Answer:
a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b)0.6004
c)19.607
Step-by-step explanation:
Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2
X ~ Poisson(A) where [tex]\lambda = \frac{10.2}{200} = 0.051[/tex]
a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar
[tex]\frac{1}{4} \times 200 = 50[/tex]
50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55
So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment
Let X denotes the number of grams to be eaten before another fragment is detected.
[tex]P(X>10)= e^{-\lambda \times x}= e^{-0.051 \times 10}= e^{-0.51}=0.6004[/tex]
c)The expected number of grams to be eaten before encountering the first fragments :
[tex]E(X)=\frac{1}{\lambda}=\frac{1}{0.051}=19.607 gram[/tex]s
Real Numbers Quiz Active 1 2 3 4 Which answer describes the type of numbers that are dense? whole numbers and integers O whole numbers but not integers rational numbers and irrational numbers rational numbers but not irrational numbers
Answer:
C. rational numbers and irrational numbers
Step-by-step explanation:
Rational numbers are those numbers that can be used to express the ratio of two whole numbers. An example is the figure 2. It can be expressed as a fraction of another number like when we write 2/8. Both figures are rational. Irrational numbers cannot be used to express the ratio of two whole numbers or integers. An example is a digit like 0.666666... Rational and irrational numbers are real numbers because real numbers encompass all the types of numbers we can think of, positive, negative, decimals, whole, etc.
The density of numbers is seen in the fact that there is no vacuum created between real numbers when plotted on the number line.
Unpredictable numbers that are distributed over a certain range are ____.
A. Random numbers
B. Random equations
C. Random formulas
D. Tables of formulas
Answer:
random numbers
Step-by-step explanation:
because they are randomly picked
Unpredictable numbers that are distributed over a certain range are _Random numbers_.
What is random experiment?Random experiments are repeated multiple times to determine its likelihood.
The number of times an experiment is repeated is better described as number of trials.
The range of a function is defined as the set of all the possible output values that are valid for the given function.
Now, Unpredictable numbers that are distributed over a certain range are random numbers because they are randomly picked.
Unpredictable numbers that are distributed over a certain range are _Random numbers_.
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Alex has to fill his 10 gallon fish tank with water. He only has a 1 pint bucket. How many times will he have to fill his bucket to fill the tank?????W
Answer:
80
Step-by-step explanation:
8 pints in a gallon so then you multiply 8 x 10 and get 80
Answer:
80
Step-by-step explanation:
1 gallon = 8 pints8 × 10 = 80I hope this helps!
The terminal side of angle θ intersects the unit circle in the first quadrant at (925,y). What are the exact values of sinθ and cosθ?
Correct question is;
The terminal side of angle θ intersects the unit circle in the first quadrant at (9/25,y). What are the exact values of sinθ and cosθ?
Answer:
sinθ = (√544)/25) and cosθ = 9/25
Step-by-step explanation:
We are given that (9/25,y) lies on the unit circle. Thus, from general representation of equation of a circle, we can write that;
(9/25)² + y² = 1²
y² = 1 - (9/25)²
y² = (625 - 81)/25²
y² = 544/25²
y = ±(√544)/25
We are told the point is in the first quadrant and so we will choose the positive value of y = (√544)/25.
Therefore, the terminal side of the angle θ intersects the unit circle at [9/25, (√544)/25)]
In unit circle geometry, cosθ = x, while sinθ = y.
Thus; sinθ = (√544)/25) and cosθ = 9/25
The exact value of [tex]sin\theta[/tex] and [tex]cos\theta[/tex] is [tex]cos\theta = \frac{9}{25} , sin\theta = \frac{\sqrt{544} }{25}[/tex] and this can be determined by forming the equation of circle.
Given :
The terminal side of angle [tex]\theta[/tex] intersect at unit circle ([tex]\frac{9}{25}, y[/tex]).
From general representation of equation of circle , we can write
[tex]x^{2} + y^{2} = a^{2}\\[/tex]
[tex](\frac{9^{2} }{25^{2} })[/tex] + [tex]y^{2} = 1^{2}[/tex]
[tex]y^{2} = 1 - \frac{81}{625}[/tex]
[tex]y^{2} = \frac{625-81}{625}[/tex]
[tex]y^{2}=\frac{544}{625}[/tex]
Taking square root both sides
[tex]y= \frac{\sqrt{544} }{\sqrt{625} }[/tex]
[tex]y = \frac{\sqrt{544} }{25}[/tex]
We are taking only because point lies in first quadrant.
