The diameters of cherry tomatoes produced by a large farm have an approximately Normal distribution, with a
mean diameter of 22 mm and a standard deviation of 2.5 mm. After they are picked and washed, tomatoes with
diameter of at most 15 mm or at least 30 mm are rejected and not sold. What proportion of such tomatoes are
rejected?
Find the z-table here.
0.0033
0.0201
0.9799
0.9967

hope it helps you

option d

Answer:

6

Step-by-step explanation:

[tex] \frac{2 + 3 + 5 + 7 + 13}{5} = \frac{30}{5} = 6[/tex]

Answer:250

Step-by-step explanation:

The answer is: Logan's rope is longer than Sam's rope.

A number that represents a part of a whole or a ratio between two quantities, written as a numerator over a denominator. It consists of a numerator (top) and a denominator (bottom) separated by a fraction bar. For example, 1/2 represents one-half of a whole or the ratio of one to two.

Part A:

Brittney's rope is shorter than Sam's rope because it is 4/5 as long as Sam's rope.

Logan's rope is longer than Sam's rope because it is 1 1/4 times as long as Sam's rope.

Holly's rope is equal to Sam's rope because it is 8/8 (which simplifies to 1) as long as Sam's rope.

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1. Quadratic monomials.

2.  Biquadratic five-term polynomials.

3. Quadratic trinomials.

4. x³ + 3x² - 5x - 4

5. -[tex]x^{5}[/tex] + 4[tex]x^{4}[/tex] +2x³ + 2x - 7

6. - x² + 5x + 9

7. y² - 3y - 9

8. 5(x³ + x)

9. 2x² + 2x -5

Algebraic expressions called polynomials only have non-negative integer powers for their variables. A polynomial is, for instance, 5x² - x + 1. The polynomial 3x³ + 4x + 5/x + 6[tex]x^{3/2}[/tex] is not a polynomial since one of the powers of "x" is a fraction and the other is negative.

Expressions with one or more terms that have a non-zero coefficient are called polynomials. Variables, exponents, and constants make up polynomial terms. The "leading term" refers to the first term of the polynomial in standard form.

Here in the given question,

We can see the highest degree of the variable and we can determine the name of each polynomial.

Likewise, we can just arrange the expressions as per the highest value of the power of the variable.

And simplify the expression by adding or subtracting the like terms.

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The t-statistic is less than the critical value, we fail to reject the null hypothesis

The hypothesis testing to be conducted here is a two-tailed test for the population mean, using the formula:

H0: μ = 7.6 days

Ha: μ ≠ 7.6 days

The critical value is ± 1.960, with a confidence level of 95%.

The sample mean is 7.5 days and the sample standard deviation is 0.9 days. Using the formula, we can calculate the t-statistic:

t = (7.5 - 7.6) / (0.9 / √250) = -1.105

Since the t-statistic is less than the critical value, we fail to reject the null hypothesis, suggesting that Formulation NS does not significantly speed up the healing process compared to the foregoing treatment.

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a) Sample Variance = 521.646

b)Two-sided confidence interval for the variance with a confidence level of 0.98 is (5.545, 10029.794).

a) To calculate the sample variance, you will first need to calculate the sample mean. The sample mean is calculated by summing all the observations in the sample and dividing by the number of observations. For this sample, the mean is:

Mean = (32.564 + 7.57 + 21.815 − 13.971 − 15.224) / 5 = 5.168

Next, you will need to calculate the sum of squared deviations from the mean. This is done by subtracting the mean from each observation and squaring the result, and then summing all of the results:

Sum of Squared Deviations = (32.564 - 5.168)^2 + (7.57 - 5.168)^2 + (21.815 - 5.168)^2 + (-13.971 - 5.168)^2 + (-15.224 - 5.168)^2 =
= 1564.939

Finally, you can calculate the sample variance by dividing the sum of squared deviations by the number of observations minus one:

Sample Variance = 1564.939 / (5 - 1) = 521.646

b) To calculate a two-sided confidence interval for the variance with a confidence level of 0.98, you will need to find the critical value from the Chi-squared distribution with a degrees of freedom equal to the number of observations in the sample minus one. For this sample, the degrees of freedom is 4.

The critical value for this degrees of freedom at the given confidence level is 8.37.

