Answer:
the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes is 0.4215
Step-by-step explanation:
Let consider Q to be the opening altitude.
The mean μ = 135 m
The standard deviation = 35 m
The probability that the equipment damage will occur if the parachute opens at an altitude of less than 100 m can be computed as follows:
[tex]P(Q<100) = P(\dfrac{X- 135}{\sigma} < \dfrac{100 - 135}{35}})[/tex]
[tex]P(Q<100) = P(z< \dfrac{-35}{35}})[/tex]
[tex]P(Q<100) = P(z<-1)[/tex]
[tex]P(Q<100) = 0.1587[/tex]
If we represent R to be the number of parachutes which have equipment damage to the payload out of 5 parachutes dropped.
The probability of success = 0.1587
the number of independent parachute n = 5
the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes can be computed as:
P(R ≥ 1) = 1 - P(R < 1)
P(R ≥ 1) = 1 - P(R = 0)
The probability mass function of the binomial expression is:
P(R ≥ 1) = [tex]1 - (^5_0)(0.1587)^0(1-0.1587)^{5-0}[/tex]
P(R ≥ 1) =[tex]1 - (\dfrac{5!}{(5-0)!})(0.1587)^0(1-0.1587)^{5-0}[/tex]
P(R ≥ 1) = 1 - 0.5785
P(R ≥ 1) = 0.4215
Hence, the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes is 0.4215
In the following problem, the expression is the right side of the formula for cos (alpha - beta) with particular values for alpha and beta. cos (79 degree) cos (19 degree) + sin (79 degree) sin (19 degree)
Identify alpha and beta in each expression.
The value for alpha: degree
The value for beta: degree
Write the expression as the cosine of an angle. cos degree
Find the exact value of the expression. (Type an exact answer, using fraction, radicals and a rationalized denominator.)
Answer:
1. [tex]\alpha = 79[/tex] and [tex]\beta = 19[/tex]
2. [tex]cos(60)[/tex]
3. [tex]cos(60) = \frac{1}{2}[/tex]
Step-by-step explanation:
Given
[tex]cos(\alpha - \beta )[/tex]
[tex]cos(79)cos(19) + sin(79)sin(19)[/tex]
Solving for [tex]\alpha[/tex] and [tex]\beta[/tex]
In trigonometry;
[tex]cos(\alpha - \beta ) = cos\alpha\ cos\beta + sin\alpha\ sin\beta[/tex]
Equate the above expression to [tex]cos(79)cos(19) + sin(79)sin(19)[/tex]
[tex]cos(\alpha - \beta ) = cos\alpha\ cos\beta + sin\alpha\ sin\beta[/tex] and [tex]cos(\alpha - \beta ) = cos(79)cos(19) + sin(79)sin(19)[/tex]
By comparison
[tex]cos\alpha\ cos\beta + sin\alpha\ sin\beta = cos(79)cos(19) + sin(79)sin(19)[/tex]
Compare expression on the right hand side to the left hand side
[tex]cos\alpha\ cos\beta = cos(79)cos(19) \\\\ sin\alpha\ sin\beta = sin(79)sin(19)[/tex]
This implies that
[tex]cos\alpha\ = cos(79)\\cos\beta = cos(19) \\\\ and\\\\sin\alpha\ = sin(79)\\sin\beta = sin(19)[/tex]
By further comparison
[tex]\alpha = 79[/tex] and [tex]\beta = 19[/tex]
Substitute [tex]\alpha = 79[/tex] and [tex]\beta = 19[/tex] in [tex]cos(\alpha - \beta )[/tex]
[tex]cos(\alpha - \beta ) = cos(79 - 19)[/tex]
[tex]cos(\alpha - \beta ) = cos(60)[/tex]
Hence, the expression is [tex]cos(60)[/tex]
Solving for the exact values;
Express [tex]cos(60)[/tex] as a difference of angles
[tex]cos(60) = cos(90 - 30)[/tex]
Recall that [tex]cos(\alpha - \beta ) = cos\alpha\ cos\beta + sin\alpha\ sin\beta[/tex]
So;
[tex]cos(90- 30 ) = cos(90) cos(30) + sin(90) sin(30)[/tex]
------------------------------------------------------------------------------------
In trigonometry;
[tex]cos(90) = 0[/tex]; [tex]cos(30) = \frac{\sqrt{3}}{{2}}[/tex]; [tex]sin(90) = 1[/tex]; [tex]sin(30) = \frac{1}{2}[/tex];
---------------------------------------------------------------------------
[tex]cos(90- 30 ) = cos(90) cos(30) + sin(90) sin(30)[/tex] becomes
[tex]cos(90- 30 ) = 0 * \frac{\sqrt{3}}{2} + 1 * \frac{1}{2}[/tex]
[tex]cos(90- 30 ) = 0 + \frac{1}{2}[/tex]
[tex]cos(90- 30 ) = \frac{1}{2}[/tex]
Hence;
[tex]cos(60) = \frac{1}{2}[/tex]
Which statement would produce a tautology? A. p q B. p q C. p p D. q p
Answer: C. p = p
Step-by-step explanation:
A tautology is a statement that is always true.
