The combustion of a sample of butane, C4H10 (lighter fluid), produced 2.46 grams of water.
2 C4H10 + 13O2 -------> 8CO2 + 10H2O
(a) How many moles of water formed?
(b) How many moles of butane burned?
(c) How many grams of butane burned?
(d) How much oxygen was used up in moles?
(e) How much oxygen was used up in grams?

Answers

Answer 1

a. 0.137

b. 0.0274

c. 1.5892 g

d. 0.1781

e. 5.6992 g

Further explanation

Given

Reaction

2 C4H10 + 13O2 -------> 8CO2 + 10H2O

2.46 g of water

Required

moles and mass

Solution

a. moles of water :

2.46 g : 18 g/mol = 0.137

b. moles of butane :

= 2/10 x mol water

= 2/10 x 0.137

= 0.0274

c. mass of butane :

= 0.0274 x 58 g/mol

= 1.5892 g

d. moles of oxygen :

= 13/2 x mol butane

= 13/2 x 0.0274

= 0.1781

e. mass of oxygen :

= 0.1781 x 32 g/mol

= 5.6992 g

Answer 2

0.137moles of water is formed, 0.0274 moles or 1.5892 g of butane burned and 0.1781 moles or 5.6992 g of O₂ is used.

What is combustion reaction?

Those reaction in which fuel is oxidized by the oxygen molecules and produce carbon dioxide and water molecule.

Given chemical reaction is:
2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

Given mass of water = 2.46 grams

Moles will be calculated as:

n = W/M, where

W = given mass

M = molar mass

(a) Moles of water formed is calculated as:

Moles of water n = 2.46g / 18 g/mol = 0.137moles

(b) From the stoichiometry of the reaction, it is clear that:

10 moles of water = produced by 2 moles of butane

0.137 moles of water = produced by 2/10×0.137=0.0274 moles of butane

(c) Weight of butane is calculated by using moles:

W = 0.0274 × 58 g/mol = 1.5892 g

(d) From the stoichiometry of the reaction, it is clear that:

2 moles of butane = react with 13 moles of O₂

0.027 moles of butane = react with 13/2×0.027=0.1781 moles of O₂

(e) Mass of oxygen is calculated as:
W = 0.1781 x 32 g/mol = 5.6992 g

Hence, (a) 0.137moles, (b) 0.0274 moles, (c) 1.5892 g, (d) 0.1781 moles and (e) 5.6992 g.

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Related Questions

true or false
sugar melting an example of oxidation
and
water evaporating

Answers

Answer:

false i think

Explanation:

Which of the following is an example of a chemical element a. Salt B.water c.sugar d.sodium

Answers

Answer:

the answer is sodium

Explanation:

hope this helps

yes sir , the answer should be sodium

A scientist was studying a population of elephants. The first year, he counted a population of 80. Over the next eight
years, the population's numbers were 94, 100, 103, 110, 125, 120, 125, 120. What appears to be the carrying capacity
for this population?
0 120
0124
O 125
O 126

Answers

Answer:

The carrying capacity of this population would be 125 we know this because we see that this number occur multiple times and seems to be the tipping point after which the number of the population always go down

Answer:

The carrying capacity of this population would be 125 we know this because we see that this number occur multiple times and seems to be the tipping point after which the number of the population always go down

Explanation:

Pls help!!
1000 L of nitrogen and 2400 L of hydrogen are mixed to produce ammonia. The volume of ammonia produced is

A. 1200 L

B. 1000 L

C. 2400 L

D. 1600 L

Answers

Answer: D. 1600 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}[/tex]

[tex]\text{Number of moles of nitrogen}==\frac{1000L}{22.4L}=44.6moles[/tex]

[tex]\text{Number of moles of hydrogen}==\frac{2400L}{22.4L}=107.1moles[/tex]

[tex]N_2(g)+3H_2(g)\rightarrow 2NH_3(g)[/tex]  

According to stoichiometry :

3 moles of [tex]H_2[/tex] require 1 mole of [tex]N_2[/tex]

Thus 107.1 moles of [tex]H_2[/tex] will require=[tex]\frac{1}{3}\times 107.1=35.7moles[/tex] of [tex]N_2[/tex]

Thus [tex]H_2[/tex] is the limiting reagent as it limits the formation of product and [tex]N_2[/tex] is the excess reagent.

