The average cost per month of a 2-bedroom apartment in Grayson was $625 last year. This year, the average cost is $650. What is the percent increase from last year to this year? *

4%
25%
14%
3.8%

Answer:

3/2

Step-by-step explanation:

9514 1404 393

Answer:

  36

Step-by-step explanation:

"Varies directly" means the relationship is proportional:

  y/9 = 16/4

  y = 9·16/4 = 36

The value of y is 36 when x = 9.

Answer:

[tex]\displaystyle \int {\frac{1}{\sqrt{x} \sqrt{1-x} } } \, dx = 2arcsin(\sqrt{x}) + C[/tex]

General Formulas and Concepts:

Calculus

Step-by-step explanation:

Step 1: Define

[tex]\displaystyle \int\limits {\frac{1}{\sqrt{x} \sqrt{1-x} } } \, dx[/tex]

Step 2: Identify

Set up variables for u-substitution and integral trig.

[tex]\displaystyleu = \sqrt{x}\\a = 1\\du = \frac{1}{2\sqrt{x}}dx[/tex]

Step 3: integrate

We are given the expression:                                                                              

[tex]\int\limits {\frac{1}{\sqrt[]{x} }*\frac{1}{\sqrt[]{ 1-x^{2}}} } \, dx[/tex]

U-substitution:                                                                                                      

let u = [tex]x^{1/2}[/tex]             [So, x = u²]

[tex]\frac{du}{dx} = \frac{1}{2\sqrt[]{x}}[/tex]                 [differentiating both sides wrt x]

dx = du*2√(x)

dx = 2u(du)            [Since u = √x]

Finding the Integral:                                                                                              

Plugging these values in the given expression:

[tex]\int\limits {u^{-1}*(1-u^{2})^{-1/2} } \, 2\sqrt[]{x}*du[/tex]

[tex]\int\limits {\frac{1}{u}*\frac{1}{\sqrt[]{ 1-u^{2}}}*2u } \, du[/tex]

The 'u' in the numerator and denominator will cancel out

[tex]\int\limits {\frac{1}{\sqrt[]{ 1-u^{2}}}*2 } \, du[/tex]

Since 2 is a constant

[tex]2\int\limits {\frac{1}{\sqrt[]{ 1-u^{2}}} } \, du[/tex]

Using the property: [tex]\int\limits {\frac{1}{\sqrt[]{1-x^{2}} }} \, dx[/tex] = ArcSin(x) + C

2*ArcSin(u) + C

Since u = √x :

2*ArcSin(√x) + C

Answer:

The two points are (0,1) and (0.75, 0)

Step-by-step explanation:

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

Answer:

P(white ball)=0.29

Step-by-step explanation:

12 yellow balls

5 red balls

7 white balls

12+5+7=24

so 24 balls in the bag

[tex]\frac{7}{24}[/tex]=0.2916

rounded to the nearest is 0.29

Answer:

3x

7-k

m/4

(5x)+12

Step-by-step explanation:

most of the words like and are just fillers. and basically means together in this instance

Step-by-step explanation:

AB = 72 so, then FB would be half of that

so 72 divided by 2 would be 36

5x+1=36 then do substitution

-1 from both sides (from +1 you gotta do the inverse)

5x = 35

divide 5 from both sides because in between 5 and x is a times so the inverse of that is divide

x = 7

Answer:

2.5

Step-by-step explanation:

The slope of the line is; [tex]\frac{rise}{run}[/tex] and can be found using the formula;

[tex]\frac{y_{2} - y_{1}}{x_{2}-x_{1}}[/tex]

Given the points;

( 6, 3 ) and ( 4, -2)

Substitute the points in and solve;

[tex]\frac{(-2) - (3)}{(4) - (6)}[/tex]

[tex]\frac{-5}{-2}\\\\\frac{5}{2}\\\\= 2.5[/tex]

Answer:

$115.2

Step-by-step explanation:

Step one:

Given data

A store used to sell an MP3 for $72 and we are told that this 50% of the wholesale price.

