Answer:
His average speed.
Explanation:
Average speed = Total distance travelled / total time .
In the given case odometer measures total distance travelled . Dividing it by time will give average speed .
Average velocity can not be the answer as it is measured by dividing displacement by time . Displacement here is zero because initial and final point are same . Instantaneous velocity is given by the speedometer . It keeps on changing all the time . It is actually speed at a particular point of time . It can not be average velocity or speed .
which of the following changes will increase the frequency of an oscillating pendulum?
a. an increase in the mass of the pendulum.
b. an increase in the initial height of release.
c. an increase in the length of the rope.
d. more than one of the above
e. none of the above
explain your answer.
NO LINKS.
Answer:
e. none of the above
Explanation:
The frequency of an oscillating pendulum is the number of oscillation per unit time.
Mathematically, the frequency of an oscillating pendulum is given by the formula;
F = 1/2π√(k/m)
Where;
F is the frequency of oscillation.
k is the spring constant.
m is the mass of the spring.
Hence, none of the changes mentioned will increase the frequency of an oscillating pendulum.
A box is at rest on a table. What can you say about the forces acting on the box?
The upward
and the downward
are balanced.
Answer:
normal force and gravitational force
Explanation:
I hope this helps :D
I cant solve this problem, and our teacher said that this would be in the test we'll have tomorrow, can someone help me?
A body of m = 6.8kg is launched with a speed of 7.5 m / s towards the top of an inclined plane of 15 ° with respect to the horizontal. in the absence of friction, what displacement does it make before reversing the direction of motion?
Answer:
d = 11.1 m
Explanation:
Since the inclined plane is frictionless, this is just a simple application of the conservation law of energy:
[tex] \frac{1}{2} m {v}^{2} = mgh[/tex]
Let d be the displacement along the inclined plane. Note that the height h in terms of d and the angle is as follows:
[tex] \sin(15) = \frac{h}{d} \\ or \: h = d \sin(15) [/tex]
Plugging this into the energy conservation equation and cancelling m, we get
[tex] {v}^{2} = 2gd \sin(15)[/tex]
Solving for d,
[tex]d = \frac{ {v}^{2} }{2g \sin(15) } = \frac{ {(7.5 \: \frac{m}{s}) }^{2} }{2(9.8 \: \frac{m}{ {s}^{2} })(0.259)} \\ = 11.1 \: m[/tex]
How are work and power different
Work is defined as the process of energy transfer to the motion of an object through the application of force. Power is defined as the amount of energy transferred in unit time.
A standard parallel plate capacitor is connected to a battery and is given enough time to charge fully. After it is fully charged, the capacitor is disconnected from the battery. After that, prankster Bob comes along and pulls the plates further apart from each other, doubling the distance d between the plates. How do the following quantities change? The choices are: quadruple, double, stay the same, halve, or quarter.
a) Capacitance
b) Charge on the capacitor
c) Voltage across the capacitor
d) Electric field within the capacitor
e) Energy stored in the capacitor
f) Does Bob have to do work in order to pull the plates apart? (Yes or no, and a brief explanation)
g) Are parts (e) and (f) consistent, given that the battery was disconnected?
Answer:
a) capacitance is doubled., b) Q = cte, c) oltage doubling the distance doubles, d) ΔE =0, e) U = Q² / 2C, f) W>0
Explanation:
he capacitance of a condensate is
C =[tex]\frac{ Q}{ \Delta V} =\epsilon_o \frac{A}{d}[/tex]
let's use this expression to answer the question
a) Capacitance.
Without distance, the capacitance is doubled.
Answer: Half
b) The charge.
As the battery is disconnected, no more electrons reach the capacitor, so the charge remains the same
Q = cte
c) the voltage
ΔV = E d = ([tex](\frac{Q}{\epsilon_o A}) \ d[/tex]
so the voltage doubling the distance doubles
d) The electric field between parallel plates is constant
E = Q / A eo
E =0
e) The stored energy is described by the expression
U = Q² / 2C
as capacitance decreases and discant increases, stored energy increases
f) The work to separate the positive charge, that the force must be in the same direction as the electric force
g) when the battery is disconnected the energy in the capacitor remains constant
Electromagnetic waves are commonly referred to as _________
O electricity
O magnetism
O light
In a cloud chamber experiment, a proton enters a uniform 0.260 T magnetic field directed perpendicular to its motion. You measure the proton's path on a photograph and find that it follows a circular arc of radius 6.42 cm.
Required:
How fast was the proton moving?
