Answer:
625πmm³
Step-by-step explanation:
The exact volume of the figure will be the sum total of volume of the two comes and one cylinder.
Volume of a cone = 1/3πr²h
r is the radius of the cone
h is the height of the cone
Since the cone are 15mm high, their individual height = 15mm
Diameter = 10mm, radius = 5mm
Volume of a cone = 1/3× π × 5²×15
Volume of a cone = 1/3 × π × 25 × 15
Volume of a cone = 125πmm³
Volume of both cones = 2(125π) = 250πmm³
Volume of a cylinder = πr²h
Height of the cylinder = 15mm
Radius of the cylinder = 5mm
Volume of the cylinder = π(5)²×15
Volume of the cylinder = 375πmm³
Volume of the composite solid = volume of the two cones + volume of cylinder.
= 250πmm³+375πmm³
= 625πmm³
Answer: 625pimm^3
Step-by-step explanation:
Use the inverse trigonometric keys on a calc to find the measure of Angle A.
Step-by-step explanation:
θ = [tex]cos^{-1}[/tex] 17 m/27 m = 50.9°
PLZZZ HELP MEEE!!!!!!!!!!
Answer:
Step-by-step explanation:
Graph shown in the attachment,
- Since every value of x corresponds to a distinct value of y, so the graph represents a function.
- Every input value of x of the table has a output value of y, therefore, it's a function.
- In the set of ordered pairs (5, 8) and (5, 2), input value x = 5 has two output values for y,
y = 8 and y = 2
Therefore, it's not a function and (5, 8) should be changed to make the relation a function.
Which graph matches the equation y+3=2(x+3)?
Answer:
The leftmost graph [with the points (-3,-3) and (0,3)]
Step-by-step explanation:
y+3=2(x+3)
y+3=2x+6
y=2x+3
The y-intercept is 3, meaning that the line passes through the point (0,3), and it's slope is 2, so it travels 2 units up and 1 unit over. Thus the correct graph is the top left graph, with the two points (-3,-3) and (0,3).
The graph is considered as the creation of a diagram that depicts a relationship connecting two or more items, and further discussion can be defined as follows:
Given:
[tex]\bold{y+3=2(x+3)}[/tex]
To find:
graph=?
Solution:
[tex]\bold{y+3=2(x+3)}[/tex]
Solving the given equation:
[tex]\to \bold{y+3=2(x+3)}\\\\\to \bold{y+3=2x+6}\\\\\to \bold{y=2x+6-3}\\\\\to \bold{y=2x+3}\\\\[/tex]
In this, the y-intercept is 3, indicating that the line crosses through the point (0,3), and the slope is 2, showing that it moves 2 units up and 1 unit over. And as a result, the proper graph is the upper left graph, with two points [tex]\bold{(-3,-3)\ and\ (0,3)}[/tex].Please find the graph in the attached file.
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can someone do this ???
I really need help asap please :( anyone know the answer ?
Answer:
see below
Step-by-step explanation:
x = kendalls money
98 = 7x
Divide each side by 7
98/7 = 7x/7
14=x
Kendall had 14 dollars
Answer:
D
Step-by-step explanation:
94 divided by 7 = 14 also
7x (x is 14) = 94
∠MNQ and ∠PNR are vertical angles. What is the value of x?
Answer:
Step-by-step explanation:
I don’t know the answer
The value of x such that ∠MNQ and ∠PNR are vertical angles is 40
How to determine the value of x?The given parameters are:
MNQ = 3x - 6
PNR = 114
Vertical angles are equal.
So, we have:
3x - 6 = 114
Add 6 to both sides
3x = 120
Divide both sides by 3
x = 40
Hence, the value of x is 40
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what is 1/3 of 48 in numbers
Answer:
16
Step-by-step explanation:
Multiply it by 1/3 and it equals 16
Answer:
16
Step-by-step explanation:
48/3=16
help please writer the answer as letters
Answer:
B, D, D
Step-by-step explanation:
the correct answer for A is choice B. answer choice C is correct for question B.
Step-by-step explanation:
answer choice D is correct for C.
If A(4 -6) B(3 -2) and C (5 2) are the vertices of a triangle ABC fine the length of the median AD from A to BC. Also verify that area of triangle ABD = Area of triangle ACD
Answer:
a) The median AD from A to BC has a length of 6.
b) Areas of triangles ABD and ACD are the same.
