supply plane needs to drop a package of food to scientists working on a glacier in greenland. the plane flies 190 m m above the glacier at a speed of 160 m/s m / s . for help with math skills, you may want to review: mathematical expressions involving squares for general problem-solving tips and strategies for this topic, you may want to view a video tutor solution of dock jumping. part a how far short of the target should it drop the package? express your answer with the appropriate units.

You can run the car’s air conditioning before attempt to unflood the car engine.

If you aren't short on gas, you can leave your car idling with the air conditioner on for as long as you wish. However, you shouldn't do this with the engine off, since this will quickly drain the battery and leave you in need of a jumpstart. Internal Combustion Engines (ICEs) that have been flooded with too much fuel are rendered inoperable. Sometimes, giving a flooded engine some time to dry out is the best solution.

You can let the excess gas out of your car by opening the hood and leaving it that way for as long as possible. After waiting around 20 minutes, try to start the car up again without pressing the gas. If that doesn't work, you might want to inspect the spark plugs.

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The work required for the dog to come to a complete stop is -900 J (work = force x distance = (30 kg x 9.8 m/s^2) x (1 m))

The distance over which the force is applied, in this case, would be the distance the dog travels as it slows down to a stop. This distance would depend on the initial velocity of the dog, the force applied to slow it down, and the amount of time it takes for the dog to come to a stop. In this case, the initial velocity is 1 m/s and the force applied is the opposite of the dog's weight, or -30 kg x 9.8 m/s^2. However, without information on the amount of time it takes for the dog to come to a stop or the deceleration of the dog, it is not possible to determine the exact distance over which the force is applied.

It is important to note that the distance over which force is applied is a scalar value and is independent of the direction of motion.

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A 1000 kilogramme FRICTION is driving at a pace of 130 metres per second. To bring a car to a stop, the brakes are applied. Hence, 223 J is the average output power

To prevent sliding vehicles or spinning wheels, friction or traction are essential. The act of rubbing one surface or object against another is known as friction. The maximum acceleration and shortest stopping distance are determined by the friction between the tyres of your car and the road.

Because there is only frictional force acting on the car, friction is acting backwards. The amount of friction that can be applied to a vehicle's tyres to prevent road traction is as high as.

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When a panther appears and attempts to eat the monkey, the monkey performs 3740 J of work to increase its speed.

Work in physics is the energy transferred to or from an object by applying force along a displacement. In its most basic form, work equals the product of force strength and distance traveled for a constant force aligned with the direction of motion. Work is the transfer of energy caused by a force acting on an object as it moves. The work done by a force on an object is calculated as the product of the magnitude of the force multiplied by the magnitude of the displacement multiplied by the cosine of the angle between them.

Here,

W=1/2mv1²-1/2mv2²

=1/2*40(14²-3²)

=3740 J

The monkey does 3740 J of work of increase its speed when a panther appears and tries to eat the monkey.

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The maximum height of the water after coming out of the nozzle is affected is by the initial speed and the value of the

The water level of the tank on the building is 20m. The hose leads from the tank bottom to the ground and leads to the nozzle that is point to the top.

Here, we know, the energy will also be conserved because the there is o external force, so the kinetic energy at the top will be equal to the potential energy at the bottom in the ideal case.

Now, we can write,

1/2mv² = mgh

v = √(2gh)

g is the acceleration due to gravity and the h is the height of the tank.

Putting values,

v = √(2 x 10 x 20)

v = 20 m/s

Now, we can use the equation of motion,

v = √(2hg)

h = v²/2g

v is the speed of the water from the nozzle.

h = 10m.

This is because we have considered the ideal case where there is no energy loss, so water will go till a height of 10m when it comes out of the nozzle. The height rise is affected by the initial speed.

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The tin can carry approximately 880 grams of lead shot without sinking in water.

To calculate this: Start with the equation for buoyancy: Buoyant force = Density of fluid x Volume x Gravity

Substitute in the values for the tin can: Buoyant force = Density of water x 1100 cm3 x 9.8 m/s^2

Convert the volume to liters: 1100 cm³ = 1.1 liters

Substitute in the density of water (1 g/cm^3): Buoyant force = 1 x 1.1 x 9.8

Solve for the buoyant force: Buoyant force = 10.78 N

To find the maximum weight of lead shot that the can carry without sinking, subtract the weight of the can (80 g) from the buoyant force (10.78 N) and convert it to grams: 898 g

So the tin can carry approximately 898 grams of lead shot without sinking in water.

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Distance traveled time is 4 meters per second.Count the number of seconds it would take the plane to fly a mile and convert that number to seconds.

The formula in this situation is Distance = Rate/Time.Rate (or Speed) times Distance traveled time.Adding together the distances covered by each plan results in a total distance of 1275 km.Though each flight takes 1.5 hours to complete, the planes' velocities are different by a hundred kilometers per hour.