The terminal side of angel [tex]\theta[/tex] unit circle in first quadrant at [tex](\frac{9}{25} , \frac{\sqrt{544} }{25})[/tex]
In unit circle
[tex]x = cos\theta , y = sin\theta[/tex]
[tex]\rm cos\theta = \frac{9}{25} , sin\theta = \frac{\sqrt{544} }{25}[/tex].
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g What is the max number of 4-element-subsets of we can select, such that intersection of any 3 of them is empty?
Answer:
16Step-by-step explanation:
In order to get the max number of 4-element-subsets of we can select, such that intersection of any 3 of them is empty, we need to calculate the power of the set having four elements. Let the set containing the element be A as shown;
Let set A = {a, b, c, d}
Power of the set P(A) = [tex]2^n[/tex] where:
n is the total number of element in the set. Since we have four elements in the set, n = 4
[tex]P(A) = 2^4\\P(A) = 16[/tex]
This means that the set A have 16 subsets. The subsets of the set are:
{}, {a}, {b}, {c}, {d}, {a, b}, {a, c}, {a, d}, {b, c}, {b, d}, {c, d}, {a, b, c}, {a, b, d}, {b, c, d}. {a, c, d}, {a, b, c, d}.
From all the subsets, it can be seen that intersection of set {a} and {b}, {a} and {c}, {c} and {d} are empty.
Hence the max number of 4-element-subsets of we can select, such that intersection of any 3 of them is empty is 16
An SEO account manager is concerned website developers are using too many keywords per web page. The SEO account manager would like to carry out a hypothesis test and test the claim that a web page has, on average, more than 10 keywords. Why is this hypothesis test right-tailed
Answer:
The hypothesis test is right tailed because of claim made by SEO account manager that a web page on average has more than 10 keywords.
Step-by-step explanation:
The given hypothesis test is right tailed due to the claim made by SEO account manager. The tail of hypothesis test decided by looking at alternative hypothesis. The claim stated as " a web on average has more than 10 keywords" and this leads to alternative hypothesis as
Ha:μ>10.
The alternative hypothesis shows the greater than area or also known as right tailed area. Thus, given hypothesis test is right tailed.
On a lunch counter, there are 3 oranges, 5 apples, and 2 bananas. If 3 pieces of fruit are selected, find the probability that 1 orange, 1 apple, and 1 banana are selected (does not have to be in that order).
Answer:
[tex]Probability = \frac{1}{24}[/tex]
Step-by-step explanation:
Given
[tex]Oranges = 3[/tex]
[tex]Apples = 5[/tex]
[tex]Banana = 2[/tex]
[tex]Total = 10[/tex]
Required
Determine the probability of 1 orange, 1 apple and 1 banana
Since, order is not important:
[tex]Probability = P(Orange) * P(Apple) * P(Banana)[/tex]
[tex]Probability = \frac{3}{10} * \frac{5}{9} * \frac{2}{8}[/tex]
The difference in the numerator is as a result of picking the fruit without replacement
[tex]Probability = \frac{30}{720}[/tex]
[tex]Probability = \frac{1}{24}[/tex]
Probability is simply how likely something is to happen.
The probability of 1 orange, 1 apple, and 1 banana are [tex]\frac{1}{24}[/tex]
On lunch counter,
Number of oranges = 3
Number of apples = 5
Number of bananas = 2
If 3 piece of fruit is selected then, probability of 1 orange, 1 apple and 1 banana
[tex]=\frac{3}{10}*\frac{5}{9} *\frac{2}{8} \\\\=\frac{30}{720}\\\\=\frac{1}{24}[/tex]
Therefore, the probability of selecting 1 orange, 1 apple, and 1 banana are [tex]\frac{1}{24}[/tex]
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The length of a rectangle is three times its width.
If the perimeter of the rectangle is 56 yd, find its area.
Answer:
147 yards
Step-by-step explanation:
Use a system of equations
Let x be length of rectangle and y be width of rectangle
x = 3y
2x + 2y = 56
Substitute x = 3y into second equation, we have 2(3y) + 2y = 56. Combine like terms and we have 8y = 56. y = 7.
Substituting y = 7 into the first equation, we have x = 3(7), and x = 21.
Area is length times width, so area is 21 * 7 = 147
Answer:
area= 147 yd
Step-by-step explanation:
l= 21 yd
w= 7 yd
Formula: a=lxw (area=length x width)
a=21 x 7
21 x 7=147 yd
you must have a common denominator when ? fractions
Step-by-step explanation:
ADD::If the denominators are not the same, you must find the common denominator by finding the least common multiple of the 2.
SUBTRACT::If the denominators are not the same, you must find the common denominator by finding the least common multiple of the 2.
The sum of three consecutive odd integers is 18 less than five times the middle number fimd the three integers
Answer:
7, 9, 11
Step-by-step explanation:
x+x+2+x+4=5(x+2)-18
3x+6=5x+10-18
3x+6=5x+-8
3x=5x+-14
-2x=-14
x=7
Which expression is equivalent to 27 + 15?
1) 3(24 + 12)
2) 319 + 5)
3) 9(3 + 15)
4) 9(18+ 6)
By definition, two rays labeled Ab and AC must exist with which of the following conditions?
Answer:
A. The two rays form angle CAB.
C. The two rays make a line AC.
D. The two rays intersect at point A.
E. The two rays are perpendicular.
This is shown in figure 1 in the attachment provided.
Step-by-step explanation:
The given rays, [tex] \overrightarrow{AB} [/tex] and [tex] \overrightarrow{AC} [/tex] shows that both rays have a common endpoint A.
Therefore, the following conditions exists:
A. "The two rays form angle CAB."
Take a look at figure 1 in the attachment provided below. The two rays meet at point A to form angle CAB.
C. "The two rays make a line AC."
As shown in figure 2 in the attachment provided below, [[tex] \overrightarrow{AB} [/tex] and [tex] \overrightarrow{AC} [/tex] have a common end point, A, and they extend in opposite directions to form a straight line AC. [tex] (\overline{AC}) [/tex]
D. "The two rays intersect at point A."
This is shown in figure 1 in the attachment provided.
E. "The two rays are perpendicular."
Since [tex] \overrightarrow{AB} [/tex] and [tex] \overrightarrow{AC} [/tex] intersect at point A, they are perpendicular to each other, forming a right angle at point A. This we can see in figure 2 provided in the attachment.
2) Chicken soup is 3 cans for $0.55. How much would a
dozen soup cans cost?
Answer:
It would cost $2.20
Step-by-step explanation:
If 3 cans = $.55
then 3*4 = 12
soooo 4*.55 = 2.20
Hope this helps!!!
Describe the similarities and differences between a bar graph and a histogram.
Answer:
Bar graphs are used with nominal or ordinal scores; histograms are used with interval or ratio scores.
Step-by-step explanation:
How many pies are there if someone eats 2 and then someone else eats 4 then I eat 13? We started with 200 pies.
Answer:
183
Step-by-step explanation: 13+4=17 200-17=183
Answer:
181
Step-by-step explanation:
4x+7 (3x-3)<-9
Please show steps
Answer: 3x-3 needs to be done first, and then 4x+7, and then multiply and whatever you get will be your answer
Step-by-step explanation:
I will give brainliest! 2(6x+3)
Answer: 12x+6
Step-by-step explanation:
distributive property
Answer:
=12x + 6
Step-by-step explanation:
What is 2+2-2X2 divided by 2??
Answer:
0
Step-by-step explanation:
cause 2+2 is 4 and 2x2 is four and since u put - it take it away a then divide 0 by 2 u get 0
12. An object is fired from the top of a 200 ft. tower with an initial velocity of 80 ft/sec. and is
modeled by the equation h(t) = -16t^2+80t + 200.
a) How long after firing does it reach its maximum height?
b) What is the maximum height?
Answer:
a) The object reaches its maximum height at t=2.5 seconds
b) The maximum height is 300 m
Step-by-step explanation:
Maximum Value of a Function
First derivative criteria:
If f(t) is a real continuous function of t and the first derivative of f called f'(t) exists, then solving the equation:
f'(t)=0
Gives the critical points of f, some of which could be maximum or minimum.
Second derivative criteria:
If t=t1 is a critical point of f(t) and the second derivative of f:
f''(t1) is positive, then t1 is a minimum of f
f''(t1) is negative, then t1 is a maximum of f.
f''(t1)=0, no conclusion can be drawn.
The height of the object is modeled by the function:
[tex]h(t) = -16t^2+80t + 200[/tex]
a)
To find the maximum height, we use the above criteria.
Find the first derivative:
h'(t) = -32t+80
Equate h'(t)=0
-32t+80=0
Solve:
[tex]-32t=-80[/tex]
[tex]t=80/32=2.5[/tex]
t=2.5 seconds
Find the second derivative:
h''(t)=-32
Since the second derivative is negative, the critical point is a maximum.
The object reaches its maximum height at t=2.5 seconds
b) Evaluate h(2.5)
[tex]h(2.5) = -16\cdot 2.5^2+80\cdot 2.5 + 200[/tex]
[tex]h(2.5) = -100+200 + 200[/tex]
h(2.5)=300 m
The maximum height is 300 m
the answer to the universe, life, and everything
Answer:
my life hurts now
Step-by-step explanation:
Answer:
42
Step-by-step explanation:
GET A BOOK U MORON
Which is the better deal 8 ounces of shampoo for $0.99 or 12 ounces for $1.47?
Answer:
12 ounces for $1.47.
Step-by-step explanation:
:) ello
4950/6 + 112 x 1.75 = ? x 2
Answer:
1021
Step-by-step explanation:
Answer:
1021 is the answer to this question
What is the best estimate of 49.13 + 0.58?
A: 80
B: 40
C: 25
D: 50
Answer:
D.50
Step-by-step explanation:
its the closes whole number to 49.13
Question Help
Jane took 30 min to drive her boat upstream to water-ski at her favorite spot. Coming back later in the day, at the same boat speed, took her 20 min. If the current in
that part of the river is 4 km per hr, what was her boat speed in still water?
Her boat speed in still water was km per hr.
Answer:
The speed of the boat is 20 km/hr
Step-by-step explanation:
Let s be the speed of boat in still water
Let d be the distance
Upstream speed = s-4
Jane took 30 min to drive her boat upstream to water-ski at her favorite spot.
So, Distance traveled in upstream =[tex]Speed \times time =(s-4) \times \frac{30}{60}[/tex]
Downstream speed = s+4
So, Distance traveled in downstream = [tex]Speed \times time =(s+4) \times \frac{20}{60}[/tex]
So, [tex](s-4) \times \frac{30}{60}=(s+4) \times \frac{20}{60}[/tex]
30s-120=20s+80
10s=200
s=20
Hence The speed of the boat is 20 km/hr
Ronald has a 10% solution of the fertilizer Super Grow. How much pure Super Grow should he add to the mixture to get 36 oz of a 12.5% concentration?
Answer:
1 oz
Step-by-step explanation:
Given that:
% solution of super grow fertilizer = 10%
To obtain mixture of 36oz of a 12.5% concentration
Let oz of pure supergrowth to be added = s
(Initial % * (36 - s) + s) / 36 = target concentration
(10% * (36 - s) + s) / 36 = 12.5%
(0.1(36 - s) + s) / 36 = 0.125
Cross multiply:
0.1(36 - s) + s =. 0.125 * 36
3.6 - 0.1s + s = 4.5
3.6 + 0.9s = 4.5
0.9s = 4.5 - 3.6
0.9s = 0.9
s =. 0.9/0.9
s = 1
Hence, 1 oz of pure supergrowth should be added to the 10% solution to get 36 oz of a 12.5% concentration.
PLEASE HELP
Select the correct answer from each drop-down menu. Options are (equal to, not equal to)
Answer:
Not equal to.
Step-by-step explanation:
Please help me solve What is m
Answer:
a=60
b=85
c=35
Step-by-step explanation:
a is shown to be 60 in the text along with c being 85 with its angle so just add 60 and 85 to get 145 and fill in the remaining to get 180 which gives you c as 35
Subtract -2x^2+4x-1−2x
2
+4x−1minus, 2, x, squared, plus, 4, x, minus, 1 from 6x^2+3x-96x
2
+3x−96, x, squared, plus, 3, x, minus, 9.
Your answer should be a polynomial in standard form.
Answer:
8x²- x -8
Step-by-step explanation:
The question is not well written. I guess what you mean is:
Subtract -2x^2+4x-1 ( minus 2x squared plus 4x minus 1) from 6x^2+3x-9 (6x squared plus 3x minus 9).
To subtract -2x^2+4x-1 from 6x^2+3x-9, that is
6x^2+3x-9 - (-2x^2+4x-1). This can be written as
6x²+3x-9 - (-2x²+4x-1)
Now, opening the bracket, we will get
6x²+3x-9 +2x²-4x+1
Then, collecting like terms, we get
6x²+2x²+3x-4x-9+1
6x²+2x² = 8x²
3x-4x = -x
-9+1 = -8
∴6x²+2x²+3x-4x-9+1 becomes
8x²-x -8
The answer is 8x²-x -8.
Simplified form of the polynomial :
8x²- x -8
Given(correct form of question):
Subtract -2x²+4x-1 ( minus 2x squared plus 4x minus 1) from 6x²+3x-9 (6x squared plus 3x minus 9).
Now,
To subtract -2x²+4x-1 from 6x²+3x-9, that is
6x²+3x-9 - (-2x²+4x-1). This can be written as
6x²+3x-9 - (-2x²+4x-1)
Now, opening the bracket, we will get
6x²+3x-9 +2x²-4x+1
Then, collecting like terms, we get
6x²+2x²+3x-4x-9+1
6x²+2x² = 8x²
3x-4x = -x
-9+1 = -8
∴6x²+2x²+3x-4x-9+1 becomes 8x²-x -8
Thus,
The answer is 8x²-x -8.
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A short quiz has two true-false questions and one multiple-choice question with four possible answers. A student guesses at each question. Assuming the choices are all equally likely and the questions are independent of each other, the following is the probability distribution of the number of answers guessed correctly. What is the Probability of two or more questions right? X 0 1 2 3 P(X) .1875 .4375 .3125 .0625
Answer:
[tex]P(X\geq 2) = 0.375[/tex]
Step-by-step explanation:
Given
X ------0 --------1 -------- 2--------- 3
P(X) --.1875 -.4375 ---.3125 --- .0625
Required
Determine [tex]P(X\geq 2)[/tex]
This is calculated as:
[tex]P(X\geq 2) = P(X = 2) + P(X = 3)[/tex]
[tex]P(X\geq 2) = 0.3125 + 0.0625[/tex]
[tex]P(X\geq 2) = 0.375[/tex]
POSSIBLE POINTS: 3.33
Tracy wants to buy some pies for her sisters and she has a budget of $82 to spend on $5
apple pies, $4.5 banana pies, and $5.5 chocolate pies. She wants to buy 16 pies for her
sisters and must buy as many chocolate pies as apple pies and banana pies combined.
How many of each item should she buy? Write a system of equations to help you solve
this problem.
# of applie pies =
# of banana pies =
# of chocolate piles =
1
2 3
Answer:
From the information given, you can write the following system of equations:
x+y+z=16 (1)
5x+4.5y+5.5z=82 (2)
z=x+y (3)
You can replace (3) in (1) and (2):
x+y+x+y=16
2x+2y=16 (4)
5x+4.5y+5.5(x+y)=82
5x+4.5y+5.5x+5.5y=82
10.5x+10y=82 (5)
Now, you have the following equations:
2x+2y=16 (4)
10.5x+10y=82 (5)
You can isolate x in (4):
2x=16-2y
x=8-y (6)
Then, you have to replace (6) in (5):
10.5(8-y)+10y=82
84-10.5y+10y=82
84-82=10.5y-10y
2=0.5y
y=2/0.5
y=4
Now, you can replace the value of y in (6) to find x:
x=8-4
x=4
Finally, you can replace the vaue of x and y in (3) to find z:
z=4+4
z=8
According to this, she should buy 4 apple pies, 4 banana pies and 8 chocolate pies.