A. p = q
This is not always true. Counterexample: p = 1 & q = 2
B. p = q
This is the same as A (above)
C. p = p
This is ALWAYS true!
D. q = p
This is the same as A but in reverse order.
Find the slope of the line that passes through the points (-2, 4) and (-5, -6).
-217
10/3
-2/3
Answer:
10/3.
Step-by-step explanation:
To find the slope, we do the rise over the run.
In this case, the rise is 4 - (-6) = 4 + 6 = 10.
The run is -2 - (-5) = -2 + 5 = 3.
So, the slope is 10/3.
Hope this helps!
10/3
Step-by-step explanation:
gradient=y²-y¹
x²-x¹
= -6-4
-5-(-2)
= -10
-5+2
= -10
-3
=10/3
Please HELP best answer will receive a BRAINLIEST. Given the probability density function f ( x ) = 1/3 over the interval [ 4 , 7 ] , find the expected value, the mean, the variance and the standard deviation.
Answer:
Step-by-step explanation:
Assume that f(x) = 0 for x outside the interval [4,7]. We will use the following
[tex]E[X^k] = \int_{4}^{7}x^k f(x) dx[/tex]
[tex]Var(X) = E[X^2]- (E[X])^2[/tex]
Standard deviation = [tex] \sqrt[]{Var(X)}[/tex]
Mean = [tex]E[X][/tex]
Then,
[tex]E[X] = \int_{4}^{7}\frac{1}{3}dx = \frac{7^2-4^2}{2\cdot 3} = \frac{11}{2}[/tex]
[tex]E[X^2] = \int_{4}^{7}\frac{x^2}{3}dx = \frac{7^3-4^3}{3\cdot 3} = 31[/tex]
Then, [tex]Var(x) = 31-(\frac{11}{2})^2 = \frac{3}{4}[/tex]
Then the standard deviation is [tex]\frac{\sqrt[]{3}}{2}[/tex]
Three of the sides will require fencing and the fourth wall already exists. If the farmer has 116 feet of fencing, what are the dimensions of the region with the largest area
Answer:
29 ft x 58 ft
Step-by-step explanation:
Let x be the length of each side perpendicular to the wall, and y be the length of the side parallel to the wall.
The amount of wire available is:
[tex]116 = 2x+y\\y=116-2x[/tex]
The area of the region is:
[tex]A=xy=x(116-2x)\\A(x)=116x-2x^2[/tex]
The value of 'x' for which the derivate of the area function is zero will yield the maximum area:
[tex]A(x)=116x-2x^2\\A'(x) = 116-4x=0\\x=29\ ft[/tex]
The value of y is:
[tex]y=116-2*29\\y=58\ ft[/tex]
The dimensions of the region with the largest area are 29 ft x 58 ft.
