Answer:
0.58 +/- 0.115
(0.465, 0.695)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
p+/-z√(p(1-p)/n)
Given that;
Proportion p = 29/50 = 0.58
Number of samples n = 50
Confidence interval = 90%
z(at 90% confidence) = 1.645
Substituting the values we have;
0.58 +/- 1.645√(0.58(1-0.58)/50)
0.58 +/- 1.645(0.069799713466)
0.58 +/- 0.114820528652
0.58 +/- 0.115
(0.465, 0.695)
The 90% confidence interval estimate of the true population proportion of account customers who have a visa card with the bank is;
0.58 +/- 0.115
(0.465, 0.695)
What is the probability that the hand is a two of a kind? A two of a kind has two cards of the same rank (called the pair). Among the remaining three cards, not in the pair, no two have the same rank and none of them have the same rank as the pair. For example, {4♠, 4♦, J♠, K♣, 8♥} is a two of a kind.
Question:
A 5-card hand is dealt from a perfectly shuffled deck of playing cards.
What is the probability that the hand is a two of a kind?
A two of a kind has two cards of the same rank (called the pair). Among the remaining three cards, not in the pair, no two have the same rank and none of them have the same rank as the pair. For example, {4♠, 4♦, J♠, K♣, 8♥} is a two of a kind.
Answer:
P(two of a kind) = 42.3%
Step-by-step explanation:
The probability that the hand is a two of a kind is given by
P(two of a kind) = No. of ways to produce two of a kind/Total no. of ways to deal 5-hand cards
There are total 52 cards in a standard deck of playing cards.
Total number of ways to deal 5-card hand is given by
Total number of ways = ₅₂C₅
Total number of ways = 2595960
So there are 2595960 different ways of dealing 5-card hands
Now we will find out the number of ways to produce two of a kind.
The number of ways to select the rank of two matching cards is given by
Rank of matching cards = ₁₃C₁ = 13
Since the matching cards must be of same rank.
The number of ways to select the rank of remaining 3 cards is given by
Rank of remaining 3 cards = ₁₂C₃ = 220
Since the remaining ranks are now 12.
The number of ways to select the suits of two matching cards is given by
Suits of two matching cards = ₄C₂ = 6
The number of ways to select the suits of 1st non-matching card is given by
Suits of 1st non-matching card = ₄C₁ = 4
The number of ways to select the suits of 2nd non-matching card is given by
Suits of 2nd non-matching card = ₄C₁ = 4
The number of ways to select the suits of 3rd non-matching card is given by
Suits of 3rd non-matching card = ₄C₁ = 4
Finally, the probability is
P(two of a kind) = No. of ways to produce two of a kind/Total no. of ways to deal 5-hand cards
P(two of a kind) = (₁₃C₁ × ₁₂C₃ × ₄C₂ × ₄C₁ × ₄C₁ × ₄C₁) / ₅₂C₅
P(two of a kind) = (13 × 220 × 6 × 4 × 4 × 4) / 2595960
P(two of a kind) = 1098240/2595960
P(two of a kind) = 0.423
P(two of a kind) = 42.3%
Solve the given initial value problem. y triple prime plus 11 y double prime plus 38 y prime plus 40 y equals 0y′′′+11y′′+38y′+40y=0 y (0 )equals 0y(0)=0, y prime (0 )equals negative 19y′(0)=−19, y double prime (0 )equals 117
The linear homogeneous ODE
[tex]y'''+11y''+38y'+40y=0[/tex]
has characteristic equation
[tex]r^3+11r^2+38r+40=0[/tex]
which factors to
[tex](r+2)(r+4)(r+5)=0[/tex]
and hence has roots at [tex]r=-2,-4,-5[/tex]. So the characteristic solution to the ODE is
[tex]y_c=C_1e^{-2x}+C_2e^{-4x}+C_3e^{-5x}[/tex]
Use the given initial conditions to solve for each C.
[tex]y(0)=0\implies C_1+C_2+C_3=0[/tex]
[tex]y'(0)=-19\implies -2C_1-4C_2-5C_3=-19[/tex]
[tex]y''(0)=4C_1+16C_2+25C_3=117[/tex]
[tex]\implies C_1=-9,C_2=8,C_3=1[/tex]
so that the particular solution is
[tex]\boxed{y(x)=-9e^{-2x}+8e^{-4x}+e^{-5x}}[/tex]
Leah is 2 less than 3 times Rachel's age. 3 years from now, Leah will be 7 more than twice Rachel's age. How old will Rachel be in 3 years from now?
