the diagram above shows a uniform metre rule, X Y which is balance horizontally at the 90cm mark, when a mass of 0.4kg is suspended from Y. what is the mass of the metre rule​

The Diagram Above Shows A Uniform Metre Rule, X Y Which Is Balance Horizontally At The 90cm Mark, When

Answers

Answer 1

Answer:

0.1 Kg

Explanation:

Please see attached photo for explanation.

In the attached photo, M is the mass of the metre rule.

From the attached photo,

Anticlock wise moment = M × 40

Clockwise moment = 0.4 × 10

Anticlock wise moment = Clockwise moment

M × 40 = 0.4 × 10

M × 40 = 4

Divide both side by 40

M = 4 / 40

M = 0.1 Kg

Thus, the mass of the metre rule is 0.1 Kg

The Diagram Above Shows A Uniform Metre Rule, X Y Which Is Balance Horizontally At The 90cm Mark, When

Related Questions

A student is giving a presentation to a class describing magnetic and electric fields in a region of space. First, the student describes what happens when there is a constant magnetic field in the region of space. Then, the student describes what happens when there is a time-dependent magnetic field in the region of space. Which of the following a correct description by the student abo what occurs when the magnetic field changes from being constant to being time dependent?
a. When the magnetic field is constant, there is only a magnetic field in the region of space. When the magnetic field is time dependent, there will be both a magnetic field and an electric field in the region of space.
b. When the magnetic field is constant, there will be both a magnetic field and an electric field in the region of space. When the magnetic field is time dependent, there is only a magnetic field in the region of space.
с. In both situations, there will be both a magnetic field and an electric field in the region of space. In both situations, there will only be a magnetic field in the region of space. If the magnetic field is not constant over the region, then there will be both a magnetic field and an electric field in the region of space
d. In both situations there will only be a magnetic field in the region of space. If the magnetic field is not constant over the region, there will still be only a magnetic field in the region of space.

Answers

Answer:

a. When the magnetic field is constant, there is only a magnetic field in the region of space. When the magnetic field is time dependent, there will be both a magnetic field and an electric field in the region of space.

Explanation:

This is true because according to Maxwell's equation, a time dependent magnetic field produces an electric field.

When the magnetic field is constant, there is no electric field in that region of space. But, when it begins to vary, an electric field is then generated by Maxwell's equation which is given by

CurlE = -dB/dt

So, there is initially no electric field when the magnetic field is constant, but it exists when the magnetic field becomes time dependent.

So when dB/dt = 0

CurlE = 0 ⇒ E = 0

So when dB/dt ≠ 0

CurlE ≠ 0 ⇒ E ≠ 0

Radioactive isotopes are used in medicine to create images of internal
structures of the human body. What process is used to create theses
isotopes?
A. Gamma decay
B. Fusion
C. Alpha decay
D. Fission

Answers

Answer:

The correct option is D) Fission

Explanation:

There are several methods through which Radioactive isotopes are created.

Using a nuclear reactor that has a field of neutrons, insert a stable sample such as Lutetium-176. When it gets bombarded with neutrons, it acquires some, and fission is said to have occurred. Note that when Lutetium-176 acquires a neutron, it becomes radioactive Lu-177. Fission is also used to create Fluorine-18. To obtain the same, you need to bombard pure or enriched [[tex]^{18} O[/tex]] water with ~18 MeV protons which are high energy in nature. The bombarding is achieved using a cyclotron or an accelerator.

Cheers

A transparent oil with index of refraction 1.15 spills on the surface of water (index of refraction 1.33), producing a maximum of reflection with normally incident violet light (wavelength 400 nm in air). Assuming the maximum occurs in the first order, determine the thickness of the oil slick.