As 3 moles of [tex]H_2[/tex] give = 2 moles of [tex]NH_3[/tex]

Thus 107.1 moles of [tex]H_2[/tex] give =[tex]\frac{2}{3}\times 107.1=71.4moles[/tex]  of [tex]NH_3[/tex]

Volume of [tex]NH_3=moles\times {\text {Molar volume}}=71.4moles\times 22.4L/mol=1600L[/tex]

Thus volume of ammonia produced is 1600 L

In the following compound (HCl) How many electrons are gained and lost by each atom?
In the following compound (NaCl) How many electrons are gained and lost by each atom

Answers

Explanation:

In HCL, one positive atom is given to chlorine from hydrogen so that it can complete it's octate. chlorine take one electron from hydrogen.

In NaCl, Sodium takes one electron from chlorine to complete its orbit with eight electrons. Chlorine gives one electron to sodium.

Which statement describes why the viscosity of water is lower than that of
olive oil?
A. The molecules that make up water have more kinetic energy than
the molecules that make up olive oil.
B. The molecules that make up water can more easily slide past one
another than the molecules that make up olive oil.
C. The molecules that make up water have less kinetic energy than
the molecules that make up olive oil.
D. The molecules that make up water are larger than the molecules

Answers

Answer:

Option B. The molecules that make up water can more easily slide past one another than the molecules that make up a olive oil.

The molecules that make up water can more easily slide past one another than the molecules that make up olive oil. Hence, option B is correct.

What is viscosity?

Viscosity is a term used to describe FLUIDS, which includes liquids and gases. Viscosity refers to the ability of a gas or liquid to resist flow.

Olive oil has a higher viscosity than water because it is a much larger molecule than water with larger dispersion forces.

Hence, option B is correct.

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Calculate how many grams of Aluminum are needed to produce 21.6 grams of Aluminum oxide (Al2O3).

4Al + 3O2 → 2Al2O3

i need this like rn please.

Answers

Answer:

0.347

Explanation:

Al is the limiting reagent.

Explanation:

The stoichiometry of the reaction is such that 4 moles of Al are required for every 3 moles of diatomic oxygen. This means that if the ratio of Al to diatomic oxygen is greater than 4/3, then the oxygen is the limiting reagent. If the ratio of Al to diatomic oxygen is less than 4/3, then Al is the limiting reagent.

The problem state that the ratio of Al to diatomic oxygen is

0.32

0.26

=

16

13

=

48

39

<

52

39

=

4

3

The ration of Al to diatomic oxygen is less than 4/3, so Al is the limiting reagent.

We can also see this if we ask the question "How much Aluminum" is required to completely react 0.26 moles of diatomic oxygen??

0.26

moles

O

2

×

4

moles

A

l

3

moles

O

2

0.347

moles

A

l

So it would take 0.347 moles of Al to completely react with all of the oxygen, however there is only 0.32 moles of Aluminum present, so there is not enough Al to react with all of the oxygen, and so we say that the Al is the limiting reagent.

The mass of Aluminum are needed to produce 21.6 grams of Aluminum oxide (Al₂O₃) is

What is mass?

Mass of any element is equal to the product of its number of moles and molar mass.

For the compound, Aluminum oxide (Al₂O₃)

The atomic masses of Aluminum is 23 and oxygen is 16.

Molecular or molar mass = ( 2 × 23 ) + ( 3 × 16 ) units

M = 46 + 48 = 94 units

The mass of Aluminum in 1 mole of aluminum oxide ,46 grams in 94 grams

Mass of Aluminum in the given 21.6 g of Aluminum oxide will be;

94 grams of Aluminum oxide contains 46 grams of Aluminum.

21.6 grams of Aluminum oxide will contain ( 46 / 94 ) × 21.6 = 10.57g of Aluminum.

