Answer:
the clock rate of the first machine need to be 1.7 GHz
Explanation:
Given:
CPI of A = 1.9
CPI of B = 1.1
machine, B executes the same program with 20% less instructions and with a CPI of 1.1 at 800MHz
To find:
In order for the two machines to have the same performance, what does the clock rate of the first machine need to be
Solution:
CPU execution time = Instruction Count * Cycles per Instruction/ clock rate
CPU execution time = (IC * CPI) / clock rate
(IC * CPI) (A) / clock rate(A) = (IC * CPI)B / clock rate(B)
(IC * 1.9) (A) / clock rate(A) = (IC * (1.1 * (1.0 - 0.20)))(B) / 800 * 10⁶ (B)
Notice that 0.20 is basically from 20% less instructions
(IC * 1.9) / clock rate = (IC * (1.1 * (1.0 - 0.20))) / 800 * 10⁶
(IC * 1.9) / clock rate = (IC*(1.1 * ( 0.8))/800 * 10⁶
(IC * 1.9) / clock rate = (IC * 0.88) / 800 * 10⁶
clock rate (A) = (IC * 1.9) / (IC * 0.88) / 800 * 10⁶
clock rate (A) = (IC * 1.9) (800 * 10⁶) / (IC * 0.88)
clock rate (A) = 1.9(800)(1000000) / 0.88
clock rate (A) = (1.9)(800000000) / 0.88
clock rate (A) = 1520000000 / 0.88
clock rate (A) = 1727272727.272727
clock rate (A) = 1.7 GHz
In a system where Round Robin is used for CPU scheduling, the following is TRUE when a process cannot finish its computation during its current time quantum? The process will terminate itself. The process will be terminated by the operating system. The process's state will be changed from running to blocked. None of the mentioned.
Answer:
B. The process will be terminated by the operating system.
Explanation:
When Round Robin is used for CPU scheduling, a time scheduler which is a component of the operating system is used in regulating the operation. A time limit is set for each of the processes to be run.
So, when a process fails to complete running before its time elapses, the time scheduler would log it off and return it to the queue. This queue is in a circular form and gives each of the processes a chance to run its course.
Based on the information given regarding CPU scheduling, the correct option is C. The process's state will be changed from running to blocked.
It should be noted that in a system where Round Robin is used for CPU scheduling, when a process cannot finish its computation during its current time quantum, the process's state will be changed from running to blocked.
It should be noted that a prices transition to a blocked state occurs when it's waiting for some events like a particular resource becoming available.
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(1) Prompt the user to enter a string of their choosing. Output the string.
Ex: Enter a sentence or phrase: The only thing we have to fear is fear itself. You entered: The only thing we have to fear is fear itself.
(2) Complete the GetNumOfCharacters() function, which returns the number of characters in the user's string. Use a for loop in this function for practice. (2 pts)
(3) In main(), call the GetNumOfCharacters() function and then output the returned result. (1 pt) (4) Implement the OutputWithoutWhitespace() function. OutputWithoutWhitespace() outputs the string's characters except for whitespace (spaces, tabs). Note: A tab is '\t'. Call the OutputWithoutWhitespace() function in main(). (2 pts)
Ex: Enter a sentence or phrase: The only thing we have to fear is fear itself. You entered: The only thing we have to fear is fear itself. Number of characters: 46 String with no whitespace: The only thing we have to fear is fear itself.
Answer:
See solution below
See comments for explanations
Explanation:
import java.util.*;
class Main {
public static void main(String[] args) {
//PrompT the User to enter a String
System.out.println("Enter a sentence or phrase: ");
//Receiving the string entered with the Scanner Object
Scanner input = new Scanner (System.in);
String string_input = input.nextLine();
//Print out string entered by user
System.out.println("You entered: "+string_input);
//Call the first method (GetNumOfCharacters)
System.out.println("Number of characters: "+ GetNumOfCharacters(string_input));
//Call the second method (OutputWithoutWhitespace)
System.out.println("String with no whitespace: "+OutputWithoutWhitespace(string_input));
}
//Create the method GetNumOfCharacters
public static int GetNumOfCharacters (String word) {
//Variable to hold number of characters
int noOfCharactersCount = 0;
//Use a for loop to iterate the entire string
for(int i = 0; i< word.length(); i++){
//Increase th number of characters each time
noOfCharactersCount++;
}
return noOfCharactersCount;
}
//Creating the OutputWithoutWhitespace() method
//This method will remove all tabs and spaces from the original string
public static String OutputWithoutWhitespace(String word){
//Use the replaceAll all method of strings to replace all whitespaces
String stringWithoutWhiteSpace = word.replaceAll(" ","");
return stringWithoutWhiteSpace;
}
}
A____server translates back and forth between domain names and IP addresses.
O wWeb
O email
O mesh
O DNS
Answer:
DNS
Explanation:
Hope this helps
the language is Java! please help
public class Drive {
int miles;
int gas;
String carType;
public String getGas(){
return Integer.toBinaryString(gas);
}
public Drive(String driveCarType){
carType = driveCarType;
}
public static void main(String [] args){
System.out.println("Hello World!");
}
}
I'm pretty new to Java myself, but I think this is what you wanted. I hope this helps!
A have a string, called "joshs_diary", that is huge (there was a lot of drama in middle school). But I don't want every one to know that this string is my diary. However, I also don't want to make copies of it (because my computer doesn't have enough memory). Which of the following lines will let me access this string via a new name, but without making any copies?
a. std::string book = joshs_diary;
b. std::string & book = joshs_diary; const
c. std::string * book = &joshs_diary;
d. std::string book(joshs_diary);
e. const std::string & book = joshs_diary;
f. const std::string * const book = &joshs_diary;
g. std::string * book = &joshs_diary;
Answer:
C and G
Explanation:
In C language, the asterisks, ' * ', and the ampersand, ' & ', are used to create pointers and references to pointers respectively. The asterisks are used with unique identifiers to declare a pointer to a variable location in memory, while the ampersand is always placed before a variable name as an r_value to the pointer declared.
