The test statistic of two brands of batteries is -2.177.
How to calculate test statistic?[tex]n_1[/tex] = size of sample 1 = 16
[tex]n_2[/tex] = size of sample 2 = 21
[tex]\bar{x_1}[/tex] = mean of sample 1 = 210
[tex]\bar{x_2}[/tex] = mean of sample 2 = 225
[tex]\sigma_{1}[/tex] = standard deviation of sample 1 = 20
[tex]\sigma_{2}[/tex] = standard deviation of sample 2 = 23
T test is test for statistical hypothesis that follows t-distribution table under null hypothesis. T test is used when test statistic would follow a normal distribution if the value of a scaling term in the test statistic were known. So, for this case we use t test for test statistic,
t = [tex]\frac{\bar{x_1}-\bar{x_2}}{\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}}[/tex]
t = [tex]\frac{210-225}{\sqrt{\frac{20^2}{16}+\frac{23^2}{21}}}[/tex]
t = [tex]\frac{-15}{\sqrt{\frac{400}{16}+\frac{529}{21}}}[/tex]
t = -15 / 7.0845
t = -2.117
Thus, the two brands of batteries have test statistic result is -2.117
Your question is incomplete, but most probably your full question was
Suppose you are testing to see if there is a difference in population mean lifetime of two brands (1,2) of batteries. Random samples of batteries are taken for each brand and the following data are recorded:
Sample 1: n1= 16, X1 = 210, s1= 20
Sample 2: n2= 21, X2 = 225, s2= 23
What is the test statistic assuming unequal population standard deviations?
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Find the Average Rate of Change between each pair of points.
1) (-10, 7), (6, 20)
Answer:
13/16
Step-by-step explanation:
When 2/9is rewritten using long division the result is best described as an?
Answer:
a mixed fraction or decimal
Monica deposits $100 into a savings account that pays a simple interest rate of 3.3%. Paul deposits $200 into a savings account that pays a simple interest rate of 2.1%. Monica says that she will earn more interest in 1 year because her interest rate is higher. Is she correct? Justify your response.
[tex]~~~~~~ \stackrel{\textit{\LARGE Monica}}{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$100\\ r=rate\to 3.3\%\to \frac{3.3}{100}\dotfill &0.033\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (100)(0.033)(1) \implies I = 3.3 \\\\[-0.35em] ~\dotfill[/tex]
[tex]~~~~~~ \stackrel{\textit{\LARGE Paul}}{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$200\\ r=rate\to 2.1\%\to \frac{2.1}{100}\dotfill &0.021\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (200)(0.021)(1) \implies I = 4.2[/tex]
well, Monica needs to check more closely what was in that last cup of coffee she drank, she's hallucinating.
A recent college graduate is planning to take the first three examinations in the coming summer. She will take the first exam in June. If she passes that exam, then she will take the second exam in July, and if she also passes that one, then she will take the third exam in September. If she fails an exam, then she is not allowed to take any others. The probability that she passes the first exam is 0.9. If she passes the first exam, then the conditional probability that she passes the second one is 0.8, and if she passes both the first and the second exams, then then the conditional probability that she passes the third exam is 0.7.
The recent college graduate upon passing her exam with a probability will be as follows:
(a) Let the event where she passes the exam be denoted as [tex]E_{i}[/tex] and by i-th exam.
