Suppose that Shaun and his friend give Shirley a big shove all at once, applying a force of F=980 N . What is Shirley's acceleration, aS , during this shove? (Take positive values to be to the right.)

Answers

Answer 1

Answer:

a = 17.81 m/s²

Explanation:

Given that,

Shaun and his friend give Shirley a big shove all at once, applying a force of F=980 N

Let us assume that the mass of Shaun and his friend is 55 kg.

Let a is the acceleration during this shove.

The second law of motion is given by :

F = ma

[tex]a=\dfrac{F}{m}\\\\a=\dfrac{980}{55}\\\\=17.81\ m/s^2[/tex]

So, the acceleration of Shirley is 17.81 m/s².


Related Questions

pair of two hollow cups is term as​

Answers

Answer:

Magdeburg hemispheres are a pair of large copper hemispheres, with mating rims.

Explanation:

They were used to demonstrate the power of atmospheric pressure. When the rims were sealed with grease and the air was pumped out, the sphere contained a vacuum and could not be pulled apart by teams of horses.

Magdeburg hemispheres

If 25 kg of ice at 0°C is combined with 4 kg of steam at 100°C, what will be the final equilibrium temperature (in °C) of the system?

Answers

Answer:

The temperature of the final equilibrium temperature of the system is 19.7⁰C

Explanation:

Given;

mass of the ice, m₁ = 25 kg

temperature of the ice =  0°C

mass of the steam, m₂ = 4 kg

temperature of the steam, = 100 ⁰C

Let the temperature of the resulting mixture = t

Apply the principle of conservation of energy.

Heat required to melt the ice + Heat gained by the mixture = Heat required to convert the water to steam + Heat lost by the mixture

[tex]m_1L_f + m_1c (t - 0) = m_2L_v + m_2c(100 - t)[/tex]

where;

Lf is the latent heat of fusion of ice =  3.33 x 10⁵ J/kg.

Lv is the latent heat of vaporization of water, = 2.260 x 10⁶ J/kg

c is the specific heat capacity of water = 4,200 J/kg

[tex]m_1L_f + m_1c (t - 0) = m_2L_v + m_2c(100 - t)\\\\25 \times 3.33\times 10^5 + 25\times 4,200 (t ) = 4\times 2.26\times 10^6 + 4\times 4,200(100 - t)\\\\8,325,000 + 105,000t = 9,040,000 + 1,680,000 - 16,800t\\\\105,000t + 16,800t = 10,720,000 - 8,325,000\\\\121,800t = 2,395,000\\\\t = \frac{2,395,000}{121,800} \\\\t = 19.7 \ ^0 C[/tex]

The temperature of the final equilibrium temperature of the system is 19.7⁰C

Which of the following never cause a change in the motion of an object? O A. Net forces O B. Unbalanced forces C. Balanced forces D. Contact forces​

Answers

Answer:

Hello There!!

Explanation:

The answer is C. Balanced forces.

hope this helps,have a great day!!

~Pinky~

Balanced forces never cause a change in the motion of an object. Hence, option C is correct, rest are not correct.

What is a Balanced Force?

Unless another force is added, forces will always be in balance. The forces are equal, for instance, when the paper, pencil, and pen are set. Selfishly, they push and pull. However, when gravity is added, it pulls the object down, causing it to fall.

When two forces are equal in size and have the same direction, they are said to be balanced. They are thought of as being in an equilibrium state. The motion or direction of an object cannot be changed by balanced forces; instead, they maintain the object's motion at a constant speed.

A force that is exerted in one direction more than it is in the other is said to have imbalanced forces. An object's speed and/or direction change when unbalanced forces are exerting pressure on it.

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Consider two identical stars, A and B. Star B is 10 times farther away than star A. What is the difference in magnitudes between the two stars?

Answers

You can't tell. It depends on other things besides just their distance.

IF the stars are really really "identical", then the magnitude of Star-B is the number that is 6 more than the magnitude of Star-A.

