The 500 cubic centimeter of 0.250 M Na2SO4 solution,
added to an aqueous solution of 15.00 grams of barium
chloride, resulted in the formation of a white precipitate of
barium sulfate. How many moles and how many grams of
barium sulfate are formed, respectively?

The 500 Cubic Centimeter Of 0.250 M Na2SO4 Solution,added To An Aqueous Solution Of 15.00 Grams Of Bariumchloride,

Answers

Answer 1

Answer:

0.072 moles, 16.776g.

Explanation:

The reaction of Na2SO4 and BaCl2 occurs as follows:

Na2SO4(aq) + BaCl2(aq) → BaSO4(s) + 2NaCl(aq)

To solve this question we must find the moles of each reactant. As the reaction is 1:1, the reactant with the low number of moles is limiting reactant. The moles of limiting reactant = Moles BaSO4. The mass can be obtained with the molar mass of BaSO4 -233.38g/mol-

Moles Na2SO4:

500cm³ = 0.500L * (0.250mol / L) = 0.125 moles

Moles BaCl2 -Molar mass: 208.23g/mol-

15.00g * (1mol / 208.23g) = 0.072 moles

The moles of BaSO4 are 0.072 moles and its mass is:

0.072 moles * (233.38g / mol) = 16.8g ≈ 16.776g


Related Questions

Please choose a claim and then answer the question below please ty I would appreciate it!

Answers

Answer:

Claim 1

Explanation:

I chose this claim because I believe that when the plates under the earth move or shift, that's what causes an earthquake and when everything starts to shake. If it was the other way around there wouldn't be any reason for an earthquake to start.

hope that helped :)

Answer:

Plates move, which can cause earthquakes.

Explanation:

Tectonic plates are always slowly moving, however sometimes they can "lock" together, creating pressure and build up. The release of this energy results in a Tectonic earthquake. Therefore, the movement of plates causes earthquakes.

I am one percent away from failing. I just need help. No false answers
How many grams of Al(OH)3 are produced from 3.00 g of AlCl3 with excess of NaOH?

Answers

Answer:

I did it in steps in the picture I just hope it helps you to understand:)

What is the mass of a sample of NH3 containing 3.80 x 1024 molecules of NH3? (5 points)
74.8 grams
107 grams
89.4 grams
101 grams

Answers

Answer: 107 grams

Explanation: got it right on the test

The mass of a sample of f NH₃ containing  3.80 x 10²⁴ molecules of  NH₃ is  107.27 grams.

What is a molecule?

A molecule is a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance.

6.02214076 × 10²³  molecules constitute 1 mole of NH₃

3.80 x 10²⁴ molecules constitutes of = 6.31 moles

1 mole of NH₃ = 17 gm

11.19 mole will be = 17 X 6.31

= 107.27 grams

Therefore the mass of a sample of NH₃ containing 3.80 x 10²⁴ molecules of NH₃ is 107.27 grams.

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PLEASE HELP!
The specific heat of octane, C8H18(l), is 2.22 J/(g⋅K).
How much heat is needed to raise the temperature of 76.0 g of octane from 10.6 ∘C to 26.0 ∘C?
Express your answer in joules to three significant figures.

Answers

Answer:

Q = 2.60 • [tex]10^{3}[/tex] J

Explanation:

Our specific heat capacity equation is:

Q = mC∆T

Q is the energy in joules.

m is the mass of the substance.

∆T is the temperature chance.

Let's plug in what we know.

We have 76.0 g of octaneThe specific heat capacity of octane is 2.22 J/(g•K)The temperature increases from 10.6º to 26.0º (a 15.4º increase)

Q = 76.0(2.22)(15.4)

Multiply.

Q = 2598.288

We want three significant figures.

Q = 2.60 • [tex]10^{3}[/tex]

or

Q = 2590 J

Hope this helps!

Answer:6,985.008

Explanation:

so the hear formula is mass times specific heat times change in temperature (kelvin) so what i did was got the change in temperature (41.4 K) and multiplied that times 2.22 J/(g•K)and multiplied that by 76 grams of Octane to get the Answer (not in scientific notation)

What is the main purpose of phloem tissue?

to carry food from the leaves to all the cells of the plant
to absorb water and minerals from the soil
to store extra food for the plant to use in the winter
to carry water and minerals from the roots to the lea

Answers

Plants have tissues to transport water, nutrients and minerals. Xylem transports water and mineral salts from the roots up to other parts of the plant, while phloem transports sucrose and amino acids between the leaves and other parts of the plant.

