The average cholesterol content of a certain brand of eggs is 215 milligrams, and the standard deviation is 15 milligrams. Assume the variable is normally distributed. If a single egg is randomly selected, what is the probability that the egg will be with cholesterol content greater than 220 milligrams
Answers
Answer:
"The probability that the egg will be with cholesterol content greater than 220 milligrams" is 0.37070 (37.070% or simply 37%)
Step-by-step explanation:
We have here a normally distributed random variable. The parameters that characterize this distribution is the mean, [tex] \\ \mu[/tex], and the standard deviation, [tex] \\ \sigma[/tex].
In this question, we have that:
[tex] \\ \mu = 215[/tex] milligrams.[tex] \\ \sigma = 15[/tex] milligrams.And we want to know the probability that a randomly selected single egg "will be with cholesterol content greater than 220 milligrams."
To answer the latter, we need to use the following key concepts:
Z-scores.The cumulative standard normal distribution, andThe [cumulative] standard normal table.The z-scores are standardized values and represent the distance (for the raw score) from the mean in standard deviations units. A positive z-score indicates that it is above [tex] \\ \mu[/tex] and, conversely, a negative result that the value is below it.
The cumulative distribution function generates the values for the cumulative standard normal distribution displayed in the standard normal table.
The standard normal distribution is employed to find probabilities for any normally distributed data and we only need to calculate the corresponding z-score (or standardized value). This distribution has a [tex] \\ \mu = 0[/tex] and [tex] \\ \sigma = 1[/tex].
As we can see, all of these concepts are intertwined, and each of them is important because:
To find the corresponding probability, we first need to obtain the z-score.After this, we can consult the standard normal table, whose values are tabulated from the cumulative standard normal distribution, to find the requested probability.Finding the probability
We can get the z-score using the formula:
[tex] \\ z = \frac{x - \mu}{\sigma}[/tex] [1]
Where x is the raw value we want to standardize using the previous formula, and, in this case is 220 milligrams, [tex] \\ x = 220[/tex] milligrams.
Thus (without using units):
[tex] \\ z = \frac{x - \mu}{\sigma}[/tex]
[tex] \\ z = \frac{220 - 215}{15}[/tex]
[tex] \\ z = \frac{5}{15}[/tex]
[tex] \\ z = \frac{5}{5} * \frac{1}{3}[/tex]
[tex] \\ z = 1 * \frac{1}{3}[/tex]
[tex] \\ z = 0.3333333...[/tex]
To consult the standard normal table, we only need [tex] \\ z = 0.33[/tex], because it only has values for two decimal digits. As a result, the value will be a little inexact (but near to the true value) compared to that obtained using statistical software (or maybe a more precise table).
With this value (which is positive and, therefore, above the mean), we need to carefully see the first column of the mentioned table to find z = 0.3. Then, in the first row, we only need to select that column for which we can add the next digit, in this case, 3 (it appears as +0.03). That is, we are finding the probability for [tex] \\ z = 0.33[/tex].
Then, the cumulative probability for [tex] \\ z = 0.33[/tex] is:
[tex] \\ P(x<220) = P(z<0.33) = 0.62930[/tex]
However, the question is asking for "cholesterol content greater than 220 milligrams" or
[tex] \\ P(x>220) = P(z>0.33)[/tex]
Since
[tex] \\ P(x<220) + P(x>220) = 1[/tex]
Which is the same for a standardized value:
[tex] \\ P(z<0.33) + P(z>0.33) = 1[/tex]
Then
[tex] \\ P(z>0.33) = 1 - P(z<0.33)[/tex]
Therefore
[tex] \\ P(x>220) = P(z>0.33) = 1 - P(z<0.33)[/tex]
[tex] \\ P(x>220) = 1 - P(z<0.33)[/tex]
[tex] \\ P(x>220) = 1 - 0.62930[/tex]
[tex] \\ P(x>220) = 0.37070[/tex]
Thus, "the probability that the egg will be with cholesterol content greater than 220 milligrams" is 0.37070 (37.070% or simply 37%).
The graph below shows a shaded area that corresponds to the found probability.