Answers

Answer:

The thickness of the oil slick. t = 173.91 nm

Explanation:

Oil film thickness t is given by the equation

[tex]t = \frac{\lambda}{2n}[/tex]

where λ = wavelength of incident light in air = 400 nm

and n = index of refraction of oil

therefore,

[tex]t =\frac{400}{2\times 1.15}\\t= 173.91 nm[/tex]

The thickness of the oil slick. t = 173.91 nm

Transverse wave is an example of mechanical wave which requires a medium Which statement BEST describes the movement of transverse waves with reference to the direction of its travel? to propagate. a. The individual particles mo ve in a circle. b. Th e individual particles move in an ellipse. c. The individual particles move parallel to the direction of ravel. d. The individual particles move perpendicular to the direction of travel.

Answers

Answer:

d) the individual particles move perpendicular to the direction of travel

Calculate the workdone to stretch an elastic string by 40cm if a force of 10 newton produces an extension of 4cm in it

Answers

Answer:

Workdone = 20 Joules

Explanation:

Given the following data;

Force = 10N

Extension, e = 4cm to meters = 4/100 = 0.04 meters

Workdone extension = 40cm to meters = 40/100 = 0.4 meters

To find the work done;

First of all, we would find the spring constant using the formula;

Force = spring constant * extension

10 = spring constant * 0.04

Spring constant = 10/0.04

Spring constant = 250 N/m

Next, we find the work done;

Workdone = ½ke²

Where;

k is the spring constant.

e is the extension.

Substituting into the formula, we have;

Workdone = ½ * 250 * 0.4²

Workdone = 125 * 0.16

Workdone = 20 Joules

Determine the angle between the directions of vector A with rightwards arrow on top = 3.00i + 1.00j and vector B with rightwards arrow on top = -3.00i + 3.00j.

A) 117°


B) 88.1°


C) 26.6°


D) 30.0°


E) 45.2°

Answers

Answer:

C) 26.6

Explanation:

I don't know how to calculate vector

The angle between the two vectors is 117⁰

The given parameters;

vector A = 3.00i + 1.00j

vector B = -3.00i + 3.00j

The  angle between the two vectors is calculated as follows;

[tex]cos \ \theta = \frac{A\ . \ B}{|A| \ . \ |B|}[/tex]

The dot product of vector A and B is calculated as;

[tex]A \ . \ B = (3i \ + j) \ . \ (-3i \ + 3j) = (3\times -3) + (1 \times 3) = -9 + 3 =- 6[/tex]

The magnitude of vector A and B is calculated as;

[tex]|A| = \sqrt{3^2 + 1^2} = \sqrt{10} \\\\|B| = \sqrt{(-3)^2 + (3)^2} = \sqrt{18}[/tex]

The  angle between the two vectors is calculated as;

[tex]cos \ \theta = \frac{-6}{\sqrt{10} \ . \sqrt{18} } \\\\cos \ \theta = \frac{-6}{\sqrt{180} } \\\\cos \ \theta = -0.4472\\\\\theta = cos \ ^{-1} (-0.4472) \\\\\theta = 116.6^0 \approx 117^0[/tex]

Thus, the angle between the two vectors is 117⁰

Learn more here: https://brainly.com/question/15006306


A roller coaster does a loop de loop at 35 m/s, with a radius of 32 meters. What is the
acceleration?

Answers

Answer:

The answer to the question is:

[tex]38.28 m {s}^{ - 2} [/tex]

The acceleration of the roller coaster is 38.28 m/s.

What is centripetal acceleration?

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.

Given that: the speed of the  roller coaster: v = 35 m/s.

Radius of the loop: r = 32 meter.

Centripetal acceleration of the roller coaster = speed²/radius

= (35×35)/32 m/s²

= 38.28 m/s².

Learn centripetal acceleration here:

https://brainly.com/question/14465119

#SPJ2

Which of the following is true of a boat moving on water with
no net force acting on it?*
A. It is rising with increasing speed.
B. It is sinking with increasing speed.
C. It is traveling at a constant velocity.
D. It is accelerating forward.

Answers

Your answer is D it is accelerating forward
the answer is D since there is no net force touching or acting upon it

Which point has more gravitational potential energy?






How is the energy changing in the picture

Answers

Point A has more gravitational potential because that energy is the energy stored in an object in this case the pencil and it is in a vertical position and it is off the ground cause it to have height. And the energy in the picture changed because the pencil will soon drop to the ground

The diagram shows four locations in the electric field of a positive point charge.