The speed, in meters per second, of a paper airplane that flies 24 meters in 6 seconds will be 4 meters per second.

Distance traveled by airplane = 24 meters.

Time taken = 6 seconds

Therefore, the speed will be:

= Distance / Time taken

= 24 meters / 6 seconds

= 4 meters per second.

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The average density of the Earth in g/cm3 is 5.51 g/cm3 and the density at the stage when the sun will end up as a white dwarf in diameter is  [tex]1.1X10^{6} g/cm^{3}[/tex].

For solving the part (a) of the question, we know that,

Mass of the Earth: 5.97x [tex]10^{24} \\[/tex] kg.

Radius of the Earth: 6.37 x [tex]10^{6}[/tex] m.

The formula of the density is :

Density = Mass/ Volume.

Here, Volume is  4/3 [tex]\pi[/tex][tex]r^{3}[/tex].

Substituting all the values written above in the density equation,

Density is  5.51 g/cm3 .

For solving the part (a) of the question, we know that,

Mass of the Sun: 1.99x [tex]10^{30} \\[/tex] kg.

Radius : 7500 km

The formula of the density is :

Density = Mass/ Volume.

Here, Volume is  4/3 [tex]\pi[/tex][tex]r^{3}[/tex].

Substituting all the values written above in the density equation,

Density is 1.1X10^{6}  g/cm^{3}.

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The total number of charges moved to power up the light for 20 min is 3.75 x 10¹⁹

The voltage of the battery = 1.50 V
The power supplied by the battery = 0.45 W

The flashlight will glow for 20 min

The total number of charges moved during the flashing of the flashlight can be found using the formula,

              I = P/V
where I is the current

          P is the power

          V is the voltage supplied

We also know that,

            I = Q/t

Let us substitute this equation, with the above equation, and we get

           Q = Pt/V

Now, let us substitute the known values in the above equation, we get

           Q = 0.45 x 20 / 1.50

              = 9 / 1.50

              = 6 C

Then, the number of charges is

            n = Q/e

where e is the charge of an electron

            n = 6 / 1.6 x 10⁻¹⁹

               = 3.75 x 10¹⁹

Therefore, the number of charges moved is 3.75 x 10¹⁹

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The output power of the hearing aid is approximately 1.6 micro-watts.

What is the sound level supplied to the ear canal by the hearing aid?

The sound stage furnished to the ear canal by using the hearing resource is ninety dB. This is precise within the trouble assertion, in which it's miles said that the female calls for an amplification of 30 dB to pay attention the tv set at a regular extent of 60 dB. Consequently, the hearing resource materials sound at ninety dB to the ear canal. The sound degree is measured in decibels (dB) and is used to specific the relative loudness of a sound. The higher the decibel degree, the louder the sound is.

A sound stage of 90 dB is considered loud and can reason harm to the ears if uncovered to it for an extended time frame.

Lets find the intensity as follows,:

β = 10log( I / Io) where Io = 10^-12 W/m^2

90dB = 10log( I / 10^-12 W/m^2)

9 = log ( I / 10^-12)

10^9 = I / 10^-12

I = .001 W/m^2

Put this  into the equation of I = P/a

The diameter is .0076m so the radius us .0038m

a = pi(.0038^2) = 4.534x10^-5 m^2

Then we multiply that by the intensity above

(.001 W/m^2)(4.534x10^-5 m^2) = 4.534x10^-8 W

output power of the hearing aid = 4.534x10^-8 W

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The kinetic energy of this vehicle is 605.835 KJ when its mass is 1687 kg and traveling at speed of 96.6 km/h.

Given,

mass of the car, m = 1687 kg

speed, v = 96.6 km/h

we know that, Kinetic energy

KE = 1/2 mv²

But we need KE in Joule or KJ

so first we convert km/h to m/s

v = 96.6 km/h = 96.6 x (1000/3600) m/s

v = 26.8 m/s

Now,

KE = 1/2 x 1687 x (26.8)²

or KE = 605835.44 Joule = 605835.44 x 10⁻³ Kilojoule

or KE = 605.835 KJ

Therefore, the kinetic energy of this vehicle is 605.835 KJ when its mass is 1687 kg and traveling at speed of 96.6 km/h.

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The electric potential at that same point also equal to zero where electric field is also zero.

The work energy required to carry a unit of electric charge from a reference point to a particular point in an electric field is known as the electric potential (also known as the electric field potential, potential drop, or the electrostatic potential). It is, more specifically, the energy per unit charge for a test charge that is so small that the disturbance of the field under investigation is insignificant.

