Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tacoma's population be in 2010?

Answer:

$3.25 for 1 pound of coleslaw

Step-by-step explanation:

i think,.

Given:

The statement is " a is the fourth root of 16".

To find:

The true statement for the given statement.

Solution:

The given statement is

a is the fourth root of 16.

Mathematically, it can be written as

[tex]a=\sqrt[4]{16}[/tex]

Taking power 4 on both sides.

[tex]a^4=(\sqrt[4]{16})^4[/tex]

[tex]a\times a\times a\times a=16[/tex]

Therefore, the correct option is A.

A true statement ,  if a is the fourth root of 16 is

a x a x a x a = 16

Important Information :

'a' is the fourth root of 16 can be written as

[tex]a=\sqrt[4]{16}[/tex]

To remove fourth root, we take exponent 4 on both sides

[tex]a=\sqrt[4]{16}\\(a)^4=(\sqrt[4]{16})^4[/tex]

Exponent 4  and fourth root will get cancelled

[tex]a^4=16\\a \cdot a\cdot a \cdot a=16[/tex]

a x a x a x a = 16

A true statement ,  if a is the fourth root of 16 is

a x a x a x a = 16

learn more about the radicals here:

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Answer:

[tex]P(X > 11) = 0.368[/tex]

[tex]P(X > 22) = 0.135[/tex]

[tex]P(X > 33) = 0.050[/tex]

[tex]x = 33[/tex]

Step-by-step explanation:

Given

[tex]E(x) = 11[/tex] --- Mean

Required (Missing from  the question)

[tex](a)\ P(X>11)[/tex]

[tex](b)\ P(X>22)[/tex]

[tex](c)\ P(X>33)[/tex]

(d) x such that [tex]P(X <x)=0.95[/tex]

In an exponential distribution:

[tex]f(x) = \lambda e^{-\lambda x}, x \ge 0[/tex] --- the pdf

[tex]F(x) = 1 - e^{-\lambda x}, x \ge 0[/tex] --- the cdf

[tex]P(X > x) = 1 - F(x)[/tex]

In the above equations:

[tex]\lambda = \frac{1}{E(x)}[/tex]

Substitute 11 for E(x)

[tex]\lambda = \frac{1}{11}[/tex]

Now, we solve (a) to (d) as follows:

Solving (a): P(X>11)

[tex]P(X > 11) = 1 - F(11)[/tex]

Substitute 11 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-\frac{1}{11}* 11})[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-\frac{11}{11}})[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-1})[/tex]

Remove bracket

[tex]P(X > 11) = 1 - 1 + e^{-1}[/tex]

[tex]P(X > 11) = e^{-1}[/tex]

[tex]P(X > 11) = 0.368[/tex]

Solving (b): P(X>22)

[tex]P(X > 22) = 1 - F(22)[/tex]

Substitute 22 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-\frac{1}{11}* 22})[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-\frac{22}{11}})[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-2})[/tex]

Remove bracket

[tex]P(X > 22) = 1 - 1 + e^{-2}[/tex]

[tex]P(X > 22) = e^{-2}[/tex]

[tex]P(X > 22) = 0.135[/tex]

Solving (c): P(X>33)

[tex]P(X > 33) = 1 - F(33)[/tex]

Substitute 33 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-\frac{1}{11}* 33})[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-\frac{33}{11}})[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-3})[/tex]

Remove bracket

[tex]P(X > 33) = 1 - 1 + e^{-3}[/tex]

[tex]P(X > 33) = e^{-3}[/tex]

[tex]P(X > 33) = 0.050[/tex]

Solving (d): x when [tex]P(X <x)=0.95[/tex]

Here, we make use of:

[tex]P(X<x) = F(x)[/tex]

Substitute [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X<x) = 1 - e^{-\lambda x}[/tex]

So, we have:

[tex]0.95 = 1 - e^{-\lambda x}[/tex]

Subtract 1 from both sides

[tex]0.95 -1= 1-1 - e^{-\lambda x}[/tex]

[tex]-0.05=- e^{-\lambda x}[/tex]

Reorder the equation

[tex]e^{-\lambda x} = 0.05[/tex]

Substitute 1/11 for [tex]\lambda[/tex]

[tex]e^{-\frac{1}{11} x} = 0.05[/tex]

Solve for x:

[tex]x = -\frac{1}{1/11}\ ln(0.05)[/tex]

[tex]x = -11\ ln(0.05)[/tex]

[tex]x = 32.9530550091[/tex]

[tex]x = 33[/tex] --- approximated

It would be B)no.

