Taiga’s teacher asked him to draw a polygon with vertices (–4, –5), (–5, 2), (–5, 3), (–4, 5), (2, 3), and (–3, 0) and to identify the polygon. Taiga drew the polygon below and identified it as a heptagon.
Which explains whether Taiga is correct?
Taiga is correct because the polygon has six sides.
Taiga is correct because the sides have different lengths.
Taiga is not correct because the polygon is a hexagon.
Taiga is not correct because he drew the polygon incorrectly.

Answer:

#7

#8

The difference:

#9

#10

Max is right

Answer:

I think the answer is 5 down and over to the left 3.

Step-by-step explanation:

I just counted from the point on the (4,3) and counted down until it was line up with the other point. Next, I counted from there to the other point.

Answer:

Gasoline 7%

Step-by-step explanation:

2500 * 0,07 = 175

Number * 0, percent = answer

Gasoline is the part of Shaquira's budget which is $175.

In mathematics, a value or ratio that can be expressed as a fraction of 100 is known as a percentage. To find the % of a number, divide it by its value, then multiply the result by 100. Since one percent (symbolized as 1%) is equal to one hundredth of something, 100 percent stands for everything, and 200 percent refers to twice the amount specified.

As per the given data:

Shaquira's monthly income = $2,500

Monthly Budget Utilities = 18% of income

Entertainment = 9% of income

Rent = 51% of income

Gasoline = 7% of income

Food = 15% of income

To find which part is $175 let's calculate all parts:

Monthly Budget Utilities = (18/100) × 2,500 = $450

Entertainment = 9% × 2,500 = $225

Rent = 51% × 2,500 = $1275

Gasoline = 7% × 2,500 = $175

Food = 15% × 2,500 = $375

Hence, gasoline is the part of Shaquira's budget which is $175.

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Answer:

4123

Step-by-step explanation:

A=Pert,

where A is the balance of the account, P is the principal, r is the annual interest rate (as a decimal), and t is the time (in years). We are given that P=2800, r=0.043, and t=9. Substituting the values into the formula and using a calculator to evaluate, we find

A=Pert=2800e(0.043)(9)≈4123.16

Answer:

44

Step-by-step explanation:

because 11x4 is 44...

Answer:

15y>36+9

15y>45

y>45^15

y>3

Answer:

[tex](a)\ y =0\ or\ y=4\ or\ y=6[/tex]

[tex](b) \ (-\infty,4)\ u\ (6,\infty)[/tex]

[tex](c)\ (4,6)[/tex]

Step-by-step explanation:

Given

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

Solving (a): The constants

This implies that:

[tex]\frac{dy}{dt} = 0[/tex]

So, we have:

[tex]y^4 - 10y^3 + 24y^2 = 0[/tex]

Factorize:

[tex]y^2(y^2 - 10y + 24) = 0[/tex]

Expand and Factorize the expression in bracket

[tex]y^2(y^2 - 6y - 4y + 24) = 0[/tex]

[tex]y^2(y(y - 6) - 4(y - 6)) = 0[/tex]

[tex]y^2(y - 4)(y - 6) = 0[/tex]

Split

[tex]y^2 =0\ or\ y-4=0\ or\ y-6=0[/tex]

Solve for y

[tex]y =0\ or\ y=4\ or\ y=6[/tex]

The above represents the constants

Solving (b): Increasing values

Here

[tex]\frac{dy}{dx} > 0[/tex]

Follow the same process in (a) but replace all = with >

i.e.

[tex]y^2(y - 4)(y - 6) > 0[/tex]

[tex]y >0\ or\ y>4\ or\ y>6[/tex]

Test the values of each inequality

For [tex]y > 6[/tex]; say [tex]y = 7[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 7^4 - 10*7^3 + 24*7^2[/tex]

[tex]\frac{dy}{dt} = 147[/tex]

[tex]147 > 0[/tex]

This is true for [tex]\frac{dy}{dx} > 0[/tex];  This implies that: [tex](6, \infty)[/tex]

For [tex]y > 4[/tex] Say [tex]y = 5[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 5^4 - 10*5^3 + 24*5^2[/tex]

[tex]\frac{dy}{dt} = -25[/tex]

This is false:

Say [tex]y = 3[/tex] i.e. [tex]y < 4[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 3^4 - 10*3^3 + 24*3^2[/tex]

[tex]\frac{dy}{dt} = 27[/tex]

[tex]27 > 0[/tex]

This is true for [tex]\frac{dy}{dx} > 0[/tex]. This implies that: [tex](0,4)[/tex]

For [tex]y > 0[/tex]

