suppose that you drive the 9.7 km from your university to home in 25.5 min. (note: average speed is distance traveled divided by time of travel.) your average speed in km/h is

"I understand how to properly use the PEFM to measure my peak expiratory flow and will use it daily to track my lung function," the newly diagnosed asthmatic states in the statement.

Option B is correct.

A peak flow meter measures how quickly you can expel air from your lungs by blowing as forcefully and quickly as you can. This is what peak flow means.

This drop indicates the possibility of an asthma attack. You can figure out what "triggered" the drop in blood pressure by measuring your peak flow, which medications to add or take off, and when you might need emergency care.

A peak flow meter is simple to use. How to figure out your peak flow:

which statement shows that the newly diagnosed asthma patient understands how to use a peak expiratory flow meter (pefm)?

A. Wear gloves during blood glucose monitoring and during any other procedure that involves potential exposure to blood or body fluids.

B. "I understand how to properly use the PEFM to measure my peak expiratory flow and will use it daily to track my lung function."

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The correct option is B. Earth is the size of the tip of the ballpoint pen about 15 metres away from the Sun.

Radius of the sun = 7× 10⁸ m

Radius of the earth = 6.37 × 10⁶ m

Radius of the grape fruit = 7.6 × 10⁻² m

As the sun is said to be the size of the grapefruit, scale = (7.6 × 10⁻²)/(7× 10⁸) = 10⁻¹⁰

This means the scale is approximately, 1: 10⁻¹⁰

So, the size of the earth = 6.37× 10⁶ ×10⁻¹⁰ = 6.37×10⁻⁴ m (size of ballpoint)

As we know that the distance between the sun and the earth = 14.9 × 10¹⁰ m

So, in our scale, distance between the sun and the earth = 14.9× 10¹⁰× 10⁻¹⁰  = 14.9 m

which is approximately 15 meters.

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If one piece is placed above another, the repulsive force can be great enough to support the top piece's weight.

calculate the magnitude of the charge if electrostatic force?

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The reason for the modest preference for 1/2 kx2 is that you only need to measure one variable—the displacement x—in order to identify the stored energy. Utilizing 1/2 F/x necessitates measuring both displacement and force, which is frequently difficult to do.

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Since parallax is a difference inside this apparent position of an item when viewed along two separate lines of sight, a very wide gap between perspectives (referred to as the baseline) is necessary to detect a parallax shift in a far-off object.

An object's position changing due to your motion is known as parallax. For instance, if you gaze at a close object and tilt your head slightly to the side, the thing appears to be moving back and forth.

One of the most crucial techniques astronomers use to determine distance is parallax. It is incredibly precise but can only be used for close stars. By calculating how close an object is, the technique appears to move against the background of more distant objects.

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In order to calculate the mass of the helicopter, we must first calculate the force of the air resistance.

The mass of the helicopter can be calculated using the formula:

mass = lift force / (acceleration due to gravity x sin(angle of lift force))

mass = 42500 N / (9.81 m/s2 x sin(78.3°))

mass = 4289 kg.

m = F / a

where F is the lift force and a is the acceleration due to gravity (9.81 m/s^2).

Plugging in the given values, the mass of the helicopter can be calculated as:

m = 42500 N / (9.81 m/s^2)

m = 4317.3 kg

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The ball's exit velocity from the boy's hand was 39.4 m/s.

The time it took the ball to reach its highest point is 4 seconds, which is the explanation.

Use the first equation of motion, v = u + gt, to determine the ball's initial velocity when it left the boy's hand.

Initial velocity (v) is used here. terminal velocity is u. t is the amount of time, and g is the gravitational acceleration, with a value of 9.8 m/s2.

At its highest point, the ball's final velocity, v, equals zero.

When the supplied values are substituted in the equation above, we get 0=u-9.8m/s2.

Therefore, the ball's exit velocity from the boy's hand was 39.4 m/s.

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Infants extracting an increasing number of potential word forms from the speech stream they hear, begin to associate these with concrete, perceptually available objects is referred to as statistical learning.

Statistical learning refers to the process by which infants extract potential word forms from the speech stream they hear and begin to associate them with concrete, perceptually available objects. This process is thought to be a crucial component of language development, as it allows infants to begin to understand the structure and meaning of the language they are exposed to.

Through statistical learning, infants are able to identify patterns and regularities in the speech they hear, such as the relationship between a word and the object it refers to. This ability enables them to begin to build a vocabulary and develop an understanding of the grammar and syntax of their native language. Additionally, statistical learning may also play a role in the development of other cognitive abilities, such as memory and attention.

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Your question seems incomplete, but I suppose the question was:

"As infants extract an increasing number of potential word forms from the speech stream they hear, they begin to associate these with concrete, perceptually available objects in their world. this is referred to as"

Power (in watt) will he use to do the same amount of work in three times the time:

m=100 kgg=10 m/sh=10 m

W=mgh=100×10×10=10000 J

P= t/W

10000/20​

=500 W

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Answer:

KE

Explanation:

It has KE only because it is in motion, but 0 GPE because it is on the ground.  For it to have any GPE it would have to be at some height above the ground.

Using wheel clocks is the best option.

To stop an aerial device from moving or chattering on an angled frozen solid surface, wheel chocks are intended to be installed in front of and behind the wheels of the aerial device. The aerial equipment can't move or chatter since the chocks mechanically stop the wheels from rotating. Additionally, they can be utilised to keep the apparatus stable on the surface by adding an additional layer of friction between the ground and the object. Wheel chocks are an efficient way to stop aerial equipment from shifting or chattering on an angled frozen solid surface when used in conjunction with hand stabilisers.

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The velocity of the third piece 2/11. (13 j - 15i)

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The final velocity of plank with respect to the ice will be (-Mg×Vgp)/(Mg+Mp) and it will be in direction opposite to the girl.

Mass of the girl, = Mg

Mass of the plank, = Mp

Velocity of the girl with respect to plank, = Vgp

Velocity of the plank with respect to ice, = Vpi

Velocity of girl with respect to ice, = Vgi

Initially both girl and the plank were at rest with respect to ice, so initial momentum of both was zero. So final momentum of both with respect to ice will be zero.

Mg×Vgi + Mp×Vpi = 0

Mg×Vgi = -Mp×Vpi .....equation (1)

We know that velocity of girl with respect to the ice will be the sum of velocity of the girl with respect to the plank and the velocity of the plank with respect to the ice.

Vgi = Vpi + Vgp.... put this value in equation (1)

Mg×(Vpi + Vgp) = -Mp×Vpi

Mg×Vpi + Mg×Vgp) = -Mp×Vpi

Vpi(Mg + Mp) = -Mg×Vgp

Vpi = -Mg×Vgp/(Mg + Mp)

A negative sign indicates that the velocity of the plank will be in the opposite direction to the girl.

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--The give question is incomplete, the complete question is:

"A girl of mass Mg is standing on a plank of mass Mp. Both are originally at rest on a frozen lake that constitutes a frictionless, flat surface. The girl begins to walk along the plank at a constant velocity Vgp to the right relative to the plank. (The subscript gp denotes the girl relative to the plank.)

What is the velocity Vpi of the plank relative to the surface of the ice? (Use the following as necessary: Vgp, Mg, and Mp. Indicate the direction with the sign of your answer. Let the positive direction be in the direction that the girl walks.)"--

Answer:

Explanation:

he modulus of elasticity (E) can be calculated using the formula:Stress = Force / AreaStrain = Change in length / Initial lengthModulus of Elasticity (E) = Stress / StrainWe have the Force = 8000 N, Area = 0.7 m^2, Change in length = 0.002 m and initial length = 5 in = 0.127 mStress = Force / Area = 8000 N / 0.7 m^2 = 11428.57 N/m^2Strain = Change in length / Initial length = 0.002 m / 0.127 m = 0.0157Modulus of elasticity (E) = Stress / Strain = 11428.57 N/m^2 / 0.0157 = 727,279.9 N/m^2So the modulus of elasticity for the material of the bar is 727,279.9 N/m^2This is the ratio of the applied stress to the corresponding strain within the elastic limit, which is a measure of a material's resistance to deformation.

Answer:

A paradox is a statement, proposition, or situation that seems illogical, absurd or self-contradictory, but which, upon further scrutiny, may be logical or true — or at least contain an element of truth. Paradoxes often express ironies and incongruities and attempt to reconcile seemingly opposing ideas.

Explanation:

hope this help :)

The frequency would be 1/2pi [tex]\sqrt{\frac{pE}{I}}[/tex].

We know that,

Tau=-pEsinФ captures the sense

and the size of the effect.

This is the restoring torque to return the tilted dipoles to their aligned equilibrium position.

If the amplitude of movement is small,

we may replace sinθ with θ in radians.

Thus τ≈−pEθ.

Since this has a simple negative proportionality to the angle of rotation, the dipole oscillates in a simple harmonic motion,

like a torsion pendulum with a torsion constant

κ=pE. In this case, angular frequency ω is given by

ω² = [tex]\frac{k}{I}[/tex] = [tex]\frac{pE}{I}[/tex]

where I denotes thee rotational inertia of the particular dipole. The frequency of oscillation is

f= ω/ 2pi

=  1/2pi [tex]\sqrt{\frac{pE}{I}}[/tex]

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​

​

An object can encounter some resistance when moving through the fluid medium of air.

The drag force is the oppositional force applied by the air to a moving object. The size of the cross section A of the front face of the item, the density of the air, and the square of the object's velocity v all contribute to the drag force.

With motion exclusively in the vertical direction and letting

downward be positive, we have that

dv/dt = g - pv, where g = 32 ft/[tex]s^{2}[/tex], and so

dv/dt + pv = g. The integrating factor is [tex]e^{(pt)}[/tex], so

d/dt([tex]e^{(pt)}[/tex] * v) = g×[tex]e^{(pt)}[/tex] ----->

[tex]e^{(pt)}[/tex] * v = (g/p)*[tex]e^{(pt)}[/tex] + C ----->

v(t) = (g/p) + C×[tex]e^{(pt)}[/tex]

Now v(0) = (g/p) + C = 0, and so C = -g/p, giving us

v(t) = (g/p)×(1 - [tex]e^{(pt)}[/tex]).

Now we are given that lim(t->infinity)(v(t)) = 99 mi/h = 145.2 ft/s,

so since [tex]e^{(pt)}[/tex]-> 0 as t -> infinity we have g/p = 145.2 ft/s ------>

p = 32 ft/s^2 / (145.2 ft/s) = 0.2204 s^-1 .

Next, since we have defined downward as positive, the expression

we have for v(t) will equal dy/dt where y(0) = 0 and y increases as

the paratrooper falls. So

dy/dt = v(t) = (g/p)×(1 - [tex]e^{(pt)}[/tex])), so

y(t) = (g/p)×(t + (1/p)×[tex]e^{(pt)}[/tex]) + K.

Now y(0) = (g/p)×(0 + (1/p)) + K = 0 ----->

K = -(g/p^2) = 32 / 0.2204^2 = -658.76 ft, so

y(t) = (145.2)×(t + (4.5372)×e^(-0.2204×t)) - 658.76.

Next, y(6) =  (145.2)×(6 + (4.5372)×e^(-0.2204×6)) - 658.76 = 444.84 feet.

The computed drag coefficient is substantially higher than anticipated.

The free fall distance is the longest distance an individual can travel in a predetermined amount of time. However, the distance covered in the time frame indicated in the news report is significantly greater than the greatest distance that could be covered. Consequently, the news story is exaggerated.