A positively charged particle has vectors perpendicular to the surface and pointing laterally outward. The vectors farther from the surface are shorter. There are 4 dots to the right of the positively charged particle. The closest to the particle is labeled W and the particles further away are labeled X, Y and Z.

At which point is the electric potential the greatest?

W
X
Y
Z

Answers

Answer:

W

Explanation:

The closer you get to the center of the positive point of the electrical feild the stronger the pull gets. Therfore W is the best option.

Answer:

W

Explanation:

The closer you get to the center of the positive point of the electrical feild the stronger the pull gets. Therfore W is the best option.

how does gravity affect objects of different mass close to earth, and how does that effect change as an object moves farther from earth?

Answers

Answer:

It makes it lighter when its closer and heavier when its farther way.

Explanation:

[3]2] Resistors X and Y are connected in series with a 6.0 V battery of negligible intemal
resistance.
R

X has resistance R and Y has resistance > .
A voltmeter of resistance R is connected across Y.

x

6ov |
Y
h
What is the reading on the voltmeter?
[1 mark]

A00V [Le]
B15V [e]
C 3.0V [=]
D45V fe] \

Answers

Using ohm's law and the characteristics of series and parallel circuits, we find that the correct answer is B: Voltage on the voltmeter 1.5 V

given parameters

    * The element X has a resistance Rₓ = R

    * Element Y with resistance R_y = R / 2

     * The voltmeter with internal resistance R_v = R

    * Battery voltage V = 6V

    * the circuit is in the diagram

To find

     The Voltmeter reading.

For this exercise we use ohm's law which establishes a linear relationship between voltage and current

      V = i R

Let's solve the circuit in parts:

1 part.  We reduce the part in parallel, finding its equivalent resistance

            R_ {eq1}

The equivalent resistance between Y element and the voltmeter that is in parallel, therefore their equivalent resistance is

         [tex]\frac{1}{R_{eq1} } = \frac{1}{R_y} + \frac{1}{R_v}[/tex]

         [tex]\frac{1}{R_{eq1} }= \frac{1}{\frac{R}{2} } + \frac{1}{R} = \frac{3}{R}[/tex]

         [tex]R_{eq1} = \frac{R}{3}[/tex]

Now element X and this equivalent resistance are in series ( see attached), so the equivalent resistance of the entire circuit is

        R_{eq} = Rₓ + R_{eq1}

         

we substitute

       R_{eq} = [tex]R + \frac{R}{3} = \frac{4}{3} \ R[/tex]

2 part. We look for the current of the circuit, usin the ohm's Law

        V = i R_{eq}

        i = [tex]\frac{V}{R_{eq} }[/tex]

        i = [tex]\frac{6}{\frac{4R}{3} } = \frac{18}{4R}[/tex]

        i = 4.5 / R

In a series circuit the current is constant and the total voltage is the sum voltage of each element, so the voltage in the parallel R_{eq1}

        V₂ = I R_{eq1}

        V₂ = [tex]\frac{4.5}{R} \ \frac{R}{3}[/tex]4.5 / R R / 3

        V₂ = 1.5 V

3 part. The voltmeter and the Y element  are in parallel, so the voltage in the two elects is the same,  consequently the voltage of the voltmeter (V_v)

          V_v = V₂ = 1.5 V

Using ohm's law and the properties of series and parellel circuits we find the voltage across the voltmeter

           V_v = 1.5 V

To learn about series and parallel circuits here:  brainly.com/question/11409042

PLEASE HELP MEE PLEASE!​

Answers

Answer:

Answer C. grams

Explanation:

I hope you like it

Types of telescope
for Space
observation​

Answers

Answer:The three main types are reflecting telescopes, refracting telescopes, and catadioptric telescopes. Radio telescopes collect and focus radio waves from distant objects. Space telescopes orbit Earth, collecting wavelengths of light that are normally blocked by the atmosphere.