Therefore, 10.57g of Aluminum are needed to produce 21.6 grams of Aluminum oxide (Al₂O₃)

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Explain how the transfer of heat causes air to rise?
plzzzzzz help mee
also friction is not the answer

Answers

Answer:

Air in the atmosphere acts as a fluid. The sun's radiation strikes the ground, thus warming the rocks. As the rock's temperature rises due to conduction, heat energy is released into the atmosphere, forming a bubble of air which is warmer than the surrounding air. This bubble of air rises into the atmosphere.

Explanation:

I hope this helps and pls mark me brainliest :)

What is the percent composition of nitrogen in a 2.57 g sample of Al(NO3)3?

Answers

Answer:

19.8% of Nitrogen

Explanation:

In the Al(NO₃)₃ there are:

1 atom of Al

3 atoms of N

And 9 atoms of O

The molar mass of Al(NO₃)₃ is:

1 Al * (26.98g/mol) = 26.98g/mol

3 N * (14g/mol) = 42g/mol

9 O * (16g/mol) = 144g/mol

26.98 + 42 + 144 = 212.98g/mol

We can do a conversion using these molar masses to find the mass of nitrogen is the sample, that is:

2.57g * (42g/mol / 212.98g/mol) =

0.51g N

Percent composition of nitrogen is:

0.51g N / 2.57g * 100

= 19.8% of Nitrogen

Which statement best explains the type of bond that will form between two elements from group 6A in the model?

A. The two elements will form a covalent bond because both elements will share a single electron in order to have full outer shells

B. The two elements will form a covalent bond because both elements will share a pair of electrons in order to have full outer shells.

C. The two elements will form an ionic bond because one of the elements will donate one electron to the other element in order to have full outer shells.

D. The two elements will form an ionic bind because one of the elements will donate two electrons to the other elements in order to have full outer shells.

*Will give brainliest*​

Answers

Answer:

D is the answer

Like my answer

There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, the correct option is option D.

What is chemical Compound?

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.

An ionic compound is a metal and nonmetal combined compound.  Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.

The two elements will form an ionic bind because one of the elements will donate two electrons to the other elements in order to have full outer shells.

Therefore, the correct option is option D.

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2. A sample of oxygen gas is placed in a rigid 1.5L glass container at STP. If the gas is
heated to 100 degrees (Celcius) what is the new pressure in mmHg?

Answers

The new pressure : P₂ = 1038.39 mmHg

Further explanation

Given

1.5 L container at STP

Heated to 100 °C

Required

The new pressure

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure).

So P₁ =  1 atm = 760 mmHg

T₁ = 273 K

T₂ = 100 °C+273 = 373 K

Gay Lussac's Law  

When the volume is not changed, the gas pressure is proportional to its absolute temperature  

[tex]\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]

Input the value :

P₂=(P₁.T₂)/T₁

P₂=(760 x 373)/273

P₂ = 1038.39 mmHg

Na * 6.02 * 10^23 pls help an it got to include na

Answers

Answer:

6.02E23Na

Explanation:

you just convert the element to a decimal form

A camper pours 500 g of coffee, initially in a pot at 80 oC, into a 110-g aluminum cup initially at 30 oC. What is the final temperature? Assume that coffee has the same specific heat as water and that no heat is exchanged with the surroundings. (cwater=4.18 J/goC). (cAluminum=0.900J/g.C)

Answers

The final temperature : t=77.74 °C

Further explanation

Given

500 g coffee, t = 80 °C

110 g aluminum cup, t = 30 °C

Required

The final temperature

Solution

Q in = Q out

Q absorbed = Q released

Q aluminum cup = Q coffee

110 x 0.9 x (t-30)=500 x 4.18 x (80-t)

99t-2970=167200-2090t

2189t=170170

t=77.74 °C

determine the density of an object that is 25 cm long 10 cm wide and 2 cm high with a mass of 50 g

Answers

Answer:

[tex]\boxed {\boxed {\sf \rho= 0.1 \ g/cm^3 }}[/tex]

Explanation:

Density is found by dividing the mass by the volume.

[tex]\rho=\frac{m}{v}[/tex]

The mass is 50 grams, but we have to find the volume.

Assuming this is a solid rectangular object, we can use this formula for volume:

[tex]v=l*w*h[/tex]

The length is 25 centimeters, the width is 10 centimeters, and the height is 2 centimeters.

