The 600-N ball shown is suspended on a string AB and rests against the frictionless vertical wall. The string makes an angle of 30° with the wall. The line AB goes through the center of the ball, and the contact point with the wall is at the same vertical height as the center of the ball. The ball presses against the wall with a force of magnitude:

Answers

Answer 1

Answer: T = 692.82 and 346.4 N

Explanation:

Given that;

w = 600 N

∅ = 30°

ΣFy = ma

a = 0 m/s²

ΣF = T(cos30°) - W = 0

T(cos30°) = W

we Divide both sides by cos30°

T = W / cos30o

T= 600N / cos30°

T = 692.82

and ∑fx

F = T sin∅

F = 692.82 × (sin30°)

F = 346.4 N

Answer 2

The equilibrium condition allows finding the result for the force of the ball against the wall is:

The force of the ball directed towards the wall is 346.4 N

Newton's second law gives a relationship between force, mass and acceleration of bodies. In the case where the acceleration is zero, it is called the equilibrium condition.

            ∑ F = 0

A free-body diagram is a diagram of the forces without the details of the bodies. In the attached we have a free-body diagram of the system.

Let's use trigonometry to break down stress.

          sin 30 = [tex]\frac{T_x}{T}[/tex]  

          cos 30 = [tex]\frac{T_y}{T}[/tex]  

          T_y = T cos 30

          Tₓ = T sin 30

Let's write the equilibrium condition for the system.

y-axis.

         T_y -W = 0

          T cos 30 = W

          [tex]T = \frac{W}{cos 30}[/tex]  

x-axis.

        R - Tₓ = 0

        R = T sin 30

 

We substitute

        [tex]R = \frac{W}{cos 30} \ sin 30 \\R = W \ tan 30[/tex]

Let's calculate.

        R = 600 tan 30

        R = 346.4 N

This force is directed from the wall towards the ball, by Newton's third law the force of the ball is of equal magnitude and opposite direction, that is, directed towards the wall.

In conclusion with the equilibrium condition we can find the result for the force of the ball against the wall is:

The force of the ball directed towards the wall is 346.4 N

Learn more about the equilibrium condition here: brainly.com/question/18117041

The 600-N Ball Shown Is Suspended On A String AB And Rests Against The Frictionless Vertical Wall. The

Related Questions

A ball thrown vertically upward returns to the thrower 25s later determine the speed with which it was thrown​

Answers

25/2=12.5s

12.5*9.8=122.5 m/s

A model of Earth’s water budget shows that the precipitation on oceans is 420,000 km3 and the precipitation on land is 130,000 km3. If the evaporation from land is 90,000 km3, how much is the evaporation from oceans?

Answers

Answer:

Evaporation from oceans = 460,000 km³

Explanation:

Given:

Precipitation on oceans = 420,000 km³

Precipitation on land = 130,000 km³

Evaporation from land = 90,000 km³

Find:

Evaporation from oceans

Computation:

Evaporation from oceans = Precipitation on oceans + Precipitation on land - Evaporation from land

Evaporation from oceans = 420,000 km³ + 130,000 km³ - 90,000 km³

Evaporation from oceans = 460,000 km³

Answer:ccccccC

Explanation:okay

A car is traveling at 60 mph. If the rate of speed increases 4 mph each hour,
how long will it be before the car is traveling at a rate of 80 mph?
A) 4 hours
B) 5 hours
C) 6 hours
D 7 hours​

Answers

Answer:

5 hours ................

Answer:

B=5 hrs

explanation:

becoz if you add 4 mph/hr

it will graually be 80 in 5 hrs

At noon on a clear day, sunlight reaches the earth's surface at Madison, Wisconsin, with an average intensity of approximately 2.00 kJ·s−1·m^−2. If the sunlight consists of photons with an average wavelength of 510.0 nm, how many photons strike a 5.20 cm^2 area per second?

Answers

Answer:

The number of photons per second that strike the given area is 2.668 x 10⁸ photons/second

Explanation:

Given;

intensity of the sunlight, I = 2.00 kJ·s−1·m^−2

area of incident, A = 5.2 cm² = 5.2 x 10⁻⁴ m²

Energy of incident photons per second on the given area;

E = IA

E = (2000)( 5.2 x 10⁻⁴)

E = 1.04 J/s

Energy of a photon is given is by;

[tex]E = \frac{hc}{\lambda} \\\\E = \frac{(6.626*10^{-34})(3*10^8)}{(510*10^{-9})}\\\\E = 3.898*10^{-19} \ J/photon[/tex]

The number of photons per second that strike the given area is;

[tex]n = \frac{1.04 \ J/s}{3.898*10^{-19} \ J/photon} \\\\n = 2.668*10^{18} \ photons/second[/tex]

Therefore, the number of photons per second that strike the given area is 2.668 x 10⁸ photons/second

A block slides down an inclined plane. Which force does zero work?

a. normal force
b. friction
c. the weight
d. all of the above
e. none of the above

Answers

Answer:

e

Explanation:

cause you have any attachments are not sure if you can get it

When a block slides down an inclined plane, normal force does zero work. Hence, option (a) is correct.

What is force?

The definition of force in physics is: The push or pull on a massed object changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. A spring balance can be used to calculate the Force. The Newton is the SI unit of force.

The component of a contact force in mechanics known as the normal force is perpendicular to the surface that an item encounters.

As normal force always acts perpendicular to the motion, this force does zero work.

But friction force the weight acts in opposite direction of the motion, this force does work against the motion.

In an inclined plane, the parallel component of  weight does work along the motion.

Learn more about normal force here:

https://brainly.com/question/18799790

#SPJ2

Two objects attract each other with a gravitational force of magnitude 1.01 10-8 N when separated by 19.9 cm. If the total mass of the two objects is 5.11 kg, what is the mass of each?

Answers

Answer:

m₂ = 1.17 kg

Explanation:

Given that,

Force between two objects, [tex]F=1.01\times 10^{-8}\ N[/tex]

Mass of object 1, [tex]m_1=5.11\ kg[/tex]

Distance between masses, r = 19.9 cm = 0.199 m

The gravitational force between two masses is given by :

[tex]F=\dfrac{Gm_1m_2}{r^2}[/tex]

m₂ is the mass of object 2

[tex]m_2=\dfrac{Fr^2}{Gm_1}\\\\m_2=\dfrac{1.01\times 10^{-8}\times (0.199)^2}{6.67\times 10^{-11}\times 5.11}\\\\=1.17\ kg[/tex]

So, the mass of second object is 1.17 kg.

_______mirrors or lenses always produce smaller images.​

Answers

Answer:

The images produced by a convex mirror are smaller than the object it reflects. The image produced by a concave lens is always virtual. The image in a convex mirror is always upright and is smaller than the object.

Explanation:

:)

I went for a walk one day. I walked north 6.0 km at 6.0 km/h and then west 10 km at 5.0 km/hr.
Determine the total distance of the entire trip

Answers

Answer:

The total distance of the entire trip is 16 Km

Explanation:

Distance and Displacement

A moving object constantly travels for some distance at certain periods of time. The total distance is the sum of each individual distance the object traveled. It can be written as:

dtotal = d1 + d2 + d3 + ... + dn

This sum is obtained independently of the direction the object moves.

The displacement only takes into consideration the initial and final positions of the path defined by the object in its moving. The displacement, unlike distance, is a vectorial magnitude and can be even zero if the object starts and ends the movement at the same point.

The described movements are 6 Km North and 10 Km West. Regardless of the speed or time taken, the total distance is:

d = 6 Km + 10 Km = 16 Km

The total distance of the entire trip is 16 Km

. A crane does 62,500 joules of work to lift a boulder a distance of 25.0 meters. How much did the boulder
weigh? (Hint: The weight of an object is considered to be a force in units of newtons.)
13

Answers

Answer:

2500 N

Explanation:

The weight of the object can be found by using the formula

[tex]f = \frac{w}{d} \\ [/tex]

w is the workdone

d is the distance

From the question we have

[tex]f = \frac{62500}{25} \\ [/tex]

We have the final answer as

2500 N

Hope this helps you

Consider a block sliding down a ramp whose motion is opposed by frictional forces. The total energy of this system is modeled by the equation:
Etotal = 1/2mv^2 + mgh + Ff(f is underscore)d

Which part of the equation represents the amount of energy converted to thermal energy?