Answer:
15
Step-by-step explanation:
Let's call Leah's age l and Rachel's age r. We can write:
l = 3r - 2 (1)
l + 3 = 2(r + 3) + 7 (2)
Substituting (1) into (2) we get:
(3r - 2) + 3 = 2(r + 3) + 7
3r + 1 = 2r + 13
r = 12
In 3 years Rachel will be 12 + 3 = 15 years old.
3. A metal fabricating plant currently has five major pieces under contract each with a deadline for completion. Let X be the number of pieces completed by their deadlines, and suppose it's PMF p(x) is given by x 0 1 2 3 4 5 p(x) .05 .1 .15 .25 .35 .1 (a) Find and plot the CDF of X. (b) Use the CDF to find the probability that between one and four pieces, inclusive, are completed by their deadline
Answer:
a) The cumulative distribution function would be given by:
x 0 1 2 3 4 5
F(X) 0.05 0.15 0.30 0.55 0.9 1
b) [tex] P(1 \leq X \leq 4) = F(4) -F(0) =0.9-0.05 = 0.85 [/tex]
And replacing we got:
[tex]P(1 \leq X \leq 4) =0.85[/tex]
Step-by-step explanation:
For this case we have the following probability distribution function given:
x 0 1 2 3 4 5
P(X) 0.05 0.1 0.15 0.25 0.35 0.1
We satisfy the conditions in order to have a probability distribution:
1) [tex] \sum_{i=1}^n P(X_i)=1[/tex]
2) [tex] P(X_i) \geq 0, i=1,2,..,n[/tex]
Part a
The cumulative distribution function would be given by:
x 0 1 2 3 4 5
F(X) 0.05 0.15 0.30 0.55 0.9 1
Part b
For this case we want to find this probability:
[tex] P(1 \leq X \leq 4) = F(4) -F(0) =0.9-0.05 = 0.85 [/tex]
And replacing we got:
[tex]P(1 \leq X \leq 4) =0.85[/tex]
Each limit represents the derivative of some function f at some number a. State such an f and a in each case.
lim √9 + h - 3 / h
h-->0
Answer:
a = 0f(h) = [tex]\frac{\sqrt{9+h} - 3}{h}[/tex]limit of the function is 1/6Step-by-step explanation:
The general form representing limit of a function is expressed as shown below;
[tex]\lim_{h \to a} f(h)[/tex] where a is the value that h will take and use in the function f(h). It can be expressed in words as limit of function f as h tends to a. Comparing the genaral form of the limit to the limit given in question [tex]\lim_{h \to 0} \frac{\sqrt{9+h} - 3}{h}[/tex], it can be seen that a = 0 and f(h) = [tex]\frac{\sqrt{9+h} - 3}{h}[/tex]
Taking the limit of the function
[tex]\lim_{h \to 0} \frac{\sqrt{9+h} -3}{h}\\= \frac{\sqrt{9+0}-3 }{0}\\= \frac{0}{0}(indeterminate)[/tex]
Applying l'hopital rule
[tex]\lim_{h \to 0} \frac{\frac{d}{dh} (\sqrt{9+h} - 3)} {\frac{d}{dh} (h)}\\= \lim_{h \to 0} \frac{1}{2} (9+h)^{-1/2} /1\\=\frac{1}{2} (9+0)^{-1/2}\\= \frac{1}{2} * \frac{1}{\sqrt{9} } \\= 1/2 * 1/3\\= 1/6[/tex]
You have $150 to spend at a store. If you shoes cost $30 and belts cost $25, write an equation that represents the different ways that you could spend a total of $150
Answer:
you could buy a pair of shoes and a belt still have 95 dollars to spend
8 cm
10 cm
The surface area of the above figure is
A. 816.8 cm2
B. 879.6 cm2
C. 565.5 cm2
D. 1131.0 cm
Hi there u have not given us the figure please correct the answer and I will send my answer.Is it a cylinder cuboid cube or?
Example and Answer Please.Giving Brain
Answer:
The ones you got wrong, have to have a negative sign...
Step-by-step explanation:
Brainliest here
What’s the correct answer for this question?
Answer:
Step-by-step explanation:
the event of drawing a spade card
The pool at the apartment building is 30 feet long, 20 feet wide, and 5 feet deep. It has been fikked 4 feet deep. How many more cubic feet of water are needed to finish filling the pool?
Answer:
600 cubic feet of water
Step-by-step explanation:
If the pool is filled 4 feet and the pool is 5 feet deep, that leaves 1 foot of depth left to fill. This makes the volume equation 30 x 20 x 1 which equals 600.
