Answer:
CO2
Explanation:
There is one atom of carbon and two atoms of oxygen in carbon dioxide.
Estimate the volume of a solution of 5M NaOH that must be added to adjust the pH from 4 to 9 in 100 mL of a 100 mM solution of a phosphoric acid?
Answer:
3mL of 5M NaOH must be added to adjust the pH to 7.20
Explanation:
When NaOH is added to phosphoric acid, H₃PO₄, the reaction that occurs are:
NaOH + H₃PO₄ ⇄ NaH₂PO₄ + H₂O pKa1 = 2.15
NaOH + NaH₂PO₄ ⇄ Na₂HPO₄ + H₂O pKa2 = 7.20
NaOH + Na₂HPO₄ ⇄ Na₃PO₄ + H₂O pKa3 = 12.38
We can adjust the pH at 7.20 = pKa2 if NaH₂PO₄ = Na₂HPO₄. To make that, we must convert, as first, all H₃PO₄ to NaH₂PO₄ and the half of NaH₂PO₄ to Na₂HPO₄. To solve this question we need to find the moles of phophoric acid in the initial solution. 1.5 times these moles are the moles of NaOH that must be added to fix the pH to 7.20:
Moles H₃PO₄:
100mL = 0.100L * (0.100mol / L) = 0.0100 moles H₃PO₄
Moles NaOH:
0.0100 moles H₃PO₄ * 1.5 = 0.0150 moles NaOH
Volume NaOH:
0.0150 moles NaOH * (1L / 5moles) = 3x10⁻³L 5M NaOH are required =
3mL of 5M NaOH must be added to adjust the pH to 7.203 mL of 5 Molar NaOH is required to adjust the pH of phosphoric acid.
What is pH?It is the negative log of the concentration of Hydrogen ions in the solution.
To calculate the volume of NaOH first, calculate the moles of NaOH and H₃PO₄.
Moles of H₃PO₄.
[tex]\rm moles \ of \ H_3PO_4 = 100\rm \ mL = 0.100\rm \ L \times (0.100 \ mol / L)\\\\\rm moles \ of \ H_3PO_4 = 0.01[/tex]
The moles of NaOH:
[tex]\rm Moles \ of \ NaOH =0.01 \ moles \ H_3PO_4\times 1.5 \\\\\rm Moles \ of \ NaOH= 0.0150[/tex]
The volume of NaOH:
[tex]\rm Volume\ of \ NaOH = \rm 0.0150\ moles\ NaOH \times (1 \ L / 5 \ moles) \\\\\rm Volume\ of \ NaOH = 3\times 10^{-3} L[/tex]
Therefore, 3 mL of 5 Molar NaOH is required to adjust the pH of phosphoric acid.
Learn more about pH:
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what is an example of a change in genetic traits of an organism do to human affect
Answer:
A person's skin color, hair color, dimples, freckles, and blood type are all examples of genetic variations that can occur in a human population.
Explanation:
What is the electronegativity difference
between sodium and chlorine?
Answer: 2.23 is the difference.
Explanation: Sodium has an electronegativity of 0.93 and Chlorine has an electronegativity of 3.16, so when Sodium and Chlorine form an ionic bond, in which the chlorine takes an electron away from sodium, forming the sodium cation, Na+, and the chloride anion, Cl-.
Calculate the energy of an electron in the n = 2 level of a hydrogen atom.
Answer: The energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.
Explanation:
Given: n = 2
The relation between energy and [tex]n^{th}[/tex] orbit of an atom is as follows.
[tex]E = - \frac{13.6}{n^{2}} eV[/tex]
Substitute the values into above formula as follows.
[tex]E = - \frac{13.6}{n^{2}} eV\\= - \frac{13.6}{(2)^{2}}\\= - 3.40 eV[/tex]
The negative sign indicates that energy is being released.
Thus, we can conclude that the energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.
Combustion of a 1.031-g sample of a compound containing only carbon, hydrogen,
and oxygen produced 2.265 g of CO2(g) and 1.236 g of H2O(g). What is the
empirical formula of the compound?
3 국
Molar masses in g/mol: CO2 = 44.01; H20 = 18.02; C = 12.01; H = 1.01
C3H50
Answer:
C₃H₈O
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 1.031 g
Mass of CO₂ = 2.265 g
Mass of H₂O = 1.236 g
Empirical formula =?
Next, we shall determine the mass of carbon, hydrogen and oxygen in the compound. This can be obtained as follow:
For carbon, C:
Mass of CO₂ = 2.265 g
Molar mass of CO₂ = 44.01 g/mol
Molar mass of C = 12.01 g/mol
Mass of C =?