A fisherman uses a spring scale to weigh a tilapia fish. He records the fish weight as a kilograms and notices that the spring stretches b centimeters. Which expression represents the spring constant (1 =9.8 )? A). 980ab B). 9.8ab C). 9.8ab D). 980ab
Answer:
k = [tex]\frac{980a}{b}[/tex]
Step-by-step explanation:
Fisherman noticed a stretch in the spring = 'b' centimetres
Weight of the fish = a kilograms
If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,
F = kΔx
Where k = spring constant
Δx = stretch in the spring
F = weight applied
F = mg
Here 'm' = mass of the fish
g = gravitational constant
F = a(9.8)
= 9.8a
Δx = b centimetres = 0.01b meters
Therefore, 9.8a = k(0.01b)
k = [tex]\frac{9.8a}{0.01b}[/tex]
k = [tex]\frac{980a}{b}[/tex]
Therefore, spring constant of the spring will be determined by the expression, k = [tex]\frac{980a}{b}[/tex]
The chart below lists the original and sale prices of items at a clothing store.
Clothing Prices
Original price Sale price
$7.99
$5.59
$10.99
$7.69
$12.99
$9.09
$15.99
$11.19
$24.99
$17.49
$29.99
$20.99
Which statement best describes why the sale price is a function of the original price?
As the original price increases, the sale price also increases.
The sale price is always less than the original price.
For every original price, there is exactly one sale price.
The sales price is never less than zero.
Answer: C) For every original price, there is exactly one sale price.
For any function, we always have any input go to exactly one output. The original price is the input while the output is the sale price. If we had an original price of say $100, and two sale prices of $90 and $80, then the question would be "which is the true sale price?" and it would be ambiguous. This is one example of how useful it is to have one output for any input. The input in question must be in the domain.
As the table shows, we do not have any repeated original prices leading to different sale prices.
Answer:
C STAY SAFE!!!
Step-by-step explanation:
Ok we know this cant be A the reason is It says tha the original price is increasing so thats FALSE... its trying to trick you so no
The second choice says The sale price is always less than the original price. well take a look at the sale prices are they? Obiously not so False
Ok the third option For every original price, there is exactly one sale price. well this is true ask yourself each it helps.
Last option The sales price is never less than zero. erm FALSE OBIOUSLY THIS IS TRUE JUST NOT TRUE ITS WRONG
THE ANSER IS C
what is the value of this expression when a = 2 and b = -3 ? a^3 - b^3 / 5
Answer:
13 2/5
Step-by-step explanation:
a = 2 and b = -3
so the question asks whats.... a^3 - b^3/5
First we plug in the values of a and b
(2)^3 - (-3)^3 /5
Now we solve the ones in paranthesis first
(2)^3 = 8 because 2×2×2 and
-(-3)^3 forget about the - outside the parenthesis so
(-3)^3 = (-27) because (-3)×(-3)×(-3)
now we put it back together
8 -(-27)/5
the two minus become plus so
8 + 27/5
Now we solve it like fractions
8 and 27/5
simplify
13 and 2/5
Hope that helps!
The population of fruit flies in a laboratory grows geometrically and is checked everyday at noon. If the population began with 80 fruit flies and reached 125 in two days, what is the population after 4 days?
Answer:
[tex]\boxed{195}[/tex]
Step-by-step explanation:
The fruit flies grows geometrically.
[tex]125=80k^2[/tex]
Find the value of k.
[tex]\sqrt{\frac{125}{80} } =k[/tex]
[tex]1.25=k[/tex]
[tex]P=80(1.25)^t[/tex]
[tex]t[/tex] is number of days.
[tex]P=80(1.25)^4[/tex]
[tex]P=195[/tex]
Suppose a car depreciates linearly the second you drive it off the lot. If you purchased the car for $31,500 and after 5 years the car is worth $20,500, find the slope of the depreciation line.
Answer: m = - 2200
Step-by-step explanation: Slope of a line is a number which describes the steepness and direction of a linear graph. It is represented by the letter m.
The year a car is bought and its price means:
f(0) = 31,500
Five years later, the price is $20,500, i.e.:
f(5) = 20,500
With these two pairs of value, slope is calculated as:
[tex]m = \frac{y-y_{0}}{x-x_{0}}[/tex]
[tex]m = \frac{20500-31500}{5-0}[/tex]
[tex]m = \frac{- 1100}{5}[/tex]
m = - 2200
The slope of the depreciation line is m = -2200 and it is negative because the line decreases along time.
