Spemann organizer is a dorsal structure . Planar cell polarity involves interaction with ECM. Hedgehog and Wingless are both secreted factors that establish the anterior/posterior identity of parasegments in Drosophila.

Answers

Answer 1

The Spemann organizer is a dorsal structure involved in embryonic development. Planar cell polarity is a cellular process that includes interactions with the extracellular matrix (ECM). Hedgehog and Wingless are secreted factors that play roles in establishing the anterior/posterior identity of parasegments in Drosophila.

The Spemann organizer is a region in the developing embryo that plays a critical role in dorsal-ventral patterning. It was first identified by the German embryologist Hans Spemann and his student Hilde Mangold during their experiments with salamander embryos. The Spemann organizer is responsible for inducing the formation of the dorsal mesoderm and axial structures during embryonic development. It secretes various signaling molecules, such as Chordin and Noggin, which inhibit the activity of BMP (Bone Morphogenetic Protein) signaling and promote the development of dorsal structures.

Planar cell polarity refers to the coordinated orientation of cells within a tissue plane. It involves the alignment and polarization of cells along a specific axis, which is essential for the proper organization and function of tissues. Planar cell polarity is regulated by a complex network of signaling pathways and interactions with the extracellular matrix. The ECM provides cues and signals that guide the polarization of cells, influencing their orientation and behavior.

Hedgehog and Wingless are two secreted factors involved in establishing the anterior/posterior identity of parasegments in Drosophila, a commonly studied model organism in developmental biology. Hedgehog signaling pathway plays a key role in patterning the anterior/posterior axis by establishing concentration gradients of Hedgehog protein, which then activates target genes in a concentration-dependent manner. Wingless, also known as Wnt, is another signaling pathway that helps establish the anterior/posterior identity by regulating gene expression in specific regions of the embryo.

In summary, the Spemann organizer is a dorsal structure involved in embryonic development, planar cell polarity involves interactions with the extracellular matrix, and Hedgehog and Wingless are secreted factors that play important roles in establishing the anterior/posterior identity of parasegments in Drosophila.

To know more about Spemann organizer refer here:

https://brainly.com/question/31104587?#

#SPJ11


Related Questions

rDNA O when 2 different DNA from two different species are joined together
O example human insulin gene placed in a bacterial cell O DNA is copied along with bacterial DNA O Proteins are then made known as recombinant proteins. O All of the above •

Answers

All of the statements mentioned about DNA and recombinant DNA are correct.

The correct answer is: All of the above.

What occurs in the DNA combination?

When two different DNA from two different species are joined together, several processes occur:

The human insulin gene, for example, can be placed in a bacterial cell. This is achieved through genetic engineering techniques such as gene cloning or recombinant DNA technology.

The DNA containing the human insulin gene is copied along with the bacterial DNA through DNA replication. This ensures that the foreign DNA is replicated along with the host DNA during cell division.

Once the recombinant DNA is present in the bacterial cell, the cell's machinery translates the genetic information into proteins. In the case of the human insulin gene, the bacterial cell will produce insulin proteins using the instructions provided by the inserted gene. These proteins are known as recombinant proteins.

Learn more about DNA at: https://brainly.com/question/2131506

#SPJ4

Explain how meiosis and sexual reproduction generate
biodiversity. Discuss the advantage(s) and disadvantage(s) of
sexual reproduction in the light of evolution.

Answers

Meiosis and sexual reproduction help to generate diversity in organisms. Sexual reproduction occurs when two individuals from different sexes come together and produce offspring that inherit traits from both parents. Here are the advantages and disadvantages of sexual reproduction in the light of evolution:Advantages of sexual reproduction: Sexual reproduction allows for variation among offspring which is useful in unpredictable environments.

It is possible for a genetic mutation to be beneficial, and sexual reproduction is a means of allowing such mutations to be propagated. Sexual reproduction also allows for the exchange of genetic material between organisms, which can increase genetic diversity and help adaptability.Disadvantages of sexual reproduction: Sexual reproduction can be time-consuming and resource-intensive. It requires the finding of a mate and the production of gametes which can be expensive.

There is also a risk of producing offspring that are not viable, which can be costly to the organism. Another disadvantage is that sexual reproduction results in the breaking up of successful genetic combinations, which can be disadvantageous in some situations. In conclusion, while there are both advantages and disadvantages to sexual reproduction, the ability to generate genetic diversity is crucial to the long-term survival of species.

To know more about sexual reproduction visit:-

https://brainly.com/question/29541212

#SPJ11

In hepatocytes (liver celliss), the process by which apically destined proteins travel from the basolateral region across the cytoplasm of the cell before fusing with the apical membrane is called: a. transcellular b. endocytosis c. paracellular d. exocytosis

Answers

In hepatocytes (liver cells), the process by which apically destined proteins travel from the basolateral region across the cytoplasm of the cell before fusing with the apical membrane is called transcellular transport.

The hepatic cells or hepatocytes are highly specialized and responsible for the synthesis, secretion, and modification of the proteins, which play vital roles in the physiological functions. Hepatocytes are also responsible for the detoxification of xenobiotics and the storage of various essential nutrients, hormones, and vitamins.

The transport process involves several steps that include receptor-mediated endocytosis, vesicle fusion, and exocytosis of apical vesicles. Transcellular transport is an essential physiological process and is regulated by several factors, including intracellular signaling pathways, cytoskeletal elements, and molecular motors. In conclusion, hepatocytes use transcellular transport to move proteins from the basolateral region to the apical membrane.

To know more about transcellular visit:  

https://brainly.com/question/14017386

#SPJ11

Elongation continues in translation until a STOP codon is reached on the mRNA. a) True b) False

Answers

a) True.

During translation, elongation refers to the process of adding amino acids to the growing polypeptide chain. It continues until a STOP codon is encountered on the .

The presence of a STOP codon signals the termination of protein synthesis and the release of the completed polypeptide chain from the ribosome.

Learn more about polypeptide   here:  

https://brainly.com/question/28495042

#SPJ11

Variable number tandem repeat (VNTR) is a ______
a. Gene b. polymorphism c. translocation d. both a and b

Answers

Variable number tandem repeat (VNTR) is both a gene and a polymorphism. Therefore, the correct answer is d. both a and b, as VNTRs are both a gene and a polymorphism.

VNTR refers to a type of DNA sequence variation characterized by the presence of short DNA segments that are repeated in tandem (i.e., consecutive repetitions of the same sequence). These repetitive sequences can vary in the number of repeats between individuals, giving rise to the term "variable number tandem repeat."

