The demand for the video games provided by Mid-Tech Video Games Inc. has exploded in the last several years. Hence, the owner needs to hire several new technical people to keep up with the demand. Mid-Tech gives each applicant a special test that Dr. McGraw, the designer of the test, believes is closely related to the ability to create video games. For the general population, the mean on this test is 100. Below are the scores on this first test for the applicants. 95 105 120 81 90 115 99 100 130 10 The owner is interested in the overall quality of the job applicants based on this test. Compute the mean and the median scores for the 10 applicants. What would you report to the owner

Answers

Answer 1

Answer:

Mean: 94.5.

Median: 99.5

Standard deviation: 33.1

We can tell the owner that the applicants don't have a score significantly below from 100.

Step-by-step explanation:

First, we analize the sample and calculate the statistics (mean, median and standard deviation).

Mean of the sample:

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{10}(95+105+120+81+90+115+99+100+130+10)\\\\\\M=\dfrac{945}{10}\\\\\\M=94.5\\\\\\[/tex]

The median, as the sample size is an even number, can be calculated as the average between the fifth and sixth value, sort by value:

[tex]\text{Median}=\dfrac{99+100}{2}=99.5[/tex]

The standard deviation is:

[tex]s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{9}((95-94.5)^2+(105-94.5)^2+(120-94.5)^2+. . . +(10-94.5)^2)}\\\\\\s=\sqrt{\dfrac{9834.5}{9}}\\\\\\s=\sqrt{1092.7}=33.1\\\\\\[/tex]

To tell if this sample has a value significantly lower than the expected score of 100, we should make a hypothesis test.

The claim is that the mean score is significantly lower than 100.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=100\\\\H_a:\mu< 100[/tex]

The significance level is 0.05.

The sample has a size n=10.

The sample mean is M=94.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=33.1.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{33.1}{\sqrt{10}}=10.467[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{94.5-100}{10.467}=\dfrac{-5.5}{10.467}=-0.53[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=10-1=9[/tex]

This test is a left-tailed test, with 9 degrees of freedom and t=-0.53, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t<-0.53)=0.306[/tex]

As the P-value (0.306) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean score is significantly lower than 100.


Related Questions

Can someone please help me

Answers

Answer:

20

Step-by-step explanation:

If the two triangles are similar, then corresponding sides must share a constant ratio. This means that:

[tex]\dfrac{10}{6}=\dfrac{25}{15}=\dfrac{x}{12}[/tex]

Let's use the second ratio:

[tex]\dfrac{25}{15}=\dfrac{x}{12}[/tex]

Multiply both sides by 12:

[tex]\dfrac{25\cdot 12}{15}=x \\\\x=20[/tex]

Hope this helps!

Find the area of the region in the first quadrant bounded on the left by the ​y-​axis, below by the line y equals one third x comma above left by yequalsxplus​4, and above right by yequalsminusx squaredplus10.

Answers

Answer:

The bounded area  is: [tex]\frac{73}{6}\approx 12.17[/tex]

Step-by-step explanation:

Let's start by plotting the functions that enclose the area, so we can find how to practically use integration. Please see attached image where the area in question has been highlighted in light green. The important points that define where the integrations should be performed are also identified with dots in darker green color. These two important points are: (2, 6) and (3, 1)

So we need to perform two separate integrals and add the appropriate areas at the end. The first integral is that of the difference of function y=x+4 minus function y=(1/3)x , and this integral should go from x = 0 to x = 2 (see the bottom left image with the area in red:

[tex]\int\limits^2_0 {x+4-\frac{x}{3} } \, dx =\int\limits^2_0 {\frac{2x}{3} +4} \, dx=\frac{4}{3} +8= \frac{28}{3}[/tex]

The next integral is that of the difference between [tex]y=-x^2+10[/tex] and the bottom line defined by: y = (1/3) x. This integration is in between x = 2 and x = 3 (see bottom right image with the area in red:

