Answer:
a survey
Explanation:
how kids like the playground or they do not like it at all
a mass of 0.8kg at the end of a rope 0.5m long is whirled round ina horizontal circle at an angular speed of 10 rads^-1. what is it's angular momentum?
Answer:
L = 2 J.s
Explanation:
The angular momentum of an object travelling in a horizontal circle is given by the following formula:
[tex]L = mvr[/tex]
where,
L = Angular momentum = ?
m = mass = 0.8 kg
v = linear speed = rω
r = radius of circular path = length of rope = 0.5 m
ω = Angular Speed = 10 rad/s
therefore,
[tex]L = mr^2\omega\\L = (0.8\ kg)(0.5\ m)^2(10\ rad/s)\\[/tex]
L = 2 J.s
The cheetah is one of the fastest-accelerating animals, because it can go from rest to 27 m/s (about 60 mi/h) in 4.0 s. If its mass is 110 kg, determine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in
(a) watts
(b) horsepower.
Answer:
A. 10023.75 Watts
B. 13.44 horse power
Explanation:
A. Determination of the power in Watts.
We'll begin by calculating the energy of the cheetah. This can be obtained as follow
Velocity (v) = 27 m/s
Mass (m) = 110 kg
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 110 × 27²
KE = 55 × 729
KE = 40095 J
Finally, we shall determine the power in Watts. This can be obtained as follow:
Kinetic energy (KE) = 40095 J
Time (t) = 4 s
Power (P) =?
Power = Energy /time
Power = 40095 / 4
Power = 10023.75 Watts
B. Determination of the power in horse power.
Power in Watts = 10023.75 Watts
Power in horse power =?
Recall:
746 Watts = 1 hp
Therefore,
10023.75 Watts = 10023.75 / 746
10023.75 Watts = 13.44 hp
Therefore, the power in horse power is 13.44 hp
F = 480N
Mass = 15 kg
What is your acceleration?
ira a saber diosito xdddi.l.Explanation:
Which are uses of convex mirrors? Check all that apply.
magnifying mirrors for putting on makeup
side-view mirrors on vehicles
hallway safety mirrors
focusing automobile headlights
lenses in sunglasses
Answer:
B. Side-view mirrors on vehicles
C. Hallway safety mirrors
E. Lenses in sunglasses
Explanation:
Trust Me, Look At Attachment.
Answer:
2, 3, and 5 on Edge, 2022.
Explanation:
I had this question on Edge.
(See the attachment below.)
The rest of the answers are:
O Slide 8 - Sample Response: The image seems to be behind the mirror, but nothing is really there.
O Slide 9 - Concave
O Slide 10 - Same size
A Body OF Volume 36cc Floats With 3/4 of its volume submerged in water . The density Of Body is
1. 0.25g/cc 2. 0.75g/cc
3. 0.9g/cc 4. 0.1g/cc
Answer:
Density of body = 0.25g/cc
Explanation:
Given:
Volume submerged in water = 3/4
Find:
Density Of Body
Computation:
Density of body = fraction of body in liquid x density of water
Density of body = [1-3/4]1
Density of body = 0.25g/cc
Martin has hypothesized that the size and types of trees differ between valleys and higher elevations. He sets up a transect line in a wooded valley and randomly creates three 10 x 10 meter plots along the transect line, recording GPS coordinates for the northwest corner of each plot. He identifies and measures (diameter at breast height) every tree within the plots. He repeats this procedure in a wooded area on the ridge above the valley.
Using the scenario above, state the independent and dependent variables.
Answer: The dependent Variables include: Size and Types of trees.
The independent Variables include:
geographic elevations that is, valleys and the higher elevations.
Explanation:
The dependent variable simply refers to the variable a researcher tests or measures during an experiment. On the other hand, the independent variable simply refers to the variable that's controlled during an experiment.
Based on the definition above, the dependent variables include the size and the types of trees while the independent variables include the
geographic elevations that is, the valleys and the higher elevations.
Which process involves a chemical change?
Sugar dissolves in hot water.
B
Candle wax changes from a solid to a liquid.
A chair breaks.
D
Water evaporates from a heated test tube.
E
Exposed iron in a moist environment rusts.
The person kicks the ball in the image below 20 meters. Suppose the soccer ball in the image is replaced by one that is twice the mass of a regular soccer ball. How could the person kick the ball the same distance as the first soccer ball?
( will give brainliest if you help! )
( no trolling or I’ll report you)
Answer:
D
Explanation:
What problem did Katherine face in checking other people’s calculations in the movie ¨Hidden figures¨
Answer:
Information from the leading mathematicians was considered "classified".
define prism and itz colo plz tell me fast
Answer:
A prism is a clear crystal that refracts light
Explanation:
A voltage is applied to a resistor,
which creates a 1.50 A current. If
you double the resistance, keeping
the voltage the same, what will the
new current be?
(Unit = A)
Answer:
Explanation:
By Ohms Law, Voltage = Current * Resistance
Keeping the voltage the same and doubling the resistance, the current will be halved.
So the new current = 1.5/2 = 0.75A
By using Ohms law, the current will be 0.75A.
What is Ohm's law?Ohm's law states that the current flowing through a resistance is proportional to potential difference across the resistance under constant temperature and pressure conditions. Ohm's law can be expressed as:
V =IR
Here, I = 1.50 AR = R Ωso, V = 1.50 R Now Voltage is same but resistance is doubled so new resistance is
Now, put the values of given data in ohms law formula:
2RI = 1.50 R/ 2R = 0.75A
Hence current is 0.75A
To know more about Ohms law here
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A ball is thrown up at a 60 degree angle and lands in 18.5 seconds. what is the initial velocity of the ball?
[tex] \sf \bullet \: \theta = {60}^{ \circ} [/tex]
[tex] \sf \bullet \:Time \: of \: flight , \: t = 18.5 \: s[/tex]
To Find :-[tex] \bullet \sf \: Initial \: velocity , \: u[/tex]
Solution :-[tex] \bf \star\boxed{ \bf t = \dfrac{2u \: sin \theta}{g} }[/tex]
[tex] : \implies \sf 18.5 = \dfrac{2u \: sin60}{10} [/tex]
[tex] : \implies \sf \: 2u \: sin60 = 185[/tex]
[tex]: \implies \sf u = \dfrac{185 \times 2}{ \sqrt{3} \times 2 } [/tex]
[tex]: \implies \sf u = \dfrac{185}{1.73} [/tex]
[tex] \bf: \implies u = 107 \: m {s}^{ - 1} [/tex]
What do you call this item?(it’s a hat)
Answer:
No, it's a cap
Explanation:
Hats have circular or rounded edges all around but with Caps, it has a pointed round front edge
An electromagnetic wave moves through electric and magnetic fields. How might the movement of the wave be described?
A.
The vibrations of the fields are perpendicular to the direction in which the wave moves.
B.
The wave moves back and forth through the fields.
C.
The vibrations of the fields are parallel to the direction in which the wave moves.
close
D.
The wave moves through the fields in a random motion.
A. The vibrations of the fields are perpendicular to the direction in which the wave moves.
An electromagnetic wave moves through electric and magnetic fields, and the movement of the wave can be described as the vibrations of the fields being perpendicular to the direction in which the wave moves, as in option A.
What is the significance of an electromagnetic wave?Electromagnetic waves have many applications, including the transmission of information and energy, and they are also used in other technologies such as radio, television, hospitals, wireless communications, and so on. Other different rays, such as microwaves, infrared radiation, visible light, ultraviolet radiation, etc., are used in different fields, such as X-rays for imaging, etc.
Hence, an electromagnetic wave moves through electric and magnetic fields, and the movement of the wave can be described as the vibrations of the fields being perpendicular to the direction in which the wave moves, as in option A.
Learn more about the electromagnetic wave here.
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Which of the following planets were the ancient Greeks able to see and make careful observations of?
Saturn and Neptune
Neptune and Uranus
Mars and Venus
Mercury and Uranus
Answer:
Neptune and Uranus
Explanation:
Did a quiz on this not to long ago
A student lifts their 75 N backpack 0.50 m onto their chair. How much work is done?