P(passes all exams) = P([tex]E_{3} E_{2} E_{1}[/tex]) = P([tex]E_{3} | E_{2} E_{1}[/tex])P([tex]E_{2} | E_{1}[/tex])P([tex]E_{i}[/tex])
= (0.7)(0.8)(0.9)
= 0.504
(b) By calculating,
[tex]P (E_{1} E_2^{c} | (E_{1} E_{2} E_{3})^{c})[/tex] = [tex]\frac{P (E_{1} E_2^{c} | (E_{1} E_{2} E_{3})^{c})}{P((E_{1} E_{2} E_{3})^{c})}[/tex]
= [tex]\frac{P(E_{1} E^{c}_{2}) }{P((E_{1} E_{2} E_{3})^{c})}[/tex]
= [tex]\frac{P(E^{c}_{2} | E_{1)}P(E_{1 )} } {{P((E_{1} E_{2} E_{3})^{c})}}[/tex]
= [tex]\frac{(1- P (E_{2}|E_{1})) P(E_{1})}{1-P(E_{1} E_{2} E_{3} }[/tex]
= [tex]\frac{(1-0.8) X 0.9}{1-0.504}[/tex]
where we know the denominator from part (a)
≈ 0.3629
Probability theory deals with numerical representations of the likelihood that an event will happen or that a statement is true. A probability is a number between 0 and 1, where 0 essentially signifies an event's impossibility and 1 generally denotes certainty. The likelihood that something will happen is what is commonly referred to as probability. We can talk about the likely of one outcome, or the likelihood of a few outcomes, when we don't know how an event will turn out. An event's probability distribution is studied in statistics.
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Data was collected for sample of organic snacks. The amount of sugar (in mg) in each snack is summarized in the histogram below . Which statement best describes the meaning of onle of the bars in the histogram? 210 snacks have mg of sugar 1 snacks have about 210 mg of sugar. The largest number of snacks have 12 mg of sugar 210 snacks have betwcen 200 and 220 mg of sugar
The histogram's best summary is option (D), "there are a total of 12 snacks with the same amount of sugar."
What is a histogram?While bar charts show categorical variables, histograms show quantitative or numerical data.
The majority of the time, a histogram's numerical data will be continuous (having infinite values).
It would be ridiculous to try and show all possible values of a continuous variable along an axis.
So, the y-axis displays the number of snacks.
The x-axis displays how much sugar is in each snack.
The histogram's first column reveals that 2 snacks each contain between 220 and 224 mg of sugar.
The second column reveals that around 3 snacks have 224–228 mg of sugar.
The third column reveals that 8 snacks range in sugar content from 228 to 232 mg.
Twelve snacks are identified in the fourth column as having between 232 and 236 mg of sugar.
Twelve snacks are identified in the fourth column as having between 232 and 236 mg of sugar.
The fifth column reveals that 11 snacks range in sugar content from 236 to 240 mg.
Three snacks are shown to contain between 240 and 244 mg of sugar in the sixth column.
According to the seventh column, 2 snacks contain 244–248 mg of sugar.
The total number of observations is 41 nibbles, or 2+3+8+12+11+3+2.
So, the best statement that describes the histogram is "The most snacks with the same quantity of sugar are 12 in total."
Therefore, the histogram's best summary is option (D), "there are a total of 12 snacks with the same amount of sugar."
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Complete question:
Data were collected for a sample of organic snacks. The amount of sugar (in mg) in each snack is summarized in the histogram below. Which statement best describes the meaning of one of the bars in the histogram?
2
4
6
8
10
12
amount of sugar (mg)
220
224
228
232
236
240
244
248
Frequency
a. 2 snacks have about 226 mg of sugar.
b. 226 snacks have 2 mg of sugar.
c. 226 snacks have between 224 and 228 mg of sugar.
d. The largest number of snacks have 12 mg of sugar
o of the four expressions x y, x 5y, x – y, and 5x – y are chosen at random, what is the probability that their product will be of the form of x 2 – (by) 2 , where b is an integer?
The probability of the product of the given expressions is in the form of x² - (by)² is equal to 1/6.
As given in the question,
Given four expressions are:
( x + y ) , ( x + 5y ) , ( x - y ) and ( 5x - y )
Product of any two expression to have two degree expressions :
( x + y )( x + 5y ) = x² + 6xy + 5y²
( x + y )( x - y ) = x ² - y²
( x + y )( 5x - y ) = 5x² + 4xy -y²
( x + 5y )( x - y ) = x² + 4xy -5y²
( x + 5y )( 5x - y ) = 5x² + 24xy -5y²
(x - y) ( 5x - y) = 5x² - 6xy + y²
Total number of possible outcome of the product with degree 2 = 6
Favourable outcomes in the form of x² - ( by )² is x² - y² = x² -(1y)²
Here b = 1 is an integer.