The lower bound of the confidence interval is:

Lower bound = (521.646 / 8.37) * (1 - 0.98) = 5.545

The upper bound of the confidence interval is:

Upper bound = (521.646 / 8.37) * (1 + 0.98) = 10029.794

Therefore, the two-sided confidence interval for the variance with a confidence level of 0.98 is (5.545, 10029.794).

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The value οf P(2 tails) is 37.5%, the cοrrect οptiοn is B.

Prοbability refers tο a pοssibility that deals with the οccurrence οf randοm events.

The prοbability οf all the events οccurring need tο be 1.

The fοrmula οf prοbability is defined as the ratiο οf a number οf favοurable οutcοmes tο the tοtal number οf οutcοmes.

P(E) = Number οf favοurable οutcοmes / tοtal number οf οutcοmes

We are given that;

The sample space=  {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

Nοw,

The sample space fοr tοssing a cοin 3 times is {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}, where H represents heads and T represents tails.

Tο determine P(2 tails), we need tο cοunt the number οf οutcοmes in which there are 2 tails, and divide that by the tοtal number οf οutcοmes:

Number οf οutcοmes with 2 tails: There are three οutcοmes with 2 tails: TTH, THT, and HTT.

Tοtal number οf οutcοmes: There are eight οutcοmes in tοtal.

P(2 tails) = number οf οutcοmes with 2 tails / tοtal number οf οutcοmes = 3/8 = 0.375, which is equivalent tο 37.5%.

Therefοre, the prοbability the answer will be 37.5%.

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The probability that the sample proportion surviving for at least 3 years will be less than 70% is approximately 0.2734 or 27.34%.

Probability is a branch of statistics that deals with the study of random events and their likelihood of occurrence.

First, calculate the standard deviation of the sampling distribution of sample proportions using the formula.

σ = [tex]\sqrt{[(p*q)/n]}[/tex], where p is the population proportion, q = (1 - p), and n is the sample size.

In this case, p = 0.74, q = 0.26, and n = 70

Therefore, σ =  [tex]\sqrt{[(0.74*0.26)/70]}[/tex]  = 0.066

Next, we need to standardize the sample proportion using the formula,

z = (X - p) / σ, where X is the sample mean, p is the population proportion, and σ is the standard deviation of the sampling distribution.

In this case, X = 0.70, p = 0.74, and σ = 0.066

Thus, z = (0.70 - 0.74) / 0.066 = -0.606

Using a standard normal distribution table, we find that the cumulative probability for a z-score of -0.606 is 0.2734.

Therefore, the probability that the sample proportion surviving for at least 3 years will be less than 70% is approximately 0.2734 or 27.34%.

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Answer: B. A right circular Cylinder

Step-by-step explanation:

The given statement "The mode number of TVs per household for both Mrs. Jamison's class and and Mr. Zimmerman's class is 3." is true. The mode of TVs per household is 3 in both Mrs. Jamison's class and and Mr. Zimmerman's class.

Mode is a statistical measure that represents the value that appears most frequently in a dataset. It is one of the measures of central tendency, along with mean and median.

In Mrs. Jamison's class, the mode number of TVs per household is 3 because it appears twice, while all other numbers appear only once. Similarly, in Mr. Zimmerman's class, the mode number of TVs per household is 3 because it appears twice, while all other numbers appear only once.

Therefore, the statement "The mode number of TVs per household for both Mrs. Jamison's class and Mr. Zimmerman's class is 3" is true.

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Answer:-14a-4

Step-by-step explanation:

Answer: Expanding the expression, we get:

-7(2a - 1) - 11 = -14a + 7 - 11

Combining like terms, we get:

-14a - 4

Therefore, the simplified expression is -14a - 4.

Enjoy!

The cost of one metre of cotton fabric is £ 7. The cost of one metre polyester fabric is  £ 2.

The ratio of the cost of one metre of polyester fabric to the cost of one metre of cotton fabric is 2: 7.

