Answer:
b????
Explanation:
hope its right
The development of the current atomic theory has changed over time as a result of different proposed models and experiments as per the chronological order of the development of the atomic models, the correct answer is option B
What are atomic models?There are some models that are used to explain the arrangements of subatomic particles inside the atom based on the atomic theory of atom are known as the atomic models.
As given in the problem statement The development of the current atomic theory has changed over time as a result of different proposed models and experiments. The chronological order of the atomic model is given as follows
John Dalton's atomic model
The Plum Pudding Model, developed by J.J. Thomson,
Using the alpha particle bombardment experiment on a thin sheet of gold, Rutherford's model
Niels Bohr's model explained the revolving nature of the electrons in the different shells around the nucleus of the atom.
Erwin Schrodinger's model explains the arrangement of the subatomic particles as the electron Cloud Model
Thus, the correct answer is option B.
Learn more about the atomic models here,
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A car traveled 885mi from El Paso, TX to Dallas, TX in 12.5 hours. What was the car's average speed?
Answer:
The car's average speed is 70.8 mph
Explanation:
The given parameters are;
The total distance traveled = 885 miles
The time of travel = 12.5 hours
The average speed is given by the following equation;
[tex]Average \ speed = \dfrac{Total \ Distance \ traveled}{Total \ time \ taken \ to \ travel \ the \ distance}[/tex]
Therefore, we have;
[tex]Average \ speed = \dfrac{885 \ miles}{12.5 \ hours} = 70.8 \ miles \ per \ hour[/tex]
Therefore, the car's average speed = 70.8 mph.
Answer:
The car's average speed is 70.8 mph
Explanation:
the acceleration due to gravity of the moon is 1.67
Answer:
I think it's 1.625 m/s2
A train travels with a speed of 115km/hr. How much time does it take to cover a distance of 470km.
It would take approximately 4 hours for the train to cover a distance of 470km.
4 hours 5 minutes 13.04 seconds
I need help
What should be done when the National Weather Service issues a severe weather watch?
Evacuate immediately.
Seek shelter immediately.
Take immediate action.
Begin to prepare.
When the net force on an object is zero, what do we know about the motion of that object
Answer:
The objects speed or motion does not change if the net force is 0.
Explanation: There basically doesn't have anything acting on it so it stays put.
Why do women typically tend to have slightly greater stability than men?
A.
Women are shorter than men, and shorter people are more stable.
B.
Men have more muscle mass in their lower bodies that makes them stiff and less stable.
C.
Women have lower centers of gravity, and lower centers of gravity provide more stability.
D.
The increased muscle mass in their upper bodies makes their centers of gravity difficult to find.
Please select the best answer from the choices provided.
A
B
C
D
Answer:
C
Explanation:
I figured it sounded more accurate
A loudspeaker produces a sound wave of frequency 50hz.
The amplitude of sound wave is increased.
What is heard?
A) a louder sound of higher pitch.
B) a louder sound of the same pitch.
C) a sound of higher pitch but the same loudness.
D) a sound of the same pitch and loudness as before
Answer:
B) a louder sound of the same pitch.
Explanation:
Given that the loudspeaker produces a sound wave of frequency 50hz and the amplitude of the sound wave is increased.
As loudness of the sound depends on the amplitude of the sound while pitch depends on the frequency of the sound.
On increasing the amplitude of the sound there is no effect on the frequency of the sound, so, the loudness of the sound will increase while the pitch remains unchanged.
Therefore, on increasing the amplitude of the soundwave a louder sound of the same pitch is heard.
Hence, option (B) is correct.
what is one standard kilogramun si system
Answer:
The kilogram (kg) is defined by taking the fixed numerical value of the Planck constant h to be 6.62607015 ×10−34 when expressed in the unit J s, which is equal to kg m2 s−1, where the meter and the second are defined in terms of c and ∆νCs.
Which of the following is NOT one of the essential components of an exercise program?
Answer:
i dont know dude but ask someone who is in your grade lol
Explanation:
What is the average depth of the oceanic crust? What percentage of our planet does it cover?
