Suppose GRE Quantitative scores are normally distributed with a mean of 587587 and a standard deviation of 152152. A university plans to offer tutoring jobs to students whose scores are in the top 14%14%. What is the minimum score required for the job offer? Round your answer to the nearest whole number, if necessary.

Answer:

It's the option D

6 root 2 units

Answer:

see below

Step-by-step explanation:

5x - 6y = 21

Let x = 0 and solve for y to find the y intercept

-6y = 21

Divide by -6

y = 21/-6 = -7/2

The y intercept is (0,-7/2)

5x - 6y = 21

Let y = 0 and solve for x to find the x intercept

5x = 21

Divide by 5

y = 21/5 = 21/5

The x intercept is (21/5,0)

Answer:

x=4.2 (x-intercept)

y=-3.5 (y-intercept)

Step-by-step explanation:

To find the x-intercept, we know that y=0. To find the y-intercept, we know that x=0. All we have to do is plug in 0 into either x or y to find the x-intercept and y-intercept.

X-intercept

5x-6(0)=21

5x-0=21

5x=21

x=4.2

Y-intercept

5(0)-6y=21

0-6y=21

-6y=21

y=-3.5

She will receive a lot more money because she is already retired from work already and will win as bit more money

Answer:

12x8+5=101/8

101/8-74/5

40/8=5

5x101=505

40/5=8

8x74=592

therefore 505/40-592/40=

-87/40=-2.175

Answer:

The correct answer would be 2.175

Step-by-step explanation:

i got it right :))

Answer:

[tex] m=\frac{y_2 -y_1}{x_2 -x_1} =\frac{0-800}{400-0}= -2[/tex]

And then we can find the y intercept using one point for example (0,800) and we have:

[tex] 800= -2*0+ b[/tex]

[tex] b= 800[/tex]

And our model would be:

[tex] y = -2x +800[/tex]

And the x intercept would be if y=0 then

[tex] 0 =-2x +800[/tex]

[tex] x =400[/tex]

x intercept =400 represent the value of x when y =0

y intercept = 800 represent the value of y when x =0

Step-by-step explanation:

We have the following points given:

(0, 800) and (400, 0)

If we want to find the x intercept and y intercept we need to remember that we need to set a linear model given by:

[tex] y=mx +b[/tex]

Where

[tex] m=\frac{y_2 -y_1}{x_2 -x_1} =\frac{0-800}{400-0}= -2[/tex]

And then we can find the y intercept using one point for example (0,800) and we have:

[tex] 800= -2*0+ b[/tex]

[tex] b= 800[/tex]

And our model would be:

[tex] y = -2x +800[/tex]

And the x intercept would be if y=0 then

[tex] 0 =-2x +800[/tex]

[tex] x =400[/tex]

x intercept =400 represent the value of x when y =0

y intercept = 800 represent the value of y when x =0

Answer:

And then we can find the y intercept using one point for example (0,800) and we have:

And our model would be:

And the x intercept would be if y=0 then

x intercept =400 represent the value of x when y =0

y intercept = 800 represent the value of y when x =0

Step-by-step explanation:

We have the following points given:

(0, 800) and (400, 0)

If we want to find the x intercept and y intercept we need to remember that we need to set a linear model given by:

Where

And then we can find the y intercept using one point for example (0,800) and we have:

And our model would be:

And the x intercept would be if y=0 then

x intercept =400 represent the value of x when y =0

y intercept = 800 represent the value of y when x =0

Step-by-step explanation:

Answer:  b) Each sold the same number of vehicles

Step-by-step explanation:

This question is only asking for the quantity of vehicles (not the total amount earned) so we can disregard the second matrix and find the sum of each row in the first matrix.

Kelly: 8 + 2 + 6 = 16

Scott: 7 + 8 + 1 = 16

Mark: 10 + 4 + 2 = 16

The total number of vehicles sold by each person is the same

113/32

Step-by-step explanation:

7 squared is 49, 4 cubed is 64, 2 to the 5th power is 32.

49 plus 64 is 113 divided by 32

3.53125

Step-by-step explanation:

7^2+4^3/2^5

= 49+64/32

= 113/32

= 3.53125

If one of the vertices on the x-axis is (x, 0), then the other vertex on the same axis is (-x, 0), so that the rectangle has base 2x. The other two vertices on the parabola are the points (x, 6 - x²) and (-x, 6 - x²), so the height of the rectangle is 6 - x².

