the first liquid that comes out of a woman's breast after delivery is called?
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The mass of iron required by one mole or 187.5 g of copper nitrate is 234 g. Then the mass of Fe required by 4 g of copper nitrate is 5 g.

Copper nitrate is an ionic compound formed by donating electrons from metallic copper to the nitrate group. Copper nitrate easily undergoes displacement reactions.

The reaction of copper nitrate with iron is written below:

[tex]\rm Cu(NO_{3})_{2} + 4 Fe \rightarrow 2Fe_{2}(NO_{3})_{2} + Cu[/tex]

As per this reaction, one mole of copper nitrate requires 4 moles of Fe.

molar mass of Fe = 58.5

mass of 4 moles = 234 g

molar mass of copper nitrate = 187.5 g.

187.5 g of copper nitrate need 234 g of Fe. Hence, 4 g of Cu needs:

234 × 4 /187.5 = 5 g

Therefore, the mass of Fe requires is 5 g.

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Answer:

0.324 mole of sodium

Explanation:

From the question given above, the following data were obtained:

Volume of sodium = 7.25 L

Number of mole of sodium =..?

The number of mole of sodium that occupies 7.25 L can be obtained as follow:

22.4 L = 1 mole

Therefore,

7.25 L = 7.25 L × 1 mole / 22.4 L

7.25 L = 0.324 mole

Therefore, 0.324 mole of sodium is present in the container.

Answer:

See explanation and image attached

Explanation:

Fischer esterification is a type of reaction used  to convert carboxylic acids to ester in the presence of excess alcohol and a strong acid which acts as a catalyst. Another final product formed in the reaction is water.

The mechanism for the fischer esterification of Benzoic acid and  C H 3 O H in the presence of HCl as the catalyst is shown in the image attached to this answer.

The final products of the reaction are methyl benzoate, water and H^+ as shown in the image attached.

The methyl ester, water, and the acid catalyst (HCl) are byproducts of the Fischer esterification process, which involves protonation, nucleophilic attack, elimination, and deprotonation processes.

Carbonyl oxygen protonation: The carbonyl oxygen of the carboxylic acid (benzoic acid) is protonated by the acid catalyst (HCl) in the first step. The protonation of the carbonyl carbon increases its electrophilicity and promotes the alcohol's nucleophilic assault. Attack by the alcohol's nucleophilic oxygen (methanol, CH3OH) on the protonated carboxylic acid's carbonyl carbon results in the formation of a tetrahedral intermediate. The acid catalyst also helps with this phase. Elimination of water: In the following step, the water molecule must be removed from the tetrahedral intermediate. The hydroxyl group (-OH) from the carboxylic acid and a hydrogen from the hydroxyl group of the alcohol are removed to create this water molecule. Deprotonation: A deprotonation occurs after the removal of water.

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Answer:

Explanation:

The chemical reaction of the well-balanced equation is as follows:

[tex]\mathbf{2NiCl_{2(aq)}+2Na_2S_{(aq)} \to 4NaCl_{(aq)}+2NiS_{s}}[/tex]

The aforementioned reaction's ionic equation is:

[tex]\mathbf{2Ni^{2+}_{(aq)}+4Cl^-_{(aq)}+ 4Na^+_{(aq)}+2S^{2-}_{(aq)} \to 4Na^+_{(aq)}+4Cl^-_{(aq)}+2NiS_{(s)}}[/tex]

From above; Na⁺ and Cl⁻ appear on both sides;

Hence, the net ionic equation is:

[tex]\mathbf{2Ni^{2+}_{(aq)}+2S^{2-}_{(aq)} \to 2NiS_{(s)}}[/tex]

The strongest acid as per dissociation constant is hydrochloric acid.

Acids are defined as substances which on dissociation yield H+ ions , and these substances are sour in taste. Compounds such as  HCl, H₂SO₄ and HNO₃ are acids as they yield H+ ions on dissociation.

According to the number of H+ ions which are generated on dissociation acids are classified as mono-protic , di-protic ,tri-protic and polyprotic  acids  depending on the number of protons which are liberated on dissociation.

Acids are widely used in industries  for  production of fertilizers, detergents  batteries and dyes.They are used in chemical industries for production of chemical compounds like salts which are produced by neutralization reactions.Acids are also used in titrations.

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Answer:

0.1 mole of CH₄

Explanation:

From the question given above, the following data were obtained:

Volume of CH₄ = 2.24 L

Number of mole of CH₄ =?

The number of mole of CH₄ can be obtained as follow:

Recall:

1 mole of a gas occupy 22.4 L at stp. This implies that 1 mole of CH₄ occupies 22.4 L at stp.

22.4 L = 1 mole of CH₄

Therefore,

2.24 L = 2.24 × 1 mole of CH₄ / 22.4

2.24 L = 0.1 mole of CH₄.

A distillation column is a process unit in which a feed mixture is separated by multiple partial vaporizations.

It should be noted that distillation simply means a process that has to do with the conversion of liquid into vapor.

In this case, distillation column is a process unit in which a feed mixture is separated by multiple partial vaporizations.

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Answer:

0.278 mol

Explanation:

Step 1: Given and required data

Mass of acetic acid (m): 16.7 g

Chemical formula of acetic acid: CH₃COOH (C₂H₄O₂)

Step 2: Calculate the molar mass (M) of acetic acid

We will use the following expression.

M(C₂H₄O₂) = 2 × M(C) + 4 × M(H) + 2 × M(O)

M(C₂H₄O₂) = 2 × 12.01 g/mol + 4 × 1.01 g/mol + 2 × 16.00 g/mol = 60.06 g/mol

Step 3: Calculate the number of moles (n) of acetic acid

We will use the following expression.

n = m/M

n = 16.7 g/(60.06 g/mol) = 0.278 mol

Answer: The given transition metal ions in order of decreasing number of unpaired electrons are as follows.

[tex]Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}[/tex]

Explanation:

In atomic orbitals, the distribution of electrons of an atom is called electronic configuration.

The electronic configuration in terms of noble gases for the given elements are as follows.

[tex]Fe^{3+} - [Ar] 3d^{5}[/tex]

So, there is only 1 unpaired electron present in [tex]Fe^{3+}[/tex].

[tex]Mn^{4+} - [Ar]3d^{3}[/tex]

So, there are only 3 unpaired electrons present in [tex]Mn^{4+}[/tex].

[tex]V^{3+} - [Ar] 3d^{2}[/tex]

So, there are only 2 unpaired electrons present in [tex]V^{3+}[/tex].

[tex]Ni^{2+} - [Ar] 3d^{8}[/tex]

So, there will be 2 unpaired electrons present in [tex]Ni^{2+}[/tex].

[tex]Cu^{+} - [Ar] 3d^{10}[/tex]

So, there is no unpaired electron present in [tex]Cu^{+}[/tex].

Therefore, given transition metal ions in order of decreasing number of unpaired electrons are as follows.

[tex]Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}[/tex]

Thus, we can conclude that given transition metal ions in order of decreasing number of unpaired electrons are as follows.

[tex]Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}[/tex]

Given the data from the question,

A. The number of mole of water needed for the reaction is 1 mole

Bi. The number of mole of C₂H₂ formed is 0.5 mole

Bii. The number of mole of Ca(OH)₂ formed is 0.5 mole

Mole = mass / molar mass

Mole of CaC₂ = 32 / 64

Mole of CaC₂ = 0.5 mole

Balanced equation

CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂

From the balanced equation above,

1 mole of CaC₂ required 2 moles of H₂O

Therefore,

0.5 mole of CaC₂ will require = 0.5 × 2 = 1 mole of H₂O

Thus, 1 mole of H₂O is needed for the reaction.

Balanced equation

CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂

From the balanced equation above,

1 mole of CaC₂ reacted to produce 1 mole of C₂H₂

Therefore,

0.5 mole of CaC₂ will also react to produce 0.5 mole of C₂H₂

Thus, 0.5 mole of C₂H₂ was obtained from the reaction

Balanced equation

CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂

From the balanced equation above,

1 mole of CaC₂ reacted to produce 1 mole of Ca(OH)₂

Therefore,

0.5 mole of CaC₂ will also react to produce 0.5 mole of Ca(OH)₂

Thus, 0.5 mole of Ca(OH)₂ was obtained from the reaction

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Answer: It attracts other water molecules  is a property of water.

Explanation:

A property of a substance where its molecules stick to each other is called cohesion.

For example, water molecules attracts each other because water has the property of cohesion.

Whereas water has high heat capacity.

Water can exist in solid, liquid or vapor form.

Thus, we can conclude that it attracts other water molecules  is a property of water.

Answer

above answer is correct

Explanation:

Answer:

It must be negative, for the reaction to be feasible.

explanation:

Answer:

1.64 g/mL

Explanation:

Step 1: Calculate the mass of the solid

m(solid+flask) = m(solid) + m(flask)

m(solid) = m(solid+flask) - m(flask)

m(solid) = 48.8565 g - 35.9325 g = 12.9240 g

Step 2: Calculate the mass of water

m(solid+flask+water) = m(solid+flask) + m(water)

m(water) = m(solid+flask+water) - m(solid+flask)

m(water) = 140.8321 g - 48.8565 g = 91.9756 g

Step 3: Calculate the volume occupied by 91.9756 g of water

The density of water is 0.998203 g/mL.

91.9756 g × 1 mL/0.998203 g = 92.1412 mL

Step 4: Calculate the volume occupied by the solid

The 100.00 mL are occupied by the solid and the water.

100.00 mL = V(solid) + V(water

V(solid) = 100.00 mL - V(water)

V(solid) = 100.00 mL - 92.1412 mL = 7.86 mL

Step 5: Calculate the density of the solid

12.9240 g of the solid occupy 7.86 mL.

ρ = 12.9240 g/7.86 mL = 1.64 g/mL

Answer:

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

Explanation:

The activity series helps us to easily define whether or not a reaction will occur.

Elements at the top of the activity series are highly reactive and will always displace those at the bottom of the series in any reaction.

With the above information in mind, let us answer the questions given above.

Ag + NaNO₃ —> Na + AgNO₃

The above reaction will not occur because Na is higher than Ag in the activity series. Thus, Ag cannot displace Na from solution.

Pb + Mg(NO₃)₂ —> Pb(NO₃)₂ + Mg

The above reaction will not occur because Mg is higher than Pb in the activity series. Thus, Pb cannot displace Mg from solution.

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

The above reaction will occur because Mg is higher than Fe in the activity series. Thus, Mg will displace Fe from solution.

Cu + Mg(NO₃)₂ —> Cu(NO₃)₂ + Mg

The above reaction will not occur because Mg is higher than Cu in the activity series. Thus, Cu cannot displace Mg from solution.

From the above illustration, only

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

Will occur.

Answer:

[tex]Y=63.1\%[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reaction:

[tex]4C_2H_3Cl + 7O_2 \rightarrow 8CO + 6H_2O + 2Cl_2[/tex]

It turns out possible for us to realize about the 7:8 mole ratio of O2 to CO, and therefore, the theoretical yield of the latter is calculated via stoichiometry:

[tex]m_{CO}=57.8gO_2*\frac{1molO_2}{32.0gO_2}*\frac{8molCO}{7molO_2} *\frac{28.01gCO}{1molCO} =57.82gCO[/tex]

Finally, the percent yield is calculated by dividing the actual yield, 36.5 g by the just computed theoretical one:

[tex]Y=\frac{36.5g}{57.8g} *100\%\\\\Y=63.1\%[/tex]

Regards!

there is an absence of presence of variables:(

Answer:

I HOPE THIS HELPS

Explanation:

Answer: Hello, please, the question is not complete. Attached is the complete question.

Answer:

1. Their bond strength

2. Their acidic strength

3. the size of their central atom

Explanation:

CH4 and Si4 compounds belong to the same molecular geometry and group and they do have the same bond angle and they do not contain lone pair and they have no repulsion. we can conclude that they are from the carbon family.

NH3 and PH3 have the same molecular geometry  an bond angle which we can say they are 3 bond and 1 lone pair. they are from the nitrogen family and lone pair.

NOTE: Bond angle shows that first atomically is f second period and PH3 is from third period (This is the Drego rule)  

HF and HCL have the same molecular geometry and bond angle.

The question is incomplete, the complete question is:

A certain substance X has a normal freezing point of [tex]-6.4^oC[/tex] and a molal freezing point depression constant [tex]K_f=3.96^oC.kg/mol[/tex]. A solution is prepared by dissolving some glycine in 950. g of X. This solution freezes at [tex]-13.6^oC[/tex] . Calculate the mass of urea that was dissolved. Round your answer to 2 significant digits.

Answer: The mass of glycine that can be dissolved is [tex]1.3\times 10^2g[/tex]

Explanation:

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

[tex]\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m[/tex]

OR

[tex]\text{Freezing point of pure solvent}=\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}[/tex]           ......(1)

where,

Freezing point of pure solvent = [tex]-6.4^oC[/tex]

Freezing point of solution = [tex]-13.6^oC[/tex]

i = Vant Hoff factor = 1 (for non-electrolytes)

[tex]K_f[/tex] = freezing point depression constant = [tex]3.96^oC/m[/tex]

[tex]m_{solute}[/tex] = Given mass of solute (glycine) = ?

