Answer:
a. 100.
b. 31500.
Explanation:
So, we are given the following data which is going to help in solving this particular question.
The time required to execute (on the average) = 1/2 microsecond , a page fault takes of processor time to handle = 250 microseconds and the disk time to read in the page = 10 milliseconds.
Thus, the time taken by the processor to handle the page fault = 250 microseconds / 1000 = 0.25 milliseconds.
The execution time = [ 1/2 microseconds ]/ 1000 = 0.0005 milliseconds.
The number of Pages sent in a second by the disc = 1000/10 milliseconds = 100.
Assuming U = 1.
Hence, the disc transfer time = [2/3 × 1 } + [ 1/3 × 0.25 milliseconds + 15 ] × 2.
=0.667 + 15.083.
= 15.75 millisecond.
Average number of instruction = 15.75/0.0005 = 31500.
It should be noted that the number of pages in a second will be 100 pages.
From the information given, it was stated that the instruction takes 1/2 microsecond to execute and a page fault takes 250 microseconds of processor time to handle plus 10 milliseconds of disk time to read the page.
Therefore, the execution time will be:
= 0.5/1000
= 0.0005
Therefore, the number of pages will be:
= 1000/10
= 100
Also, the disc transfer time will be;
= (2/3 × 1) + (1/3 × 0.25 + 15) × 2
= 0.667 + 15.083
= 15.75
Therefore, the average number of instructions will be:
= 15.75/0.0005
= 31500
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Create an array of doubles to contain 5 values Prompt the user to enter 5 values that will be stored in the array. These values represent hours worked. Each element represents one day of work. Create 3 c-strings: full[40], first[20], last[20] Create a function parse_name(char full[], char first[], char last[]). This function will take a full name such as "Noah Zark" and separate "Noah" into the first c-string, and "Zark" into the last c-string. Create a function void create_timecard(double hours[], char first[], char last[]). This function will create (write to) a file called "timecard.txt". The file will contain the parsed first and last name, the hours, and a total of the hours. See the final file below. First Name: Noah
Solution :
[tex]$\#$[/tex]include [tex]$<stdio.h>$[/tex]
[tex]$\#$[/tex]include [tex]$<string.h>$[/tex]
void parse[tex]$\_$[/tex]name([tex]$char \ full[]$[/tex], char first[tex]$[],$[/tex] char last[tex]$[])$[/tex]
{
// to_get_this_function_working_immediately, _irst
// stub_it_out_as_below._When_you_have_everything_else
// working,_come_back_and_really_parse_full_name
// this always sets first name to "Noah"
int i, j = 0;
for(i = 0; full[i] != ' '; i++)
first[j++] = full[i];
first[j] = '\0';
// this always sets last name to "Zark"
j = 0;
strcpy(last, full+i+1);
// replace the above calls with the actual logic to separate
// full into two distinct pieces
}
int main()
{
char full[40], first[20], last[20];
double hours[5];
// ask the user to enter full name
printf("What is your name? ");
gets(full);
// parse the full name into first and last
parse_name(full, first, last);
// load the hours
for(int i = 0; i < 5; i++)
{
printf("Enter hours for day %d: ", i+1);
scanf("%lf", &hours[i]);
}
// create the time card
FILE* fp = fopen("timecard.txt", "w");
fprintf(fp, "First Name: %s\n", first);
fprintf(fp, "Last Name: %s\n", last);
double sum = 0.0;
for(int i = 0; i < 5; i++)
{
fprintf(fp, "Day %i: %.1lf\n", i+1, hours[i]);
sum += hours[i];
}
fprintf(fp, "Total: %.1f\n", sum);
printf("Timecard is ready. See timecard.txt\n");
return 0;
}
What may make it easy for cybercriminals to commit cybercrimes? Select 2 options.
Cybercrimes are not classified as real crimes, only as virtual crimes.
They operate from countries that do not have strict laws against cybercrime.
They are not physically present when the crime is committed.
The United States has no law enforcement that acts against them.
Law enforcement agencies lack the expertise to investigate them.
Answer: They operate from countries that do not have strict laws against cybercrime.
They are not physically present when the crime is committed.
Explanation:
edg
Answer:
They operate from countries that do not have strict laws against cybercrime.
They are not physically present when the crime is committed.
Explanation:
Which functions do you use to complete Step 3e? Check all that apply.
Animations tab
Animation styles
Design
Lines
Motion Paths
Reordering of animations
Answer: Animations tab
Animation styles
Lines
Motion paths
Explanation: Edg2021
importance of information
literay to the society
Explanation:
Information literacy is important for today's learners, it promotes problem solving approaches and thinking skills – asking questions and seeking answers, finding information, forming opinions, evaluateing sources, and making decisions fostering successful learners, effective contributors, and confident individuals.what does the
command do
Which of the following is step two of the Five-Step Worksheet Creation Process?
Answer:
Add Labels.
As far as i remember.
Explanation:
Hope i helped, brainliest would be appreciated.
Have a great day!
~Aadi x
Add Labels is step two of the Five-Step Worksheet Creation Process. It helps in inserting the data and values in the worksheet.
What is label worksheet in Excel?A label in a spreadsheet application like Microsoft Excel is text that offers information in the rows or columns around it. 3. Any writing placed above a part of a chart that provides extra details about the value of the chart is referred to as a label.
Thus, it is Add Labels
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By using your own data, search engines and other sites try to make your web experience more personalized. However, by doing this, certain information is being hidden from you. Which of the following terms is used to describe the virtual environment a person ends up in when sites choose to show them only certain, customized information?
A filter bubble
A clustered circle
A relational table
An indexed environment
Answer:
A filter bubble
Explanation:
1. P=O START: PRINT PP = P + 5 IFP
<=20 THEN GOTO START: * what is output
Answer:
0
5
10
15
20
Explanation:
P=O should be P=0, but even with this error this is the output.
When P reaches 20 it will execute the loop once more, so 20 gets printed, before getting increased to 25, which will not be printed because then the loop ends.