The equation

[tex]\frac{24x2+25x-47ax}{-2=8x-3-53}[/tex]

ax−2 is true for all values of x≠

2/a, where a is a constant.

What is the value of a?


A) -16

B) -3

C) 3

D) 16

Answers

Answer 1

Answer:

There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:

24x2+25x−47=(−8x−3)(ax−2)−53

You should then multiply (−8x−3) and (ax−2) using FOIL

("First, Outer, Inner, Last")

24x2+25x−47=−8ax2−3ax+16x+6−53

Then, reduce on the right side of the equation

24x2+25x−47=−8ax2−3ax+16x−47

Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.

The other option which is longer and more tedious is to attempt to plug in all of the answer choices for a and see which answer choice makes both sides of the equation equal. Again, this is the longer option, and I do not recommend it for the actual SAT as it will waste too much time.

soo the final answer is B  -3

Answer 2

Answer:

hi im new here and im a dumb A**

Explanation:

giid luck\

dont report me pls


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