Related Questions
People were surveyed worldwide, being asked the question "How important is acquiring wealth to you?" of 1500 respondents in country A, 1185 said that it was of more than average importance. In country B, of 1302 respondents, 613 said it was of more than average importance.
1) (Round to three decimal places as needed):
a. The sample proportions for country A are: ___
b. The sample proportions for country B are: ___
2) What is the confidence interval for country A? Select the correct choice below and, if necessary, fill in the answer boxes within your choice.
a. The 90% confidence interval for country A is (__%, ___%) [Round to one decimal place as needed.]
b. The conditions for constructing a confidence interval are not satisfied.
3) Compare to the confidence interval for country B. Choose the correct answer below.
a. It is not possible to make a comparaison because the conditions for creating a confidence interval are not satisfied.
b. It appears that the proportion of adults who feel this way in country A is more than those in country B.
c. It appears that the proportion of adults who feel this way in country A is about the same as those in country B.
d. it appears that the proportion of adults who feel this way in country B is more than those in country A.
Answers
Answer:
1) A = 0.79
B = 0.4708
2) CI = (0.7728, 0.8072)
3) CI = (0.4481, 0.4935)
b. It appears that the proportion of adults who feel this way in country A is more than those in country B.
Step-by-step explanation:
1) Sample proportions for both Population A and B
For country A:
Sample size,n = 1500
Sample proportion = [tex] \frac{1185}{1500} = 0.79 [/tex]
For Country B:
Sample size,n = 1302
Sample proportion = [tex] \frac{613}{1302} = 0.4708 [/tex]
2) Confidence interval for country A:
Given:
Mean,x = 1185
Sample size = 1500
Sample proportion, p = 0.79
q = 1 - 0.79 = 0.21
Using z table,
90% confidence interval, [tex] Z _\alpha /2 = 1.64 [/tex]
Confidence interval, CI:
[tex] \frac{p +/- Z_\alpha_/2}{\sqrt{(p * q)/n}} [/tex]
[tex] = \frac{0.79 - 1.64}{\sqrt{(0.79 * 0.21)/1500}}, \frac{0.79 + 1.64}{\sqrt{(0.79 * 0.21)/1500}} [/tex]
[tex] CI = (0.7728, 0.8072) [/tex]
3) Confidence interval for country A:
Given:
Mean,x = 613
Sample size = 1302
Sample proportion, p = 0.4708
q = 1 - 0.4708 = 0.5292
Using z table,
90% confidence interval, [tex] Z _\alpha /2 = 1.64 [/tex]
Confidence interval, CI:
[tex] \frac{p +/- Z_\alpha_/2}{\sqrt{(p * q)/n}} [/tex]
[tex] = \frac{0.4708 - 1.64}{\sqrt{(0.4708 * 0.5292)/1302}}, \frac{0.4708 + 1.64}{\sqrt{(0.4708 * 0.5295)/1302}} [/tex]
[tex] CI = (0.4481, 0.4935) [/tex]
From both confidence interval, we could see that that the proportion of adults who feel this way in country A is more than those in country B.
Option B is correct.
Let x1 = 12, y1 = 15, and y2 = 3. Let y vary inversely with x. Find x2.
Answers
Answer:
x2 = 60
Step-by-step explanation:
If the variables x and y are inversely proportional, the product x * y is a constant.
So using x1 and y1 we can find the value of this constant:
[tex]x1 * y1 = k[/tex]
[tex]12 * 15 = k[/tex]
[tex]k = 180[/tex]
Now, we can use the same constant to find x2:
[tex]x2 * y2 = k[/tex]
[tex]x2 * 3 = 180[/tex]
[tex]x2 = 180 / 3 = 60[/tex]
So the value of x2 is 60.
A study conducted at a certain college shows that "53%" of the school's graduates find a job in their chosen field within a year after graduation. Find the probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating. 0.989 0.978 0.927 0.167 0.530
Answers
Answer:
0.989
Step-by-step explanation:
For each graduate, there are only two possible outcomes. Either they find a job in their chosen field within a year after graduation, or they do not. The probability of a graduate finding a job is independent of other graduates. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
A study conducted at a certain college shows that "53%" of the school's graduates find a job in their chosen field within a year after graduation.