Therefore the wholesale price is

72*2= $144

Required:

The special sales cost at 20% discount

Step two:

We are told that the special sale is at a 20% discount on the wholesale

= 20/100*144

=0.2*144

=$28.8

Therefore the special sales price is

= 144-28.8

=$115.2

Answer:

Intersection

Step-by-step explanation:

The intersection of two set A and B is defined as the elements which can be found in both set A and set B.

For instance :

A = {1, 3, 5, 7, 9, 11}

B = {2, 4, 6, 7, 8, 9, 10}

The intersection of the two sets A and B denoted as ;

AnB = {7, 9}

Answer:

24

Step-by-step explanation:

x = 8, y = 3, z = 2

(1/4) x {8[2(3)+3(2)]}

(1/4) x {8(6 + 6)}

(1/4) x {48 + 48} (by distributing)

1/4 x 96

= 24

Answer:

Grace's brother has $47.

Answer: "reduced by a factor of One-third."

Step-by-step explanation:

Suppose that the original magazine has a length L and a width W.

If it is photocopied using a scale factor of K, then the measures of the photocopy will be:

length = K*L

Width = K*W

In this case, the scale factor is K = 1/3, then the measures of the photocopy will be:

length = (1/3)*L = L/3

Width = (1/3)*W = W/3

For usual notation:

When k > 1, we have an enlargement by a factor k

when 0 < k < 1, we have a reduction by a factor k

in this case, k = 1/3, then:

We have a reduction by a factor of 1/3

The correct option is:

"reduced by a factor of One-third."

Answer: D-reduced by a factor 1/3

Step-by-step explanation:

got it correct on edge 2021

Step-by-step explanation:

[tex] \underline{ \underline{ \text{Given}}}[/tex] :

[tex] \underline{ \underline{ \text{To \: prove}}} : [/tex]

[tex] \tt{ \sqrt{ab} - \sqrt{bc} - \sqrt{cd} = \sqrt{(a - b - c)(b - c - d)} } [/tex]

[tex] \underline{ \underline{ \text{Solution}}} : [/tex]

Left hand side ( L.H.S ) :

[tex] \tt{ \sqrt{ab} - \sqrt{bc} - \sqrt{cd}} [/tex]

⟶ [tex] \tt{ \sqrt{d {k}^{3} \cdot \: d {k}^{2} } - \sqrt{d {k}^{2} \cdot \: dk } - \sqrt{dk \cdot \: d} }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2} {k}^{5} } - \sqrt{ {d}^{2} {k}^{3} } - \sqrt{ {d}^{2}k } }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2} \cdot \: {k}^{2} \cdot \: {k}^{2} \cdot \: k } - \sqrt{ {d}^{2} \cdot \: {k}^{2} \cdot \: k \: } - \sqrt{ {d}^{2}k } }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2} } \cdot \sqrt{ {k}^{2} } \cdot \: \sqrt{ {k}^{2} } \cdot \: \sqrt{k} } - \sqrt{ {d}^{2} }\cdot \: \sqrt{ {k}^{2}} \cdot \: \sqrt{k} \: - \sqrt{ {d}^{2} } \cdot \: \sqrt{k} [/tex]

⟶ [tex] \tt{d {k}^{2} \sqrt{k} - dk \sqrt{k} - d \sqrt{k} }[/tex]

⟶ [tex] \tt{ d\sqrt{k} \: ( {k}^{2} - k - 1) } [/tex]

Right Hand Side ( R.H.S) :

[tex] \tt{ \sqrt{(a - b - c)(b - c - d)}} [/tex]

⟶ [tex] \tt{ \sqrt{(d {k}^{3} - d {k}^{2} - dk)( d{k}^{2} - dk - d)} }[/tex]

⟶ [tex] \tt{ \sqrt{ \{dk( {k}^{2} - k - 1) \} \: \{d( {k}^{2} - k - 1) \}} }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2}k( {k}^{2} - k - 1) ^{2} } } [/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2}k } \cdot \: \sqrt{ {( {k}^{2} - k - 1)}^{2} } } [/tex]

⟶[tex] \tt{ \sqrt{ {d}^{2} } \cdot \: \sqrt{k} \cdot \: \sqrt{( {k}^{2} - k - 1) ^{2} } }[/tex]

⟶ [tex] \tt{d \sqrt{k} \: ( {k}^{2} - k - 1) } [/tex]

L.H.S = R.H.S

Hence , Proved !