A. mg
B. Ffd
C. mgh
D. 1/2 mv^2

Answers

b because it’s the most expla

Answer:

Do you have the answers for the unit 6 test?

Explanation:

PLZ

Bob rides his bike with a constant speed of 10 miles per hour. How long will he take to travel a distance of 15 miles?

Answers

[tex]{\underline{\pink{\textsf{\textbf{ Answer : }}}}}[/tex]

➡ 150hrs.

[tex]{\underline{\pink{\textsf{\textbf{Explanation : }}}}}[/tex]

➡ Time = distance × speed

➡ Time = 15*10

➡ Time = 150hrs ans.

PRACTICE
z
1.
What happens to the force of gravity between two objects if the distance between them is doubled?

Answers

Answer:

If the mass of one of the objects is doubled, then the force of gravity between them is doubled. ... Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces

Explanation:

^^^^yea. What he said lol

How do the magnetic fields of Uranus and Neptune suggest that the mantles inside those planets are fluid?

Answers

Answer:

The surface must be a good absorber of light. Spectra of the planets proved that methane in the atmospheres of these planets is what absorbs red light.

Explanation:

5.

State the number of significant digits in each measurement and

express the value in scientific notation.

a. 110 m

f. 20.40 m/s

b. 0.2°C

g0.71 ns

c. 0.090 11 kg

h. 0.06 kg

d. 52.5 X 10 - 3

7040 m

600.0 N

וורן

e.

Answers

Answer:

Tanong mo po sa guro mo welcome pasensya need ko po ng point

why is a mountain ? what is a animal ? what is love ?

Answers

Answer:

When we love someone we experience the same positive thoughts and experiences as when we like a person. But we also experience a deep sense of care and commitment towards that person. Being “in love” includes all the above but also involves feelings of sexual arousal and attraction.

Explanation:

answer? physics Q for 3rd secondary..

Answers

Answer:

The 300 Ohm resistor

Explanation:

They are in series, so the current has to be the same in both.  P = I^2R, so with the same current, the larger resistor dissipates more power.

What did Isaac Newton’s investigation if the gravity explain ?

Answers

Answer:

Gravity acts on all objects in the universe.

Explanation:

The angle of incidence is the angle between the the normal of the surface. and A. point of incidence B. reflected ray C. incident ray D. refracted ray​

Answers

Answer: c. incident ray

Explanation:

A 12-V battery is connected across a 100-Ω resistor. How many electrons flow through the wire in 1.0 min?

Answers

Answer:

The quantity of charge or electron flowing the wire in the given time is 4.5 x 10¹⁹ electrons.

Explanation:

Given;

emf of the battery, V = 12 V

resistance of the resistor, R = 100-Ω

time of current flow, t = 1 min

charge of 1 electron = 1.602 x 10¹⁹ C

The current through this circuit is given by;

I = V / R

I = (12) / (100)

I = 0.12 A

The quantity of charge or electron flowing the wire in the given time is calculated as;

Q =It

where;

I is the current flowing through the wire

t is the time of current flow = 1 x 60s = 60 s

Q = 0.12 x 60

Q = 7.2 C

1.602 x 10⁻¹⁹ C --------------- 1 electron

7.2 C -----------------------------? electron

[tex]= \frac{7.2 }{1.602*10^{-19}} \\\\= 4.5*10^{19} \ electrons[/tex]

Therefore, the quantity of charge or electron flowing the wire in the given time is 4.5 x 10¹⁹ electrons.

A person stands at the deep end of a swimming pool and looks at his dive mask which is at the bottom of the pool at a depth of 3.19 m. The index of refraction for water is 1.33. At what depth does the person see his dive mask (apparent depth in meters)? Your answer should be a number with three decimal places, do not include the unit.