[tex]v= 25 \ cm * 10 \ cm * 2 \ cm[/tex]

[tex]v= 250 \ cm^2 * 2 \ cm[/tex]

[tex]v= 500 \ cm^3[/tex]

Now we know the mass and volume:

[tex]m= 50 \ g\\v= 500 \ cm^3[/tex]

Substitute the values into the formula.

[tex]\rho = \frac{50 \ g}{500 \ cm^3}[/tex]

[tex]\rho= 0.1 \ g/cm^3[/tex]

The density of the object is 0.1 grams per cubic centimeter.

please help
find the impractical formula of the compound that contains 46.6 g of magnesium 61.4 g of sulfur and 92.0 g of oxygen. type subscripts for each element

Answers

Answer: The empirical formula is [tex]MgSO_3[/tex]

Explanation:

Mass of Mg= 46.6 g

Mass of S= 61.4 g

Mass of O = 92.0 g

Step 1 : convert given masses into moles.

Moles of Mg =[tex]\frac{\text{ given mass of Mg}}{\text{ molar mass of Mg}}= \frac{46.6g}{24g/mole}=1.942moles[/tex]

Moles of S =[tex]\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{61.4g}{32g/mole}=1.918moles[/tex]

Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{92.0g}{16g/mole}=5.75moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Mg = [tex]\frac{1.942}{1.918}=[/tex]

For S= [tex]\frac{1.918}{1.918}=1[/tex]

For O =[tex]\frac{5.75}{1.918}=3[/tex]

The ratio of Mg: S: O = 1: 1: 3

Hence the empirical formula is [tex]MgSO_3[/tex]

37 grams of H3PO4 ????

Answers

Answer:

76 grams is the correct answer to this question

PLEASE HELP RN ITS URGENT

Answers

Answer: transporting oxygen-rich blood to the body

Explanation:

Select all that are compounds.
H2O
CH4
He
O2
NaCl

Answers

Answer:

NaCl, H2O

Explanation:

Compounds are substances that contain atoms of two or more different elements.

NaCL , H2O ...........

If 5.3 moles of magnesium phosphate react with excess sodium chloride how many moles of magnesium chloride will be formed?

Answers

Answer:
154.0831 g
Explanation:
The formula for the calculation of moles is shown below:

Given: For
Given mass = 41.0 g
Molar mass of = 24.31 g/mol
Moles of = 41.0 g / 24.31 g/mol = 1.6865 moles
Given: For
Given mass = 175 g
Molar mass of = 162.2 g/mol
Moles of = 175 g / 162.2 g/mol = 1.0789 moles
According to the given reaction:

3 moles of Mg react with 2 moles of
1 mole of Mg react with 2/3 moles of
1.6865 mole of Mg react with (2/3)*1.6865 moles of
Moles of = 1.1243 moles
Available moles of = 1.0789 moles
Limiting reagent is the one which is present in small amount. Thus, is limiting reagent. (1.0789 < 1.1243)
The formation of the product is governed by the limiting reagent. So,
2 moles of gives 3 moles of magnesium chloride
1 mole of gives 3/2 moles of magnesium chloride
1.0789 mole of gives (3/2)*1.0789 moles of magnesium chloride
Moles of magnesium chloride = 1.61835 moles
Molar mass of magnesium chloride = 95.21 g/mol
Mass of magnesium chloride = Moles × Molar mass = 1.61835 × 95.21 g = 154.0831 g

How many moles of NaF are produced in the resction between sodium bromide and calcium fluoride when 550 grams of sodium bromide are used

Answers

Answer: 5 moles of NaF would be produced when 550 grams of Sodium bromide are used.

Explanation:

From the question, the balanced chemical formula is illustrated below:

2NaBr + CaF2 → 2NaF + CaBr2

From the equation above;

Molecular mass of NaBr = 23 + 80 = 103g/ mol

Molecular mass of CaF2= 40+ (19×2)= 78g/ mol

Molecular mass of NaF = 23+19 = 42g/ mol

From the balanced chemical equation;

2 moles of NaBr reacted with 1mole of CaF to give 2 moles of NaF.