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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Answer:

8(x-y);use x=5,and y=2

8(5 - 2) = 8(3) = 24

answer

24

Step-by-step explanation:

good? Brainliest?

Step-by-step explanation:

-70x^4 + 30x

= 10x(-7x^3 + 3)

ANSWER: 10x(-7x^3 + 3)

Answer:

L = (-1.5, 2) U = (1.5, 2.5) V = (1, -0.5)

Step-by-step explanation:

Just divided everything by two.

Answer:

s

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given costs:

Sum of the costs:

Average cost is sum divided by number:

Answer:

14 × (19 + 6)

hope it helps

The expression represents the total number of cans of beans Mr. Jenkins is, (19+6)×14, So Option B is correct.

An expression is a sentence with at least two numbers or variables having mathematical operation. Math operations can be addition, subtraction, multiplication, division.

For example, 2x+3

Given that,

Mr. Jenkins has 19 cases of beans

He also has 6 cases of beans in the stock room

There are 14 cans of beans in each case

Expression for total number of beans = ?

Total number of beans  = Total number of cases ×beans in each case

Total number of beans = (beans in grocery store+beans in stock room)×14

Total number of beans = (19 +6) × 14

Hence, the expression is  (19 +6) × 14

To know more about Expressions check:

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Answer:

B - The values of both x and y will be real numbers greater than or equal to 0.

The answer choice that best describes the values of x and y is B - The values of both x and y will be real numbers greater than or equal to 0.

Given that peaches are being sold for $2 per lb.

If we define x as the number of pounds that you buy, and y as the cost of these peaches, we can write the function:

y = $2*x

Therefore, the best description of the values of x and y is found in option B. The value of x can be any real number greater than or equal to 0, but the value of y must be an integer greater than or equal to 0.

Read more about equations here:

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Answer:

wht

!?

............

..............

..

.

We know these triangles are congruent with the missing side, N would be equal to 15.

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

We know these triangles are congruent.

To find the missing side, N

ΔABC ≅ΔQRS

AC/QS = BC/RS

2/5 = 6/n

n = 6 x 5/2

n = 30/2

n = 15

Thus, the value of N is 15.

Learn more about triangles;

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Answer:

the anwser is 242

Step-by-step explanation:

I dont see a q anywhere but you would sub p and 9 and do the equation so times 10 and 9 and then distribute 22 or in your calculator jus enter 22(90-79) and you would get 242

Answer:

The answer is 1

Step-by-step explanation:

Answer:

  [tex]\sqrt{\frac{2x^{5} }{18} }[/tex]   = [tex]\frac{\sqrt{x^{5} } }{3}[/tex]

Step-by-step explanation:

Given expression

            [tex]\sqrt{\frac{2x^{5} }{18} }[/tex]

we know that the algebra formula

[tex]\sqrt{\frac{a}{b} } = \frac{\sqrt{a} }{\sqrt{b} }[/tex]

[tex]\sqrt{\frac{2x^{5} }{18} } = \frac{\sqrt{2} \sqrt{x^{5} } }{\sqrt{18} } = \frac{\sqrt{2} \sqrt{x^{5} } }{\sqrt{9} \sqrt{2} }[/tex]

          = [tex]\frac{\sqrt{x^{5} } }{3}[/tex]

Answer:

27.95 and 34.05 are compatible because when you add up the decimals, the equal 0, which makes it easier to add. 27. 95 + 34.05 = 61.00.

Same with 19.37 and 21.63, it adds up to 40.00

The answer to all of this would be 101.00

Answer: X = 1

Y= 5

Step-by-step explanation:

Plug in y = 3x + 2 in the Y coordinate to find X

-4x + 4(3x + 2) = 16

Now you can solve for X

X = 1

Then plug in 1 in the X coordinate to find Y

-4(1)+ 4y= 16

Now you can solve for Y

Y= 5

YOUR WELCOME

Answer:

k = i√ 5 , -i√ 5

Step-by-step explanation:

3 + kx^2 + 2 = ?

3 + k(1)^2 + 2 = ?

5 + k(1)^2 = ?

5 + k^2 = ?

k^2 = -5

k = i√ 5 , -i√ 5