Answers

Answer:

2.398

Explanation:

In order to solve this problem we are required to use the following information and the question expects us to give depth at which theask is seen.

Dn = D x nobservation/n object

This is the formula for apparent depth

Depth = 3.19

The index of refraction for water is 1.33

3.19x1/1.33

= 3.19/1.33

= 2.398m

the person see his dive mask at

2.398m (apparent depth in meters

A large beaker of water is filled to its rim with water. A block of wood is then carefully lowered into the beaker until the block is floating. In this process, some water is pushed over the edge and collects in a tray. The weight of the water in the tray is:______

a. Greater than the weight of the block.
b. Less than the weight of the block.
c. Equal to the weight of the block.

Answers

Answer:

c. Equal to the weight of the block.

Explanation:

We know that when an object floats , the displaced water by the floating body

has weight equal to the weight of the body . In this condition the upthrust becomes equal to the weight of the body .

In the present case the beaker is full to the brim with water . Then the body was made to float into it . While attaining equilibrium in water , it displaces water whose weight must have been equal to its weight . That liquid got spilled over the edge and collected on the tray .

So water collected on the tray must be equal to the weight of the body floating.

A 4.0 kg mess kit sliding on a frictionless surface explodes into two 2.0 kg parts: 3.0 m/s, due north, and 5.0 m/s, 30° north of east.What is the original speed of the mess kit?

Answers

Answer:

3.49m/s

Explanation:

We have mess of kit = 4kg

Then pieces are 2kg

3m/s due north

5m/s, 30⁰ due south

MiVi = m1v1 + m2v2

We break velocities to have x and y components

MiVi = m1v1(cosθ+sin θ1j) + m2v2(v2cos θ2i+sin2 θj)

θ1 = 90⁰north

θ2 = 30⁰ north east

Vi = 2/4x3m/s(cos90i + sin90j)+2/4x5m/s(cos30i + sin30j)

= 2.16i + 2.75j

Vi = √Vx²+Vy²

Vi = √ (2.16)²+(2.75)²

Vi = 3.49m/s

This is the original speed of the kit

A ball is kicked off the ground reaching a maximum height of 60m and lands 80m away. Calculate the initial speed and the angle above the horizontal of the ball when it was kicked​

Answers

Answer:

36.87°

Explanation:

Given

Maximum height = 60m

Horizontal distance (range) = 80,m

Required

Initial speed U

Angle of launch

To get the speed, we will use the range formula;

R = U √2H/g

80 = U√2(60)/9.8

80 = U√12.25

80 = 3.5U

U = 80/3.5

U = 22.86m/s

Get the angle of launch

Using the formula

Theta = tan^-1(y/x)

y is the vertical distance

x is the horizontal distance

Theta = tan^-1(60/80)

Theta = tan^-1(0.75)

Theta = 36.87°

Hence the angle of launch is 36.87°

A relaxed spring of length 0.15 m stands vertically on the floor; its stiffness is 1070 N/m. You release a block of mass 0.5 kg from rest, with the bottom of the block 0.6 m above the floor and straight above the spring. How long is the spring when the block comes momentarily to rest on the compressed spring?

Answers

Answer:

x' = 0.085 m = 8.5 cm

Explanation:

The law of conservation of energy says that:

Potential Energy Stored in Spring = Loss in Gravitational Potential Energy of Block

(1/2)kΔx² = mgh

where,

k = stiffness of spring = 1070 N/m

Δx = change in length of spring = ?

m = mass of block = 0.5 kg

g = 9.8 m/s²

h = height of block above spring = 0.6 m - 0.15 m = 0.45 m

Therefore,

(1/2)(1070 N/m)Δx² = (0.5 kg)(9.8 m/s²)(0.45 m)

Δx = √[2(2.205 Nm)/(1070 N/m)]

Δx = 0.064 m

but,

Δx = x - x' = 0.15 m - x' = 0.064 m

x' = 0.15 m - 0.064 m

x' = 0.085 m = 8.5 cm

A man walks south at a speed of 2.00 m/s for 60.0 minutes. He then turns around and walks north a distance 3000 m in 25.0 minutes. What is the average velocity of the man during his entire motion?