Then the area of the rectangle is given by the function

[tex]A(x)=2x(6-x^2)=12x-2x^3[/tex]

Compute the critical points of A:

[tex]A'(x)=12-6x^2=0\implies x=\pm\sqrt2[/tex]

So the maximum area is obtained when the vertices are the points (-√2, 0), (√2, 0), (√2, 4), and (-√2, 4). This rectangle has base 2√2 and height 4, giving a maximum area of 8√2.

The maximum area is obtained when the vertices are the points

(-√2, 0), (√2, 0), (√2, 4), and (-√2, 4).

This rectangle has base 2√2 and height 4, giving a maximum area of 8√2.

The area of a rectangle is expressed as shown:

A = xy

x is the length of the rectangle

y is the width

Given that y = 6 - x²

If its other two vertices above the x-axis and lying on the parabola, hence

the length of the rectangle will be 2x

The area of the rectangle will be A = 2x(6-x²)

If the dimension of the rectangle is at the maximum, hence dA/dx=0

A = 12x - 2x³

dA/dx = 12 - 6x²

0 = 12 - 6x²

6x² = 12

x² = 12/6

x² = 2

x = ±√2

Hence the maximum area is obtained when the vertices are the points

(-√2, 0), (√2, 0), (√2, 4), and (-√2, 4).

This rectangle has base 2√2 and height 4, giving a maximum area of 8√2.

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Answer:

(a) The formula to calculate the amount of money (A) that Aizuddin must pay the bank after n years, with the original amount of borrowed money is 6300 RM, interest of 8%, compounded annually, is described as following:

A = principal x (1 + rate)^(time in year)

A = 6300 x (1 + 8/100)^n

(b) The amount of interest charged (AC) that Aizuddin must pay after n years:

AC = A - 6300

AC = 6300 x (1 + 8/100)^n - 6300

AC = 6300 x [(1 + 8/100)^n - 1]

Hope this helps!

Answer:

w || n and n ⊥ m

Step-by-step explanation:

To find out which statement is true, recall the following:

1. 2 lines are said to be parallel to each other if they do not intersect at any given point and are of the same distant apart. Parallel is denoted by ||

2. 2 lines are said to be perpendicular if both lines intersect at a right angle. It is denoted by ⊥

==>From the diagram given, we can see that w and n are of the same distant apart and they do not intersect at any given point.

Also, we can see that n and m intersect at point X to at right angle.

Therefore, we can conclude that w || n and n ⊥ m

Answer:

[tex]508.68[/tex] [tex]in^{2}[/tex]

Step-by-step explanation:

[tex]\pi r^{2} (1/2)[/tex]

[tex](3.14)(18^{2})(1/2)[/tex]

[tex]12717/25 = 508.68[/tex]

Answer

A. 18(3/4)π

Explanation

In the attached file

Answer:

r = 4.2805cm

Step-by-step explanation:

ok first the shape its made of two slant height and and an arc of degree 70°

The total perimeter = 28cm

The formula for the total perimeter= 2l + 2πl(70/360)

Where l is the radius of the shape.

But l = 2r

So

= 2l + 1.2217l

= 3.2217l

28 = 3.2217l

l = 28/3.2217

l = 8.691

Recall that l = 2r

8.691= 2r

r = 8.691/2

r = 4.2805cm

Answer:

Step-by-step explanation:

if N=2.0

4.9 N=4.9×2=9.8

9.8/1.4=7

which is an integer.

so N=2.0

Refer to the provided image.

A triangle with one of its angles to be 90°. That is if a triangle has one right angle then the triangle is a right-angled triangle.

A right-angled triangle's hypotenuse is the longest side. It's the side that's on the opposite side of the right angle.

A leg of a right-angled triangle is the side that is adjacent to the right angle.

The height of the right-angled triangle when the hypotenuse is considered as the base is called the Altitude of the right-angled triangle.

Considering the definitions above label the figure accordingly.

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Answer:

The probability that at least 13 flights arrive late is 2.5196 [tex]\times 10^{-6}[/tex].

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

[tex]P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........[/tex]

where, n = number of trials (samples) taken = 18 Southwest flights

           r = number of success = at least 13 flights arrive late

          p = probability of success which in our question is probability that

                flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = Number of flights that arrive late.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X [tex]\geq[/tex] 13)

P(X [tex]\geq[/tex] 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= [tex]\binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}[/tex]

= [tex]\binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}[/tex]

= 2.5196 [tex]\times 10^{-6}[/tex].