Answer:

oii me manda mensagem fofo vc tem namorada fofo

A uniform ladder of length 10.8 m is leaning against a vertical frictionless wall. The weight of the ladder is 323 N, and it makes an angle of 1.16 radians with the floor. A man weighing 734 N climbs slowly up the ladder. When he has climbed to a point that is 7.46 m from the base of the ladder (measured along the ladder), the ladder starts to slip. Find the coefficient of static friction between the floor and the ladder.

Answers

Answer:

0.3625

Explanation:

From the given information:

Consider the equilibrium conditions;

On the ladder, net torque= 0

Thus,

[tex]\tau_{net} = 0[/tex]; and

[tex]-fL \s in \theta +m_L g \dfrac{L}{2} cos \theta + mg (7.46\ m) cos \theta = 0[/tex]

However, by rearrangement;

[tex]fL \s in \theta =m_L g \dfrac{L}{2} cos \theta + mg (7.46\ m) cos \theta \\ \\ \mu(m_L + m) gL \ sin \theta = (323 \ N) ( 10.8 \ meters) \ cos 56^0 + (734 \ N) (7.46 \ m) \ cos \ 66.46^0[/tex]

[tex]\mu= \dfrac{ (323 \ N) ( 10.8 \ m) \ cos 56^0 + (734 \ N) (7.46 \ m) \ cos \ 66.46^0}{\Big [(323 \ N)+(734 \ N) \Big] (10.8 \ m)}[/tex]

[tex]\mathbf{\mu= 0.3625 }[/tex]

Scenario
In a game of football player theme running and each other A wider running out with lotyy. A du x ahead the wide receivers a comeback heading directly towards him at a different below . The wide role and comeback continue running toward each other ar constant spend The location where the cornerback tackle the wide receiver, la moured from the wide recer initial position
Draw a diagram of the situation described above.

Answers

Answer:

hello your question is poorly written and I have tried to understand it hence I will give a general diagram as related to your question

answer : attached below

Explanation:

Attached below is the required diagram of the situation you are trying to describe

let the wide receiver be ; W

Corner back = C

westward velocity = Vw

eastward velocity = Vc

at initial position  X = Xw

x = 0 ( initial position )

please help me with this! i will give brainliest if you get it right! NO LINKS OR IM REPORTING

Answers

Number 7 is no motion

Anatomy and Phys PLEASE HELP

Identify at least two STDs that are caused by different microorganisms (such as bacteria, viruses, and so on). Propose at least two ethical strategies for helping to prevent these STDs OTHER THAN abstinence and male and female condoms.

Answers

         

                  least two STDs that are caused by different microorganisms (such as bacteria, viruses, and so on). Propose at least two ethical strategies for helping to prevent these STDs OTHER THAN abstinence and male and female condoms.

Answer:

Explanation:

Chlamydia is a bacterial infection that affects the reproductive system in a myriad of nasty and invasive ways, including pain during micturition, genital discharge, and spreading to the rectum and eyes. Other than safe sex practices and abstinence, ways to prevent and treat Chlamydia are antibiotics for both partners (if they're both infected) and surgical intervention in severe cases.

Trichomoniasis is a parasitic sexually transmitted disease that infects women but can affect men during intercourse, women who are infected are more likely to suffer from pain in the vaginal area during moments including micturition and intercourse as foul-smelling discharge. The more concerning aspect of this disease is how women afflicted are more likely to give premature birth and spread the infection to the baby upon birth. Much like Chlamydia, Trichomoniasis can be prevented via safe-sex practices and abstinence, but it can also be treated by antibiotics for both sexual partners to prevent spreading it between them.

The environment of Ecology is made up of how many levels?

Answers

Answer:

There are 5 general layers; organism, population, community, ecosystem, and biosphere.

Explanation:

Hope this helps!

A positively charged particle travels horizontally northward and enters a region where a field may exist. This region may contain only a magnetic field, only an electric field, or both a magnetic field and an electric field. When the particle enters the region, the particle does not speed up or slow down, but it does deflect in the downward direction. What is correct about the field or fields within the region and provides correct reasoning?