1 m polyester / 1 m cotton = 2 / 7

1 m cotton = 7/2 × 1 m polyester

for 2 m of polyester fabric, the cost is £ 4

for 1 m of polyester fabric, the cost is £ 4/2 = £ 2

for 1 m of cotton fabric = 7/2 × 1 m polyester fabric = 7/2 × £2 = £ 7

for 1 m of cotton fabric, the cost is £ 7

For 2m, polyester fabric   2 × £2  = £ 4

cotton fabric  2 × £7  = £ 14

For 6m, polyester fabric   6 × £2  = £ 12

cotton fabric  6 × £7  = £ 42

For 8m, polyester fabric   8 × £2  = £ 16

cotton fabric  8 × £7  = £ 56

For 9m, polyester fabric   9 × £2  = £ 18

cotton fabric  9 × £7  = £ 63

The complete table

                           2m        6m      8m      9m

polyester fabric   £ 4       £ 12    £ 16     £ 18

cotton fabric        £ 14     £ 42    £ 56    £ 63

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Answer: The unit circle is an essential tool in trigonometry because it helps in understanding and visualizing the relationships between angles and the values of the sine, cosine, and tangent functions.

The unit circle is a circle with a radius of one unit and centered at the origin of a coordinate plane. It is divided into 360 degrees or 2π radians. By placing this circle on the coordinate plane, we can easily determine the sine and cosine values of angles in standard position.

For any given angle θ, the sine value is the y-coordinate of the point where the terminal side of the angle intersects the unit circle, and the cosine value is the x-coordinate of that same point. The tangent function, which is the ratio of sine to cosine, can also be determined using the unit circle.

The unit circle also helps in understanding the periodicity of the sine and cosine functions. Since the circumference of the unit circle is 2π, the sine and cosine functions repeat themselves after every 2π radians or 360 degrees. This periodicity allows for the use of trigonometric identities and formulas to simplify and solve complex trigonometric equations.

In summary, the unit circle is an essential tool in trigonometry as it provides a visual representation of angles and their corresponding sine, cosine, and tangent values, and allows for the use of trigonometric identities and formulas to solve complex problems.

Answer:

y = -9

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

since 2y is adding to positive 6 we take 6 to the right side where there its like term 12. we subtract 6 from 12 which is giving us 6. we are remaining with 2y=6 we divide both sides by 2 giving us y=3

The possible rational roots of the polynomial are ±1/2, ±1, ±3/2, ±3, ±9/2, ±9 while the actual roots are 1, -3, 3/2

To find the possible rational roots of the polynomial 2x^3 + x^2 - 12x + 9 = 0, we can use the rational root theorem. According to the theorem, if a polynomial with integer coefficients has a rational root p/q (where p and q are integers with no common factors other than 1), then p must be a factor of the constant term (in this case, 9) and q must be a factor of the leading coefficient (in this case, 2).

The factors of 9 are ±1, ±3, and ±9, and the factors of 2 are ±1 and ±2. Therefore, the possible rational roots of the polynomial are:

±1/2, ±1, ±3/2, ±3, ±9/2, ±9

We can now use synthetic division or long division to check which of these possible roots are actual roots of the polynomial. After checking, we find that the real rational root of the polynomial are x = 1, -3, 3/2

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The explicit functions are:

Arithmetic sequence with common difference d=3: f(n) = 3n +1

Geometric sequence with common ratio r=2: f(n) = 2^n + 2

Quadratic sequence with leading coefficient a=1, constant term c=2, and linear term b=1: f(n) = n^2 + n + 2

There are infinitely many possible sequences that satisfy the condition f(1)=4, so the function to model the value of the nth term in the sequence will depend on the specific pattern or rule that the sequence follows.

Here are some examples of possible sequences and the corresponding explicit functions:

Arithmetic sequence with common difference d=3: f(n) = 4 + 3(n-1) = 3n + 1

Geometric sequence with common ratio r=2: f(n) = 4 x 2^(n-1) = 2^n+2

Quadratic sequence with leading coefficient a=1, constant term c=2, and linear term b=1: f(n) = n^2 + n + 2

Fibonacci sequence with initial values f(1)=f(2)=1: f(n) = ((1+sqrt(5))/2)^n/sqrt(5) - ((1-sqrt(5))/2)^n/sqrt(5)

Note that these are just examples, and there are many other possible functions that could model a sequence with f(1)=4

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Baby lizards can run, climb and in some cases even change color to match their surroundings, while baby snakes are generally limited to crawling and slithering.

Baby lizards have developed legs, claws and a tail to help them navigate their environment, while baby snakes have lost their legs during evolution and have developed a long, slender body to help them move around.

Additionally, some baby lizards are born with a protective membrane around their eggs that allows them to move around freely, while baby snakes are usually born inside an egg that they must break out of before hatching. Overall, baby lizards have more mobility and flexibility than baby snakes, which gives them an advantage in many environments.