[tex]\int\limits^3_2 {-x^2+10-\frac{x}{3} } \, dx =-9+30-\frac{3}{2} -(-\frac{8}{3} +20-\frac{2}{3} )=\frac{39}{2} -\frac{50}{3} =\frac{17}{6}[/tex]

Now we need to add the two areas found in order to get the total area:

[tex]\frac{28}{3} +\frac{17}{6} =\frac{73}{6}\approx 12.17[/tex]

In the matrix equation below, what are the values of x and y?​

Answers

Answer: x=3 y=1

Step-by-step explanation:

2)
Which of these objects are two-dimensional? Check all that apply.
A.Point
B.Segment
C.Square
D. Line
E. Solid
F. Plane

Answers

Answer:

Option C and F

Step-by-step explanation:

=> Square and Plane a two-dimensional objects.

Rest of the objects are either 1 - dimensional or 3- dimensional.

A polynomial is factorable, but it is not a perfect square trinomial or a
difference of two squares. Can you factor the polynomial without finding the GCF?

Answers

Answer:

So in this problem, we're told that a polynomial is fact herbal and it's not a perfect square. Try no meal or a difference of two squares. Can you factor the pie? Nomi bite or polynomial without finding the G C F. So no Jacey after is allowed. So if it's not a perfect squared, try no meal. So not a perfect square. We know it's not this, and we also know it's not a difference of two squirt if it's not any of these or if it's not either of these, but we can't find the G. C F. There are three different ways we could find the factored form. You could do it by grouping where you separating the polynomial into two parts and factor them individually before combining. You could also use the sum or a difference of cubes. This is for a cubic or a um, polynomial of third degree, and you could also use fractional or negative exponents. So even if you can't find the G c f or use these methods, there are still three ways you can factor the

Step-by-step explanation:

Glad i could help!

What is the algebraic expression for "the sum of three times a number and seven"? A. 3 x + 7 B. 3 x + 11 x C. 3 + 7 x

Answers

Answer:

3x+7

Step-by-step explanation:

Three times a number, let x be the number and 7 so plus 7

The algebraic expression for the given phrase is 3x+7. Therefore, the correct answer is option A.

The given phrase is "the sum of three times a number and seven".

Variables and constants are combined to generate algebraic expressions using a variety of techniques. Terms comprise expressions. A term is the sum of several elements. Both numerical and algebraic (literal) factors are acceptable.

Let the unknown number be x.

Three times of a number = 3x

The number 7 is added to the  obtained sum.

That is, 3x+7

So, the expression is 3x+7

The algebraic expression for the given phrase is 3x+7. Therefore, the correct answer is option A.

To learn more about an expression visit:

https://brainly.com/question/28170201.

#SPJ4

What is the relative change from 6546 to 4392

Answers

Answer:

The relative change from 6546 and 4392 is 49.04

Step-by-step explanation:

What is the number of ways to
arrange 5 objects from a set of 8
different objects?

Answers

Answer:

6,720 ways

Step-by-step explanation:

Since in the problem arrangemnt is being asked this is a problem of permutation.

No . of ways of arranging r things out of n things is given by

P(n,r) =   n!/(n-r)!

In the problem given we have to arrange 5 objects from set of 8 objects.

Here n = 8 and p = 5

it can be done in in

P(8,5) =   8!/(8-5)! ways

8!/(8-5)!  = 8!/3! = 8*7*6*5*4*3!/3! = 8*7*6*5*4 = 6,720

Thus,  number of ways to  arrange 5 objects from a set of 8

different objects is P(8,5) =   8!/(8-5)! =  6,720 .

which of these is a step constructing an inscribed square using technology?

Answers

Answer:

  Mark the points of intersection between circle A and line AB.

Step-by-step explanation:

The attached shows an inscribed square created using technology. We started with point A and B, drew the circle with radius AB, and drew the line AB. Then we marked point C at the intersection of circle A and line AB.

