The attachment contains the question.

Answer:

C

Step-by-step explanation:

Answer:

minutes at daytime rate: 3.00

minutes at nighttime rate: $2.70

total cost of call: $8.55

Step-by-step explanation:

split up the hours so you have the 5 cent charge per minute for 1 hour and you have the 3 cents a minute for an hour and a half after 8.

multiply 5 cents a minute by 60 to get the amount of money for the first hour($3.00),

next multiply 3cents a minute by an hour and a half (90 minutes) to get $2.70

next add the money together to get $5.70 and multiply that by 1.5 to get $8.55

Answer:

i think it is 80sq cm

Step-by-step explanation:

Answer: 30 Kit Kats

Step-by-step explanation:

The ratio of Kit Kats to Snickers is 5:4 or [tex]\frac{5}{4}[/tex]

Let us name Kit Kats as "k", if there are 24 Snickers:

we need to find the number of Kit Kats that keeps ratio constant

[tex]\frac{5}{4} = \frac{k}{24}[/tex] ... crossmultiply

5 * 24 = 4 * k

120 = 4k

k = 30

Answer:

16 tickets

Step-by-step explanation:

Number of tickets he has to sell = 25

Number of tickets he has sold = 9

How many tickets does he still need to sell?

Number of tickets he still needs to sell = Number of tickets he has to sell - Number of tickets he has sold

= 25 - 9

= 16 tickets

Number of tickets he still needs to sell = 16 tickets

Therefore, Fahad still needs to sell 16 more tickets

Answer:        7x+2x = 108

find  x, then you know the amounts.

Step-by-step explanation:

Answer:

84 oz. water and 24 oz. powder

Step-by-step explanation:

Okay so the ratio of water to powder is 7x:2x, x being however much you increase the number based off the question

The sum of water and powder is 108

so, 7x+2x=108

9x=108

x=12

that means water is 7*12=84 oz.

        and powder is 2*12=24 oz.

to check: 84+24=108

Answer:

C

Step-by-step explanation:

Answer:

2 should be added to the data

Step-by-step explanation:

Hope this helps!

If im wrong im sorry!

Answer:

18 should be added

Step-by-step explanation:

So we have one 10 and one 11 in this data set, and we need to figure out which number we need to add to get a mean of 13

let's make this unknown number x

to find the mean, we add up all the values of the numbers on the data set, and divide it by how many numbers we have.

we have 3 numbers, and our numbers are 10, 11, and x. When we add 10, 11, and x together, and then divide by 3, the value is 13

as an equation we will have:

(10+11+x)/3=13

combining like terms in the numerator, it will be:

(21+x)/3=13

We need to solve this equation, and the denominator of 3 just makes harder to do that.

Clear the fraction by multiplying both sides by 3

21+x=39

subtract 21 from both sides

x=18

so that means that 18 should be added to the data set to get a mean of 13.

Hope this helps!

Answer:

Step-by-step explanation:

Use the rise over run formula

y2-y1/x2-x1

1992-1990/3317-3038

2/-279

-139.5

Answer:

Hey!

Step-by-step explanation:

Your answer would be 1/8

Have a nice day!♥

And ty XD

Answer:

A

y=3x+11

Step-by-step explanation:

The slope of the line perpendicular to y=-1/3x-4 is 3, and A is the only choice with the slope of 3.

Answer:

24

Step-by-step explanation:

Answer: 20

Step-by-step explanation:

Answer:

option 4 is correct answer of this question

6/x^3

Step-by-step explanation:

hope it helps and your day will be full of happiness

Answer:

2/5

Step-by-step explanation:

It's 2/5 because it goes up 2 and over 5

Answer:

A hope this helps

Step-by-step explanation:

Answer:

1 3/4

Step-by-step explanation:

First, find out how many times does 4 goes into 7, and you get 1 so 1 is the first part of your answer. Then you ask yourself what is 7-4? And you get 3, this is the top part of the fraction the numerator, as for the bottom the denominator, you just keep it as is. which leads you to get 1 3/4

The required 7 / 4 as the whole number is 1 3/4 (mixed fraction).