This means that [tex]p = 0.53[/tex]
6 randomly selected graduates
This means that [tex]n = 6[/tex]
Probability that at least one finds a job in his or her chosen field within a year of graduating:
Either none find a job, or at least one does. The sum of the probabilities of these outcomes is 1. So
[tex]P(X = 0) + P(X \geq 1) = 1[/tex]
We want [tex]P(X \geq 1)[/tex]
So
[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{6,0}.(0.53)^{0}.(0.47)^{6} = 0.011[/tex]
So
[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.011 = 0.989[/tex]
A door delivery florist wishes to estimate the proportion of people in his city that will purchase his flowers. Suppose the true proportion is 0.070.07. If 492492 are sampled, what is the probability that the sample proportion will differ from the population proportion by greater than 0.030.03?
Answers
Answer:
The probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.009.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
[tex]\mu_{\hat p}=p[/tex]
The standard deviation of this sampling distribution of sample proportion is:
[tex]\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}[/tex]
As the sample size is large, i.e. n = 492 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by the normal distribution.
The mean and standard deviation of the sampling distribution of sample proportion are:
[tex]\mu_{\hat p}=p=0.07\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.07(1-0.07)}{492}}=0.012[/tex]
Compute the probability that the sample proportion will differ from the population proportion by greater than 0.03 as follows:
[tex]P(|\hat p-p|>0.03)=P(|\frac{\hat p-p}{\sigma_{\hat p}}|>\frac{0.03}{0.012})[/tex]
[tex]=P(|Z|>2.61)\\\\=1-P(|Z|\leq 2.61)\\\\=1-P(-2.61\leq Z\leq 2.61)\\\\=1-[P(Z\leq 2.61)-P(Z\leq -2.61)]\\\\=1-0.9955+0.0045\\\\=0.0090[/tex]
Thus, the probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.009.
Please answer this correctly
Answers
Answer:
1/2
Step-by-step explanation:
There is a 50/50 chance for the coin to land either heads or tails. Convert that to probability and it is 1/2.
The only time a coin would not be 50/50 chance is if the coin is weighted.
Answer:
1/2 is probability
becoz one side is head or one is tail
2x^2+8x = x^2-16
Solve for x
Answers
Answer:
x=-4
Step-by-step explanation:
[tex]2x^2+8x=x^2-16[/tex]
Move everything to one side:
[tex]x^2+8x+16=0[/tex]
Factor:
[tex](x+4)^2=0[/tex]
By the zero product rule, x=-4. Hope this helps!
Answer:
x=-4
Step-by-step explanation:
Move everything to one side and combine like-terms
x²+8x+16
Factor
(x+4)²
x=-4
hey guys please help
Answers
Answer:
[tex]7.98 \:m[/tex]
Step-by-step explanation:
Area of a triangle is base times height divided by 2.
[tex]A= \frac{bh}{2}[/tex]
[tex]69.6= \frac{b \times 17.45}{2}[/tex]
[tex]69.6 \times 2= b \times 17.45[/tex]
[tex]139.2=b \times 17.45[/tex]
[tex]\frac{17.45b}{17.45}=\frac{139.2}{17.45}[/tex]
[tex]b=\frac{2784}{349}[/tex]
[tex]b=7.97707[/tex]
The appropriate unit is meters.
Answer:
7.98 m
Step-by-step explanation:
Can someone plz help me solved this problem I need help plz help me! Will mark you as brainiest!
Answers
Answer: a) base = 1 ft b) height = 4 ft
Step-by-step explanation:
Set this up as a right triangle where base = x, height = 2x + 2, and hypotenuse (length of the ladder) = 13
Use Pythagorean Theorem to create a quadratic equation, factor, then apply the Zero Product Property to solve for x.
(x)² + (2x + 2)² = 13²
x² + 4x² + 8x + 4 = 169
5x² + 8x - 165 = 0
(5x + 13) (x - 1) = 0
x = -13/5 x = 1
We know that distance cannot be negative so disregard x = -13/5.
The only valid answer is x = 1
base = x --> x = 1
height = 2x + 2 --> 2(1) + 2 = 4
A triangular window has an area of 594 square meters. The base is 54 meters. What is the height?