The mayor of a town has proposed a plan for the annexation of a new community. A political study took a sample of 10001000 voters in the town and found that 29)% of the residents favored annexation. Using the data, a political strategist wants to test the claim that the percentage of residents who favor annexation is more than 26&%. Determine the P-value of the test statistic. Round your answer to four decimal places.
Answer:
We accept H₀
p-value = 0,1618
Step-by-step explanation:
We are going to solve a one tail proportion-test ( right tail)
We assume Normal distribution
Sample population 1000
Political strategist to test wants to test:
Null hypothesis H₀ p = p₀ or p = 26 %
Alternate hypothesis Hₐ p > p₀ or p > 26%
We assume CI 90 % then
α = 10 % α = 0,1 and z score for α = 0,1 is critical value
z = 2,32 ( note 2,32 is z score for α = 0,1017 "good approximation")
To compute z(s)
z(s) = ( p -p₀ ) / √ p₀q₀/n
z(s) = ( 0,29 - 0,26 ) /√ 0,26*0,74/1000
z(s) = 0,03 / 0,014
z(s) = 2,14
We compare z(s) and z(c)
z(s) < z(c)
2,14 < 2,32
z(s) is in the acceptance region we accept H₀
The p-value for z(s) is from z-table
p-value = 0,1618
PLEASE HELP ASAP!! Write a polynomial f(x) that satisfies the following conditions. Polynomial of lowest degree with zeros of -4 (multiplicity of 1), 2 (multiplicity of 3), and with f(0)=64
Answer:
See below.
Step-by-step explanation:
So, we have the zeros -4 with a multiplicity of 1, zeros 2 with a multiplicity of 3, and f(0)=64.
Recall that if something is a zero, then the equation must contain (x - n), where n is that something. In other words, for a polynomial with a zero of -4 with a multiplicity of 1, then (x+4)^1 must be a factor.
Therefore, (x-2)^3 (multiplicity of 3) must also be a factor.
Lastly, f(0)=64 tells that when x=0, f(x)=64. Don't simply add 64 (like what I did, horribly wrong). Instead, to keep the zeros constant, we need to multiply like this:
In other words, we will have:
[tex]f(x)=(x+4)(x-2)^3\cdot n[/tex], where n is some value.
Let's determine n first. We know that f(0)=64, thus:
[tex]f(0)=64=4(-2)^3\cdot n[/tex]
[tex]64=-32n, n=-2[/tex]
Now, let's expand:
Expand:
[tex]f(x)=(x+4)(x^2-4x+4)(x-2)(-2)[/tex]
[tex]f(x)=(x^2+2x-8)(x^2-4x+4)(-2)[/tex]
[tex]f(x)=(x^4-4x^3+4x^2+2x^3-8x^2+8x-8x^2+32x-32)(-2)[/tex]
[tex]f(x)=-2x^4+4x^3+24x^2-80x+64[/tex]
This is the simplest it can get.
David says he has 2/3 of a pipe length left, while Don says he has 11/16 of a length left. Which person has the longest section left?
Answer:
Don
Step-by-step explanation:
1. We make the fractions have common denominators so it is easier to compare them. We can do this buy multiplying 2/3 by a factor of 16, so it becomes 32/48. For 11/16, we multiply by a factor of 3 so it becomes 33/48. It is now apparent that Don has the longer pipe.
Don has the longest section of pipe because the fraction number 11/16 is greater than the fraction number 2/3.
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The decimal number is the sum of a whole number and part of a fraction number. The fraction number is greater than zero but less than one.
David says he has 2/3 of a line length left, while Wear says he has 11/16 of a length left.
Convert the fraction numbers 2/3 and 11/16 into the decimal number. Then we have
2/3 = 0.6667
11/16 = 0.6875
The decimal number 0.6875 is greater than 0.6667. Then the fraction number 11/16 is greater than the fraction number 2/3.
Don has the longest section of pipe because the fraction number 11/16 is greater than the fraction number 2/3.