Answer:

12

Step-by-step explanation:

1:4 = 3:12

Answer:

12 cups of water

Step-by-step explanation:

The ratio of fertilizer is 1. To get to 3 you times it by 3. Therefore to find how much water you need you'd have to do the same to the other side of the ratio, times it by three. So it would be 3:12

Answer:

Yes, they are consistent.

A 99​% confidence interval is consistent with a​ two-sided test with significance level alpha=0.01 because if a​ two-sided test with this significance level does not reject the null​ hypothesis, then the confidence interval does contains the value in the null hypothesis.

Step-by-step explanation:

Yes, they are consistent.

A 99​% confidence interval is consistent with a​ two-sided test with significance level alpha=0.01 because if a​ two-sided test with this significance level does not reject the null​ hypothesis, then the confidence interval does contains the value in the null hypothesis.

The critical values of the confidence level are equivalent to the critical values in the hypothesis test. In the case that the conclusion of the test is to not reject the null hypothesis, the test statistic falls within the acceptance region: its value is within the critical values of the two-sided test.

Then, it is also within the critical values of the confidence interval and the sample mean (or other measure) will be within the confidence interval bounds.

Answer:

a) C. The population must be normally distributed.

b) P(x < 65.8) = 0.8159

c) P(x > 64.2) = 0.3015

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

[tex]\mu = 62, \sigma = 14, n = 11, s = \frac{14}{\sqrt{11}} = 4.22[/tex]

(a) What must be true regarding the distribution of the population in order to use the normal model to compute probabilities regarding the sample me

n < 30, so the distribution of the population must be normal.

The correct answer is:

C. The population must be normally distributed.

(b) Assuming the normal model can be used, determine P(x < 65.8).

This is the pvalue of Z when X = 65.8. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{65.8 - 62}{4.22}[/tex]

[tex]Z = 0.9[/tex]

[tex]Z = 0.9[/tex] has a pvalue of 0.8159.

So

P(x < 65.8) = 0.8159

(c) Assuming the normal model can be used, determine P(x > 64.2).

This is 1 subtracted by the pvalue of Z when X = 64.2. So

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{64.2 - 62}{4.22}[/tex]

[tex]Z = 0.52[/tex]

[tex]Z = 0.52[/tex] has a pvalue of 0.6985.

1 - 0.6985 = 0.3015

So

P(x > 64.2) = 0.3015

Answer:

[tex] X= v_i t + \frac{1}{2}a t^2 [/tex]

And from this equation we can solve for a like this:

[tex] 205m = 3.5m/s *(28.7s) +\frac{1}{2}a (28.7s)^2[/tex]

And solving for a we got:

[tex] 104.55m = \frac{1}{2}a (28.7s)^2[/tex]

[tex] a = \frac{2*104.55m}{(28.7s)^2)}= 0.254 m/s^2[/tex]

Step-by-step explanation:

For this case we have the velocity , distance and time given:

[tex] v = 3.5 m/s, d=205m, t =28.7s[/tex]

And we know from kinematics that he velocity can be expressed like this:

[tex] v_f = v_i +a t[/tex]

We also know that the distance is given by:

[tex] X= v_i t + \frac{1}{2}a t^2 [/tex]

And from this equation we can solve for a like this:

[tex] 205m = 3.5m/s *(28.7s) +\frac{1}{2}a (28.7s)^2[/tex]

And solving for a we got:

[tex] 104.55m = \frac{1}{2}a (28.7s)^2[/tex]

[tex] a = \frac{2*104.55m}{(28.7s)^2)}= 0.254 m/s^2[/tex]

Answer:

Step-by-step explanation:

The objective is to  Show that if the set of images {T(v1)......T(vp)} is linearly dependent, then {v1......vp} is linearly dependent.