Answers
Answer:
22 m
Step-by-step explanation:
Use the formula for the area of a triangle. Fill in the known values and solve for the unknown.
A = (1/2)bh
594 m^2 = (1/2)(54 m)h
h = (594 m^2)/(27 m) = 22 m
The height of the window is 22 meters.
if cos theta < 0 and cot theta > 0, then the terminal point determined by theta is in:
A. Quadrant 1
B. Quadrant 3
C. Quadrant 4
D. Quadrant 2
please help me !
Answers
Answer:
If cosine theta < 0 and cotangent theta > 0, then the terminal point determined by theta is in: quadrant 3.
Step-by-step explanation:
hope this helps you :) my answer is the Step-by-step explanation: and the answer :)
Considering the signals of the sine and the cosine of the trigonometric function, it is found that it's quadrant is given by:
B. Quadrant 3
What are the signals of the sine and the cosine in each quadrant?Q1: cos > 0, sin > 0.Q2: cos < 0, sin > 0.Q3: cos < 0, sin <0.Q4: cos > 0, sin < 0.In this problem, we have that the cosine is negative, and the cotangent is positive. Cotangent is cosine divided by sine, hence if it is positive, both cosine and sine have the same signal, since cos < 0, sine is negative, they are in third quadrant and option B is correct.
More can be learned about the quadrants of trigonometric functions at https://brainly.com/question/24551149
#SPJ2
plz help me divide and simplify
Answers
Answer:
Step-by-step explanation:
Which of the following is a polynomial with roots: − square root of 3 , square root of 3, and −2? (6 points) Question 7 options: 1) x3 − 2x2 − 3x + 6 2) x3 − 3x2 − 5x + 15 3) x3 + 2x2 − 3x − 6 4) x3 + 3x2 − 5x − 15
Answers
Answer:
The polynomial is [tex]x^{3} - 1.46x^{2} - 3.93x + 6[/tex]
Step-by-step explanation:
A nth order polynomial f(x) has roots [tex]x_{1}, x_{2}, ..., x_{n}[/tex] such that [tex]f(x) = (x - x_{1})*(x - x_{2})*...*(x - x_{n}}[/tex],
Which of the following is a polynomial with roots: − square root of 3 , square root of 3, and −2?
So
[tex]x_{1} = x_{2} = \sqrt{3}[/tex]
[tex]x_{3} = -2[/tex]
Then
[tex](x - \sqrt{3})^{2}*(x - (-2)) = (x - \sqrt{3})^{2}*(x + 2) = (x^{2} -2x\sqrt{3} + 3)*(x + 2) = x^{3} + 2x^{2} - 2x^{2}\sqrt{3} - 4x\sqrt{3} + 3x + 6[/tex]
Since [tex]\sqrt{3} = 1.73[/tex]
[tex]x^{3} + 2x^{2} - 3.46x^{2} - 6.93x + 3x + 6 = x^{3} - 1.46x^{2} - 3.93x + 6[/tex]
The polynomial is [tex]x^{3} - 1.46x^{2} - 3.93x + 6[/tex]
Write the Algebraic expression for each of the following.
1. Sum of 35 and 65
2. Take away 14 from y
3. Subtract 3 from the product of 6 and s
4. 10 times the sum of x and 8 5. Take away p from 6
Answers
Step-by-step explanation:
1. 35 + 65
2. y - 14
3. (6 x s) - 3
4. 10(x+8.5).. 6-p
An insurance company examines its pool of auto insurance customers and gathers the following information: (i) All customers insure at least one car. (ii) 70% of the customers insure more than one car. (iii) 20% of the customers insure a sports car. (iv) Of those customers who insure more than one car, 15% insure a sports car. Calculate the probability that a randomly se
Answers
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
An insurance company examines its pool of auto insurance customers and gathers the following information: (i) All customers insure at least one car. (ii) 70% of the customers insure more than one car. (iii) 20% of the customers insure a sports car. (iv) Of those customers who insure more than one car, 15% insure a sports car. Calculate the probability that a randomly selected customer insures exactly one car, and that car is not a sports car?