We had a perpendicular to AB drawn through A, and marked its intersection with circle A as points D and E. Finally, we drew inscribed square BDCE.

__

Other answer choices may somehow be involved. We'd need to see the construction to be sure. The one shown above seemed most likely.

A simple random sample of 5 months of sales data provided the following information: Month: 1 2 3 4 5 Units Sold: 94 105 85 94 92 (a) Develop a point estimate of the population mean number of units sold per month. x = (b) Develop a point estimate of the population standard deviation. If required, round your answer to two decimal places. s =

Answers

Answer:

a) x = 94 units/month

b) s = 51.50 units/month

Step-by-step explanation:

The adequate point estimation of the population mean and standard deviation are the sample mean and sample standard deviation.

a) Point estimation of the population (sample mean)

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(94+105+85+94+92)\\\\\\M=\dfrac{470}{5}\\\\\\M=94\\\\\\[/tex]

b) Point estimation of the population standard deviation (sample standard deviation)

[tex]s=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2\\\\\\s=\dfrac{1}{4}((94-94)^2+(105-94)^2+(85-94)^2+(94-94)^2+(92-94)^2)\\\\\\s=\dfrac{206}{4}\\\\\\s=51.50\\\\\\[/tex]

Using statistical concepts, it is found that:

a) The point estimate for the population mean is of: [tex]\overline{x} = 94[/tex]

b) The point estimate for the population standard deviation is of: [tex]s = 7.18[/tex]

Item a:

The mean of a data-set is the sum of all observations in the data-set divided by the number of observations.The point estimate for the population mean is the sample mean.

In this problem, the sample is: 94, 105, 85, 94, 92.

Thus, the mean is:

[tex]\overline{x} = \frac{94 + 105 + 85 + 94 + 92}{5} = 94[/tex]

Item b:

The standard deviation of a data-set is the square root of the sum of the differences squared between each observation and the mean, divided by one less than the number of values.The point estimate for the population standard deviation is the sample standard deviation.

Then:

[tex]s = \sqrt{\frac{(94-94)^2+(105-94)^2+(85-94)^2+(94-94)^2+(92-94)^2}{4}} = 7.18[/tex]

A similar problem is given at https://brainly.com/question/13451786

Please answer this correctly

Answers

Answer:

3| 4 4 7

4| 0 3 4

5| 5 5 5

6| 0 1 3 8 9

7| 9

8| 1 4 6 8

hope it helps!

Step-by-step explanation:

Check the numbers and list out the tens digit in stem (that is 3-8) and then write the corresponding leaf values

Assume that the population proportion is 0.56. Compute the standard error of the proportion, σp, for sample sizes of 100, 200, 500, and 1,000. (Round your answers to four decimal places.)

Answers

Answer:

Standard errors are 0.049, 0.035, 0.022, and 0.016.

Step-by-step explanation:

The given value of population proportion (P) = 0.56

Given sample sizes (n ) 100, 200, 500, and 1000.

Now standard error is required to calculate.

Use the below formula to find standard error.

When sample size is n = 100

[tex]\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{100}} =0.049[/tex]

When sample size is n = 200

[tex]\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{200}} = 0.035[/tex]

When sample size is n = 500

[tex]\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{500}} =0.022[/tex]

When sample size is n = 1000

[tex]\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{1000}} = 0.016[/tex]

I Am Thinking of a number. 1/12 of it equals 6. 1/3 of it equals_________.

Answers

Answer:

24

Step-by-step explanation:

hello

let's note x the number we are looking for

[tex]\dfrac{x}{12}=6\\<=> x = 6*12=72[/tex]

so 1/3 of it equals

[tex]\dfrac{72}{3}=24[/tex]

another way to see it is that 12=4*3

so 1/3 of it equals 6*4=24

hope this helps

Please answer this correctly

Answers

Answer:

Step-by-step explanation:

Baltimore orioles : 1,000,000 + 1,000,000 + 500,000

Click 2 full bag and 1 half bag

Kansas city royals : 1,000,000 +500,000

Click 1 full bag and 1 half bag

Newyork Yankees  : 1,000,000 + 1,000,000 + 1,000,000 +1,000,000 +1,000,000 + 500,000

Click 5 full bag + 1 half bag

What transformations to the linear parent function, f(x) = x, give the function
g(x) = 4x - 2? Select all that apply.
A. Shift down 2 units.
B. Vertically stretch by a factor of 4.
O c. Horizontally stretch by a factor of 4.
O D. Shift left 2 units.​

Answers

Answer:

A. Shift down 2 units.

B. Vertically stretch by a factor of 4.

Step-by-step explanation:

Given the function

f(x)=x

If we stretch y vertically by a factor of m, we have: y=m·f (x)

Therefore:

Vertically stretching f(x) by a factor of 4, we have: 4x.

Next, if we take down f(x) by k units we have: y= f(x)-k

Therefore: Taking down 4x by 2 units, we obtain:

g(x)=4x-2

Therefore, Options A and B applies.

The length of a 95% confidence interval for mean Age is which of the following? (Because of potential roundoff, choose the closest.) Click here to reference the data needed to answer the question. a. 3.37 b. 3.72 c. 4.27 d. 3.11

Answers

Answer:

The length of a 95% confidence interval for mean Age is 3.72.

Step-by-step explanation:

The data is provided for the age of 100 adults.

The mean and standard deviation are:

[tex]\bar x=47.8\\\\s=9.3744[/tex]

As the sample size is too large the z-interval will be used for the 95% confidence interval for mean.

The critical value of z for 95% confidence level is, z = 1.96.

The length of a confidence interval is given by:

[tex]\text{Length}=2\cdot z_{\alpha/2}\cdot\frac{s}{\sqrt{n}}[/tex]

           [tex]=2\times 1.96\times\frac{9.3744}{\sqrt{100}}\\\\=3.6747648\\\\\approx 3.67\\\\\approx 3.72[/tex]

Thus, the length of a 95% confidence interval for mean Age is 3.72.

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level. Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. Using the data, construct the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level.

Answers

Answer:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

[tex]n = 1537, \pi = \frac{353}{1537} = 0.2297[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 - 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2087[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 + 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2507[/tex]

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

What is the answer? x^2-y^2=55

Answers

Answer:

To solve for x we can write:

x² - y² = 55

x² = y² + 55

x = ±√(y² + 55)

To solve for y:

x² - y² = 55

y² = x² - 55

y = ±√(x² - 55)

Here's a graph of a linear function. Write the
equation that describes that function.
Express it in slope intercept form.

Answers

Answer:

y = x-2

Step-by-step explanation:

Pick two points on the line

(0,-2) and (2,0)

We can find the slope

m = (y2-y1)/(x2-x1)

   = (0--2)/(2-0)

   = (0+2)/(2-0)

   2/2

  =

We know the y intercept is -2 (  where it crosses the y axis)

y = mx +b is the slope intercept form of the equation  where m is the slope and b is the y intercept

y = 1x -2

y = x-2

Answer: [tex]y=x-2[/tex]

Step-by-step explanation:

I explained the other problem you asked, why couldnt you apply that info to this one? Either way, Ill explain it again.

We can see the slope intercept is -2, so b = -2

To get the slope, just from visualization. Look at the y value and x value direction for which you gotta take to get to the next coords. From the y-intercept, you go up 1 and then right 1. 1/1 = 1

How many units of insulin are in 0.75 ML a regular U – 100 insulin

Answers

Answer:

0.75 ML of insulin contains 75 units of insulin

Step-by-step explanation:

U - 100 insulin hold 100 units of insulin per ml

This means that:

1 ML = 100 units

∴ 0.75 ML = 100 × 0.75 = 75  units

Therefore 0.75 ML of insulin contains 75 units of insulin

If
f(x) = 13x + 1, then
f-1(x) =

Answers

Answer:

(x-1)/13

Step-by-step explanation:

y = 13x+1

To find the inverse, exchange x and y

x = 13y+1

Solve for y

Subtract 1 from each side

x-1 =13y+1-1

x-1 = 13y

Divide each side by 13

(x-1)/13 = y

The inverse is (x-1)/13

Answer:

f(x) = 13x + 1

To find the inverse let f(x) = y

y = 13x + 1

x = 13y + 1

13y = x - 1

y = (x-1)/13

The inverse is x-1/13.