In terms of being a gene, VNTRs can be present within or near genes and can influence gene expression or function. They can be associated with specific traits, diseases, or genetic disorders.

Moreover, VNTRs are also considered a type of polymorphism. Polymorphisms refer to variations in DNA sequences that are present in a population. VNTRs represent one form of genetic polymorphism due to their variable nature. The number of repeats in a VNTR region can differ between individuals, making it a useful tool for genetic analysis, including forensic DNA profiling and paternity testing.

Learn more about genetic polymorphism here:

https://brainly.com/question/32883923

#SPJ11

QUESTION 25 Which of following does NOT secrete a lipase? a. the salivary glands
b. the stomach c.the small intestine d. the pancreas
QUESTION 26 Which of the following is the correct sequence of regions of the small intestine, from beginning to end? a. Ileum-duodenum -jejunum b. Duodenum-ileum -jejunum c. Ileum-jejunum - duodenum
d. Duodenum-jejunum - ileum QUESTION 27 Accessory organs of the digestive system include all the following except. a. salivary glands b. teeth.
c. liver and gall bladder d.adrenal gland QUESTION 28 The alimentary canal is also called the. a. intestines b.bowel c. gastrointestinal (Gl) tract
d. esophagus
QUESTION 29 The tube that connects the oral cavity to the stomach is called the a. small intestine b. trachea c.esophagus d.oral canal

Answers

In this set of questions, to identify the option that does NOT secrete a lipase, the correct sequence of regions in the small intestine, the organs that are considered accessory organs of the digestive system.

In question 25, the correct answer is option a. the salivary glands. Salivary glands secrete amylase to initiate the digestion of carbohydrates but do not secrete lipase.

In question 26, the correct answer is option b. Duodenum-ileum-jejunum. The correct sequence of regions in the small intestine, from beginning to end, is duodenum, jejunum, and ileum.

In question 27, the correct answer is option d. adrenal gland. Accessory organs of the digestive system include the salivary glands, teeth, liver, and gallbladder. The adrenal gland is not directly involved in the digestive process.

In question 28, the correct answer is option c. gastrointestinal (GI) tract. The alimentary canal, or the digestive tract, is also referred to as the gastrointestinal tract.

In question 29, the correct answer is option c. esophagus. The tube that connects the oral cavity to the stomach is called the esophagus, which serves the purpose of transporting food from the mouth to the stomach.

Overall, these questions cover various aspects of the digestive system, including secretions, anatomical sequences, and organs classification. Understanding these concepts is essential for comprehending the process of digestion and the functions of different components of the digestive system.

Learn more about digestion here

https://brainly.com/question/32136745

#SPJ11

1.
Statement 1: Dendritic cells are phagocytes with professional antigen-presenting properties.
Statement 2: Neutrophils circulate as part of the blood and act as surveillance to detect presence of pathogens.
A) Statement 1 is true. Statement 2 is false.
B) Statement 2 is true. Statement 1 is false.
C) Both statements are true.
D) Both statements are false.
2. Histamine is a signaling molecule that plays a significant role in regulating immune responses such as during allergic reactions and inflammation. It causes blood vessels to dilate and become more permeable so that white blood cells can immediately reach the site of injury, damage, or infection. What types of white blood cells can release histamine?
A) basophils and mast cells
B) B cells and T cells
C) dendritic cells
D) neutrophils
3. What molecules are released by activated helper T cells?
A) immunoglobulins
B) antigen
C) cytokines
D) histamine

Answers

1. The correct answer is A) Statement 1 is true. Statement 2 is false. Dendritic cells are indeed phagocytes with professional antigen-presenting properties,

Whereas neutrophils are primarily known for their role in phagocytosis and are not considered professional antigen-presenting cells.

2. The correct answer is A) basophils and mast cells. Basophils and mast cells are types of white blood cells that can release histamine. Histamine release by these cells is associated with allergic reactions and inflammation.

3. The correct answer is C) cytokines. Activated helper T cells release cytokines, which are signaling molecules that play a critical role in coordinating and regulating immune responses.

Immunoglobulins are antibodies produced by B cells, while antigen is the target of an immune response. Histamine is released by basophils and mast cells, as mentioned in the previous question.

For more such questions on Dendritic cells

https://brainly.com/question/31787830

#SPJ8

Both the extrinsic and intrinsic activation pathways of procoagulation converge to activate _________________ which subsequently converts fibrinogen into fibrin, among its many functions.
O Von Willebrand Factor
O Factor XIII
O Protein C
O Thrombin
O Factor V

Answers

Both the extrinsic and intrinsic activation pathways of procoagulation converge to activate thrombin which subsequently converts fibrinogen into fibrin, among its many functions. So, the correct option is Thrombin.

What is thrombin?

Thrombin is a protease enzyme that can cleave and activate numerous clotting factors, as well as fibrinogen and factor XIII, among other proteins. It is critical in the coagulation process, which is the body's natural way of stopping bleeding.

The formation of thrombin occurs through the activation of either the intrinsic or extrinsic coagulation pathway. Prothrombin is transformed into thrombin through a complex series of intermediate reactions that necessitate the involvement of other coagulation factors.

Thus, the correct option is Thrombin.

To know more about coagulation pathway, refer to the link below:

https://brainly.com/question/30983063#

#SPJ11

In some insect species the males are haploid. What process (meiosis or mitosis) is used to produce gametes in these males?
Wiskott-Aldrich Syndrome (WAS) is an X-linked disorder characterized by low platelet counts, eczema, and recurrent infections that usually kill the child by mid childhood. A woman with one copy of the mutant gene has normal phenotype but a woman with two copies will have WAS. Select all that apply: WAS shows the following
Pleiotropy
Overdominance
Incomplete dominance
Dominance/Recessiveness
Epistasis

Answers

In some insect species, the males are haploid, and mitosis is used to produce gametes in these males. Wiskott-Aldrich Syndrome (WAS) shows Dominance/Recessiveness.

In some insect species, the males are haploid. Mitosis is used to produce gametes in these males. This is because mitosis is the type of cell division that occurs in somatic cells. It results in the production of two identical daughter cells with the same chromosome number as the parent cell. Meiosis, on the other hand, is the type of cell division that occurs in germ cells. It results in the production of four genetically diverse daughter cells with half the chromosome number of the parent cell.Therefore, mitosis is used to produce gametes in male haploid insect species.