Assume that in a statistics class the probability of receiving a grade of A equals .30 and the probability of receiving a grade of B equals .30. The probability that a randomly selected student from this class will receive either an A or a B equals.
a. .09
b. .6
c. .9
d. .3
Answer:
Answer D is correct
(Please hurry)
Explain how to find the value of x
Answer:
96
Step-by-step explanation:
Exterior angles add up to 360
360 - 134-130 = 96
x = 96
Isaac is organizing a 5-kilometer road race. The safety committee
recommends having a volunteer every 1 of a kilometer and at
the finish.
| Are 10 volunteers enough?
Answer:
10 volunteers are more than recommendedStep-by-step explanation:
The recommended number of volunteers is five (5)
Since the the distance of the race is 5km,
and the safety committees recommends 1 volunteer per kilometre.
Hence ten (10) volunteers is more than enough
Which expression can be used to find 45% of 54?
Answer:
54 · 0.45
Step-by-step explanation:
This expression will give you 45% of 54, since 54 will be multiplied by the decimal equivalent to 45%
Answer:
0.45 · 54
Step-by-step explanation:
In math, 45% is equal to 0.45, because percents are out of a hundre. ’of’ is just another way of putting a multiplicative sign, so it would be 0.45 · 54
Write down the 1st term in the sequence given by:t(n) =n^2+4
Answer:
5
Step-by-step explanation:
t(1) = [tex]1^{2} + 4 = 5[/tex]
I need help asaap!!!!
Answer:
Answer choice 3
Step-by-step explanation:
Option 3 is correct one
∠TQS ≅ ∠RSQ
⇒ ΔTQS ≅ ΔRSQ
⇒ QR≅ST and QT≅RS
QRST is parallelogram by definition
Answer:
Option 3
Step-by-step explanation:
Angle TQS is congruent to angle RSQ and can be proved by alternating interior angle theorem.
Triangle TQS is congruent to triangle RSQ.
Line QR is congruent to line ST.
Line QT is congruent to line RS.
In the theory of learning, the rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized. Assume that the rate at which material is forgotten is proportional to the amount memorized. Suppose M denotes the total amount of a subject to be memorized and A(t) is the amount memorized in time t > 0. Determine a differential equation for the amount A(t) when forgetfulness is taken into account. (Assume the constants of proportionality for the rate at which material is memorized and the rate at which material is forgotten are k1 > 0 and k2 > 0, respectively. Use A for A(t).)
dA/dt =
Answer:
dA/dt = k1(M-A) - k2(A)
Step-by-step explanation:
If M denote the total amount of the subject and A is the amount memorized, the amount that is left to be memorized is (M-A)
Then, we can write the sentence "the rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized" as:
Rate Memorized = k1(M-A)
Where k1 is the constant of proportionality for the rate at which material is memorized.
At the same way, we can write the sentence: "the rate at which material is forgotten is proportional to the amount memorized" as:
Rate forgotten = k2(A)
Where k2 is the constant of proportionality for the rate at which material is forgotten.
Finally, the differential equation for the amount A(t) is equal to:
dA/dt = Rate Memorized - Rate Forgotten
dA/dt = k1(M-A) - k2(A)
8. 3/4 is expressed as a percentage is
Answer:
75%
Step-by-step explanation:
Divide 3 by 4 to get 0.75. Round to 75%.
Answer:
75%
Step-by-step explanation:
Divide 3 by 4 to get 0.75 and multiply by 100 to convert from a decimal to a percentage. The answer will be 75%.
Hope this helps!!! PLZ MARK BRAINLIEST!!!
6 x 6 x 6 x 6 x 6 x 6 x 6= 6^x
Answer:
[tex] 6^7 [/tex]
Step-by-step explanation:
[tex]6 \times 6 \times 6 \times 6 \times 6 \times 6 \times 6 = 6^7 \\ [/tex]
Hey there!
6 * 6 * 6 * 6 * 6 * 6 * 6 ➡️ 6^7
= 36 * 36 * 36 * 6
= 1,296 * 36 * 6
= 46,656 * 6
= 279,936
Therefore, your answer is: 6^7
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
The table shows the heights of the winners and runners-up of 8
presidential elections. Find the line of regression that predicts the
runner-up's height given the winner's height. Determine if the
regression line is a good predictor of heights for the winners and
runner-ups of presidential elections.
Winner
69.5
73
73
74
74.5
74.5
71
71
Runner-Up
72
69.5
70
68
74
74
73
76
Answer:
The table shows the heights of the winners and runner-ups of 8 presidential elections. Find the line of regression that predicts the runner-up's height given the winner's height. Determine if the regression line is a good predictor of heights for the winners and runner-ups of presidential elections.