You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable preliminary estimation for the population proportion. You would like to be 80% confident that you estimate is within 2.5% of the true population proportion. How large of a sample size is required?

Answers

Answer:

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.025}{1.28})^2}=655.36[/tex]  

And rounded up we have that n=656

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 80% of confidence, our significance level would be given by [tex]\alpha=1-0.80=0.20[/tex] and [tex]\alpha/2 =0.10[/tex]. And the critical value would be given by:

[tex]z_{\alpha/2}=\pm 1.28 [/tex]

Solution to the problem

The margin of error for the proportion interval is given by this formula:  

[tex] ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]    (a)  

Since we don't have prior info for the proportion of interest we can use [tex]\hat p=0.5[/tex] as estimator. And on this case we have that [tex]ME =\pm 0.025[/tex] and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

[tex]n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}[/tex]   (b)  

And replacing into equation (b) the values from part a we got:

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.025}{1.28})^2}=655.36[/tex]  

And rounded up we have that n=656

Calculate balloon volume for each balloon at maximum inflation from the circumference data. (You will have to assume that the balloon was a perfect sphere.) To calculate balloon volume, first find the radius (in cm) of the balloon by using the formula C = 2πr. Then, use the radius' value in the formula V = (4/3)πr3 to calculate volume (in cm3). Show all your work, place units on all numbers (even those within the calculations), and express your answers with appropriate sig figs. (12 pts)

Answers

Answer:

r₁ = 3.583cm

V₁= 192.55cm³

r₂= 5.176cm

V₂ = 580.283cm³

r₃ = 5.255cm

V₃ = 607.479cm³

Step-by-step explanation:

assuming circumferences of each balloons are given as follows C₁ = 22.5cm, C₂ = 32.5cm and C₃ = 33cm

Recall C = 2πr

volume of a sphere is 4/3πr³

A complex electronic system is built with a certain number of backup components in its subsystems. One subsystem has eight identical components, each with a probability of 0.45 of failing in less than 1,000 hours. The sub system will operate if any four of the eight components are operating. Assume that the components operate independently. (Round your answers to four decimal places.)

Required:
Find the probability that the subsystem operates longer than 1000 hours.

Answers

Answer:

0.7396 = 73.96% probability that the subsystem operates longer than 1000 hours.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either they fail in less than 1000 hours, or they do not. The components operate independently. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Eight components:

This means that [tex]n = 8[/tex]

Probability of 0.45 of failing in less than 1,000 hours.

So 1 - 0.45 = 0.55 probability of working for longer than 1000 hours, which means that [tex]p = 0.55[/tex]

Find the probability that the subsystem operates longer than 1000 hours.

We need at least four of the components operating. So

[tex]P(X \geq 4) = P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 4) = C_{8,4}.(0.55)^{4}.(0.45)^{4} = 0.2627[/tex]

[tex]P(X = 5) = C_{8,5}.(0.55)^{5}.(0.45)^{3} = 0.2568[/tex]

[tex]P(X = 6) = C_{8,6}.(0.55)^{6}.(0.45)^{2} = 0.1569[/tex]

[tex]P(X = 7) = C_{8,7}.(0.55)^{7}.(0.45)^{1} = 0.0548[/tex]

[tex]P(X = 8) = C_{8,8}.(0.55)^{8}.(0.45)^{0} = 0.0084[/tex]