Number of favourable outcomes = 1
Required probability = 1/6
Therefore, the probability of the product in the form of x² - ( by )² is equal to 1/6.
The complete question is:
If two of the four expressions x + y, x + 5y, x – y, and 5x – y are chosen at random, what is the probability that their product will be of the form of x2 – (by)2, where b is an integer?
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Calculate the ditance between the point H= (−9, 0) and J= (−1,−8) in the coordinate plane
The distance between the point H= (−9, 0) and J= (−1,−8) in the coordinate plane is 8√2 units.
Define the term distance formula?The Pythagorean theorem is used to calculate the distance using the distance formula. If we are aware of the coordinates of both the 2 points as in XY plane, we may calculate the distance between them. The distance formula can be used to calculate the distance between both P and Q if P(x1, y1) with Q(x2, y2) are the two main points in a plane.For the stated question-
Distance formula;
d = √(x2 -x1)² + (y2 - y1)²
H(x1, y1) = (−9, 0)
and J(x2, y2) = (−1,−8)
Put the values;
HJ = √(-1 + 9)² + (-8 - 0)²
HJ = √(64 + 64)
HJ = 8√2
Thus, the distance between the point H= (−9, 0) and J= (−1,−8) in the coordinate plane is 8√2 units.
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37. What type of interval training consists of overhead squats, front squats, and romanian deadlifts?
LSD training is type of interval training consists of overhead squats, front squats, and romanian deadlifts
Whats the definition for intervals?
in·ter·val ˈin-tər-vəl. plural intervals. : a space of time between events or states. a two-month interval between medical treatments. There were long intervals during the game in which nothing exciting happened
The area of focus of the Single Leg Romanian Deadlift is the back of the individuals legs and hips. By engaging in this activity, a person is getting a great workout for his or her glutes, hamstrings, lats. It requires the person to lift one leg directly beside the balance leg and then bend from waist to slowly reach hand toward the toes of the balance leg.
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what is the half-life of a radioactive substance that decays at a continuous rate of 11% per minute? (round to one decimal places.)
5.94 minutes is the half-life, or the amount of time it takes to half the substance to degrade (about 6 minutes).
Define the half-life of a radioactive substance?A radioactive sample's half-life is the amount of time it takes for half of its atomic nuclei to spontaneously transform into another nuclear species and emit particles and energy.When we use the formula A = A0(1 - r)t,
where A is the quantity of a substance we have at any given moment (t), A₀ is the quantity we have at the beginning (at t = 0), and r is the rate of decay, we may state the following:(1/2)A₀ = A₀(1 - 0.11)t
[Divide both sides by A₀ results in:
1/2 = (0.87)t
Using the log of both sides;:
log(1/2) = log(0.87)t
Using a logarithm property, we can bring the "t" to the front, giving us:
log(1/2) = t.log(0.89)
[Dividing both sides with log(0.89) gets us:
t = log(1/2)/log(0.89)
Using calculator for soling the values.
t = 5.94 seconds
Thus, 5.94 minutes is the half-life, or the amount of time it takes to half the substance to degrade (about 6 minutes).
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Consider how the following scenario could be modeled with a binomial distribution, and answer the question that follows. 54.4% of tickets sold to a movie are sold with a popcorn coupon, and 45.6% are not. You want to calculate the probability of selling exactly 6 tickets with popcorn coupons out of 10 total tickets (or 6 successes in 10 trials).
The value used for the parameter p is 0.544.
The number of successes in a sample of size n drawn with replacement from a population of size N is typically modeled using the binomial distribution. The mean for this type of distribution is computed by multiplying the number of trials (n) by the probability that they will succeed (p). Then, mean = n×p. The variance is n×p×q, where q is the probability that the event fails. The standard deviation is √(n×p×q).
Here, given that the percentage of tickets sold with popcorn is 54.4% and those not sold is 45.6%, the parameter (p) we used to calculate when the event occurs is 0.544. Because it is the probability that the sale of movie tickets with popcorn occurs.
The answer is 0.544.
The complete question is -
Consider how the following scenario could be modeled with a binomial distribution, and answer the question that follows.
