What is 4/5 to the 5th power
Ginny and her classmates formed a study group. The number of girls in the study group was 3 more than twice the number
of boys. There were 11 girls in the study group. How many boys were in the study group?
Answer:
I think the answer is 4 boys
Step-by-step explanation:
Let the no of boys be y.
No. of girls = 11
= 3 + 2y (equation)
3 + 2y = 11
3 - 3 + 2y = 11 - 3
2y = 8
2y/2 = 8/2
y = 4
Boys = 4
The values of the sample mean, sample standard deviation, and (estimated) standard error of the mean are 2.482, 1.614, and 0.295, respectively. Does this data suggest that the true average percentage of organic matter in such soil is something other than 3%
Complete Question
The complete question is shown on the first uploaded image
Answer:
Yes the test suggest that the true average percentage of organic matter in such soil is something other than 3%
Step-by-step explanation:
From the question we are told that
The sample mean is [tex]\= x = 2.482\%[/tex]
The standard deviation is [tex]\sigma = 1.614[/tex]
The standard error is [tex]SE = 0.295[/tex]
The sample size is [tex]n = 30[/tex]
The level of significance is [tex]\alpha = 0.05[/tex]
The null hypothesis is [tex]H_o : \mu = 3\%[/tex]
The alternative hypothesis is [tex]H_a : \mu \ne 3\%[/tex]
Now the degree of freedom is evaluated as
[tex]df = n - 1[/tex]
[tex]df = 30 - 1[/tex]
[tex]df = 29[/tex]
The test statistics is mathematically evaluated as
[tex]t = \frac{ 2.482 - 3}{ 0.295}[/tex]
[tex]t = -1.756[/tex]
The p-value is obtained from the the student t -distribution table , the value is
[tex]p-value = P( T \le t)= 2 * t_{ t, df } = t_{ -1.756 , 29 } = 2 *0.0448= 0.0896[/tex]
The reason for the 2 in the equation is because the test is a two -tailed test i.e -1.756 and 1.756
Given that the [tex]p-value > \alpha[/tex] then we fail to reject the null hypothesis
Hence the test the suggest that the true average percentage of organic matter in such soil is something other than 3%
kh
use h = 10. and k = 4
4
Please answer this correctly without making mistakes I need to finish this today as soon as possible
Answer:
14 miles
Step-by-step explanation:
Since we know that the distance of the paths from Cedarburg to Allenville is 22 and 13/16 miles, and we know the distance from Cedarburg to Lakeside is 8 and 13/16 miles.
We know that the total distance is made up of the distance from C to L and L to A.
So 22 and 13/16 = 8 and 13/16 + L to A
We can subtract 22 and 13/16 by 8 and 13/16 to get 14 miles.
Hope this helps.
Officer Jacobi drove 180 miles in his patrol car during part of May. The distance represents 40% of May. How many miles did he drive all of May? a) 710 miles b) 420 miles c) 720 miles d) 450 miles Need Help on How to work this problem out, what formula would I use?
Answer:
D: 450 miles
Step-by-step explanation:
So we know that Officer Jacobi drove 180 miles, which represents 40% of the total distance driven. In other words, 40% of the total distance traveled is 180. Thus (let D be the total distance traveled):
[tex]0.4D=180[/tex]
This equation is basically saying that 40% (0.4) of the total distance driven is 180 miles. To solve for the total distance D, we can divide both sides by 0.4. Thus:
[tex]0.4D=180\\D=450[/tex]
So the answer is D or 450 miles.
Note that there isn't a specific formula you would use. These types of problems require you to write out an equation yourself.
I need help with questions 1 and 2 and please be specific and please no links or I will have you reported
Answer:
Step-by-step explanation:
NO perimeter does not map directly to area....
take a square with side of 5 ... area is 5*5 which is 25 perimeter is 20
if you now take a rectangle with long side 8 and short side 2
the perimeter is 20 but the area is 16
PLEASE PLEASE PLEASE HELP ME ANSWER THIS QUESTION QUICK!! The picture of the question is down below.
Answer:
x = -2 or x = 2
Step-by-step explanation:
The solution is the points of intersection of the line and the parabola.
x = -2 or x = 2
Answer:
x = -2 and x=2
Step-by-step explanation:
The solution to the system is where the two graphs intersect
The meet at x = -2 and x=2
Help Quick Please. Will give brainliest.
Answer:
72[tex]\sqrt{3}[/tex] units²
Step-by-step explanation:
The area (A) of the triangle is calculated as
A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the perpendicular height )
Here b = ST = a = 12 and h = RS
To calculate RS use the tangent ratio in the right triangle and the exact value
tan60° = [tex]\sqrt{3}[/tex] , thus
tan60° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{RS}{ST}[/tex] = [tex]\frac{RS}{12}[/tex] = [tex]\sqrt{3}[/tex] ( multiply both sides by 12 )
RS = 12[tex]\sqrt{3}[/tex]
Thus
A = [tex]\frac{1}{2}[/tex] × 12 × 12[tex]\sqrt{3}[/tex] = 6 × 12[tex]\sqrt{3}[/tex] = 72[tex]\sqrt{3}[/tex] units²
evaluate the expression 3 divided by -729
Answer:
-0.00411522633
Step-by-step explanation:
Find the measure of b. A. 63 B. 27 C. 31.5 D. 126
Answer:
126°
Step-by-step explanation:
If that angle is 27, so is angle a.
180-27-27=126
2 divided by ___=42 two divided by what equals 42?
II. Round to the nearest hundred.
11. 582
12. 1,234
13. 640
14. 770
15. 1,104 can you please tell what the answer?
Answer:
582-600
1,234-1,200
640-600
770-800
1,104-1,100
How many degrees must the flyswatter pass through before it is horizontal?
Answer:
90°
Step-by-step explanation:
assuming it's upright and you swat it down it will go down by 90°
Please help almost done will give brainliest
x and y are related.
х
-2
-1
0
1
2
3
y
-4
-4.5
-5
-5.5
-6
-6.5
y = -0.5x + [?]
Enter the answer that belongs in [?].
Answer:
-5
Step-by-step explanation:
y = -0.5x + [?]
The equation is put in slope intercept form
slope intercept form: y = mx + b
where m = slope and b = y intercept
We want to find the y intercept.
the y intercept is the value of y when x = 0
looking at the table when x = 0, y = -5 so the y intercept is -5.
In other words -5 belongs in [?]
What is the domain of the function in the graph?
Answer:
7≤r≤12
Step-by-step explanation:
The domain is the values that the input takes
The input goes from 7 to 12
7≤r≤12
Answer: Choice B) [tex]7 \le r \le 12[/tex]
=============================================================
Explanation:
The domain is the set of allowed x inputs of a function.
How far to the left can we go on this red line? That would be x = 7.
How far to the right? That would be x = 12.
We can have x equal anything between 7 and 12, including both endpoints. We include the endpoints because they are filled in circles (as opposed to open holes).
So the domain is [tex]7 \le x \le 12[/tex]. If we replace x with r, then we update that inequality into [tex]7 \le r \le 12[/tex]. This replacement happens because r is along the horizontal x axis.
Explain why within any set of ten integers chosen from 2 through 24, there are at least two integers with a common divisor greater than 1 g
Step-by-step explanation:
Here are some examples of ten integers (in this case prime numbers) chosen from 2 to 24;
2, 3, 5, 7, 9, 15, 17, 19, 21, 23
Lets take for example the integers 15 and 21, they have a common divisor 3 which is greater than 1. Which implies that the number 3 can divide through 15 and 21 without a remainder, that is, 21 ÷ 3 = 7, 15 ÷ 3 = 5. Also note that 3 is a divisor of 9.
Therefore, we could right say that within any set of ten integers chosen from 2 through 24, there are at least two integers with a common divisor greater than 1.
Please answer this correctly without making mistakes
Answer:
6 1/6 pounds
Step-by-step explanation:
since 2/3 coverted into sixths is 4/6, and 14-6 is 8, and 1/2 into sixths is 3/6, 4/6-3/6 is 1/6. You put the whole in the front and you have 6 1/6
Define the operation a∇b = 2+b^a What is the value of (1∇2)∇3?
Answer:
83
Step-by-step explanation:
1∇2= (2+2^1)
=2+2=4
(4)∇3= (2+3^4)
=2+81
=83
(II) Time intervals measured with a stopwatch typically have an uncertainty of about 0.2 s, due to human reaction time at the start and stop moments.What is the percent uncertainty of a hand-timed measurement of (a) 5.5 s, (b) 55 s, (c) 5.5 min?
Answer:
(a) 36.36%
(b) 0.36%
(c) 0.06%
Step-by-step explanation:
Given that the time intervals measured with a stopwatch have an uncertainty of about 0.2 s.
We want to know what is the percent uncertainty of a hand-timed measurement of:
(a) 5.5 s
Percentage = (0.2/5.5) × 100
≈ 36.36%
(b) 55 s
Percentage = (0.2/55)×100
≈ 0.36%
(c) 5.5 min
5.5 min = 5.5 × 60 s
= 330 s
Percentage = (0.2/330)×100
≈ 0.06%
(100 points) Select the correct answer.
Danny's 7 friends contributed an equal amount of money to buy him a birthday present. The present cost $84. How much money did each friend contribute?
A. 12
B. 36
C. 48
D. 84
Contribution per head
84/712Option A
What are the solutions?
It's the third option.
Completing the square yields
x ² + 9x + 7 = 0
(x ² + 9x + 81/4) + 7 = 81/4
(x + 9/2)² + 7 = 81/4
Now solving for x gives
(x + 9/2)² = 53/4
x + 9/2 = ± √(53/4) = ± √53/2
x = (-9 ± √53)/2
A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores. Marketing managers are prone to look at the estimate and ignore sampling error. A random sample of 36 stores this year shows mean sales of 83 units of a small appliance with a standard deviation of 5 units. During the same point in time last year, a random sample of 49 stores had mean sales of 78 units with standard deviation 3 units.Required:Construct a 95 percent confidence interval for the difference in population means.
Answer:
The 95% confidence interval for the difference in population means is (−26.325175 , 36.325175)
Step-by-step explanation:
Given that :
sample size n₁ = 36
sample mean [tex]\over\ x[/tex]₁ = 83
standard deviation [tex]\sigma[/tex]₁ = 5
sample size n₂ = 49
sample mean [tex]\over\ x[/tex]₂= 78
standard deviation [tex]\sigma[/tex]₂ = 3
The objective is to construct a 95% confidence interval for the difference in the population means
Let the population means be [tex]\mu_1[/tex] and [tex]\mu_2[/tex]
The 95% confidence interval or the difference in population means can be calculated by using the formula;
[tex](\overline{x_1} - \overline{x_2}) \pm t_{\alpha /2} \ \times s_{p}[/tex]
where;
the pooled standard deviation [tex]s_{p} = \dfrac{(n_1-1)s_1^2+(n_2-1)s^2_2}{n_1+n_2-2}[/tex]
[tex]s_{p} = \dfrac{(36-1)5^2+(49-1)3^2}{36+49-2}[/tex]
[tex]s_{p} = \dfrac{(35)25+(48)9}{83}[/tex]
[tex]s_{p} = \dfrac{875+432}{83}[/tex]
[tex]s_{p} = \dfrac{1307}{83}[/tex]
[tex]s_p[/tex] = 15.75
degree of freedom = [tex]n_1 +n_2 -2[/tex]
degree of freedom = 36+49 -2
degree of freedom = 85 - 2
degree of freedom = 83
The Critical t- value 95% CI at df = 83 is
t critical = T.INV.2T(0.05, 83) = 1.9889
Therefore, for the population mean , we have:
= (83 - 78) ± (1.9889 × 15.75)
= 5 ± 31.325175
= 5 - 31.325175 , 5 + 31.325175
= (−26.325175 , 36.325175)
What is the result of question?
Answer:
B
Step-by-step explanation:
x can not be greater than (1,325-270)/26 because $270 is fixed for the rental
Find the 100th term of the sequence 4, 7, 10, 13...
a) 301
b) 313
c) 281
d) 279
Answer:
A
Step-by-step explanation:
The first term of the sequence is 4, the common difference is 3. So the equation of this sequence is 4+(n-1)*3 or 1+3*n. Plug in n=100
ZA and ZB are complementary angles. If m A = (8x + 27)° and m
ZB = (6x – 21)°, then find the measure of ZB.
Answer:
15
Step-by-step explanation:
Complementary angles add to 90 degrees
8x+27 + 6x-21 = 90
Combine like terms
14x+6 = 90
Subtract 6 from each side
14x+6-6 = 90-6
14x = 84
Divide by 14
14x/14 = 84/14
x=6
We want angle B
B = 6x-21 = 6*6-21 =36-21 = 15
Find the area of the shaded regions:
area of Arc subtending [tex]360^{\circ}[/tex] (i.e. the whole circle) is $\pi r^2$
so area of Arc subtending $\theta^{\circ}$ is, $\frac{ \pi r^2}{360^{\circ}}\times \theta^{\circ}$
$\theta =72^{\circ}$ so the area enclosed by one such arc is $\frac{\pi (10)^272}{360}$
abd there are 2 such arcs, so double the area.
[tex] \LARGE{ \underline{ \boxed{ \rm{ \purple{Solution}}}}}[/tex]
Given:-Radius of the circle = 10 inchesAngle of each sector = 72°Number of sectors = 2To FinD:-Find the area of the shaded regions....?How to solve?For solving this question, Let's know how to find the area of a sector in a circle?
[tex] \large{ \boxed{ \rm{area \: of \: sector = \frac{\theta}{360} \times \pi {r}^{2} }}}[/tex]
Here, Θ is the angle of sector and r is the radius of the circle. So, let's solve this question.
Solution:-We have,
No. of sectors = 2Angle of sector = 72°By using formula,
⇛ Area of shaded region = 2 × Area of each sector
⇛ Area of shaded region = 2 × Θ/360° × πr²
⇛ Area of shaded region = 2 × 72°/360° × 22/7 × 10²
⇛ Area of shaded region = 2/5 × 100 × 22/7
⇛ Area of shaded region = 40 × 22/7
⇛ Area of shaded region = 880/7 inch. sq.
⇛ Area of shaded region = 125.71 inch. sq.
☄ Your Required answer is 125.71 inch. sq(approx.)
━━━━━━━━━━━━━━━━━━━━
ax+r=7 , solve for x
Answer:
3
Step-by-step explanation:
a is 4 and 3 is x so 4+3=7
Answer: a=2 {x=3} r=1. 2(3)+ 1= 7
Step-by-step explanation:
If there are 25 students in a class - 11 are guys and 14 are girls what is the probability that one of the students on the class is a guy?
Answer:
0.44
Step-by-step explanation:
11/25 = 0.44 = 44%
Answer:
11/25
Step-by-step explanation:
since there are 25 students, there will be 25 choices, and the 25 will be the denominator
and there are 11 guys so there will be 11 choices of guys and the 11 will go on top
A website developer wished to analyze the clicks per day on their newly updated website. Let the mean number of clicks per day be μ. If the website developer wants to know if the number of clicks per day is different than 200 clicks a day, on average, what are the null and alternative hypotheses?
Answer:
Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 200 clicks a day
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 200 clicks a day
Step-by-step explanation:
We are given that a website developer wished to analyze the clicks per day on their newly updated website.
The website developer wants to know if the number of clicks per day is different than 200 clicks a day, on average.
Let [tex]\mu[/tex] = mean number of clicks per day.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 200 clicks a day
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 200 clicks a day
Here, the null hypothesis states that the mean number of clicks per day is 200 clicks a day.
On the other hand, the alternate hypothesis states that the mean number of clicks per day is different than 200 clicks a day.
Hence, this is the correct null and alternative hypotheses.
Answer: Null Hypothesis [tex]H_0:\mu=200[/tex]
Alternate Hypothesis[tex]H_a:\mu\neq200[/tex]
Step-by-step explanation:
Let [tex]\mu[/tex] be the mean number of clicks per day.
Given, a website developer wished to analyze the clicks per day on their newly updated website.
The website developer wants to know if the number of clicks per day is different than 200 clicks a day, on average.
i.e. he wants to check either [tex]\mu=200\text{ or }\mu\neq 200[/tex]
Since a null hypothesis is a hypothesis believes that there is no difference between the two variables whereas an alternative hypothesis believes that there is a statistically significant difference between two variables.
So, Null Hypothesis [tex]H_0:\mu=200[/tex]
Alternate Hypothesis[tex]H_a:\mu\neq200[/tex]
Hence, the required null and alternative hypotheses.
Null Hypothesis [tex]H_0:\mu=200[/tex]
Alternate Hypothesis[tex]H_a:\mu\neq200[/tex]