Winner: 69.5; 73; 73; 74; 74.5; 74.5; 71; 71
Runner-Up: 72; 69.5; 70; 68; 74; 74; 73; 76
a. y = 95.4 - 0.321x; no, because the r-value is low.***
b. y = -0.321 + 95.4x; no, because the r-value is low.
The regression line is NOT a good predictor of heights for the winners and runner-ups of presidential elections because the r-value is low
Calculations and Parameters:Given that:
The data given for the winners are:
69.5; 73; 73; 74; 74.5; 74.5; 71; 71
The runners up are:
72; 69.5; 70; 68; 74; 74; 73; 76
With this, we can see that a. y = 95.4 - 0.321x; no, because the r-value is low.
Read more about lines of regression here:
https://brainly.com/question/25987747
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Zed went to the store and bought a bag of chips. He estimated there would 1 point
be 350 chips in the package, but realized there were only 210 chips in that
package. What was his percent error?'
Answer:
66.67%
Step-by-step explanation:
They do not say that I estimate a value of 350 chips but in reality there were 210 chips in total, we have that the error formula is:
Percentage error (%) = (estimated value - actual value) / actual value × 100 (in absolute value)
replacing:
Percentage error (%) = | 350 - 210 | / 210 × 100
Percentage error (%) = 140/210 * 100
Percentage error (%) = 66.67
Which means that the percentage error is 66.67%
Please help! Correct answer only, please! Which of the following is one of the cheapest routes to pass through each vertex once starting and ending with Vertex "A" and using the Nearest Neighbor Algorithm. A. ABDCA, $890 B. ACDBA, $900 C. ABCDA, $960 D. None of the Above
Answer: c) ABCDA, $960
Step-by-step explanation:
The nearest Neighbor Algorithm states to choose the next vertex based only on the weights of the neighbor of that vertex.
Starting at A: Options are B = 220, C = 240, D = 310
Choose B because it has the smallest value.
From B: Options are C = 200, D = 210
Choose C because it has the smallest value.
From C: There is only one option --> D = 230 (we cannot choose A because it was our starting point and we haven't touched every vertex, yet).
From D: We touched all of the vertices so return to the starting point, A = 310
A → B → C → D → A --> 220 + 200 + 230 + 310 = 960
Notice that if we looked at the entire circuit first, this is NOT the optimum path. But this is the result using the Nearest Neighbor Algorithm.
In a 30 degree, 60 degree, 90 degree triangle shortest side is 9. Find the lengths of the other sides
Answer:
To find the second-shortest side we'll multiply 9 by √3 which is 9√3 and for the hypotenuse we'll do 9 * 2 = 18.
A stuffed animal business has a total cost of production C=12x+30 and a revenue function R=20x. Find the break-even point and express it as an ordered pair in the form (x,y).
Answer:
The break-even point is when x is equal to 3.75
Step-by-step explanation:
At the break-even point, total cost function is equal to the total revenue function. In that regard, break-even is when;
C = 12x + 30 is equal to R = 20x.
thus, 12x + 30 = 20x
then, 12x - 12x + 30 = 20x - 12x
therefore, 30 = 8x
then, 30/8 = 8x/8
finally, x = 15/4 or 3.75
A stuffed animal business has a total cost of production C=12x+30 and a revenue function R=20x, the Break even point is (3.75,75)
Given :
A stuffed animal business has a total cost of production C=12x+30 and a revenue function R=20x.
Break even point occurs when revenue = cost
R=C
Replace the expression and solve for x
[tex]R=C\\20x=12x+30\\20x-12x=30\\8x=30\\divide \; by \; 8\\x=\frac{15}{4}\\x=3.75[/tex]
Now we find out y using Revenue
[tex]R= 20x\\R=20(3.75)\\R=75[/tex]
So y is 75
Break even point is (3.75,75)
Learn more : brainly.com/question/15281855
The dean of the School of Fine Arts is trying to decide whether to purchase a copy machine to place in the lobby of the building. The machine would add to student convenience, but the dean feels compelled to earn an 10 percent return on the investment of funds. Estimates of cash inflows from copy machines that have been placed in other university buildings indicate that the copy machine would probably produce incremental cash inflows of approximately $14,000 per year. The machine is expected to have a three-year useful life with a zero salvage value. (Use appropriate factor(s) from the tables provided.)
Required:
Use Present Value PV of $1 to determine the maximum amount of cash the dean should be willing to pay for a copy machine. (Round intermediate calculations and final answer to 2 decimal places.)