.Wiskott-Aldrich Syndrome (WAS) shows the Dominance/Recessiveness. Dominant alleles are those that determine a phenotype in a heterozygous (Aa) or homozygous (AA) state. Recessive alleles determine a phenotype only when homozygous (aa). In the case of WAS, a woman with one copy of the mutant gene has a normal phenotype because the normal gene can mask the effect of the mutant gene. However, a woman with two copies of the mutant gene will have WAS because the mutant gene is now in a homozygous state. Therefore, the mutant allele is recessive to the normal allele.

In some insect species, the males are haploid, and mitosis is used to produce gametes in these males. Wiskott-Aldrich Syndrome (WAS) shows Dominance/Recessiveness.

To know more about Wiskott-Aldrich  syndrome visit:

brainly.com/question/30765213

#SPJ11

If excess metabolic fuel is taken in over time, metabolic fuel is stored for the long term. In what form(s) is metabolic fuel stored for the long term? What tissue(s) is it stored in? And how is this storage impacted by the form(s) in which the excess metabolic fuel is taken in as?

Answers

When excess metabolic fuel is taken in over time, metabolic fuel is stored for the long term in adipose tissue. Adipose tissue is the primary site of storage for metabolic fuel in the body. The fuel is stored in the form of triglycerides (i.e., three fatty acids attached to a glycerol molecule).

Excess metabolic fuel is taken in when energy intake exceeds energy expenditure. This excess fuel is converted to fat and stored in adipose tissue for the long term. Adipose tissue is present throughout the body and serves as an energy reserve for times of low energy availability.

The form(s) in which the excess metabolic fuel is taken in can impact this storage in various ways. For example, if the excess fuel is taken in the form of carbohydrates, the body will first store this excess glucose in the liver and muscles in the form of glycogen.

However, once these storage sites are full, the excess glucose is converted to fat and stored in adipose tissue. If the excess fuel is taken in the form of dietary fat, the body can readily store this fat directly in adipose tissue without first converting it to another form.

However, it's worth noting that the types of dietary fat consumed can impact the storage and metabolism of this fuel. For example, saturated and trans fats tend to be more readily stored as fat in adipose tissue than unsaturated fats.

To know more about adipose tissue visit:

https://brainly.com/question/30764836

#SPJ11

Transmembrane movement of a substance down a concentration gradient with no involvement of membrane protein a.belongs to passive transport
b. is called facilitated diffusion c.belongs to active transport d.is called simple diffusion

Answers

Transmembrane movement of a substance down a concentration gradient with no involvement of membrane protein is called simple diffusion. Simple diffusion is a type of passive transport that occurs without the involvement of membrane proteins.

Passive transport, also known as passive diffusion, does not require energy input from the cell, and substances move down their concentration gradient. It includes simple diffusion and facilitated diffusion.In simple diffusion, molecules move directly through the lipid bilayer of the plasma membrane from high concentration to low concentration. Small molecules such as oxygen, carbon dioxide, and water can move across the membrane through simple diffusion. Facilitated diffusion, on the other hand, requires the involvement of membrane proteins to transport molecules across the membrane.

The membrane protein creates a channel or a carrier for the solute to cross the membrane, but the movement still goes down the concentration gradient.The movement of molecules in active transport is opposite to that of passive transport, moving from an area of low concentration to an area of high concentration. Active transport requires the use of energy, usually in the form of ATP, to pump molecules across the membrane against the concentration gradient. Therefore, we can conclude that the correct option is d. is called simple diffusion.

To kknow more abou diffusion visit:
https://brainly.com/question/14852229
#SPJ11

1 pts Arrange the following correct sequence of events during exhalation: 1. Air (gases) flows out of lungs down its pressure gradient until intrapulmonary pressure is 0 (equal to atmospheric pressure

Answers

Air flows out of the lungs during bin the following correct sequence of events:

1. Contraction of the diaphragm and external intercostal muscles reduces intrapleural pressure.

2. Decreased intrapleural pressure causes the lungs to recoil, compressing the air within the alveoli.

3. The compressed air flows out of the lungs down its pressure gradient until intrapulmonary pressure is 0, equal to atmospheric pressure.

During exhalation, the primary muscles involved are the diaphragm and the external intercostal muscles. These muscles contract, causing the volume of the thoracic cavity to decrease. As a result, the intrapleural pressure within the pleural cavity decreases. The decreased intrapleural pressure leads to the recoil of the elastic lung tissue, which compresses the air within the alveoli.

As the volume of the thoracic cavity decreases, the pressure within the alveoli increases. This increased pressure creates a pressure gradient between the lungs and the atmosphere. The air naturally flows from an area of higher pressure (within the lungs) to an area of lower pressure (outside the body) until the pressures equalize. This process continues until the intrapulmonary pressure reaches 0, which is equal to atmospheric pressure.

Overall, the sequence of events during exhalation involves the contraction of the diaphragm and external intercostal muscles, the recoil of the lungs, and the resulting flow of air out of the lungs down its pressure gradient until the intrapulmonary pressure matches the atmospheric pressure.

Learn more about Diaphragm

brainly.com/question/33442514

#SPJ11

QUESTION 15 Which of these factors is most likely to reduce a population of organisms regardless of the population density? a. Predation
b. Outbreak of a disease c. Parasitic infections d. Severe drought

Answers

A severe drought is the most likely factor to reduce a population of organisms, regardless of the population density.

The factor that is most likely to reduce a population of organisms regardless of the population density is a severe drought. The other factors such as predation, outbreak of a disease, and parasitic infections can cause a reduction in population density, but their effects are more pronounced when the population is high than when it is low.

In the event of a severe drought, the quantity of water available for plants and animals to consume decreases, leading to a significant reduction in the number of available resources.

When this occurs, the population density of organisms may decrease substantially or even go extinct since the organisms require water to survive. Therefore, a severe drought is the most likely factor to reduce a population of organisms, regardless of the population density.

Factors are the determinants that contribute to the growth or decline of a population. Populations can either decrease or increase in size, and there are various factors that influence this.

Factors that may contribute to an increase in the population of organisms include a decrease in predator numbers, favorable weather conditions, and an abundance of resources, while factors that may lead to a decrease in population density include predation, disease outbreaks, parasitic infections, and natural disasters.

In the event of an outbreak of a disease, the population density is reduced since the disease affects a large number of organisms. In the case of parasitic infections, organisms are infected by other organisms that feed on them and, as a result, reduce the population density.

Predation also reduces the population of organisms, but it is more effective when the population is high.

On the other hand, when the population is low, predation has little effect on the population density.

In summary, a severe drought is the most likely factor to reduce a population of organisms, regardless of the population density.