Answer: Oceanic crust, the outermost layer of Earth's lithosphere that is found under ... Sort out the facts and see how deep your knowledge goes in this quiz of the world's oceans. ... They commonly are thin (only about 10 cm [4 inches] thick) and cover a ... km (85 square miles) of seafloor to an average depth of 70 metres (230 feet).
Explanation:
The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7 x 10 to the -9th power coulombs what is the distance between the two charges
Answer:
0.28 m
Explanation:
The following data were obtained from the question:
Force (F) = 5×10¯⁶ N
Charge 1 (q₁) = 6.7×10¯⁹ C
Charge 2 (q₂) = 6.7×10¯⁹ C
Electrical constant (K) = 9×10⁹ Nm²C¯²
Distance apart (r) =?
Thus, the distance between the two charges can be obtained as follow:
F = Kq₁q₂/r²
5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²
5×10¯⁶ = 4.0401×10¯⁷ / r²
Cross multiply
5×10¯⁶ × r² = 4.0401×10¯⁷
Divide both side by 5×10¯⁶
r² = 4.0401×10¯⁷ / 5×10¯⁶
Take the square root of both side
r = √(4.0401×10¯⁷ / 5×10¯⁶)
r = 0.28 m
Therefore, the distance between the two charges is 0.28 m
URGENT! 40 POINTS! For each situation below, find the work done on the box using both energy and forces.
1. A 2 kg box initially at rest slides down a frictionless ramp (at 15ᵒ from the ground) for
1 second.
2. A 2 kg box is thrown upward with an initial speed of 3.5 m/s. Consider the box from
the time it was thrown until it reaches its maximum height.
3. A 2 kg box is dropped from an initial height of 10 m.
I have some physics, I just don't know what formulas to use or where to start. Help is much appreciated.
Answer:
i’m not sure one second let me try to figure it out
Explanation:
How long will it take an object traveling at 7 m/s to reach a distance of 26 meters
Answer:
3 hours 71 minutes
Explanation:
As because Speed= distance/time taken
so time taken= 3.71
Un automóvil se mueve a velocidad constante v = 60 [km/h]. Si el tiempo de reacción del conductor al ver la luz roja de una intersección es de 0.5 [s], y ´este desacelera a razón de 40 [m/s2 ] ¿Qué distancia recorre el automóvil desde el instante en que el conductor nota la se˜nal hasta detenerse por completo? Entiéndase por tiempo de reacción, el intervalo de tiempo transcurrido entre el instante en que se percibe la señal y el instante en que se lleva a cabo la acción (instante en que el conductor activa el sistema de frenado).
Answer:
El automóvil recorre una distancia de 11.806 metros antes de deternerse por completo.
Explanation:
De acuerdo con el enunciado, el conductor nota la luz roja, empieza a decelerar 0.5 segundos después y decelera hasta detenerse. La distancia total recorrida por el automóvil desde el instante en que el conductor nota la luz roja ([tex]\Delta s_{T}[/tex]), medida en metros:
[tex]\Delta s_{T} = \Delta s_{1}+\Delta s_{2}[/tex] (1)
Donde:
[tex]\Delta s_{1}[/tex] - Distancia recorrida a velocidad constante, medida en metros.
[tex]\Delta s_{2}[/tex] - Distancia recorrida hasta alcanzar el reposo, medida en metros.
Si suponemos que la segunda etapa describe un movimiento uniformemente acelerado, entonces la distancia recorrida total que representada por la siguiente fórmula:
[tex]\Delta s_{T} = v_{o}\cdot \Delta t_{o} + \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a}[/tex] (2)
Donde:
[tex]v_{o}[/tex] - Velocidad inicial del automóvil, medida en metros por segundo.
[tex]v_{f}[/tex] - Velocidad final del automóvil, medida en metros por segundo.
[tex]\Delta t_{o}[/tex] - Tiempo de reacción del conductor, medido en segundo.
[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.