Answer:
37.5 J
Explanation:
With work done equation: W=Fs
W=75*0.50=37.5 J
or use mgh=(75)(0.5) which is the same
A piece of paper floats though the air towards the ground. At one point, the air resistance (Fair) on the
paper pushes up with 0.01 N of force. Force due to gravity (Fg) pulls the ball down with a force of 0.02 N.
Show your work
Answer:
-0.01N
Explanation:
I'm assuming you're asking for the net force of the paper.
0.01N - 0.02N = -0.01N
Three children are struggling and pulling on a single toy. Two of the children, Abe and Barry, are EACH (individually) pulling with a force of 60 Newtons. The third child, Eric, is pulling with enough force to exactly balance Abe and Barry (no child is winning the tug-o-war for the toy). We can label our forces A, B, and E (from each child's name). These three forces are in equilibrium.
If Abe is pulling toward the North and Barry is pulling toward the East, we want to find the total force R due to Abe and Barry (the Resultant of their forces). Note: in THIS case the two forces and R form a right-triangle (with R as the hypotenuse) - as seen using graphical vector addition. As a convention let's have NORTH upward and EAST rightward on this page.
a. Sketch an ACCURATE free-body diagram (three arrows outward from a point showing LABELED forces A, B, and E - each arrow a reasonable length and correct direction):
b. Sketch a labeled diagram for graphical addition of A and B to get R:
c. Show the calculation of the magnitude of R from the magnitudes of A and B:
d. Give the magnitude of force E (in units of Newtons):
e. Describe the direction of force E in terms of the "cardinal" directions (north, east, south, and/or west):
Solution :
c). [tex]$\vec{F}_A = $[/tex] force applied by Abe
[tex]$\vec{F}_B = $[/tex] force applied by Barry
[tex]$\vec{F}_E = $[/tex] force applied by Eric
[tex]$\vec{F}_R = $[/tex] Resultant force
[tex]$\vec{F}_A $[/tex] in the vector form can be written as :
[tex]$\vec{F}_A = 0 \hat{i} + 60 \hat{j}$[/tex]
[tex]$\vec{F}_B $[/tex] in the vector form can be written as :
[tex]$\vec{F}_B = 60 \hat{i} + 0 \hat{j}$[/tex]
The resultant,
[tex]$\vec{F}_R= \vec{F}_A+\vec{F}_B $[/tex]
[tex]$=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$[/tex]
[tex]$=60 \hat i + 60 \hat j$[/tex]
[tex]$|\vec{F}_R| = \sqrt{60^2+60^2}$[/tex]
= 84.853 N
d). As the three forces are in equilibrium, therefore,
[tex]$|\vec F_E| = |\vec F_R|$[/tex]
[tex]$|\vec F_E| =84.853 \ N$[/tex]
e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.
The direction of the resultant force is :
[tex]$\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$[/tex]
[tex]$ = \tan ^{-1}\left(\frac{60}{60}\right)$[/tex]
= 45° north east
The direction of the force E is 45° west or 45° south west.
PLEASE HELP What is it called when the moon passes through the penumbra of Earth’s shadow?(1 point)
total solar eclipse
partial solar eclipse
total lunar eclipse
partial lunar eclipse
If 11,550 J heat is absorbed by a copper object when it is heated from 20.0°C to 30.0°C,
what is the mass of the copper?
The specific heat of copper is 385 J/kgK.
Answer:
The mass of the copper is 3.00kg
Explanation:
Oberon is a moon of Uranus. It has a mass of 3.01 x 1021 kg and is 761.4 km away from Uranus. If the force of gravity
of Uranus is pulling 3.00 x 1025 N on Oberon, what is the mass of Uranus? (6 points)
Answer:
acc to formula= F= G m1m2/rsq
mass of Uranus= F×r sq/G×m
M=3.00×10^25×761.4×761.4×10^6/6.67×10^ -11×3.01×10^21
=3×10^25-8×7614×7614/667×301×10^-2-11+21-2
=173918988×10^11/200767
=866×10^11(approx)
On top labeled A 2 waves 1 above the other, with crests and troughs that line up. On bottom labeled B 2 waves, 1 above the other, so that the crests of the top wave line up with the troughs of the bottom wave.