To know more about organisms visit;

brainly.com/question/13278945

#SPJ11

One way of identifying a drug target in a complex cellular extract is to use an affinity approach, i.e. fix the drug to a resin (agarose etc) and use it to "pull down "" the target from the extract. What potential problems do you think may be encountered with attempting this approach?

Answers

One way of identifying a drug target in a complex cellular extract is by using an affinity approach which involves fixing the drug to a resin such as agarose. The target is then "pulled down" from the extract.

However, this approach may encounter some potential problems such as:

Non-specific binding: The drug resin could bind to other molecules that are unrelated to the target protein, leading to inaccurate results.Difficulty in obtaining a pure sample: Even though the target molecule could bind to the drug resin, other proteins and molecules can also bind which makes it challenging to obtain a pure sample.Low Abundance Targets: In a complex cellular extract, the target molecule may exist in low abundance and the signal might not be strong enough to detect, making it difficult to pull down.Biochemical Incompatibility: The drug and the resin may not be compatible with the target, thus it may not bind or bind weakly which means the target protein might not be able to be pulled down.

Therefore, while the affinity approach is a very useful and important method for drug target identification, it also has its limitations and potential problems that need to be considered.

Learn more about Affinity approach:

brainly.com/question/14240799

#SPJ11

Which statement about Mitosis is correct?
At the end of mitosis there is four different daughther cells
At the end of mitosis there is four identical daughther cells
At the end of mitosis there is two different daughther cells
At the end of mitosis there is two identical daughther cells

Answers

The correct statement about mitosis is that (D) at the end of mitosis, there are two identical daughter cells. During mitosis, the replicated chromosomes align and separate, ensuring that each daughter cell receives a complete set of chromosomes.

Mitosis is a process of cell division in which a single cell divides into two identical daughter cells.

This process occurs in various stages, including prophase, metaphase, anaphase, and telophase. At the end of telophase, the cytoplasm divides through cytokinesis, resulting in the formation of two separate cells.

These daughter cells contain the same genetic information as the parent cell and are identical to each other. Mitosis plays a crucial role in growth, tissue repair, and asexual reproduction in organisms.

Therefore, (D) at the end of mitosis, there are two identical daughter cells is the correct answer.

To know more about the mitosis refer here,

https://brainly.com/question/31626745#

#SPJ11

Describe how mutations in oncogenes can induce genome instability, and contrast with genome instability induced by mutations in tumour suppressor genes.

Answers

Mutations in oncogenes and tumor suppressor genes can cause genomic instability, leading to the development of cancer. Mutations in oncogenes and tumor suppressor genes can lead to genome instability by affecting cellular pathways responsible for DNA damage repair, cell cycle control, and apoptosis.

Mutations in oncogenes and tumor suppressor genes can cause genomic instability, leading to the development of cancer. Mutations in oncogenes and tumor suppressor genes can lead to genome instability by affecting cellular pathways responsible for DNA damage repair, cell cycle control, and apoptosis. Mutations in oncogenes are genes that are capable of initiating the development of cancer in normal cells. Their mutations increase the activity of a protein encoded by the oncogene, leading to an uncontrolled cell growth and division, which can lead to cancer. However, when mutated, oncogenes can also activate DNA damage repair mechanisms that cause genomic instability, such as DNA replication and cell division that can lead to gene amplification and gene rearrangements.

On the other hand, tumor suppressor genes act to prevent the development of cancer by regulating cell proliferation, DNA repair, and apoptosis. Their mutations, on the other hand, lead to genomic instability, which can cause the loss of critical genes, uncontrolled cell growth, and the development of cancer. When tumor suppressor genes are mutated, they fail to control the cellular mechanisms responsible for DNA damage repair, cell cycle control, and apoptosis, which can cause genomic instability and the development of cancer.

Therefore, mutations in oncogenes can induce genomic instability by affecting cellular pathways that regulate DNA repair, cell cycle control, and apoptosis, while mutations in tumor suppressor genes can induce genomic instability by disrupting the same cellular pathways responsible for the regulation of DNA repair, cell cycle control, and apoptosis.

To know more about genome visit:

https://brainly.com/question/30336695

#SPJ11

Homologous DNA recombination:
A)Requires 5'-end generation at double-stranded DNA breaks
B)Occurs at the tetrad stage during meiosis
C)Is responsible for transposon movement in human cells
D)Repairs mutations caused by deamination events
E)Inverts DNA sequences as a mechanism to regulate genes

Answers

Homologous DNA recombination repairs mutations caused by deamination events. The correct option is (D).

Homologous recombination is the exchange of genetic information between two DNA molecules with high sequence similarity. This can occur during normal DNA replication in dividing cells, but the process is usually regulated to ensure that accurate copies are made and the genome remains stable.

During homologous recombination, a broken DNA molecule is repaired using a template DNA molecule that has the same or very similar sequence. The two DNA molecules are aligned, and sections are swapped between the two, resulting in a complete, unbroken DNA molecule.

A mutation is a change in DNA sequence that may occur naturally or be induced by external factors such as radiation, chemicals, or other environmental agents. Deamination is a type of mutation that can occur when a nitrogenous base is changed to a different base through the removal of an amine group. For example, cytosine can be deaminated to uracil, which is normally found only in RNA. If this change occurs in a DNA molecule, it can lead to problems with replication and transcription, which may result in genetic disorders or diseases.

Homologous recombination can be used to repair mutations caused by deamination events by providing a template DNA molecule with the correct sequence. When a broken DNA molecule is repaired using homologous recombination, the template DNA molecule is used to fill in the missing or damaged sections of the broken DNA molecule. This ensures that the correct sequence is restored, and any mutations caused by deamination or other factors are repaired.

Thus, the correct option is D.

Learn more about Homologous DNA: https://brainly.com/question/29792912

#SPJ11

Discuss the role of the autonomic nervous system in controlling the body’s
functions.Your response should discuss both the sympathetic and the
parasympathetic divisions. Your response sho

Answers

The autonomic nervous system (ANS) plays a crucial role in controlling the body's functions and maintaining homeostasis. It consists of two main divisions: the sympathetic and the parasympathetic nervous systems.

The sympathetic division of the ANS is responsible for the body's "fight-or-flight" response during stressful or emergency situations. When activated, it prepares the body for intense physical activity or response to a threat. The sympathetic division increases heart rate, dilates the airways, stimulates the release of stress hormones like adrenaline, and redirects blood flow to vital organs and skeletal muscles. This division helps mobilize energy resources, enhances alertness, and heightens overall physical performance.