Answers

Answer:

v = 0.823 m/s

Explanation:

A man walks south at a speed of 2.00 m/s for 60.0 minutes.

The distance covered in South = 60 × 60 × 2 = 7200 m

He then turns around and walks north a distance 3000 m in 25.0 minutes.

As they moved in opposite direction, net displacement will be : 7200 - 3000 = 4200 m

Average velocity of the man = net displacement/time

[tex]v=\dfrac{4200\ m}{(60+25)\times 60}\\\\=0.823\ m/s[/tex]

So, the average velocity of the man is 0.823 m/s.

Which city did King David make the royal capital of the Kingdom of Israel?
Canaan
Jerusalem
Philistine
Cairo

Answers

Answer:

Jerusalem

Explanation:

because now a days jerusalem is the royal capital of the kingdom of israel so i conclude that the answer is jerusalem

How much work would be done on a particle with 5.0 C of charge on it if it moved from an equipotential line at 5.5 volts to another equipotential line at 3.5 volts?

Answers

Answer:

10J

Explanation:

In this question we have the following information

The charge of the particle is q = 5 C

The equipotenetial level is V1 = 5.5 v

and also the

equipotenetial level is V2 = 3.5 v

So we calculate the

work done W=q x (v1-v2)

workdone = 5 x (5.5-3.5)

= 5x2

=10 J

Workdone = 10 J

So we conclude that the workdone on a particle with these information is 10j


The earliest mineral observed to showmagnetic properties is called
A leadstone
Blodestone
Cloadstone
Dnone of the above
E all of the above

Answers

Answer:

B: lodestone

Explanation:

Each magnet has its magnetic poles, north (N) and south (S). Diversified ones are attracted and reptiles of the same name are repelled, similarly to charges, so it was considered possible to separate the magnet at the north and south poles.

Magnetic properties can be lost if the magnet is exposed to high temperatures if it falls or due to some mechanical shocks.

"2.40 A pressure of 4 × 106N/m2 is applied to a body of water that initially filled a 4300 cm3 volume. Estimate its volume after the pressure is applied."

Answers

Answer:Final volume after pressure is applied=4,292cm3

Explanation:

Using the bulk modulus formulae

We have that The bulk modulus of waTer is given as  

K =-V dP/dV

Where  K, the bulk modulus of water = 2.15 x 10^9N/m^2

2.15 x 10^9N/m^2= - 4,300 x  4 × 106N/m2 / dV

dV = - 4,300 x  4 × 10^6N/m^2/ 2.15 x 10^9N/m^2

dV (change in volume)= -8.000cm^3

Final volume after pressure is applied,

V= V+ dV

V= 4300cm3 + (-8.000cm3)

=4300cm3 - 8.000cm3

Final Volume, V =4,292cm3

A stone is dropped from a bridge 45 meters above the surface of a river. What is the time required for the stone to reach the water’s surface?

Answers

Answer:

C.  3.0 s

Explanation:

Well, I've taken this question before, so I went back and this was the answer I put, which was correct.

Hope this helps! <3 May I have brainliest if it helps you enough?

It will take 3 s for the stone to get to the surface of the water.

We'll begin by listing out what was given from the question. This includes:

Height (h) = 45 m

Time (t) =?

NOTE: Acceleration due to gravity (g) is 10 m/s²

From the data above, we can obtain the time taken for the stone to get to the surface of the water as follow:

H = ½gt²

45 = ½ × 10 × t²

45 = 5 × t²

Divide both side by 5

[tex]t^{2} = \frac{45}{5} \\\\t^{2} = 9[/tex]

Take the square root of both side

[tex]t = \sqrt{9}[/tex]

t = 3 s

Therefore, it will take 3 s for the stone to get to the surface of the water.

Learn more: https://brainly.com/question/19339518

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