The Earth orbits the Sun at a speed of 30 km/s. At that speed it completes one path around the Sun every year. Of course, as that happens we are heading toward a different place in space constantly, always accelerating toward the Sun to stay on the circular path. Suppose at a paritcular instant we are headed in the direction of a distant star and we measure the speed of the light from that star as it arrives on Earth. In the vacuum of space we would measurea. 299,792,458 m/sb. 299,792,428 m/sc. 299,792,488 m/sd. 0 m/s

Answer:

A) pass the ball to a teammate

B) Smash the shuttlecock downward in your opponents court

C)Do a fake hit . . .

D) Do a fake hit . . .

(Best guess)

Answer:

C, Red has the longest one

c red

red has longest wavelength

amnh dot org

Answer:

Explanation:

1 ) angular frequency ω = √ ( k / m )

=√ ( 170 / 50 )

= 1.844 rad /s

2πn = 1.844 where n is frequency of oscillation

n = 1.844 / (2 x 3.14 )

= .294 per sec

= .294 x 60 = 18 approx. per minute .

Velocity just after collision of composite mass ( using law of conservation of momentum )

= 25 x 2.8 / 50

v = 1.4 m/s

If new amplitude be A

1/2 k A² = 1/2 m v²

m = 25 + 25 = 50 kg

170 x A² = 50 x 1.4²

A = 0.76 m

3 ) period of oscillation = 1 /n

= 1 / .294

= 3.4 s

4 ) It will take complete one period of oscillation ie 3.4 s to come to its original position.

Answer:

Hello! Your answer would be, A) True

Explanation:

Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥

Answer:

2420 J

Explanation:

From the question given above, the following data were obtained:

Force (F) = 22.9 N

Angle (θ) = 35°

Distance (d) = 129 m

Workdone (Wd) =?

The work done can be obtained by using the following formula:

Wd = Fd × Cos θ

Wd = 22.9 × 129 × Cos 35

Wd = 22.9 × 129 × 0.8192

Wd ≈ 2420 J

Thus, the workdone is 2420 J.

Answer:

0.4112 m

Explanation:

The mass of the 1st ball = 3.6 kg

The height of the 1st ball =3.5 m

The mass of the 2nd ball = 3.6 kg

Mass of the bar M = 9.9 kg

Length of the bar L = 4.2 m

The velocity of the ball when it dropped from the height is calculated by using the formula:

[tex]\dfrac{1}{2}mv_1^2 = mgh_1 \\ \\ v = \sqrt{2gh_1} \\ \\ v =\sqrt{2\times9.8 \times 3.5} \\ \\ v = 8.283 \ m/s\\\\[/tex]

Provided that the bar is pivoted at the center and the ball is placed at the two ends, the moment of inertia for the bar is:

[tex]I = \dfrac{1}{12}ML^2 + m_1 (\dfrac{L}{2})^2 + m_2(\dfrac{L}{2})^2 \\ \\ =\dfrac{1}{12}(9.9kg)(4.2m)^2 + [3.6 kg+3.6kg](\dfrac{4.2}{2 \ m})^2 \\ \\ = 46.305 \ kg.m^2[/tex]

The angular momentum of the system due to the ball can be determined by using the formula:

L = mvr

L = (3.6 kg) (8.283 m/s) (2.1 m)

L = 62.61948 kg. m²

Now, Using the law of conservation:

[tex]L_i = L_f \\ \\ 62.61948 \ kg.m^2/s = I \omega \\ \\[/tex]

[tex]\omega = \dfrac{62.6198 \ kg.m^2/s}{46.305 \ kg.m^2}[/tex]

[tex]\omega =1.352 \ rad/s[/tex]

The linear angular velocity is deduced to be:

[tex]v = r \omega \\ \\ v = (2.1 \ m) ( 1.352 \ rad/s) = 2.839 \ m/s[/tex]

∴

the height raised by the second ball is:

[tex]h_2 = \dfrac{v^2}{2g} \\ \\ h_2 = \dfrac{(2.839)^2}{2(9.8 \ m/s^2)} \\ \\ h_2 =0.4112 \ m[/tex]

Answer:

J = 1600 kg-m/s

Explanation:

Given that,

The mass of charging bull rams, m = 800 kg

Initial speed, u = 5 m/s

Final speed, v = 3 m/s

We need to find the impulse the bull  experience by smashing the fence. Let it is J. We know that, impulse is equal to the change in momentum such that,

J = m(v-u)

Put all the values,

J = 800(3-5)

= 800(-2)

= -1600 kg-m/s

Hence, the magnitude of impulse is equal to 1600 kg-m/s.

Answer:

Δx = 6.33 x 10⁻³ m = 6.33 mm

Explanation:

We can use the Young's Double Slit Experiment Formula here:

[tex]\Delta x = \frac{\lambda L}{d}\\\\[/tex]

where,

Δx = distance between consecutive dark fringes = width of central bright fringe = ?