During batting practice, the ballplayer swings his bat with a velocity of 16
m/s. If the bat is 0.7 m long, what is the centripetal acceleration at the end of
the bat? (Ignore the length of the ballplayer's arm.)
A 561.2
B 489.4
C 611.3
D 365.7
in need of help ASAP

Answers

The answer might be B

A single 1,000 kg train car moving at 3.0 m/s collides with the back of two 1,000 kg train cars linked together. It latches onto the car it strikes as the two parts of the coupled cars exert forces on each other. What is the speed of the cars immediately afterward?

1.0 m/s

1.5 m/s

3.0 m/s

0.0 m/s

Answers

I believe the answer is 1.0 m/s

Answer:

Its 1.0 m/s

Explanation:

I checked to quiz

An 88.0 kg sprinter starts a race with an acceleration of 1.60 m/s2. What is the net external force (in N) on him

Answers

Answer:

The correct answer is "140.8 N".

Explanation:

Given:

Mass,

m = 88 kg

Acceleration,

a = 1.60 m/s²

Now,

The net external force for him will be:

⇒ [tex]F_{ext}=Mass\times Acceleration[/tex]

By putting the values, we get

           [tex]=88\times 1.60[/tex]

           [tex]=140.8 \ N[/tex]

A bullet has a mass of 0.0042kg. The muzzle velocity of the bullet coming
out of the barrel of the rifle is 993m/s. What is the KE of the bullet as it
exits the gun barrel?

Answers

Answer:

KE= 1/2mv^2= 1/2*0.0042kg*993m/s= 2.0853joule

In movies, there are explosions in space with fire and smoke but there is no oxygen in space. What is wrong? What would really happen ?

Answers

Answer:

For an explosion with fire to occur, there must be a combustion of oxygen, and there is no oxygen in space, so that would be the mistake.

So it is NOT possible to say that in space there can be explosions. And what really happened would be the non-existence of this phenomenon in that place.

Two students are debating about the nature of light:a.Student 1: Looking at the chart, I see that light with a shorter wavelength has the highest frequency. But all light has the same speed.b.Student 2: I disagree with your Student 1. If light has a higher frequency, then it will have a faster speed than light with a lower energy.

Answers

Answer:

student 1 is right and student 2 is wrong

Explanation:

In the graph that the two students are observing is a graph of energy and frequency vs. wavelength, this graph is constructed using the relationship between a wave and its wavelength and frequency.

          c = λ f

therefore for all waves we have the speed salami.

Therefore student 1 is right and student 2 is wrong

What is the rate at which distance changes called

Answers

Answer:

a yard

Explanation:

FORCE AND DISPLACEMENT AT AN ANGLE A sailor pulls a boat a distance of 30.0 m along a dock using a rope that makes a 25.0° angle with the horizontal. How much work does the rope do on the boat if its tension is 255 N?​

Answers

Answer: 6117.58 J

Explanation:

We know that W=Fd*cos(theta) where theta is the angle between the displacement and the force.

In this case, we are given that F=225 N, d=30 m, and theta=25 degrees.

Plugging all this in we get

W=225*30*cos(25)=6117.58 J

Work done by the rope when sailor pulls the boat in the dock is 6930.9 J

What is work ?

The work is defined by the product of force and displacement. Its standard formula is,

[tex]W = F.d.Cos\alpha[/tex]

Here F is force, d is displacement and α is angle subtended by force from horizontal.

As given in the question,

      F = 255N, d = 30m, α = 30°

On putting in the above formula

      W = 255×30×Cos30°  

           =7650×0.906

           = 6930.9 J

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Which image illustrates the absorption of a wave as it strikes a surface?

Answers

Answer: I think D

Explanation:

Answer:

Correct option is (C) . D

Explanation

In diagram D the ray incidents on the surface but it does not reflected.It is clear that surface absorbed the ray.Surface may be perfect black body that has absorbed incident ray.What is black body ?

A surface that absorbs all the incident rays or radiation , is called black body . Platinum black can be taken as a perfect black body with the 98% absorption.