Hope This Helps!

Answer:

18.75

Step-by-step explanation:

18.75

Answer:

4

Step-by-step explanation:

subtract negative 4 by negative 8

Answer:

i think 25.09 weighs more

Step-by-step explanation: well simply 25.018 has more decimal places down therefore making it a smaller number

sorry if you get it wrong :c

Answer:

=[tex](x-1)(x+6)[/tex]

Step-by-step explanation:

Answer:

[tex]x^{2} +5x-6=(x-1)(x+6)[/tex]

Step-by-step explanation:

Answer:

Sam will be 24 and his mom U can figure that out

Step-by-step explanation:

Math

Answer:

24

Step-by-step explanation:

`12

Answer:

1,2 = 1,negative2

3,6 = 3,negative 6

-1,2 = negative 1, negative 2

-2,-2 = negative2, 2

Step-by-step explanation:

Sorry all i could do was reflect the coordinates across the x-axis.

The figure reflected along x-axis will have vertices A(1, -2), B (3, -6), C(-1, -2), and D(-2, 2).

When we reflect a figure along the x-axis the coordinate point of y changes its sign, (x, y) becomes (x, - y).

Think of holding the x-axis with two fingers and rotating it.

Given, we reflect a figure with vertices A(1,2) B (3,6), C(-1,2), and D(-2,-2)

across the x-axis.

∴ The rotated coordinate will be A(1, -2), B (3, -6), C(-1, -2), and D(-2, 2).

learn more about translation here :

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12873t456473892220-209873

Answer:

=32x−24

Step-by-step explanation:

Answer:

The speed of the jet with no wind is 240 miles per hour.

Step-by-step explanation:

The speed of the jet with no wind is equivalent to the speed of the jet relative to wind. Physically speaking, we have the following system of linear equations under the assumption that both speeds of wind and jet are constant:

In favor of wind

[tex]\frac{s}{t_{F}} = v_{W}+v_{J/W}[/tex] (1)

Against wind

[tex]-\frac{s}{t_{A}} = v_{W} -v_{J/W}[/tex] (2)

Where:

[tex]s[/tex] - Travelled distance, measured in miles.

[tex]t_{F}[/tex], [tex]t_{A}[/tex] - Time, measured in hours.

[tex]v_{W}[/tex] - Wind speed, measured in miles per hour.

[tex]v_{J/W}[/tex] - Jet speed relative to wind, measured in miles per hour.

If we know that [tex]t_{F} = 5\,h[/tex], [tex]t_{A} = 7\,h[/tex], [tex]v_{W} = 40\,\frac{mi}{h}[/tex], then the speed of the jet with no wind is:

[tex]\frac{s}{5} = 40 + v_{J/W}[/tex] (3)

[tex]-\frac{s}{7} = 40-v_{J/W}[/tex] (4)

[tex]\frac{s}{5}-40 = 40 +\frac{s}{7}[/tex]

[tex]\frac{s}{5}-\frac{s}{7} = 80[/tex]

[tex]\frac{7\cdot s - 5\cdot s}{35} = 80[/tex]

[tex]2\cdot s = 2800[/tex]

[tex]s = 1400\,mi[/tex]

From (3), we find that speed of the jet with no wind is:

[tex]v_{J/W} = \frac{s}{5}-40[/tex]

[tex]v_{J/W} = \frac{1400}{5}-40[/tex]

[tex]v_{J/W} = 240\,\frac{mi}{h}[/tex]

The speed of the jet with no wind is 240 miles per hour.

Answer:

He Had It Bronzed

Step-by-step explanation:

Hope this help pls mark as brainlest!!