54.4% of tickets sold to a movie are sold with a popcorn coupon, and 45.6% are not.
You want to calculate the probability of selling exactly 6 tickets with popcorn coupons out of 10 total tickets (or 6 successes in 10 trials).
What value should you use for the parameter p?
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Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.69 and standard deviation 0.74. in USE SALT (a) If a random sample of 25 specimens is selected, what is the probability that the sample average sediment density is at most 3.00? Between 2.69 and 3.00? (Round your answers to four decimal places. at most 3.00 between 2.69 and 3.00 (b) How large a sample size would be required to ensure that the first probability in part (a) is at least 0.99? (Round your answer up to the nearest whole number.)
The formula to convert the sample mean to a z score is, z = (x−μ)/σ/√n
a) Probability that the sample average sediment density is at most 3 is 0.9525 and probability between 2.69 and 3.00 is 0.4525..
b) Large Sample size is approx. 4 ..
We have given that,
Suppose the sentiment density of a randomly selected specimen from a certain region is normally distributed with
Sample mean , X-bar = 2.69
Sample size , n = 25
Standard deviations, σ = 0.74
a) we have to see what's the probability that the sample average setiment is at most 3 and then we're going to calculate between 2.69 and 3 point, so the firstly we have to calculate the standard error.
standard error = σ/√n = 0.74/√25
=> standard error = 0.148
the probability that x is between 2.69 and 3 in the probability of 2.69, i.e P (2.69<z <3)
P(at most 3 ) = P( X-bar <3) = P( X-bar - u /σ /√n<( 3 - 2.69) /0.74/5 )
=> P(z< 1.67) = 0.9525
P (2.69<z <3) = P( 2.69 - 2.69/0.74/5<z< 1.67)
=> P( <z< 1.67) = 0.4525
b) A large sample size is needed to make sure the first probability is 0.99.
If P(X-bar <3) = 0.99
=> P( 0<z<(3-2.69)/0.74/√n ) = 0.99
=> (3 - 2.69 )/0.74 /√n = 2.33
=> 0.31 √n /0.25 = 2.33
=> n = ( 2.33×0.25/0.31)² = 3.5 ~ 4
Hence, sample size is 4 and P( <z< 1.67) is 0.4525
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best answer gets brainliest
Answer:g(-8)=-62
Step-by-step explanation:
8x+2=-62. minus 2 to both sides
8x=-64. divide both sides by 8 to isolate x of the left
x=-8. final answer
g(-8)=-62
what is the GCF sum of 6+18
Answer:
GCF = 6; sum = 6(1 +3)
Step-by-step explanation:
You want the greatest common factor of 6 and 18.
GCFThe greatest common factor is the largest factor common to both numbers. Here, we can factor the numbers as ...
6 = 6·1
18 = 6·3
The factor 6 is common to both numbers. (Other numbers, such as 1, 2, and 3 are also common factors, but 6 is the largest.)
The GCF is 6.
In terms of the GCF, the sum can be written ...
6 +18 = 6(1 +3)
__
Additional comment
If the smaller number is not a factor of the larger, then the next value to check is the difference between the larger and smaller.
Euclid's algorithm tells you the remainder from division of the larger by the smaller will be zero when the divisor is the GCF. Otherwise, the remainder can be used to replace the larger number for trying again.
Here, 18/6 = 3 r 0, so 6 is the GCF.
Describe the error in the work shown. 62 + 3 + 5 x 2 36 + 8 x 2 36 + 16
this is due tomorrow pls help
The error is not using PEMDAS in right order and the answer is 75.
What is PEMDAS?PEMDAS is a method of operation in which operations are done in the order of parentheses first , then exponents, multiplication, division, addition and subtraction in the respective manner.
Given expression, 62 + 3 + 5 x 2
By using PEMDAS,
Step.1 - Firstly do the multiplication;
62 + 3 + 5 x 2 = 62 + 3 + 10
Step.2 - Now add the remaining terms;
62 + 3 + 10 = 75
Therefore, the answer is 75 .
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Lauren runs 2100 meters in 6 minutes. How many meters can Lauren run in one minute?