Answer:
the proton speed of the proton was 1.6 × 10⁶ m/s
Explanation:
Given the data in the question;
Radius r = 6.42 cm = 0.0642 m
magnetic field B = 0.260 T
we know that; charge of proton q = 1.602 × 10⁻¹⁹ C
And mass of proton m = 1.672 × 10⁻²⁷ kg
we know that; Magnetic Force F = qvBsinθ
where q is the charge of proton, v is velocity, B is the magnetic field and θ is angle ( 90° )
Also the Centripetal force experienced by the particle is;
F = mv² / r
where r is radius, m is mass of proton and v is velocity
hence;
qvBsinθ = mv² / r
we solve for v
rqvBsinθ = mv²
divide both sides by mv
rqvBsinθ / mv = mv² / mv
rqBsinθ / m = v
so we substitute
v = [ 0.0642 m × (1.602 × 10⁻¹⁹ C) × 0.260 T × sin(90°) ] / 1.67 × 10⁻²⁷ kg
v = 2.6740584 × 10⁻²¹ / 1.672 × 10⁻²⁷
v = 1.6 × 10⁶ m/s
Therefore, the proton speed of the proton was 1.6 × 10⁶ m/s
When gas condense it ______ heat and temperature _____
A. gain heat, temperature decrease
B. gain heat, temperature increase
C. loses heat, temperature doesn't change
Answer:
C
Explanation:
A 30-N iPad is dropped from a height of 10 m and strikes the ground with a speed of 13 m/s.
What average force of air friction acted on the iPad as it fell?
Answer:
Initially the PE of the object was W * h = 30 * 10 = 300 Joules
The KE of the object when it struck the ground was 1/2 M v^2
KE = 1/2 * 30/9.8 * 13^2 = 259 J
So the object lost 41 J to friction during the fall
Since Work = Force * distance
Force = 41 J / 10 m = 4.1 N (the average force of friction)
A student decides to give his bicycle a tune up. He flips it upside down (so there's no friction with the ground) and applies a force of 34 N over 0.6 seconds to the pedal, which has a length of 16.5 cm. If the back wheel has a radius of 33.0 cm and moment of inertia of 1200 kg cm^2, what is the tangential velocity of the rim of the back wheel in m/s
Answer:
[tex]V=9.2565m/s[/tex]
Explanation:
From the question we are told that:
Force [tex]F = 34 N[/tex]
Time [tex]t = 0.6 s[/tex]
Length of pedal [tex]l_p=16.5cm \approx0.165m[/tex]
Radius of wheel [tex]r = 33 cm = 0.33 m[/tex]
Moment of inertia, [tex]I = 1200 kgcm2 = 0.12 kg.m2[/tex]
Generally the equation for Torque on pedal [tex]\mu[/tex] is mathematically given by
[tex]\mu=F*L\\\mu=34*0.165[/tex]
[tex]\mu=5.61N.m[/tex]
Generally the equation for angular acceleration [tex]\alpha[/tex] is mathematically given by
[tex]\alpha=\frac{\mu}{l}[/tex]
[tex]\alpha=\frac{5.61}{0.12}[/tex]
[tex]\alpha=46.75[/tex]
Therefore Angular speed is \omega
[tex]\omega=\alpha*t[/tex]
[tex]\omega=(46.75)*(0.6)[/tex]
[tex]\omega=28.05rad/s[/tex]
Generally the equation for Tangential velocity V is mathematically given by
[tex]V=r\omega[/tex]
[tex]V=(0.33)(28.05)[/tex]
[tex]V=9.2565m/s[/tex]
A horizontal line labeled B has an arrow labeled A strike it from right and above and then another arrow D emerges from the strike point at the same angle as A. A dotted line C evenly divides the angle between A and D.
In the mirror diagram shown, which is the normal?
A
B
C
D
Answer:
c is the actual answer.
Explanation:
Answer:
c is correct
Explanation:
1. Which statement about data attenuation is true? (1 point)
Data carried on a fiber-optic cable experience more attenuation than data broadcast from a radio tower.
Fiber-optic cables experience very little attenuation over large distances.
Data carried on a fiber-optic cable experience more attenuation than data carried on a copper wire.
Data carried on a copper wire and data broadcast from a radio tower experience very little attenuation over large distances.
2. Which statement is an example of information being carried by an electromagnetic wave that has been interpreted by humans?(1 point)
A sound wave in an ultrasound machine transmits information about the parts of the body it travels through.
A seismic wave changes speed, conveying information about the materials it has passed through.
A wave in the ocean changes, indicating a change in the depth of the water.
A light wave from a distant galaxy experiences redshift, indicating that the galaxy is moving away from Earth.
3. Which statement is true about a parabolic dish? (1 point)
It reflects waves and focuses them to a point.
It refracts waves in the dish.
It absorbs the wave energy.
It filters the type of electromagnetic radiation.
4. Which natural phenomenon describes guitar strings vibrating at certain natural frequencies?(1 point)
interference
beats
oscillation
resonance
5. What will increase the power output when doing work?(1 point)
doing less work in the same amount of time
doing the same work in less time
doing the same work in more time
doing less work and increasing the amount of time
Answer:
1. c
2. d
3. a
4. d
5. c
Explanation:
im pretty sure im right
What makes water move through the water cycle? A the sun the rain C precipitation the ground
Answer: A. The Sun
Explanation: A. The Sun makes water move through the water cycle
At its peak, a tornado is 65 m in diameter and has 350 km/h winds. What is its frequency in revolutions per second?
Answer:
Explanation:
circumference = diameter * [tex]\pi[/tex]
circumference = 65 * [tex]\pi[/tex]
circumference = 204.2035225m
350 km/h = 97.222222 m/s
0.4761 revolutions per second
How many times does the kinetic energy of a car increase when traveling 60 mph as opposed to traveling 15 mph?
K.E. increases
5
4
16
20
Answer:
20
Explanation:
i'm not so sure with my answer
A nurse asks a doctor about medication for a
patient in a hospital. The doctor accidentally tells
the nurse to give the patient the wrong
medication, and the nurse follows the doctor's
orders. Which type of medical error has occurred?
Answer:
medication error thats easy
Find the Input force, if the Mechanical Advantage of the simple machine used is 5 and Output force is 50 N.
P.S PLEASE DO NOT POST A LINK THAT I HAVE TO DOWNLOAD EVERY TIME I ASK A QUESTION PEOPLE POST THAT JUST POST A WRITEN ANSWER WITH AN EXPLINATION THAT IS ALL
Answer:
6N
Explanation:
define quant......am physics
Answer:
✍ What is quantum physics?➳ It's the physics that explains how everything works; the best description we have of the nature of the particles that make up matter and the forces with which they interact. Quantum physics underlies how atoms work, and so why chemistry and biology work as they do.What is the efficiency of an engine that exhausts 440 J of heat to a cold reservoir and receives 570 J of heat from a hot reservoir? *
Answer:
Efficiency = 77%
Explanation:
Input energy = 570 J
Output energy = 440 J
To find the efficiency;
[tex] Efficiency = \frac {Out-put \; energy}{In-put \; energy} * 100 [/tex]
Substituting into the equation, we have;
[tex] Efficiency = \frac {440}{570} * 100 [/tex]
[tex] Efficiency = 0.7719 * 100 [/tex]
Efficiency = 77.19 ≈ 77%
Therefore, the efficiency of the engine is 77 percent.
PLZ HELP NO SNEAKY LINK OR I WILL REPORT U OR NON ANSWERS
The blending of the fundamental tone with overtones produces the __?__of an instrument.
Answer:
The blending of the fundamental tone with overtones produces the Sound Quality of Musical Instruments of an instrument.
The blending of the fundamental tone with overtones produces the sound quality of Musical Instruments of an instrument.
The tone of a sound wave determines the timbre, also known as timber, of the auditory impressions it creates. The wave structure of a sound, which varies with the amount of overtones, or harmonics, present, their frequencies, and their relative intensities, determines the timbre of the sound.Resonance is a common technique used by musical instruments to enhance sound waves and increase volume. When an object vibrates in response to sound waves of a particular frequency, this is known as resonance.What are tones and overtones?Aside from a simple sine wave, the fundamental tone and numerous additional tones of various frequencies make up the waveforms of all sounds. Overtones or harmonics are non-fundamental tones that are whole-number multiples of the fundamental tone.Learn more about sound quality of Musical Instruments brainly.com/question/9571788
#SPJ2
A force F making an angle with the horizontal is acting on an object resting on the table. Which statement is true for the motion of sliding the object on the table? A. It is independent of all the forces acting on the object. B. It depends only on the forces acting along the x-axis. C. It depends only on the forces acting along the y-axis. D. It depends only on the normal force acting on the object. E. It depends only on the frictional force acting on the object.
Answer:
C
Explanation:
it depends only on the forces acting along the y- axis
Answer:
The statement that is true for the motion of sliding the object on the table is : its independent of all forces acting on the object
Explanation:
Part A : A cylindrical water tank 10cm high and 520cm in diameter is filled with solution with a density of 0.75 g/cm^3
a) What is the water pressure on the bottom of the tank? (pressure in psi)
Show calculations
b) What is the average force on the bottom?
