"Strike anywhere matches contain the compound tetraphosphorus trisulfide, which burns to form tetraphosphorus decaoxide and sulfur dioxide gas. How many milliliters of sulfur dioxide, measured at 751 torr and 21.0°C, can be produced from burning 0.869 g of tetraphosphorus trisulfide?"

Answers

Answer 1

Answer:

Can be produced 288mL of SO₂

Explanation:

Based in the reaction:

P₄S₃ + 8O₂ → P₄O₁₀ + 3SO₂

Where 1 mole of tetraphosphorus trisulfide reacts producing 3 moles of sulfur dioxide gas.

0.869g of tetraphosphorus trisulfide (Molar mass of P₄S₃: 220.09g/mol) are:

0.869g P₄S₃ ₓ (1mol / 220.09g) = 3.948x10⁻³ moles of P₄S₃

As 3 moles of SO₂ are produced per mole of P₄S₃:

3.948x10⁻³ moles of P₄S₃ ₓ (3 moles SO₂ / 1 mole P₄S₃) = 0.0118 moles SO₂

Using PV = nRT

V = nRT / P

Where n are 0.0118 moles, R gas constant (0.082atmL/molK), T absolute temperature (21.0°C + 273.15K = 294.15K), and P pressure (751torr / 760 = 0.988atm).

Replacing:

V = 0.0118molₓ0.082atmL/molKₓ294.15K / 0.988atm

V = 0.288L = 288mL


Related Questions

Because cylinder with a volume of 3.00dm^3 contains 8.00 moles of oxygen gas at a temperature of 50.0 K. What is the pressure inside the cylinder? ( R=8.31)

Answers

Answer:

Option A. 1110 KPa.

Explanation:

The following data were obtained from the question:

Volume (V) = 3 dm³

Number of mole (n) = 8 moles

Temperature (T) = 50K

Gas constant (R) = 8.31 KPa.dm³/Kmol

Pressure (P) =..?

Pressure inside the cylinder can be obtained by using the ideal gas equation as follow:

PV =nRT

P x 3 = 8 x 8.31 x 50

Divide both side by 3

P= (8 x 8.31 x 50) /3

P = 1108 ≈ 1110 KPa

Therefore, the pressure inside the cylinder is 1110 KPa

Use the Heisenberg uncertainty principle to calculate the uncertainty (in meters) in the position of a honeybee weighing 0.67 g and traveling at a velocity of 0.80 m/s . Assume that the uncertainty in the velocity is 0.1 m/s.

Answers

Answer:9.84x 10^-31m

Explanation: 9.84x 10^-31m

Heisenberg uncertainty principle states that  says that the position and momentum of a particle cannot be known at the same time and accurately. and that the values  of position and momentum all times must be greater than h/4π.

Using the formula for Heisenberg Uncertainty principle

Δx. Δp ≥ h / 4π

=Δx. m ΔV ≥ h / 4π

where h = Planck’s constant = 6.62607004 × 10-34 m2 kg / s

Δx is the uncertainty in position

Δp is the uncertainty in momentum

m = mass

Δv=is the uncertainty in velocity

Given,

v = 0.80m/s,

m = 0.67 g = 0.67 g / 1000

= 0.00067 kg

h = 6.62607004 × 10-34 m2 kg / s

uncertainty in the velocity is 0.1 m/s.

Δv = 0.80×0.1 = 0.080m/s

Δx. m ΔV ≥ h / 4π

Δx  ≥ h / 4πm ΔV

6.62607004 × 10-34 / 4 π x 0.08 x 0.00067

=6.62607004 × 10-34 / 4 x3.14  5.3 x 10^-5 = 9.84x 10^-31m

The combustion of 1.685 g of propanol (C3H7OH) increases the temperature of a bomb calorimeter from 298.00 K to 302.16 K. The heat capacity of the bomb calorimeter is 13.60 kJ/K . Determine ΔH for the combustion of propanol to carbon dioxide gas and liquid water. g

Answers

Answer:

ΔH =  - 2020.57 kJ/mol

Explanation:

Given that :

mass of propanol = 1.685 g

the molar molar mass = 60 g/mol

Thus; the number of  moles = mass/molar mass

= 1.685 g/60 g/mol

= 0.028 g/mol

However ;

ΔH = heat capacity C × Δ T

Given that:

The temperature increases from  298.00 K to 302.16 K.

Then ;

Δ T = 302.16 K - 298.00 K

Δ T = 4.16 K

heat capacity C = 13.60 kJ/K

ΔH = 13.60 kJ/K × 4.16 K

ΔH =  56.576 kJ

The equation of the given reaction can be represented as :

[tex]C_3H_7OH_{(l)}+\dfrac{3}{2}O_{2(g)} \to 3CO_{2(g)} +4H_2O_{(l)}[/tex]

Thus for 0.028 mol of heat liberated; ΔH =  56.576 kJ

For 1 mole of heat liberated now:

ΔH =  56.576 kJ/0.028 mol

ΔH =  2020.57 kJ/mol

SInce , Heat is liberated, the reaction undergoes an exothermic reaction thus;

ΔH =  - 2020.57 kJ/mol

What is the law of conservation and what happens when two substances at different temperatures come into contact.

Answers

Answer:

- Both energy and matter cannot be neither created nor destroyed.

- An equilibrium temperature will be reached.

Explanation:

Hello,

In this case, the law of conservation is applied to both matter and energy, and it states that both energy and matter cannot be neither created nor destroyed. Specifically, in chemical reactions, it states that in closed systems, the mass of the reactants equals the mass of the products even when the number of moles change. Moreover, for energy, if two substances at different temperatures come into contact, the hot one will cool down and the cold one will heat up until an equilibrium temperature so the energy lost by the hot one is gained by the cold one, which accounts for the transformation of energy.

Best regards.

Two aqueous solutions are both at room temperature and are then mixed in a coffee cup calorimeter. The reaction causes the temperature of the resulting solution to fall below room temperature. Which of the following statements is true?
A. The products have a lower potential energy than the reactants.
B. This type of experiment will provide data to calculate AErxn.
C. The reaction is exothermic.
D. Energy is leaving the system during reaction.
E. None of these statements are true.

Answers

Answer:

the correct option is that C. The reaction is exothermic.

Explanation:

When the temperature decreases, and that the final temperature is lower than the initial, it indicates that less calories were perceived in the calorimeter, therefore said reaction releases heat to the external environment, thus being an exothermic reaction.

The reaction of given two liquids that have been resulted in the lowering of the temperature of the solution has been an exothermic reaction. Thus option C is correct.

There has been a decrease in the temperature of the solution after the mixing of the two solutions.

This can be described as the reaction between the two molecules that will result in the release of the energy from the system to the surroundings. The release of energy will result in the lowering of the temperature of the system.

The reaction in which the release of energy has been there is termed an exothermic reaction. Thus the reaction of given two liquids that have been resulted in the lowering of the temperature of the solution has been an exothermic reaction. Thus option C is correct.

For more information about the reaction temperature, refer to the link:

https://brainly.com/question/24118258

Which 3 laws combine to make the Combined Gas Law?

Answers

Answer:

Boyle's Law, Charles' Law, and Gay-Lussac's Law

Explanation:

Answer:

Boyle's Law, Charles's Law, and Gay-Lussac's Law

Explanation:

Consider each of the following molecules in turn: (a) dimethyl ether, (CH3)2O; (b) trimethylamine, (CH3)3N; (c) trimethylboron, (CH3)3B; and (d) carbon dioxide (CO2). Describe the hybridization state of the central atom (i.e., O, N, B, or C) of each molecule, tell what bond angles you would expect at the central atom, and state whether the molecule would have a dipole moment.

Answers

Answer:

Consider each of the following molecules in turn: (a) dimethyl ether, (CH3)2O; (b) trimethylamine, (CH3)3N; (c) trimethylboron, (CH3)3B; and (d) carbon dioxide (CO2). Describe the hybridization state of the central atom (i.e., O, N, B, or C) of each molecule, tell what bond angles you would expect at the central atom, and state whether the molecule would have a dipole moment.

Which metal will spontaneously react with Zn2+

(aq),

but will not spontaneously react with Mg2+

(aq)

according to the activity series

Answers

The options of the question is not given so the options are;

(1) Mn(s)

(2) Cu(s)

(3) Ni(s)

(4) Ba(s)

Answer: Mn(s)

Explanation:

The spontaneous reaction depends on the Eo value. The positive Eo value are spontaneous and the negative Eo values are not spontaneous.

so, here the Eo values are:

Eo Zn2+/Zn = -0.763v

Eo Mg2+/Mg = 2.37v

Eo Mn2+/Mn = -1.18v

Therefore, Eo cell (with Zn as one of the half-cell) =  Eo Zn2+/Zn - Eo Mn2+/Mn

=  -0.763 - (-1.18)

 = 0.417v

Whereas, Eo cell (with Mg as one of the half-cell) =  Eo Mg2+/Zn - Eo Mn2+/Mn

=  -2.37 - (-1.18) = -1.19v

Thus, Mn(s) metal will spontaneously react because it has a positive  Eo value and  Zn2+(aq), but will not spontaneously react with Mg2+(aq) because it has negative Eo value.

