Suppose the average life for new tires is thought to be bell-shaped and symmetrical with a mean of 45,000 miles and a standard deviation of 4,000 miles Based on this information, what interval of miles would approximately 95% of tires be expected to last within?A 41000 10 49.000B. 42,000 to 47.000C 45,000 to 49.000D 37 000 to 53000 

Answer:  kg⋅m/s2,

Step-by-step explanation:

I hope you do well on your test Good luck!!!

There are two main subtypes of quantitative data, which are discrete data and continuous data. Each subtype has different techniques for analysis.

1. Discrete data: This type of data represents whole numbers or counts that can only take specific values. Examples include the number of students in a class or the number of cars in a parking lot. Techniques used to analyze discrete data include:
  a. Frequency distribution: A summary of the number of times each value appears in the dataset.

 b. Measures of central tendency: Calculating the mean, median, and mode of the dataset to understand its central point.

 c. Measures of dispersion: Assessing the range, variance, and standard deviation to understand the spread of the data.

2. Continuous data: This type of data represents measurements that can take any value within a range, such as height, weight, or temperature. Techniques used to analyze continuous data include:

 a. Histogram: A graphical representation of the distribution of the data, using bars to represent the frequency of values within specific intervals.

  b. Probability density function: A mathematical function that describes the probability of a continuous random variable falling within a specific range.

  c. Regression analysis: A statistical method for analyzing the relationship between a dependent variable and one or more independent variables.

Both discrete and continuous data can also be analyzed using inferential statistics, such as hypothesis testing and confidence intervals, to make inferences about a population based on a sample of the data.

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The number of days that had a high temperature of at least 16°C would be = 25days.

From the dot plot given above, the different temperature ranges according to the different days.

Temperature 6° = 1 day

Temperature 7°= 2 days

Temperature. 8° = 2 days

Temperature 9° = 3 says

Temperature 10° = 5 days

Temperature. 11° = 3 days

Temperature. 12° = 4 days

Temperature. 13° = 1 days

Temperature. 14° = 2 days

Temperature. 16° = 2 days

Therefore, the total number of days = 1+2+2+3+5+3+4+1+2+2 = 25 days

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Answer:

The scale factor is 20.

Explanation:

The scale factor is the ratio of the corresponding side lengths (or areas or volumes) of the two similar figures. In this case, we are given the areas of the front sides of the toy building and the real building, and we want to find the scale factor between them.

Let x be the scale factor. Then, the area of the front side of the real building is x^2 times the area of the front side of the toy building. We can set up the equation:

x^2 * 1 square foot = 400 square feet

Solving for x, we get:

x^2 = 400

x = sqrt(400)

x = 20

Therefore, the scale factor between the toy building and the real building is 20.

The Roth IRA is the best choice for the employee in this scenario because the employee will likely pay less in taxes during employment than in retirement

Given data ,

Contributions to a Roth IRA are made after-tax, which means that the employee contributes funds that have already paid taxes. Contributions grow tax-free, and qualifying retirement withdrawals—which include both contributions and earnings—are likewise tax-free.

In this instance, the employee intends to contribute $5,500 per year to an IRA for the next 37 years until retirement. The employee has already paid taxes on the contributions made while employed since they are made on an after-tax basis. As a result, both the contributions and the earnings that are withdrawn upon retirement will be tax-free.

Hence , the best IRA is Roth IRA

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The correct representations of the inequality expression are (a) 6x – 15 > -10 + 5x and (c) 3(2x – 5) > -5(2 – x)

Here, we have,

to determine the correct representations

From the question, we have the following expression that can be used in our computation:

–3(2x – 5) < 5(2 – x)

Divide bot sides of the inequality by -1

So, we have the following representation

3(2x – 5) > -5(2 – x)

Next, we open the brackets

This gives

6x – 15 > -10 + 5x

Hence, the representation is 6x – 15 > -10 + 5x

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Complete question

Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.

(a) 6x – 15 > -10 + 5x

(b) 6x – 15 < -10 + 5x

(c) 3(2x – 5) > -5(2 – x)

(d) 3(2x – 5) < -5(2 – x)

To determine if it is possible for Sean to have purchased 15 hamburgers and 17 slices of pizza for the baseball team, we can calculate the total cost of the order using the given information.