Step-by-step explanation:
a) A median is a line that begin in a vertix and end at a midpoint of a side opposite to vertix. As first step the location of the point is determined:
[tex]D (x,y) = \left(\frac{x_{B}+x_{C}}{2},\frac{y_{B}+y_{C}}{2} \right)[/tex]
[tex]D(x,y) = \left(\frac{3 + 5}{2},\frac{-2 + 2}{2} \right)[/tex]
[tex]D(x,y) = (4,0)[/tex]
The length of the median AD is calculated by the Pythagorean Theorem:
[tex]AD = \sqrt{(x_{D}-x_{A})^{2}+ (y_{D}-y_{A})^{2}}[/tex]
[tex]AD = \sqrt{(4-4)^{2}+[0-(-6)]^{2}}[/tex]
[tex]AD = 6[/tex]
The median AD from A to BC has a length of 6.
b) In order to compare both areas, all lengths must be found with the help of Pythagorean Theorem:
[tex]AB = \sqrt{(x_{B}-x_{A})^{2}+ (y_{B}-y_{A})^{2}}[/tex]
[tex]AB = \sqrt{(3-4)^{2}+[-2-(-6)]^{2}}[/tex]
[tex]AB \approx 4.123[/tex]
[tex]AC = \sqrt{(x_{C}-x_{A})^{2}+ (y_{C}-y_{A})^{2}}[/tex]
[tex]AC = \sqrt{(5-4)^{2}+[2-(-6)]^{2}}[/tex]
[tex]AC \approx 4.123[/tex]
[tex]BC = \sqrt{(x_{C}-x_{B})^{2}+ (y_{C}-y_{B})^{2}}[/tex]
[tex]BC = \sqrt{(5-3)^{2}+[2-(-2)]^{2}}[/tex]
[tex]BC \approx 4.472[/tex]
[tex]BD = CD = \frac{1}{2}\cdot BC[/tex] (by the definition of median)
[tex]BD = CD = \frac{1}{2} \cdot (4.472)[/tex]
[tex]BD = CD = 2.236[/tex]
[tex]AD = 6[/tex]
The area of any triangle can be calculated in terms of their side length. Now, equations to determine the areas of triangles ABD and ACD are described below:
[tex]A_{ABD} = \sqrt{s_{ABD}\cdot (s_{ABD}-AB)\cdot (s_{ABD}-BD)\cdot (s_{ABD}-AD)}[/tex], where [tex]s_{ABD} = \frac{AB+BD+AD}{2}[/tex]
[tex]A_{ACD} = \sqrt{s_{ACD}\cdot (s_{ACD}-AC)\cdot (s_{ACD}-CD)\cdot (s_{ACD}-AD)}[/tex], where [tex]s_{ACD} = \frac{AC+CD+AD}{2}[/tex]
Finally,
[tex]s_{ABD} = \frac{4.123+2.236+6}{2}[/tex]
[tex]s_{ABD} = 6.180[/tex]
[tex]A_{ABD} = \sqrt{(6.180)\cdot (6.180-4.123)\cdot (6.180-2.236)\cdot (6.180-6)}[/tex]
[tex]A_{ABD} \approx 3.004[/tex]
[tex]s_{ACD} = \frac{4.123+2.236+6}{2}[/tex]
[tex]s_{ACD} = 6.180[/tex]
[tex]A_{ACD} = \sqrt{(6.180)\cdot (6.180-4.123)\cdot (6.180-2.236)\cdot (6.180-6)}[/tex]
[tex]A_{ACD} \approx 3.004[/tex]
Therefore, areas of triangles ABD and ACD are the same.
The distance it takes a truck to stop can be modeled by the function Image description d = stopping distance in feet v = initial velocity in miles per hour f = a constant related to friction When the truck's initial velocity on dry pavement is 40 mph, its stopping distance is 138 ft. Determine the value of f, rounded to the nearest hundredth.
Answer: 0.39
Step-by-step explanation:
We are required to determine the the value of f, rounded to the nearest hundredth
The value of f, rounded to the nearest hundredth is 0.39
Given function:
[tex]d(v) = \frac{2.15 {v}^{2} }{64.4f} [/tex]
Where,
d = stopping distance in feet
v = initial velocity in miles per hour
f = a constant related to friction
When
v = 40 mph
d = 138 ft
f = ?
[tex]d(v) = \frac{2.15 {v}^{2} }{64.4f} [/tex]
[tex]138= \frac{2.15 {(40)}^{2} }{64.4f} [/tex]
138(64.4f) = 2.15(1600)
8,887.2f = 3440
f = 3440 / 8,887.2
f = 0.3870735439733
Approximately to the nearest hundredth f = 0.39
Therefore, the value of f, rounded to the nearest hundredth is 0.39
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Which of them do I turn into a decimal, a fraction, or a mixed number?.
Tyler just lit a new candle and then let it burn all the way down to nothing. The initial length of the candle was 15 inches and the candle burned at a rate of 1.25 inches per hour. Write an equation for L,L, in terms of t,t, representing the length of the candle remaining unburned, in inches, tt hours after the candle was lit.