Si conocemos que [tex]v_{o} = 16.667\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex], [tex]\Delta t_{o} = 0.5\,s[/tex] y [tex]a = -40\,\frac{m}{s^{2}}[/tex], entonces la distancia recorrida total es:
[tex]\Delta s_{T} = \left(16.667\,\frac{m}{s} \right)\cdot (0.5\,s)+\frac{\left(0\,\frac{m}{s} \right)^{2}-\left(16.667\,\frac{m}{s}\right)^{2}}{2\cdot \left(-40\,\frac{m}{s^{2}} \right)}[/tex]
[tex]\Delta s_{T} = 11.806\,m[/tex]
El automóvil recorre una distancia de 11.806 metros antes de deternerse por completo.
Directions: Summarize the main ideas of this lesson by answering the question below.
How might a person acquire a fear of or aversion to something even though it has no negative effect
on him or her?
Answer:
Explanation:
Trypophobia is a fear or disgust of closely-packed holes. People who have it feel queasy when looking at surfaces that have small holes gathered close together.A person may start by imagining what they fear, then looking at pictures of the fear object, and then finally being near or even touching the source of their anxiety. In the case of trypophobia, a person with symptoms may start by simply closing his eyes and imagining something such as a honeycomb or seed poThey can help you find the root of the fear and manage your symptoms. Last medically reviewed on July 20, 2017 Medically reviewed by Timothy J. Legg, Ph.D., CRNP — Written by Annamarya Scaccia ...
question in the photo
Calculate the kinetic energy of a 50 kg cart moving at a speed of 7.1 m/s.
ill give u 100 points if you give me the right answer.
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[tex]\huge\boxed{\fcolorbox{black}{yellow}{HOPE\: IT \: HELPS}}[/tex]
HOPE IT HELPS
[tex]\begin{gathered}\begin{gathered}\\\huge\underline{ \mathbb\blue{Please}\:\mathbb\green{Mark}\:\mathbb\orange{As}}\:\end{gathered}\end{gathered}[/tex]
Please Mark As
[tex]\huge\underline{ \mathbb\red{Brilliant}\:\mathbb\purple{Answers}}[/tex]
Brilliant Answers
An object is falling from a height of d and reaches a final velocity of vf. Calculate velocity when the object has fallen a distance d/2.
Answer:
The final velocity, [tex]v_{f}[/tex], is gd.
Explanation:
The condition here is a free falling object. Thus from the third equation of motion under free fall, we have;
[tex]v_{f}[/tex] = [tex]v_{i}[/tex] + 2gs
where [tex]v_{f}[/tex] is the final velocity of the object, [tex]v_{i}[/tex] is the initial velocity of the object, g is the gravitational force and s is the height.
Since the object falls from a height of d, then [tex]v_{i}[/tex] = 0 m/s, and s = d.
So that;
[tex]v_{f}[/tex] = 0 + 2gd
= 2gd
[tex]v_{f}[/tex] = 2gd
When the distance is [tex]\frac{d}{2}[/tex], [tex]v_{i}[/tex] = 0 m/s.
Then;
[tex]v_{f}[/tex] = 2g[tex]\frac{d}{2}[/tex]
[tex]v_{f}[/tex] = g x d
When the object falls through the height [tex]\frac{d}{2}[/tex], then the final velocity is gd.
Two skaters A and B. having masses 50 kg and
70 kg respectively, stand facing each other 6 m
apart on a horizontal smooth surface. They pull
on a rope stretched between them. How far does
each move before they meet?
(A) both move 3 m
(B) A moves 2.5 m and B moves 3.5 m
(C) A moves 3.5 m and B moves 2.5 m
(D) both move 4 m
(E) none of the above
Answer:
Explanation:
Hell im good dude
The fall of a body on the earth surface cannot be a complete free fall ? why
what are the harmful effects of drugs in the body?
Explanation:
causes hallucinations
causes lung cancer eg cigarettes
causes bad breath
damages the nervous system eg cocaine
Explanation:
Drug use can lead to an addiction. Effects of
drugs on the body can slowly destroy vital
systems and functions. Drug dependence can quickly begin to affect your psychological and physical health, and can also affect your work and social life.
hope it helps!
Asha walks 15 m west, then 20 m north, then 15 m east. Calculate the distance
covered by Asha.(a) (Numbering problem)_
Distance walked to the west= 15m
" " " " north= 20m
" " " " east = 15m
Total Distance= (15+ 20+ 15) m
= 50m
Asha covered 50m distance in total.
What is the height of a shelf that has 15 kg objects with 450 J of gravitational potential energy
What would the mechanical advantage of a ramp be if the length is 25 feet and the height is 5 feet?
10
125
5
30
Answer:
5.
Explanation:
From the question given above, the following data were obtained:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =?
Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:
Mechanical advantage = length /height
MA = L/H
With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =.?
MA = 25 / 5
MA = 5
The, the mechanical advantage of the ramp is 5.
Answer:
5.
Explanation:
From the question given above, the following data were obtained:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =?
Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:
Mechanical advantage = length /height
MA = L/H
With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =.?
MA = 25 / 5
MA = 5
The, the mechanical advantage of the ramp is 5.
A 1500 kg car has an applied forward force of 5000 N and experiences an air resistance of 1250 N. What is the car's acceleration?
Answer:
[tex]2.33\ m/s^2[/tex]
Explanation:
Net Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
Fn = m.a
Where a is the acceleration of the object. The net force is the sum of the individual vector forces applied to the object.
The m=1500 Kg car has two horizontal forces applied: the forward force of 5000 N that causes the movement and the air resistance force of 1250 N that opposes motion.
The net force is Fn = 5000 N - 1500 N = 3500 N
To find the acceleration, we solve the equation for a:
[tex]\displaystyle a=\frac{Fn}{m}[/tex]
[tex]\displaystyle a=\frac{3500}{1500}[/tex]
[tex]\boxed{a = 2.33\ m/s^2}[/tex]
The car's acceleration is [tex]a = 2.33\ m/s^2[/tex]
WILL MARK BRAINLY!! QUICK HELP PLEASE!
A 40.0 kg rocket produces a
764 N upwards force ("thrust").
What is the net force acting on
the rocket?
Answer:
372Explanation:(40.0)×(9.8)=392
764N-392=372
Which frequency would be the third harmonic in a series for an open-pipe resonator if the fundamental is 440 Hz
Answer:
1320 Hz
Explanation:
The third harmonic is given as 3fo, where fo is the fundamental frequency.
The fundamental frequency is the lowest frequency that can occur in a pipe. In an open pipe, both even and odd harmonics occur which are multiples of the fundamental frequency fo. Hence the harmonics in an open pipe are; 2fo, 3fo,4fo..... etc.
For the third harmonic; 3fo = 3 (440 Hz) = 1320 Hz
A child pushes a 100 kg refrigerator with a force of 50 N, but the refrigerator does not move. Suppose the coefficient of static friction between the floor and the refrigerator is 0.4. What is the force due to friction in this scenario
Answer:
50 N
Explanation:
Since the refrigerator doesn’t move, that means the force of friction equals the amount of force the child exerts on the fridge. If the friction force were greater than the force by the child, the fridge would start accelerating towards the child. If it were less than the force the child exerted, the fridge would start accelerating away from the child. Therefore, the net force must be 0, in this case, the friction force is equal to the force the child exerted, for it to stay at rest (as Newton’s First Law stated).
I hope this helps! :)
Bolt starts the race not moving, but then increased his speed until he reaches a top speed. Once Bolt reaches his top speed he maintains that speed for a few seconds to:
a) move at a constant velocity
b) accelerating by moving faster
c) accelerating by moving slower
Is it a, b, or c?
Answer:
a) move at a constant velocity
Explanation:
HELP ASAP!! WILL TRY TO GIVE BRAINLIEST
Distinguish among hypertonic, hypotonic, and isotonic solutions
Explanation:
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