Answer:
$34,816.60
Step-by-step explanation:
The computation of the maximum amount of cash should willing to pay for the copy machine by using the present value is shown below:
Present value is
[tex]= Incremental\ cash\ flows \times PVIFA\ factor[/tex]
where,
Incremental cash flows is $14,000 per year
Discount rate is 10%
And, the number of years is three years
PVIFA factor for 10% at 3 years is 2.4869
Refer to the PVIFA factor table
Now placing these values to the above formula
So, the present value is
[tex]= \$14,000 \times 2.4869[/tex]
= $34,816.60
The graph of an absolute value function has a
vertex at (-2,3) and passes through the point (-1,
0). Using transformations of the parent function,
has the graph been dilated by a scale factor other
than 1? Explain
Answer:
Yes. The graph of the parent function has been dilated by a scale factor other than 1.
Step-by-step explanation:
Let the parent function of the absolute value function is,
f(x) = |x|
This function passes through (0, 0) and slope = 1 or -1.
After transformation vertex (0, 0) becomes (-2, 3) and a point through which this function passes through is (-1, 0)
Slope of the function = [tex]\frac{3-0}{-2+1}[/tex]
= -3
Since slope of the transformed function is less than the parent function. (-3 < -1)
Therefore, parent function will be dilated by a scale factor other than 1.
Answer:
edge answer
Step-by-step explanation:
Yes, the graph has been dilated.
Using the standard form of the equation, substitute in the values: h = –2, k = 3, x = –1, and y = 0.
Solve the equation to get a = –3.
Graphically, the parent function follows the pattern of right 1, up 1. Moving 1 unit to the right from the vertex, you can move down 3 units to get to the point (–1, 0), so it has been horizontally compressed.
Simplify this equation x2-5x-36
Answer:
[tex]=\left(x+4\right)\left(x-9\right)[/tex]
Step-by-step explanation:
[tex]x^2-5x-36\\\mathrm{Break\:the\:expression\:into\:groups}\\=\left(x^2+4x\right)+\left(-9x-36\right)\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2+4x\mathrm{:\quad }x\left(x+4\right)\\\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9x-36\mathrm{:\quad }-9\left(x+4\right)\\=x\left(x+4\right)-9\left(x+4\right)\\\mathrm{Factor\:out\:common\:term\:}x+4\\=\left(x+4\right)\left(x-9\right)[/tex]
8x - 4 < - 12 or 8x + 7 >23 i need help to find answer
Answer:
x>4/3 and x<1
Step-by-step explanation:
8x-4 < -12
8x<-12+4
x<8/8
x<1
8x+7> 23
8x>23-7
x>12/8
simplify : x>4/3
The last part of question says find temperature at 11pm
Answer:
3 deg C
Step-by-step explanation:
Start with -8 deg and add 11 deg.
-8 + 11 = 3
Answer: 3 deg C
In a grinding operation, there is an upper specification of 3.150 in. on a dimension of a certain part after grinding. Suppose that the standard deviation of this normally distributed dimension for parts of this type ground to any particular mean dimension LaTeX: \mu\:is\:\sigma=.002 μ i s σ = .002 in. Suppose further that you desire to have no more than 3% of the parts fail to meet specifications. What is the maximum (minimum machining cost) LaTeX: \mu μ that can be used if this 3% requirement is to be met?
Answer:
Step-by-step explanation:
Let X denote the dimension of the part after grinding
X has normal distribution with standard deviation [tex]\sigma=0.002 in[/tex]
Let the mean of X be denoted by [tex]\mu[/tex]
there is an upper specification of 3.150 in. on a dimension of a certain part after grinding.
We desire to have no more than 3% of the parts fail to meet specifications.
We have to find the maximum [tex]\mu[/tex] such that can be used if this 3% requirement is to be meet
[tex]\Rightarrow P(\frac{X- \mu}{\sigma} <\frac{3.15- \mu}{\sigma} )\leq 0.03\\\\ \Rightarrow P(Z <\frac{3.15- \mu}{\sigma} )\leq 0.03\\\\ \Rightarrow P(Z <\frac{3.15- \mu}{0.002} )\leq 0.03[/tex]
We know from the Standard normal tables that
[tex]P(Z\leq -1.87)=0.0307\\\\P(Z\leq -1.88)=0.0300\\\\P(Z\leq -1.89)=0.0293[/tex]
So, the value of Z consistent with the required condition is approximately -1.88
Thus we have
[tex]\frac{3.15- \mu}{0.002} =-1.88\\\\\Rrightarrow \mu =1.88\times0.002+3.15\\\\=3.15[/tex]