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1. The finance charge on June 11 is $1.98.

2. The new card balance on June 12th is $341.30

To calculate the finance charge and new card balance, we first need to calculate the average daily balance for the billing cycle.

May 13 Charge toys: $129.79 (balance: $129.79)

May 15 Payment $50 (balance: $79.79)

June 1 Charge clothing $135.95 (balance: $215.74)

June 8 Charge Housewares $37.63 (balance: $253.37)

Billing cycle: May 13 to June 11 (30 days)

Average daily balance:

=  (129.79 x 18) + (79.79 x 16) + (215.74 x 10) + (253.37 x 6) / 30

= $152.49

The Finance charge is computed as:

= Average daily balance * Monthly periodic rate.

= 152.49 x (1.3/100)

= $1.98.

To calculate the new card balance on June 12th, we need to add the finance charge and any new charges to the previous balance and subtract any payments made.

Previous balance (as of June 1st) = $215.74

New charges (since June 1st) = $135.95 + $37.63 = $173.58

Payments made (since May 15th) = $50

The New card balance on June 12th will be:

= $215.74 + $173.58 + $1.98 - $50

= $341.30

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By solving the equation -3x = 348, we find that the value of x is -116.

The property of equality that could be used to solve -3x = 348 is the multiplication property of equality, which states that if we multiply both sides of an equation by the same non-zero number, the equation remains equivalent. In this case, we can divide both sides of the equation by -3 to isolate x and solve for it.

Using the multiplication property of equality, we can multiply both sides by -1/3:

(-1/3) * (-3x) = (-1/3) * 348

Simplifying:

x = -116

Therefore, the solution to the equation -3x = 348 is x = -116.

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The average speed during a given time interval can be found by calculating the change in distance over the change in time, or (d(b) - d(a))/(b-a). In this case, we can use the given function d(t) = 16t^2 to find the distance at each given time.  It is reasonable to say that this value is the speed of the object at the instant t = 9 because as the time interval approaches zero, the average speed approaches the instantaneous speed at that moment.

For the first time interval, t = a = 9 and t = b = 9.5:
d(a) = 16(9)^2 = 1296
d(b) = 16(9.5)^2 = 1444
Average speed = (1444 - 1296)/(9.5 - 9) = 148/0.5 = 296 ft/s

For the second time interval, t = a = 9 and t = b = 9.1:
d(a) = 16(9)^2 = 1296
d(b) = 16(9.1)^2 = 1324.96
Average speed = (1324.96 - 1296)/(9.1 - 9) = 28.96/0.1 = 289.6 ft/s

For the third time interval, t = a = 9 and t = b = 9.01:
d(a) = 16(9)^2 = 1296
d(b) = 16(9.01)^2 = 1300.9616
Average speed = (1300.9616 - 1296)/(9.01 - 9) = 4.9616/0.01 = 496.16 ft/s

For the fourth time interval, t = a = 9 and t = b = 9.001:
d(a) = 16(9)^2 = 1296
d(b) = 16(9.001)^2 = 1296.288016
Average speed = (1296.288016 - 1296)/(9.001 - 9) = 0.288016/0.001 = 288.016 ft/s

For the fifth time interval, t = a = 9 and t = b = 9.0001:
d(a) = 16(9)^2 = 1296
d(b) = 16(9.0001)^2 = 1296.0288016
Average speed = (1296.0288016 - 1296)/(9.0001 - 9) = 0.0288016/0.0001 = 288.016 ft/s

As the time intervals get smaller and smaller, the average speed approaches 288 ft/s.

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The maximum value of p is 107.09 and it is obtained when x = 1.44, y = 31.02, z = 0, and w = 0.

To maximize the objective function p = 6x + 9y + 3.3z + 12w

We can use the simplex method.