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Which of the following statements best describes energy conservation in heat engines?

A. The heat engine's energy is exhausted to the outside system.

B. The sum of the heat placed into the hot reservoir and the work collected equals the energy transferred from the cold reservoir.

C. A volume of heat is discharged to the cold body where some waste energy is in a form of heat in this engine.

D. The work derived from the heat engine is equal to the energy placed into the hot reservoir. ​

Answers

B is the correct answer

It is important to use the correct drying tempture because it prevents shrinkage and will not damage the garment.
True or False

Answers

Answer:

fjowe

Explanation:

kbegtrf3g4ef j3kq4ef 3w4beysrf2w4er8f6ywgbaebf7v2wy4egdwa4i6e5

This answer is true.

write the chemical equation of rust ​

Answers

ANSWER

4Fe+ 3O2 → 2Fe2O.

EXPLANATION

iron (Fe) combines with oxygen (O2) to form rust, or iron oxide (Fe2O3). The equation for this reaction is: 4Fe+ 3O2 → 2Fe2O.

The answer is O2+Fe+H20—>Fe2O3H20

amount of pressure of liquid increases with ?​

Answers

Answer: Pressure increases as the depth increases.

Answer:

depths cause it help it with a lot and that it the answer

Which nucleus completes the following equation?

Answers

Answer:

Option D. ²⁰⁸₈₄Po

Explanation:

From the question given above, the following data were obtained:

²¹²₈₆Rn —> ⁴₂He + ?

Let the unknown be ⁿₓD. Thus, the equation becomes:

²¹²₈₆Rn —> ⁴₂He + ⁿₓD

Next, we shall determine n, x and D. This can be obtained as follow:

212 = 4 + n

Collect like terms

212 – 4 = n

208 = n

n = 208

86 = 2 + x

Collect like terms

86 – 2 = x

84 = x

x = 84

ⁿₓD => ²⁰⁸₈₄D = > ²⁰⁸₈₄Po

²¹²₈₆Rn —> ⁴₂He + ²⁰⁸₈₄Po

Thus, option D gives the correct answer to the question.

A hair dryer is supplied with 900 coulombs of charge per minute.
What is the current in amperes?

Answers

That’s would be 900 amperes.

A package of mass m is released from rest at a warehouse loading dock and slides down a 3.0-m-high frictionless chute to a waiting truck. Unfortunately, the truck driver went on a break without having removed the previous package, of mass 2m, from the bottom of the chute. Suppose the packages stick together. What is their common speed after the collision

Answers

Answer:

The speed of combined package after the collision is [tex]\frac{\sqrt(2gh)}{4}\\[/tex].

Explanation:

mass of first package = m

height , h = 3 m

mass of second package = 3 m

let the speed of first package is u as it strikes with the second package.

Use the third equation of motion

[tex]v^2 = u^2 + 2 gh \\\\u^2 = 0 + 2 g h \\\\u = \sqrt {2gh}[/tex]

Let the velocity of combined package after the collision is v.

Use the conservation of momentum

[tex]m\times u + 3m \times 0= (m + 3m)\times v\\\\m u = 4mv \\\\v=\frac {u}{4}\\\\v = \frac{\sqrt(2gh)}{4}\\\\[/tex]

While an object is in projectile motion (with upward being positive) with no air resistance ct is in projectile motion (with upward being positive) with no air resistance, Group of answer choices the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g. the vertical component of its velocity remains constant and the vertical component of its acceleration is equal to -g the horizontal component of its velocity remains constant and the horizontal component of its acceleration is equal to -g the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to zero. the vertical component of both its velocity and its acceleration remain constant.

Answers

Answer:

The horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g.

Explanation:

This is because, the projectile has both vertical and horizontal components of velocity. But, its vertical component of velocity changes as the object moves whereas, its horizontal component of velocity remains constant.

Also, the projectile has only vertical component of acceleration and no horizontal component of acceleration since, its horizontal component of velocity remains constant. Thus, no change in the horizontal component of velocity.

The vertical component of acceleration is equal to -g since, the weight is the only vertical force acting on it.

So, the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g.

What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wavelength of 555 nmnm

Answers

Answer:

The minimum thickness of soap film is [tex]2.086\times 10^{-7} m[/tex].

Explanation:

wavelength = 555 nm

refractive index, n = 1.33

For the destructive interference,

the thickness is given by

[tex]t =\frac{m \lambda }{2 n}[/tex]

Here, m is the order, n is the refractive index and [tex]\lambda[/tex] is the wavelength.

For minimum thickness, m = 1

So the thickness is  

[tex]t =\frac{1 \times 555\times 10^{-9} }{2 \times 1.33}\\\\t = 2.086\times 10^{-7} m[/tex]

A air glider of mass 1.0 kg that is equipped with a spring bumper travels at a speed of 2.5 m/s toward a second stationary glider of mass 0.75 kg. What is the final speed of the 0.75 kg cart

Answers

Answer:

the final speed of the 0.75 kg cart is 2.86 m/s

Explanation:

Given;

mass of the air glider, m₁ = 1.0 kg

initial speed of the air glider, u₁ = 2.5 m/s

mass of the stationary cart, m₂ = 0.75 kg

initial speed of the stationary cart, u₂ = 0

Let the final speed of the stationary cart = v₂

Also, let the final speed of the air glider = v₁

Since the air glider has a spring bumper, the collision will be elastic.

Apply the following principle of conservation of linear momentum for elastic collision.

m₁u₁  +  m₂u₂  = m₁v₁   +   m₂v₂

(1 x 2.5)  + 0.75(0)  =  v₁   +  0.75v₂

2.5 = v₁  +  0.75v₂

v₁ = 2.5 - 0.75v₂ ----------- (1)

Apply one-dimensional velocity concept since the collision occured in one direction;

u₁ + v₁  = u₂  +  v₂

2.5  +  v₁   = 0   +  v₂

v₁ = v₂  - 2.5 ----- (2)

solve (1) and (2) together;

v₂  - 2.5 = 2.5 - 0.75v₂

v₂ + 0.75v₂ = 2.5  +  2.5

1.75v₂ = 5

v₂ = 5 / 1.75

v₂ = 2.86 m/s

Therefore, the final speed of the 0.75 kg cart is 2.86 m/s

Plz help!! WILL MARK BRAINLIEST :)
Which forces are easier to anticipate and
design for, internal or external? Why do
you think this is so?

Answers

Answer:

The external forces such as wind, water and the vibration of the earth when an earthquake happens create internal forces within a structure. Internal forces such as shear, tension and compression can destroy the inner framework of a building or a bridge even though it is made of super strong steel and concrete.

I Hope This Will Help You ...

A violinist is tuning her violin to 440Hz. She plays the note while listening to an electronically generated tone and hears 3Hz, which increases to 4Hz when she tightens the violin. What was the frequency of the note played by the violin when she heard the 3 Hz beats

Answers

Answer:

[tex]X=438Hz[/tex]

Explanation:

From the question we are told that:

Beat Frequency [tex]Fb=440Hz[/tex]

Actual Frequency [tex]F_a=3Hz[/tex]

Generally the equation for Frequency Heard X is mathematically given by

[tex]X=beat\ frequency\ +\ actual\ frequency[/tex]

[tex]X=F_a+Fb[/tex]

[tex]X= 440Hz+3Hz[/tex]

[tex]X=438Hz[/tex]

If, for a given velocity, the maximum range is at a projection angle of 45, then there must be equal ranges for angles above and below this. Show this explicitly.

Answers

Explanation:

The range R of a projectile is given by

[tex]R = \frac{v_0^2}{g} \sin 2\theta[/tex]

The maximum range [tex]R_{max}[/tex] occurs when [tex]\sin 2\theta = 1\:\text{or}\:\theta = 45°[/tex]. Let [tex]\alpha[/tex] be the angle above or below 45°. Now let's look at the ranges brought about by these angle differences.

Case 1: Angle above 45°

We can write the range as

[tex]R_+ = \dfrac{v_0^2}{g} \sin 2(45° + \alpha)= \dfrac{v_0^2}{g} \sin (90° + 2\alpha)[/tex]

[tex]\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} (\sin 90° \cos 2\alpha + \cos 90° \sin 2\alpha)[/tex]

[tex]\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} \cos 2\alpha\:\:\:\:\:(1)[/tex]

Case 2: Angle below 45°

We can write the range as

[tex]R_- = \dfrac{v_0^2}{g} \sin 2(45° - \alpha)= \dfrac{v_0^2}{g} \sin (90° - 2\alpha)[/tex]

[tex]\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} (\sin 90° \cos 2\alpha - \cos 90° \sin 2\alpha)[/tex]

[tex]\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} \cos 2\alpha\:\:\:\:\:(2)[/tex]

Note that the equations (1) and (2) are identical. Therefore, the ranges are equal if they differ from 45° by the same amount.

Explain the phenomenon and change in potential energy

Answers

Answer:

Explanation:

The change in potential is then defined as the negative of the work done by that force. ... You can't have work done by gravity AND a change in gravitational potential energy. You have to do it one way or the other. This means that the most important step in solving work-energy problems is choosing a system.

the phenomenon is An object that has potential energy can transfer that energy into kinetic energy when the object begins to move, due to its mass or position. For example, a person jumping on a trampoline has potential energy when they reach the peak of a jump, and their force changes direction from upward to downward.

A stretched rubber band is an example of which type potential energy

Answers

Answer: elastic potential energy

Explanation:

Answer:

Elastic potential energy

Explanation:

A stretched rubber band has the potential to do work or change things. This form of energy is called elastic potential energy.

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#keep learning!!

An engineer carries a set of titanium rods, each with a length of and mass of , up a ladder from the floor of a fabrication facility. He sets them down on an overhead walkway above the floor. Unfortunately, as soon as he does of the rods roll off the walkway and fall to the floor. The engineer climbs back down and brings the fallen rods back up to the walkway. Calculate the change in gravitational potential energy of the engineer's set of rods

Answers

Answer:

0.0512 kJ

Explanation:

From the given information, since the values were not given:

Then, Let assume that:

A set of 50 titanium rods is handled by the engineer, with 50cm length and 20g of mass.

The overhead walkway = 5.3 m

In this process, 12 rods roll of the walkway

We are to determine the change in the Gravitational P.E

Change in P.E = final P.E- initial P.E

Change in P.E = (50 mgh) - (0)

Change in P.E =  [tex](50\times \dfrac{20}{1000}\times 9.8 \times 5.3 )-0[/tex]

Change in P.E =  51.94 Joules

Change in P.E = 0.05194 Joules

Change in P.E ≅ 0.0512 kJ

Phosphorus (P) is an element with an atomic number of 15 and an atomic mass of 31. How many neutrons are in an atom of phosphorus? A.15 B.16 C.31 D.46​

Answers

(31-15 = 16).

Explanation:

the element phosphorus (P) has an atomic number of 15 and a mass number of 31. Therefore, an atom of phosphorus has 15 protons, 15 electrons, and 16 neutrons

Phosphorus (P) is an element with an atomic number of 15 and an atomic mass of 31, there are 16 neutrons in an atom of phosphorus, therefore the correct answer is option B

What is the atomic number?

The total number of protons present in an atom is known as the atomic number of that atom. The atomic number has no correlation either with the number of neutrons or the number of electrons present inside an atom.

As given in the problem Phosphorus (P) is an element with an atomic number of 15 and an atomic mass of 31

Total number of proton in phosphorus = 15

Total number of neutrons in the phosphorus = atomic mass - atomic number

Total number of neutrons in the phosphorus =31 -15

Total number of neutrons in the phosphorus  = 16

Thus, the total number of neutrons in a phosphorus atom would be 16, therefore the correct answer is option B

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