Given that:

[tex]\mathbf{[T(v_1) +T(v_2) ...T(v_p)]}[/tex] is linearly dependent set

Thus; there exists scalars [tex]\mathbf{k_1 , k_2 ... k_p}[/tex] ; ( read as "such that")  [tex]\mathbf{k_1 T(v_1) +k_2T(v_2) ...k_pT(v_p)=0}[/tex]

[tex]\mathbf{= T(k_1 v_1 +k_2v_2 ...k_pv_p)=0}[/tex]

T = 0                                  (for the fact that T is linear transformation)

[tex]\mathbf{k_1 v_1 +k_2v_2 ...k_pv_p=0}[/tex]     (due to T is one-one)

NOTE: Not all Ki's are zero;

Thus;

[tex]\mathbf{[v_1,v_2 ...v_p] }[/tex]  is linearly dependent

It negation also illustrates that :

If [tex]\mathbf{[v_1,v_2 ...v_p]}[/tex] is also linearly independent then [tex]\mathbf{[T(v_1),T(v_2) ...T(v_p)]}[/tex] is also linearly independent.

Answer:

Step-by-step explanation:

a) Confidence interval is written as

Sample proportion ± margin of error

Margin of error = z × √pq/n

Where

z represents the z score corresponding to the confidence level

p = sample proportion. It also means probability of success

q = probability of failure

q = 1 - p

p = x/n

Where

n represents the number of samples

x represents the number of success

From the information given,

n = 451

x = 1.5/100 × 451 = 7

p = 7/451 = 0.02

q = 1 - 0.02 = 0.98

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.97 = 0.1

α/2 = 0.01/2 = 0.03

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.03 = 0.97

The z score corresponding to the area on the z table is 2.17. Thus, Thus, the z score for a confidence level of 97% is 2.17

Therefore, the 97% confidence interval is

0.02 ± 2.17√(0.02)(0.98)/451

= 0.02 ± 0.014

b) x represents the number of members of the 50 Plus Fitness Association who ran and died in the same eight–year period.

P represents the proportion of members of the 50 Plus Fitness Association who ran and died in the same eight–year period.

The distribution that should be used is the normal distribution

Answer:

So the formula for mean is you add up all of the numbers and divide by the number of numbers, that will give you the mean/average. So that means that (12+25+33+N)/4 = 120. We can simplify by first adding all of the numbers and multiplying both sides by 4 which will cancel out the four on the right side.

70+N/4 = 120

480 = 70+N

So then we subtract 70 from both sides.  Then we get 410 = N.

The answer is

Answer:

  1

Step-by-step explanation:

The quadratic relation is a perfect square:

  y = (7x +3)²

so has one zero, where the factor is zero:

  7x +3 = 0

  7x = -3

  x = -3/7

_____

It is useful to have handy reference to the form of the square of a binomial:

  (a +b)² = a² +2ab +b²

Here, your first clue is that 49x² and 9 are both perfect squares: (7x)² and (3)². It is easy to check that the middle term is twice the product of these roots:

  2(7x)(3) = 42x . . . . matches the middle term

So, the given expression is equivalent to ...

  y = (7x +3)²

Options:

The supplier products have a lower mean than claimed

The supplier is more accurate than they claimed

The supplier products have a higher mean than claimed

The supplier is less accurate than they have claimed

Answer:

The supplier is less accurate than they have claimed

Step-by-step explanation:

Confidence Interval for supplier claim, CI = (20.45, 21.05)

Confidence Interval for your claim, CI = (20.48, 21.02)

Calculate the mean of the Confidence Interval for the supplier's claim:

[tex]\bar{X_s} = \frac{20.45 + 21.05}{2} \\\bar{X_s} = \frac{41.50}{2}\\\bar{X_s} = 20.75[/tex]

Calculate the mean of the Confidence Interval for your claim :

[tex]\bar{X_y} = \frac{20.48 + 21.02}{2} \\\bar{X_y} = \frac{41.50}{2}\\\bar{X_y} = 20.75[/tex]

Both the supplier and you have the equal mean

Margin of Error by the supplier = 21.05 - 20.75 = 0.30

Margin of Error by you = 21.02 - 20.75 = 0.27

Since the margin of error for the supplier is more, you can conclude that the suppler is less accurate than they have claimed.

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Supplier claims that they are 95% confident that their products will be in the interval of 20.45 to 21.05. You take samples and find that the 95% confidence interval of what they are sending is 20.48 to 21.02. What conclusion can be made?

The supplier products have a lower mean than claimed

The supplier is more accurate than they claimed

The supplier products have a higher mean than claimed

The supplier is less accurate than they have claimed

Answer:

The margin of error reported by the supplier is greater as compared to the actual margin of error. A greater margin of error results in less accuracy.

Therefore, we can conclude that the supplier is less accurate than they have claimed.