[tex]y > 0[/tex] implies that: [tex]y < 4[/tex]

For [tex]y < 0[/tex] say [tex]y = -1[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = (-1)^4 - 10*(-1)^3 + 24*(-1)^2[/tex]

[tex]\frac{dy}{dt} = 35[/tex]

This is true for [tex]\frac{dy}{dx} > 0[/tex]. This implies that [tex](-\infty, 0)[/tex]

We have: [tex](-\infty,0), (0,4)\ and\ (6,\infty)[/tex]

[tex](-\infty,0)\ and\ (0,4)[/tex] can be combined to give: [tex](-\infty,4)[/tex]

So, the interval is: [tex](-\infty,4)\ u\ (6,\infty)[/tex]

Solving (c): Decreasing values

Here

[tex]\frac{dy}{dx} < 0[/tex]

i.e.

[tex]y^2(y - 4)(y - 6) < 0[/tex]

[tex]y <0\ or\ y<4\ or\ y<6[/tex]

Test the values of each inequality

For [tex]y < 6[/tex]; say [tex]y = 5[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 5^4 - 10*5^3 + 24*5^2[/tex]

[tex]\frac{dy}{dt} = -25[/tex]

This is true for [tex]\frac{dy}{dx} < 0[/tex];  This implies that: [tex](\infty,6)[/tex]

For [tex]y < 4[/tex]; say [tex]y = 3[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 3^4 - 10*3^3 + 24*3^2[/tex]

[tex]\frac{dy}{dt} = 27[/tex]

This is false

Say [tex]y = 5[/tex] i.e.  [tex]y > 4[/tex]

This is the same as: [tex]y < 6[/tex]

So, we have the interval to be: [tex](4,\infty)[/tex]

For [tex]y < 0[/tex] say [tex]y = -1[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = (-1)^4 - 10*(-1)^3 + 24*(-1)^2[/tex]

[tex]\frac{dy}{dt} = 35[/tex]

This is false

Say [tex]y = 2[/tex] i.e [tex]y > 0[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 2^4 - 10*2^3 + 24*2^2[/tex]

[tex]\frac{dy}{dt} = 32[/tex]

This is also false

So, the intervals are: [tex](4,\infty)[/tex] and [tex](\infty,6)[/tex].

This can be merged as: [tex](4,6)[/tex]

Hence, the interval for [tex]\frac{dy}{dt} < 0[/tex] is [tex](4,6)[/tex]

Answer:

Step-by-step explanation:

uhhh i think so its 84 is abc but adc is missing try 48  i dont know but i try

Answer:

who knows

Step-by-step explanation:

Answer:

3,990

Step-by-step explanation:

Answer:

u = 10.88

Step-by-step explanation:

u - 6.46 = 4.42

u - 6.46 + 6.46 = 4.42 + 6.46

u = 10.88

Answer:

b. 45 N

Step-by-step explanation:

The sum of the forces exerted by the two miners = 25 + 20

                                           = 45 N

Since after applying a force of 45 N by the two miners the cart remained stationary, it implies that a resistance force of at least 45 N acts against their push. Thus, the force exerted by the road could be equal to 45 N or greater than 45 N.

Probably, if the sum of the forces applied is 46 N, the cart would move. Which depends on the value of resistance force applied by the road. Thus, the appropriate answer from the given option is B.

Since the force applied on the cart equals the resistance force exerted by the road, the cart would not move.

Step-by-step explanation:

Slope = m

y - y° = m(x - x°)

m(x - x°) = y - y°

m = (y - y°)/(x - x°)

y intercept x = 0

... and I don't know :")

Answer:60

Step-by-step explanation:

Answer:

The point of a pencil

Step-by-step explanation:

all other three mesure 90 the point of pencil is not square shape in order for it to be right angle its gotta be square shape hope this helps! may i be marked brainliest?

Answer:

3 / 5 and 6 options

Step-by-step explanation:

A quadratic function has the form

an² + bn + c ( a ≠ 0 )

From the given table

n² + 1 ← is in this form ( 3rd option )

n(n + 4)

= n² + 4n ← is in this form ( 5th option )

n(n + 6) + 2

= n² + 6n + 2 ← is in this form ( 6th option )

Answer:

m - n = 501

Step-by-step explanation:

Remark

The first thing you have to do is find the number of odd and even numbers. This is where you have to be careful because there is a danger of being out by one.