1. Determine whether the following hydroxide ion concentrations ([OH−]) correspond to acidic, basic, or neutral solutions by estimating their corresponding hydronium ion concentrations ([H3O+] using the ion product constant of water (Kw).
Kw = [H3O+][OH−] = [1×10−7 M][1×10−7 M] = 1×10−14 M
Hydronium ion concentration [H3O+] Solution condition
Greater than 1×10−7 M Acidic
Equal to 1×10−7 M Neutral
Less than 1×10−7 M Basic
Drag the appropriate items to their respective bins.
1. [OH−] = 6×10−12 M
2. [OH−] = 9×10−9 M
3. [OH−] = 8×10−10 M
4. [OH−] = 7×10−13 M
5. [OH−] = 2×10−2 M
6. [OH−] = 9×10−4 M
7. [OH−] = 5×10−5 M
8. [OH−] = 1×10−7 M
A. Acidic
B. Neutral
C. Basic
2. A solution has [H3O+] = 5.2×10−5M . Use the ion product constant of water
Kw=[H3O+][OH−]
to find the [OH−] of the solution.
3. A solution has [OH−] = 2.7×10−2M . Use the ion product constant of water
Kw=[H3O+][OH−]
to find the [H3O+] of the solution.

Answers

Answer:

Question 1.

1. [OH−] = 6×10−12 M  is less than 1 * 10⁻⁷, therefore is acidic.

2. [OH−] = 9×10−9 M  is less than 1 * 10⁻⁷, therefore is acidic.

3. [OH−] = 8×10−10 M  is less than 1 * 10⁻⁷, therefore is acidic.

4. [OH−] = 7×10−13 M  is less than 1 * 10⁻⁷, therefore is acidic.

5. [OH−] = 2×10−2 M  is greater than 1 * 10⁻⁷, therefore is basic.

6. [OH−] = 9×10−4 M  is greater than 1 * 10⁻⁷, therefore is basic.

7. [OH−] = 5×10−5 M  is greater than 1 * 10⁻⁷, therefore is basic.

8. [OH−] = 1×10−7 M  is equal to 1 * 10⁻⁷, therefore is neutral

Question 2:

[OH⁻] = 1.92 * 10⁻⁸ M

Question 3:

[H₃O⁺] = 3.70 * 10⁻¹¹ M

Explanation:

The ion product constant of water  Kw = [H₃O⁺][OH⁻] = 1 * 10⁻¹⁴ M² is a constant which gives the product of the concentrations of hydronium and hydroxide ions of dissociated pure water. The concentrations of the two ions are both equal to 1 * 10⁻⁷ in pure water.

A solution that has [OH⁻] greater than 1 * 10⁻⁷ is basic while one with [OH⁻] less than 1 * 10⁻⁷ is acidic.

1. [OH−] = 6×10−12 M  is less than 1 * 10⁻⁷, therefore is acidic.

2. [OH−] = 9×10−9 M  is less than 1 * 10⁻⁷, therefore is acidic.

3. [OH−] = 8×10−10 M  is less than 1 * 10⁻⁷, therefore is acidic.

4. [OH−] = 7×10−13 M  is less than 1 * 10⁻⁷, therefore is acidic.

5. [OH−] = 2×10−2 M  is greater than 1 * 10⁻⁷, therefore is basic.

6. [OH−] = 9×10−4 M  is greater than 1 * 10⁻⁷, therefore is basic.

7. [OH−] = 5×10−5 M  is greater than 1 * 10⁻⁷, therefore is basic.

8. [OH−] = 1×10−7 M  is equal to 1 * 10⁻⁷, therefore is neutral

Question 2:

Kw = [H₃O⁺][OH⁻] = 1 * 10⁻¹⁴ M²

[H₃O⁺][OH⁻] = 1 * 10⁻¹⁴ M²

[OH⁻] = 1 * 10⁻¹⁴ M²/ [H₃O⁺]

[OH⁻] = 1 * 10⁻¹⁴ M²/5.2*10⁻⁵ M

[OH⁻] = 1.92 * 10⁻⁸ M

Question 3:

Kw = [H₃O⁺][OH⁻] = 1 * 10⁻¹⁴ M²

[H₃O⁺][OH⁻] = 1 * 10⁻¹⁴

[H₃O⁺] = 1 * 10⁻¹⁴ M²/ [OH⁻]

[H₃O⁺] = 1 * 10⁻¹⁴ M²/ 2.7 * 10⁻² M

[H₃O⁺] = 3.70 * 10⁻¹¹ M

For each of the following pairs of elements
(1C and N2) (1Ar and Br2)
pick the atom with
a. more favorable (exothermic) electron affinity.
b. higher ionization energy.
c. larger size.
How do you even go about do this?

Answers

Explanation:

Electron affinity is defined as the energy released by the addition of an electron to any gaseous atom. Electron affinity of an atom depends on the electronic configuration.

a).The carbon has vacant p-orbital and nitrogen has half-filled configuration which is more stable. Therefore, one electron can be easily added to carbon whereas nitrogen having more stable configuration releases more amount of energy on adding one electron. Therefore, nitrogen has more electron affinity than carbon.

The bromine has vacant p-orbital whereas argon has filled orbital which is most stable. Therefore, one electron can be easily added to bromine whereas argon having  more stable configuration releases more amount of energy on adding one electron.Therefore, argon has more electron affinity than bromine.

Answer:

1. a. C; b. N; c. C; 2. a. Br; b. Ar; c. Br

Explanation:

Use your Periodic Table and follow the trends in atomic properties (Fig. 1).

Electron affinity increases from left to right and from bottom to top.

The elements with the most exothermic EA are at the upper right corner

Exceptions are the noble gases (group 18) and the pnictogens (group 18).

The elements of Group 18 have a complete octet and have no tendency to accept electrons.  

The elements of Group 15 have half-filled p subshells. They are more stable than the elements immediately preceding them, so they are less exothermic when adding an electron.  

Ionization energy increases from left to right and from bottom to top.  

The atoms with the highest IE are at the upper right corner.

Atomic size increases from right to left and from bottom to top.  

The largest atoms are on the lower-left corner.

1. C vs N

(a)   EA: C. N is a Group 15 element

(b)    IE: N. N is further to the right.

(c) Size: C. C is further to the left.

2. Ar vs Br

(a)   EA: Br. Ar is a noble gas.

(b)    IE: Ar. Ar is further to the right.

(c) Size: Br. Br is nearer to the bottom.


Spell out the full name of the compound.

Answers

Explanation:

Step one look for the longest chain of carbon atoms

Longest chain is 7 C atoms

Step 2 look for double bonds or others functional groups

it is present in 3rd carbon

Therefore IUPAC name is 3-heptene

From point of stereochemistry it can also be written as trans-3-heptene as the hydrogens are placed in opposite side of the C=C bond.

Hope this helps...

The compound name is: trans 3-heptene

What is molecular compound?

Molecular compounds are inorganic compounds that take the form of discrete molecules.

Looking at the given compound:

1. We need to look for the highest carbon chain, So in this compound the highest carbon chain is of 7 carbon atoms.

2. This compound also has a double bond in between that is present at the third carbon which can be detected by numbering the carbon in a order where the lowest number will come over a double bond.

3. Lastly, we can derive the name for this compound as hept-3-ene or 3-heptene.

4. Also, there is one more thing to notice here which is the position of two hydrogen that are present as substituents since they are placed opposite to each other thus we can name it as trans 3-heptene.

Thus, the compound name is: trans 3-heptene.

Find more information about Compound here:

brainly.com/question/1603500

A loud classroom demonstration involves igniting a hydrogen filled balloon. The hydrogen within the balloon reacts explosively with oxygen in the air to form water. If the balloon is filled with a mixture of hydrogen and oxygen, the explosion is even louder than if the balloon is filled only with hydrogen-the intensity of the explosion depends on the relative amounts of oxygen and hydrogen gas within the balloon. Look at the molecular views representing different amounts of hydrogen and oxygen gas in four different balloons of equal size. Based on the balanced chemical equation (you will have to write one), which balloon will make the loudest explosion

Answers

Hey there!

balanced chemical reaction:

2 H₂ (g) + 1 O₂ ( g )  ----------> 2 H₂O ( g )

Reagents :

H = 2 * 2 = 4

O = 1 * 2 =  2

----------------------

total = 4 + 2 => 6

Products:

H = 2 * 2 = 4

O = 2 * 1 = 2

___________

total = 4 + 2 => 6

Hope this helps

Use the link Standard Reduction Potentials. Write net equations for the spontaneous redox reactions that occur during the following or none (all lower case) if there is no extensive reaction. Use the lowest possible coefficients. A) Iron metal is dipped into a Ni2+ solution.B) Copper metal is added to hydrochloric acid.C) A silver wire is added to nitric acid (HNO3).D) Magnesium metal is added to waterE) Chromium metal is added to a solution of Mg2+

Answers

Answer:

a) Fe(s) + Ni^2+(aq) ----> Fe^2+(aq) + Ni(s)

b) no reaction

c) no reaction

d) 2Mg(s) + 2H2O(l)-----> 2Mg^2+(aq) + O2(g) +4H^+(aq)

e) no reaction

Explanation:

It is important to say here that the ability of a particular chemical specie to displace another chemical specie is dependent on the relative standard reduction potentials of the species involved.

All the reactions stated above are redox reactions. Let us take reaction E as an example. Mg^2+ has a reduction potential of -2.37 V while Cr^3+ has a reduction potential of -0.74V. Since the reduction potential of magnesium is more negative than that of chromium, there is no reaction when a piece of chromium metal is dipped into a solution of Mg^2+.

Similarly, though metals displace hydrogen gas from dilute acids, metals that are less than hydrogen in the reactivity series cannot do that. This explains why there is no reaction when copper and silver are dipped into dilute acid solutions.

Reaction occurs when iron is dipped into a nickel solution because the reduction potential of Fe^2+ is far more negative than that of Ni^2+.

QUESTION 11
Which of the following compounds has the highest boiling poid?
O CH3CH2CH2COOH
O CH3OCH2CH2CH3
O CH3CH2CH2OH
O CH3CH2CH2CHO

Answers

Answer:

CH3CH2CH2COOH

Explanation:

Both carboxylic acids and alcohols posses hydrogen bonding. The difference between the two lies in the strength of the hydrogen bonding and the structure of the molecules.

Alcohols predominantly form linear hydrogen bonds in which the dipole of the -OH group of one molecule interacts with that of another molecule. This gives a linear arrangement of hydrogen bonded intermolecular interactions which significantly impacts the boiling point of alcohols.

However, the carboxylic acids posses the carbonyl (C=O) which is more polar and interacts more effectively with the -OH bond to form dimmer species. These dimmers have a much higher boiling point than the corresponding alcohols due to stronger hydrogen bonds. Hence CH3CH2CH2COOH has a greater boiling point than CH3CH2CH2OH.

The other compounds in the options do not posses hydrogen bonds hence they will have much lower boiling points.

3. In the above molecules, generally the octet rule can not be followed for every atom. When there are too many electrons or two few electrons and the atoms cannot or will not form multiple bonds, which atom in the structure does not receive a complete or has an expanded octet? Explain why only one atom in the structure is affected in these situations.

Answers

Answer:

The octet rule is possible in those atoms which has high number of electrons in their shells.

Explanation:

The octet rule is a type of rule in which the atom has 8 electrons in its outermost shell or valance shell. This rule is not possible for hydrogen and helium because there are very less number of electrons and we know that octet rule needed more number of electrons. Only one atom may be hydrogen or helium is affected in the structure is affected in these situations due to presence of less number of electrons in shells.

Which molecule will have a double bond?

Answers

Answer:

Covalent Molecule

Explanation:

A reaction occurs between sodium carbonate and hydrochloric acid, producing sodium chloride, carbon dioxide, and water. Which is the correct set of coefficients, respectively, for the balanced reaction?
a. 5 10 10 5 5
b. 1 2 2 1 1
c. 8 6 5 10 5
d. none of these

Answers

Answer:b

Explanation:

The correct set of coefficients of the balanced chemical equation of sodium carbonate and hydrochloric acid is 1, 2, 2, 1, 1. Therefore, option (b) is correct.

What is the balanced chemical equation?

The chemical equation in which the number of atoms of each element of substances is equal on either side of the chemical equation is known as a balanced chemical equation.

The law of conservation of mass must be followed by every balanced chemical equation. By obeying this law, the total mass of reactants should be equal to the total mass of the products in a balanced chemical equation.

Given the chemical equation of the reaction between sodium carbonate and hydrochloric acid,

Na₂CO₃  +  HCl  →  NaCl  +  H₂O  +  CO₂

The balanced chemical equation will be the one in which the number of Na, C, O, H, and Cl will be equal on both sides of the equation.

Na₂CO₃  +  2 HCl  →  2 NaCl  +  CO₂  +  H₂O  

Therefore, the set of coefficients for the balanced reaction is 1, 2, 2, 1, 1.

Learn more about the balanced chemical equation, here:

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#SPJ2

Write a balanced molecular equation for hydrochloride acid solution combined with a potassium hydroxide solution, an acid base reaction occurs

Answers

Answer:

HCl (aq) + KOH (aq) --------> KCl (aq) + H2O (l)   [balanced molecular equation]

Explanation:

Balanced molecular equation has all the components of reaction written as "molecules" thus the name molecular (the other equations break appropriate components into ions, those are total ionic or net ionic equation)

We know hydrochloride acid solution is written as HCl (aq) and potassium hydroxide solution is written as KOH (aq). We know from our knowledge that when acids react with bases they make salt and water, so now we react!

HCl (aq) + KOH (aq) --------> KCl (aq) + H2O (l)   [balanced molecular equation]

Write chemical equation and balance for copper(II)nitrate and barium sulfide

Answers

Answer:

Cu(NO3)2 + BaS ==> Ba(NO3)2 + CuS

Explanation:

Ba(NO3)2 + CuSO4 = BaSO4 + Cu(NO3)2 (Barium nitrate + Copper (II) sulfate)

Nitrogen monoxide is produced by combustion in an automobile engine. For the following reaction, 4.36 grams of nitrogen monoxide are mixed with excess oxygen gas . The reaction yields 5.46 grams of nitrogen dioxide . nitrogen monoxide ( g ) oxygen ( g ) nitrogen dioxide ( g ) What is the theoretical yield of nitrogen dioxide

Answers

Answer:

[tex]6.68~g~NO_2[/tex]

Explanation:

We have to start with the combustion reaction:

[tex]NO~+~O_2~->~NO_2[/tex]

Then we can balance the reaction:

[tex]2NO~+~O_2~->~2NO_2[/tex]

If we want to find the theoretical yield, we have to calculate the amount of [tex]NO_2[/tex]. To do this, we have to first convert the 4.36 g of [tex]NO[/tex] to moles [tex]NO[/tex] (using the molar mass 30 g/mol), then we have to convert from moles of [tex]NO[/tex] to moles of [tex]NO_2[/tex] (using the molar ratio) finally, we have to convert from moles of [tex]NO_2[/tex] to grams of [tex]NO_2[/tex] (using the molas mass 46 g/mol), so:

[tex]4.36~g~NO\frac{1~mol~NO}{4.36~g~NO}\frac{2~mol~NO_2}{2~mol~NO}\frac{46~g~NO_2}{1~mol~NO_2}=6.68~g~NO_2[/tex]

I hope it helps!

HELP PLEASE!
When phenol dissolves in water, a few (no all) of the molecules ionize H+ from the -OH group. This makes it
O a reducing agent
O an oxidizing agent
O a weak acid
a weak base

Answers

Answer: a weak acid

Explanation:

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases. Oxidizing agent is the substance which itself gets reduced by gaining electrons and thus oxidize others.

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced. Reducing agent is the substance which itself gets oxidized by losing electrons and thus reduces others.

Weak acids are those substances which dissociate partially to give [tex]H^+[/tex] ions when dissolved in water.

[tex]C_6H_5OH\rightleftharpoons C_6H_5O^-+H^+[/tex]

Weak bases are those substances which dissociate partially to give [tex]OH^-[/tex] ions when dissolved in water.

[tex]NH_4OH\rightleftharpoons NH_4^++OH^-[/tex]

Calculate ΔG (in kJ) for the following reaction at 1.0 atm for C2H6, 0.5 atm for O2, and 2.0 atm for CO2, and 25 oC: C2H6 (g) + O2 (g) ---> CO2 (g) + H2O (l) (unbalanced) ΔGfo C2H6 (g) = - 32.89 kJ/mol; ΔGfo CO2 (g) = - 394.4 kJ/mol; ΔGfo H2O (l) = - 237.13 kJ/mol

Answers

Answer:

Explanation:

Calculate ΔG (in kJ) for the following reaction at 1.0 atm for C2H6,

0.5 atm for O2, and

2.0 atm for CO2, and

25 oC:

C2H6 (g) + O2 (g) ---> CO2 (g) + H2O (l) (unbalanced)

ΔGfo C2H6 (g) = - 32.89 kJ/mol;

ΔGfo CO2 (g) = - 394.4 kJ/mol;

ΔGfo H2O (l) = - 237.13 kJ/mol

The balance equation of this reaction is

[tex]2C_2H_6 (g) + 7O_2 (g) ---> 4CO_2 (g) + 6H_2O (l)[/tex]

[tex]\Delta G_{rxn}=\sum G^o_f(product)-\sum G^o_f(reactant)[/tex]

[tex]=4G^o_f(CO_2)+6G^o_f(H_2O)-7G^o_f(O_2)-2G^o_f(C_2H_6)\\\\[/tex]

[tex][4(-394.4)+6(-237.13)-7(0)-2(-32.89)]kJ/mol\\\\=-1577.6-1422.78+65.78\\\\=-3000.38+65.78\\\\=-2934.6kJ/mol[/tex]


will give BRAINLIEST!!! Will give BRAINLIEST

A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water.
Answer the following questions, being sure to include units and remember sig figs. Show your work.


What possible issues may result from air bubbles in the burette for this experiment? Be specific about
how this may affect the final calculated concentration of acid (Will it be lower or higher than actual?
Why?)

Answers

Answer:

The calculated concentration of acid will be higher than the actual concentration of acid

Explanation:

We have information that all enable us to calculate the concentration of KOH in the solution. From the question, we have;

Mass of KOH= 14.555g

Molar mass of KOH= 56.1056 g/mol

Volume of solution= 500 ml

Number of moles of KOH= ???

From;

m/M= CV

m= mass of KOH

M= molar mass of KOH

C= concentration of KOH solution

V= volume of solution

Substituting values;

14.555g/56.1056 g/mol = C× 500/1000

0.259 moles = 0.5C

C= 0.259/0.5

C= 0.518 M

If the acid is HA, the reaction equation is;

KOH(aq) + HA(aq) ----> KA(aq) + H2O(l)

The concentration of the acid is usually determined via titration. This involves delivering a particular volume of acid in a burette into the base and watching out for the volume of acid used at end point. If there are air bubbles in the burette, then more volume of acid is recorded than that actually used and this will make the calculated concentration of the acid to be higher than the actual concentration of acid present.

How many elements make up most of the ocean?

Answers

Answer:

Hydrogen and oxygen

Explanation:

Answer:

eight

Explanation:

the elements of course are the following

hydrogen

oxygen

calcium

sodium

sulfur

magnesium

chlorine

potassium

i hope this helps you

AMMONIUM CARBONATE
5. How many grams of nitrogen (N) are in a mass of ammonium carbonate that contains
1.23x10^23 carbon atoms?​

Answers

Answer:

Zero

Explanation:

Hello,

The question require us to calculate the mass of nitrogen present in aluminium carbonate.

This can easily be calculated using Avogadro's number as a constant with some minor calculations but however in this case, we can't because there's no single atom of nitrogen present in aluminium carbonate hence we can't calculate the mass of nitrogen present in it.

Chemical formula of aluminium carbonate = Al₂(CO₃)₃.

From the above chemical formula, we can see that there's no single atom of nitrogen present in the formula hence the mass of nitrogen present in aluminium carbonate that contains 1.23×10²³ carbon atoms is zero.

What force is needed to accelerate a truck with mass 2,000 kg at a rate of 5.0
m/s22
O A. 1,000 N
B. 20,000 N
C. 2,000 N
O D, 10,000 14

Answers

Answer:

D

Explanation:

[tex]F=ma \\\\F=2000\cdot 5=10,000N[/tex]

Hope this helps!