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The final speed is v and the change in the total kinetic energy is 6mv² (Option B)

The final speed after the collision can be obtained as illustrated below:

Momentum before = momentum after

m₁u₁ + m₂u₂ = v₀(m₁ + m₂)

Divide both sides by (m₁ + m₂)

v₀ = [m₁u₁ + m₂u₂] / (m₁ + m₂)

v₀ = [(2m × 3v) + (4m × 0)] / (2m + 4m)

v₀ = [6mv + 0] / 6m

v₀ = 6mv / 6m

v₀ = v

Thus, the final speed is v

First, we shall determine the total initial kinetic energy. Details below:

KE₁ = ½m₁u₁² + ½m₂u₂²

KE₁ = [½ × 2m × (3v)²] + [½ × 2m × 0²]

KE₁ = [m × 9v²] + 0

KE₁ = 9mv²

Next, we shall determine the total final kinetic energy. Details below:

KE₂ = ½mv²

KE₂ = ½ × 6m × v²

KE₂ = 3mv²

Finally, we shall determine the change in the kinetic energy of the car can be obtained as follow:

Total Initial Kinetic energy (KE₁) = 9mv²

Total final Kinetic energy (KE₂) = 3mv²

Change in total kinetic energy (ΔKE) =?

ΔKE =KE₁ - KE₂

ΔKE = 9mv² - 3mv²

ΔKE = 6mv²

In conclusion,

Thus, the correct answer is Option B

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The skateboard was initially at rest, and by the time of Newton's first law, it would still be in that state. This law asserts that unless acted upon by an external or net force, a body will remain at rest or continue in a condition of uniform motion with constant velocity (in a situation where not only one force is in action).

According to this law, in order to move the skateboard, it needs an external source of force, which the skateboarder indirectly provides.

The skateboarder reverses forward on the pavement (that is he applies a force on the road in a direction opposite the direction of intended motion).

According to Newton's third law, the skateboarder's action results in an equal and oppositely directed reaction from the road on the skateboarder.

According to Newton's third law, action and response are equal but directed in opposite directions. As a result, the road pulls the skateboarder forward in response to this rearward force, which moves both the skateboarder and the skateboard in the same direction.

The acceleration of the cart is inversely related to its mass. As a result, the acceleration of the cart will decrease as its mass increases.

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The new acceleration of the barrel rider if the speed is doubled is 14.4m/s².

Acceleration in physics refers to the amount by which a speed or velocity increases i.e. the change of velocity with respect to time.

The acceleration of a moving body is directly proportional to the speed of that body i.e. an increase in speed equates to an increase in acceleration.

According to this question, a barrel rider is moving in a circle with a speed of 7.0 m/s. The acceleration of the rider is 7.2 m/s². However, the speed of the object is somehow increased to 14.0 m/s.

This suggests that the acceleration of the rider will also be doubled and hence, be 14.4m/s².

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Water has the highest surface tension than ethanol, methanol, or ethanal.

The cohesive nature of a liquid's molecules gives rise to a property of the liquid's surface known as surface tension, which enables the liquid to resist the action of an outside force. After mercury, water has the highest surface tension of any liquid. This is because hydrogen bonds are present in water molecules, which gives water its high surface tension. As a result of water's surface tension, water molecules that are in close proximity to one another at the liquid's surface (where they are in contact with air) stick together to form an invisible film. When water is heated to 25 degrees Celsius, its surface tension is 72 dynes/cm. To crack a film of water on the surface that is one centimeter long and requires 72 dynes of force.

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The wave speed is 01 m/s, which can be calculated by using the formula:

wave speed distance between two successive maxima/time interval between two successive maxima

In this case, the distance between two successive maxima is given as 1.2m and the time

interval between two successive maxima is given as 12s.

So, the wave speed can be calculated as:

wave speed = 1.2m/12s = 0.1 m/s

It is worth mentioning that the wave speed is a scalar quantity, which means it has only magnitude and no direction. The given information is about the transverse wave which is a type of wave in which the oscillation is perpendicular to the direction of energy transfer

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The initial horizontal speed of the proton is 0.16 m/s.

