Suppose 7.17g of barium acetate is dissolved in 350mL of a 79.0mM aqueous solution of sodium chromate. Calculate the final molarity of barium cation in the solution. You can assume the volume of the solution doesn't change when the barium acetate is dissolved in it. Round your answer to 1 significant digit.

Answers

Answer 1

Answer:

0.0802 M.

Explanation:

Hello!

In this case, since the barium acetate has the following formula:

[tex]Ba(CH_3COO)_2[/tex]

So its molar mass is 255.43 g/mol, in order to compute the molarity of the barium cation, we first need the moles in 7.17 g:

[tex]n_{Ba(CH_3COO)_2} = 7.17g*\frac{1molBa(CH_3COO)_2}{255.43g} =0.0281molBa(CH_3COO)_2[/tex]

Now, since one mole of barium acetate contains one mole of barium cations, we infer there are 0.0281 moles of barium cations. Moreover, since the molarity is computed by dividing the moles of those ones by the volume of the solution in liters, 350 mL (0.350 L) as it does not change, it turns out:

[tex]M=\frac{0.0281molBa^{2+}}{0.350L}\\\\M=0.0802M[/tex]

Best regards!


Related Questions

The Question A 1.80 x 10-2 kg block of metal has the following dimensions: 0.4981 inches by 0.531 inches, by 0.5839 inches. Determine the density of the block in g/mL. Using the provided list of metals and their respective densities, what is the metal's identity

Answers

Answer:

Zinc

Explanation:

m = Mass of block [tex]1.8\times 10^{-2}\ \text{kg}=18\ \text{g}[/tex]

Dimension of block is 0.4981 inches by 0.531 inches, by 0.5839 inches

[tex]1\ \text{inch}^3=16.3871\ \text{mL}[/tex]

Volume of block

[tex]V=0.4981\times 0.531\times 0.5839\times 16.3871\ \text{mL}[/tex]

Density is given by

[tex]\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{18}{0.4981\times 0.531\times 0.5839\times 16.3871}\\\Rightarrow \rho=7.112\ \text{g/mL}[/tex]

The density of the metal is [tex]7.112\ \text{g/mL}[/tex]. The metal here is zinc.

Which two elements have similar characteristics?

Answers

Answer:

The two elements are FLUORINE AND CHLORINE. These two elements have similar characteristics because they belong to the same group in the periodic table. On the periodic table, elements with similar properties are grouped together in the same group. Both chlorine and fluorine belongs to the halogen group.

Explanation:

Hope it helps, some how.

WHICH ONE IS TRUE WHICH ONE IS FALSE?
The number of valence electrons decreases from left to right across each period.
The number of valence electrons increases from top to bottom within each group.
All of the elements in group 9 have nine valence electrons.
Elements with the most valence electrons are in group 18.

Answers

Answer:

The number of valence electrons increases from top to bottom within each group.

Explanation:

The valence electrons are the outermost shell electrons.

Therefore, the number of valence electrons does not increase from top to bottom within each of the group.

Down a group, the number of valence electrons remains the same.

For group I elements, the number of electrons is 1.

 The group is the vertical arrangement of elements.

From left to right across a period, the number of valence electrons increases because you move from group to group.

11. A 4.175 gram sample of a certain hydrate of copper (II) sulfate, CuSO,• xH,O, is heated until all
the water is driven off. The resulting anhydrous compound weighs 3.120 grams. What is the
formula of the hydrate?

Answers

The  formula of the hydrate = CuSO₄• 3H₂O

Further explanation

Given

4.175 grams sample CuSO₄• xH₂O

3.120 grams anhydrous compound CuSO₄

Required

The formula

Solution

mass of H₂O driven off :

= 4.175 - 3.12

= 1.055 g

MW CuSO₄ = 159.5 g/mol

MW H₂O = 18 g/mol

mol ratio of CuSO₄ : H₂O :

= 3.12/159.5 : 1.055/18

= 0.01956 : 0.05861

= 1 : 3

Based on the data provided, the formula of the hydrated salt is CuSO4.3H20

What is the formula of the hydrate?

The formula of the hydrate is determined from the mole ratio of the anhydrous saltand water.

Mass of water = 4.175 - 3.120

mass of water = 1.055 g

Mole ratio= mass/molar mass

molar mass of CuSO4 = 160 g/mol

molar mass of H2O = 18 g/mol

CuSO4 = 3.120/160 = 0.0195

H2O = 1.055/18 = 0.0586

CuSO4 = 0.0195/0.0195 = 1

H2O = 0.0586/0.0195 = 3

Therefore, the formula of the hydrated salt is CuSO4.3H20

Learn more about hydrated salts at: https://brainly.com/question/24920157

Chromuate found inside which of the following structures of a eukaryotic cell?