Mass of C = molar mass of C / molar mass of CO₂ × mass of CO₂
Mass of C = 12.01/44.01 × 2.265
Mass of C = 0.618 g
For hydrogen, H:
Mass of H₂O = 1.236 g
Molar mass of H₂O = 18.02 g/mol
Molar mass of H₂ = 2 × 1.01 = 2.02 g/mol
Mass of H =?
Mass of H = Molar mass of H₂ / Molar mass of H₂O × Mass of H₂O
Mass of H = 2.02/18.02 × 1.236
Mass of H = 0.139 g
For oxygen, O:
Mass of compound = 1.031 g
Mass of C = 0.618 g
Mass of H = 0.139 g
Mass of O =?
Mass of O = Mass of compound – (mass of C + mass of H)
Mass of O = 1.031 – ( 0.618 + 0.139)
Mass of O = 1.031 – 0.757
Mass of O = 0.274 g
Finally, we shall determine the empirical formula. This can be obtained as follow:
C = 0.618 g
H = 0.139 g
O = 0.274 g
Divide by their molar mass
C = 0.618 / 12.01 = 0.051
H = 0.139 / 1.01 = 0.138
O = 0.274 / 16 = 0.017
Divide by the smallest
C = 0.051 / 0.017 = 3
H = 0.138 / 0.017 = 8
O = 0.017 / 0.017 = 1
Therefore, the empirical formula of the compound is C₃H₈O
Based on the data provided, the empirical formula of the compound is C₃H₈O
What is empirical formula?The empirical formula of compound is its simplest formula showing the mole ratio of the elements in the compound.
First, the mass of carbon, hydrogen and oxygen in the compound is determined first as follows:
For carbon, C:
Mass of CO₂ = 2.265 g
Molar mass of CO₂ = 44.01 g/mol
Molar mass of C = 12.01 g/mol
Mass of C = 12.01/44.01 × 2.265
Mass of C = 0.618 g
For hydrogen, H:
Mass of H₂O = 1.236 g
Molar mass of H₂O = 18.02 g/mol
Molar mass of H₂ = 2 × 1.01 = 2.02 g/mol
Mass of H = 2.02/18.02 × 1.236
Mass of H = 0.139 g
For oxygen, O:
Mass of compound = 1.031 g
Mass of C = 0.618 g
Mass of H = 0.139 g
Mass of O = Mass of compound – (mass of C + mass of H)
Mass of O = 1.031 – ( 0.618 + 0.139)
Mass of O = 0.274 g
To determine the empirical formula of a compound, the mole ratio of the elements are determined as follows:
Mole ratio = reacting mass/molar massMole ratio of the elements:
Carbon Hydrogen Oxygen
0.618 g/12.01 0.139 / 1.01 0.274 / 16
0.051 0.138 0.017
Divide by the smallest ratio to convert to whole numbers
0.051 / 0.017 0.138 / 0.017 0.017 / 0.017
3 : 8 : 1
Therefore, the empirical formula of the compound is C₃H₈O
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Enthalpy change is the
a. amount of energy absorbed or lost by a system as heat during a process at constant pressure.
b. entropy change of a system at constant pressure.
c. pressure change of a system at constant temperature.
d. temperature change of a system at constant pressure.
Answer:
I believe is A
Explanation:
Enthalpy change is the name given to the amount of heat evolved or absorbed in a reaction carried out at constant pressure.
Which group of elements will form molecular compounds? (Choose all that apply)
how to solve x² in differential
Answer:
x² = mutiphy by them self
Explanation:
Un recipiente cerrado, de 4,25 L, con tapa móvil, contiene H2S(g) a 740 Torr y 50,0°C. Se introduce en ese recipiente N2(g) a temperatura y presión constantes, de manera que el volumen final es el doble del volumen inicial. Calcular la cantidad de N2(g) en el recipiente, expresada en moles.
porfi ayuda
Answer:
[tex]n_{N_2}=6.41mol[/tex]
Explanation:
¡Hola!
En este caso, teniendo en cuenta la información dada por el problema, inferimos que primero se debe usar la ecuación del gas ideal con el fin de calcular las moles de gas que se encuentran al inicio del experimento:
[tex]PV=nRT\\\\n=\frac{RT}{PV} \\\\n=\frac{0.08206\frac{atm*L}{mol*K}*(50.0+273.15)K}{740/760atm*4.25L}\\\\n=6.41mol[/tex]
Seguidamente, usamos la ley de Avogadro para calcular las moles finales, teniendo el cuenta que el volumen final es el doble del inicial (8.50 L):
[tex]n_2=\frac{6.41mol*8.50L}{4.25L}\\\\n_2=12.82mol[/tex]
Quiere decir que las moles de N2(g) que se agregaron son:
[tex]n_{N_2}=12.81mol-6.41mol\\\\n_{N_2}=6.41mol[/tex]
¡Saludos!