The expression for electric potential at a point due to a charge Q is given as,

[tex]P=K\times\frac{Q}{R}[/tex]

while expression for electric field at the same point is,

[tex]E=K\times\frac{Q}{R^{2} }[/tex]

And the resultant electric potential or field will be the vector sum in the case of electric field and algebraic sum in the case of potential. Because, electric field is a vector quantity and electric potential is a scalar quantity.

So, zero electric field does not guarantees that electric potential will also be zero. It will depend on the distance (r) of the point from the two charges.

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The "Load Capacity" of a jack refers to the greatest weight it can support. Maximum weight of cargo that has been authorised by the country where the vehicle was registered.

We can determine the necessary minimum capacity for a trailer jack by analysing the concentration of loads in a typical trailer.

Thus, the "Load Capacity" of a jack refers to the greatest weight it can support.

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The time taken by the electron  is [tex]3.33*10^{-8} seconds[/tex] .

Complete question:

An electron traveling at  [tex]3*10^{6} m/s[/tex] enters a 0.1 m region with a uniform electric field. Find the time it takes the electron to travel through the region of the electric field, assuming it does not hit the side walls.

(See the figure attached)

Since, no field and hence no force act on the electron along X-direction.

Hence, [tex]v_{x}[/tex] remains constant.

Now time taken = t = l/[tex]v_{x}[/tex]

Where,

l = length of field = 0.1 m

v = speed of electron = [tex]3*10^{6} m/s[/tex]

Putting this value in above equation, we get t = [tex]3.33*10^{-8} seconds[/tex] .

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The core is almost entirely comprised of metal, notably iron and nickel, in contrast to the crust and mantle, which are rich in minerals. The iron-nickel alloys in the core are denoted by the chemical symbols NiFe.

The densest sort of solid matter in space is metal. They are often made of heavier metals that have not undergone chemical fusion. Iron and nickel are the most frequent metallic elements that have not yet been mixed, at least inside our Solar System. As we can see from Earth's structure, metals may be liquid like rocks in the hot cores of huge bodies. Consequently, the iron- and nickel-rich metals dominate the core. In the case of Earth, we know that the metal is melted in the outer core, yet there is high-pressure solid metal within that liquid (inner core).

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Charles's law means that the volume of a gas is directly proportional to its absolute temperature

Boyle's Law tells us that the volume of a gas increases as the pressure decreases. Charles's law tells us that the volume of a gas increases with increasing temperature

This is stated by Karl's law, also known as the law of volumes

For a dry gas sample, its volume and Kelvin temperature are directly proportional if the pressure is kept constant

 [tex]\begin{equation*} PV=nRT \end{equation*}[/tex]           P : is a Pressure(Pa)

  [tex]\begin{equation*} V=\frac{nRT}{P} \end{equation*}[/tex]              V : is volume ([tex]m^{3}[/tex])

                              T : absolute temperature (K)

                              R : gas constant [tex]\begin{equation*} 8.314K^{-1}.mol^{-1} \end{equation*}[/tex]

                               n : amount of substance of the gas (mole)

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Mike would rapidly forget most of the material that he read. Dr. Ummel conducts a memory experiment where he shows a fight between two men and describes the contact as "punching" to one group and "tapping" to the other group.

What is meant by memory ?

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The equation that can be used to calculate the mechanical advantage of a simple machine is as follows: MA = delta x0 / delta x1 (option D).

Mechanical advantage is the ratio of the output force produced by a machine (especially a simple machine) to the applied input force.

The mechanical advantage (MA) is used to analyze the forces in simple machines like levers and pulleys.

Mechanical advantage = Fo/Fi

Where;

According to this question, option D best describes the equation that can be used to calculate the mechanical advantage of a simple machine.

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Using the fine focus when trying to put a specimen in sharp focus when using the 40x objective lens ensures that the specimen is brought into focus as accurately and precisely as possible.

This knob is used to adjust the specimen's focus. Additionally, it is used to highlight specific areas of the specimen. The coarse focus knob should often be used to get near before switching to the fine focus knob for fine tweaking.

The fine focus allows for a much finer adjustment of the specimen's position to be made, which is necessary when using a higher magnification objective lens like the 40x.

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Answer: (D.) It does not include object with different masses

Explanation:

It does not include objects with different masses. Therefore, option D is correct.

The force that pulls items toward the center of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity. A universal, non-contact force, gravity. The gravitational pull of the Earth keeps everything on its surface.

All objects with mass, including our Earth, really bend and curve spacetime, which is what causes gravity to pull you toward the ground. What you experience as gravity is that curvature. If things of different masses are dropped from the same height, they will still impact the ground at the same time because Earth provides everything with the exact same acceleration.

One thing that is wrong about Marcus' experiment is that it does not include objects with different masses. Therefore, option D is correct.

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The time spent in the air by the rock is 4.2 seconds.

The range of the of the rock's motion is 88.2 m.

The time spent in the air by the rock is its time of motion and it is calculated as follows;

t = √ ( 2h / g )

where;

t = √ ( 2 x 85 / 9.8 )

t = 4.2 seconds

The range of the of the rock's motion is calculated as follows;

x = vt

x = 21 m/s  x 4.2 s

x = 88.2 m

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The magnitude of the acceleration due to gravity near the surface of Mars is[tex]2*d / 4.41s^2[/tex].

To calculate the acceleration due to gravity near the surface of Mars, we can use the equation:

d = 1/2 * a * t^2

Where d is the distance fallen, a is the acceleration due to gravity, and t is the time taken to fall.

We know that on Earth, the marker took 1.3s to fall to the ground and on Mars it took 2.1s. We also know that the distance fallen is the same on both planets, since the marker was dropped from the same height. Therefore, we can set the distance fallen equal on both planets and use the equations above to solve for the acceleration due to gravity on Mars:

d = 1/2 * a_Earth * (1.3s)^2 = 1/2 * a_Mars * (2.1s)^2

a_Mars = 2d / (2.1s)^2

a_Mars = 2d / (4.41s^2)

Where d is the distance fallen and a_Earth = 9.8 m/s^2 is acceleration due to gravity on Earth.

Therefore, the magnitude of the acceleration due to gravity near the surface of Mars is [tex]2*d / 4.41s^2[/tex]

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Answer:

To determine the rider's acceleration after two minutes, we need to find the second derivative of the distance function s(t) = 3t^3 + 2t^2 + 4 with respect to time. In other words, we need to find the rate of change of the rider's velocity.

The first derivative of s(t) with respect to time is v(t) = 9t^2 + 4t.

The second derivative of s(t) with respect to time is a(t) = 18t + 4.

Now that we have the second derivative, we can find the acceleration after two minutes.

a(2) = 18(2) + 4 = 40 miles/min^2

Therefore the rider's acceleration after two minutes is C. 40 miles/min^2

By disassembling the circuit and connecting a "ammeter" in series (or in-line) with it, all of the electrons that are flowing through the circuit must also pass through the meter in order to measure current in the circuit.

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The gas can be heated at constant pressure if a piston moves outward to let the gas expand as it's heated. Alternatively, the gas can be heated at constant .

Define constant pressure?

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No, we are unable to estimate the austonian's height using this information.

Its Austonian height makes it the second-tallest structure in Texas, behind The Independent, and the second-tallest all-residential structure in North America, west of the Mississippi River.

The second-tallest structure in Austin is the Austinian, which has a connection to an external site. According to a tale, if you drop a rock from the top of a building on a chilly January morning, you will hear the sound of its hit seconds later.

The 58-story Independent, which is 690 feet (210 m) tall and has 58 stories, is the tallest finished structure in the American city of Austin, Texas. After Houston and Dallas, it is the tallest skyscraper in Texas and the tallest all-residential tower west of the Mississippi River. It was completed in 2019.

height of austonian = 16[tex]t^{2}[/tex].

t = [tex]\sqrt{H}[/tex]/4.

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Desalination removes potentially harmful minerals and chemicals in addition to the salt that is present in your water.

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Answer:

5.791244495 KNm

Explanation:

hope it helps

Answer:

-5770

Explanation:

other guy is trash

The rate of heat transfer through the layers of the cylinder will be constant.

There is no heat flow from the sides of the object. The cross-sectional area of ​​a body in the direction of heat flow is constant. This is called one-dimensional heat flow because the temperature of a body is a function of only one dimension (distance from each side of the body). Heat transfer from the hot combustion gases includes forced convection through the hot gas boundary layer, conduction through the cylinder wall, and forced convection (including boiling) into the coolant liquid in head, engine block, and piston.

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The correct answer is option d. The ancients realized that stars did not revolve around the Sun like the planets do, and thus arrived at this conclusion.

One of the ways the ancients knew the planets were different from the stars was by observing their motion in the night sky. Unlike stars, which appear stationary in the sky, the planets were observed to move along a regular path relative to the stars. This movement was known as planetary retrograde and could be observed over the course of many nights.

The ancients also noticed that the planets have a larger angular size in our sky than the stars. This made them more easily distinguishable and allowed them to be distinguished from the stars.

Finally, the ancients noticed that some of the planets had moons orbiting them, which none of the stars did. This was a key factor in distinguishing the planets from the stars.

All in all, the ancients knew the planets were different from the stars by observing their movement in the night sky, noticing the angular sizes, and observing the moons orbiting some of the planets. By understanding these phenomena, the ancients were able to catalog the heavenly bodies and give them each a name.

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