More about the Algebra link is given below.
https://brainly.com/question/953809
#SPJ2
Exhibit 3-3Suppose annual salaries for sales associates from Hayley's Heirlooms have a bell-shaped distribution with a mean of $32,500 and a standard deviation of $2,500.The z-score for a sales associate from this store who earns $37,500 is ____
Answer:
The z-score for a sales associate from this store who earns $37,500 is 2
Step-by-step explanation:
From the given information:
mean [tex]\mu[/tex] = 32500
standard deviation = 2500
Sample mean X = 37500
From the given information;
The value for z can be computed as :
[tex]z= \dfrac{X- \mu}{\sigma}[/tex]
[tex]z= \dfrac{37500- 32500}{2500}[/tex]
[tex]z= \dfrac{5000}{2500}[/tex]
z = 2
The z-score for a sales associate from this store who earns $37,500 is 2
√50 as a mixed radical!
Answer:
5sqrt(2)
Step-by-step explanation:
you can split 50 into sqrt(25×2)
and the sqrt(25) is 5, so than your left with just the 2 in the sqrt.
Determine the amount of paint required to cover a wall that is 11feet high and 15feet wide, if the wall has two rectangular windows (which are not to be painted), each measuring 3feet by 7feet.
Answer:
123 Square Feet. Of Paint. Probably gonna take a little more than a sample-size quart, let me know how it turns out.
Step-by-step explanation:
You would need 11*15=165 square feet of paint. BUT
You need 42 less square feet, because there are 2, 7*3=21 square-foot windows.
165-42
taking a test- Which expression represents the surface area of the cone? A cone with diameter 12 inches, height 8 inches, and slant height 10 inches. S A = pi r l + pi r squared (pi) (6) (10) + (pi) (6 squared) (pi) (8) (10) + (pi) (8 squared) (pi) (12) (10) + (pi) (12 squared) (pi) (10) (12) + (pi) (10 squared)
Answer:
[tex]SA = \pi (6) * 10+\pi ( 6)^2[/tex]
Step-by-step explanation:
The surface area of a cone is given by
[tex]SA = \pi rl +\pi r^2[/tex]
r is the radius and l is the slant height.
The diameter is 12 inches, the radius is 12/2 = 6 inches.
The slant height is 10 inches.
[tex]SA = \pi (6) * 10+\pi ( 6)^2[/tex]
Answer:
SA of cone = [tex](\pi )(6)(8) + (\pi )(6)^2[/tex]
Step-by-step explanation:
Surface Area of cone = [tex]\pi rh+\pi r^2[/tex]
Where r = 6 inches (Diameter = 12 inches) , h = 8 inches (We'll not consider the slant height)
SA of cone = [tex](\pi )(6)(8) + (\pi )(6)^2[/tex]
think about whether the diagram represents a function.
Step-by-step explanation:
im sorry but i need more info or a picture or something to actually anwser the question...
hhhelpp meeee!! I WILL GIVE BRAINLIEST
Answer:
We're solving for CD. If we look at ΔABD we notice that it's a 30-60-90 triangle which has a side length ratio of 1:√3:2 and in this case the 1 is 300 so side BD = 300√3. Similarly, ΔABC is also a 30-60-90 triangle but this time the √3 is 300 so side BC = 100√3. We know that CD = BD - BC using PWP so the answer is 300√3 - 100√3 = 200√3 = 346.4 feet.
Samantha has 5 granola bars. She wants to give 1/3 of a granola bar to each friend. Which expression can she use to find the number of friends to whom she can give granola bars?
Answer:
5/(1/3)
Step-by-step explanation:
She has 5 granola bars and gives 1/3 of one to each of her friends. To find how many friends she can give it to, divide 5 by 1/3. You would get a total of 15 friends that you can give granola bars to. The question is asking for an expression so the expression would be 5/(1/3) or 5*3
Answer:
1/3 x = 5
x=15
Step-by-step explanation:
You’re multiplying 1/3 times the number of friends (x), and then multiplying both sides by the reciprocal to solve for x
3) and
What is the equation, in point-slope form, of the line that
is perpendicular to the given line and passes through the
point (-4, 3)?
O y-3 = -2(x+4)
Oy-3=-{(x + 4)
y-3 = {(x + 4)
O y-3 = 2(x + 4)
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
The given line passes through the points (-4, -3) and (4, 1).