Step-by-step explanation:

Supplier claims that they are 95% confident that their products will be in the interval of 20.45 to 21.05.

The mean is given by

Mean = (Upper limit + Lower limit)/2

Mean = (21.05 + 20.45)/2

Mean = (41.50)/2

Mean = 20.75

The margin of error in this case is

MoE = Upper limit - Mean

MoE = 21.05 - 20.75

MoE = 0.30

You take samples and find that the 95% confidence interval of what they are sending is 20.48 to 21.02.

The mean is given by

Mean = (Upper limit + Lower limit)/2

Mean = (21.02 + 20.48)/2

Mean = (41.50)/2

Mean = 20.75

The margin of error in this case is

MoE = Upper limit - Mean

MoE = 21.02 - 20.75

MoE = 0.27

As you can notice the margin of error reported by the supplier is greater as compared to the actual margin of error. A greater margin of error results in less accuracy.

Therefore, we can conclude that the supplier is less accurate than they have claimed.

Answer:

$5073.37

Step-by-step explanation:

We can use the simple interest rate (appreciation) formula: A = P(1 + r)^t

Because it gives us 3 months, we need to put it in terms of years. That will give us 1/4 of a year:

A = 5000(1 + 0.06)^0.25

When you plug that into the calc, you should get 5073.37 as your final answer!

Answer:

8,15 and 17 are Pythagorean triplets,the Pythagorean triplets of 15 are: (15,112 and113),(15,8 and 17),(15,20 and 25),(15,9and 12),(15,36 and 39)

Answer:

Step-by-step explanation:

If

[tex]a=m^2-n^2;\ b=2mn;\ c=m^2+n^2[/tex]

for m > n, then a, b, c make a Pythagorean triplet.

[tex]m^2-n^2=15\to(m-n)(m+n)=15\\\\(m-n)(m+n)=(3)(5)\to m-n=3\ \wedge\ m+n=5[/tex]

We have the system of equations:

[tex]\underline{+\left\{\begin{array}{ccc}m-n=3\\m+n=5\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2m=8\qquad\text{divide both sides by 2}\\.\qquad\boxed{m=4}[/tex]

Substitute to the second equation:

[tex]4+n=5\qquad\text{subtract 4 from both sides}\\\boxed{n=1[/tex]

Therefore we have:

[tex]a=4^2-1^2=16-1=15\\b=2(4)(1)=8\\c=4^2+1^2=16+1=17[/tex]

[tex]2mn=15[/tex]  it's impossible, because 15 is not an even number.

[tex]m^2+n^2=15[/tex]

Let's consider all possible sums of two numbers resulting in 15.

We will check which of the numbers are perfect squares.

1 + 14

2 + 13

3 + 12

4 + 11

5 + 10

6 + 9

7 + 8

(Bold not perfect squares)

There are no two perfect squares among the listed pairs of numbers.

Other:

15, 112, 113

We know the Egyptian triangle with sides of length 3, 4, 5.

By modifying this Pythagorean triplet by multiplying by 3 we get:

(3)(3) = 9; (3)(4) = 12; (3)(5) = 15

By modifying this Pythagorean triplet by multiplying by 5 we get:

(5)(3) = 15; (5)(4) = 20; (5)(5) = 25

Answer:

8.80$

Step-by-step explanation:

Total 20.20. 6.06 x 2=12.12. 20.20-12.12=8.80$

Mathew paid 8.80$

Clarence paid 12.12$

Daniel paid 6.06$

Answer:

The probability that at least one of the children get the disease from their mother is 0.7125.

Step-by-step explanation:

We are given that a human gene carries a certain disease from the mother to the child with a probability rate of 34%.

Suppose a female carrier of the gene has three children. Assume that the infections of the three children are independent of one another.

Let Probability that children get the disease from their mother = P(A) = 0.34

SO, Complement of the event "At least one of the children get the disease from their mother"= P(A') = 1 - P(A)

where A' = event that children do not get the disease from mother.

So, P(A') = 1 - P(A) = 1 - 0.34 = 0.66

Now, probability that at least one of the children get the disease from their mother = 1 - Probability that none of the three children get disease from their mother

                     = 1 - P(X = 0)

                     = 1 - (0.66 [tex]\times[/tex] 0.66 [tex]\times[/tex] 0.66)

                     = 1 - 0.2875 = 0.7125