The art teacher buys containers to store 1,314

Answer:

(D). 5 km²

Step-by-step explanation:

QR² = 11² + 14² - 2(11)(14)cos77°

QR ≈ 15.739 km

P = 14 + 11 + 15.739 = 40.739 km

s = [tex]\frac{P}{2}[/tex] ≈ 20.37 km

[tex]A_{PQR}[/tex] = [tex]\sqrt{20.37(20.37-11)(20.37-14)(20.37-15.739)}[/tex] ≈ 75 km²

Solution :

68 % of the students owns iPod and a smart phone. So

p' = 0.68

q' = 1'

   = 1 - 0.68

   = 0.32

Since CL = 0.97, we know that [tex]$\alpha = 1 - 0.97 = 0.03 $[/tex]

The area to the left of [tex]$z_{0.015}$[/tex] is 0.015 and the area to the right of  [tex]$z_{0.015}$[/tex]  is [tex]$1 - 0.015 = 0.985 $[/tex]

Thus using [tex]$TI \ 83, 83+ \ or \ 84+$[/tex] calculator function [tex]$\text{InvNorm} (0.985, 0.1), z_{0.015} = 2.17$[/tex]

[tex]$\text{EBP} = z_{\alpha / 2} \times \left( \sqrt{\frac{p'q'}{n}}\right) $[/tex]

[tex]$\text{EBP} = 1.645 \times \sqrt{\frac{0.68 \times 0.32}{300}} $[/tex]

       = 0.0269

Therefore, we are ninety seven percent confident that a true proportion of all the students who has iPod as well as a smart phone is between the 0.6531 and 0.7069

a). (0.7731, 0.8269); We estimated that with 90% confidence, the true percentage of all the students in district who are against a new legislation is between 77.31% and 82.69%.

b). Now,

Press the 'STAT' and then arrow over to perform TEST.

Now arrow down to the A:1 - PropZint and then place Enter.

Arrow a down x and then enter the 300 x 0.68

Similarly arrow  a down to given n and then enter the 300

Now arrow down to the C-level and the enter the 0.97

Arrow a down for calculating and press the enter button.

The confidence interval is (0.6531, 0.7069)

a). (0.7731, 0.8269); We estimated that with 90% confidence, the true percentage of all the students in district who are against a new legislation is between 77.31% and 82.69%.

Answer:

The second number ($1,541.02) is greater

Step-by-step explanation:

In the 100s place of the second number is a 5 and in the first a 4

Even though they have the same 1000s number 500 is larger that 400

I believe your question is referring to which is greater-than, less-than, or if it's equal-to?

If so, then: $1,451.02 < $1,541.02

Answer:

1,771.6 inches.

Step-by-step explanation:

As there are 13 girls and 15 boys in the class, there are a total of 28 students (13 + 15). Thus, while the average height of these is 161 cm, the total height in centimeters of all the students is 4.508 centimeters (161 x 28).

Now, 1 centimeter is equal to 0.393 inches. Thus, since 4.508 x 0.393 equals 1,771.6, the height in inches of the entire class measured together is 1,771.6 inches.

Answer:

Step-by-step explanation:

7x + 6 + 5

six and five both are regular numbers but the 7x is not like term

7x + 11

Answer:

b which is 20 each time they add 5

Answer:

BC=26.05

Step-by-step explanation:

by tan(X) rule

tan(61)=47/BC

BC= 47 / tan(61)

BC=26.05

Answer:

Step-by-step explanation:

Given Information :

Hypotenuse : Not given

Opposite : 47

Adjacent : BC

Angle ( θ) = 61°

Using SOHCAHTOA

[tex]Tan\: \theta = \frac{Opposite}{Adjacent} \\\\Tan \: 61 = \frac{47}{BC} \\\\1.804 = \frac{47}{BC}\\\\Cross\:Multiply\\1.804BC= 47\\\\Divide\:both\:sides\:by\:1.8 \\\\\frac{1.804BC}{1.804} = \frac{47}{1.804} \\\\BC= 26.05[/tex]

Answer:

I hope this helps!!!

Step-by-step explanation:

Answer: I would go towards B

Step-by-step explanation:

122/8 = 15.25

This is more towards 15, so put the dot in the middle of 14 and 16

Answer:

[tex]y = 43[/tex]

Step-by-step explanation:

Given

[tex]First\ Minute = 7[/tex]

[tex]Additional\ Minutes = 4[/tex] per minute

Required

Determine the cost of a 10 minutes call

First, we need to determine the expression for the call charges.

Let:

The relationship between x and y is:

[tex]y = First\ Minute + Additional\ Minutes(Number\ of\ minutes\ - 1)[/tex]

i.e.

[tex]y = 7 + 4(x - 1)[/tex]

1 is subtracted from the total minutes because the first minute has a fixed rate.

For a 10 minutes call

[tex]x = 10[/tex]

[tex]y = 7 + 4(x - 1)[/tex]

[tex]y = 7 + 4(10 - 1)[/tex]

[tex]y = 7 + 4*9[/tex]

[tex]y = 7 + 36[/tex]

[tex]y = 43[/tex]

Hence, the charges for a 10 minutes call is: Rs.43

First,

tan(θ) = sin(θ) / cos(θ)

and given that 90° < θ < 180°, meaning θ lies in the second quadrant, we know that cos(θ) < 0. (We also then know the sign of sin(θ), but that won't be important.)

Dividing each part of the inequality by 2 tells us that 45° < θ/2 < 90°, so the half-angle falls in the first quadrant, which means both cos(θ/2) > 0 and sin(θ/2) > 0.

Now recall the half-angle identities,

cos²(θ/2) = (1 + cos(θ)) / 2

sin²(θ/2) = (1 - cos(θ)) / 2

and taking the positive square roots, we have

cos(θ/2) = √[(1 + cos(θ)) / 2]

sin(θ/2) = √[(1 - cos(θ)) / 2]

Then

tan(θ/2) = sin(θ/2) / cos(θ/2) = √[(1 - cos(θ)) / (1 + cos(θ))]

Notice how we don't need sin(θ) ?

Now, recall the Pythagorean identity:

cos²(θ) + sin²(θ) = 1

Dividing both sides by cos²(θ) gives

1 + tan²(θ) = 1/cos²(θ)

We know cos(θ) is negative, so solve for cos²(θ) and take the negative square root.

cos²(θ) = 1/(1 + tan²(θ))

cos(θ) = - 1/√[1 + tan²(θ)]

Plug in tan(θ) = - 12/5 and solve for cos(θ) :

cos(θ) = - 1/√[1 + (-12/5)²] = - 5/13

Finally, solve for sin(θ/2) and tan(θ/2) :

sin(θ/2) = √[(1 - (- 5/13)) / 2] = 3/√(13)

tan(θ/2) = √[(1 - (- 5/13)) / (1 + (- 5/13))] = 3/2

Answer:

B)13 pints

Step-by-step explanation:

SO first we find the unit rate

We know that in 90 minutes (hour and a half), the water leaked 6 pints form 2;30 to 4

Now So we can divide to find unit rate

6/90=1/15

So 1 pint for every 15 minutes

And now we want to know the amount it takes from 2:30 to 6:30 which is 4 hours

40 hours is 240 minutes

SO we can divide now

240/15=16

SO 16 pints leaked but the question asked for remaining water in container

So 29-16 is 13

So B)13

Answer:

117

Step-by-step explanation:

Answer:

117

Step-by-step explanation:

2+2=4

45+68=113

113+4=117

Answer:

51% of the money was spent, that is, 51/100. In conclusion, Jemina still has 49/100 of the money available.

Step-by-step explanation:

Since Jemima received $ 5 in pocket money, and spent $ 1.75 on a magazine and $ 0.80 on a drink, to determine the proportion of money he spent and the proportion he has left, the following calculation must be performed:

5 - (1.75 + 0.80) = X

5 - 2.55 = X

2.45 = X

5 = 100

2.55 = X

(2.55 x 100) / 5 = X

255/5 = X

51 = X

Therefore, 51% of the money was spent, that is, 51/100. In conclusion, Jemina still has 49/100 of the money available.

Answer:

4708.060

Step-by-step explanation:

The third place after the decimal is the thousands place, so there is nothing to change considering we do not know anything after the six. If a number after the number after six was 5 or higher, it would be 4708.007 :)

Answer:

It is A, since the lines is always touching

Step-by-step explanation:

Line always touch or if the graph just has 1 line= Infinite solution

If the lines never touch or Parallel lines= No solution

If the lines touch each other once= 1 solution

Answer:

The answer is -3.

Step-by-step explanation:

3x²-7x+1

=3(1)²-7(1)+1

=3-7+1

=-4+1

=-3

Answer: I pretty sure they are all right

Step-by-step explanation:

Answer:

$5825000

Step-by-step explanation:

You just take 23.3% of the 25 million dollars silly.

Answer:

She can purchase 6 tickets.

Step-by-step explanation:

Because 75 divided by 12 is 6.25 so that means she can purchase 6 tickets.

Answer:

You can purchase 8 tickets without the order fee but if put the order fee on you can purchase 6 tickets.

Hope this helps!

5 ln(x - 2) + 8 ln(x + 3) - 3 ln(x + 8)

ln(x - 2)⁵ + ln(x + 3)⁸ - ln(x + 8)³

since [tex]a\log_cb=\log_cb^a[/tex] (for any base c)

ln((x - 2)⁵ (x + 3)⁸ / (x + 8)³)

since [tex]\log_c(a)+\log_c(b)=\log_c(ab)[/tex] and [tex]\log_c(a)-\log_c(b)=\log_c\frac ab[/tex] (also for any base c)

Answer:

Subsitute the known point: (-1,3)

y>-5x^4+ 7x^3 +8.

3> -5(-1)^4 + 7(-1)^3 + 8

3> -5(1) + 7(-1) + 8

3> -5 - 7 + 8

3 > -4

True

3 Is greater than -4.

Answer:

True

Step-by-step explanation:

Just got it right on edge!