation:

Given that,

Electric field, E = 550 V/m

The speed of the proton, v = 105 m/s

We need to find the magnitude of the magnetic field such that the beam of protons continues along its straight-line trajectory.

To move in a straight line, the magnitude of the electric force from the field and the magnetic field must be equal i.e.

[tex]qE=qvB\\\\B=\dfrac{E}{v}\\\\B=\dfrac{550}{105}\\\\B=5.23\ T[/tex]

So, the magnitude of the magnetic field is equal to 5.23 T.

Answer:

yes its c

Explanation:

took it already

Answer:

Explanation:

Suppose m₂ is greater than m₁ and it is going down . m₁ will be going up.

Let tension in string be T₁ and T₂  . Let common acceleration of system be a

For motion of m₁

T₁-m₁g = m₁a ----- (1)

For motion of m₂

m₂g- T₂ = m₂a ------- (2)

For motion of pulley

(T₂-T₁ )R represents net torque

(T₂-T₁ )R = I x α where I is moment of inertia of disc and α is angular acceleration of disc

(T₂-T₁ )R = 1/2 M R² x a / R

(T₂-T₁ ) = M a /2

Adding (1) and (2)

(m₂-m₁)g = (m₂+m₁)a + (T₂-T₁ )

(m₂-m₁)g = (m₂+m₁)a + Ma/2

(m₂-m₁)g = (m₂+m₁+ 0.5M)a

a = (m₂-m₁)g / ( (m₂+m₁+ 0.5M)

The acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].

Given to us

Masses = m₁, m₂

The radius of the pulley = R

Mass of the pulley = M

Assumption

We know the acceleration due to gravity is denoted by g,

[tex]T_1 = m_1(a+g)[/tex]......... equation 1

[tex]T_2 = m_2(a-g)[/tex]......... equation 2

The inertia of the pulley,  [tex]I = \dfrac{1}{2}MR^2[/tex]

Acceleration of the pulley, [tex]a = {\alpha }\times {R}[/tex]

[tex](T_2-T_1)R = I \times \alpha \\\\[/tex]

Substitute the values we get,

[tex][m_2(a-g)-m_1(a+g)]R = \dfrac{1}{2} MR^2 \times \dfrac{a}{R}\\\\[/tex]

[tex][m_2a-m_2g-m_1a-m_1g]R= \dfrac{1}{2} MR \times a[/tex]

[tex]m_2a-m_1a-m_2g-m_1g= \dfrac{1}{2} M \times a[/tex]

[tex]a(m_2-m_1)-g(m_2+m_1)= 0.5M \times a[/tex]

[tex]a(m_2-m_1)-0.5Ma=g(m_2+m_1)\\\\a(m_2-m_1-0.5M) = g(m_2+m_1)\\\\a = \dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex]

Hence, the acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].

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Answer:

1) A. .33 hr

2) B. 6ft

3) A. 58mi/hr

Answer:

the effect on energy is due to the force applied to the frisbee to throw it back in the tree.

Explanation:

Answer:

Let z = 200 ft and y = 150 ft

Also since 60 mph = 88 ft/sec then 4 mph = 88/15 = 5.87 ft.sec

Now   x^2 + y^2 = z^2

x dx/dt + y dy/dt = z dz/dt       differentiate wrt t

Or x dx/dt = z dz/dt    since dy/dt = zero

x = (200^2 - 150^2)^1/2 = 132.3 ft

dz/dt = x / z * dx/dt = 132.3 / 200 * 5.87 = 3.88 ft/sec

Energy can neither be created nor be destroyed.

Answer:

the law of conservation of energy states that the total energy of an isolated system remains constant.

Hello,

✔ We have: KE = PE (potential energy)

PE = m x g x h

The potential energy that the pebble of mass 1 has is called PE1 and the potential energy that the pebble of mass 2 has is called PE2  

PE1 = PE2 ⇔ PE1/PE2 = 1

[tex]\frac{m_1\times g\times h}{m_2\times g\times 4h} = 1 \\ \\ \frac{m_1}{m_2\times 4} = 1 \\ \\ \frac{m_1}{m_2} = 4[/tex]

The mass m1 is therefore 4 times greater than that of the stone of mass m2.

tbm queria saber essa pergunta!!

Answer:

    vₐ₀ = 29.56 m / s

Explanation:

In this exercise the initial velocity of car A is asked, to solve it we must work in parts

* The first with the conservation of the moment

* the second using energy conservation

let's start with the second part

we must use the relationship between work and kinetic energy

             W = ΔK                             (1)

for this part the mass is

             M = mₐ + m_b

the final velocity is zero, the initial velocity is v

friction force work is

              W = - fr x

the negative sign e because the friction forces always oppose the movement

we write Newton's second law for the y-axis

              N -W = 0

              N = W = Mg

friction forces have the expression

              fr =μ N

              fr = μ M g

we substitute in 1

               -μ M g x = 0 - ½ M v²

             v² = 2 μ g x

let's calculate

              v² = 2  0.750  9.8  6.00

              v = ra 88.5

              v = 9.39 m / s

Now we can work on the conservation of the moment, for this part we define a system formed by the two cars, so that the forces during the collision are internal and therefore the tsunami is preserved.

Initial instant. Before the crash

         p₀ = + mₐ vₐ₀ - m_b v_{bo}

instant fianl. Right after the crash, but the cars are still not moving

         p_f = (mₐ + m_b) v

         p₀ = p_f

         + mₐ vₐ₀ - m_b v_{bo} = (mₐ + m_b) v

         mₐ vₐ₀ = (mₐ + m_b) v + m_b v_{bo}

let's reduce to the SI system

          v_{bo} = 64.0 km / h (1000m / 1km) (1h / 3600s) = 17.778 m / s

let's calculate

         660 vₐ₀ = (660 +490) 9.39 + 490 17.778

         vₐ₀ = 19509.72 / 660

         vₐ₀ = 29.56 m / s

we can see that car A goes much faster than vehicle B

The energy that a substance contains is known as heat. Thus, the correct option for this question is B.

Entropy may be characterized as the measurement of the degree of randomness or in other words, it is the increase in the disorganization within a system. It is the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.

Equilibrium is a state of balance between opposing forces or actions that is either static or dynamic. It symbolizes the circumstance of being balanced in nature.

Thermal energy is a type of energy that is significantly contained within a system that is responsible for its temperature. Heat is the flow of thermal energy.

Therefore, the energy that a substance contains is known as heat. Thus, the correct option for this question is B.

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Answer:

D.The striking foot pushes backward against the ground. The friction with the ground provides an equal and opposite force forward

Answer:

d

Explanation:

Explanation:

W=F×s

w=20N×6m=120J

W=120J

Answer:

Acceleration of car = -5 m/s south

Explanation:

Given:

Initial velocity = 15 m/s

Final velocity = 5 m/s

Time taken = 2 sec

Find:

Acceleration of car

Computation:

Acceleration = Change in velocity / time

Acceleration of car = [5-15] / 2

Acceleration of car = -5 m/s south

Answer:

hello your question has some missing parts below are the missing parts

A Circular, 10-turn coil has a radius of 10.7 cm and is oriented with its plane perpendicular to a 0.2-T magnetic field.

answer : 1 volt

Explanation:

Determine the Average induced EMF during this mishap

A' = A/2  ( for a semi circle )

where A = [tex]\frac{\pi r^2}{2}[/tex]

To determine the Average induced EMF apply the relation below

| E | =  η * [tex]\frac{\beta A}{T}[/tex]   ----- ( 1 )

Replace A in equation 1 with  A = [tex]\frac{\pi r^2}{2}[/tex]

hence equation becomes : | E | =  η * βπr^2 / 2T'

where : T' = 0.0365 ,  β = 0.2 , η = 10 , r = 0.107

∴| E |  = 0.999 ≈ 1volts

Answer:

The magnitude of the lift generated by the wings of the airplane is 130,340 N.

Explanation:

Given;

mass of the airplane, m = 13,300 kg

speed of the airplane, v = 560 km/h = 155.56 m/s

The magnitude of the lift generated by the wings of the airplane is calculated as;

[tex]F_l = mg\\\\where;\\\\F_l \ is \ the \ magnitude \ of \ the \ lift \ generated\\g \ is \ acceleration \ due \ to \ gravity = 9.8 \ m/s^2\\\\F_l = 13,300 \times \ 9.8\\\\F_l = 130,340 \ N[/tex]

Therefore, the magnitude of the lift generated by the wings of the airplane is 130,340 N.

Answer:

14,432 g

Explanation:

PE=mh

360,800 J = (m)(25)

[tex]\frac{360,800 J}{25 m}[/tex] = m

14,432 g = m

Answer:

62.5 °

Explanation:

✓From law of reflection, angle of incidence equals angles of reflection .

✓the angle between the reflected ray can be determined using trigonometry, we know that

horizontal distance x =60.1 cm

the vertical distance is y =31.3

Then

tan( θ) =( y / x)

If we substitute the values we have,

tan θ = 31.3 / 60.1

θ = tan⁻¹ (0.5208)

θ = 27.5°

This angle is been measured using x-axis (horizontal)BBut in optics we can measured with respect to y-axis then angle becomes

θ = 90 - 27.5

θr = 62.5 °

θr = θi= 62.5°

the angle of incidence θiat which the laser beam strikes the mirror is 62.5°

Answer:

a) 10.23°C

b) - 0.8795 kJ / k

Explanation:

Given data :

mass of ice = 100 gram = 0.1 kg

mass of water in calorimeter = 100 grams = 0.1kg

temperature of water in calorimeter = 373K

a) Determine the Final temperature of the water once thermal equilibrium is established

Heat lost by water  = heat gained by Ice

Mwater * CPwater * Δt = Mice * Lice + Mice * CPwater * Δt

0.1 * (4.2 * 10^3 ) * ( 100 - t ) = ( 0.1 * 334 * 10^3 ) +  0.1 * (4.2 *1063 ) * ( T - 0 )

42000 = 33400 + 0.2 * 4200 * T

∴ equilibrium temp ( T ) = 10.23°C

B) Determine the entropy change of the universe of the process

Entropy change of ice = 33400/ 273 + 0.1 * 42 * 10^3 * In 283.23 / 273

                                     = 276.84 J/K

Entropy change of water = 0.1 * 42* 10^3 * In 283.23 / 273

                                          = -1156.34 J/K

Hence Entropy change of variance = 276.84 J/K + ( - 1156.34 J/K )

= - 0.8795 kJ / k