What is the maximum number of VLANs that can be configured on a switch supporting the 802.1Q protocol? Why?
Answer:
4096 VLANs
Explanation:
A VLAN (virtual LAN) is a group of devices on one or more LAN connected to each other without physical connections. VLANs help reduce collisions.
An 802.1Q Ethernet frame header has VLAN ID of 12 bit VLAN field. Hence the maximum number of possible VLAN ID is 4096 (2¹²). This means that a switch supporting the 802.1Q protocol can have a maximum of 4096 VLANs
A lot of VLANs ID are supported by a switch. The maximum number of VLANs that can be configured on a switch supporting the 802.1Q protocol is 4,094 VLANS.
All the VLAN needs an ID that is given by the VID field as stated in the IEEE 802.1Q specification. The VID field is known to be of 12 bits giving a total of 4,096 combinations.But that of 0x000 and 0xFFF are set apart. This therefore makes or leaves it as 4,094 possible VLANS limits. Under IEEE 802.1Q, the maximum number of VLANs that is found on an Ethernet network is 4,094.
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Write a program that reads in 10 numbers from the user and stores them in a 1D array of size 10. Then, write BubbleSort to sort that array – continuously pushing the largest elements to the right side
Answer:
The solution is provided in the explanation section.
Detailed explanation is provided using comments within the code
Explanation:
import java.util.*;
public class Main {
//The Bubble sort method
public static void bb_Sort(int[] arr) {
int n = 10; //Length of array
int temp = 0; // create a temporal variable
for(int i=0; i < n; i++){
for(int j=1; j < (n-i); j++){
if(arr[j-1] > arr[j]){
// The bubble sort algorithm swaps elements
temp = arr[j-1];
arr[j-1] = arr[j];
arr[j] = temp;
}
}
}
}
public static void main(String[] args) {
//declaring the array of integers
int [] array = new int[10];
//Prompt user to add elements into the array
Scanner in = new Scanner(System.in);
//Use for loop to receive all 10 elements
for(int i = 0; i<array.length; i++){
System.out.println("Enter the next array Element");
array[i] = in.nextInt();
}
//Print the array elements before bubble sort
System.out.println("The Array before bubble sort");
System.out.println(Arrays.toString(array));
//Call bubble sort method
bb_Sort(array);
System.out.println("Array After Bubble Sort");
System.out.println(Arrays.toString(array));
}
}
How has the rise of mobile development and devices impacted the IT industry, IT professionals, and software development
Answer:
Throughout the interpretation section elsewhere here, the explanation of the problem is summarized.
Explanation:
The growth of smartphone production and smartphone apps and services, as well as the production of smartphones, has had a positive influence on the IT industry, IT practitioners, as well as the development of the technology. As normal, the primary focus is on smartphone apps instead of just desktop software. As we recognize, with innovative features, phone applications, and smartphones are all made, built, modernized every day, and always incorporated with either the latest technology.This has now resulted in far more jobs and employment for the IT sector, and therefore new clients for service-based businesses. It provided various-skilling the application production industry for IT experts including learning how to work on emerging technology. The demand for software production and software growth is evolving at a greater speed than it's ever been, so the increase of smartphone production and smartphones has had a very beneficial effect on perhaps the IT sector, IT practitioners, and business development.A country, called Simpleland, has a language with a small vocabulary of just “the”, “on”, “and”, “go”, “round”, “bus”, and “wheels”. For a word count vector with indices ordered as the words appear above, what is the word count vector for a document that simply says “the wheels on the bus go round and round.”
Please enter the vector of counts as follows: If the counts were ["the"=1, “on”=3, "and"=2, "go"=1, "round"=2, "bus"=1, "wheels"=1], enter 1321211.
1 point
Answer:
umm that is a todler song
Explanation:
umm that is a todler song that they sing to them when there crying
A country, called Simpleland, has a language with a small vocabulary of just “the”, “on”, “and”, “go”, “round”, “bus”, and “wheels”. As per the given scenario, the vector of counts will be 2111211. The correct option is C.
What are the ways to count items in a vector?C++ has a built-in function that counts the length of the vector. Size is the function's name ().
It returns the size or total number of elements of the vector that was utilized to create it. There is no need for debate.
The number of observations (rows) includes deleted observations as well. In an SAS data collection, there can be a maximum of 2 63-1 observations, or roughly 9.2 quintillion observations. For the majority of users, going above that limit is quite rare.
The vector of counts in the above scenario will be 2111211.
Thus, the correct option is C.
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What are two examples of items in Outlook?
a task and a calendar entry
an e-mail message and an e-mail address
an e-mail address and a button
a button and a tool bar
Answer:
a task and a calendar entry
Explanation:
ITS RIGHT
Answer:
its A) a task and a calendar entry
Explanation:
correct on e2020
What is his resolution amount
B1:B4 is a search table or a lookup value
Answer:
lookup value
Explanation:
How does asymmetric encryption work?
A.
It uses only one key to encrypt and decrypt a message.
B.
A private key is used to encrypt the message and the public key is used to decrypt the message.
C.
Either the public key or the private key can be used to encrypt and decrypt a message.
D.
Public key is used to encrypt the message and private key is used to decrypt the message.
Answer:
i choose choice D
Explanation:
reason as to my answer public keys are simply input keys used to encrypt data into either a computer or any electrical device as private keys are out put used to either erase or edit