On the other hand, the parasympathetic division is responsible for the body's "rest-and-digest" response. It promotes relaxation, conserves energy, and supports normal bodily functions during non-stressful situations. The parasympathetic division decreases heart rate, constricts the airways, stimulates digestion, and promotes nutrient absorption. It also helps maintain normal blood pressure, supports sexual arousal, and aids in the elimination of waste materials.

To know more about autonomic nervous system (ANS)

brainly.com/question/32266694

#SPJ11

The two strands of a DNA molecule are held together by what type of bonds?
a. carbon
b. hydrogen
c. nitrogen
d. none of the above

Answers

The correct answer is b. hydrogen bonds. The DNA molecule consists of two strands that are twisted around each other in a double helix structure.

The hydrogen bonds are formed between the nitrogenous bases of the nucleotides. The nitrogenous bases in DNA include adenine (A), thymine (T), cytosine (C), and guanine (G). Adenine forms three hydrogen bonds with thymine, and cytosine forms two hydrogen bonds with guanine.

Specifically, adenine and thymine are connected by two hydrogen bonds, while cytosine and guanine are connected by three hydrogen bonds. It is important to note that the backbone of the DNA molecule is formed by sugar-phosphate bonds, which run along the outside of the double helix structure and provide structural support.

Learn more about double helix here: https://brainly.com/question/30666817

#SPJ11

The only cell type in the alveoli able to freely move around is the:
Select one:
a. pseudostratified type I epithelial cells.
b. alveolar macrophages.
c. type II simple cuboidal cells.
d. type II surfactant secreting alveolar cells.
e. simple squamous epithelial cells.

Answers

The cell type in the alveoli that is able to freely move around is the alveolar macrophages.

Alveolar macrophages, also known as dust cells, are the immune cells found within the alveoli of the lungs. They are responsible for engulfing and removing foreign particles, such as dust, bacteria, and other debris that may enter the respiratory system. These cells have the ability to move freely within the alveolar spaces.

Other cell types mentioned in the options have specific functions within the alveoli but do not possess the same mobility as alveolar macrophages. Pseudostratified type I epithelial cells and simple squamous epithelial cells are specialized cells that form the lining of the alveoli and are involved in gas exchange.

Type II simple cuboidal cells, also known as type II pneumocytes, are responsible for producing and secreting surfactant, a substance that reduces surface tension in the alveoli. Type II surfactant-secreting alveolar cells are also involved in surfactant production. While these cell types play important roles in maintaining the structure and function of the alveoli, they are not known for their ability to freely move within the alveolar spaces like alveolar macrophages do.

Learn more about immune cells here:

https://brainly.com/question/31736435

#SPJ11

STATION 3 - SALTATORIAL VERTEBRATES (kangaroos, kangaroo rats,
gerbils, jerboas, tarsiers, frogs)
3e. How has the trunk of frogs become shorter (1 mark)? What is
the adaptive advantage?
3b. What is th

Answers

STATION 3 - SALTATORIAL VERTEBRATES (kangaroos, kangaroo rats, gerbils, jerboas, tarsiers, frogs)3e. The trunk of frogs has become shorter in order to achieve a more advanced way of jumping.

The shorter trunk increases the efficiency of the jump, as it makes the body more compact, and lessens the weight of the hind legs as the frog moves in the air. The shorter trunk of the frog also provides an advantage by enabling it to move easily and smoothly through the water, as the decreased drag allows it to swim faster.

Saltatorial is a type of locomotion that involves hopping or jumping, and it is one of the most energy-efficient ways of getting around for the animals that use it. The kangaroo rat is one of the most notable examples of a saltatorial vertebrate, and it has evolved a number of adaptations to suit its jumping lifestyle.

To know more about locomotion visit:

https://brainly.com/question/13343069

#SPJ11

For many medical conditions, adult stem cells are not suitable for treatment so researchers aim to use embryonic stem cells. Compare and contrast the advantages and disadvantages of both adult and embryonic stem cells in cell- based regenerative therapies. Your answer should demonstrate a detailed knowledge of both embryonic and adult stem cell sources, their isolation and characterisation. Your answer should also address the potential ethical and political issues related to stem cell research. (10 marks)

Answers

Embroynic and adult stem cells both have advantages and disadvantages in the cell-based regenerative therapies.

Below are some of the comparisons and contrasts:

Embryonic stem cells :Embryonic stem cells are derived from the inner cell mass of blastocysts that have been fertilized by in vitro fertilization (IVF) procedures or cloned by somatic cell nuclear transfer (SCNT).

Advantages: Embryonic stem cells have a high potential to differentiate into any type of cells in the human body and they can divide indefinitely, therefore, can be used to develop any type of cell to regenerate tissues for therapeutic use.

Disadvantages: One of the major disadvantages of embryonic stem cells is their potential to form tumors when transplanted in the human body. They require the administration of immunosuppressive drugs to reduce the risk of rejection. Adult stem cells are present in various organs, tissues, and blood of the human body. They can be isolated from bone marrow, blood, adipose tissue, and other organs.

Advantages: Adult stem cells are present in an already developed organ so they do not require the destruction of an embryo, hence there are no ethical issues involved in their usage. They can be obtained from the patient's own body, therefore, there are no issues of immune rejection. They also have a low risk of tumor formation when used for therapeutic purposes.

Disadvantages: Adult stem cells have limited differentiation potential. they can differentiate only into a limited number of cell types. Also, the number of adult stem cells in the human body decreases with age, which can limit their potential to be used in regenerative therapies.  The ethical and political issues relating to stem cell research are complex and require a careful consideration of the interests of patients, scientists, and society as a whole.

To know more about adult stem visit:

https://brainly.com/question/31145166

#SPJ11

what is virus host interaction ? i dont find clear info. i have assingment ant i dont know what i write please helppppp

Answers

Virus-host interaction refers to the relationship and interactions between a virus and its host organism. It involves the complex interplay between the virus and the host's cells, tissues, and immune system.

During virus-host interaction, viruses infect host cells and hijack their cellular machinery to replicate and produce new virus particles. The virus enters the host's cells, releases its genetic material (DNA or RNA), and takes control of the cellular processes to produce viral proteins and replicate its genetic material.

This can lead to various consequences for the host, ranging from mild symptoms to severe diseases.

The host organism's immune system plays a crucial role in the virus-host interaction. It detects the presence of viruses and mounts an immune response to eliminate the infection.

The interaction between the virus and the host's immune system can result in a dynamic battle, with the virus trying to evade the immune response and the immune system attempting to control and eliminate the virus.

