Answer:
B.) -9
Step-by-step explanation:
The value of b if 3/2 is the axis of symmetry for the graph of the function f(x)=3x2+bx+4 is -9
How to calculate the axis of symmetry of a function?The standard equation of a function in vertex form is given as:
f(x) = (a + x)^2 + h
Given the function f(x)=3x^2+bx+4 with an axis of symmetry of 3/2, the vertex is expressed as:
3/2= -b/2a
-b/2(3)=3/2
-b/6=3/2
Cross multiply
-2b = 18
-b=9
Hence the value of b if 3/2 is the axis of symmetry for the graph of the function f(x)=3x2+bx+4 is -9
Learn more on axis of symmetry here: https://brainly.com/question/21191648
Can somebody help me with writing a real-life problem on this subject Finding angle measures of a right or isosceles triangle given angles with variables thank you?
Answer:
See Explanation
Step-by-step explanation:
See attachment for illustration
(a) Right triangle
The sum of [tex]angles[/tex] in a [tex]right[/tex] [tex]triangle[/tex]is:
[tex]x + y + 90 = 180[/tex]
Subtract 90 from bot sides
[tex]x + y = 90[/tex]
Make x the subject
[tex]x = 90 - y[/tex]
Make y the subject
[tex]y = 90 - x[/tex]
This implies that, subtract the known angle from 90 to get the unknown angle.
Assume [tex]x = 40[/tex]
We make use of: [tex]y = 90 - x[/tex]
[tex]y = 90 - 40 = 50[/tex]
(b) Isosceles triangle
The sum of angles in an isosceles triangle is:
[tex]x + y + y = 180[/tex] ---- y appear twice because the base angles are equal
[tex]x + 2y = 180[/tex]
Make x the subject
[tex]x = 180 - 2y[/tex]
Make y the subject
[tex]y = \frac{180 - x}{2}[/tex]
Assume [tex]x = 40[/tex], we make use of:
[tex]y = \frac{180 - x}{2}[/tex]
[tex]y = \frac{180 - 40}{2}[/tex]
[tex]y = \frac{140}{2}[/tex]
[tex]y = 70[/tex]
Assume [tex]y = 70[/tex], we make use of:
[tex]x = 180 - 2y[/tex]
[tex]x = 180 - 2 * 70[/tex]
[tex]x = 180 - 140[/tex]
[tex]x = 40[/tex]