Alkenes are more stable than alkanes. True or False

Answers

Answer:

Yes

Explanation:

Alkenes are relatively stable compounds, but are more reactive than alkanes because of the reactivity of the carbon–carbon π-bond. Most reactions of alkenes involve additions to this π bond, forming new single bonds.

PLEASE QUICKLY. I'll give BRAINLIEST. A sample contains 25% parent isotope and 75% daughter isotopes. If the half-life of the parent isotope is 72 years, how old is the sample?

144 years old
216 years old
288 years old
360 years old

Answers

From the calculations and the principles of radioactivity, the age of the parent isotope is 144 years

What is radioactivity?

The term radioactivity has to do with the spontaneous decay of a substance.

We know that we have about 25% parent isotope still remaining hence;

[tex]0.693/t1/2 =2.303/t log No/N\\When N =0.25 No and t1/2 = 72 years\\0.693/72 =2.303/t log No/0.25No\\0.0096 = 2.303/t *0.60206\\0.0096 = 1.3865/t\\t = 1.3865/0.0096\\t =144 years[/tex]

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Answer:

A. 144 years old

Explanation:

why metal in the middle of metal activity series can't be obtained by heating ors in air​

Answers

Answer:

See Explanation

Explanation:

The way by which a metal is obtained from its ore is determined by the chemical reactivity of the metal.

Metals that are highly reactive are chiefly obtained by electrolysis of the metal salt. These metals are found high up in the metal activity series.

Metals that are at the middle of the series are moderately reactive and are obtained by electrolysis or by reduction since they still form ionic salts.

Metals that are far lower in the series can only be obtained by heating them in air because they are mostly unreactive.

Hence, moderately reactive metals at the middle of the series are not obtained by roasting in air.

Gas particles that are at low temperature and high pressure and are close to changing phases are considered:
a)Real Gases

b)Ideal Gases

c)Both Ideal and Real Gases

Answers

Answer is a ........

Balance the following equation:
Cr + __02 +_Cr203

Answers

Answer:

4Cr + __302 -->_2Cr203.....

A trophic level is a number that tells you the position an organism occupies in a food chain or food pyramid.
True
False

Answers

Answer:

true

Explanation:

The back of a water droplet acts as a mirror. When light hits the back of the water droplet, it bounces back to our eyes. This is called ____________.

Answers

The back of a water droplet acts as a mirror. When light hits the back of the water droplet, it bounces back to our eyes. This is called reflection.

A gas has an initial pressure of 120 kPa, a volume of 23 liters, and a temperature of 20°C. If the pressure is raised to 150 kPa the new volume is 17 liters, what is the new temperature of the gas? *
A.100 K
B.0.003 K
C.270.7 K
D.18.4 K

Answers

Answer: C 270.7 k is the temperature of the gas

Can someone please help, 20 points
Draw 3-ethyl-2,4-dimethyl octanoic acid

Answers

3-ethyl-2.4-dimethyl-octanoic acid

True or False
a. The cones in our eyes detect color, while the rods perceive brightness.
b. In white light, white objects absorb all the colors.
c. At night, when light is dim, our cones are not activated so objects will appear as their normal color.
P.
d. Violet has the longest wavelength which is why it gets refracted the most.
V
e. The angle of incidence always equals the angle of reflection.

Answers

true

false

true

true

false

Carbon dioxide and water are produced when pentane (C5H12) reacts with oxygen. What is the balanced equation for this reaction?

○C5H12(g) + O29) - CO2(g) + H2O(g) ○C5H12(g) + O2(g) - 5CO2(g) + H2O(g)
○C5H12(g) +802(g) - 5CO2(g) + 6H2O(g) ○5CO2(g) + 6H2009) - C5H12(g) + 802(g)
○C5H12(g) +502(g) - 5CO2(g) + 6H2(g)
○CH2(g) +O2(g) + CO2(g) + H2(g) ​

Answers

Answer:

C

Explanation:

C5H12(g) +802(g) - 5CO2(g) + 6H2O(g)

The balanced chemical equation of pentane (C5H12) which reacts with oxygen is

C5H12(g) +802(g) - 5CO2(g) + 6H2O(g)

What is balanced chemical equation?