Combustion analysis of 2.400 g of an unknown compound containing carbon, hydrogen, and oxygen produced 4.171 g of CO2and 2.268 g of H2O. What is the empirical formula of the compound

Answers

Answer:

[tex]C_3H_8O_2[/tex]

Explanation:

Hello,

In this case, for the given combustion process, we can compute the present moles of carbon atoms by considering that the only product containing carbon is CO2, thus, we have:

[tex]n_C=4.171gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2} =0.095molC[/tex]

Next, we compute the moles of hydrogen that is present at the water only as a product:

[tex]n_H=2.268gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O} =0.252molH[/tex]

Then, we compute the moles of oxygen by considering the oxygen present in both the CO2 and H2O and the initial sample:

[tex]m_O=2.400g-0.095molC*\frac{12gC}{1molC} -0.252molH*\frac{1gH}{1molH} \\\\m_O=1.008gO\\\\n_O=1.008gO*\frac{1molO}{16gO} =0.063molO[/tex]

Now, we divide the moles of C, H and O by the moles of O since they are lower amount, in order to compute the subscript in the empirical formula:

[tex]C=\frac{0.095}{0.063}=1.5\\ \\H=\frac{0.252}{0.063}=4\\ \\O=\frac{0.063}{0.063}=1[/tex]

But the smallest whole number is:

[tex]C_3H_8O_2[/tex]

Regards.

Pre-Lab Study Questions / 9
1. Where are the valence electrons in an atom?
valen
2. How are positive and negative ions fomed?
3. Why are electrons shared in molecular compounds?​

Answers

Answer:

See detailed answer with explanation below.

Explanation:

Valence electrons are electrons found on the outermost shell of an atom. They are the electrons in an atom that participate in chemical combination. Recall that the outermost shell of an atom is also referred to as its valence shell. Let us consider an example; if we look at the atom, sodium-11, its electronic configuration is 2,8,1. The last one electron is the valence electron of sodium which is found in its outermost or valence shell.

Positive ions are formed when electrons are lost from the valence shell of an atom. For instance, if the outermost electron in sodium is lost, we now form the sodium ion Na^+ which is a positive ion. Positive ions possess less number of electrons compared to their corresponding atoms.

Negative ions are formed when one or more electrons is added to the valence shell of an atom. A negative ion possesses more electrons than its corresponding atom. For example, chlorine(Cl) contains 17 electrons but the chloride ion (Cl^-) contains 18 electrons.

In molecular compounds, a bond is formed when two electrons are shared between the bonding atoms. Each bonding atom may contribute one of the shared electrons (ordinary covalent bond) or one of the bonding atoms may provide the both shared electrons (coordinate covalent bond). The shared pair may be located at an equidistant position to the nucleus of both atoms. Similarly, the electron may be drawn closer to the nucleus of one atom than the other (polar covalent bond) depending on the electro negativity of the two bonding atoms.

The electrons are shared in order to complete the octet of each atom by so doing, the both bonding atoms now obey the octet rule. For example, two chlorine atoms may come together to form a covalent bond in which each chlorine atom has an octet of electrons on its outermost shell.

Perform the conversions between energy units.
861 kJ=
J
3495 kcal=
kJ
7.84×106

Answers

Answer:

861 kJ = 861000 J,

3495 kcal = 14623.08 kJ

Explanation:

As I mentioned before, the last bit " 7.84 × 106 " just threw me off track, so I am simply going to assume that that does not appear in your question.

_______________________________________________________

Now we have 861 kilojoules, and have to convert it into joules for this first bit. Kilo being equal to 1000, to convert to joules you would have to multiply 861 by 1000, = 861000 Joules.

This second bit here asks us to convert 3495 kilocalorie to kilojoules. The difference between the two is that one is about 4.18 times greater than the other, so 3495 kilocalorie = 3495 * 4.18 = 14623.08 kilojoules.

Hope that helps!

Among three bases, X−, Y−, and Z−, the strongest one is Y−, and the weakest one is Z−. Rank their conjugate acids, HX, HY, and HZ, in order of decreasing strength. Rank the acids from strongest to weakest. To rank items as equivalent, overlap them.

Answers

Answer: HZ > HX > HY in order of decreasing strengths.

Explanation: Generally, the rule is that the stronger the acid, the weaker its conjugate base and vice versa; same rule applies for bases and their conjugate acids.

So the weakest base Z- would have the strongest conjugate acid. Consequently, the strongest base Y- would have the weakest conjugate acid.

I hope this was MORE helpful as this is the correct answer.

The ranking of the conjugate acids in order of decreasing strength (i.e from strongest to weakest) is; HZ < HX < HY

First we must know that the stronger a base is, the weaker is it's conjugate acid and the weaker a base is, the stronger is it's conjugate acid.

Therefore, the order of decreasing strength of the conjugate acid is; HZ < HX < HY

Read more:

https://brainly.com/question/23917439

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