Answer: 350 meters
Step-by-step explanation: if she can run 2100 meters in 6 minutes to get 1 minute you can to divide by 6. so 6 minutes turn to 1 minute and 350 meters.
Solve the inequality 5x > –15 for x.
Answer: x > -3
Steps:
5x > -15 Bring 5 to the other side (multiplication ---> division)
x > -15/5 Divide
x > -3
The solution of the inequality 5x > -15 after solving the inequality expression is x > -3.
Given an inequality expression:
5x > -15
It is required to find the value of x after solving the expression.
In order to solve this, it is required to isolate the value of the variable, in this case, x, on one side and the constant terms on the other side.
In order to isolate the variable:
Divide both sides by 5.
x > [tex]\frac{-15}{5}[/tex]
x > -3
Hence, the solution of the inequality expression is x > -3.
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a multiple choice exam has a mean of 100 and a standard deviation of 13. about what percent of people would be expected to score 115 or more on the exam?
1.15 percentile of people would be expected to score 115 or more
What is Standard Deviation?
A standard deviation (or σ) is a measure of how widely distributed the data is in reference to the mean. A low standard deviation suggests that data is grouped around the mean, whereas a large standard deviation shows that data is more spread out.
Solution:
Mean = 100
Standard Deviation = 13
To solve the given problem we need to calculate the Z - Score
Z = X - Mean / Standard Deviation
P(X > 115)
Z = 115 - 100 / 13
Z = 15 / 13
Z = 1.15 Percentile
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Given g(x) = -5x + 1, find g(1).
Answer:
-4
Step-by-step explanation:
Answer:
-4
Step-by-step explanation:
g(x) tells us what the variable is and what variable should be replaced with a value.
g(1) tells us the value that will replace x.
Plug in 1 to the equation:
-5(1) + 1 = g(1) (multiply)
-5 + 1 = g(1) (combine like terms)
-4 = g(1)
Therefore, g(1) is equal to -4
(3x +33)"
(4x+8)
Find B
Answer: B=90 degrees maybe
Step-by-step explanation:
Joan's Nursery specializes in custom-designed landscaping for residential areas. The estimated labor cost associated with a particular landscaping proposal is based on the number of plantings of trees, shrubs, and so on to be used for the project. For cost-estimating purposes, managers use two hours of labor time for the planting of a medium-sized tree. Actual times from a sample of 10 plantings during the past month follow (times in hours). 1.6 1.4 2.7 2.3 2.5 2.3 2.6 3.0 1.3 2.3 With a 0.05 level of significance, test to see whether the mean tree-planting time differs from two hours. (a) State the null and alternative hypotheses. H0: ???? = 2 Ha: ???? ≠ 2 H0: ???? < 2 Ha: ???? ≥ 2 H0: ???? ≤ 2 Ha: ???? > 2 H0: ???? ≥ 2 Ha: ???? < 2 H0: ???? > 2 Ha: ???? ≤ 2 (b) Compute the sample mean. (c) Compute the sample standard deviation. (Round your answer to three decimal places.) (d) What is the test statistic? (Round your answer to three decimal places.) What is the p-value? (Round your answer to four decimal places.) p-value = (e) What is your conclusion? Reject H0. We cannot conclude that the mean tree-planting time differs from two hours. There is no reason to change from the two hours for cost estimating purposes.Do not reject H0. We cannot conclude that the mean tree-planting time differs from two hours. There is no reason to change from the two hours for cost estimating purposes. Do not reject H0. We can conclude that the mean tree-planting time differs from two hours. There is a reason to change from the two hours for cost estimating purposes.Reject H0. We can conclude that the mean tree-planting time differs from two hours. There is a reason to change from the two hours for cost estimating purposes.
The null hypothesis for the sample data set is given by H₀ : μ = 2 and the alternate hypothesis for the data is H₁ : μ > 2 .
a)H₀ : μ = 2
H₁ : μ > 2
We cannot reject the null hypothesis and conclude that no significant evidence exists to confirm that the mean tree-planting time differs from two hours.