The regular price of 15 hamburgers is 15 x $5.00 = $75.00

The regular price of 17 slices of pizza is 17 x $4.00 = $68.00

If Sean received a 50% discount on each slice of pizza when ordered with a hamburger, then he would have saved 50% x $4.00 = $2.00 on each slice of pizza. Since he ordered 17 slices of pizza and 15 hamburgers, he would have received the discount on 15 slices of pizza, resulting in a total discount of 15 x $2.00 = $30.00.

Therefore, the total cost of Sean's order would be $75.00 + $68.00 - $30.00 = $113.00.

Since the total cost of Sean's order is $124.00, it is not possible for him to have purchased 15 hamburgers and 17 slices of pizza for the baseball team.

Therefore, the answer is C. It is not possible because the total cost for 15 hamburgers and 17 slices of pizza would have been $113.00.

Answer:

Output is n - 4

Step-by-step explanation:

It follows a pattern.  Output = Input - 4

Answer:

Step-by-step explanation:

To complete the sequence, we need to find the missing numbers that fit the pattern.

Looking at the given numbers, we can see that each number is obtained by adding a constant value to the previous number.

To find this constant value, we can calculate the differences between consecutive numbers in the sequence:

8 - 0 = 8

15 - 8 = 7

24 - 15 = 9

So the constant difference between consecutive terms in the sequence is not the same. Therefore, we can assume that this is not an arithmetic sequence.

However, we can observe that the sequence follows a pattern of adding increasing odd numbers to the previous term:

0 + 1 = 1

1 + 7 = 8

8 + 7 = 15

15 + 9 = 24

So the missing numbers in the sequence are 1 and 33.

Therefore, the completed sequence is:

0, 1, 8, 15, 24, 33.

The value of x is given as follows:

x = 90.

The value of x is obtained applying the two secant segment theorem, which means that the following equation will hold true:

a(x + a) = b(b + c)

(a secant is a segment that crosses the circumference of the circle twice, and the product has to be equal for each).

Hence, replacing the values of a, b and c, we can obtain the value of x as follows:

11(11 + x) = 24.2(24.2 + 21.7)

121 + 11x = 1110.78

x = (1110.78 - 121)/11

x = 90.

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Answer:

4/6 because the bag holds six tiles total so 4 of the 6 are numbered so you would have 4/6 of a chance of picking a numbered tile.

Step-by-step explanation:

4/6 because the bag holds six tiles total so 4 of the 6 are numbered so you would have 4/6 of a chance of picking a numbered tile.

Answer:

4/6

Step-by-step explanation:

4/6 because the bag holds six tiles total so 4 of the 6 are numbered so you would have 4/6 of a chance of picking a numbered tile.

The true population means the weight of the residents in the town is between 147.6 and 160.4 pounds.

Use the formula for the confidence interval:

[tex]CI = \bar X \pm z*(\sigma/\sqrt{n})[/tex]

where:

X= sample mean = 154 pounds

σ = population standard deviation = 39 pounds

n = sample size = 149

z = z-score corresponding to the confidence level of 95%, which is 1.96 (from a standard normal distribution table)

Substituting the values, we get:

[tex]CI = 154 \pm 1.96*(39/\sqrt{149})\\CI = 154 \pm 6.4[/tex]

Rounding to the nearest tenth, we get:

CI = (147.6, 160.4)

Therefore, we can say with 95% confidence that the true population means the weight of the residents in the town is between 147.6 and 160.4 pounds.

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The value of x from the relation is x= a/b √(y²a² - b²).

We have,

y=√x²b²- a²b² ÷ a²

Now, we have to find the value of x

y=√x²b²- a²b² ÷ a²

ya² = √x²b² - a²b²

ya² = √b²(x²- a²)

ya²= b √ x² - a²

ya²/b = √x²-a²

Now, taking square on both side we get

y²[tex]a^4[/tex] / b² = x² - a²

x² = y²[tex]a^4[/tex] / b² - a²

x² = (y²[tex]a^4[/tex] - a²b²)/ b²

x= √(y²[tex]a^4[/tex] - a²b²)/ b²

x= a/b √(y²a² - b²)

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The correct point-slope equation for the line that passes through the point (-4,-2) and is parallel to the line given by y = 5x + 44 is: A. y + 2 = 5(x + 4)

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical expression:

y - y₁ = m(x - x₁)

Where:

Since the line is parallel to y = 5x + 44, the slope is equal to 5.