Answer: [tex]0.1066\ psi, 15.611\ kN[/tex]
Explanation:
Given
the height of the tank is [tex]h=10\ cm[/tex]
The diameter of the tank is [tex]d=520\ cm[/tex]
Density of solution [tex]\rho=0.75\ g/cm^3\ or\ 750\ kg/m^3[/tex]
[tex](a)[/tex] Water pressure at the bottom of the tank is
[tex]P=\rho gh\\P=750\times 9.8\times 0.1\\P=735\ Pa[/tex]
[tex]1\ Pa=0.000145038\ psi[/tex]
[tex]\Rightarrow P=735\ Pa\ or\ 0.1066\ psi[/tex]
[tex](b) \text{Average force on the bottom is the product of pressure and area of the base}[/tex]
[tex]F_{avg}=735\times \pi \cdot (\frac{520}{200})^2\\\\F_{avg}=735\times 3.142\times 6.76\\F_{avg}=15,611.34\ N\ or\ 15.611\ kN[/tex]
Cual es la Ecuación de velocidad de una onda en función del índice de la amplitud de una cuerda
Answer:
Well velocity is the varaible with direction
Explanation:
Suppose you observe a star orbiting the galactic center at a speed of 1400 km/s in a circular orbit with a radius of 26 light-days. Calculate the mass of the object that the star is orbiting. Express your answer in solar masses to two significant figures.
Answer:
M = 9.9 x 10⁶ Solar masses
Explanation:
Here the centripetal force is given by the gravitational force between star and the object:
[tex]Gravitational\ Force = Centripetal\ Force \\\frac{mv^2}{r} = \frac{GmM}{r^2}\\\\M = \frac{v^2r}{G}[/tex]
where,
M = Mass of Object = ?
v = orbital speed of star = 1400 km/s = 1400000 m/s
G = Universal Gravittaional Constant = 6.67 x 10⁻¹¹ N.m²/kg²
r = distance between star and object = (26 light-days)(2.59 x 10¹³ m/1 light-day) = 6.735 x 10¹⁴ m
Therefore,
[tex]M = \frac{(1400000\ m/s)^2(6.735\ x\ 10^{14}\ m)}{6.67\ x \ 10^{-11}\ N.m^2/kg^2}[/tex]
M = (1.97 x 10³⁷ kg)(1 solar mass/ 1.989 x 10³⁰ kg)
M = 9.9 x 10⁶ Solar masses
A woman of mass 55 kg stands on the rim of a frictionless merry-go-round of radius 2.0m and rotational inertia 1250 kg-m2 that is not moving. She throws a rock of mass 350g horizontally in a direction that is tangent to the outer edge of the merry-go-round. The speed of the rock, relative to the ground, is 2.0m/s. Afterward, what are (a) the angular speed of the merry-go-round and (b) the linear speed of the woman
Answer:
a) [tex]\omega=9.10*10^{-4}rad/sec[/tex]
b) [tex]V=1.8217*10^{-3}[/tex]
Explanation:
From the question we are told that:
Mass of woman [tex]M_w=55kg[/tex]
Radius of merry go round [tex]r=2.0m[/tex]
Rotational inertia [tex]i= 1250 kg-m2[/tex]
Mass of rock [tex]M_r=350g \approx 0.350kg[/tex]
Speed of rock [tex]V_r=2.0m/s[/tex]
Tangent angle to the outer edge [tex]\theta=1[/tex]
a)
Generally the equation for conservation of momentum is mathematically given by
[tex]M_r(ucos\theta)r=(I+M_wr^2)\omega[/tex]
[tex]0.350(2.0cos1)(2.0)=(1250+(55)(2.0)^2)\omega[/tex]
[tex]1.3998=1470\omega\\\omega=\frac{1.339}{1470}[/tex]
[tex]\omega=9.10*10^{-4}rad/sec[/tex]
b)
Generally the equation for linear speed V is mathematically given by
[tex]V=r\omega\\V=2.0*9.10*10^{-4}[/tex]
[tex]V=1.8217*10^{-3}[/tex]
What is the resulting acceleration when a net force of 18 N is applied to a 3.0 kg mass?
O A. 6.0 m/s2
C. 54 m/s2
O B. 15 m/s2
O D. 9.8 m/s2
Answer:
F =ma
a=f/m =18/3= 6m/m²
Explanation:
the resulting acceleration will 6 m/s² because the question asking us to solve for the acceleration.
A mass on a string is swung in a circle of radius 0.75m at 7.0m/s.what its rate of acceleration.
Explanation:
ac = v^2/r
= (7.0 m/s)^2/(0.75 m)
= 65 m/s^2
PLS THIS IS DUE IN 2 MINUTES
Which has more momentum, a 0.5kg toy car moving a 5 m/s or a 1000kg real car that is
parked?
Answer:
The toy car
Explanation:
the real car is parked so yeah but maybe in some way technically the real car has more "momentum"
Does anybody know how to answer any of these questions? Any of them without a check mark.
Explanation:
sorry I can't help u right now