Answer:
The decay takes 6min
Explanation:
The decay of an isotope as Thallium-208 follows the equation:
ln[A] = -kt + ln[A]₀
Where [A] is amount of isotope after time t
k is decay constant = ln 2 / t(1/2)
[A]₀ is initial amount of the isotope
Replacing:
[A] = 15.0g
k = ln 2 / t(1/2) = ln 2 / 3min = 0.23105 min⁻¹
t = ?
[A]₀ = 60.0g
ln[A] = -kt + ln[A]₀
ln[15.0g] = -0.23105 min⁻¹*t + ln[60.0g]
-1.38629 = -0.23105 min⁻¹*t
6min = t
The decay takes 6min
How did we discover the Milky Way is a spiral galaxy?
For the reaction: 2H2 + O2 → 2H2O, how many grams of water are produced from
6.00 moles of H2?
Answer:
108 g
Explanation:
2H₂ + O₂ → 2H₂OFirst we convert 6.00 moles of H₂ into moles of H₂O, using the stoichiometric coefficients of the reaction:
6.00 mol H₂ * [tex]\frac{2molH_2O}{2molH_2}[/tex] = 6.00 mol H₂OThen we can convert 6.00 moles of H₂O into grams, using the molar mass of water:
6.00 mol H₂O * 18 g/mol = 108 gThe answer is 108 grams of water.
Use Hess’s Law to calculate the heat of reaction for the following reaction:
2H2O2 → 2H2O +O2 ∆H=?
2H2 +O2 → 2H2O ∆H=-572 KJ
2H2O2 → 2H2 + 2O2 ∆H=376 KJ
The heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ
Calculating heat of reaction using Hess's lawFrom the question, we are to calculate the heat of reaction for the reaction
2H₂O₂ → 2H₂O +O₂ ∆H=?
Using Hess's law
Hess's Law of constant heat summation states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes
From the given equations,
2H₂ +O₂ → 2H₂O ∆H= -572 KJ ---------- (1)
2H₂O₂ → 2H₂ + 2O₂ ∆H= 376 KJ ----------- (2)
Adding equations (1) and (2), we get
2H₂O₂ → 2H₂O +O₂ ∆H= -572 KJ + 376 KJ
2H₂O₂ → 2H₂O +O₂ ∆H= -196 KJ
Hence, the heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ.
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1) A container holds 5,000 mL of CO2 at 742 atm. What will be the volume of the CO2 if the pressure is increased to 795 atm?
Answer:
[tex]V_2=4667mL[/tex]
Explanation:
Hello there!
In this case, based on the given information, it is possible for us to provide an answer to this question by using the Boyle's law as directly proportional relationship between volume and pressure:
[tex]P_2V_2=P_1V_1[/tex]
Thus, by solving for the final volume, V2, as required, we obtain the following:
[tex]V_2=\frac{P_1V_1}{P_2} \\\\V_2=\frac{5,000mL*742atm}{795atm}\\\\V_2=4667mL[/tex]
Regards!
C5H12 + 8O2 —> 5CO2 +6 2O
Balance it
Answer:
it is already balanced
c5h12+8O2-->5CO2 +6h2o
Explanation:
Use the amount (mol) of solute and amount (mol) of solvent to calculate the mole fraction. An aqueous solution of ethanol, CH3CH2OH, has a concentration of 0.216 mol/L and has a density of 0.996 g/mL. What are the mass percent and mole fraction of CH3CH2OH in this solution
Answer:
%m/m = 0.9975%
Xₐ = 0.0039
Explanation:
In order to do this, we need various data. First to all, we need tje molecular mass of the ethanol. this can be obtained in handbooks, or simply taking the atomic weights of carbon (12 g/mol), Hydrogen (1 g/mol) and oxygen (16 g/mol) and summing those values:
MM C₂H₆O = (2*12) + (6*1) + (16*1) = 46 g/mol
Now, there is an expression that is commonly used to determine the molarity of a solution given the mass percent and density, and assuming of course, 1 liter of solution:
M = d * %m/m * 1000 / MM * 100 (1)
From here, we can solve for %m/m:
%m/m = M * MM * 100 / d * 1000
As the problem is not saying the volume of solution, we can easily assume we have 1 liter of solution. Therefore, the %m/m replacing the given data is:
%m/m = 0.216 *46 * 100 / 0.996 * 1000
%m/m = 0.9975%To get the mole fraction, we first need to get the volume of solvent. From the density, we can get the mass of solution:
m = V * d
m = 1000 * 0.996 = 996 g of solution.
The mass of solute is:
m = 0.216 mol/L * 46 g/mol
m = 9.936 g/L, or simply we have 9.936 g of ethanol in 1 L of solution.