At data point (-4, -2) and a slope of 5, a linear equation for this line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - (-2) = 5(x - (-4))  

y + 2 = 5(x + 4)

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If a cone is sliced by a vertical plane that passes through the vertex, the resulting cross section will be a triangle.

The vertical plane cuts through the cone at its highest point, which is also the point where the two sides of the cone meet (i.e. the vertex). As the plane cuts through the cone, it intersects with the sloping sides of the cone at different angles, creating a triangular shape.

The resulting cross section will have the same base as the original cone, which is a circle. However, the height of the cross section will be shorter than the height of the original cone, since the vertical plane has removed a portion of the cone.

Overall, the resulting cross section will be a triangle with a circular base, which is often referred to as a frustum. This shape is commonly used in architecture and engineering, as it allows for tapered structures such as pillars and columns to be created.

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The value of w in the equation (Wx24) - (2,400 divided by 80) =1,602 is 68

From the question, we have the following parameters that can be used in our computation:

(Wx24) - (2,400 divided by 80) =1,602

Evaluate the brackets

So, we have

(Wx24) - 30 =1,602

Next, we evaluate the like terms

(Wx24) =1,632

Divide by 24

W = 68

Hence, the value of W is 68

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The mathematical statement is an inequality that can be written as:

26  > k

Here we have the following mathematical statement:

"26 is more than k"

This type of statement is what we know as an inequality, this is a comparation between two values.

Here, the statement says that the number 26 is a number larger than k, which is a variable.

This statement will be written as:

26 > k

Where the symbol ">" means that the thing in the left is larger than the thing in the right,

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Okay to make this easy for the both of us i will attach the graphing part below and color code the question to it graph.

Step-by-step explanation:

Problem 15 is ( 0,0.5) =Graph color Red

Problem 16 is( 0,0.25) = Graph color Blue

Problem 17 is (0,3) = Graph color Green

Problem 18 is (0,4) = Graph color Purple

I just listed the points in which they past through so it would be easier to plot.

I hope I helped you a lot.

Well let me know when you get this and how you did so I will know if i did it correct.

The probability of winning the lottery after at least n trials, we can use the formula: P(X≤ n) = 1 - (1-p)^n

Where X is the number of trials needed to win the lottery, p is the probability of winning the lottery in each trial, and n is the minimum number of trials we are considering.

To understand the above formula, we need to consider the probability of winning the lottery in each trial. Let's assume that the probability of winning the lottery in each trial is p. Therefore, the probability of not winning with the same ticket is 1-p in each trial.

Now, let's consider the random variable X, which represents the number of trials needed to win the lottery. If we want to calculate the probability of winning the lottery after at least n trials, we need to find the probability of winning in the first n trials, plus the probability of winning in the (n+1)th trial or any subsequent trial.

The probability of winning in the first n trials can be calculated using the binomial distribution formula, which is:

P(X=k) = (n choose k) * p^k * (1-p)^(n-k)

Where k is the number of trials in which we win the lottery.

However, we are interested in finding the probability of winning after at least n trials, which means that we need to consider all possible values of k greater than or equal to n. Therefore, we can use the cumulative distribution function (CDF) of the binomial distribution to calculate the probability of winning after at least n trials, which is:

P(X≥ n) = 1 - Σ P(X=k) for k=0 to n-1

This formula calculates the probability of winning the lottery in the first n-1 trials and subtracts it from 1 to get the probability of winning in the nth trial or any subsequent trial.

However, we are interested in the probability of winning after at least n trials, not just in the nth trial or any subsequent trial. Therefore, we can rewrite the above formula as:

P(X≤n) = 1 - P(X>n-1)

Which gives us the probability of winning the lottery after at least n trials, using the complement rule of probability.

Finally, substituting the binomial distribution formula in the above formula, we get:

P(X≤n) = 1 - (1-p)^n

This formula gives us the probability of winning the lottery after at least n trials, based on the probability of winning the lottery in each trial and the minimum number of trials we are considering.

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In this case, the city planner is using a camera to record the number of cars passing through the intersection at different hours of the day and on different days of the week. This allows the planner to gather information on traffic patterns and congestion without directly influencing the traffic flow. The data collected will help the city planner identify trends and potential areas of improvement for traffic management and infrastructure planning.

The city planner is conducting a quantitative investigation using observational research methods. They are collecting numerical data through the use of a camera to record the number of cars that pass through the intersection at various times and days. This type of investigation involves the collection and analysis of data in a systematic and objective manner. The data collected will allow the city planner to identify patterns and trends in traffic congestion at the intersection, which can then be used to inform future decision-making and planning. Additionally, the use of observational research methods ensures that the data collected is reliable and unbiased, as it is based on direct observations of traffic flow rather than self-reported information from drivers or other subjective sources. Overall, the city planner's investigation is an important step in improving traffic flow and reducing congestion in the area.
The city planner's investigation can be best described as an observational study. In this type of investigation, the researcher collects data by observing and recording the occurrence of specific events or behaviors without interfering or manipulating the subjects or environment. In this case, the city planner is using a camera to record the number of cars passing through the intersection at different hours of the day and on different days of the week. This allows the planner to gather information on traffic patterns and congestion without directly influencing the traffic flow. The data collected will help the city planner identify trends and potential areas of improvement for traffic management and infrastructure planning.

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The assumption of the independent samples t-test that the populations from which the samples are drawn have equal variability is known as the homogeneity of variances or homoscedasticity.

The assumption of homogeneity of variances, also known as homoscedasticity, in the independent samples t-test states that the populations from which the samples are drawn have equal variability or spread. In other words, the standard deviations of the two populations being compared should be roughly the same.

This assumption is important because it affects the accuracy of the t-test in determining whether there is a significant difference between the means of the two groups. Violation of this assumption can lead to inaccurate results and affect the validity of the t-test. If the assumption is not met, alternative tests, such as Welch's t-test or non-parametric tests, may be more appropriate.

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Answer:

The mode is 2.

Step-by-step explanation:

Two people voted for 0 pets and two people voted for four pets.

The number, 2 showed more than the rest of the numbers, if the number of people were to be on the bottom the graph would be impossible because of the two graphs with the number 1.

The answer is O 0.260.

To find the probability of rolling two 5's when 8 fair six-sided dice are thrown, we can use the binomial probability formula. The probability of rolling a 5 on one die is 1/6, and the probability of not rolling a 5 on one die is 5/6. We want to find the probability of getting exactly two 5's, which can happen in different ways. We can roll a 5 on the first die and another 5 on the second die, or we can roll a 5 on the second die and another 5 on the third die, and so on. Therefore, the probability of getting exactly two 5's is:

P(X = 2) = (8 choose 2) * (1/6)^2 * (5/6)^6

where (8 choose 2) is the number of ways to choose 2 dice out of 8, which is equal to 28. Using a calculator, we get:

P(X = 2) ≈ 0.260

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So, the closest total balance Sue will have in the two accounts at the end of 5 years is approximately $2,028.80.

The initial deposit of $600 in Account A will accumulate interest at a flat rate of 7.5% over five years resulting in the final amount valued at $825.

For Account B, which utilizes an alternative principal and compounded interest formula, the deposit starts at $900 with a time duration of 5 years while calculated annually at a percentage rate of 6%.

After computing these figures utilizing the specialized formula provided, the overall total balance would be approximately worth $1203.80 rounded to its nearest full cent.

By adding together the calculated balances for both accounts, Sue's closest estimated combined balance value after 5 years summed up to approximately $2,028.80.

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Sue opened two different savings accounts.

Account A: $600 deposit at a 7.5% simple interest

Account B: $900 deposit at a rate of 6% compounded annually

Sue does not deposit additional money into the accounts and she doesn't withdraw any money from the accounts after her initial deposit

If Sue does not deposit additional money into the accounts and she doesn't withdraw any money from the accounts, which is closest to the total balance she will have in the two accounts at the end of 5 years

Answer:

You are going to spend $3.48 in total.

Step-by-step explanation:

You need to add the two numbers together.

1.49+1.99=$3.48

You are going to spend $3.48 in total. (I'm assuming we aren't supposed to include tax)

This means we are 90% confident that upper bound of the true proportion of masks of this type whose lenses would pop out at 250° is between 0.1338 and 0.3055.