Answers

Answer:

Chromuates are found in the chromosomes of the eukaryotic cells!!!!

Explanation:

I learned this in 7th grade!!!!

Mark Me Brainliest plzz

Which of the following represents a compound made of five molecules
OCOS
OC205
Осо
5002

Answers

I think B I’m not sure

all organisms begins life as a ________ cell.

Answers

Answer:

All organisms begin life as a single cell

Explanation:

Single cell also did you know 15 minutes can save you 15% more on car insurance

Assign oxidation numbers to the element in each of the following compounds. Remember an oxidation number is for one atom of the element.

a. HgO
b. Al4C3
c. CrF2
d. Fe2S3

Answers

Answer:

a.  x = + 2

b.  x = + 3

c.  x = + 2

d.  x = + 3

Explanation:

The oxidation number is a formal charge assigned to an atom present in a molecule or formula unit or ion based on some arbitrary rules.

a.

HgO

The oxidation number of Hg in HgO is:

x + (-2) = 0

x = +2

b.

Al₄C₃

The oxidation number of Al in Al₄C₃ is:

4x +(3 × -4) = 0

4x - 12 = 0

4x = +12

x = 12/4

x = +3

c. CrF₂

x + ( 2 × - 1) = 0

x - 2 = 0

x = + 2

d. Fe₂S₃

2x + ( 3 × - 2) = 0

2x + (-6) = 0

2x = 6

x = 6/2

x = +3

A student is making a glucose solution. The student is using 12.55 g of glucose (C6H1206) and a 500 mL volumetric flask. Use this information to calculate the molarity of the glucose solution.​

Answers

Answer:

M = 0.138 M

Explanation:

Given data:

Mass of glucose = 12.55 g

Volume of solution = 500 mL

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 12.55 g/ 180.156 g/mol

Number of moles = 0.069 mol

Volume in L:

500 mL × 1 L /1000 mL

0.5 L

Molarity:

M = 0.069 mol / 0.5 L

M = 0.138 M

< Progress: 19/21 groups Due Jan 15 at 11:55 PM Use the References to access important values if needed for this question. The compound cobalt (II) sulfate forms a hydrate with seven water molecules per formula unit. What are the name and formula of the hydrate

Answers

Answer:

CoSO4.7H2O

Cobalt II tetraoxosulphate VI heptahydrate

Explanation:

According to IUPAC nomenclature, compounds are named systematically.

We were told that there are seven water molecules in each formula unit Hence the correct formula of the compound is CoSO4.7H2O

According to IUPAC system, the metal is first named, followed by its oxidation state in Roman numerals. Then the name of the anion is mentioned as well as the number of water molecules. We have to take into account the correct prefix signifying the number of molecules of water of crystallization.

If you have a gas sample with a pressure of 2 atm, a volume of 40 L and a temperature of 300 K, what will be the number of moles of gas in that sample?

Answers

Answer:

n = 3.25 mol

Explanation:

Given data:

Pressure of sample = 2 atm

Volume of sample = 40 L

Temperature = 300 K

Number of moles = ?

Solution:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

2 atm ×40 L = n × 0.0821 atm.L/mol.K × 300 K

80 atm.L = n  × 24.63 atm.L/mol

n = 80 atm.L  /24.63 atm.L/mol

n = 3.25 mol

Insulin is a protein that is used by the body to regulate both carbohydrate and fat metabolism. A bottle contains 225 mL of insulin at a concentration of 20.0 mg/mL . What is the total mass of insulin in the bottle?

Answers

The total mass of insulin in the bottle : m = 4500 mg

Further explanation

Given

225 ml of insulin

The concentration 20 mg/ml

Required

The total mass of insulin

Solution

Density is the ratio of mass per unit volume

Can be formulated

ρ = m / V

m = ρ x V

Input the value :

m = 20 mg/ml x 225 ml

m = 4500 mg

Classify each of the compounds as an ionic compound, a covalent compound or an acid.a. BaCl2______________________d. CH4______________________b. MnO2______________________e. H2S*______________________c. H3AsO4______________________f. CH3OH

Answers

Answer:

a. BaCl2 is ionic compound.

b. CH4 is covalent compound.

b. MnO2 is ionic compound.

e. H2S is covalent compound.

c. H3AsO4 is ionic compound.

f. CH3OH is covalent compound.