The outcome of virus-host interaction can vary depending on factors such as the virulence of the virus, the host's immune response, and the specific mechanisms employed by the virus to evade or manipulate the host's defenses.

Understanding virus-host interactions is essential for developing strategies to prevent and control viral infections.

To know more about Virus-host interaction, refer here:

https://brainly.com/question/10485082#

#SPJ11

Give ans for each statement
1.A protein linked to a disease state is being studied by scientists. They discover that the disease protein has the same amino acid sequence as the protein in healthy people. State right or wrong: Does the following explanation provide a plausible biological explanation for the disease state?
a.The RNA polymerase does not correctly read the codon code on the mRNA.
b.The protein is not being regulated properly.
c.The disease protein is incorrectly folded.
d. The disease protein lacks a post-translational modification.
e.The protein amounts differ because they are expressed differently.

Answers

The RNA polymerase does not correctly read the codon code on the mRNA, protein is not being regulated properly, the disease protein is incorrectly folded, the disease protein lacks a post-translational modification, and the protein amounts differ because they are expressed differently; are all plausible biological explanations for the disease state.

An explanation is given below to all options:a) The RNA polymerase does not correctly read the codon code on the mRNA:This may cause a different protein or premature termination of translation if it occurs, and so it may have a disease-causing effect.b) The protein is not being regulated properly:If the protein is underexpressed or overexpressed, it may have a disease-causing effect.c) The disease protein is incorrectly folded:As a result, it may be inactive or toxic, causing harm to the organism.

d) The disease protein lacks a post-translational modification:This may impair protein function or cause the protein to become toxic in some way, causing harm to the organism.e) The protein amounts differ because they are expressed differently:Different cells or tissues may express different quantities of the protein, resulting in different effects. Therefore, all the five options are right for plausible biological explanations for the disease state.

To know more about RNA visit:-

https://brainly.com/question/25979866

#SPJ11

Microtubules are «dynamically unstable».
What is dynamic instability, and what does this mean for the function of the microtubules?
Explain the mechanism behind this process.

Answers

Microtubules are the largest elements of the cytoskeleton, which are composed of protein polymers that are intrinsically polar and assembled by the regulated polymerization of α- and β-tubulin heterodimers.

Microtubules are highly dynamic, which means that they are continuously being generated and broken down. This process is referred to as dynamic instability.

Dynamic instability is a mechanism that explains the dynamic behaviour of microtubules. The term dynamic instability is a description of the way in which microtubules change shape over time.

It means that microtubules are constantly shifting and changing shape, breaking down and reforming in a process that is dependent on the activity of the microtubule network.

Microtubules are able to undergo dynamic instability because of their unique composition. Each microtubule is made up of multiple tubulin subunits that are arranged in a spiral pattern.

This arrangement creates a structure that is both strong and flexible, allowing the microtubules to bend and twist in response to changes in the cell environment.

To know more about polymerization visit:

https://brainly.com/question/27354910

#SPJ11

Chi square test. A cross is made to study the following in the Drosophila fly: black body color (b) and vermilion eye color (v). A heterozygous red-eyed, black-bodied female was crossed with a red-eyed, heterozygous male for cream body color. From the crossing the following progeny was obtained in the filial generation 1 (F1):
F1 Generation:
130 females red eyes and cream colored body
125 females red eyes and black body
70 males red eyes and cream body
55 males red eyes and black body
60 males vermilion eyes and cream body
65 males vermilion eyes and black body
The statistical test hypothesis would be that there is no difference between the observed and expected phenotypic frequencies.
a) Using the information provided, how is eye color characteristic inherited? why?
b) How is the characteristic of skin color inherited?

Answers

a. Eye color is inherited as sex-linked inheritance, with vermilion eye color being a sex-linked trait.

b. Skin color is inherited through autosomal inheritance, with black and cream body coloration being determined by alleles on autosomal chromosomes.

a. Eye color characteristic in the Drosophila flies is inherited as sex-linked inheritance. In this case, vermilion eye color is a sex-linked trait, with the genes that determine eye color located on the X chromosome. Males only have one X chromosome, so if they receive the X-linked allele for vermilion eye color from their mother, they will express that trait.

This is because they lack a second X chromosome to mask the expression of the allele. On the other hand, females have two X chromosomes and can inherit two alleles, one from each parent. If a female receives even one copy of the vermilion allele, she will express that trait.

b. The characteristic of skin color, specifically body color, in the Drosophila flies is inherited through autosomal inheritance. In this case, black body color is a recessive trait, while cream body color is dominant. Both black and cream body coloration requires the presence of the respective allele on the two homologous autosomal chromosomes.

In the given cross, both the male and female flies are heterozygous for the genes that determine skin color. This indicates that the trait for body color is inherited through autosomal inheritance, where the presence of the dominant allele (cream body color) masks the expression of the recessive allele (black body color).

Know more about the skin color click here:

https://brainly.com/question/14466617

#SPJ11

Question 13 0.05 pts Which of the following mechanisms produces the MOST diversity in T cell receptors? imprecise joining of VDJ segments O having multiple V region segments from which to choose somatic hypermutation having multiple C region gene segments from which to choose Question 17 0.05 pts Which statement BEST DESCRIBES the function of the C3 component of complement? It forms part of a convertase on the bacteria and is recognized by neutrophils through the receptor CR1. It binds to antibody Fc that are bound to the surface of the bacteria. It initiates the end-stage of complement to form part of the Membrane Attack Complex (MAC). O It initiates the extrinsic pathway of coagulation

Answers

13. Imprecise joining of VDJ segments. The answer 1 is correct.

20. IgE and mast cells. The option 4 is correct.

17. It initiates the end-stage of complement to form part of the Membrane Attack Complex (MAC). The option 3 is correct.

Question 13: The mechanism that produces the MOST diversity in T cell receptors is the "imprecise joining of VDJ segments." This process involves the rearrangement of variable (V), diversity (D), and joining (J) gene segments during T cell development.

Question 20: An inflammatory response that occurs immediately upon exposure to antigen is MOST LIKELY to be mediated by "IgE and mast cells." IgE antibodies are specialized immunoglobulins that are involved in allergic and immediate hypersensitivity reactions.

Upon exposure to an antigen, IgE antibodies bind to mast cells, which are present in tissues throughout the body.

Question 17: The function of the C3 component of complement is BEST DESCRIBED by the statement "It initiates the end-stage of complement to form part of the Membrane Attack Complex (MAC)." The complement system is a part of the innate immune response and plays a crucial role in host defense against pathogens.

C3 is a central component of the complement cascade. Activation of C3 leads to the formation of C3 convertase, which cleaves C3 into C3a and C3b.