Will there be noise cancellation in example A or example B?
Answer:
b
Explanation:
Answer:
B B*
Explanation:
B BBBBB
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB
write any three utilities of plastics
Explanation:
container, bottles, boxes, cups
A heat engine does 200 J of work per cycle while exhausting 400 J of waste heat. what is the engine's thermal efficiency?
The engine thermal efficiency is 50%
The engine does 200 joules of work per cycle
It exhausts 400 j
The thermal efficiency can be calculated as follows
= 200/400
= 0.5 × 100
= 50 %
Hence the engine thermal efficiency is 50%
Please see the link below for more information
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The velocity of an object with mass = 2kg is given as a function of time:
V = 2ti + 4[tex]t^{2}[/tex]j
Find the force acting on the object at t = 2 seconds.
Answer:
The force acting on the object at [tex]t = 2\,s[/tex] is [tex]\vec F = (4, 32)\,[N][/tex].
Explanation:
Given that object has a constant mass in time, the force acting on the object ([tex]\vec F[/tex]), in newtons, is defined by following expression:
[tex]\vec F = m\cdot \vec a[/tex] (1)
Where:
[tex]m[/tex] - Mass, in kilograms.
[tex]\vec a[/tex] - Acceleration, in meters per square second.
By definition of acceleration, we know that:
[tex]\vec a = \frac{d}{dt} \vec v[/tex] (2)
Let suppose that given vector velocity is expressed in meters per second. If we know that [tex]m = 2\,kg[/tex], [tex]\vec v = (2\cdot t, 4\cdot t^{2})\,\left[\frac{m}{s} \right][/tex] and [tex]t = 2\,s[/tex], then the force acting on the object is:
[tex]\vec a = (2, 8\cdot t)\,\left[\frac{m}{s^{2}} \right][/tex]
[tex]\vec F = (4, 16\cdot t)\,[N][/tex]
[tex]\vec F = (4, 32)\,[N][/tex]
The force acting on the object at [tex]t = 2\,s[/tex] is [tex]\vec F = (4, 32)\,[N][/tex].
Photosynthesis is an example of an endothermic reaction. Which statement is true about photosynthesis?
A.
Energy is absorbed in the reaction.
B.
Thermal energy is given off by the reaction.
C.
It is a type of combustion reaction.
D.
Light is given off by the reaction.
Answer:
its a
Explanation:
a p e x trust me
[O.04H]The table below shows the use of some energy production methods over time.
Type of energy Average energy used annually in the past (in million tons) Average energy used annually at present (in million tons) Average energy most likely to be used annually in the future (in million tons)
Oil 200 4000 300
Gas 100 2500 700
Coal 1000 2500 1500
Wind 0.1 50 2000
Hydropower 0.7 60 150
Tidal power 0.02 50 500
Based on the table, which of these statements best describes the impact of different methods of energy production on the environment in the past?
There was a rise in the height of tides.
There was a rise in greenhouse gases.
The coastal ecosystem was harmed.
The coastal areas were highly polluted.
I think The coastal areas were highly polluted
Answer:
i think its greenhouse gases may increase
Explanation:
PLEASE HELP!!!!
ITS URGENT!
Answer:
the answer is D
Explanation:
In a 1953 experiment a rocket sled went from 284 m/s to rest within 178 m. If the test subject, John Stapp, had a mass of 84.0 kg: a) what is the amount of Work done to stop the John Stapp? b) how much Force was applied to John Stapp?
8) A force of 10 N stretches a spring 0.50 m from equilibrium. What is the value of the spring constant?
Explanation:
We use Hooke's Law, which states that,
F=kx
F- is the force in newtons
k- is the spring constant
x- is the extension of the spring in meters
Solving for k we get k=F/x
k= 10N/0.50m
=100 N/m