Answer:
WAV, MP3, MID.
Explanation:
Power point has option to record the audio with the presentation slides. If the audio is not recorded with the slides creation then separate audio recording can be added to the presentation. The audio format needs to be supported by the power point and audio file format should be WAV, MP3 or MID. Audio formats other than this are not supported by the power point and if audio is in different it needs to be converted in MP3 to include in the presentation.
xtan-1x differentiate using first principle
Answer:
[tex]F'(x) = \frac{x}{{1 +x^{2} } } + tan^{-1} (x)}[/tex]
Explanation:
Given - F(x) = xtan⁻¹x
To find - Differentiate using first principle
Formula used -
First Principal :
F'(x) = [tex]\lim_{h \to 0} \frac{f(x+h) - f(x)}{h}[/tex]
and
[tex]tan^{-1}(A - B) = tan^{-1}(\frac{A - B}{1 + AB} )[/tex]
Proof -
Given that, F(x) = xtan⁻¹x
⇒F(x+h) = (x+h) tan⁻¹(x+h)
So,
[tex]F'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}\\= \lim_{h \to 0} \frac{(x+h)tan^{-1} (x+h) - xtan^{-1} x}{h}\\= \lim_{h \to 0} \frac{xtan^{-1} (x+h) + htan^{-1} (x+h) - xtan^{-1} x}{h}\\= \lim_{h \to 0} \frac{x(tan^{-1} (x+h) - tan^{-1} x) + htan^{-1} (x+h)}{h}\\= \lim_{h \to 0} \frac{x}{h} (tan^{-1} (x+h) - tan^{-1} x) + tan^{-1} (x+h)}[/tex]
Now,
We know that,
[tex]tan^{-1}(A - B) = tan^{-1}(\frac{A - B}{1 + AB} )[/tex]
[tex]F'(x) = \lim_{h \to 0} \frac{x}{h} (tan^{-1} (x+h) - tan^{-1} x) + tan^{-1} (x+h)}\\= \lim_{h \to 0} \frac{x}{h} tan^{-1} (\frac{(x+h) - x}{1 + (x+h)x}) + tan^{-1} (x+h)}\\= \lim_{h \to 0} \frac{x}{h} tan^{-1} (\frac{h}{1 + (x+h)x}) + tan^{-1} (x+h)}\\\\= \lim_{h \to 0} \frac{x}{h\frac{1 + x(x+h)}{1 +x(x+h)} } tan^{-1} (\frac{h}{1 + (x+h)x}) + tan^{-1} (x+h)}\\= \lim_{h \to 0} \frac{x}{{1 +x(x+h)} }.\frac{1 +x(x+h)}{h} tan^{-1} (\frac{h}{1 + (x+h)x}) + tan^{-1} (x+h)}[/tex]
Now,
We know that,
[tex]\lim_{h \to 0} \frac{tan^{-1} x}{x} = 1[/tex]
∴ we get
[tex]F'(x) = \lim_{h \to 0} \frac{x}{{1 +x(x+h)} }.\frac{1 +x(x+h)}{h} tan^{-1} (\frac{h}{1 + (x+h)x}) + tan^{-1} (x+h)}\\ = \lim_{h \to 0} \frac{x}{{1 +x(x+h)} }.\lim_{h \to 0}\frac{1 +x(x+h)}{h} tan^{-1} (\frac{h}{1 + (x+h)x}) + \lim_{h \to 0}tan^{-1} (x+h)}\\= \frac{x}{{1 +x(x+0)} }.1 + tan^{-1} (x+0)}\\= \frac{x}{{1 +x(x)} } + tan^{-1} (x)}\\= \frac{x}{{1 +x^{2} } } + tan^{-1} (x)}[/tex]
So,
We get
[tex]F'(x) = \frac{x}{{1 +x^{2} } } + tan^{-1} (x)}[/tex]
Why are the more strict tools for assessing green products those that demand second-or third-party verification?
O The assessment process is more adaptable.
O The assessment process takes longer.
The assessment process iphore independent.
The assessment process is more elaborate.
Answer:
C,
The assessment process is more independent.
Explanation:
Which of the following is typical of the selection of survey participants? They can indicate partiality toward a group. They must be surveyed more than once. They can be selected on purpose by a researcher. They must be representative of the population.
Answer:
Option D
Explanation:
In general a sample collected from a set of naturally distributed data set must also follow the bell curve or natural distribution
In other way round it can be said that sample set must have the same characteristics as that of the main set and hence a sample must be representative of the population.
Option D is correct
Answer:
the answer is they must be representative of the population.
Explanation:
I took the test and got it right.
When removing masking tape:
0
pull tape straight up.
O make sure the vehicle surface temperature is above 60°F.
O make sure it is done before the detailing process.
O use a wax and grease remover to loosen the tape adhesive.
Table of Contents
you make sure it’s done before the detailing process ! this is so you can begin the process without ruining the original piece.
if you were to pull straight up, it would damage the area around it by cracking or removing ♡
Match the thermal conductivity to the material by drawing a line between them.
Glass Aluminum Insulating Material
205 W/m.K 0.035 W/m.K 0.935 W/m.K
Answer:
Glass → 0.935 W/(m·K)
Aluminum → 205 W/(m·K)
Insulating Material → 0.035 W/(m·K)
Explanation:
Thermal conduction is the motion of molecules of a body, randomly, across a segment or region that has a temperature gradient that results in the transportation of energy
The thermal conductivity of a material is a measure of the ability of the material to transfer or conduct heat energy
Due to the availability of moving charged particles in metals, metals conduct heat more than non-metals as we can use metal pots for cooking but we cannot readily cook using non metallic material using thermal materials directly on a stove
Therefore, aluminum has a higher thermal conduction than glass and glass will have a higher thermal conduction than an insulating material
We therefore have;
Aluminum → 205 W/(m·K)
Glass → 0.935 W/(m·K)
Insulating Material → 0.035 W/(m.K).
Who else goes to Loveland High school?
Answer:
i dont go there lol and omg i wouldent be telling random people were you go to school it aint safe
Explanation:
Answer:one of my friends
Explanation:
my friend leo goes to it im soon gonna go to it.
What is the approximate time of death if the body temperature was 50°F?
The approximate time of death of a body whose temperature was 50°F = 48.6 hours
How to calculate time of death?The time of death is your by the forensic experts for investigation purposes.
The body loses 1 °F every one hour.
The human body is = 98.6*F
Therefore, to calculate the time of death of the body whose temperature is 50°F = 98.6 - 50
= 48.6 × 1 hour = 48.6 hours
Learn more about forensic science here:
https://brainly.com/question/19238665