Which molecule will have double bonds?
(4 Points)
Fluorine
Nitrogen
Hydrogen
Oxygen
A 0.750 M sample of phosphorus pentachloride decomposes to give phosphorus trichloride and chlorine gases.If the equilibrium concentration of PCl5 is 0.650M,what is the equilibrium constant for the reaction?
PCl5(g) --------> PCl3(g)+ Cl₂(g)
A) Keq = 0.0133
B) Keq = 0.0154
C) Keq = 0.133
D) Keq = 0.154
E) Keq = 65.0
Answer:
Explanation:
Amount of phosphorus pentachloride reacted = 0.75 M - 0.65 M = 0.10 M
PCl₅(g) --------> PCl₃(g)+ Cl₂(g)
1 mole 1 mole 1 mole
Amount of phosphorus pentachloride reacted = 0.75 M - 0.65 M = 0.10 M
PCl₃(g) and Cl₂(g) formed are .10 M and .10 M
Keq = [ PCl₃] x [ Cl₂ ] / [ PCl₅ ]
= .10 M x .10 M / .65 M
= .0154
B ) is the correct choice .
Heterozygous- a person having two different alleles for a gene is also called
Answer:
heterozygous.
Explanation:
A genotype consisting of two different alleles of a gene for a particular trait (Aa). Individuals who are heterozygous for a trait are referred to as heterozygotes.
Many enjoys the warm waters of a ______.
Geyser
Volcano
Hot spring
Furmarole
Tectonic
Answer:
hot spring
Explanation:
The mineral water in hot springs can also help reduce stress by relaxing tense muscles. Meanwhile as your body temperature rises in the bath, and then cools once you exit can also help you relax and fall into a deeper sleep.
Thermal energy naturally flows from _________ matter to _______ matter.
Answer:
Warmer
Cooler
Explanation:
1. Calculate and interpret the equilibrium constant. Using the reaction below.
The equilibrium concentrations 0.60 M for E, 0.80 M for F, and 1.30 M for G. (Note: E, F, and G are all gases.) Do not include your solution.
Answer:
kc = [G]² / [E] [F], kc = [1.30M]² / [0.60M] [0.80M]
Explanation:
The reaction is:
E + F ⇄ 2G
The equilibrium constant, kc, must be written as the ratio of the molar concentrations of products over reactants. Each concentration powered to its coefficient.
For the reaction of the problem, kc is:
kc = [G]² / [E] [F]Replacing the given concentrations:
kc = [1.30M]² / [0.60M] [0.80M]What is the Ksp expression for the dissociation of calcium oxalate?Immersive Reader
(4 Points)
Ksp=[Ca⁺²] x [C₂O₄⁻²]
Ksp=[Ca⁺²]² x [C₂O₄⁻²]
Ksp=[Ca⁺²]⁴ x [C₂O₄⁻²]
Ksp=[Ca⁺²] x [C₂O₄⁻²]²
Answer:
Ksp = [Ca⁺²] × [C₂O₄⁻²]
Explanation:
Step 1: Write the balanced reaction for the dissociation of calcium oxalate
CaC₂O₄(s) ⇄ Ca⁺²(aq) + C₂O₄⁻²(aq)
Step 2: Write the expression for the solubility product constant (Ksp) of calcium oxalate
The solubility product constant is the equilibrium constant for the dissociation reaction, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It doesn't include solids nor pure liquids because their activities are 1.
Ksp = [Ca⁺²] × [C₂O₄⁻²]
chemical properties of citric acid
Answer:
Citric Acid is a weak acid with a chemical formula C6H8O7.
...
Properties of Citric Acid – C6H8O7.
C6H8O7 Citric Acid
Molecular Weight/ Molar Mass 192.124 g/mol
Density 1.66 g/cm³
Boiling Point 310 °C
Melting Point 153 °C
Hope it helps❤️
At what temperature, in Celsius, will 88.0 g of Ne exert a pressure of 350. kPa in a
48.5 L container? NOTE: You must show your calculation on the attached scratch
paper, including which of the Gas Law formulas you used. *
Answer:
191 °C
Explanation:
We'll begin by calculating the number of mole in 88.0 g of Ne. This can be obtained as follow;
Mass of Ne = 88.0 g
Molar mass of Ne = 20 g/mol
Mole of Ne =?