What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (-4, 3)?
a) y - 3 = -2(x + 4)
b) y - 3= - (x + 4)
c) y - 3 = (x + 4)
d) y - 3 = 2(x + 4)
Answer:
The equation of the line that is perpendicular to the given line and passes through the point (-4, 3) is
a) y - 3 = -2(x +4)
Step-by-step explanation:
First of all, we will find the slope of the given line.
We are given that the line passes through the points (-4, -3) and (4, 1)
[tex](x_1, y_1) = (-4,-3) \\\\(x_2, y_2) = (4,1) \\\\[/tex]
The slope of the equation is given by
[tex]$ m_1 = \frac{y_2 - y_1 }{x_2 - x_1} $[/tex]
[tex]m_1 = \frac{1 -(-3) }{4 -(-4)} \\\\m_1 = \frac{1 + 3 }{4 + 4} \\\\m_1 = \frac{4 }{8} \\\\m_1 = \frac{1 }{2} \\\\[/tex]
Recall that the slopes of two perpendicular lines are negative reciprocals of each other.
[tex]$ m_2 = - \frac{1}{m_1} $[/tex]
So the slope of the other line is
[tex]m_2 = - 2[/tex]
Now we can find the equation of the line that is perpendicular to the given line and passes through the point (-4, 3)
The point-slope form is given by,
[tex]y - y_1 = m(x -x_1)[/tex]
Substitute the value of slope and the given point
[tex]y - 3 = -2(x -(-4) \\\\y - 3 = -2(x +4)[/tex]
Therefore, the correct option is (a)
y - 3 = -2(x + 4)
The equation of the line in point-slope form is y - 3 = -2(x + 4)
What is a linear equation?
A linear equation is in the form:
y = mx + b
Where y,x are variables, m is the rate of change and b is the y intercept.
The line passes through the point (-4, -3) and (4, 1). Hence:
Slope = (1 - (-3)) / (4 - (-4)) = 1/2
The slope of the line perpendicular to this line is -2 (-2 * 1/2 = -1).
The line passes through (-4, 3), hence:
y - 3 = -2(x - (-4))
y - 3 = -2(x + 4)
The equation of the line in point-slope form is y - 3 = -2(x + 4)
Find out more on linear equation at: https://brainly.com/question/14323743
A polynomial function is shown below:
f(x) = x3 - 4x2 - x + 4
Which graph best represents the function? (5 points)
Answer:
Simply plug in the polynomial into a graphing calc.
Step-by-step explanation:
what is that is the derivative of
x^2-x+3 at the point
x=5
What value of x where
x²-x+3
a minimum?
Answer:
see explanation
Step-by-step explanation:
differentiate using the power rule.
[tex]\frac{d}{dx}[/tex]( a[tex]x^{n}[/tex] ) = na[tex]x^{n-1}[/tex] , thus
[tex]\frac{d}{dx}[/tex](x² - x + 3 ) = 2x - 1
x = 5 → 2(5) - 1 = 10 - 1 = 9
To find the value of x for minimum , equate [tex]\frac{d}{dx}[/tex] to zero
2x - 1 = 0 , then
2x = 1 and
x = [tex]\frac{1}{2}[/tex]
A random sample of 144 observations produced a sample proportion of 0.4. An approximate 90% confidence interval for the population proportion p is between:_______
a) 0.320 and 0.480
b) 0.333 and 0.480
c) 0.333 and 0.467
d) 0.359 and 0.441
e) 0.313 and 0.487
Answer:
CI =(0.333, 0.480)
Step-by-step explanation:
The formula for calculating the confidence interval is expressed as shown;
CI = p±Z * √p(1-p)/n±0.5/n
Z is the z-score at 90% confidence
p is the sample proportion
n is the sample size
Given n = 144, p = 0.4 and z-score at 90% CI = 1.645 (from z table)
Substituting this values;
CI = p ± 1.645*√0.4(1-0.4)/144 ±0.5/n
CI = 0.4 ± 1.645*√0.4(0.6)/144 ± 0.5/144
CI = 0.4 ±1.645 * √0.24/144 ± 0.00347
CI = 0.4 ±1.645 * 0.04087± 0.00347
CI = 0.4±0.06723±0.00347
CI =(0.333, 0.480)
Write down the first 6 elements of the following sequence (where n ∈ Z+), then give a recursive definition for an. Do not forget the base case. (You do not need to prove it is correct).
a. an - 3n - 10
b. an= (1+(-1)^n)^n
c. an= 2n! (2)
Answer:
a. The first six terms are:
-7, -4, -1, 2, 5, 8
b. The first six terms are:
0, 2, 0, 2, 0, 2.
c. The first six terms are:
4, 8, 24, 96, 480, 2880
Step-by-step explanation:
a. an - 3n - 10
For n = 1
a1 = 3(1) - 10
= -7
For n = 2
a2 = 3(2) - 10
= -4
For n = 3
a3 = 3(3) - 10
= -1
For n = 4
a4 = 3(4) - 10
= 2
For n = 5
a5 = 3(5) - 10
= 5
For n = 6
a6 = 3(6) - 10
= 8
The first six terms are:
-7, -4, -1, 2, 5, 8
b. an= (1+(-1)^n)^n
For n = 1
a1 = (1+(-1)^1)^1
= 0
For n = 2
a2 = (1+(-1)^2)^1
= 2
For n = 3
a3 = (1+(-1)^3)^1
= 0
For n = 4
a4 = (1+(-1)^4)^1
= 2
For n = 5
a5 = (1+(-1)^5)^1
= 0
For n = 6
a6 = (1+(-1)^6)^1
= 2
The first six terms are:
0, 2, 0, 2, 0, 2.
c. an= 2n! (2)
For n = 1
a1 = 2(1!)(2)
= 4
For n = 2
a2 = 2(2!)(2)
= 8
For n = 3
a3 = 2(3!)(2)
= 24
For n = 4
a4 = 2(4!)(2)
= 96
For n = 5
a5 = 2(5!)(2)
= 480
For n = 6
a6 = 2(6!)(2)
= 2880
The first six terms are:
4, 8, 24, 96, 480, 2880
Which of the following is a point-slope equation of a line that passes through
the points (5,2) and (-1,-6)?
A. y-2-(X-5)
B. y-2-(X-5)
C. y-2 =(x-5
D. V-2--0-5)
Please, check the options of the question. The point-slope equation needs the slope, m, in the equation.
Answer:
The point-slope equation of the points (5,2) and (-1,-6) is
[tex] \\ y - 2 = \frac{4}{3}(x-5)[/tex] or,
[tex] \\ y + 6 = \frac{4}{3}(x+1)[/tex]
which are the same as
[tex] \\ 3y-4x+14 = 0[/tex] , (which is not a point-slope equation, though)
Step-by-step explanation:
The point-slope equation is given by:
[tex] \\ y - y_{1} = m(x - x_{1})[/tex]
Where m is the slope of the line:
[tex] \\ m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}[/tex]
Having the points (5,2) and (-1,-6), then
[tex] \\ m = \frac{-6 - 2}{-1 -5}[/tex]
[tex] \\ m = \frac{-8}{-6}[/tex]
[tex] \\ m = \frac{4}{3}[/tex]
Then, the point-slope equation of the points (5,2) and (-1,-6) is
[tex] \\ y - 2 = \frac{4}{3}(x-5)[/tex] or
[tex] \\ y + 6 = \frac{4}{3}(x+1)[/tex]
The below graph represents both lines (they are the same line).
Given: , ∠DAC ≅ ∠BCA Prove: ∆ADC ≅ ∆CBA Look at the proof. Name the postulate you would use to prove the two triangles are congruent. SAS Postulate SSS Postulate AAA Postulate
Answer:
SAS Postulate
Step-by-step explanation:
The contributors to the proof are listed in the left column. They consist of a congruent Side, a congruent Angle, and a congruent Side. The SAS Postulate is an appropriate choice.
I _____ some stuff A)'ve done B)'s do C)'s doing D)'s did E) 've
Answer:
A and E
Step-by-step explanation:
If the answer was A, it would translate to:
I have done some stuff.
If the answer was D, it would translate to:
I have some stuff.