equation

l = a + (n - 1)*d

Solution even

l = 1000

a = 2

d = 2

1000 = 2 + (n - 1)*2

998/2 = (n - 1) * 2 / 2

499 =  n - 1

n = 500

Solution odd

l = 1001

a = 1

d = 2

1001 = 1 + (n - 1)*2

1000 =  (n - 1)*2

1000/2 =  (n - 1)2/2

500 =  n - 1

501 = n

Sum Even of even numbers from 1 to 1001

Givens

a = 2

n = 500

l = 1000

Equation

Sum = (a + l ) * n / 2

Solution

Sum = (2 + 1000)*500/2

Sum = 1002 * 250

Sum = 250500

Sum of Odd numbers from 1 to 1001

a = 1

l = 1001

n = 501

Equation

sum = (a + l)*n/2

sum = (1 + 1001) * 501

sum = (1002)*501 / 2

Sum =  251001

Answer

m - n = 251001 - 250500 = 501

Answer:

42,500

Step-by-step explanation:

The number which is ten times greater than 4250 is 42, 500.

A branch of mathematics known as algebra deals with symbols and the mathematical operations performed on them.

Variables are the name given to these symbols because they lack set values.

In order to determine the values, these symbols are also subjected to various addition, subtraction, multiplication, and division arithmetic operations.

Given:

The number 4,250 is ten times smaller than what number.

let the number be x.

So, x/10 = 4250

Now, make x as subject formula

x = 4250(10)

x= 42500

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Answer:

Can I see it actually?

Step-by-step explanation:

Answer:

C. (8,1)

Step-by-step explanation:

hi

f(x) = -12x²+9x

So

f'(x) =  -24x +9

if  x = 6   then  f'(6) = -24 (6) +9 = -135

Answer:

Matt=26

Brown=11

Step-by-step explanation:

Just trust me!!!

The present age of Matt given the information in the question is 26.

The present age of Brown given the information in the question is 8.

4y - 6 = x equation 1

x + y + 6 = 43 equation 2

Where:

Subsistute for x in equation 2

4y - 6 + y + 3 = 43

Combine similar terms

5y = 40

y = 8

Subsitute for y in equation 1

4(8) - 6 = x

32 - 6 = 26

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Answer:

Personification is your answer.

Hope it helps!!!

Answer:

Confidence Interval =  ( 5.6 < μ < 8.2 )

The interval shows that the mean attractiveness is Above average on a scale of 1 to 10

Step-by-step explanation:

Data Given  : 5, 8, 2, 8, 7, 6, 6, 8, 9, 9, 6, 9

a) construct a confidence interval at a 95% confidence level

confidence interval = x ± tcritical ( s / √ n ) ------ ( 1 )

n = 12

μ (mean) = ( 5+8+2+8+7+6+6+8+9+9+6+9 ) / 12  ≈ 6.92

std ( s ) = √ 1/11 *∑( xi- X )^2

= √ 1/11 *  ( 5 - 6.92)^2 + ( 8 - 6.92)^2 + ( 2 - 6.92)^2 + ( 8 - 6.92)^2 + ( 7-6.92)^2 + ( 6 - 6.92)^2 + (6 - 6.92 )^2 + ( 8 - 6.92 )^2 + ( 9 - 6.92)^2 + ( 9 - 6.92)^2 + ( 6 - 6.92 )^2 + ( 9 - 6.92 )^2

= √ 1/11 * 46.92 =  2.07

tcritical at ∝ 0.05 , df = 11  = 2.20

Back to equation 1

6.92 ± 2.2 ( 2.07 / √ 12 )

( 6.92 ± 1.31 )

Confidence Interval =  ( 5.6 < μ < 8.2 )    

Range is the output values which are the y values.

The dot is at y = 2 and the line moves upward to the right off the graph. This means the line will continue to infinity.

The range would be 2 to infinity.

(2, infinity)

The solution is (4, 125). This means that the cost of being in soccer and band for four months is the same, $125. It's where the costs of those two clubs intersect.

Step-by-step explanation:

The solution to a system of linear equations is the point where the two functions intersect. You can see from the graph that the two lines intersect at the point (4, 125)

Answer:

(4,8) is the answer.

Step-by-step explanation:

To solve by substitution, you need to isolate a variable. The bottom equation already has y isolated, so we can just plug that into the other equation:

[tex]2x=-2x+16[/tex]

Add [tex]2x[/tex] to both sides in order to get rid of the [tex]-2x[/tex] on the right side:

[tex]4x=16[/tex]

Now divide by 4 on both sides to get:

[tex]x=4[/tex]

That gives us our x. Now plug in that x into either equation. I will just choose the bottom equation:

[tex]y=2(4)\\y=8[/tex]

Therefore the solution to this problem is (4,8).

Answer:

B

Step-by-step explanation: