Suppose that a random sample of 20 items is selected from the machine. If the machine produces 5% defectives, find the probability that the sample will contain at least three defectives, by using the following methods. (a) the normal approximation to the binomial (Round your answer to four decimal places.) (b) the exact binomial tables (Round your answer to three decimal places.)

Answers

Answer 1

Answer:

a) 0.0618 = 6.18% probability that the sample will contain at least three defectives.

b) 0.076 = 7.6% probability that the sample will contain at least three defectives

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

Sample of 20 items is selected from the machine.

This means that [tex]n = 20[/tex]

5% defectives

This means that [tex]p = 0.05[/tex]

(a) the normal approximation to the binomial

The mean is:

[tex]\mu = E(X) = np = 20*0.05 = 1[/tex]

The standard deviation is:

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20*0.05*0.95} = 0.9747[/tex]

The probability is, using continuity correction, [tex]P(X \geq 3 - 2.5) = P(X \geq 2.5)[/tex] , which is 1 subtracted by the pvalue of Z when X = 2.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{2.5 - 1}{0.9747}[/tex]

[tex]Z = 1.54[/tex]

[tex]Z = 1.54[/tex] has a pvalue of 0.9382

1 - 0.9382 = 0.0618

0.0618 = 6.18% probability that the sample will contain at least three defectives.

(b) the exact binomial tables

This is:

[tex]P(X \geq 3) = 1 - P(X < 3)[/tex]

In which

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{20,0}.(0.05)^{0}.(0.95)^{20} = 0.358[/tex]

[tex]P(X = 1) = C_{20,1}.(0.05)^{1}.(0.95)^{19} = 0.377[/tex]

[tex]P(X = 2) = C_{20,2}.(0.05)^{2}.(0.95)^{18} = 0.189[/tex]

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.358 + 0.377 + 0.189 = 0.924[/tex]

[tex]P(X \geq 3) = 1 - P(X < 3) = 1 - 0.924 = 0.076[/tex]

0.076 = 7.6% probability that the sample will contain at least three defectives


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Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

tinyurl.com/wpazsebu

which is the following is true about the graph of linear inequalities?
a.)it is a line
b.)it is a parabola
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Answers

Answer:

d.) half-plane..

Reason:

A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality. The boundary line is dashed for > and < and solid for ≤ and ≥. The half-plane that is a solution to the inequality is usually shaded.

Which expression is equivalent to -6(3x-3)?
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Answers

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Write the left side of the identity in terms of sine and cosine. Rewrite the numerator and denominator separately. ​(Do not​ simplify.) Simplify the fraction from the previous step such that both the fractions have the common denominator The expression from the previous step then simplifies to using​ what? A. Addition and a Reciprocal Identity B. Addition and a Pythagorean Identity

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Answer:

[tex](a)[/tex] [tex]\frac{2}{cos\theta}/\frac{1}{sin\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

[tex](b)[/tex] [tex]\frac{2sin\theta}{cos\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

(c) Addition and Quotient identity

Step-by-step explanation:

Given

[tex]\frac{2sec\theta}{csc\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex] --- The expression missing from the question

Solving (a): Write the left hand side in terms of sin and cosine

In trigonometry:

[tex]sec\theta = \frac{1}{cos\theta}[/tex]

and

[tex]csc\theta = \frac{1}{sin\theta}[/tex]

So, the expression becomes:

[tex]\frac{2 * \frac{1}{cos\theta}}{\frac{1}{sin\theta}} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

[tex]\frac{\frac{2}{cos\theta}}{\frac{1}{sin\theta}} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

Rewrite as:

[tex]\frac{2}{cos\theta}/\frac{1}{sin\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

Solving (b): Simplify

[tex]\frac{2}{cos\theta}/\frac{1}{sin\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

Change / to *

[tex]\frac{2}{cos\theta}*\frac{sin\theta}{1} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

[tex]\frac{2sin\theta}{cos\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

Solving (c): The property used

To do this, we need to further simplify

[tex]\frac{2sin\theta}{cos\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

Take LCM

[tex]\frac{2sin\theta+ 4sin\theta}{cos\theta} =6tan\theta[/tex]

Add the numerator

[tex]\frac{6sin\theta}{cos\theta} =6tan\theta[/tex]

Apply quotient identity

[tex]\frac{sin\theta}{cos\theta} = tan\theta[/tex]

This gives

[tex]\frac{6sin\theta}{cos\theta} = 6tan\theta[/tex]

Hence, the properties applied are:

Addition and Quotient identity

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Answer:

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Step-by-step explanation:

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Answer:

True.

We can see that the line goes through (0, 0), however, the line is not dotted, therefore that point is included. (0,0) also coincides with the other inequality, which means that (0, 0) is a solution.

The sum of the ages of two brothers is 38. in four years ago the age of the elder brother was the square of the younger brother. Find their ages

Answers

Answer:

Elder brother: 25

Younger brother: 5

Step-by-step explanation:

38 - (4+4)= 30

Now trial all square numbers

e.g 2 + 4 = 6 (does not work)

5 + (5x5)= 30

The elder brother is 25 years old and the younger brother is 5 years old.

write an equation of the line that passes through the given point and has the given slope (6,4) slope -3/4

Answers

Answer:

Its slope is

m = -1/(1/2) = -2

y = -2x + b

Get b from the given point.

-4 = -2(6) + b

b = 8

y = -2x + 8

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given slope (m) = -3/4

and x1 = 6

and y1 = 4


Solve for b (y2) using x2 = 0.
m = -3/4 = (y2-y1)/(x2-x1)

-3/4 = (4-y1)/(6-0)

-3/4 = (4-y1)/6

-(3/4)*6 = 4 - y1

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therefore the correct answer should be:

Equation of the line:

y = -3/4x + 8 1/2

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Answers

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Beryllium is an extremely lightweight metal that is used in many industries, such as aerospace and electronics. Long-term exposure to beryllium can cause people to become sensitized. Once an individual is sensitized, continued exposure can result in chronic beryllium disease, which involves scarring of the lungs. In a study of the effects of exposure to beryllium disease, which involves scarring of the lungs. In a study of the effects of exposure to beryllium, workers were categorized by their duration of exposure (in years) and by their disease status (diseased, sensitized, or normal.) The results were as follows:

Duration of Exposure
< 1 1 to < 5 >= 5
Diseased 12 10 18
Sensitized 14 18 13
Normal 66 142 210

Required:
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b. Compute the expected frequencies of sensitized workers.
c. How many degrees of freedom are there?

Answers

Answer:

1. Has been answered below

2. Degree of freedom is 4

Step-by-step explanation:

Row 1: 12+10+18 = 40

Row 2: 14+18+13 = 45

Row 3: 66+142+210 = 418

Grand total = 40+45+418 = 503

Column 1 : 12+14+66 = 92

Column 2: 10+18+142 = 170

Column 3: 18+13+210 = 241

Total = 92+170+241 = 503

Expected frequencies of diseased workers

92x40/503 = 7.316

170x40/503 = 13.52

241 x 40/503 = 19.165

Expected frequencies of sensitized workers

92x45/503 = 8.23

170x45/503 = 15.20

241x 45/503 = 21.56

2.

Degree of freedom

= (Number of row -1)(number of column - 1)

= 3-1 * 3-1

= 2x2

= 4

Need help please thanks

Answers

Answer:

6.

Just count the x's on the graph...

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Robin weighs her math textbook and finds that it is 2 kilograms. How many grams does her textbook weigh?

Answers

Answer:

2000

Step-by-step explanation:

1 kilogram is 100 grams therefore 2 kilo grams is equal to 2000 grams

The word kilo means thousand in Greek and i think French

:)

Answer:

2,000 grams :)

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Answers

Answer:

k = 5/2

Step-by-step explanation:

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Answer:

[tex]\huge\boxed{\tt{\frac{8}{63} }}[/tex]

Step-by-step explanation:

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~AH1807

If the polygon is translated 3 units down and 4 units left, what will the coordinates of the new image be? Use prime notation in expressing the new coordinates.

Answers

Answer:

A' (-2,-4) B' (-3,-7) C' (-1,-8) D' (1,-6)

Step-by-step explanation:

Just take it one point at a time and move each point down 3 and 4 left. Prime notation just means to put this little sign ' so it indicates that this is the new coordinate. So A was (2,-1) and A' (the new one) is (-2,-4)

✎Question:Amirah is 4 years elder than Priya and Shirley is 2 years younger than Priya. If the sum of their ages is 47, find their respective ages ✔​

Answers

Answer:

Priya's age = 15

Amirah's age = 19

Shirley's age = 13

Step-by-step explanation:

Let x be the age of Priya.

According to the question,

Amirah's age = x + 4

Shirley's age = x - 2

Their sum is 47.

So,

x + 4 + x + x - 2 = 47

3x + 2 = 47

3x = 47 - 2

3x = 45

x = 45/3

x = 15

So,

Priya's age = 15

Amirah's age = 15 + 4 = 19

Shirley's age = 15 - 2 = 13

Answer:

Priya is 15 years old

Amirah is 19 years old and

Shirley is 13 years old

Step-by-step explanation:

let Amirah =x

let Priya = y

let Shirley = s

so we have

x= 4+y

s=y-2

x+y+s =47

we have x= 4+y

4+y+y+s=47

4+2y+s=47

2y+s=43

s-y=-2 (MULTIPLY BY NEGATIVE 1)

y-s =2

2y+s= 43

by solving simultaneously we get

3y= 45

y=15

x= 4+y

x=19

s=y-2

s= 13

so Priya is 15 years old

Amirah is 19 years old and

Shirley is 13 years old

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Answers

Thank you hope this helps see photo

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Answers

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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7

Step-by-step explanation:

free BRAINLESS it could be youea​

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C is right I thinkkkk

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Paul asked four friends how many hours of tv they watch and their grade on a recent test

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Answers

Answer:

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Step-by-step explanation:

The reflection of the point (x, y) across the x-axis is the point (x, -y).

Translate right 4- add 4 to the x coordinate

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T ( 0 , -2)     T' (0, 2)       T" ( 4 , 2)

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Answers

Answer:

$51.63

Step-by-step explanation:

Joe spent 5 days on the trip and spent $258.14 total on food. To find the cost for each day, divide 258.14 by 5.

258.14 / 5 ≈ 51.63

Solve the following question:
 
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Answers

Answer is in the photo. I can only upload it to a file hosting service. link below!

tinyurl.com/wpazsebu

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