First, we need to convert the inequalities into equalities by introducing slack variables:

(a) 1.2x + y + z + w + s1 = 121.5

(b) 2x + y − z − w + s2 = 30

(c) 2x + y + z + 1.2w + s3 = 31.5

We can then write the augmented matrix for the problem:

x y z w s1 s2 s3       b

1.2 1 1 1 1 0 0             121.5

2 1 -1 -1 0 1 0               30

2 1 1 1 0 0 1                 31.5

-6 -9 -3.3 -12 0 0 0  0

We choose the most negative coefficient in the bottom row, which is -12. We then select the pivot element in the column corresponding to this coefficient, which is 121.5 in the first row. We perform row operations to make this pivot element equal to 1 and all other elements in its column equal to 0:

x y z w s1 s2 s3                                            b

1 0.83 0.17 0.33 0.67 -0.50 -0.17            100.67

0 0.17 -1.33 -1.33 -0.83 0.50 -0.17   12.33

0 0.17 0.33 0.33 -0.67 -0.50 0.83 10.17

0 -6.50 -12.90 -12.00 4.00 4.50 1.00 408.00

Next, we choose the most negative coefficient in the bottom row, which is -12.9. We select the pivot element in the column corresponding to this coefficient, which is 0.33 in the third row. We perform row operations to make this pivot element equal to 1 and all other elements in its column equal to 0:

x y z w s1 s2 s3                                           b

1 0.00 0.85 0.40 1.44 -0.54 -0.08  107.09

0 0.00 -1.22 -1.67 -1.00 0.38 0.08 -12.93

0 1.00 2.45 2.33 -2.00 1.50 0.33         31.02

0 0.00 -2.19 -5.60 10.00 10.50 1.83 630.00

The objective function value at this point is p = 107.09.

The solution is x = 1.44, y = 31.02, z = 0, w = 0, and the maximum value of p is 107.09.

Therefore, the maximum value of p is 107.09, when x = 1.44, y = 31.02, z = 0, and w = 0.

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The shopkeeper would have saved 4756.25 - 4260 = 496.25 shillings.

What is the linear equation?

A linear equation is an algebraic equation of the form y=mx+b. where m is the slope and b is the y-intercept. We have a graph.

Let the cost of one panga be x and one jembe be y.

From the given information, we can form the following equations:

50x + 30y = 4260 --- Equation 1

25x/2 + (30/2 - 5)y = 2970 --- Equation 2

50(1.25)x + 30(0.85)y = total cost from wholesaler B --- Equation 3

Simplifying equation 2:

25x/2 + 10y - 5y = 2970

25x/2 + 5y = 2970

25x + 10y = 5940

Simplifying equation 3:

62.5x + 25.5y = total cost from wholesaler B

To solve for x and y, we can use any method of our choice. For simplicity, we will use elimination:

Multiplying equation 1 by 5:

250x + 150y = 21300 --- Equation 4

Multiplying equation 2 by 2:

25x + 20y = 5940 --- Equation 5

Subtracting equation 5 from equation 4:

225x + 130y = 15360

Substituting the value of y from equation 5:

225x + 130(297 - 2.5x) = 15360

225x + 38610 - 325x = 15360

-100x = -23250

x = 232.5

Substituting the value of x in equation 1:

50(232.5) + 30y = 4260

y = 85

Therefore, the cost of one panga is 232.5 shillings and the cost of one jembe is 85 shillings.

To find out how much the shopkeeper would have saved if he had bought from wholesaler B, we need to calculate the total cost from wholesaler B:

50(1.25)(232.5) + 30(0.85)(85) = 4756.25

The total cost from wholesaler A was 4260 shillings.

Therefore, the shopkeeper would have saved 4756.25 - 4260 = 496.25 shillings.

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The given quadrilateral is a parallelοgram and a kite.

Quadrilaterals are pοlygοns that have fοur sides, fοur vertices, and fοur angles. They are twο-dimensiοnal shapes that can be classified based οn their prοperties, such as the lengths οf their sides, the measures οf their angles, and the presence οf parallel sides οr right angles. Sοme cοmmοn types οf quadrilaterals include:

Nοw,

Tο identify the type οf quadrilateral fοrmed by the vertices T(-3,-3), U(4, 4), V(0, 6), and W(-5, 1), we need tο first find the lengths οf the sides and the slοpes οf the segments cοnnecting the vertices.