The time of motion of the proton is calculated by applying the following kinematic equation.

t = √ ( 2gh )

where;

t = √ ( 2 x 9.8 x 0.01 )

t = 0.44 second

The initial horizontal speed of the proton is calculated as;

d = Vₓt

Vₓ = d / t

Vₓ = ( 0.07 m ) / ( 0.44 s )

Vₓ = 0.16 m/s

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An electron is moving to the right with an initial speed of vo = 3.5 x 10E7 m/s when it enters a

region of space that is L = 3.3 cm wide with a uniform electric field pointing down of magnitude

E = 8.2E4 N/C. The electron will experience electric field

The electron will experience a force due to the electric field, which is given by the equation F = qE, where q is the charge of the electron (a negative value) and E is the electric field.

The force will cause the electron to accelerate in the direction of the field, which is opposite to its initial direction of motion. The acceleration of the electron can be calculated using the equation a = F/m, where m is the mass of the electron.

The distance the electron will travel before it exits the region of space can be calculated using the equation x = v_0t + 0.5a*t^2, where v_0 is the initial velocity and t is the time it takes for the electron to travel through the region.

Therefore, the correct answer is as given above

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The complete question goes thus:

An electron is moving to the right with an initial speed of vo = 3.5 x 10E7 m/s when it enters a

region of space that is L = 3.3 cm wide with a uniform electric field pointing down of magnitude

E = 8.2E4 N/C. What will happen to the electron?

After colliding, the two objects come to rest together, preserving momentum but not kinetic energy. Some motion energy is transformed to thermal energy, or heat.

A collision occurs in physics when particles, groupings of particles, or solid entities move toward one other and get close enough to interact and exert mutual effect. When two bodies come into direct touch with each other, this is referred to as a collision. The two bodies exert pressures on each other in this situation in a brief period of time. As a result of the collision, the energy and momentum of the bodies involved change. However, there are three types of collisions: elastic, inelastic, and absolutely inelastic. To summarize, momentum is preserved in all three types of collisions. What happens to the kinetic energy is what characterizes the impacts.

Here,

The two objects collide and come to rest together, retaining velocity but not kinetic energy. Some motion energy is converted to thermal energy, often known as heat.

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The maximum possible energy loss of the photon is 2.7 x 10-14 J, which is much less than the energy of the photon, 7.3 x 10-19 J.

To Calculate the energy of the photon.

E = hc/λ

E = (6.626 × 10-34 J · s)(3.00 × 108 m/s)/(29 x 10-12 m)

E = 7.3 x 10-19 J

To Calculate the maximum possible energy loss of the photon.

Max energy loss = 2m el (c2)

Max energy loss = 2(9.11 x 10-31 kg)((3.00 x 108 m/s)2)

Max energy loss = 2.7 x 10-14 J

Compare the energy of the photon and the maximum possible energy loss.

Hence, maximum possible energy loss of the photon is 2.7 x 10-14 J, which is much less than the energy of the photon, 7.3 x 10-19 J.

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At upper temperatures, the thermal conductivity decreases slowly with increasing temperature than depicted by this equation. Aluminum  has the higher temperature change.

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It will take approximately 8.3 minutes for light to travel from the Earth to 1 AU

The speed of light is a constant value of about 300,000 km/sec. To find out how long it will take light to travel to 1 AU (which is about 150 million km), we can use the formula:

Time = distance/speed

So we can substitute the values into the formula:

time = 150 million km / 300,000 km/sec

By solving the equation we get:

time = 500 seconds or approximately 8.3 minutes

Therefore, it will take approximately 8.3 minutes for light to travel from the Earth to 1 AU, which is the average distance between the Earth and the Sun.

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Answer:

Only protons and neutrons contribute to the mass of an atom.

Explanation: