Answer:
the friction force f=36
and the coefficient of friction =0.45
1/2 means that the voltage (or charge) of the system will increase to half more of what is left in a time equal to t1/2 seconds. Therefore if a system is already at half charge (t1/2 seconds after starting) then after t1/2 more seconds the system will be charged to 50% plus half of 50%. That is 25% more, or 75% of the entire charge. Let's say that four t1/2's have gone by. That means that the charge (or voltage) is at (50% + 1/2*50% + 1/2*1/2*50% + 1/2*1/2*1/2*50%) = 93.75% of maximum charge. Yikes! Now look in your manual for a more simple mathematical derivation of this concept. Given t1/2 to be 0.4406 seconds, how long should it take to reach 75% of maximum charge? answer in seconds.
Answer:
The answer is "0.047".
Explanation:
Given value:
[tex]\to t_{\frac{1}{2}}= 0.4406\\\\\to V=0.9375 V_{max}[/tex]
Calculating the capacitance:
[tex]\to V=V_{max} (1-e^{\frac{-t}{Rc}})[/tex]
In this, the t = time, which is taken to calculates its maximum voltage.
[tex]\to 0.9375 V_{max} = V_{max}(1-e^{- \frac{t}{103\times(165.279\times10^{-6})}})\\\\\to e^{- \frac{t}{103\times(165.279\times10^{-6})}}= 0.0625\\\\\to - \frac{t}{103\times(165.279\times10^{-6})} = \ln(0.0625)\\\\\to -t= 0.01702\times(-2.77258) \\\\ \to -t = -0.04719 \\\\ \to t= 0.04719 \approx 0.047 \ s[/tex]
in a nuclear plant, 1 * 10 ^27 J of energy is available from mass conversion How much mass was lost ?
Answer:
[tex]1.2\times 10^{10}\ kg[/tex]
Explanation:
Given that,
The energy of the nuclear plant, [tex]E=10^{27}\ J[/tex]
We need to find how much mass wast lost.
The relation between energy and mass is given by :
[tex]E=mc^2[/tex]
Where
c is speed of light
[tex]m=\dfrac{E}{c^2}\\\\m=\dfrac{10^{27}}{(3\times 10^8)^2}\\\\m=1.2\times 10^{10}\ kg[/tex]
So, [tex]1.2\times 10^{10}\ kg[/tex] of mass was lost.
The final velocity of a car is 30m/s. The car is accelerating at a rate of 2.5m/s2
over an 2.8m/s2
8 second period of time. What is the initial velocity of the car?
Answer:
10m/s
Explanation:
Vf=v0+at
30m/s=v0+2.5m/s^2*8s
Solve for v0=10m/s
Sorry for the vague explanation I'm on my phone right now. Hope this still helps!
Initial velocity of the car where final velocity of a car is 30m/s and it is accelerating at a rate of 2.5 [tex]m/s^{2}[/tex] over an 2.8 [tex]m/s^{2}[/tex] 8 second period of time is 10 m/s.
To find the initial velocity of the car, we can use the kinematic equation:
Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t)).
Given the final velocity (v) as 30 m/s, acceleration (a) as 2.5 [tex]m/s^{2}[/tex], and time (t) as 8 seconds, we can plug these values into the equation:
30 m/s = u + (2.5 [tex]m/s^{2}[/tex] * 8 s).
Now, solve for the initial velocity (u):
30 m/s = u + 20 m/s.
Subtract 20 m/s from both sides:
u = 30 m/s - 20 m/s = 10 m/s.
Therefore, the initial velocity of the car is 10 m/s.
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. A boy wishes to throw a ball through a house via two small openings, one in the front and the other in
the back window, the second window being directly behind the first. If the boy stands at a distance of 5m
in front of the house and the house is 6m deep and if the opening in the front window is 5m above him
and that in the back window 2m higher, calculate the velocity and the angle of projection of the ball that
will enable him to accomplish his desire.
Answer:
1) The angle of projection of the ball is approximately 52.496° above the horizontal
2) The velocity with which the boy throws the ball to enable him accomplish his desire is approximately 14.769 m/s
Explanation:
In the projectile motion of the ball, the parameters are;
The distance the boy stands from the front of the house = 5 m
The depth of the house, front to back = 6 m
The height of the opening of the front window above him = 5 m
The height of the back window = 2 m higher than the front window
Therefore, the height of the back window = 5 m + 2 m = 7 m
1) The general formula for the vertical height of a parabolic projectile motion is given as follows;
y = a·x² + b·x + c
At y = 0, x = 0, therefore, c = 0
At y = 5, x = 5, we have;
5 = a·5² + b·5
∴ 5 = 25·a + 5·b...(1)
At y = 7, x = 11, we have;
7 = a·11² + b·11
7 = 121·a + 11·b...(2)
Making 'a' the subject of equation (1) and (2) and equating both values of 'a' gives;
For equation (1);
a = (5 - 5·b)/25 = 1/5 - b/5
a = 1/5 - b/5
For equation (2);
a = (7 - 11·b)/121 = 7/121 - b/11
a = 7/121 - b/11
∴ 1/5 - b/5 = 7/121 - b/11
1/5 - 7/121 = b/5 - b/11
86/605 = 6·b/55
b = (86/605) × (55/6) = 43/33
b = 43/33
a = 1/5 - b/5 = 1/5 - (43/33)/5 = -2/33
∴ y = (-2/33)·x² + (43/33)·x
The slope of the curve = dy/dx = d((-2/33)·x² + (43/33)·x)/dx = -4/33·x + 43/33
The slope of the curve at any point on the projectile = -4/33·x + 43/33
The slope at the origin is given by plugging x = 0 as follows
The slope at the origin = -4/33 × 0 + 43/33 = 43/33
The slope at the origin = tan(θ) = 43/33
Where;
θ = The angle of projection of the ball
∴ θ = arctan(43/33) ≈ 52.496°
The angle of projection of the ball, θ ≈ 52.496° above the horizontal
2) At the back widow, the equation for the vertical height, 'h', is given as follows;
[tex]h = (tan \angle \theta) \cdot x - \left(\dfrac{g}{2 \cdot v_1^2 \cdot cos^2 \angle \theta } \right )\cdot x^2[/tex]
Where;
h = The vertical height of the back window = 7 m
tan∠θ = 43/33
x = The horizontal distance of the back window from the boy = 5 m + 6 m = 11 m
g = The acceleration due to gravity = 9.8 m/s²
v₁ = The velocity with which the boy throws the ball
cos²∠θ = cos²(arctan(43/33)) = 1089/2938
Plugging in the values gives;
[tex]7 = \left (\dfrac{43}{33} \right) \times 11 - \left(\dfrac{9.8}{2 \cdot v_1^2 \cdot \dfrac{1089}{2938} } \right )\cdot 11^2[/tex]
[tex]\therefore v_1^2 = \dfrac{71981}{330}[/tex]
[tex]\therefore v_1 = \sqrt{\dfrac{71981}{330}} \approx \pm14.769[/tex]
The velocity with which the boy throws the ball to enable him accomplish his desire, v₁ ≈ 14.769 m/s.
Displacement a combination of
Answer:
Displacement a combination of distance
Explanation:
I'm not sure eh
HELP please!!!!!!!!!!!!!!!
Between steel and iron which is more suitable for making permanent magnets electromagnet and magnetic screen give reason for your answer
Answer:
steel is suitable for making permanent magnet
as still has hi factor coercity.
iron is for electromagnet and magnetic screen as iron loses its magnetism as soon as the switch is open and a current is switched off.
Steel is better suitable for making permanent magnets than soft iron since it has higher retentivity and lower coercivity. Compared to soft iron, steel has a lower retentivity and higher coercivity. Compared to soft iron, steel is more resilient and coercive.
What is retentivity and coercivity ?Retentivity : The ability to retain the generated magnetization in a magnetic material when the magnetizing force is removedCoercivity : A measure of the ability of a material to withstand an external magnetic field without becoming demagnetized.What is Permanent magnet and Electromagnet?Permanent magnet : To be suitable for permanent magnet, material should retain its magnetism for longer time, since steel have high retentivity and coercivity . Electromagnet : To be suitable for electromagnet , material should have magnetization and demagnetizing property .
Since , steels have high remanence which means it will remain magnetized even after magnetic field is removed which is not suitable for electromagnetic . iron has high permeability so magnetization is larger and have low retentivity so that material will not retain the magnetic properties . Magnetic screen , Iron has high permeability hence it can shield better than steel
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guys pls thi is my last pointa just answer this!!!!(WILL GIVE BRAINLY) A student takes apart a wooden box. What can they build with the materials from the box?
A) They cannot make anything with the materials.
B) They can make something new with the materials.
C) They can only make a wooden box from the materials.
Answer:
i guess u could pick "B" :)
Explanation:
1. If you were the organizer of this dance event, are you favor in moving the date on May? Why
or why not?
Answer:
I am in favor of the dance event being in may. Because it is nice weather outside, more people will decide to come and spend their time there. It is also light in the evening in may, meaning that you could have the dance event at any time, and younger people will still feel safe at night, meaning their parents will be more open to lwtting kids go.
1.) A projectile is launched at 32.1 m/s and 52.6 º above the horizontal. Determine the:
a.) Maximum height of the projectile.
b.) The time it takes to reach the maximum height
c.) Time of flight
d.) Range
Answer:
a.) Maximum height of the projectile. =32.5m
b.) The time it takes to reach the maximum height=2.6s
c.) Time of flight=2.6s
d.) Range=99.5m
Explanation:
So if any of ya got like, screenshots of all the answers for Edge, 2020. Lab-Kinetic Energy-student guide, That would be really helpful. If you could help me, then I will mark you brainliest. And for you trollers out there who just want the points, could you not steal them for this one? Anyways, thanks ya'll!
Answer:
has any one finished the lab yet?????
Explanation:
A scientist performed an investigation involving a reaction that produced AI, (SO )3. How many sulfur atoms are
represented in this formula?
Answer:
D
Explanation:
Because you add them all up it equals 9
Brad has three beakers of water. Each beaker contains 500 mL of water. The temperature of the water in the first beaker is 40°C. The water in the second beaker is at 100°C, and the water in the third beaker is at 60°C. As part of a lab experiment he will carefully combine the water in all three beakers. He predicts that the combined water will have a final temperature of 50°C.
Evaluate Brad’s claim and clearly state whether he is correct or not. Explain your answer to support your evaluation.
Explanation:
uasjwwbwjwbwia GJ wkwkjwnwnwjwjjwjwd7beba s
Which of the following determines the identity of an atom?
A. atomic mass
B. mass number
C. atomic number
D. charge
A human cannonball act uses springy bungee cords instead of gunpowder to launch a person through a long cylindrical tube into the air. If a cannon is capable of launching a 55 kg test dummy 11 m into the air when launched straight up, how much energy is stored in the bungee cords? *
A. 539J
B. 605 J
C. 2965J
D. 5929 J
Answer:
Energy stored, E = 5929 J
Explanation:
Given that,
The mass of a test dummy, m = 55 kg
It is launched 11 m into the air.
We need to find the energy stored in the bungee cords. It can be calculated as follows :
[tex]E=mgh\\\\E=55\times 9.8\times 11\\\\E=5929\ J[/tex]
So, 5929 J of energy is stored in the bungee cords.
Whatb19 ÷117= some help me with this
Answer:
0.16239316239316239316239
Explanation:
ang haba nang solve ko dito hehe
What is the direction of the force of an object moving in a circle?
1.toward the center of the circle
2.toward the outside of the circle
3.straight up
4.45 degree angle
Answer:
The answer is 45 degree angle
why do you think people translate sound waves from compression waves to transverse waves ?
Answer:
Sound waves are translated into transverse waves to know the frequency, amplitude, wavelength etc of the waves.
Explanation:
They translate the sound waves to know the depth about that specific waves and translating it to transverse waves makes it easier.
Hope it helps :D
PLEASE HELP PLEASEEEE
Answer:
Concave mirror
Explanation:
Because as we move the object far away from the mirror the image gets inverted
4. Premature wrinkling due to overexposure to the Sun, what am I?
Premature Aging
Mark as brainlist
Which graph shows a vehicle traveling at a constant speed?
(look at the attached photo)
The speed of a 1200 kg car increases from 5 to 29 m/s in 12 s.
What force accelerated the car?
Answer:I think I’m not sure But I think that the force that would be accurated the car would be friction or something like that and to solve the equation you would do f/m
Explanation:
It just makes sense
1. What is the velocity of an 250-kg that has 6,250 J of energy?
Please help
Explanation:
KE = 1/2mv^2
6,250 J =1/2(250kg) v ^2
6250 J = 125kgv^2
125kg. 125kg
v =
[tex] \sqrt{50} [/tex]
HELP ASAP!!! The gravitational pull of the Moon is much less than the
gravitational pull of Earth.
Which two statements are true for an object with a mass of 20 kilograms that
weighs 44 pounds on Earth?
O A The object's weight would be the same on the Moon
B. The object's weight would be less on the Moon
C. The object's mass would be the same on the Moon
DD. The object's mass would be less on the Moon
Answer:
I'm pretty sure its B and C
Explanation:
B bc the weight is gravitational pull x mass so when the object has same mass the weight is smaller on moon
C bc mass is the same - you can't change it
The correct answers are B and C
Anyone able to help with these questions, will give brainliest to first correct anwser
Answer:
b
Explanation:
I did this question earlier
An electric iron is connected to the mains power supply of 220 V. When the electric iron is
adjusted at 'minimum heating' it consumes a power of 360 W but at 'maximum heating' it takes a
power of 840 W. Calculate the current and resistance in each case.
Answer:
Given: V = 220V, Pmin = 360W, Pmax = 840W
For minimum heating case:
We know that
Pmin = VI
360 = 220 X I
I = 1.63 amp
R = V/I
R = 220/1.63
R = 134.96ohms
For maximum heating case:
We know that
Pmax = VI
840 = 220 X I
I = 3.81 amp
R = V/I
R = 220/3.81
R = 57.74 ohms
Which has more potential energy: a baseball held 1 m above the ground or a baseball held 2 m above the ground?
The baseball held 2 meters above the ground has more potential energy than the baseball held 1 meter above the ground.
The potential energy can be calculated with the following equation:
[tex] E_{p} = mgh [/tex]
Where:
m: is the mass of the baseball
g: is the acceleration due to gravity
h: is the height
We can see from equation (1) that the potential energy depends on height, mass, and gravity. Since the question refers to the same baseball, the mass is constant besides the acceleration due to gravity, so:
Potential energy above 1 m[tex] E_{p_{1}} = mg*1 = mg [/tex] (1)
Potential energy above 2 m[tex] E_{p_{2}} = mg*2 = 2mg [/tex] (2)
By entering equation (1) into 2 we have:
[tex] E_{p_{2}} = 2mg = 2E_{p_{1}} [/tex]
Hence, the potential energy of the baseball held 2 m above the ground is twice that of the baseball held 1 m above the ground.
Therefore, the baseball held 2 m above the ground has more potential energy.
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Please help me, I'm not good in physics.
You press your physics textbook flat against a vertical wall with your hand. What is the direction of the friction force exerted by the wall on the book? (a) downward (b) upward (c) out from the wall (d) into the wall. (Serway and Jewett, 2009) What type of friction is present?
Answer:
Upward direction.
The friction is kinetic friction
An object has a mass of 3 kg and an acceleration 7 m/s2to the left. What is the force?
Answer:
your answer is 21 n
Explanation:
On which factor does the inertia of a body depend?
Answer:
The moment of inertia depends on the following factors, The density of the material. Shape and size of the body. Axis of rotation (distribution of mass relative to the axis)