Mole = mass /molar mass
Mole of Ne = 88 / 20
Mole of Ne = 4.4 moles
Next, we shall determine the temperature. This can be obtained as follow:
Mole of Ne = 4.4 moles
Pressure (P) = 350 KPa
Volume (V) = 48.5 L
Gas constant (R) = 8.314 KPa.L/Kmol
Temperature (T) =?
PV = nRT
350 × 48.5 = 4.4 × 8.314 × T
16975 = 36.5816 × T
Divide both side by 36.5816
T = 16975 / 36.5816
T = 464 K
Finally, we shall convert 464 K to celsius temperature. This can be obtained as follow:
T(°C) = T(K) – 273
T(K) = 464 K
T(°C) = 464 – 273
T(°C) = 191 °C
Thus, the temperature is 191 °C
What is the pH of a 6.2 x 10-5 M NaOH solution?
Answer:
4.21Explanation:
The pH of a solution can be found by using the formula
[tex]pH = - log [ {H}^{+} ][/tex]
From the question we have
[tex]ph = - log(6.2 \times {10}^{ - 5} ) \\ = 4.207608[/tex]
We have the final answer as
4.21Hope this helps you
URGENT
Best answer gets Brainliest!
Mg+ 2HCI ——> MgCI2+ H2
Answer:
Reaction type: Single displacement
Reactant: Magnesium
Product: Dihydrogen - H2
A container holds 40.0 mL of nitrogen at 30° C and at a constant pressure.
Find its volume if the temperature increases to 80° C?
Answer:
The correct answer is - 46.60 mL.
Explanation:
To find the volume of the gas at its new increased temperature we need to use Charl Law that shows the direct relationship between Volume and Temperature while Pressure remains constant.
V1 = 40 ml
T1 = 30 degree C + 273 = 303 K
V2 = ?
T2 = 80 degree C + 273 = 353 K
Charl Equation is:
V 1/T 1 = V 2/ T 2
(V1) * (T2)/ T1= V2
placing value:
40*353/303 = V2
= 14120/303
Vf = 46.60 mL
If the plant population decreased, the amount of carbon in the atmosphere would _______.
Increase
Stay the same
Decrease
Answer:
increase answer
Explanation:
i hope that is right
At the start of a reaction, there are 0.0249 mol N2,
3.21 x 10-2 mol H2, and 6.42 x 10-4 mol NH3 in a
3.50 L reaction vessel at 375°C. If the equilibrium constant, K, for the reaction:
N2(g) + 3H2(g)= 2NH3(g)
is 1.2 at this temperature, decide whether the system is at equilibrium or not. If it is not, predict in which direction, the net reaction will proceed.
Answer:
Explanation:
The reaction is given as:
[tex]N_{2(g)} + 3H_{2(g)} \to 2NH_{3(g)}[/tex]
The reaction quotient is:
[tex]Q_C = \dfrac{[NH_3]^2}{[N_2][H_2]^3}[/tex]
From the given information:
TO find each entity in the reaction quotient, we have:
[tex][NH_3] = \dfrac{6.42 \times 10^{-4}}{3.5}\\ \\ NH_3 = 1.834 \times 10^{-4}[/tex]
[tex][N_2] = \dfrac{0.024 }{3.5}[/tex]
[tex][N_2] = 0.006857[/tex]
[tex][H_2] =\dfrac{3.21 \times 10^{-2}}{3.5}[/tex]
[tex][H_2] = 9.17 \times 10^{-3}[/tex]
∴
[tex]Q_c= \dfrac{(1.834 \times 10^{-4})^2}{(0.0711)\times (9.17\times 10^{-3})^3} \\ \\ Q_c = 0.6135[/tex]
However; given that:
[tex]K_c = 1.2[/tex]
By relating [tex]Q_c \ \ and \ \ K_c[/tex], we will realize that [tex]Q_c \ \ < \ \ K_c[/tex]
The reaction is said that it is not at equilibrium and for it to be at equilibrium, then the reaction needs to proceed in the forward direction.
What is the function of a
catalyst?
A. Build enzymes
B. Speed up chemical reactions
C. Regulate the function of an enzyme
I believe it is to speed up chemical reactions
Which of the following
describes the zone of the
ocean where no light reaches?