Given :
X = 23.71,17.79, 29.87,18.78,28.76
b)Sample mean, x = Σx / n = 22/10 = 2.2
c) Standard deviation, s = 0.516
H0 : μ = 2
H1 : μ > 2
Test statistic :
(x - μ) ÷ (s/√(n))
n = 10
d) Test statistic :
=(2.2 - 2) ÷ (0.516/√(10))
=0.2 / 0.1631735
Test statistic = 1.23
Using the P-value from T-score we get the degrees of freedom:
df
= n - 1
= 10 - 1
= 9
P-value (1.23, 9) = 0.1249
e) Since, P-value > α ; We fail to reject the null and conclude that no significant evidence exists to support that mean tree-planting time differs from two.
A hypothesis is thetheory put up to explain a phenomenon. If a hypothesis cannot be tested by the scientific method, it cannot be referred to as a scientific hypothesis.
Scientific theories frequently start with historical observations that can't be adequately explained by the body of knowledge at this time. A hypothesis is a tested assertion regarding the relationship between two or more variables in the scientific area or a theory put out to explain an observed phenomena.
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13.
(a) What fraction of this square is shaded?
(b) What decimal part of this square is not shaded?
Answer to question 1:
2/5
Explanation:
This square is a 10 by 10 graph, meaning there is 100 total blocks, and 40 of the squares are shaded in, making 40/100 of the squares shaded. 40/100 is then simplified to 2/5.
Answer to question 2:
0.6
Explanation:
As previously stated, the graph has a total of 100 squares, and 60 of the squares are not shaded, making it 60/100 squares unshaded. 60/100 is then converted to a decimal of 0.6.
Angle d is a circumscribed angle of circle o. What is the perimeter of kite obde? 17 units 23 units 27 units 60 units.
The solution to this question is 27 units the perimeter of kite OBDE.
The definition of perimeterThe perimeter of a shape is the entire length of the shape's boundary as used in geometry. A form's perimeter can be calculated by adding the lengths of all of its sides and edges. In order to calculate it, linear distances such as centimeters, meters, inches, or feet are used.
Here
This is because 15x15 =225
8x8 = 64
225+64=289 and
the square root of 289 is 17 and that is the diameter of the circle and the hypotenuse of the triangle and since the kite has two congruent sides which are both radii or can be written as half of a diameter times two would be the same as the length of the diameter which is17+the two bottom sides (which are both 5 and 5 )
So 5+ 5 = 10 and
10 + 17 =27 or the perimeter of the kite.
Therefore ,the perimeter of kite OBDE is 27 units.
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Finn has a piece of bamboo stick that is 50 cm long. He cuts the stick once into two pieces and used it to build a rhombus-shaped kite; he used a textile 288cm^2 in area along with the sticks. How long were the two sticks?
The lengths of the bamboo sticks obtained using the quadratic formula are;
33.06 cm and 16.94 cm
What is the quadratic formula?The quadratic formula used to find the solution of quadratic equations can be presented as follows;
[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4\times a \times c} }{2 \times a}[/tex]
The area of the rhombus = 280 cm²
The length of the stick = 50 cm
Let x represent a length of the sticks , therefore;
The length of the other stick = 50 - x
The rhombus consists of two triangles
The height of the triangles is half the length of the diagonal of the rhombus, therefore;
Area = x × (50 - x) × 0.5 = 280
-0.5·x² + 25·x = 280
x² - 50·x + 560 = 0
x = (50 ± √((-50)² - 4 × 1 × (560))/(2)
x ≈ 33.06, or x ≈ 16.94
The lengths of the bamboo sticks are;
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If Amy is tardy, then she will get a detention
Write the CONVERSE of this statement
Answer:
Amy will get detention if she is tardy
Step-by-step explanation:
each year, more than 2 million people in the united states become infected with bacteria that are resistant to antibiotics. in particular, the centers of disease control and prevention have launched studies of drug-resistant gonorrhea.† suppose that, of 221 cases tested in a certain state, 14 were found to be drug-resistant. suppose also that, of 322 cases tested in another state, 6 were found to be drug-resistant. do these data suggest a statistically significant difference between the proportions of drug-resistant cases in the two states? use a 0.02 level of significance. (let p1
Yes, These data suggest a statistically significant difference between the proportions of drug-resistant cases in the two cities.