[tex]P(X \geq 4) = P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) = 0.2627 + 0.2568 + 0.1569 + 0.0548 + 0.0084 = 0.7396[/tex]

0.7396 = 73.96% probability that the subsystem operates longer than 1000 hours.

factorization of expression 4z(3a+2b-4c)+(3a+2b-4c)

Answers

Answer:

(3a+2b-4c)[4z+1]

Step-by-step explanation:

4z(3a+2b-4c)+(3a+2b-4c)

Factor out (3a+2b-4c)

(3a+2b-4c)[4z+1]

Answer:

3a+2b-4c)[4z+1]

Step-by-step explanation:

4z(3a+2b-4c)+(3a+2b-4c)

Factor out (3a+2b-4c)

(3a+2b-4c)[4z+1]

Question 2: The average price for a BMW 3 Series Coupe 335i is $39,368. Suppose these prices are also normally distributed with a standard deviation of $2,367. What percentage of BMW dealers are pricing the BMW 3 Series Coupe 335i at more than the average price ($44,520) for a Mercedes CLK350 Coupe? Round your answer to 3 decimal places.

Answers

Answer:

0.015 = 1.5% of BMW dealers are pricing the BMW 3 Series Coupe 335i at more than the average price ($44,520) for a Mercedes CLK350 Coupe

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 39368, \sigma = 2367[/tex]

What percentage of BMW dealers are pricing the BMW 3 Series Coupe 335i at more than the average price ($44,520) for a Mercedes CLK350 Coupe?

This is 1 subtracted by the pvalue of Z when X = 44520. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{44520 - 39368}{2367}[/tex]

[tex]Z = 2.18[/tex]

[tex]Z = 2.18[/tex] has a pvalue of 0.985

1 - 0.985 = 0.015

0.015 = 1.5% of BMW dealers are pricing the BMW 3 Series Coupe 335i at more than the average price ($44,520) for a Mercedes CLK350 Coupe

The promising alternative energy sources currently under development are fuel cell technology and large-scale solar energy power. The probabilities that these two sources will be successfully developed and commercially viable in the next 10 years are 0.70 and 0.85, respectively. The successful development of these two energy sources are statistically independent. Determine the following: a. The probability that there will be energy supplied by these two alternative sources in the next 10 years. b. The probability that only one of the two alternative energy sources will be commercially viable in the next 10 years.

Answers

Answer:

Step-by-step explanation:

a) Denote the event of commercially availability of f_uel cell technology as F_, commercial availability of solar power technology as S

Write the probability of energy supplied by these energy sources in the next 10 years  

P(energy supplied) = P(S ∪ F) -----(1)

Rewrite eqn (1)

P(energy supplied) = P(S) + P(F) - P(F) P(S) ----(2)

substitute 0.85 for P(S) and 0,7 for P(F) in eqn (2) to find the probability of energy supplied by these energy sources

P(energy supplied) = 0.85 + 0.7 - (0.7 * 0.85)

= 0.85 + 0.7 - (0.595)

= 1.55 - 0.595

= 0.955

Therefore, the probability that there will be energy supplied by these two alternative sources in the next 10 years is 0.955

B) write the probability of only one source of energy available

P(only one source of energy available) = [tex]P(\bar F S)[/tex] ∪ [tex]P( \bar S F)[/tex] ---(3)

Rewrite the equation (3)

P(only one source of energy available) =

[tex]=P(\bar F S)+P(\bar S F)\\\\=\{[1-P(F)]P(S)+[1-P(S)]P(F)\}---(4)[/tex]

[tex]=\{[1-0.7]0.85+[1-0.85]0.7\}\\\\=0.255+0.105\\\\=0.36[/tex]

Therefore,The probability that only one of the two alternative energy sources will be commercially viable in the next 10 years is 0.36

Help solve attached question.

Answers

Answer:

[tex]\mathrm{12\sqrt{5} \: \: inches}[/tex]

Step-by-step explanation:

Use Pythagorean theorem, where:

[tex]a^2+b^2=c^2[/tex]

Substitute in the values.

[tex]24^2+12^2=c^2[/tex]

[tex]c^2=576+144[/tex]

[tex]c^2=720[/tex]

[tex]c=\sqrt{720}[/tex]

[tex]c=12\sqrt{5}[/tex]

[tex]c=26.83281[/tex]

12 squareroot 5 inches

According to the Center for Disease Control and Prevention (CDC), up to 20% of Americans contract the influenza virus each year, and approximately 3% of all births in the United States result in birth defects each year. Consider two babies being born independently of one another. 1. The probability that both babies have birth defects is;______ a. 0.0009. b. 0.0400.c. 0.0606. d. 0.2000. 2. The probability that neither baby catches the flu in a given year is:_____ a. 0.024. b. 0.040. c. 0.230 d. 0.640. 3. Event A occurs with probability 0.1. Event B occurs with probability 0.6. If A and B are independent, then:______ a. P(A and B) = 0.06. b. P(A or B) = 0.70. c. P(A and B) = 0.70. d. P(A or B) = 0.06. 4. Event A occurs with probability 0.2. Event B occurs with probability 0.9. Event A and B:______ are disjoint cannot be independent. cannot be disjoint. are reciprocating. The center for Disease Control and Prevention reports that the rate of Chlamydia infections among American women ages 20 to 24 is 2791.5 per 100,000. Take a random sample of three American women in this age group. 5. The probability that all of them have a Chlamydia infection is:_____ a. nearly 0. b. 0.028. c. 0.084. d. 0.837 6. The probability that none of them have a Chlamydia infection is:_______ a. 0.084. b. 0.919. c. 0.972. d. nearly 1.

Answers

Answer:

(1) a. 0.0009

(2) d. 0.640

(3)

a. P(A and B) = 0.06. b. P(A or B) = 0.70.

(4)Not disjoint

(5) a. nearly 0.

(6)b. 0.919

Step-by-Step Explanation:

(1)Probability of a baby being born with a birth defect =3%=0.03

The probability that both babies have birth defects=0.03 X 0.03= 0.0009.

(2)The probability of contracting the influenza virus each year = 20%=0.2

Therefore, the probability of not contracting the influenza virus =1-0.2=0.8

The probability that neither baby catches the flu in a given year:

=0.8 X  0.8

=0.64

(3)

P(A)=0.1

P(B)=0.6

P(A or B)=P(A)+P(B)=0.1 + 0.6 =0.7

P(A and B)=P(A)XP(B)=0.1 X 0.6 =0.06

(4)

P(A)=0.2

P(B)=0.9

Event A and B cannot be disjoint.

(5)

The probability of an American woman aged 20 to 24 having Chlamydia infection  [tex]=\dfrac{2791.5}{100000}[/tex]

The probability that three randomly selected women in this age group have the infection

[tex]=\dfrac{2791.5}{100000} \times \dfrac{2791.5}{100000} \times \dfrac{2791.5}{100000} \\\\=0.00002175\\\approx 0[/tex]

(6)The probability of an American woman aged 20 to 24 not having Chlamydia infection  [tex]=1-\dfrac{2791.5}{100000}[/tex]

The probability that three randomly selected women in this age group do not have the infection

[tex]=\left(1-\dfrac{2791.5}{100000}\right)^3\\\\=0.9186\\\approx 0.919[/tex]

Find the volume of a right circular cone that has a height of 4.2m and a base with a radius of 3.4m

Answers

Answer:

  about 50.8 cubic meters

Step-by-step explanation:

The formula for the volume of a cone is ...

  V = (1/3)πr²h

Put the given values into the formula and do the arithmetic.

  V = (1/3)π(3.4 m)²(4.2 m) = 16.194π m³

__

For π to calculator precision, this is ...

  V ≈ 50.84 m³

For π = 3.14, this is ...

  V ≈ 50.82 m³

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