Answer:

He bought 2 cans of paint

Step-by-step explanation:

If he put ⅖ in each, and ⅘ total, he would have had 2 cans

Quantity of special paint additive Ernest bought = [tex] \tt \frac{4}{5} \: of \: a \: litre [/tex]

Quantity of additive he put in each can = [tex] \tt \frac{2}{5} \: of \: a \: litre [/tex]

Number of cans of paint he bought :

[tex] =\tt \frac{4}{5} \div \frac{2}{5} [/tex]

[tex] = \tt\frac{4}{5} \times \frac{5}{2} [/tex]

[tex] = \tt\frac{4 \times 5}{5 \times 2} [/tex]

[tex] =\tt \frac{20}{10} [/tex]

[tex]\color{plum} = \tt2 \: paint \: cans[/tex]

▪︎Therefore, Ernest bought 2 paint cans.

Answer:

300 sqft

Step-by-step explanation:

30 times ten is 300 and the measure is feet squared

Answer:

9000 ft 3

Step-by-step explanation:

Answer:

[tex]\displaystyle r = \sqrt{10}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Geometry

Algebra II

Step-by-step explanation:

Step 1: Define

Center (2, -3) → x₁ = 2, y₁ = -3

Circumference point (-1, -2) → x₂ = -1, y₂ = -2

In this case, the distance d from the center to the circumference point would be the radius r of the circle.

Step 2: Find Radius r

Answer:

(f o h)(-5)=-33

Step-by-step explanation:

Let f(x) = 4x - 1, h(x) = - X-3.

(f o h)=4(-x-3)-1

(f o h)=-4x-12-1

(f o h)=-4x-13

(f o h)(-5)=-4(-(-5))-13

(f o h)(-5)=-20-13

(f o h)(-5)=-33

Answer:

9 beads are purple

Step-by-step explanation:

we know that

To find out how many  beads are purple, multiply the total beads by the fraction of the beads that are purple

so

therefore

9 beads are purple

Another way to solve the problem is convert the fraction in percentage

we have

so

If the total are 18 beads

50% is 9 beads

therefore

9 beads are purple

After plotting the above equation on the coordinate plane, we can see the graph of the function.

A parametric equation in mathematics specifies a set of numbers as functions of one or more independent variables known as parameters.

We have two parametric equations:

x = 1 – t² and

y = 2t

t = y/2  and

0 ≤ t² ≤ 5

1 ≤ 1 - t²≤ 4

1 ≤ x≤ 4

Plug the above value in x = 1 – t²

x = 1- (y/2)²

x = 1 - y²/4

4x = 4 - y²

y² = 4(1 - x)

Thus, after plotting the above equation on the coordinate plane, we can see the graph of the function.

Learn more about the parametric function here:

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Answer:

750 is the answer. Hope it helps!

Answer:

4

Step-by-step explanation:keep change flip 4/5 x 5/1 = 20/5= 4

Answer:

56

Step-by-step explanation: Use the values of a, b, and c to find the discriminant.

Answer:

[tex]\Delta =56[/tex]

Step-by-step explanation:

We are given:

[tex]y = x^2 - 8x + 2[/tex][tex]y=x^2-8x+2[/tex]

So, a = 1, b = -8, and c = 2.

The discriminant (symbolized by Δ) is given by:

[tex]\Delta =b^2-4ac[/tex]

So, our discriminant in this case will be:

[tex]\Delta=(-8)^2-4(1)(2)=64-8=56[/tex]

Since our discriminant is a positive value, our equation has two real roots.

Answer:

1742 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Single light:

Mean of 1700 hours and standard deviation of 400 hours, which means that [tex]\mu = 1700, \sigma = 400[/tex]

Sample of 64:

This means that [tex]n = 64, s = \frac{400}{\sqrt{64}} = 50[/tex]

The probability is 0.20 that the sample mean lifetime is more than how many hours?

This is the 100 - 20 = 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.84

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]0.84 = \frac{X - 1700}{50}[/tex]

[tex]X - 1700 = 50*0.84[/tex]

[tex]X = 1700 + 50*0.84[/tex]

[tex]X = 1742[/tex]