It is the chemical equation in which the atom or molecules or moles of elements on both side reactant and product.

Our reactants are pentane and oxygen. Since, fourth and sixth reaction do not contain pentane. Therefore, fourth and sixth reaction are wrong.

Now, our next step is to compare product.

As we know that, Carbon dioxide and water are produced when pentane (C5H12) reacts with oxygen. So, we get to the conclusion that carbon dioxide and water are the product.

Since, rest of the equation have carbon dioxide and water as product.

On reactant side, there are 5 carbon atoms and 12 hydrogen atom. So, on product side there must be 5 carbon atoms and 12 hydrogen atom. Now we balance the oxygen atom on both side.

Thus, we concluded that the balanced chemical equation of pentane (C5H12) which reacts with oxygen is

C5H12(g) +802(g) - 5CO2(g) + 6H2O(g).

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Where and why the U.S. acid rain damage is the greatest.

Answers

Answer:

Some acid rain occurs naturally, but sulfur dioxide and nitrogen oxide emissions from smokestacks combine with rain to make sulfuric and nitric acid in amounts that harm.

Explanation:

How many formula units are there in 14.50 moles of any compound?
___X 10^___formula units

Answers

Answer:

8.73 × 10²⁴ formula units

Explanation:

To calculate the number of formula units a substance contain, we multiply the number of moles by Avagadro number (6.02 × 10²³)

number of formula units = 14.50 moles × 6.02 × 10²³

= 87.29 × 10²³

= 8.73 × 10²⁴ formula units.

Teresa has taken three tests worth 100 points each. Her scores are 85, 93, and 88. She has one test left to take.

To get an average score of 90, what must the sum of all her test scores be?
a.
400
c.
600
b.
360
d.
300

Answers

Answer:

SOrry it makes me writer sotufjksankdn

Explanation:

What is the pH of a solution with an H3O+ concentration of 5.67 x 10-4 M?
a. 1.00
b. 3.25
C. -1.00
d. -3.25

Answers

Answer:

3.25

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log [ { H_3O}^{+}][/tex]

From the question we have

[tex]ph = - log(5.67 \times {10}^{ - 4} ) \\ = 3.2464[/tex]

We have the final answer as

3.25

Hope this helps you

Which of the following steps correctly converts 3 moles of fluorine to an equivalent number of particles of fluorine?

Group of answer choices

Divide Avogadro's number by 3.

Multiply 3 by Avogadro's number.

Multiply 3 by the atomic mass of fluorine.

Divide the atomic mass of fluorine by 3.

Answers

Answer:

B) Multiply 3 by Avogadro's number

Explanation:

This is according to Study.com

3 moles of fluorine contains  18.066✖10²³ Particles. thus, option B is correct

How many are there no. of particles in 1mole?

One mole contains  6.022✖10²³  particles.

3 moles of flourine contains 3✖6.022✖10²³  particles

Hence, option “B” is correct

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please answer cansend to me​

Answers

the answer is thank u for the points!
What? It’s too blurry try doing it again

Use the equation below:
2Na + Cl2 ==> 2NaCl
+ O
How many grams of NaCl are produced when 1.25 moles of Cl2 reacts with Na?

Answers

Explanation:

2/1×1.25

=2.5 mole of NaCl are produced

weight of NaCl produced = moles × molar mass of NaCl

weight of NaCl produced = 2.5×58.5

weight of NaCl produced =146.5 grams

I’d appreciate the help! :)

Here is the reaction:

3 NO2 (g) + H2O (l) = 2HNO3 (l) + NO (g)

Answers

Answer: 300g

Explanation:

first we write the given values on top

224L. x

3 NO2 (g) + H2O (l) = 2HNO3 (l) + NO (g)

22.4L 30g

then we form a formula

224L/22.4L= x/30g

224*30/22.4

6720/22.4= 300g

Which of the following are acid formulas? (Choose 2)
NH3
CH3OH
NaOH
HNO3
H2SO4
CH4

Answers

Answer:

HNO3 & H2SO4

Explanation:

HNO3 is Nitric acid and H2SO4 is Sulphuric acid

HELP!! Suppose that the pressure of 1.00 L of gas is 380 mm Hg when the temperature is 200. K. At what
temperature is the volume 2.00 L and the pressure 0.750 atm?

Answers

Numa máquina térmica uma parte da energia térmica fornecida ao sistema(Q1) é transformada em trabalho mecânico (τ) e o restante (Q2) é dissipado, perdido para o ambiente.



sendo:

τ: trabalho realizado (J) [Joule]
Q1: energia fornecida (J)
Q2: energia dissipada (J)


temos: τ = Q1 - Q2

O rendimento (η) é a razão do trabalho realizado pela energia fornecida:

η= τ/Q1

Exercícior resolvido:
Uma máquina térmica cíclica recebe 5000 J de calor de uma fonte quente e realiza trabalho de 3500 J. Calcule o rendimento dessa máquina térmica.

solução:

τ=3500 J
Q1=5000J

η= τ/Q1
η= 3500/5000
η= 0,7 ou seja 70%

Energia dissipada será:



τ = Q1 - Q2
Q2 = Q1- τ

Q2=5000-3500
Q2= 1500 J

Exercicio: Qual seria o rendimento se a máquina do exercicio anterior realizasse 4000J de trabalho com a mesma quantidade de calor fornecida ? Quanta energia seria dissipada agora?



obs: Entregar foto da resolução ou o cálculo passo a passo na mensagem

112 g of aluminum carbide react with 174 g water to produce methane and aluminum hydroxide in the reaction shown below.

2 Al4C3(s) + 12 H2O(l) → 3 CH4(g) + 4 Al(OH)3(s)

If aluminum carbide is the limiting reactant, how many moles of the excess reactant are left over
a
37.3 mol
b
4.68 mol
c
7.33 mol
d
131.94 mol

Answers

Answer: 4.999 moles of excess reactant will be left over.

Explanation:

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]       .....(1)

Given mass of aluminium carbide = 112 g

Molar mass of aluminium carbide = 143.96 g/mol

Putting values in equation 1:

[tex]\text{Moles of aluminium carbide}=\frac{112g}{143.96g/mol}=0.778mol[/tex]

For the given chemical reaction:

[tex]2Al_4C_3(s)+12H_2O(l)\rightarrow 3CH_4(g)+4Al(OH)_3(s)[/tex]

By the stoichiometry of the reaction:

2 moles of aluminium carbide reacts with 12 moles of water

So, 0.778 moles of aluminium carbide will react with = [tex]\frac{12}{2}\times 0.778=4.668 mol[/tex] of water

Given mass of water = 174 g

Molar mass of water = 18 g/mol

Putting values in equation 1:

[tex]\text{Moles of water}=\frac{174g}{18g/mol}=9.667mol[/tex]

Moles of excess reactant (water) left = 9.667 - 4.668 = 4.999 moles

Hence, 4.999 moles of excess reactant will be left over.

Choose the options below that are true of standard reduction potential. (select all that apply) Select all that apply: All standard reduction potentials are measured against that of the reduction of hydrogen ions to H2 gas. The standard reduction potential of a cell is determined by subtracting the standard reduction for the reaction at the anode from the standard reduction potential for the reaction at the cathode. Standard reduction potentials are dependent on reaction stoichiometry. The standard reduction potential for a cell is determined by adding the standard reduction potential for the reaction at the anode to the standard reduction potential for the reaction at the cathode.

Answers

Answer:

All standard reduction potentials are measured against that of the reduction of hydrogen ions to H2 gas.

Explanation:

The standard hydrogen electrode (SHE) serves as a sort of reference electrode. All standard electrode potentials of chemical systems are measured against the standard hydrogen electrode whose electrode potential has been arbitrarily set at 0.00 V.

The reduction potential of any other system is measured against the standard hydrogen electrode by connecting that half cell to the standard hydrogen electrode and observing the reading of the voltmeter. The standard hydrogen electrode consists of hydrogen ions of unit activity, hydrogen gas at 1 atm and the system is maintained at a temperature of 298 K.

Standard reduction potentials are measured against that of the reduction of hydrogen ions to [tex]H_2[/tex] gas because hydrogen is chosen as a standard reference and has electrode potential zero.

It is impossible to measure absolute electrode potential for an electrode without forming cell . Therefore it is assumed that standard electrode potential for hydrogen is zero

The standard reduction potential of a cell is determined by subtracting the standard reduction for the reaction at the anode from the standard reduction potential for the reaction at the cathode.