Using the distance fοrmula, we get:

[tex]TU = \sqrt{[(4 - (-3))^2 + (4 - (-3))^2]} = \sqrt {[7^2 + 7^2]} = \sqrt{(98)[/tex]

[tex]UV = \sqrt{[(0 - 4)^2+ (6 - 4)^2]} = \sqrt{[(-4)^2 + 2^2]} = \sqrt{(20)[/tex]

[tex]VW = \sqrt{[(-5 - 0)^2 + (1 - 6)^2]}= \sqrt{[(-5)^2+ (-5)^2]} = \sqrt{(50)[/tex]

[tex]WT = \sqrt{[(-5 - (-3))^2+ (1 - (-3))^2]} = \sqrt{[(-2)^2 + 4^2]} = \sqrt{(20)[/tex]

Next, we can find the slοpes οf the segments:

TU: m = (4 - (-3))/(4 - (-3)) = 1

UV: m = (6 - 4)/(0 - 4) = -1/2

VW: m = (1 - 6)/(-5 - 0) = 1

WT: m = (1 - (-3))/(-5 - (-3)) = -1/2

Nοw we can use these measurements tο identify the type οf quadrilateral:

Oppοsite sides are parallel: VW and TU have slοpes οf 1 and slοpes οf -1 respectively. Therefοre, the quadrilateral is a parallelοgram.

Twο adjacent sides are cοngruent: TU and UV have lengths οf sqrt(98) and sqrt(20) respectively. Therefοre, the quadrilateral is nοt a rhοmbus.

Diagοnals bisect each οther: The diagοnals TV and UW intersect at (2, 1.5), which is the midpοint οf bοth diagοnals. Therefοre, the quadrilateral is a parallelοgram.

One pair οf οppοsite sides are perpendicular: The slοpes οf UV and WT are -1/2, and the prοduct οf their slοpes is -1. Therefοre, the quadrilateral is a kite.

All sides are cοngruent: The lengths οf the sides are nοt all equal. Therefοre, the quadrilateral is nοt a square.

Thus, the quadrilateral fοrmed by the given vertices is a parallelοgram and a kite.

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Answer: At a greengrocer, two bananas and one apple cost $1.16 .

Than the equation becomes

2x + y = 1.16

one banana and one apple cost 0.71.

Than the equation becomes

x + y = 0.71

Subtracting x + y = 0.71 from 2x + y = 1.16

2x - x + y - y = 1.16 - 0.71

x = 0.45

Put in the equation x + y = 0.71

0.45 + y = 0.71

y = 0.71 - 0.45

y = 0.26

The cost of the one apple is  0.26

Step-by-step explanation:

Answer:

See attached graph for the two functions

y = cos(x)

y = 0.5

Solution set for cos(x) i.e. the values of x for which cos(x) = 0.5 in the interval 0 < x < 2π are
{π/3, 5π/3)

or

{1.05, 5.24}  in decimal

Step-by-step explanation:

I moved the original horizontal up to y = 0.5

The solutions to the two equations are where the two functions intersect

There are two intersection in the interval 0 ≤ x ≤ 2π and are at the points labeled A and B

The two points can be obtained by setting
cos(x) = 0.5 and solving for x

cos(x) = 0.5

=> x = cos⁻¹ (0.5)

= 60° and 300° in the range 0 ≤ x ≤ 2π where 2π = 360°

In terms of π,

Since π radians = 180°, 1° = π/180 radians

60° = π/180 x 60 = π/3 radians

300° =  π/180 x 300 = 5π/3 radians

Therefore the solutions to cos(x) = 0.5 are
x = π/3 and x = 5π/3
The solution set is written as {π/3, 5π/3}

In decimal

π/3 = 1.04719 ≈ 1.05

5π/3 = 5.23598 ≈ 5.24

Solution set in decimal: {1.05, 5.24}

By deducting the value of the shortest distance from the value of the longest distance on the line plot, it is possible to determine the difference between the longest and shortest distances a student has walked to get to school.

We must look at the provided line plot to ascertain the difference between the longest and shortest distances a student walks to get to school. Ten pupils were tracked across various distances using a line plot. The location of each student is indicated by a "X" on the map.

Just looking for the X with the highest and lowest frequency will yield the longest and shortest lengths. According to the line plot, the distances at which Xs occur most frequently are 2 miles away and 0.5 miles away, respectively. As a result, there is a 1.5 mile discrepancy between the student's maximum walking distance (2 miles) and their shortest walking distance (0.5 miles).

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Answer:

50.2 is the answer as the answer came in point

The Answer:

The answer to the equation that Clare gets is:

X1= -3/2 + 7/2i , X2= -3/2 - 7/2i.

The Explanation:

4x^2+12x+58=0

2x^2+6x+29=0

a=2, b=6, c=29