The mass of solvent:
solvent = 996 - 9.936 = 986.064 g
The molecular mass of water, so we can get the moles is 18 g/mol so:
moles water = 986.064 / 18 = 54.78
Finally the mole fraction:
Xₐ = 0.216 / (0.216 + 54.78)
Xₐ = 0.0039Hope this helps
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Answer:
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Explanation:
hope it is helpful to you
Decide whether below chemical reaction iis an oxidation-reduction ("redox") reaction. If the reaction is a redox reaction, write down the formula of the reducing agent and the formula of the oxidizing agent.
3O2 + 4Fe → 2Fe2O3
Answer:
Explanation:
Yes , it is a redox reaction .
3O₂ + 4Fe → 2Fe₂O₃.
Increase of oxidation number shows oxidation and decrease of oxidation number shows reduction .
Neutral atoms have zero oxidation number .
O₂ and Fe are neutral atoms so their oxidation number is zero.
In Fe₂O₃ , charge on each Fe atom is + 3 . So its oxidation number is + 3 . Similarly charge on each of O in this compound is - 2 . So its oxidation number is -2 .
Oxidation number of Fe increases from 0 to + 3 . Hence it is oxidized .
Oxidation number of O decreases from 0 to -2 . Hence it is reduced .
Fe is oxidized by O ( oxygen ) so oxygen is the oxidizing agent .
O is reduced by Fe ( iron ) so iron is the reducing agent .
The pressure inside your
bike tire is 12.2 psi. What is this pressure if expressed in
millimeters of mercury (mm Hg)? (14.7 psi = 1 atm = 760mmHg)
Answer: The pressure 12.2 psi is expressed in millimeters of mercury (mm Hg) as 630.9221 mm Hg.
Explanation:
Given: Pressure = 12.2 psi
According to the standard conversion of units, 14.7 psi = 1 atm = 760mmHg.
Therefore, 1 psi equal to how many mm Hg is calculated as follows.
[tex]14.7 psi = 760 mm Hg\\1 psi = \frac{760}{14.7} mm Hg\\= 51.7149 mm Hg[/tex]
Hence, 12.2 psi will be converted into mm Hg as follows.
[tex]1 psi = 51.7149 mm Hg\\12.2 psi = 12.2 psi \times \frac{51.7149 mm Hg}{1 psi}\\= 630.9221 mm Hg[/tex]
Thus, we can conclude that the pressure 12.2 psi is expressed in millimeters of mercury (mm Hg) as 630.9221 mm Hg.
Which of the following is most accurate regarding the water cycle
Answer:
Is this question multiple choice if it is i can most likely answer it!
Explanation:
opinion on the usage of identification of amine in daily life (medical, agriculture,etc)
Answer:
The usage is explained below
Explanation:
Amines are identified from the use of the hinsberg reaction whereby the amine is mixed well with Hinsberg reagent and done in the presence of an aqueous alkali. In this reaction, the amine will attack the electrophile which will result in the chloride being displaced and the amides being generated.
The uses of identification of amines in daily life are;
- In agriculture, it serves as a good source of making herbicides as well as acting as emulsifiers.
- In medicine, it is used in the manufacture of some popular pain killers like demerol and morphine.
- In medicine, it is used in the manufacture of an anesthetic drug known as novocaine.
- In chemical industries, amines are used as lubricating oils and also as corrosion inhibitors in boilers.
N2O3 → N2 + O2
Name the reactants in this reaction.
Name the products in this reaction.
[tex]\text{N}_{2}\text{O}_{3}=\text{nitrogen trioxide}\\\text{N}_{2}=\text{nitrogen}\\\text{O}_{2}=\text{oxygen}[/tex]
For a solution, [OH-] = 4 x 10-11M.
What is the pOH?
What is the pH?
Answer:
answer is what is the pH number is that Our New account last name is Our brothers name he will be happy to
The pOH of the solution is 10.4
The pH of the solution is 3.6
Calculating pOH & pHFrom the question, we are to determine the pOH and pH of the solution
pOH can be calculated by using the formula
pOH = -log[OH⁻]
From the question,
[OH⁻] = 4×10⁻¹¹ M
∴ pOH = -log(4×10⁻¹¹)
pOH = 10.4
Hence, the pOH of the solution is 10.4
Now, for the pH
Using the formula,
pH + pOH = 14
Then, we can write that
pH = 14 - pOH
∴ pH of the solution is
pH = 14 - 10.4
pH = 3.6
Hence, the pH of the solution is 3.6
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Give all possible, accurate, correct IUPAC names for the following compounds:
Answer:
A. 4-ethyl-hex-3,5-dien-2-ol.
B. 2-chloro-3-methyl-5-tert-butylphenol.
Explanation:
Hello there!
In this case, according to the given problems, it is possible to apply the IUPAC rules to obtain the following names:
A. 4-ethyl-hex-3,5-dien-2-ol because we have an ethyl radical at the fourth carbon and the beginning of the parent chain is on the Me (CH3) because it is closest to first OH.
B. 2-chloro-3-methyl-5-tert-butylphenol: because we start at the alcohol and have a chlorine atom on the second carbon, a methyl radical on the third carbon, a tert-butyl on the fifth carbon and the parent chain is benzene which is phenol as an alcohol.
Regards!
4. Balance the following equation. Then determine the number of mols of Nitrogen formed given the values in a,b and c.
NH3 + O2 → N2 + H2O
a. 4 mol NH3
b. 4 mol N2
c. 4.5 mol O2
Answer:
4NH3 + 3O2 → 2N2 + 6H2O
a. 2 moles
b. 4 moles
c. 3 moles
Explanation:
a. 4 mol NH3
4NH3 + 3O2 → 2N2 + 6H2O
4 : 3 : 2 : 6
4 (mol)
⇒[tex]n_{N2}[/tex] = 4 × 2 ÷ 4 = 2
b. 4 mol N2
c. 4.5 mol O2
4NH3 + 3O2 → 2N2 + 6H2O
4 : 3 : 2 : 6
4.5 (mol)
⇒[tex]n_{N2}[/tex] = 4.5 × 2 ÷ 3 = 3
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How many grams of product might form for the following reaction if 33.8 L of Oxygen gas is used in the following reaction? LiCl + O2 -> LiClO3
Answer:
91.41 g of LiClO₃.
Explanation:
We'll begin by calculating the number of mole of O₂ that occupied 33.8 L. This can be obtained as follow:
22.4 L = 1 mole of O₂
Therefore,
33.8 L = 33.8 L × 1 mole / 22.4 L
33.8 L = 1.51 mole of O₂
Next, the balanced equation for the reaction.
2LiCl + 3O₂ —> 2LiClO₃
From the balanced equation above,
3 moles of O₂ reacted to produce 2 moles of LiClO₃.
Therefore, 1.51 mole of O₂ will react to produce = (1.51 × 2)/3 = 1.01 mole of LiClO₃.
Finally, we shall determine the mass of 1.01 mole of LiClO₃. This can be obtained as follow:
Mole of LiClO₃ = 1.01 mole
Molar mass of LiClO₃ = 7 + 35.5 + (3×16)
= 7 + 35.5 + 48
= 90.5 g/mol
Mass of LiClO₃ =?
Mass = mole × molar mass
Mass of LiClO₃ = 1.01 × 90.5
Mass of LiClO₃ = 91.41 g
Thus, 91.41 g of LiClO₃ were obtained from the reaction.
An atom or ion has 16 protons, 15 neutrons, and 17 electrons. Is it positive, negative, or
neutral? Why? What element is it?
I really need help on this so can someone tell me the answer please!
Which two come together to form an ionic bond?
a. a positive cation and a ngetaive cation
b. a positive cation and a negative anion
c. a positive cation and a positive anion
d. a positive anion and a negative anion
[tex]\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}[/tex]
b. a positive cation and a negative anion
✏ Anions are negative in nature while cations are positive in nature. Together they come together by an attractive electrostatic force to form an ionic bond.
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
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There are ____ neutrons, ___ protons, and ____ electrons in 238U+5
Answer:
Explanation:
The atomic number of uranium (see periodic table) is 92, and the mass number of the isotope is given as 238. Therefore, it has 92 protons, 92 electrons, and 238 — 92 : 146 neutrons
Uranium has an atomic number of 92. There are 146 neutrons, 92 protons, and 92 electrons in 238U+5. The number of neutrons can vary from 141 to 146.
What is uranium ?Chemical element uranium has the atomic number 92 and the letter U. It is an actinide metal in the periodic table's silvery-gray series. There are 92 protons and 92 electrons in an atom of uranium, of which 6 are valence electrons.
Since uranium has an atomic number of 92, its atomic structure consists of 92 protons and 92 electrons. The nucleus of U-238 contains 146 neutrons, but this number can range from 141 to 146.
With 92 protons and 146 neutrons, Uranium-238 is the heaviest element in nature. The overall mass and charge of the nucleus are 238 nucleons, or +92.
Thus, Uranium has an atomic number of 92. There are 146 neutrons, 92 protons, and 92 electrons in 238U+5.
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Calculate the molarity of a solution that contains 5 mol of Li2O in 2.35 L of solution.
Answer:
2.13 M
Explanation:
To solve this problem we need to keep in mind the definition of molarity:
Molarity = moles / litersAs the problem gives us both the number of moles and the volume of solution, we can proceed to calculate the molarity:
Molarity = 5 mol / 2.35 LMolarity = 2.13 MThe answer is 2.13 M.
Consider the incorrectly balanced combustion equation:
2C6H6 + 602 => 12CO2 + 6H2O
Select ALL elements that are not balanced.
Carbon
Hydrogen
Oxygen
Use the standard reduction potentials located in the 'Tables' linked above to calculate the equilibrium constant for the reaction:
2H+(aq) + Cu(s) H2(g) + Cu2+(aq)
Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. You may use the OWL references to find the values you may need in this question.
Answer:
3.3 * 10^-12
Explanation:
The balanced equation of the reaction is;
2H+(aq) + Cu(s) ---------> H2(g) + Cu2+(aq)
Hence two electrons were transferred so n=2
E°cell = E°cathode - E°anode
E°cell = 0 V - 0.34 V
E°cell = - 0.34 V
Then;
E°cell = 0.0592/n log K
Substituting values;
- 0.34 = 0.0592/2 log K
- 0.34/0.0296 = log K
-11.486 = log K
K = Antilog (-11.486)
K = 3.3 * 10^-12
Matter is anything that takes up space and hasA)mass.B)color.C)length.D)length and width
Answer:
A. Mass
Explanation:
If it takes up space it has to have mass. Not everything that is matter has a color, certain length or width.
A solution has a [OH−] of 1 x 10^−11 M. What is the [H3O+] of the solution?
Explanation:
Ionic product of water, Kw
[tex]Kw = [OH {}^{ - } ][H _{3} O {}^{ + } ] \\ 1.0 \times {10}^{ - 14} = (1 \times {10}^{ - 11} )[H _{3} O {}^{ + } ] \\ [H _{3} O {}^{ + } ] = \frac{(1.0 \times {10}^{ - 14}) }{(1 \times 10 {}^{ - 11}) } \\ ][H _{3} O {}^{ + } ] = 0.001 \: M[/tex]
This element has an oxidation number of -3 and it has 16 neutrons. What element is this room made of
Answer: Element is P, phosphor
Explanation: Phosphor has oxidation number -III and it has 15 protons. So it is possible to have 16 neutrons. Other elements having oxidation number -III are N and As which can not have an isotope with 16 neutrons.
what is the valence number of HCO3-.
A saline solution has 1.9 grams of NaCI in 100 mL of solution. Calculate the molarity
Answer: Molality = concentration = 0,33 mol/l
Explanation: Concentration c = n/V and n = m/M
M = 55,44 g/mol and m = 1.9 g , V = 0.100 l
c = m/(MV)
In alkanes with three or fewer carbon atoms,
a. the chains can be straight or branched.
b. usually one but sometimes more than one molecular structure is possible.
c. structural isomers exist.
d. only one molecular structure is possible.
Answer: Only one molecular structure is possible.
How many molecules are present in 135 g of Teflon C2F4
The elemental particles like the atoms, molecules and compounds present in a given substance is called an Avogadro's number. This number is expressed as [tex]N_{A}[/tex] and is equal to [tex]6.022 \times 10^{23} \;\rm mol^{-1}[/tex].
[tex]8.06 \times 10 ^{23}[/tex] molecules are present in 135 g of Teflon [tex]\rm C_{2}F_{4}[/tex].
How to calculate the molecules?Given,
Mass of the Teflon = 135 gThe molecular weight of [tex]\rm C_{2}F_{4}[/tex] = 100.02 g/molWe have 135 g, so moles will be:
[tex]\begin{aligned}\rm Moles (n) &=\dfrac{ \rm Mass }{\;\rm Molar \;\rm mass}\\\\\rm n &= \dfrac{135 \rm g }{100.02 \rm g/mol} \\\\\rm n &= 1.34 \;\rm mole\end{aligned}[/tex]
Hence,
1 mole contains [tex]6.022140857 \times 10^{23}[/tex] (Avogadro's number)
So 1.34 moles will contain,
[tex]\begin{aligned}&=1.34 \times 6.022140857 \times 10^{23}\\\\&= 8.06 \times 10 ^{23}\;\rm molecules\end{aligned}[/tex]
Therefore, [tex]8.06 \times 10 ^{23}[/tex] molecules are present in 135 g of Teflon [tex]\rm C_{2}F_{4}[/tex].
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