                        [tex]E_c_e_l_l[/tex]°[tex]= E_c_a_t_h_o_d_e[/tex]°[tex]- E_a_n_o_d_e[/tex]°

The species liking to get reduced is defined in term of standard reduction potential.

The species whose standard reduction potential is to be calculated is placed at cathode and at anode hydrogen electrode is used.

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how many grams of caco3 are needed to react with 15.2g of hcl​

Answers

Answer:

Balanced equation:

CaCO3 (s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)

1mol CaCO3 will react with 2 mol HCl

Mol HCl in 32.8mL of 1.25M solution = 32.8mL / 1000mL/L * 1.25mol /L = 0.041 mol HCl

This will react with 0.041/2 = 0.0205 mol CaCO3

Molar mass CaCO3 = 100g/mol

Mass of CaCO3 reacted = 0.0205mol *100g/mol = 2.05g CaCO3.

Grams are the unit of weight or mass that depicts the quantity of a substance. The mass of calcium carbonate reacted is 2.05 gm.

What is mass?

Mass is the product of the moles of the compound and its molar mass, it is given in grams.

The balanced chemical reaction is given as:

[tex]\rm CaCO_{3} (s) + 2HCl(aq) \rightarrow CaCl_{2}(aq) + CO_{2}(g) + H_{2}O(l)[/tex]

From the reaction, 1 mole of calcium carbonate reacts with 2 moles of hydrochloric acid.

Moles of hydrochloric acid is calculated as:

[tex]\begin{aligned} \rm n &= \rm Molarity \times Volume (L)\\\\&= 0.0328 \times 1.25\\\\&= 0.041\;\rm mol\end{aligned}[/tex]

Now, the moles of calcium carbonate it will react with will be 0.0205 moles.

Mass of calcium carbonate is calculated as:

[tex]\begin{aligned} \rm mass &= \rm molar\; mass \times moles\\\\&= 0.0205 \times 100\\\\&= 2.05 \; \rm g\end{aligned}[/tex]

Therefore, 2.05 gm of calcium carbonate is needed to react with 15.2 gm of hydrochloric acid.

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How many moles of aluminum sulfide will be produced if 12 moles of Sg react?

Answers

Answer:

Molar mass = [9(12.0)+8(1.01)+4(16.0)] = 180.1 g/mol Moles = 112 g 1 mol x 180.1 g = 0.622 mol (3 sig figs)

Explanation:

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please help fast, thanks ! Plss help i need helpThe diagram below shows undisturbed fossils in sedimentary rocks in two different locations. (2 points) The picture shows two layers of rocks. In location 1, the top layer has fossils of leaves, the middle layer has fossils of fish, and the bottom layer has fossils of sea shells. In location 2, the top layer has fossils of sea shells; the middle layer has fossils of fish, and the bottom layer has fossils of leaves.Which of these conclusions is most likely correct about the locations?A. Both the locations have dense forests.B. Both the locations are submerged under water.C. Location 1 is a forest at present and Location 2 was a forest in the past.D. Location 2 is a forest at present and Location 1 was a forest in the past. Which defense mechanism is known as "motivated forgetting"?A. projectionB. repressionC. denialD. rationalization Someone please help- what dose 2 + 2 = ????????? 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Treat each question independent of the other questions - so your answer to question 46 should not be influenced by theanswer to question 45, and so on:Preferred Stock - 6% cumulative, $20 par value, 10,000 shares authorized, 5,000 shares issued and outstanding . . $100,000Contributed Capital in excess of par value, Preferred Stock . . 250,000Common Stock, $5 par value, 20,000 shares authorized, 10,000 shares issued and outstanding. . . . . . . . . . 50,000Contributed Capital in excess of par value, Common Stock . .450,000Total Contributed Capital . . . . . . . . . . . . $ 850,000Retained Earnings . . . . . . . . . . . . . . . . . 150,000Total Stockholders' Equity . . . . . . . . . . . .$ 1,000,00045. The average issue price per share of preferred stock must have been:A) $20.00B) $50.00C) $70.00D) $35.00E) $45.0046. Marcy Company did not pay any dividends in 2004. In 2005, they declared and paid total dividends of $4,000, and in 2006, they declared total dividends of $20,000. 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