Answer:
P( X' ∩ Y' ) = 0.205
Step-by-step explanation:
Let X is the event that the customer insures more than one car.
Let X' is the event that the customer insures exactly one car.
Let Y is the event that customer insures a sport car.
Let Y' is the event that customer insures not a sport car.
From the given information we have
70% of customers insure more than one car.
P(X) = 0.70
20% of customers insure a sports car.
P(Y) = 0.20
Of those customers who insure more than one car, 15% insure a sports car.
P(Y | X) = 0.15
We want to find out the probability that a randomly selected customer insures exactly one car, and that car is not a sports car.
P( X' ∩ Y' ) = ?
Which can be found by
P( X' ∩ Y' ) = 1 - P( X ∪ Y )
From the rules of probability we know that,
P( X ∪ Y ) = P(X) + P(Y) - P( X ∩ Y ) (Additive Law)
First, we have to find out P( X ∩ Y )
From the rules of probability we know that,
P( X ∩ Y ) = P(Y | X) × P(X) (Multiplicative law)
P( X ∩ Y ) = 0.15 × 0.70
P( X ∩ Y ) = 0.105
So,
P( X ∪ Y ) = P(X) + P(Y) - P( X ∩ Y )
P( X ∪ Y ) = 0.70 + 0.20 - 0.105
P( X ∪ Y ) = 0.795
Finally,
P( X' ∩ Y' ) = 1 - P( X ∪ Y )
P( X' ∩ Y' ) = 1 - 0.795
P( X' ∩ Y' ) = 0.205
Therefore, there is 0.205 probability that a randomly selected customer insures exactly one car, and that car is not a sports car.
f(x)
9 - 4x
8x - 1
INVERSE??
Answers
Answer:
(x+9)/(8x+4)
Step-by-step explanation:
Please answer this correctly
Answers
Answer:
13 students
Step-by-step explanation:
At least 30 and fewer than 67 makes it 30-66
So,
30-66 => 13 students
Answer:
16
Step-by-step explanation:
There are two columns in the diagram.
The column headed stem represents tens while the column headed leaf represents units. e.g. 2 3 = 23
So we just have to count how many of the numbers are less than 8 in the 6th Stem column and all the numbers below it, which are:
20, 23, 28, 31, 31, 34, 38, 40, 44, 50, 51, 53, 54, 65, 65, 66
What is the total surface area of the square pyramid 8in 5in
Answers
Answer:
A≈166.45 in^2
Step-by-step explanation:
A=a^2+2a√(a2/4+h^2)
a = base = 8 in
h = height = 5 in
A = 8^2+16√(8^2/4+5^2) = 166.449... in^2
224
Step-by-step explanation:
because my teacher said it was right
An economist at Vanderbilt University devised a study to compare different types of online auctions. In one experiment he compared a Dutch auction to a first-place sealed bid auction. In the Dutch auction the item for sale starts at a very high price and is lowered gradually until someone finds the price low enough to buy. In the first-price sealed bid auction each bidder submits a single sealed bid before a particular deadline. After the deadline, the person with the highest bid wins. The researcher auctioned off collectible trading cards from the game Magic: The Gathering. He placed pairs of identical cards up for auction; one would go into Dutch auction and the other to the first-price sealed bid auction. He then looked at the difference in the prices he received on the pair. He repeated this for a total of 88 pairs.
[a] Explained why the data should be analyzed using paired samples as opposed to two independent samples.
[b] What makes a pair?
[c] What is the explanatory variable? Is it categorical or quantitative?
[d] What is the response variable? Is it categorical or quantitative?
[e] State the relevant hypotheses in words:
Null hypothesis:
Alternative hypothesis:
[f] Define the parameter of interest and give the symbol that should be assigned to it.
[g] State the relevant hypotheses in symbols (using a parameter):
Null hypothesis:
Alternative hypothesis:
[h] Assume the p-value is 0.17 (write a conclusion).
