Answer:
249.14 mm³
Step-by-step explanation:
r = diameter/2
= 7.8 /2
volume = 4/3 π r³
= 4/3 * 3.15 * (7.8/2)³
= 249.14 mm³
An octagonal pyramid ... how many faces does it have, how many vertices and how many edges? A triangular prism ... how many faces does it have, how many vertices and how many edges? a triangular pyramid ... how many faces does it have, how many vertices and how many edges?
1: 8 faces and 9 with the base 9 vertices and 16 edges
2: 3 faces and 5 with the bases 6 vertices and 9 edges
3: 3 faces and 4 with the base 4 vertices and 6 edges
Hope this can help you.
Given the function f(x) = 3x - 1, explain how to find the average rate of change between x = 1 and x = 4.
Step-by-step explanation:
f(1) = 3×1 - 1 = 2
f(4) = 3×4 - 1 = 12-1 = 11
so, the functional value changes 11-2=9 units on an x interval of 4-1=3 units length.
the average change rate is the total change across the x interval relative to the interval length.
that is
9/3 = 3
which is the slope (= the factor of x) in the line equation.
for a line its change rate for any point is the same constant. and that is therefore automatically also the average change rate across an interval of x values.
if the change rate would be different for different parts of the function, it would not be a straight line.
Answer:
3
Step-by-step explanation:
The average rate of f(x) in the closed interval [ a, b ] is
[tex]\frac{f(b)-f(a)}{b-a}[/tex]
Here [ a, b ] = [ 1, 4 ] , then
f(b) = f(4) = 3(4) - 1 = 12 - 1 = 11
f(a) = f(1) = 3(1) - 1 = 3 - 1 = 2
average rate of change = [tex]\frac{11-2}{4-1}[/tex] = [tex]\frac{9}{3}[/tex] = 3
giving brainliest to whoever finishes this correctly! :)
Give the domain and range.
x –2 0 2 y –1 0 1
a. domain: {2, 0, 2}, range: {1, 0, 1} b. domain: {–2, 0, 2}, range: {–1, 0, 1} c. domain: {–1, 0, 1}, range: {–2, 0, 2} d. domain: {1, 0, 1}, range: {2, 0, 2}
Answer:
B. domain {-2, 0, 2}, range {-1, 0, 1}
Step-by-step explanation:
The x values and y values as ordered pairs would be: (-2,-1), (0,0), (2,1)
The domain is the all of the values of x and the range is all the values of y.
Find the zeros of the quadratic function f(x) = 1/2(x- 7)^2 – 8
Answer:
x = 11 or 3
Step-by-step explanation:
f(x) = (1/2)(x- 7)² – 8
to find the zeros, we equate f(x) = 0
f(x) = 0
(1/2)(x- 7)² – 8 = 0 (add 8 to both sides)
(1/2)(x- 7)² = 8 (multiply both sides by 2)
(x- 7)² = (8)(2)
(x- 7)² = 16
x-7 = ±√16
x-7 = ±4
hence,
x - 7 = 4
x = 4 + 7
x = 11
or
x - 7 = -4
x = -4 +7
x = 3
Answer:
x = 11 or 3
Step-by-step explanation:
I confirmed the answer in grandpoint.
Find the largest integer which belongs to the following interval: (−∞, 8)
Answer:
7
Step-by-step explanation:
The following range includes numbers from negative infinity to 8. But, 8 isn't included, because there is a parentheses not a bracket. So, basically you can have 7.9999999. But, it asks for an integer, so it is 7.
The largest integer which belongs to the interval: (−∞, 8) is 7
To determine the largest integer, we will first ascertain what the use of parentheses and brackets denote.
The use of parentheses ( ) stands for open interval, that is, the extreme numbers of the set are not included.
If the brackets [ ] were used instead, that will be closed interval, that is, the extreme numbers of the set are included.
Since ( ) were used in the question, that means the extreme numbers −∞ and 8 are NOT included in the set.
