The equilibrant is the equal to the resultant magnitude but opposite in direction.


True

False


Answer and I will give you brainiliest
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Answer:

c

Explanation:

ok so i dont know srry5

Answer:

Uniform area charge density rho is needed is 3.82*10^-8 C.m^-2

Explanation:

See the attached files.

To find the rho, I used Gauss law for cylindrical shell which is equation 1 and Gauss law for the rod which is equation 4.

Note that in equation 4, Lamda is the charge per length while L is the length if the rod. Also R is the radius of the shell.

The final answer is 3.82*10^-8 C.m^-2 which is the uniform area charge density rho is needed.

Answer:

the sign and magnitude of the charge is - 2 x 10⁻⁵ C.

Explanation:

Given;

mass of the particle, m = 1.43 g = 0.00143 kg

electric field experienced by the particle, E = 700 N/C

The force experienced by the particle is calculated as;

F = mg = EQ

Where;

Q is the magnitude of the charge

[tex]Q = \frac{mg}{E} \\\\Q = \frac{0.00143 \times 9.8}{700} \\\\Q = 2\times 10^{-5} \ C[/tex]

The force must be upward in opposite direction to the electric field. Since the force and the electric field are in opposite direction, the charge must be negative.

Therefore, the sign and magnitude of the charge is - 2 x 10⁻⁵ C.

The particle to remain stationary, when placed in a downward-directed electric the force must be in opposite direction which upward directed.

The charge of the given particle to remain stationary should be [tex]-2\times10^{-5}[/tex] C.

The electric force experienced by the body when placed it into the electromagnetic field is called electric charge.

Given information-

The mass of the particle is 1.43 g or 0.00143 kg.

The magnitude of the downward-directed electric field is 700 N/C.

The magnitude of the free-fall acceleration is 9.80 meter per second squared.

The electric field is defined as the electric force per unit charge. It can be given as,

[tex]E=\dfrac{F}{q}[/tex]

Rewrite the equation for the charge,

[tex]q=\dfrac{F}{E}[/tex]

Force experienced by the particle is equal to the product of mass and free fall acceleration (gravity). Thus,

[tex]q=\dfrac{0.00143\times9.8}{700}\\q=2\times10^{-5}[/tex]

Thus the magnitude of the charge is [tex]2\times10^{-5}[/tex] C.

The particle to remain stationary, when placed in a downward-directed electric the force must be in opposite direction which upward directed. For the opposite direction the sign of the charge should be negative.

Thus the charge of the given particle to remain stationary should be [tex]-2\times10^{-5}[/tex] C.

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Answer:

Explanation:

Angle of incidence at the longer face = 45⁰ ( see the figure in the attached file )

For total reflection from longer face

i = C where C is critical angle .

And relation between critical angle and refractive index is as follows .

μ = 1 / sinC

= 1 / sin45

= √2

= 1.414 .

Answer:

a) 36°

b) 0.109 kg

Explanation:

Heat flows from brass to copper with the brass having its temperature

Length of brass = 0.4

Length of copper = 0.8

Temperature of = 36.15

See attachment for calculation

The temperature at the joint is 36.15°C

The amount of ice melted is 1.086 kg

The rate of transfer of thermal energy,

   H = Q/t = KAΔT/L

  where, K is the thermal conductivity of the substance, A is cross-sectional area, ΔT is temperature difference at the ends and L is the length

As given in the question,

  the length of the brass section   [tex]L_{1}[/tex] = 0.4 m

  it's thermal conductivity      [tex]K_{b}[/tex] = 109 J[tex]s^{-1}m^{-1}K^{-1}[/tex]

  the temperature at the brass end  [tex]T_{1}[/tex] = 373K

  the length of the copper section [tex]L_{2}[/tex] = 0.8 m

  it's thermal conductivity      [tex]K_{c}[/tex] = 385 J[tex]s^{-1}m^{-1}K^{-1}[/tex]

  the temperature at the brass end  [tex]T_{1}[/tex] = 273K

 cross-sectional area of both the substance is same A = 0.007 [tex]m^{2}[/tex]

  Let the temperature at the joint be T

The rate of heat flow must be constant across the whole length of the setup.

Hence at the joint,

   [tex]\frac{K_{b}A(T_{1}-T) }{L_{1} } =\frac{K_{c}A(T-T_{2}) }{L_{2} }[/tex]

⇒ [tex]\frac{ 109*A*(373-T)}{0.4} =\frac{385*A(T-273)}{0.8}[/tex] ⇒ T=309.15 K

⇒ T = 36.15°C is the temperature at the joint.

Now we have to calculate the equivalent thermal conductivity K of the setup in order to calculate the amount of heat transfer.

considering equivalent thermal conductivity K throughout the setup we can form the following equation to calculate its value

   [tex]\frac{KA(T_{1}-T_{2} ) }{L_{1}+L_{2} } =\frac{K_{c}A(T-T_{2}) }{L_{2} }[/tex]

   ⇒   [tex]\frac{ K*A*(100)}{1.2} =\frac{385*A(36.15)}{0.8}[/tex]

   ⇒  K = 208.76 J[tex]s^{-1}m^{-1}K^{-1}[/tex]

the amount of heat transferred at the copper end in ice-water mixture in 5 minutes(300 seconds) :

        Q = [tex]\frac{KA(T_{1}-T_{2} ) }{L_{1}+L_{2} }[/tex] × t =  [tex]\frac{208.76*0.007*100}{1.2}[/tex] × 300 = 36533 J

        latent heat of fusion of ice [tex]L_{f}[/tex] = 33600 J/kg

         [tex]Q=mL_{f}[/tex]

         [tex]m=\frac{Q}{L_{f} }[/tex]

         [tex]m=\frac{36533}{33600}[/tex] ⇒ m = 1.086 kg of ice is melted in 5 minutes

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Explanation:

You do the radius times the circumference of the earth

Answer:

6.3N

Explanation:

Guessed it right on castle learning

Answer:

6.3 N

Explanation:

F=kx

F=(25N/m)(0.25m)

6.3 N

Answer:

C. The star is receding from you with the speed of 3000 km/s

Explanation:

To get this answer we use the doppler effect equation . The formula for a receding emissor is given in the attachment.

We solve for V

V = 3x10⁶m/s

V = 3000km/s

We have the wavelength to be shifting towards red. Therefore we conclude that it is receding. We say the star is receding with speed of 3000km/s towards you.

Thank you!

Answer:

30.4 s

Explanation:

A pilot , with plane accelerated at 4 g starts greying out . In the problem , the acceleration of jet is 4 g

a = 4 x 9.8 = 39.2 m /s²

initial velocity u = 0

Final velocity = 3.60 times speed of sound

= 3.6 x 331 = 1191.6 m /s

v = u + at

Putting the values

1191.6 = 0 + 39.2 t

t = 30.4 s .

Answer: ITS 1 TRUST ME MAN BYE K

Explanation: OK BYE TRUST YEAH

It's c I think ( 4 , 2 , 6 , )

Option C shows the direction of the force of the ball on the spring. The direction of the force of the ball on the spring will be downwards.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

The spring is extended downward because the weight is always act downwards. The direction of the force of the ball on the spring will be downwards.

Hence, option C shows the direction of the force of the ball on the spring

To learn more about the force, refer to the link;

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Answer:

θ = 90º

Explanation:

The velocity is given by

          v = [tex]\frac{dr}{dt}[/tex]

calculate

          v = 3 i ^ + √2 j ^ + 2t k ^

acceleration is defined by

         a = dv / dt

         a = 2 k ^

one way to find the angle is with the dot product

         v. a = | v | | a | cos θ

         cos θ= v.a / | v | | a |

Let's look for the value of each term

       v. a = 4 t

        | v | = [tex]\sqrt{3^2 + 2 + (2t)^2 }[/tex] = [tex]\sqrt{ 11 + 4t^2}[/tex]

        | a | = 2

they ask us for the angle for time t = 0

         v. a = 0

        | v | = √11 = 3.317

we substitute

        cos θ = 0 /√11

        cos θ = 0

therefore the angles must be θ = 90º

Answer:

Explanation:

Average velocity = Total displacement / total time

Average speed = total distance covered / total time

a )

For the entire trip from your front door to the bench

Total displacement = 55 - 35 = 20 m  [ first displacement is positive and second displacement is negative , because second displacement is in opposite direction ]

Total displacement = 20 m

Total time = 30 + 36 = 66 s

Average velocity = 20 / 66

= .303 m / s

b )

For the entire trip from your front door to the bench

Total distance covered  = 55 + 35 = 90  m

Total time = 30 + 36 = 66 s

Average speed  = 90 / 66

= 1.36  m / s

Answer:

Explanation:

The box is moving with constant velocity so acceleration of box is zero . That means net force on the box is zero .

The weight component acting on box parallel to incline plane

= mg sin 30⁰ = 20 x 9.8 x sin 30 = 98 N

This force is acting down the plane , hence to make the net force zero acting on box , force exerted by person will also be 98 N up the incline .

Force exerted by person = 98 N

distance travelled in 5 s

= velocity x time

= 2 x 5 = 10 m

Work done by person

= 98 x 10

= 980 J .

Answer:

The answer is below

Explanation:

Let a be the initial velocity of motorcycle A and b be the initial velocity of motorcycle B.

After 5.68 seconds, both motorcycle had the same velocity (v), therefore for motorcycle A:

(a - v) / 5.68 = 3.87

a - v = 21.9816

v = a - 21.9816

For motorcycle B:

(b - v) / 5.68 = 18.2

b - v = 103.376

v = b - 103.376

Therefore:

a - 21.9816 = b - 103.376

b - a = -21.9816 + 103.376

b - a = 81.3944

a) The difference between their speeds at the beginning was 81.3944 m/s

b) Since b - a = 81.3944. This means that the initial velocity of motorcycle B is greater than that of motorcycle A by 81.3944 m/s.

Therefore motorcycle B was moving faster

Answer:

If the forces are balanced, the resultant force is zero. If the forces on an object are unbalanced, this is what happens: a stationary object starts to move in the direction of the resultant force. a moving object changes speed and/or direction in the direction of the resultant force.

Explanation:

Answer:

The energy is transferred to chemical and heat energy.

Explanation:

If you define "bouncing" as leaving the ground for any amount of time, the ball stops bouncing when the elastic energy stored in the compression phase of the bounce is not enough to overcome the weight of the ball. This is the proof of the answer i Hope this helps :)

Answer:

a

Explanation:

i just took the test

Answer:

If it accelerates at 20 m/s2 for a period of 22 seconds, what is its final velocity? ... How fast is the ball falling after 5 seconds? v = v0 + gt v = 0 + 10(5) v = 50 m/s. 4. ... + ½ 2.5(15)2 x = 281 m. 5. What is the total displacement of the car in question 2? ... 8. A base jumper falls until he reaches a speed of 200 m/s

Explanation:

Answer:

i Believe the correct answer is "An open circuit being changed into a closed circuit"

Explanation:

Answer: 30 Years Old

Explanation: The constitution has around three qualifications for service in the U.S. Senate, Your age must be at least 30 years.

Answer:

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Answer:

h1/h2 = [tex]\frac{2R^2}{3R^2 + h^2}[/tex]

Explanation:

Using two rolls of tissue paper : One roll dropped normally while the other drops as some holds onto a sheet of the toilet paper ( I.e. the tissue paper drops rotating about its axis )

Determine the ratio of heights  h1/h2

mass of tissues = same

radius of tissues = same

h1 = height of tissue 1

h2 = height of tissue 2

For the first tissue ( Tissue that dropped manually )

potential energy = kinetic energy

mgh = 1/2 mv^2  

therefore the final velocity ( v^2 ) = 2gH  ----- ( 1 )

second tissue ( Tissue that dropped while rotating )

gh = [tex]\frac{v^2}{u}[/tex] ( 3 + [tex]\frac{u^2}{R^2}[/tex] ) ------ ( 2 )

To determine the ratio of heights we will equate equations 1 and 2

hence :

gh = [tex]\frac{2gH}{u}[/tex] ( 3 + [tex]\frac{u^2}{R^2}[/tex] )

∴ h1/h2 = [tex]\frac{2R^2}{3R^2 + h^2}[/tex]

HERE IS YOUR ANSWER!

Answer:

c. The roller coaster is in uniform circular motion

Explanation:

Since the loop is circular with radius r, and its instantaneous speed, v is always constant, and also, its centripetal acceleration, a' = v²/r.

Since the angular speed, ω = v/r does not change, the magnitude of its  tangential acceleration is zero although there is a change in its direction because the direction of its initial velocity changes. That is a" = rα and α = Δω/Δt since Δω = 0, α = 0 and a" = r(0) = 0

So, there is no tangential acceleration. Since there is no tangential acceleration, our instantaneous acceleration which is the vector sum of our centripetal acceleration and tangential acceleration is a = √(a'² + a"²) =  √(a'² + 0²) = √a'² = a' = v²/r

So, a is always v²/r.

Since the instantaneous acceleration is always (a = v²/r) constant, the motion is uniform. So, it is uniform circular motion.

The roller coaster is not in uniform circular motion, and [tex]a = \frac{v^2}{r}[/tex] is only applicable at the very top and bottom of the loop where the tangential acceleration vanishes.

The given parameters;

The motion tension on the loop at the lowest point in the circular motion is given as;

[tex]T = mg + \frac{mv^2}{r}[/tex]

The motion tension on the loop at the highest point in the circular motion is given as;

[tex]T = \frac{mv^2}{r} - mg[/tex]

This shows that circular motion is affected by;

Thus, we can that the roller coaster is not in uniform circular motion, and [tex]a = \frac{v^2}{r}[/tex] is only applicable at the very top and bottom of the loop where the tangential acceleration vanishes.

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Answer:

Explanation:

Increases. The force of gravity is distance dependent. Therefore, a smaller 'r' value will result in a larger force. Net force is proportional to the acceleration, so the planet will increase its speed.