Answers
Answer:
Step-by-step explanation:
a. The data should be analyzed using paired samples because the economist made two measurements (samples) drawn from the same pair of identical cards. Each data point in one sample is uniquely paired to a data point in the second sample.
b. A pair is made up of two identical cards where one would go into Dutch auction and the other to the first-price sealed bid auction.
c. The explanatory variables are the types of online auction which are the Dutch auction and the first price sealed bid auction. The explanation variable here is categorical: the Dutch auction and the first price sealed bid auction.
d. The response variable which is also known as the outcome variable is prices for the 2 different auction for each pair of identical cards. This variable is quantitative.
e. Null Hypothesis in words: There is no difference in the prices obtained in the two different online auction.
Alternative hypothesis: There is a difference in the prices obtained in the two different online auction.
f. The parameter of interest in this case is the mean prices of pairs of identical cards for both auction and is assigned p.
g. Null hypothesis: p(dutch) = p(first-price sealed auction)
Alternative hypothesis: p(dutch) =/ p(first-price sealed auction)
h. Assuming the p-value is 0.17 at an assed standard 0.05 significance level, our conclusion would be to fail to reject the null hypothesis as 0.17 is greater than 0.05 or even 0.01 and we can conclude that, there is no statistically significant evidence to prove that there is a difference in the prices obtained in the two different online auction.
combine like terms to create an equivalent expression -1/2(-3y+10)
Answers
Answer:
3/2y - 5
Step-by-step explanation:
-1/2(-3y+10)
Expand the brackets.
-1/2(-3y) -1/2(10)
Multiply.
3/2y - 5
Answer:
[tex]= \frac{ 3y}{2} - 5 \\ [/tex]
Step-by-step explanation:
we know that,
[tex]( - ) \times ( - ) = ( + ) \\ ( - ) \times ( + ) = ( - )[/tex]
Let's solve now,
[tex] - \frac{1}{2} ( - 3y + 10) \\ \frac{3y}{2} - \frac{10}{2} \\ = \frac{ 3y}{2} - 5[/tex]
Marty’s parents paid $1,800 in electric bills last year. What was their average electric rate per month?
Answers
Answer: 150
Step-by-step explanation:
How many months are in a year? 12.
The average rate per month is therefore 1800/12 = 150.
Hope that helped,
-sirswagger21
Given z = 4x – 6y, solve for y.
Answers
Answer:
Step-by-step explanation:
-6y+4x=z
-6y=z-4x
y=(z-4x)/-6
Answer:
[tex]y=\frac{z-4x}{-6}[/tex]
Step-by-step explanation:
The pie chart to the right shows how adults rate their financial shape. Suppose 4 people are chosen at random from a group of 1400. What is the probability that all four would rate their financial shape as excellent? (Make the assumption that the 1400 people are represented by the pie chart.)
Answers
Question Completion
PIE CHART NUMBERS:
Excellent 9% Good 41% Fair 36% Poor 13% Other 1%Answer:
0.000063
Step-by-step explanation:
Number of Respondents, n=1400
Probability that they would rate their financial shape as excellent = 0.09
Number of Those who would rate their financial shape as excellent
=0.09 X 1400
=126
Therefore:
The probability that 4 people chosen at random would rate their financial shape as excellent
[tex]=\dfrac{^{126}C_4 \times ^{1400-126}C_0}{^{1400}C_4} \\=\dfrac{^{126}C_4 \times ^{1274}C_0}{^{1400}C_4}\\=0.000063 $(correct to 6 decimal places)[/tex]
Determine if the expressions are equivalent.
when w = 11:
2w + 3 + 4 4 + 2w + 3
2(11) + 3 + 4 4 + 2(11) + 3
22 + 3 + 4 4 + 22 + 3
25 + 4 26 + 3
29 29
Complete the statements.
Answers
Answer:
Determine if the expressions are equivalent.
when w = 11:
2w + 3 + 4 4 + 2w + 3
2(11) + 3 + 4 4 + 2(11) + 3
22 + 3 + 4 4 + 22 + 3
25 + 4 26 + 3
29 29
Complete the statements.
Now, check another value for the variable.
When w = 2, the first expression is
11
.
When w = 2, the second expression is
11
.
Therefore, the expressions are
equivalent
.
Step-by-step explanation:
i did the math hope this helps
Answer:
Hii its Nat here to help! :)
Step-by-step explanation: A is 11 and b is 11.
C is Equal
Screenshot included.
Find the scale ratio for the map described below. 1 mm(map) equals 500 m (actual) The scale ratio is 1 to ? .
Answers
Answer:
1 : 500,000
Step-by-step explanation:
The scale of a map scale refers to the relationship (or ratio) between the distance on a map and the corresponding distance on the ground.
In the given map:
1 mm(map) = 500 m (actual)
1 meter = 1000 millimeter
Therefore:
500 meters = 1000 X 500 =500,000 millimeter
Therefore, the scale ratio of the map is:
1:500,000
The sum of a number and its reciprocal is 41/20. Find the numbers. smaller value larger value
Answers
Answer:
The numbers are 5/4 and 4/5The smaller value is 4/5The larger value is 5/4Step-by-step explanation:
Let the number be x.
The reciprocal of the number will be 1/x
If the sum of the number and its reciprocal is 41/20, this can be represented as;
[tex]x+\frac{1}{x} = 41/20\\\frac{x^{2}+1}{x} = \frac{41}{20} \\20x^{2} +20 = 41x\\20x^{2} -41x+20 = 0\\[/tex]
Uisng the general formula to get x
x = -b±√b²+4ac/2a
x = 41±√41²-4(20)(20)/2(20)
x = 41±√1681-1600/40
x = 41±√81/40
x = 41±9/40
x = 50/40 or 32/40
x = 5/4 or 4/5
if the value is 5/4, the other value will be 4/5
The numbers are 5/4 and 4/5
The smaller value is 4/5
The larger value is 5/4
Answer:
a=5/4 or 4/5
Therefore, the smaller value = 4/5
The larger value = 5/4
Step-by-step explanation:
Let the number be represented by a
And it's reciprocal be represented by 1/a
So we have
a + 1/a = 41/20
Cross Multiply
20( a +1/a) = 41
20a +20/a =41
Find the LCM which is a
20a² + 20 = 41a
20a² + 20 - 41a =0
20a² - 41a +20 = 0
20a²-25a - 16a + 20 =0
5a(4a - 5) -4( 4a - 5) = 0
(5a - 4)(4a - 5) = 0
5a - 4 = 0
5a = 4
a = 4/5
or
4a - 5 = 0
4a =5
a = 5/4
Therefore, the number which is represented by a is
1) a = 4/5 while it's reciprocal which is 1/a is 5/4
or
2) a = 5/4 which it's reciprocal which is 1/a = 4/5
Therefore, the smaller value = 4/5
The larger value = 5/4
Find f(x) - g(x) when f(x) = 2x^2 - 4x g(x) = x^2 + 6x
3x^2
x^2 + 2x
x^2 - 10x
3x^2 + 2x
Answers
Answer:
x^2 - 10x
Step-by-step explanation:
2x^2 - 4x - x^2 +6x
You subtract x^2 from 2x^2 and you get x^2
Then you add 6x and 4x together and get 10x
So then you have x^2 - 10x
(plus I took the test and this was the correct answer.)
SOMEONE PLEASE HELP ME ASAP PLEASE!!!
Answers
Answer:
38 units
Step-by-step explanation:
We can find the perimeter of the shaded figure be finding out the number of unit lengths we have along the boundary of the given figure.
Thus, see attachment below for the number of units of each length of the figure that we have counted.
The perimeter of the figure = sum of all the lengths = 7 + 7 + 10 + 2 + 2 + 6 + 2 + 2 = 38
Perimeter of the shaded figure = 38 units
A man wants to set up a 529 college savings account for his granddaughter. How much would he need to deposit each year into the account in order to have $50,000 saved up for when she goes to college in 17 years, assuming the account earns a 5% return?
Answers
Answer:
1937.98
Step-by-step explanation:
In the given question, to find the value to be added per year we will use the formula
P= A. r/n/ (1 +r/n)ⁿ - 1
Here A = 50,000
r (rate of interest) = 5 % or 0.05.
n = 1
t = 17
P = value deposit per year
therefore, P = (50,000 X 0.05)/ (1 +0.05)¹⁷ - 1
P = 2500 / 2.29- 1
= 1937.98 $.
therefore, person has to deposit 1937.98 $ per month.