Both of the sentences are grammatically correct, so A and E are the answers.
Incorrect:
B. - I's do some stuff - doesn't make sense
C. - I's doing some stuff - doesn't make sense
D. - I's did some stuff - doesn't make sense
A meteorologist who sampled 4 thunderstorms found that the average speed at which they traveled across a certain state was 16 miles per hour. The standard deviation of the sample was 4.1 miles per hour. Round the final answers to at least two decimal places.
Required:
Find the 90% confidence interval of the mean. Assume the variable is normally distributed.
Answer:
The 90 % confidence interval for the mean population is (11.176 ; 20.824 )
Rounding to at least two decimal places would give 11.18 , 20.83
Step-by-step explanation:
Mean = x`= 16 miles per hour
standard deviation =s= 4.1 miles per hour
n= 4
[tex]\frac{s}{\sqrt n}[/tex] = 4.1/√4= 4.1/2= 2.05
1-α= 0.9
degrees of freedom =n-1= df= 3
∈ ( estimator t with 90 % and df= 3 from t - table ) 2.353
Using Students' t - test
x`±∈ * [tex]\frac{s}{\sqrt n}[/tex]
Putting values
16 ± 2.353 * 2.05
= 16 + 4.82365
20.824 ; 11.176
The 90 % confidence interval for the mean population is (11.176 ; 20.824 )
Rounding to at least two decimal places would give 11.18 , 20.83
Answer:
[tex]11.18 < \mu <20.82[/tex]
Step-by-step explanation:
From the information given:
A meteorologist who sampled 4 thunderstorms of the sample size n = 16
the average speed at which they traveled across a certain state was 16 miles per hour ; i.e Mean [tex]\bar x[/tex] = 16
The standard deviation [tex]\sigma[/tex] of the sample was 4.1 miles per hour
The objective is to find the 90% confidence interval of the mean.
To start with the degree of freedom df = n - 1
degree of freedom df = 4 - 1
degree of freedom df = 3
At 90 % Confidence interval C.I ; the level of significance will be ∝ = 1 - C.I
∝ = 1 - 0.90
∝ = 0.10
∝/2 = 0.10/2
∝/2 = 0.050
From the tables;
Now the t value when ∝/2 = 0.050 is [tex]t_{\alpha / 2 ,df}[/tex]
[tex]t_{0.050 \ ,\ 3} = 2.353[/tex]
The Margin of Error = [tex]t_{\alpha / 2 ,df} \times \dfrac{s}{\sqrt{n}}[/tex]
The Margin of Error = [tex]2.353 \times \dfrac{4.1}{\sqrt{4}}[/tex]
The Margin of Error = [tex]2.353 \times \dfrac{4.1}{2}[/tex]
The Margin of Error = [tex]2.353 \times 2.05[/tex]
The Margin of Error = 4.82365
The Margin of Error = 4.82
Finally; Assume the variable is normally distributed, the 90% confidence interval of the mean is;
[tex]\overline x - M.O.E < \mu < \overline x + M.O.E[/tex]
[tex]16 -4.82 < \mu < 16 + 4.82[/tex]
[tex]11.18 < \mu <20.82[/tex]
solve for x in the diagram below
Answer:
45
Step-by-step explanation:
Both angles (2x+45) and x together form a straight angle which measures 180 degrees.
Together should make you think of adding the angle measurements.
So we have that (2x+45)+x should be 180 degrees.
The equation we want to solve is:
(2x+45)+x=180
2x+45+x=180
(2x+x)+45=180
3x+45=180
3x=180-45
3x=135
x=135/3
x=45
Let's confirm that x is 45.
(2x+45) with x=45:
(2*45+45)
(3*45)
135
So (2x+45)+x at x=45 gives us:
135+45
180
Answer has been confirmed.
Answer:
[tex]\boxed{x = 45}[/tex]
Step-by-step explanation:
=> [tex]x+2x+45 = 180[/tex] (Angles on a straight line add up to 180 degrees)
=> [tex]3x+45 = 180[/tex]
Subtracting 45 to both sides
=> 3x = 180-45
=> 3x = 135
Dividing both sides by 3
=> x = 45