Answers

Answer:

Only magnetic field present

Explanation:

Since, the positively charged particle does not speed up or slow down, but it does deflect in the downward direction.  This means only magnetic field is present.

This is because electric field changes the velocity and magnetic field changes the direction.

The magnetic force F is given by

F = qvBsinθ

Where, q = charge magnitude, v = velocity of charge, B = strength of magnetic field. and θ =the angle between the directions of v and B.

In this equation, what shows that transmutation has taken place?
242 Cm – 328 Pu + He
A. There is conservation of both nucleons and atoms.

B. The nucleus of an atom changes

C. It involves more than one element

D. The number of atoms is conserved,but the number of nucleons is not

Answers

I think it’s D but most likely A
It’d mostly A I think

6. A barber raises his customer's chair by applying a force of 150 N to the
hydraulic piston of area 0.01 m2. If the chair is attached to a piston with an
area of 0.1 m², how much force is needed to raise the customer?
STEP 1: List the known
and unknown values F =
A=
A,
STEP 2: Write the
correct equation
STEP 3: Insert the
known values into the
equation to solve for
the unknown value

Answers

Answer:

15N

Explanation:

F¹=150N

A=0.01m2²

F2=?

A2=0.1m²

P=F/A

F1/A2=F2/A1

150/0.1=F2/0.01

please help with both questions I’m giving all my points :) it’s 23 and 24

Answers

Sorry just need points

X-rays have wavelengths between 0.1 to 10 nanometers (x10-9). What is the range of its frequency?
3x1017-3x1015 Hz
3x10, 18, -3x10, 16, Hz
3x1018-3x1017 Hz
3x1017-3x1016 Hz

Answers

The 2nd one I think

helpppppppppppppppppppppppppppp............



an object is moving with initial velocity of 5 m/s. After 10 seconds final velocity is 10 m/s. Calculate its acceleration.​

Answers

Answer:

0.5 m/s 2 is the acceleration

Explanation:

hope it helped!!!

10. Refraction occurs...
A. only with light waves
B. at any, unpredictable time
C. when a wave changes speed
D. only at a wave front
E. All of the above

Answers

The answer is C! Good luck!

An experiment is performed on an unknown material and produces the given heat curve. The temperature of the material is shown as a function of heat added. Other experiments determine that the material has a temperature of fusion of fusion=235 °C and a temperature of vaporization of vapor=471 °C.
If the sample of material has a mass of =9.80 g, calculate the specific heat when this material is a solid, s, and when it is liquid, l.

Answers

The specific heat of the solid phase is 0.333 joules per gram-degree Celsius.

The specific heat of the liquid phase is 0.593 joules per gram-degree Celsius.

In this case, we need to determine that specific heat for solid and liquid states of matter. By Heat Physics, we understand that specific heat is contained in the slopes of the two sensible phases in the following form:

[tex]\frac{\Delta T}{\Delta Q} = \frac{1}{m\cdot c}[/tex] (1)

Where:

[tex]\Delta T[/tex] - Temperature change, in degrees Celsius.[tex]\Delta Q[/tex] - Heat received, in joules.[tex]m[/tex] - Mass of the sample, in grams.[tex]c[/tex] - Specific heat of the sample, in joules per kilogram-degrees Celsius.

Solid phase

If we know that [tex]m = 9.80\,g[/tex], [tex]T_{1} = 40\,^{\circ}C[/tex], [tex]T_{2} = 235\,^{\circ}C[/tex], [tex]Q_{1} = 183\,J[/tex] and [tex]Q_{2} = 819\,J[/tex], then the specific heat of the solid phase is:

[tex]c = \frac{\Delta Q}{m\cdot \Delta T}[/tex]

[tex]c = \frac{819\,J-183\,J}{(9.80\,g)\cdot (235\,^{\circ}C - 40\,^{\circ}C)}[/tex]

[tex]c = 0.333\,\frac{J}{g\cdot ^{\circ}C}[/tex]

The specific heat of the solid phase is 0.333 joules per gram-degree Celsius.

Liquid phase

If we know that [tex]m = 9.80\,g[/tex], [tex]T_{3} = 230\,^{\circ}C[/tex], [tex]T_{4} = 471\,^{\circ}C[/tex], [tex]Q_{3} = 1470\,J[/tex] and [tex]Q_{4} = 2870\,J[/tex], then the specific heat of the liquid phase is:

[tex]c = \frac{\Delta Q}{m\cdot \Delta T}[/tex]

[tex]c = \frac{2870\,J - 1470\,J}{(9.80\,g)\cdot (471\,^{\circ}C - 230\,^{\circ}C)}[/tex]

[tex]c = 0.593\,\frac{J}{g\cdot ^{\circ}C}[/tex]

The specific heat of the liquid phase is 0.593 joules per gram-degree Celsius.

We kindly invite you to see this question related to specific heat: https://brainly.com/question/11194034

Cart 1 of mass m is traveling with speed 2vo in the +x-direction when it has an elastic collision with cart 2 of
mass 2m traveling with speed vo in the same direction.
What are the velocities of the carts after the collision?
please hurry and answer

Answers

Answer:

Explanation:

Momentum conservation

[tex]m2v_0+2mv_0=mv_1+2mv_2 \quad (1/m) \quad 4v_0=v_1+2v_2\\[/tex]

Kinetic energy conservation

[tex]\displaystyle \frac{1}{2}m(2v_0)^2+\frac{1}{2}2mv_0^2=\frac{1}{2}mv_1^2+\frac{1}{2}2mv_2^2 \quad (1/m) \quad 6v_0^2=v_1^2+2v_2^2[/tex]

Solve the system

Answer:

cart 1 of mass m is traveling with 2v0 in the +x-direction when it has an elastic collision with cart 2 of mass 2m traveling with speed v0 in the same direction.

What are the velocities of the carts after the collision?

What is the answer to this?

Answers

Answer:

B

Explanation:

Answer:

B

Explanation:

Another word for kinetic energy
could be
energy.
A. Safe
B. Moving
C. Stored
D. Potential

Answers

Answer:

moving

Explanation:

hope it helped!!!

Answer:

B

Explanation:

Other Questions
qvqpr answer this 5x5-5x5+55= HELPPPPPPP PLZZZZZZZ Circle O shown below has an arc of length 4 inches subtended by an angle of 0.6 radians. Find the length of the radius, x, to the nearest tenth of an inch.help correct answer only pls Need some help please Please help! 1.) Find mED2.) Find mEA3.) Find mBDC triangle pqr is dilated by a scale factor of 2. the center of the dilation is (0,0). how does the image of triangle pqr relate to triangle pqr? Find the measure of the indicated arc 2^2018+2^2019-2^2020/2^2020-2^2021-2^2022 What term is used by chemists to quantitatively describe a solution in which a relatively small amount of solute is dissolved? Use the function below:trig graph with points at 0, 1 and pi over 2, 5 and pi, 1 and 3 pi over 2, negative 3 and 2 pi, 1What are the amplitude and midline? Amplitude: 5; midline: y = 1 Amplitude: 5; midline: y = 0 Amplitude: 4; midline: y = 1 Amplitude: 4; midline: y = 0 If 0.09/x = 1, then x = Does this equation satisfy the Laws of Conservation of Matter and Mass?24 - P4010 + H2OO yesO no How do hormones find their target cells, and what transports them to their target cells? (50 points) Determine the concentration of strontium ions in saturated solution of strontium sulfate, SrSO4, if the Ksp for SrSO4 is 3.2x10-7. can someone do this for me i wasent there when we learned it Helpppppp!!!!!!why political ideologies of socialism and communism tend to be bad systems for the individuals living under such ideologies? . A rectangular prism has a volume of 1374.28 inches. The prism is 9.4 inches wide and 17.2 inches long. What is the height of the prism? Blood accounts for 7% of the total body weight.if patient weighs 150 lbs. how many lbs. of his weight is blood Which of the following systems helps get rid of some kind of waste?Aexcretory systemBdigestive systemCrespiratory systemDall of the above _______ helps maintain the earth's comfortable climate by preventing the escape of heat radiated from the earth's surface