Given that,
To determine 7/4 as a whole number.

In mathematics, it deals with numbers of operations according to the statements. There are ,four major arithmetic operators, addition, subtraction, multiplication and division,

Fraction is defined as the number of compositions that constitutes the Whole.

Here,
The number 7/4 = quotient  + remainder / divisor
                           = 1   +   3/4

Thus,  the required 7 / 4 as the whole number is 1 3/4 (mixed fraction).

Learn more about arithmetic here:

brainly.com/question/14753192

#SPJ2

Answer:

Step-by-step explanation:

Answer:

option a

Step-by-step explanation:

95 +x=180

x=180-95=85

85+31+y=180

116+y=180

y=180-116=64

Answer:

9 grams

Step-by-step explanation:

93-21/8

Answer:

A

Step-by-step explanation:

The chance the coin will show 'tails' is 1/2, since there are only 2 sides to a coin. The chance that the die will show an even number is also 1/2, since half of the numbers on a die are even, and half are odd. But, since both of these events depend on each other, or in other words, are dependent, we have to multiply both numbers. 1/2 x 1/2 = 1/4, therefore your answer is A.

Answer:

Well, the only thing you should do is to use the formula.

if the bases are: a, b

and the height is=h

Then, this is your formula, S=½(a+b)×h

Step-by-step explanation:

Aight,

100dm=10m

S=10m

now, the formula

10=½(2.1+1.9)×h===> 20=4h==> h=5m

Answer:

[tex] A(x) = \frac{ 4x + 800 }{x}[/tex]

Step-by-step explanation:

[tex]C(x) = 4x + 800.... (given)[/tex]

[tex] \because \: A(x) = \frac{C(x) }{x}[/tex]

[tex] \therefore \: A(x) = \frac{ 4x + 800 }{x}[/tex]

Step-by-step explanation:

y = 6x-11

substitute y into 2x+3y=7

2x+3(6x-11)=7

2x + 18x-33 = 7

20 x = 7+33

x = 2

y?

y= 6(2)-11

y = 12-11 = 1

so, x = 2 and y = 1

Answer:

Yes, They are similar by SSS PMK similar to LMQ.

Step-by-step explanation:

Similar triangles corresponding side lengths are in a proportion.

KM corresponds with MQ

PM corresponds with LM.

Set up this proportion.

[tex] \frac{km}{pm} = \frac{lm}{mq} [/tex]

[tex] \frac{15}{28} = \frac{21}{39.2} [/tex]

Cross multiply

[tex]588 = 588[/tex]

So the triangles ARE Similar.

Answer:

sure whats ur question.

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

Answer:

[tex]\displaystyle 5[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{32}{39}} \hookrightarrow \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]

OR

[tex]\displaystyle \boxed{y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-1\frac{25}{39}} \hookrightarrow \frac{-\pi}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]

As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5cos\:\frac{39}{64}\pi{x} + 1,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between both photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle \frac{32}{39}\:unit[/tex]to the right, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{32}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you get [tex]\displaystyle \boxed{-\frac{32}{39}} = \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1.[/tex]Intermediate, we have two sine graphs [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5sin\:\frac{39}{64}\pi{x} + 1.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle 1\frac{25}{39}\:unit[/tex]to the right, which means that in order to match the leftward sine graph, we need to shift the graph BACKWARD [tex]\displaystyle 1\frac{25}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-1\frac{25}{39}} = \frac{-\pi}{\frac{39}{64}\pi}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-6\frac{22}{39}, 1],[/tex]from there to [tex]\displaystyle [-3\frac{11}{39}, 1],[/tex]they are obviously [tex]\displaystyle 3\frac{11}{39}\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 3\frac{11}{39}.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and in case you want to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended five units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. So, overall, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.