Know more about the immune response:

https://brainly.com/question/17438406

#SPJ4

Quantitative Inheritance (6 pts) Estimate the number of segregating genes using the below data and the Sewall Wright formula 6 pts) P1 P2 F1 F2 X=31g X=43g X=37g X=37g s=1.0 s=1.0 s=1.0 s=2.45 SP=1.0

Answers

The Sewall Wright Formula used to estimate the number of segregating genes is given by:2pq = sWhere p and q are the frequencies of the two alleles at the locus under consideration, and s is the selection differential, which is the difference between the mean phenotype of the selected parents and that of the entire parental population

P1P2F1F2X=31gX=43gX=37gX=37gs=1.0s=1.0s=1.0s=2.45SP=1.0The frequency of the X allele (p) is: p = (2 * number of homozygous dominant + number of heterozygous) / (2 * total number of individuals)p = (2 * 0 + 2) / (2 * 2) = 1The frequency of the x allele (q) is: q = (2 * number of homozygous recessive + number of heterozygous) / (2 * total number of individuals)q = (2 * 0 + 0) / (2 * 2) = 0Therefore, 2pq = 2 * 1 * 0 = 0. The number of segregating genes is zero.

To know more about genes visit:

https://brainly.com/question/31121266

#SPJ11

1. Write all the factors that determine the amount of
protein synthesis.
2. Write all the factors that affect the function of
protein.

Answers

Proteins are essential macromolecules that play diverse roles in the structure, function, and regulation of cells and organisms. Protein synthesis is the cellular process through which proteins are produced, involving the transcription of DNA into mRNA and the translation of mRNA into a polypeptide chain, which then folds into a functional protein.

1. Factors that determine the amount of protein synthesis:

Availability of amino acidsEnergy supplyTranscription factorsRibosomes and tRNAsCo- and post-translational modificationsEnvironmental factors (such as temperature, pH, etc.)The rate of protein breakdown and degradationRegulatory proteins and microRNAs

2. Factors that affect the function of protein:

Environmental factors such as temperature, pH, and salt concentrationPost-translational modificationsOther proteins, such as chaperonesMembrane compositionLipid binding.

Learn more about protein synthesis: https://brainly.com/question/884041

#SPJ11

Submit your answer to this question in order to open week 5 lessons page. Complete the table: Cellular location Cellular location Uses Main products produced at the Process in prokaryotic in eukaryotic oxygen cells cells end Glycolysis Intermediate step (prep for Krebs cycle) Krebs cycle Aerobic electron transport chain

Answers

The table compares the cellular locations, uses, and main products produced at various stages of cellular respiration in prokaryotic and eukaryotic cells.

In prokaryotic cells, glycolysis occurs in the cytoplasm, where glucose is converted into pyruvate, producing a small amount of ATP and NADH. The intermediate step, also known as the preparatory step for the Krebs cycle, takes place in the cytoplasm as well, where pyruvate is converted into acetyl-CoA.

In eukaryotic cells, glycolysis also occurs in the cytoplasm, generating ATP and NADH from glucose. However, the intermediate step takes place in the mitochondria, where pyruvate is transported and converted into acetyl-CoA.

The Krebs cycle, also known as the citric acid cycle or the tricarboxylic acid cycle (TCA cycle), takes place in the mitochondrial matrix of both prokaryotic and eukaryotic cells. It generates high-energy molecules such as NADH, FADH2, and ATP through a series of enzymatic reactions.

The aerobic electron transport chain, which is the final stage of cellular respiration, occurs in the inner mitochondrial membrane of eukaryotic cells and the plasma membrane of prokaryotic cells. It involves the transfer of electrons from NADH and FADH2 to oxygen, generating a large amount of ATP through oxidative phosphorylation.

Overall, cellular respiration is a crucial metabolic process in both prokaryotic and eukaryotic cells, enabling the production of ATP and the efficient utilization of energy from glucose in the presence of oxygen.

Learn more about cellular respiration here

https://brainly.com/question/30001303

#SPJ11

Other Questions
How does a decrease in the reserve ratio by the Federal Reserve affect the money supply and the interest rate? When the reserve requirement decreases, banks lend out a larger fraction of their deposit B C D A E Hornones from which organ have the greatest effect on the basal metabolic rate (BMR)? Patient X has become overweight and recently developed high blood pressure and a lump on their upper back. You are an endocrinologist, and you first determine that X has high cortisol levels in the blood. Your next step is to determine whether the problem lies at the level of the hypothalamus, anterior pituitary, or adrenal gland. What is the predicted level (high, normal, low) for CRH, ACTH, and cortisol if the problem is:a) due to a problem with secretion of CRH by the hypothalamus?b) due to a problem with secretion of ACTH by the anterior pituitary gland?c) due to a problem with secretion of cortisol by the adrenal gland?4 and 5. Assume that you determine that the problem is very high secretion of cortisol by the adrenal gland despite normal levels of CRH in the hypothalamus.a. Describe two possible causes of this problem, andb. If you could collect tissue samples or images of this patient's anterior pituitary or adrenal gland, what experimental evidence would support your proposed causes?Use this framework for your answer:1. Condition a) (hypothalamus defect) 2 ptsCRH levels:ACTH levels:Cortisol levels:2. Condition b) (anterior pituitary defect) 2 ptsCRH levels:ACTH levels:Cortisol levels:3. Condition c) (defect at the level of the adrenal cortex) 2 ptsCRH levels:ACTH levels:Cortisol levels:4. a. Possible cause #1 for high secretion of cortisol by the adrenal gland despite normal CRH:b. Experimental evidence that would support this cause: 2 pts5. a. Possible cause #2 for high secretion of cortisol by the adrenal gland despite normal CRH:b. Experimental evidence that would support this cause: 2 pts Part 1your client universal construction has asked if you would be able to complete tax forms for theirs employees. Gary Pearson, Don Robertson, Belinda Rumphy, Robert Sanders, and Janice Sianos were thrilled and have decided they want you to complete their taxes. The employees have worked for the company for many years and usually seem stressed round tax time. To eliminate the stress of their workers and because Universal construction was so impressed with your services on their corporate taxes, they have requested your services for their employees.The employees have compiled all their slips and they have been attached. You have decided to use to generate their returns. This seems like a great opportunity to expand clentele, as they will likeky refer you to friends and family. Please complete the five returning using TurboTax.Part 2You have received a frantic call from Guy Tremblay from UNiversal Construction on a Friday afternoon. It was not made clear to him that his forms had to be handed in and he wants his return done immediately. Thinking that you were finished all your work you have sent your computer in for maintenance. The best option is to complete a manual return for him. Please complete a manuala tax return uinf CRA forms Determine the design heating load for a residence, 30 by 100 by 10 ft (height), to be located in Windsor Locks, Connecticut (design indoor temperature is 72 F and 30% RH and outdoor temperature is 3 F and 100% RH), which has an uninsulated slab on grade concrete floor (F-0.84 Btu/ft). The construction consists of Walls: 4 in. face brick (R=0.17), % in plywood sheathing (R=0.93), 4 in. cellular glass insulation (R=12.12), and / in. plasterboard (R=0.45) Ceiling/roof: 3 in. lightweight concrete deck (R=0.42), built-up roofing (R=0.33), 2 in. of rigid, expanded rubber insulation (R=9.10), and a drop ceiling of 7 in, acoustical tiles (R=1.25), air gap between rubber insulation and acoustical tiles (R=1.22) Windows: 45% of each wall is double pane, nonoperable, metal-framed glass with 1/4 in, air gap (U-0.69) Doors: Two 3 ft by 7 A, 1.75 in. thick, solid wood doors are located in each wall (U-0.46) All R values are in hr ft F/Btu and U values are in Btu/hr ft F units. R=1/U. Why are counts about 10^10 cfu/ml generally not achievable in most liquid growth media? As the number of bacteria increase, nutrients in the growth media are used up and waste products begin to create a toxic environment resulting in bacterial death As the number of bacteria decrease, nutrients in the growth media build up and waste products begin to create a toxic environment resulting in bacterial death O The statement is false. Bacteria will readily grow to 1020 CFU/ml in most liquid growth media O Too Many To Count (TMTC) A piston-cylinder device contains 0.005 m3 of liquid water and 0.95 m3 of water vapor in equilibrium at 600 kPa. Heat is transferred at constant pressure until the temperature reaches 200C. Using appropriate software, investigate the effect of pressure on the total mass of water in the tank. Let the pressure vary from 0.1 MPa to 1 MPa. Plot the total mass of water against pressure, and discuss the results. Also, show the process on a P-V diagram using the property plot feature of the software. Solve this problem using the appropriate software. Use data from the tables. Please upload your response/solution by using the controls provided below. a. A study starts with 5,000 people. Of these, 500 have the disease in question. What is the prevalence of disease?b. A study starts with 4,500 healthy people. (Think of these as the 5000 from problem 2 minus the 500prevalent cases.) Over the next 2 years, 100 develop the disease for the first time. What is the 2-year cumulative incidence of disease? Show all work. Question 5 1 pts Some owls produce two to three pellets every twenty-four hours. Assuming the owl feeds at a constant rate, calculate how many organisms it would eat over a twenty-four hour period based on the number of skulls or shoulder blades (divide shoulder blades by two if you cannot tell right from left) found in the pellet D Question 6 1 pts Compare the remains found in your owl pellet to those of another lab group. Based on the number and types of items found in the pellet do you think they came from the same owl? Why or why not? A steam power plant that produces 125,000 kw power has a turbo-generator with reheat-regenerative unit. The turbine operates steam with a condition of 92 bar, 440 C and a flow rate of 8,333.33 kg/min. Consider the cycle with 3 extraction on 23.5 bar, 17 bar and last extraction is saturated. The condenser has a measured temperature of 45C. Solve for(a) engine thermal efficiency,(b) cycle thermal efficiency,(c) work of the engine,(d) combined engine efficiency "What is the magnitude of the inductive reactance XL at a frequency of 10 Hz, if L is 15 H?" O 0.1 ohms O 25 ohms O 0.0011 ohms O 942 48 ohms For each of these definitions, select the correct matching term from the list above.WRITE ONLY THE LETTER AGAINST THE QUESTION NUMBER.Terms:A. Ancestral characterB. CladeC. ClassificationD. Derived characterE. GenusF. Horizontal gene transferG. KingdomH. OrderI. ParsimonyJ. PheneticsK. PhylumL. SpeciesM. Specific epithetN. SystematicsO. TaxonP. TaxonomyQ. Vertical gene transfer2.1 The arranging of organisms into groups using similarities and evolutionary relationships among lineages.2.2 The science of naming, describing, and classifying organisms.2.3 The noun part of the binomial system used to describe organisms.2.4 A taxon that comprises related classes.2.5 A formal grouping of organisms such as a class or family.2.6 A monophyletic group of organisms sharing a common ancestor.2.7 The systematic study of organisms based on similarities of many characters.2.8 The transfer of genes between different species.2.9 A recently evolved characteristic found in a clade.2.10 Using the simplest explanation of the available data to classify organisms. b) Determine the 4-point Discrete Fourier Transform (DFT) of the below function: x(n)={ 01(n=0,3)(n=1,2)Find the magnitude of the DFT spectrum, and sketch the result. (10 marks) Topic: pH/blood pH/acidosis and alkalosis a. Explain the relationship between pH and hydrogen ion (proton) concentration. b. Give one medical example of acidosis and explain how it affects homeostasis. c. Give one medical example of alkalosis and explain how it affects homeostasis. Explain the conditions that make the climate on Antarcticadifferent to the climate in Papa New Guinea. A heavy particle M moves up a rough surface of inclination a = 30 to the horizontal. Initially the velocity of the particle is v = 15 m/s. The coefficient of friction is f = 0.1. Determine the distance travelled by the particle before it comes to rest and the time taken. An engine lathe is used to turn a cylindrical work part 125 mm in diameter by 400 mm long. After one pass of turn, the part is turned to be a diameter of 119mm with a cutting speed = 2.50 m/s and feed = 0.40 mm/rev. Determine the cutting time in seconds. Sometimes you can detect your protein of interest in your cell extracts (via western blotting), sometimes not. You ask whether your protein is subjected to cell cycle dependent degradation.a. Design an experiment to find out whether the amount of your protein is changing in a cell cycle dependent manner.b. Protein degradation is an important regulator of cell cycle. Name a cell cycle phase-transition event that depend on protein degradation.c. Explain the molecules mechanisms of this phase transition (hint: which molecules are degraded by what, what happens when degraded or not, how is this regulated.) Three identical capacitors of 15 micro farad are connected in star across a 415 volts, 50Hz 3-phase supply. What value of capacitance must be connected in delta to take the same line current and line voltage? Phase current in star Phase current in delta Value of Xc in delta Capacitance in delta if DEFG is a rectangle, mDEG=(4x-5) and mFGE= (6x-21) find mDGE