Explanation:

BaCl2, MnO2 and H3AsO4 are ionic compounds due to the presence of ionic bond between the atoms while on the other hand, CH4, H2S and CH3OH are covalent compounds due to the presence of covalent bond between their atoms. In covalent bonds, sharing of electrons occur whereas in ionic bonds, complete transfer of electrons occur from one atom to another atom.

PLSSS HELP!! In the demonstration, Iron reacted with the oxygen in the air. Which one ran out
first? How do you know?

Answers

it has to be iron because oxygen doesn’t run out unless being used by something like sticking it in a bubble.

is water vapor only found in hot water?

Answers

i think so, you have to have a heat source to produce water vapor
No, if you really think, there are so many things that are

12. Which gas has the greatest kinetic energy at STP?

a. He

b. Ne

c. Ar

d. none of the above (all have the same kinetic energy)

Answers

Answer:

d. none of the above (all have the same kinetic energy)

Explanation:

The kinetic theory of gases states that the molecules of an ideal gas experience a constant random motion.

At standard temperature and pressure (STP), the kinetic energy of an ideal gas such as hydrogen, argon, neon, sodium, oxygen, helium, magnesium, beryllium, nitrogen, carbon, fluorine, chlorine etc are all the same.

The standard temperature and pressure (STP) of an ideal gas is 273K and 100 kPa.

Hence, all of the gases have the same kinetic energy at standard temperature and pressure (STP).

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}MV^{2}[/tex]

Where, K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

HELP PLEASE
Instantaneous speed is the rate of motion at an instant in time. Based on this statement, a reasonable conclusion is that if and object's instantaneous speed does not chang over time then,________.

•the object is quickly speeding up
•the object is very gradually slowing down
•the object is moving at a constant speed
•the object has returned to its beginning position ​

Answers

Answer:

The object is moving at a constant speed.

A 2.54 g piece of zinc (density = 7.14 g/mL) is added to a graduated cylinder that contains 12.13 mL h2o. What will be the final volume reading on the graduated cylinder, in mL?

Answers

Answer: If I'm correct it's 12.54 mL but don't rely on this because I'm not sure

Explanation:

Answer:

12.49 ml

Explanation:

Density = mass / volume

Volume = mass / density

Volume of zinc = 2.54/7.14

Volume of zinc = 0.3557

Initial volume = 12.13 ml

Total volume = initial volume+ volume of zinc

Total volume = 12.13 + 0.3557

Total volume = 12.4857 = 12.49 ml

What is the mass of 1.0 × 10^9 molecules of aspartame?

Answers

Answer:

294.3 g/mol b.

The mass of 1.0*10^9 molecules of aspartame is 2.943*10^11 g/mol

ASPARTAME

Aspartame is  used as an artificial non-saccharide sweetener 200 times sweeter than sucrose, and is commonly used as a sugar substitute in foods and beverages.

CALCULATION

mass  of one molecule of aspartame = 294.3g/mol

mass of 1.0*10^9 molecules of aspartame =294.3*(1.0*10^9) g/mol

                                                                     =2.943*10^11 g/mol

refer https://brainly.com/question/25225559

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Decide whether the compound is ionic or molecular, if you can.

Compound is a soft waxy white solid that can be easily shaped and molded by hand. When the flame of an ordinary laboratory burner is held about away from the solid, it rapidly and extensively melts into a clear liquid.

Answers

Answer:

Molecular solid

Explanation:

Molecular solids have a very low melting point. This is because, they are composed of weak intermolecular forces hence the layers of the solid easily fall apart as the solid melts.

We can see here that the solid being considered melts easily. Hence we can conclude that it is actually a molecular solid.

Conclusion
In this activity, thermal energy was transferred ( into / out of the hand warmer while it changed from
liquid to solid.

Answers

whats the question?

For the reaction of hydrogen with iodine
H2(g) + I2(g) rightarrow 2HI(g)
relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide.

Answers

Answer:

[tex]r_{H_2} = \frac{-1}{2} r_{HI}[/tex]

Explanation:

Hello!

In this case, considering the given chemical reaction:

[tex]H_2(g) + I_2(g) \rightarrow 2HI(g)[/tex]

Thus, by applying the law of rate proportions, we can write:

[tex]\frac{1}{-1} r_{H_2} = \frac{1}{-1}r_{i_2} = \frac{1}{2} r_{HI}[/tex]

Whereas the stoichiometric coefficients of reactants are negative due their disappearance and that of the product is positive due to its appearance. In such a way, when we relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide, we obtain:

[tex]r_{H_2} = \frac{-1}{2} r_{HI}[/tex]

Best regards!

the number that go before symbols and formulas in a chemicql equation are

A.SuperScripts
B.Subscripts
C.Catalysts
D.Coefficients​

Answers

Answer: D. Coefficients

Can anybody answer this question of chemistry?