[tex]M_{solute}[/tex] = Molar mass of solute (glycine) = 75.07 g/mol

[tex]w_{solvent}[/tex] = Mass of solvent = 950. g

Putting values in equation 1, we get:

[tex]-6.4-(-13.6)=1\times 3.96\times \frac{m_{solute}\times 1000}{75.07\times 950}\\\\m_{solute}=\frac{7.2\times 75.07\times 950}{1\times 3.96\times 1000}\\\\m_{solute}=129.66g=1.3\times 10^2g[/tex]

Hence, the mass of glycine that can be dissolved is [tex]1.3\times 10^2g[/tex]

The balanced reaction equation is;  2KI(aq)+BaS(aq)→ K2S(aq) + BaI2(aq)

A chemical equation shows the conversion of reactants into products. Recall that in a chemical reactions, reactans interact with each other to yield products.

For the reaction we have in the question,the complete reaction equation is; 2KI(aq)+BaS(aq)→ K2S(aq) + BaI2(aq)

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The reaction between hydrogen ion and hydroxide ion will be as follows.

so, ratio between hydrogen and hydroxide ions is 1 : 1.

Therefore, moles of  = volume × concentration of

                            =

                             = 0.06 mol

Similarly, moles of  = volume × concentration of

                              =

                             = 0.1 mol

Therefore, ratio of moles of hydrogen and hydroxide ions is as follows.

                                    0.06 : 0.1

                                 = 0.6 : 1

As, hydroxide ions are present in excess so, hydrogen ions are the limiting reagent.

Hence, moles of water formed = moles of  ions = 0.06 mol.

So,    heat released = moles of

                               = 0.062 × 62.0 kJ/mol

                               = 3.72 kJ

                               = 3.72 × 1000 J

                               = 3720 J

Let T is the initial temperature. So,

             Heat released = Heat absorbed by the solution

                                      =

           3720 J =

                         T =

Thus, we can conclude that initial temperature is .                          

Answer:

Inertia

Explanation:

According to Galileo, the motion of a projectile can be described according to two principles.

Firstly, he argued that when the projectile is fired, it moves in straight line until it looses its impetus and falls to the ground.

The horizontal motion of the projectile is explained by the theory of inertia. According to Galileo, the two independent motions of the projectile all together leads to a mathematical curve which completely describes the motion of a projectile.

Answer:

n = 3.1 moles

Explanation:

Given that,

The volume of a balloon, V = 5.1 L

Pressure, P = 1.1 atm

Temperature, T = 22 K

We need to find the number of moles are required to fill the balloon. We know that,

Gas law, PV = nRT

Where

R is gas constant, R = 0.08206 L-atm/mol-K

So,

[tex]n=\dfrac{PV}{RT}\\\\n=\dfrac{1.1\times 5.1}{0.08206 \times 22}\\\\n=3.1[/tex]

So, there are 3.1 moles of helium are required.

The moles of helium are required to fill a 5.10 L ballon to a pressure of 1.1 atm at 22 Kelvin is 3.1 moles.

Moles of gases will be calculated by using the ideal gas equation as:

PV = nRT, where

P = pressure of gas = 1.1 atm

V = volume of gas = 5.10 L

R = universal gas constant = 0.08206 L-atm/mol-K

T = temperature of gas = 22K

n = moles of gas?

On putting all these values in the above equation and calculate for the value of n as:
n = 1.1 × 5.10 / 0.082 × 22 = 3.1 moles

Hence, the required moles is 3.1 moles.

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Answer:

See explanation

Explanation:

We must remember that the energy required to move an electron from the 1s orbital to a higher energy level depends on the size of the nuclear charge.

The higher the nuclear charge, the more closely held the 1s electron of the atom is to the nucleus and the more difficult it is to excite this electron.

Hence, it requires more energy to excite the 1s electron of silver having a larger size of nuclear charge than it is to excite a 1s electron in lithium.

Answer:

Carbon dioxide.

Explanation:

Hope this will help

Answer:

6.0 mol LiNO₃

Explanation:

First we need to determine which reactant is the limiting reactant:

We calculate with how many Ca(NO₃)₂ moles would 3.0 moles of Li₃PO₄ react, using the stoichiometric coefficients of the reaction:

There are not as many Ca(NO₃)₂ moles, so Ca(NO₃)₂ is the limiting reactant.

Using the number of moles of the limiting reactant, we calculate how many moles of LiNO₃ would be formed:

Answer:

A

Explanation:

A P E X