That is, 2 moles of NaBr= 2× 103 = 206g

2moles of NaF = 2×42= 84g

If 206g of NaBr yielded 84g of NaF

Therefore 550g of NaBr will yield Xg of NaF

X= 550×84/206

X= 224.27g of NaF

But 42g = 1 mole of NaF

Therefore 224.27g = X mole of NaF

X= 224.27 ×1/42

X is approximately 5moles.

Convert 4, 294 grams to pounds. Use the conversion factor 1 pound = 453.59 grams.

Answers

294( want (lb)/ give) = 0.68g

1. What do microorganisms share in common?​

Answers

Answer:

Bacterial species are typified by their diversity. There are three notable common traits of bacteria, 1) lack of membrane-bound organelles, 2) unicellular and 3) small (usually microscopic) size.

Explanation:

What Are the Characteristics Common to All Bacteria?

Single-Celled. Perhaps the most straightforward characteristic of bacteria is their existence as single-celled organisms. ...

Absent Organelles. ...

Plasma Membrane. ...

Cell Walls. ...

DNA.

The element with the atomic mass of 12 amu, and 6 nuetrons: (E2) A (B3) (D4) O (14)

Answers

Answer:like my photo bc i like it

Explanation:

omg i look .........................................  

Solid to Gas

As a change is state takes place, heat _______ and temperature _______.

A. Increases, stay the same
B. Stay the same, changes
C. Increases, increases

Answers

Answer:

c. c. c c c c c cçcc. ccccccccc

Explanation:

ccc cc

When solid converts to gas then heat is required to break the intermolecular forces of attraction between the particles. In this process heat increase but temperature remains the same. So option A is correct option.

What is phase transition?

Phase transition is a process in which transition takes place from one state to another of a medium on changing temperature or pressure.  Phase transition is a physical process as there is no breaking of old bond and forming of new bonds takes place.

During phase transition temperature remain constant as the extra heat that is given to the system that goes into breaking of  intermolecular forces of attraction between the particles. So overall temperature remains same but heat keeps on increasing. Hence option A is correct.

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Ca+Cl2-->CaCl2 Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.

Answers

Answer:

Oxidation half

Ca -----> Ca2+ +2elecyrons

Reduction half

Cl2 + 2electrons ------> 2Cl-

Explanation:

200cm3 of hydrogen diffused through a porous pot in 40secs. How long will it take 300cm3 of chlorine to diffuse the same pot?

Answers

Answer: time taken by chlorine to diffuse is 60 secs

Select the correct answer.

In this reaction, what effect does a change in the concentration of substances have on the reverse reaction rate?

CaCO3(s) ⇌ CaO(g) + CO2(g)

A.
The rate of the reverse reaction increases with an increase in the concentration of CaCO3(s).
B.
The rate of the reverse reaction increases with an increase in the concentration of CaO(g) and CO2(g).
C.
The rate of the reverse reaction decreases with a decrease in the concentration of CaCO3(s).
D.
The rate of the reverse reaction decreases with an increase in the concentration of CaO(g) and CO2(g).
E.
The rate of the reverse reaction increases with a decrease in the concentration of CaO(g) and CO2(g).

Answers

Answer:

A. The rate of the reverse reaction increases with an increase in the concentration of CaCO3(s)

Explanation:

If the concentration of a reactant has increased, The substance will shift in the direction of the reaction that uses the reactants, So that the Reactants substance Increases.

A. ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎

Copper (ii) carbonate decomposes to form copper (ii) oxide grains and carbon dioxide gas is given off.

Answers

Answer:

yes

Explanation:

The correct equation for the decomposition of copper carbonate is:

CuCO3 → CuO + CO2

Picture a neutral S atom. This neutral atom will have
valence electrons. To reach a more stable configuration, this atom will
(gain, lose) electrons. The charge of the ion that forms will be
ASAP PLEASE

Answers

Answer:

has 6 valence electrons as its in group 6

the atom will gain electrons

the charge will be 2- as it will gain 2 electrons to be a full configuration

a train is traveling on a straight track. it travels 200 kilometers in 4 hours, what measure can you find with these values?

Answers

Answer:

200 km is a measure of distance 4 hours is a measure of time Hence you can measure rate of change, instaneous rate of change, linear change and distribution of timeUpdated: Speed
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