The table shows some values of x and y that satisfy the equation y = acosxº + b
Х
0
30
180
60
90
120
150
y
10
4 + 373
7
4
1
4-373
-2
Find the value of y when x = 45
Answers
Answer:
Y = 3√2 +4
Step-by-step explanation:
y = acosxº + b
Let's look for the values of a and b first.
Let's get values of x and y and solve simultaneously
When x= 0 ,y=10
When x = 120, y= 1
10 =acos0 + b
10 = a +b..... equation 1
1 = acos120 + b
1= -0.5a + b ..... equation 2
10 = a +b
1= -0.5a + b
10-1= a +0.5a
9 = 1.5a
9/1.5 = a
6 = a
1= -0.5a + b ..... equation 2
1 = -0.5(6) +b
1= -3 + b
1+3 = b
4 =b
So
y = acosxº + b equal to
Y = 6cosx° + 4
So value of y when x= 45 is
Y= 6cos45° +4
Y =6(√2/2) +4
Y = 3√2 +4
The value of y when x = 45 degree is, [tex]y=3\sqrt{2}+4[/tex]
Given function is,
[tex]y = a cos(x)+ b[/tex]
From given table, It is observed that,
x = 0, y = 10 and x = 90, y = 4
Substitute above values in above equation.
[tex]a+b=10\\\\b=4[/tex]
[tex]a=10-b=10-4=6[/tex]
Now, our equation become,
[tex]y = 6 cos(x)+ 4[/tex]
Substitute x = 45 in above equation.
[tex]y=6cos(45)+4\\\\y=6*(\frac{\sqrt{2} }{2} )+4\\\\y=3\sqrt{2} +4[/tex]
Learn more:
https://brainly.com/question/13729598
A basketball coach is looking over the possessions per game during last season. Assume that the possessions per game follows an unknown distribution with a mean of 56 points and a standard deviation of 12 points. The basketball coach believes it is unusual to score less than 50 points per game. To test this, she randomly selects 36 games. Use a calculator to find the probability that the sample mean is less than 50 points. Round your answer to three decimal places if necessary.
Answers
Answer:
The probability that the sample mean is less than 50 points = 0.002
Step-by-step explanation:
Step(i):-
Given mean of the normal distribution = 56 points
Given standard deviation of the normal distribution = 12 points
Random sample size 'n' = 36 games
Step(ii):-
Let x⁻ be the random variable of normal distribution
Let x⁻ = 50
[tex]Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }[/tex]
[tex]Z = \frac{50-56 }{\frac{12}{\sqrt{36} } }= -3[/tex]
The probability that the sample mean is less than 50 points
P( x⁻≤ 50) = P( Z≤-3)
= 0.5 - P(-3 <z<0)
= 0.5 -P(0<z<3)
= 0.5 - 0.498
= 0.002
Final answer:-
The probability that the sample mean is less than 50 points = 0.002
Answer:
56
2
.001
Step-by-step explanation:
The Central Limit Theorem for Means states that the mean of any sampling distribution of the means is equal to the mean of the population distribution. The standard deviation is equal to the standard deviation of the population divided by the square root of the sample size. So, the mean of this sampling distribution of the means with sample size 36 is 56 points and the standard deviation is 1236√=2 points. The z-score for 50 using the formula z=x¯¯¯−μσ is −3.
z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09
-3.0 0.001 0.001 0.001 0.001 0.001 0.001 0.001 0.001 0.001 0.001
-2.9 0.002 0.002 0.002 0.002 0.002 0.002 0.002 0.001 0.001 0.001
-2.8 0.003 0.002 0.002 0.002 0.002 0.002 0.002 0.002 0.002 0.002
-2.7 0.003 0.003 0.003 0.003 0.003 0.003 0.003 0.003 0.003 0.003
-2.6 0.005 0.005 0.004 0.004 0.004 0.004 0.004 0.004 0.004 0.004
-2.5 0.006 0.006 0.006 0.006 0.006 0.005 0.005 0.005 0.005 0.005
Using the Standard Normal Table, the area to the left of −3 is approximately 0.001. Therefore, the probability that the sample mean will be less than 50 points is approximately 0.001.