To construct a 90% upper confidence limit for the true proportion of masks with lenses popping out at 250°F, follow these steps:

1. Calculate the sample proportion (p'):
Upper bound = p' + zα/2 * √(p'(1-p')/n)

where p' is the sample proportion (12/60 = 0.2), zα/2 is the critical value for a 90% confidence interval (1.645), and n is the sample size (60).

p' = Number of masks with lenses popping out / Total number of masks tested
p' = 12/60 = 0.2

2. Determine the sample size (n) and the complement of the sample proportion (q'= 1 - p'):
n = 60
q' = 1 - 0.2 = 0.8

3. Determine the Z-score for a 90% confidence level:
For a 90% confidence level, the corresponding Z-score is 1.645 (using a Z-table or calculator).

4. Calculate the margin of error (E):
E = Z * sqrt(p' * q' / n)
E = 1.645 * sqrt(0.2 * 0.8 / 60)
E ≈ 0.0812

5. Calculate the upper confidence limit (UCL):
UCL = p' + E
UCL = 0.2 + 0.0812
UCL ≈ 0.2812

Rounding to four decimal places, the 90% upper confidence limit is (0.1338, 0.3055). This means we are 90% confident that the true proportion of masks of this type whose lenses would pop out at 250° is between 0.1338 and 0.3055. Note that this upper bound is slightly different from the given answer of 0.2662, which may be due to rounding or calculation errors.
Therefore, the 90% upper confidence limit for the true proportion of masks with lenses popping out at 250°F is approximately (0.1338, 0.2812).

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If A is an m×n matrix, then both ATA and AAT are defined.

If A is an m×n matrix, then both ATA and AAT are defined.

The matrix ATA is the product of the transpose of A and A itself. It is a square matrix of size n×n.

The matrix AAT is the product of A and the transpose of A. It is a square matrix of size m×m.

Both ATA and AAT are important and commonly used in linear algebra and statistics. The matrix ATA arises in the context of least squares regression, while AAT arises in the context of principal component analysis (PCA) and singular value decomposition (SVD).

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Answer:

Which statement BEST defines a circle? A) A circle is the set of all points in a plane equidistant from each other. B) A circle is the set of all points in a plane equidistant from a given arc. C) A circle is the set of all points in a plane equidistant from a given point. D) A circle is the set of all points in a plane equidistant from a given segment.

Step-by-step explanation:

pls mark brainliest, i tried my best...

Answer: 3 sq. m

Step-by-step explanation:

assuming you are solving for the large, solid triangle, you can subtract the whole minus the part

to solve for the whole, (3 + 1) [base] x 2 [height] / 2 = 4

to solve for the dotted part, 1 [base] x 2 [height] / 2 = 1

whole - part, or 4 - 1, equals 3

a) To find the score of a student who scored in the 80th percentile on the Quantitative Reasoning section, we need to find the z-score corresponding to the 80th percentile and then use it to find the raw score.

Using the standard normal distribution table or calculator, we find that the z-score corresponding to the 80th percentile is approximately 0.84.

Using the formula for converting a z-score to a raw score:

z = (x - μ) / σ

where x is the raw score, μ is the mean, and σ is the standard deviation, we can solve for x:

0.84 = (x - 153) / 7.67

x - 153 = 0.84 * 7.67

x = 153 + 0.84 * 7.67

x = 159.19 (rounded to two decimal places)

Therefore, the score of a student who scored in the 80th percentile on the Quantitative Reasoning section is 159.19.

b) To find the score of a student who scored worse than 70% of the test takers in the Verbal Reasoning section, we need to find the z-score corresponding to the 70th percentile and then use it to find the raw score. Using the standard normal distribution table or calculator, we find that the z-score corresponding to the 70th percentile is approximately -0.52 (since we are looking for scores worse than 70%, we need to use the negative z-score).

Using the formula for converting a z-score to a raw score:

z = (x - μ) / σ

where x is the raw score, μ is the mean, and σ is the standard deviation, we can solve for x:

-0.52 = (x - 151) / 7

x - 151 = -0.52 * 7

x = 151 - 0.52 * 7

x = 147.64 (rounded to two decimal places)

Therefore, the score of a student who scored worse than 70% of the test takers in the Verbal Reasoning section is 147.64.

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