λ = wavelength of light = 633 nm = 6.33 x 10⁻⁷ m

L = distance between screen and slit = 3.7 m

d = slit width = 0.37 mm = 3.7 x 10⁻⁴ m

Therefore,

[tex]\Delta x = \frac{(6.33\ x\ 10^{-7}\ m)(3.7\ m)}{3.7\ x \ 10^{-4}\ m}[/tex]

Δx = 6.33 x 10⁻³ m = 6.33 mm

Answer:

As for the definitions, the tendency of two or more different molecules to bond with each other is known as Adhesion, whereas the force of attraction between the same molecules is known as Cohesion.

hopefully this helps

Answer:

Adhesion is the force of attraction between molecules of different substances while cohesion is the force of attraction between molecules of same substances.

Answer:

677 m

Explanation:

Using the definition of the sine of an angle, we can write

sin 14.1 = (height of mountain) / (slope length of mountain)

sin 14.1 = H / (2780 m) ---> H = (2780 m) x sin 14.1

= 677 m

The height of the mountain is 677.21 m

The given parameters;

length of the slope, L = 2780 m

angle of inclination, Ф = 14.1°

let the height of the mountain, = h

A simple sketch of the problem is given below;

                    ↓P

                    ↓

                    ↓ h

                    ↓                                            14.1°

                    ↓------------------------------------------------Q

A straight line  joining PQ  is  the hypotenuse of the right triangle.

The height of the right triangle is calculated as follows;

[tex]sin(14.1) = \frac{h}{PQ} \\\\\h = PQ \times sin(14.1)\\\\h = 2780 \times sin(14.1)\\\\h = 677.21 \ m[/tex]

Thus, the height of the mountain is 677.21 m

Learn more here: https://brainly.com/question/4326804

Answer:

b

Explanation:

Answer:

34.24 %

Explanation:

Since I₀ is the intensity of the un-polarized light, the intensity I₁ of the light polarized by the 1st sheet is (by the one-half rule) I₁ = I₀/2.

The intensity of polarized light I from a polarized source I' is I = I'cos²Ф where Ф is the angle between the direction of I' and I. Since the second sheet has its transmission axis at 25° with respect °o the 1st sheet, the intensity of light I₂ from the second sheet is I₂ = I₁cos²25°.

Also, the 3rd sheet has its transmission axis 47° with respect to the 1st sheet. So, the angle between the transmission axis of the 2nd sheet and 3rd sheet is 47° - 25° = 22°. So, the intensity I₃ from the 3rd sheet is I₃ = I₂cos²22°

Finally, the 4th sheet has its transmission axis 10° with respect to the 3rd sheet. So, the intensity I₄ from the 4th sheet is I₄ = I₃cos²10°.

So,  I₄ = I₃cos²10°

I₄ = I₂cos²22°cos²10°

I₄ = I₁cos²25°cos²22°cos²10°

I₄ = (I₀/2)cos²25°cos²22°cos²10°

I₄/I₀ = cos²25°cos²22°cos²10°/2

I₄/I₀ = (cos25°cos22°cos10°)²/2

I₄/I₀ = (0.9063 × 0.9272 × 0.9848)²/2

I₄/I₀ = 0.8275²/2

I₄/I₀ = 0.6848/2

I₄/I₀ = 0.3424

So, as a percentage,

I₄/I₀ × 100% = 0.3424 × 100% = 34.24 %

Answer:

(a) Energy Density = 160.94 J/m³

(b) Energy Stored = 0.192 J

Explanation:

(a)

The energy density of the magnetic field inside the solenoid is given by the following formula:

[tex]Energy\ Denisty = \frac{B^2}{2\mu_o}\\[/tex]

where,

B = magnetic field strength of solenoid = [tex]\frac{\mu_oNI}{l}[/tex]

Therefore,

[tex]Energy\ Density = \frac{\mu_oN^2I^2}{2l^2}[/tex]

where,

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

N = No. of turns = 1300

I = current = 8.15 A

L = length = 66.2 cm = 0.662 m

Therefore,

[tex]Energy\ Density = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(1300)^2(8.15\ A)^2}{2(0.662\ m)^2}[/tex]

Energy Density = 160.94 J/m³

(b)

Energy Stored = (Energy Density)(Volume)

Energy Stored = (Energy Density)(Area)(L)

Energy Stored = (160.94 J/m³)(0.0018 m²)(0.662 m)

Energy Stored = 0.192 J

This is true I think

It applies to Newton's Laws

it's true because it's a part of newtons law

Answer:

the maximum allowable current is 7302.967  amperl

Explanation:

The computation of the maximum allowable current is shown below;

Force F = mean ÷ 4π 2 I_1 I_2 ÷d  × ΔL

200 N = (10)^-7 (2I × I) ÷ 0.08 × 1.5

200 = 3.75 × 10^-6 I^2

I = √200 ÷ √ 3.75 × 10^-6

= 7302.967  amperl

Hence, the maximum allowable current is 7302.967  amperl

Basically we applied the above formula

Answer:

a

because the mechanical wave is when it goes over and over again

Answer:

The answer is a like i said 3hrs ago i dont know if this guy copied me tbh

Explanation:

Answer:

B)   I₀ = I_f= 0, C) vₐ = [tex]\frac{m_w}{m_a} \ v_w[/tex] ,  D)      t = [tex]\frac{m_a}{m_w} \ \frac{L}{v_w}[/tex]

Explanation:

A) in the attachment you can see a diagram of the movement of the key and the astronaut that is in the opposite direction to each other.

B) Momentum equals the change in momentum in the system

          I = ∫ F dt = Δp

since the astronaut has not thrown the key, the force is zero, so the initial impulse is zero

           I₀ = 0

The final impulse of the two is still zero, since it is a vector quantity, subtracting the impulse of the two gives zero, since it is an isolated system

             I_f = 0

C) We define the system formed by the astronaut and the key, for which the forces during the separation are internal and the moment is conserved

initial instant.

         p₀ = 0

final instant

         p_f = [tex]m_a v_a - m_w v_w[/tex]

We used the subscript “a” for the astronaut and the subscript “w” for the key

the moment is preserved

        po = p_f

        0 = mₐ vₐ - m_w v_w

        vₐ = [tex]\frac{m_w}{m_a} \ v_w[/tex]

D) as the astronaut goes at constant speed we can use the uniform motion relationships

         vₐ = x / t

         t = x / vₐ  

         t = [tex]\frac{m_a}{m_w} \ \frac{L}{v_w}[/tex]

Answer:

When force and displacement are in the same direction, the work performed on an object is said to be positive work. Example: When a body moves on the horizontal surface, force and displacement act in the forward path. The work is done in this case known as Positive work.

Explanation:

Hope this helps you

Answer:

V₁ = V = 120 V

Explanation:

Such a combination of capacitors in which;

1- Potential difference across each capacitor is the same

2- Total charge is distributed amongst the capacitors

; is called Parallel Combination.

Therefore, in this case, the potential difference across each capacitor will also be the same. Because the capacitors are connected in parallel here. So the voltage across 3 μF capacitor will be the same as the voltage across the 6 μF capacitor and they both will be equal to the total potential difference.

V₁ = V = 120 V

Answer:

you need 7 points and the other team just needs to stop you from scoring

Explanation:

Answer:

hope u can understand the method

Answer:

h = 3.5 m

Explanation:

First, we will calculate the final speed of the ball when it collides with a seesaw. Using the third equation of motion:

[tex]2gh = v_f^2 - v_i^2\\[/tex]

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 3.5 m

vf = final speed = ?

vi = initial speed = 0 m/s

Therefore,

[tex](2)(9.81\ m/s^2)(3.5\ m) = v_f^2 - (0\ m/s)^2\\v_f = \sqrt{68.67\ m^2/s^2}\\v_f = 8.3\ m/s[/tex]

Now, we will apply the law of conservation of momentum:

[tex]m_1v_1 = m_2v_2[/tex]

where,

m₁ = mass of colliding ball = 3.6 kg

m₂ = mass of ball on the other end = 3.6 kg

v₁ = vf = final velocity of ball while collision = 8.3 m/s

v₂ = vi = initial velocity of other end ball = ?

Therefore,

[tex](3.6\ kg)(8.3\ m/s)=(3.6\ kg)(v_i)\\v_i = 8.3\ m/s[/tex]

Now, we again use the third equation of motion for the upward motion of the ball:

[tex]2gh = v_f^2 - v_i^2\\[/tex]

where,

g = acceleration due to gravity = -9.81 m/s² (negative for upward motion)

h = height = ?

vf = final speed = 0 m/s

vi = initial speed = 8.3 m/s

Therefore,

[tex](2)(9.81\ m/s^2)h = (0\ m/s)^2-(8.3\ m/s)^2\\[/tex]

h = 3.5 m

Answer:

The Moment of a force is a measure of its tendency to cause a body to rotate about a specific point or axis.

Answer:

Torque

Explanation:

I serached it up sjdjbdjd

Answer:

the answer of this question is true

Answer:

η = 0.84 = 84%

Explanation:

The efficiency of the man can be given by the following formula:

η = output/input

where,

η = efficiency of man = ?

output = potential energy gain of the block = mgh

input = work done by man = Fd

Therefore,

[tex]\eta = \frac{mgh}{Fd}[/tex]

where,

m = mass of block = 225 kg

g = acceleration due to gravity = 9.81 m/s²

h = height gained by block = 1.2 m

F = force exerted by man = 315 N

d = distance covered by man = 10 m

Therefore,

[tex]\eta = \frac{(225\ kg)(9.81\ m/s^2)(1.2\ m)}{(315\ N)(10\ m)}[/tex]

η = 0.84 = 84%