Answer:
15 in - (1.25 in/hr)t
Step-by-step explanation:
L(t) is a function of time, t: L(t) = 15 in - (1.25 in/hr)t
Note that when the candle has burned down to nothing, L(t) = 0. How long does that take? Set 15 in - (1.25 in/hr)t equal to zero and solve for t:
(1.25 in/hr)t = 15 in, or
15 in
t = ---------------- = 12 hrs
1.25 in/hr
z is equal to ____ units. Side RS measures _____ units long
Answer:
the answer is
z is equal to 12 units. Side RS measures 9 units longs
Step-by-step explanation:
The probability that a biased coin will land on Heads is 0.43
Azmol is going to throw the coin 600 times.
Work out an estimate for the number of times the coin will land on Tails.
Answer:
[tex]342[/tex]
Step-by-step explanation:
The probability of heads landing is 0.43.
The probability of tails landing is 1-0.43=0.57.
Azmol throws the coin 600 times, so:
[tex]600 \times 0.57[/tex]
[tex]=342[/tex]
Let $\overline{XY}$ be a tangent to a circle, and let $\overline{XBA}$ be a secant of the circle, as shown below. If $AX = 15$ and $XY = 9$, then what is $AB$?
Answer:
AB=5.4 units
Step-by-step explanation:
We using the theorem of intersecting tangent and secant to solve this.
By this theorem:
[tex]XY^2=XB \times AX\\9^2=15(15-XB)\\81=225-15XB\\15XB=144\\XB=9.6\\$Therefore:\\AB=AX-XB\\AB=15-9.6\\AB=5.4$ units[/tex]
Answer:
Its 9.6, the other guy got it wrong, he already got it but accidentally added a step. Its 9.6 :)
Step-by-step explanation:
trust me :).
Someone answer this :)
Answer:
x=29.9 degrees
Step-by-step explanation:
Sides we are given: x and side length of 92.
Angle we are given: angle of measure 18.
Relative to the angle we are given, we have the opposite and adjacent sides, so we use TOA, as O is opposite and A is adjacent.
Tangent 18= x/92
Tangent 18 (92)=x
x=29.9 degrees
Answer:
29.9 to one decimal place
Step-by-step explanation:
To work out X you can find the missing angle by doing;
[tex]180 - (90 + 18) = 72[/tex]
Then use Sine rule to work out X;
[tex]x = \frac{92}{ \sin(72)} \times \sin(18) \\ x = 29.89261.....[/tex]
These box plots show the basketball scores for two teams.
Bulldogs
55
70
80
90
105
Tigers
55 60 65
85
110
Basketball scores
Which statement is the most appropriate comparison of the spreads?
O A. The range for the Bulldogs, 20, is less than the range for the
Tigers, 25.
O B. The median for the Bulldogs, 80, is more than the median for the
Tigers, 65.
O C. The interquartile range (IQR) for the Bulldogs, 20, is less than the
IQR for the Tigers, 25.
D. The interquartile ranges (IQRs) for the Bulldogs and Tigers are
both 55.
Answer:
C. The interquartile range (IQR) for the Bulldogs, 20, is less than the
IQR for the Tigers, 25.
Step-by-step explanation:
When describing the spread of a given data set in a box plot using the five-number summary, the measure that is of utmost important is the range or the interquartile range.
The range is the difference between the max and the min.
The interquartile range is the difference between Q3 and Q1.
Therefore, considering the options given:
=>Option A is incorrect because the range for bull dog is 50 (105 - 55), while the range for Tigers is 55 (110 - 55).
=>Median cannot be used for describing spread, so option B is not the most appropriate comparison of the spreads.
=>Option C is correct and the most appropriate because the interquartile range of bulldogs is 20 (90 - 70), which is less than the IQR of Tigers which is 25 (85 - 60).
=>Option D is incorrect.
Answer:
C
Step-by-step explanation:
Here is a list of what you need to make 20 buns:
180g of butter, 150g of flour, 200g of sugar and 4 eggs. Work out what you need to make 30 buns.
Answer: 270g of butter
225g of flour
300g of sugar
6 eggs
Step-by-step explanation:
You get dressed in the morning without looking at the colours of the clothes you choose. Your shirts are white or blue, your pants are black, red, or yellow, and your shoes are brown or black. How likely are you to choose a white shirt, black pants, and brown shoes?
Answer:
add up all the colors
Step-by-step explanation:
Solve.