A. up to 200 meter depth and includes
photosynthetic plants, sea anemones,
sponges, crabs, and clams
B. the "twilight zone" between 200-1000
meters deep and includes whales and octopi
and little life
C. permanent darkness below 1000 meters
with bioluminescent bacteria, bottom
feeders, and angler fish
Answer:
Bathypelagic
54% of the ocean lies in the Bathypelagic (aphotic) zone into which no light penetrates. This is also called the midnight zone and the deep ocean. Due to the complete lack of sunlight, photosynthesis cannot occur and the only light source is bioluminescence.
Explanation:
The small surface zone that has light is the photic zone. The entire rest of the ocean does not have light and is the aphotic zone.
Permanent darkness below 1000 meters with bioluminescent bacteria, bottom feeders, and angler fish is where no light reaches.
What is Darkness?This is referred to the state of being dark as a result of absence of light in the area.
The light ray penetration decreases with increase in depth thereby making areas below 1000 meters dark with bioluminescent bacteria, bottom feeders, and angler fish which is why option C was chosen.
Read more about Darkness here https://brainly.com/question/24581271
A 0.682 g sample of a weak monoprotic acid, HA was dissolved in sufficient water to make 50.0 mL of solution and was titrated with a 0.135 molar NaOH solution. After the addition of 10.6 milliliters of base, a pH of 5.65 was recorded. The equivalence point was reached after the addition of 27.4 milliliters of the 0.135 molar NaOH.
a. Calculate the number of moles of acid in the original sample.
b. Calculate the molar mass of the acid HA.
c. Calculate the [H3O+] at pH = 5.65
d. Calculate the number of moles of unreacted HA remaining in solution when the pH was 5.65.
e. Calculate the value of the ionization constant, Ka, of the acid HA.
f. Calculate the value of the ionization constant, Kb, and explain how you would use it to determine the pH of a solution of a known mass of the sodium salt (Na)(A) dissolved in a known volume of water.
In an experiment, a student wants to increase the rate of a reaction that involves gases. Which change to the reactants would accomplish this? Increase the volume to decrease pressure and to increase concentration. Increase the volume to increase pressure and to decrease concentration. Decrease the volume to decrease pressure and to increase concentration. Decrease the volume to increase pressure and to increase concentratio
Answer:
Decrease the volume to increase pressure and to increase concentration
Explanation:
A gaseous reaction is affected by the volume of the reactants. To increase the rate of the forward reaction, we need to ensure that the volume of the reactants is manipulated in such a way that the forward reaction is favored.
Thus, when the volume of reactants is decreased, the pressure increases.This increase in pressure has the same effect as increase in concentration. Hence, the rate of forward reaction increases.
A 3L sample of an ideal gas at 178 K has a pressure of 0.3 atm. Assuming that the volume is constant, what is the approximate pressure of the gas after it is heated to 278 K?
Answer: The approximate pressure of the gas after it is heated to 278 K is 0.468 atm.
Explanation:
Given: [tex]T_{1}[/tex] = 178 K, [tex]P_{1}[/tex] = 0.3 atm
[tex]T_{2}[/tex] = 278 K, [tex]P_{2}[/tex] = ?
According to Gay Lussac law, at constant volume the pressure of a gas is directly proportional to the temperature.
Formula used to calculate the pressure is as follows.
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\[/tex]
Substitute the values into above formula is as follows.
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{0.3 atm}{178 K} = \frac{P_{2}}{278 K}\\P_{2} = 0.468 atm[/tex]
Thus, we can conclude that the approximate pressure of the gas after it is heated to 278 K is 0.468 atm.
3.05 moles of H2O is equivalent to (blank amount) molecules of water.
Show your work.
Answer:
[tex]1 \: mole \: = 6.02 \times {10}^{23} \: molecules \\ 3.05 \: moles \: = (3.05 \times 6.02 \times {10}^{23} ) \: molecules \\ = 1.8361 \times {10}^{24} \: molecules[/tex]
The system we will be observing in this lab involves the cobalt(II) ion. This
ion can form two complexes, one with water and one with the chloride
ion (CI'). Below is a reaction showing the addition of chloride ions to the
cobalt - water complex.
Co(H2016 + Cl <--> COC142- + H2O
2+
pink
blue
What happened when HCl was added?
Answer:
See Explanation
Explanation:
In the equilibrium shown in the question,on the left hand side is a pink hexaaquacobalt II complex which is pink in colour. On the right hand side, we have a tetrachlorocobalt II complex which is blue in colour.
The equilibrium can be shifted from left to right by adding HCl (a source of chloride ions).
Hence, when HCl is added to the system, the equilibrium position is shifted to the right thereby yielding the blue solution of the tetrachlorocobalt II complex.