Now, let us define an integer.
An integer is a positive or negative whole number or zero.
Hence, the integers in the set will include: −∞+1, −∞ + 2, ... 5, 6, and 7.
The largest integer here is 7
Hence, the largest integer which belongs to the interval: (−∞, 8) is 7
Learn more in the link below:
https://brainly.com/question/13324131
The line perpendicular to y=3/4x+7 containing (3,-4)
Answer:
y = - [tex]\frac{4}{3}[/tex] x
Step-by-step explanation:
1). [tex]y_{1}[/tex] = [tex]m_{1}[/tex] [tex]x_{1}[/tex] + [tex]b_{1}[/tex]
[tex]y_{2}[/tex] = [tex]m_{2}[/tex] [tex]x_{2}[/tex] + [tex]b_{2}[/tex]
[tex]y_{1}[/tex] ⊥ [tex]y_{2}[/tex] if [tex]m_{2}[/tex] = - [tex]\frac{1}{m_{1} }[/tex]
2). ( [tex]x_{3}[/tex] , [tex]y_{3}[/tex] )
y - [tex]y_{3}[/tex] = m( x - [tex]x_{3}[/tex] )
~~~~~~~~~~~~~~~~~~
y = [tex]\frac{3}{4}[/tex] x + 7
[tex]m_{1}[/tex] = [tex]\frac{3}{4}[/tex]
[tex]m_{2}[/tex] = - [tex]\frac{4}{3}[/tex]
( 3, - 4 )
y - ( - 4) = - [tex]\frac{4}{3}[/tex] ( x - 3 )
y + 4 = - [tex]\frac{4}{3}[/tex] x + 4
y = - [tex]\frac{4}{3}[/tex] x
Judy got 27 546 points and 34 668 points in the first two rounds of a
game. How many points did Judy get in all?
Answer:
62 214Step-by-step explanation:
Given,
Points got by Judy in 1st round = 27 546
Points got by Judy in 2nd round = 34 668
Therefore,
Total points Judy got in the first two rounds
= 27 546 + 34 668
= 62 214 (Ans)
what song goes whoooooo Iiiiii smoooooooooke
Answer:
Lol yu lateee das "who i smoke by yung ace"
Step-by-step explanation:
Answer:
woogle said woo hoo by rock a teens
Step-by-step explanation:
a department store regularly sells a pair of pants for $49.95. they are having a sale where clothing 30% off.
after including an 8% sales tax, how much do the pants cost on sale?
A. $30.97
B. $38.96
C. $37.76
D. $32.17
Answer:
C. $37.76
Step-by-step explanation:
30% of $49.95
=30/100×49.95
=$14.99
selling price = 49.95 -14.99
= $34.96
8% sales tax included
=8/100×34.96
=$2.80
new price= 34.96+2.80
=$37.76
Please find the answer !
Answer:
ring volume is 12cm3
Step-by-step explanation:
Lr ccm=volume of water and ring - Volume of water
ring cubic centimeters =x
x=9.2cm*4.5cm*7cm - 8.8cm*4.5cm*7cm
x=289.2cm3 - 277.2cm3
x=12cm3
the diameter of Earth's moon is on average 3.8 x 10^8m. Use the formula A=4π² to find the approximate surface area. (Use 3.14 for the value of π)
Answer:
The answer is
[tex]A = 4.53 \times {10}^{17} \: {m}^{2} [/tex]
Step-by-step explanation:
Since the Earth's moon is a sphere
Surface area of a sphere from the question is given by
A = 4πr²
where r is the radius
To find the radius using the diameter we use the formula
radius = diameter / 2
[tex]radius \: = \frac{3.8 \times {10}^{8} }{2} [/tex]
[tex]radius = 1.9 \times {10}^{8} \: m[/tex]
π = 3.14
Substitute these values into the above formula
That's
[tex]A = 4 \times 3.14 \times ({1.9 \times {10}^{8} })^{2} [/tex]
We have the final answer as
[tex]A = 4.53 \times {10}^{17} \: {m}^{2} [/tex]
Hope this helps you
If a textbook costs £7.80, how many can be bought for £101.40?
Answer:
13 textbook can buy.
Step-by-step explanation:
13 textbook can buy.
Divide total by price per book:
101.40 / 7.80 = 13
13 books can be bought
-58.58 is equal to the rational number
Answer:
This is true
Step-by-step explanation:
Because a rational number can be expressed as going on forever.
Question
Consider this expression.
4/2² - 6²
Type the correct answer in the box. Use numerals instead of words. For help, see this worked example e.
When a =
-5 and b = 3, the value of the expression is
Submit
Answer:
16
Step-by-step explanation:
4 * sqrt( a^2 - b^2)
Let a = -5 and b =3
4 * sqrt( (-5)^2 - 3^2)
Do the squaring first
4 * sqrt( 25 - 9)
Subtract inside the square root
4 * sqrt( 16)
Take the square root
4 * 4
Multiply 16
Answer:
[tex]\Large \boxed{16}[/tex]
Step-by-step explanation:
[tex]4\sqrt{a^2-b^2 }[/tex]
[tex]\sf Plug \ in \ the \ values \ for \ a \ and \ b.[/tex]
[tex]4\sqrt{-5^2-3^2 }[/tex]
[tex]4\sqrt{25-9 }[/tex]
[tex]4\sqrt{16}[/tex]
[tex]4 \times 4=16[/tex]
The number of times a player has golfed in one's lifetime is compared to the number of strokes it takes the player to complete 18 holes. The correlation coefficient relating the two variables is -0.26. Which best describes the strength of the correlation and what is true about the causation between the variables?
Answer: It is a weak negative correlation and it is not likely causal.
Step-by-step explanation:
Given: The number of times a player has golfed in one's lifetime is compared to the number of strokes it takes the player to complete 18 holes. The correlation coefficient relating the two variables is -0.26.
Variables : "number of times a player has golfed in one's lifetime" and "number of strokes it takes the player to complete 18 holes".
Since -0.26 is more closer to 0 as compared to 1 , so it describes a weak negative correlation.
Also, it is not likely causal as number of times a player has golfed in one's lifetime not cause number of strokes it takes the player to complete 18 holes.
Answer: B) It is a weak negative correlation, and it is likely casual
Correct on edge 2020!
[tex]log(x) * log(2)[/tex]
Why can't this problem be solved?
Answer:
Because it is not an equation.
Step-by-step explanation:
[tex] log(x) \times log(2) \\ = log(x + 2) [/tex]
Using Normal Distribution, what is the area to the right of 0.72 under the
standard normal curve?
Answer: 0.2358
Step-by-step explanation:
Using Normal Distribution, under the standard normal curve
The area to the right of z is given by P(Z>z)=1-P(Z<z)
So, the area to the right of z= 0.72 under the standard normal curve would be:
P(Z>0.72)=1-P(z<0.72)
=1-0.7642 [By using p-value table]
= 0.2358
Hence, the area to the right of z= 0.72 under the standard normal curve is 0.2358 .
find the length of the arc . round your answers to the nearest tenth PLEASE HURRY
Answer:
10.2
Step-by-step explanation:
Length of arc=(2*pi*r)*(theta/360)
Length of arc=(2*pi*3)*(195/360)=10.2
Find the first, second, third and fourth order Maclaurin polynomials of f(x) =
arctan(x). Draw the graph of f(x) and the four polynomials on the same
diagram. (Sketch by hand or use software.)
#urgent please give me this answer and help me#
The first, second, third and fourth order Maclaurin polynomials of f(x)=arctan(x) are:
The first order Maclaurin polynomial is f(x)=xThe second order Maclaurin polynomial is also f(x)=xThe third order Maclaurin polynomial is [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]The fourth order Maclaurin polynomial is also [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]You can see the graph on the attached picture.So let's start by finding the first order maclaurin polynomial:
f(x)=f(0)+f'(0)x
so let's find each part of the function:
f(0)=arctan(0)
f(0)=0
now, let's find the first derivative of f(x)
f(x)=arctan(x)
This is a usual derivative so there is a rule we can use here:
[tex]f'(x)=\frac{1}{x^{2}+1}[/tex]
so now we can find f'(0)
[tex]f'(0)=\frac{1}{(0)^{2}+1}[/tex]
f'(0)=1
So we can now complete the first order Maclaurin Polynomial:
f(x)=0+1x
which simplifies to:
f(x)=x
Now let's find the second order polynomial, for which we will need to get the second derivative of the function:
[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}[/tex]
so:
[tex]f'(x)=\frac{1}{x^{2}+1}[/tex]
we can rewrite this derivative as:
[tex]f'(x)=(x^{2}+1)^{-1}[/tex]
and use the chain rule to get:
[tex]f''(x)=-1(x^{2}+1)^{-2}(2x)[/tex]
which simplifies to:
[tex]f''(x)=-\frac{2x}{(x^{2}+1)^{2}}[/tex]
now, we can find f''(0):
[tex]f''(0)=-\frac{2(0)}{((0)^{2}+1)^{2}}[/tex]
which yields:
f''(0)=0
so now we can complete the second order Maclaurin polynomial:
[tex]f(x)=0+1x+\frac{0}{2!}x^{2}[/tex]
which simplifies to:
f(x)=x
Now let's find the third order polynomial, for which we will need to get the third derivative of the function:
[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{f'''(0)}{3!}x^{3}[/tex]
so:
[tex]f''(x)=-\frac{2x}{(x^{2}+1)^{2}}[/tex]
In this case we can use the quotient rule to solve this:
Quotient rule: Whenever you have a function in the form , then it's derivative is:
[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]
in this case:
p=2x
p'=2
[tex]q=(x^{2}+1)^{2}[/tex]
[tex]q'=2(x^{2}+1)(2x)[/tex]
[tex]q'=4x(x^{2}+1)[/tex]
So when using the quotient rule we get:
[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]
[tex]f'''(x)=\frac{(2)(x^{2}+1)^{2}-(2x)(4x)(x^{2}+1)}{((x^{2}+1)^{2})^{2}}[/tex]
which simplifies to:
[tex]f'''(x)=\frac{-2x^{2}-2+8x^{2}}{(x^{2}+1)^{3}}[/tex]
[tex]f'''(x)=\frac{6x^{2}-2}{(x^{2}+1)^{3}}[/tex]
now, we can find f'''(0):
[tex]f'''(0)=\frac{6(0)^{2}-2}{((0)^{2}+1)^{3}}[/tex]
which yields:
f'''(0)=-2
so now we can complete the third order Maclaurin polynomial:
[tex]f(x)=0+1x+\frac{0}{2!}x^{2}-\frac{2}{3!}x^{3}[/tex]
which simplifies to:
[tex]f(x)=x-\frac{1}{3}x^{3}[/tex]
Now let's find the fourth order polynomial, for which we will need to get the fourth derivative of the function:
[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{f'''(0)}{3!}x^{3}+\frac{f^{(4)}(0)}{4!}x^{4}[/tex]
so:
[tex]f'''(x)=\frac{6x^{2}-2}{(x^{2}+1)^{3}}[/tex]
In this case we can use the quotient rule to solve this:
[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]
in this case:
[tex]p=6x^{2}-2[/tex]
p'=12x
[tex]q=(x^{2}+1)^{3}[/tex]
[tex]q'=3(x^{2}+1)^{2}(2x)[/tex]
[tex]q'=6x(x^{2}+1)^{2}[/tex]
So when using the quotient rule we get:
[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]
[tex]f^{4}(x)=\frac{(12x)(x^{2}+1)^{3}-(6x^{2}-2)(6x)(x^{2}+1)^{2}}{((x^{2}+1)^{3})^{2}}[/tex]
which simplifies to:
[tex]f^{4}(x)=\frac{12x^{3}+12x-6x^{3}+12x}{(x^{2}+1)^{4}}[/tex]
[tex]f^{4}(x)=\frac{6x^{3}+24x}{(x^{2}+1)^{4}}[/tex]
now, we can find f^{4}(0):
[tex]f^{4}(x)=\frac{6(0)^{3}+24(0)}{((0)^{2}+1)^{4}}[/tex]
which yields:
[tex]f^{4}(0)=0[/tex]
so now we can complete the fourth order Maclaurin polynomial:
[tex]f(x)=0+1x+\frac{0}{2!}x^{2}-\frac{2}{3!}x^{3}+\frac{0}{4!}x^{4}[/tex]
which simplifies to:
[tex]f(x)=x-\frac{1}{3}x^{3}[/tex]
you can find the graph of the four polynomials in the attached picture.
So the first, second, third and fourth order Maclaurin polynomials of f(x)=arctan(x) are:
The first order Maclaurin polynomial is f(x)=xThe second order Maclaurin polynomial is also f(x)=xThe third order Maclaurin polynomial is [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]The fourth order Maclaurin polynomial is also [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]You can find further information on the following link:
https://brainly.com/question/17440012?referrer=searchResults
Line l has a slope of −6/13. The line through which of the following pair of points is perpendicular to l? A. (13,−4),(−7,2) B. (6,−4),(−7,2) C. (2,6),(−4,−7) D. (6,9),(−4,−4)
=========================================================
Explanation:
The original line has a given slope of -6/13. The opposite reciprocal is 13/6. We flip the fraction and the sign from negative to positive.
With any two perpendicular slopes, they always multiply to -1
(-6/13)*(13/6) = (-6*13)/(13*6) = -78/78 = -1
--------------------
Since the perpendicular slope is 13/6, we need to see which of the four answer choices produces a slope of 13/6. Use the slope formula.
This is something you do through trial and error. You could start with A and work your way to D, or just pick at random. I'll go through each one by one starting at choice A.
---------------------
Let's try choice A
m = (y2 - y1)/(x2 - x1)
m = (2 - (-4))/(-7 - 13)
m = (2 + 4)/(-7 - 13)
m = 6/(-20)
m = -3/10, we can see that choice A is not the answer, since we want m = 13/6 instead.
-----------------------
Let's try choice B
m = (y2 - y1)/(x2 - x1)
m = (2 - (-4))/(-7 - 6)
m = (2 + 4)/(-7 - 6)
m = 6/(-13)
m = -6/13, that doesn't work either
------------------------
Let's try choice C
m = (y2 - y1)/(x2 - x1)
m = (-7 - 6)/(-4 - 2)
m = -13/(-6)
m = 13/6, we found the answer
------------------------
For the sake of completeness, here is what choice D would look like
m = (y2 - y1)/(x2 - x1)
m = (-4 - 9)/(-4 - 6)
m = -13/(-10)
m = 13/10, which isn't the slope we want
PLEASE HELP!!! (1/5) - 50 POINTS-
Answer:
consistent independent
Step-by-step explanation:
This is a graph of consistent independent equations
The lines cross and there is one solution
Inconsistent equations never cross and there is no solutions
Consistent dependent equations are equations of the same line
Answer:
Linear
Step-by-step explanation:
This is a graph of linear system of equation.
The two lines represent different equations connected with each other.
They intersect at a common point showing the solution to the system of equation.
If a system of linear equations has no solution, what does this mean about the two lines?
Answer:
The two lines do not intersect, and are parallel to one another on a graph.
Step-by-step explanation:
A system of equations consists of two or more equations with two or more variables. The solution to these variables must satisfy all of the variables in the equations in the system at the same time. Usually, all the equations in the system are considered and solved simultaneously. A linear equation might have a unique solution, an infinite solution, or no solution at all.
A system with exactly one solution is called a consistent system, and it is said to be independent, and the graph of its lines intersects at the point that is the solution to the equations. A system with an infinite number of solution is said to be dependent and the lines are coincident on a graph.
If a system has no solution, it is said to be inconsistent . The graphs of the lines do not intersect, and the lines are parallel to one another on the graph.
For two lines of linear equations to have no solution, they must be parallel to each other i.e they must have the same slope.
The standard form of writing linear equation is expressed as y = mx + b
m is the slope of the line
b is the y-intercept
For two lines of linear equations to have no solution, they must be parallel to each other i.e they must have the same slope.
For instance, the system of equations y = 2x + 7 and y = 2x - 3 have no solutions because they have the same slope.
Learn more on system of equation here: https://brainly.com/question/12526075
Simplify your answer as much as possible.
Which option is correct and how would one solve for it?
Answer:
28
Step-by-step explanation:
We need to find the value of [tex]\Sigma_{x=0}^3\ 2x^2[/tex]
We know that,
[tex]\Sigma n^2=\dfrac{n(n+1)(2n+1)}{6}[/tex]
Here, n = 3
So,
[tex]\Sigma n^2=\dfrac{3(3+1)(2(3)+1)}{6}\\\\\Sigma n^2=14[/tex]
So,
[tex]\Sigma_{x=0}^3\ 2x^2=2\times 14\\\\=28[/tex]
So, the value of [tex]\Sigma_{x=0}^3\ 2x^2[/tex] is 28. Hence, the correct option is (d).
What is 40 % of 50?????????????????????????????????????/
Answer:
20
Step-by-step explanation:
Of means multiply
40% * 50
Change to decimal form
.40 * 50
20
Can somebody help me please?
Answer:
[tex]\boxed{x \geq 353}[/tex]
Step-by-step explanation:
Hey there!
Info Given
- Dot is solid
- Line goes to the right
- Dot is at 353
So by using the given info we can conclude that the inequality is,
x ≥ 353
Hope this helps :)
Answer:
Inequality: 100 + 50w ≥ 18000
What to put on graph: w ≥ 358
Assume that a random sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level.
Answer:
Margin of Error = z∝/2 * Standard Error
Step-by-step explanation:
The formula for standard error is given by
SE = [tex]\sqrt{\frac{pq}{n} }[/tex]
Where p is the probability or proportion of success q=1-p and n is the number of trials or samples.
Now Margin of Error is given by
ME = z∝/2 * Standard Error
The confidence level is used to estimate the value of alpha.
For example 90% confidence means alpha= 1-0.9= 0.1 and alpha by 2 would be 0.05 . So the value for alpha by 2 would be 1.96
Transform the Cartesian (rectangular) equation to a polar equation: x = -9. The selected answer is incorrect.
Answer:
Solution : Option C
Step-by-step explanation:
We have the equations r² = x² + y², x = r cos(θ), and y = r sin(θ) that can be used to solve this problem. In this case we only need the second two equations ( x = r cos(θ), and y = r sin(θ) ) as we don't need to apply the concept of circles etc here.
Given : x = - 9,
( Substitute r cos(θ) for x )
r cos(θ) = - 9,
r = - 9 / cos(θ)
( Remember that sec is the reciprocal of cos(θ). Substitute sec for 1 / cos(θ) )
r = - 9 sec(θ)
Therefore the third option is the correct solution.
A hunter shot 7 ducks. The hunter's dog recovered 5/7 of the ducks. How many ducks were recover
Answer:
5
Step-by-step explanation:
Just multiply 5/7 by 7 since his dog retrieved 5/7 out of the 7 ducks he shot.
Answer:
5
Step-by-step explanation:
7*5/7
7 represents the # of ducks
5/7 represents the # of ducks that were recovered
The question asks the number of ducks that were recovered so you should multiply the total # of ducks there are by the fraction that were recovered.