5 3
+
8 4
-2 5
3 6
11
-216
12
Answer:
[tex]-\frac{11}{12}[/tex]
Step-by-step explanation:
[tex]\frac{\frac{5}{8}+\frac{3}{4}}{-\frac{2}{3}-\frac{5}{6}}[/tex]
Working on the denominator,
[tex]-\frac{4}{6}-\frac{5}{6}=\frac{-9}{6}=-\frac{3}{2}[/tex]
[tex]\frac{\frac{5}{8}+\frac{3}{4}}{-\frac{3}{2}}[/tex]
Working on the numerator,
[tex]\frac{5}{8}+\frac{3}{4}=\quad \frac{11}{8}[/tex]
[tex]\frac{\frac{11}{8}}{-\frac{3}{2}}[/tex]
[tex]-\frac{11\cdot \:2}{8\cdot \:3}=-\frac{22}{24}=-\frac{11}{12}[/tex]
Vicente has a prism- like water tank whose base area is 1.2 square meters. He bought 6 goldfish at the store and the store owner told him to make sure their density in the tank isn’t more than 4 fish per cubic meter. What is the lowest possible height so the fish aren’t too crowded
Answer: 1.25 m
Step-by-step explanation:
Area of base = 1.2 m²
Number of gold fish = 6
Density of the tank should be = 4 fish/m³
Height of the tank= ?
4 fish = 1 m³
6 fish = 6/4 = 1.5 m³
Volume required for 6 fish is 1.5 m³
V = area of base x height (h)
1.5 = 1.2 x h
h = 1.25 m
Hence, height of the tank is equal to 1.25 m.
Jorge and Jillian have cell phones with different service providers. Jorge pays $50 a text month and $1 per text message sent. Jillian pays $72 a month and $0.12 per text message sent. How many texts would each of them have to send in order for their bill to be the same amount at the end of the month?
Answer:
When they send 25 texts each, their bills will be equal
Step-by-step explanation:
Let the number of text messages that makes their bill equal be x
Jorge will have a bill of = 50 + x(1) = 50 + x
Jillian will have a bill of = 72 + 0.12(x) = 72 + 0.12x
Since their bills will now be equal, we equate both
50 + x = 72 + 0.12x
72-50 = x-0.12x
22 = 0.88x
x = 22/0.88
x = 25 texts
HELP ME PLEASE WILL MARK BRAINLIEST
Answer:
Bottom Left
Step-by-step explanation:
Break up the numbers to 7, and -8.
Break up the fractions to 1/5 and -3/5.
t – 7 = 8 I know this problem is an because it has an equals sign. The t is the . The negative sign is the . The 7 and the 8 are both .
Answer:
1. equation
2. variable
3. operation
4. constants
i took this on edge so i know the answers ^-^
help plzzzz asap i need the answer right now
Make K the subject of the formula
[tex]t = \frac{mu {}^{2} }{k} - 5mg[/tex]
Answer:
Step-by-step explanation:
[tex]t = \frac{mu^{2} }{k} -5mg\\kt = mu^{2} -5mg\\k = \frac{mu^{2} -5mg}{t}[/tex]
To make k subject of the fomula :
Step 1 : cross multiply
Step 2 : Divide both side of the equation to isolate k
The solution of the expression for the value of k will be k = (mu² - 5mgk)/t.
What is an expression?The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.
The given expression is t = (mu²)/k - 5mg. The value of the expression for the value of k will be,
The value of k will be written as,
t = (mu²)/k - 5mg
k = (mu² - 5mgk)/t
Therefore, the solution of the expression for the value of k will be k = (mu² - 5mgk)/t.
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Pls help me!!!!! I'm dead!!!!! I have like 40 of these things. Pls ;)
Answer:
4 and 5 are coefficients the rest are terms
Step-by-step explanation:
coefficients are the numbers not the letters
Answer:
Coefficient: 4, 5Term: 4p, 5b, 8cStep-by-step explanation:
The terms are the elements of the sum:
5b, 8c, 4p
The coefficients are the constant multipliers:
5, 8, 4
___
In your list of items to "drag and drop", you have ...
Coefficient: 4, 5
Term: 4p, 5b, 8c
What is the solution to this system of equations
Sorry, Please rewrite it again.
Which of the following equations represents a proportional relationship?
A: y = 3x
B: y = 1/2x + 1
C: y = x/3 + 4
D: y = 2/5 - 5
Answer:
a
Step-by-step explanation:
y=3x
thus, a proportional relationship equation is y=kx .Where k is constant
i need help help pls
Answer:
MAD = 2
Step-by-step explanation:
First We'll find the mean of data
Mean = [tex]\frac{20}{5}[/tex]
Mean = 4
Then, we'll find absolute deviation
=> |4-3| = 1
=> |4-2| = 2
=> |4-1| = 3
=> |4-1| = 3
=> |4-3| = 1
Now, taking the mean of these absolute deviations:
MAD = [tex]\frac{1+3+3+2+1}{5}[/tex]
MAD = [tex]\frac{10}{5}[/tex]
MAD = 2