Answers

Answer:

Answer:A

Answer:AExplanation:

Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol

= 180g/molNumber of moles of Glucose = Mass/Molar Mass

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55

Answer:

Answer:A

Answer:AExplanation:

Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol

= 180g/molNumber of moles of Glucose = Mass/Molar Mass

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55

Which constants would most likely be filled in the first row of the table?
O temperature and moles of gas
O volume and temperature
O
pressure and volume
pressure and moles of gas

Answers

Answer:

A

Explanation:

Correct on edge

The temperature and moles of gas constants would most likely be filled in the first row of the table. Therefore, option A is correct.

What is gas constant ?

The gas constant, denoted by R, is a physical constant that is expressed in terms of units of energy per temperature increment per mole. It's also referred to as the ideal gas constant, the molar gas constant, or the universal gas constant.

A general constant in the equation of state of gases that is equal to the product of the pressure and volume of one mole divided by the absolute temperature in the case of an ideal gas see gas law sense c.

All gases adapt an equation of state known as the ideal gas law: PV = nRT, where n is the number of moles of the gas and R is the universal gas constant.

Thus, option A is correct.

To learn more about the gas constant, follow the link;

https://brainly.com/question/24281105

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Your question is incomplete, most probably your question was

The incomplete table below shows selected characteristics of gas laws.

Name

Variables

Constants

Equation

?

?

?

PV = k

Charles's law

?

?

V = kT

?

Temperature, pressure

?

P = kT

Combined gas law

Pressure, temperature, volume

?

?

Which constants would most likely be filled in the first row of the table?

temperature and moles of gas

volume and temperature

pressure and volume

pressure and moles of gas

what is the molarity of a solutoin which contains 38.5 g of sodium chloride disolved in 325 ml solution ?

Answers

Answer:

Molarity =  2.02 M

Explanation:

Given data:

Molarity of solution = ?

Mass of sodium chloride = 38.5 g

Volume of solution = 325 mL (0.325 L)

Solution:

Number of moles = mass/molar mass

Number of moles = 38.5 g/ 58.44 g/mol

Number of moles = 0.658 mol

Molarity:

Molarity = number of moles / volume of solution in L

Molarity = 0.658 mol /0.325 L

Molarity =  2.02 M

When C2H4(g) reacts with H2O(g) to form CH3CH2OH(g) according to the following equation, energy is released into the surroundings. C2H4(g) H2O(g) CH3CH2OH(g) Is this reaction endothermic or exothermic

Answers

Answer:

Exothermic

General Formulas and Concepts:

Chemistry

Thermodynamics

Exothermic - releases heat as a productEndothermic - absorbs heat as a reactant

Explanation:

We are given that the reaction takes place between C₂H₄ (g) and H₂O (g) to form CH₃CH₂OH (g) and is releasing heat.

This means that heat would be product as it is being released during the reaction.

Therefore, we have an exothermic reaction.

An irregularly-shaped piece of aluminum (Al) has a mass of 66.0 grams. What is the volume in cm³ of this piece of aluminum if its density is 2.70 g/cm³?

Answers

Answer:

[tex]V=24.45\ \text{cm}^3[/tex]

Explanation:

Given that,

Mass of a piece of Aluminium, m = 66 grams

The density of Aluminium, d = 2.70 g/cm³

We need to find the volume of this piece in cm³.

We know that,

Density = mass per unit volume

[tex]d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{66\ g}{2.7\ g/cm^3}\\\\V=24.45\ \text{cm}^3[/tex]

So, the volume of the piece is [tex]24.45\ \text{cm}^3[/tex].

Does acid rain make new substances? Construct an argument that uses data from this investigation as evidence for your claim.

Answers

Answer:

Acid rain, like all acids, generates dissolution of chemical compounds, and reacts together with bases to be able to carry out oxide reduction reactions, which by deduction is very likely to form new substances as a result of the dissolution or acid erosion caused.

Explanation:

Acid rain is more likely to occur in large cities or large sources of pollution, since the excess of carbon dioxide in the atmosphere causes it to increase its partial pressure in a condensed way in the clouds, this is how then this cloud when being loaded with water and then generating the rain drags these masses of condensed carbon dioxide in the form of acid rain.

The degree of acidity is directly proportional to the amount of partial pressure of carbon dioxide in the atmosphere.

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