In first city, the drug-resistant proportion is significant while In other city, It is not significant.
What is Ratio and proportion ?
A ratio is an ordered pair of numbers a and b, expressed as a / b, where b is not equal to 0. A percentage is an equation in which two ratios are made equal to one another.
Let the first city to be City A and the other city as City B.
In city A, 14 cases are of drug-resistant out of total 221 cases.
In city B, 6 cases are of drug-resistant out of total 322 cases.
We'll find the proportion of drug-resistant cases of both cities,
City A = 14 / 221 = 0.06 > 0.02
City B = 6 / 322 = 0.018 < 0.02
If use a 0.02 level of significance then,
City A has significant drug-resistant cases while City B does not have significant cases.
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consider a list of randomly generated 2-letter ""words"" printed on a paper. the letters cannot be repeated. 1) how many different words are there? 26*25 2) at least how many of these ""words"" should be printed to be sure of having at least 7 identical ""words"" on the list? 26*25*7 3) at least how many identical ""words"" are printed if there are 5201 ""words"" on the list?
1) the maximum number of different 2 letter words = 650
2) 3901 words that should be printed to be sure of having at least 7 identical words on the list.
3) if there are 5201 words on the list, then there are 11 identical words
In this question, we have been given a list of randomly generated 2-letter words printed on a paper and he letters cannot be repeated.
1)the maximum no. of different 2 letter words would be,
using permutation,
^(26)P_2 = 650
2) the least number of words that should be printed to be sure of having at least 7 identical words on the list.
650 * 6 = 3900
3900 + 1 = 3901
to sure 7 identical words 3901 words should be printed.
3) the least number of identical words are printed if there are 5201 ""words"" on the list.
5201 = (520 * 10) + 1
so, there are at least 11 identical words.
Therefore, 1) the number of different 2 letter words = 650
2) the least number of words that should be printed to be sure of having at least 7 identical words on the list = 3901
3) if there are 5201 words on the list, 11 identical words should be printed.
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in a periodic review system, yyou place and order every 14 days. the lead time is 8 days. what is the uncertainty period? state your answer as a whole number, for example 44
In a periodic review system when an order is placed every 14 days, the uncertainty period is 22 days.
Lead time is the time that passes from the start to the conclusion. It helps in measuring the time taken to complete a project. It varies from industry to industry.
It is normally calculated as:
Lead time = processing time + post-processing time.
Given,
lead time = 8 days
Order place date = 14 days
uncertainty period = order date + lead time
uncertainty period = 14 + 8 = 22 days
So, we can say that in a periodic review system when an order is placed every 14 days, the uncertainty period will be 22 days.
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JUST WANT THE ANSWER NO EXPLINATION NEED HELP ASAP!
Answer:
Step-by-step explanation:
11. First option
12. 5p+4 > 14
> symbol is greater than and has an open circle, going right
Answer:
Option A for both questions--------------------------
The first questionThe graph indicates the inequality n ≤ 1, since highlighted part is to the left from the 1 and there is a closed circle.
Double both sides to get 2n:
n ≤ 1 ⇒ 2n ≤ 2And add 5 to both sides to get 7:
2n + 5 ≤ 2 + 5 ⇒ 2n + 5 ≤ 7This is matching the option A.
Question 12The graph indicates the inequality p > 2, since highlighted part is to the right from the 2 and there is a open circle.
Multiply both sides by 5 to get 5p:
p > 2 ⇒5p > 10Add 4 to both sides to get 14:
5p > 10 ⇒5p + 4 > 14This is matching the option A.
What estimate can i do for 3.5x0.4
Answer:
The answer is 1.4
Six adult tickets to a movie at the theater cost
$52.50. Find the price for one ticket.
Answer:
$8.75 for one ticket
Step-by-step explanation:
Since this is just plain division, you'd divide 52.50 by 6 and get your answer of 8.75.
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