Answer:
I think the answer is true.
Explanation:
Imagine that you have three circuit elements: a single bulb, a piece of wire, and a battery. You start by keeping these three elements separate and unconnected. You use a voltmeter to measure the voltage across each of the three elements. Then, you connect the bulb, wire, and battery together to form a complete circuit, so that the bulb lights up. You repeat the measurements you made before, using the voltmeter to measure the voltage across each element while it is in the complete circuit. For the questions below, assume that the battery and the wire are ideal.
a. Compare the voltage across the battery: a) when the battery is by itself vs b) when the battery is part of the complete circuit. Is the voltage across the battery different in these two situations, or is the voltage the same? Explain your answer.
b. Compare the voltage across the bulb: a) when the bulb is by itself vs b) when the bulb is part of the complete circuit. Is the voltage across the bulb different in these two situations, or is it the same? Explain.
c. Now compare the voltage across the piece of wire: a) when the wire is by itself vs b) when the wire is part of the complete circuit. Is the voltage across the piece of wire different in these two situations, or is it the same? Explain your answer.
d. Now consider only the situation in which the battery, wire, and bulb have been arranged to form a complete circuit in which the bulb lights up. For this situation, rank i) the voltage across the battery, ii) the voltage across the bulb, and iii) the voltage across the piece of wire, according to their absolute values, from greatest to smallest. If any are the same, or if any are zero, state that explicitly. Explain your reasoning.
Answer:
A) two voltages are equal, B) the two voltages are different
C) voltage is the same V = 0, D) V_{battery} = V_{Lamp} > V_{wire}
Explanation:
For this exercise, it is asked to build a circuit with the plug, the lamp and the battery, the circuit must be a series circuit
Before connecting the battery voltage is Vo as they indicate that it is ideal there are no losses, the voltages of the other elements are zero.
A) Voltages battery
a) single battery Vo
b) the battery is connected to the lamp this takes something current, but the electromotive force does not change therefore the voltage is Vo; This is because the battery's energy comes from a chemical reaction of the elements inside it.
in summary the two voltages are equal
B) voltage Lamp
a) when the bulb is single, its voltage is zero V = 0
since it has no energy
b) when in the circuit V = V₀ - V_r
where V_r is the voltage across the wire, due to its resistance, the energy for these voltages is given by the battery
in this case the two voltages are different
C) the voltage across the wire
a) unconnected V = 0
b) connected V = V₀ - V_L
where V_L is the voltage across the lamp due to its resistance
we can write the wire voltage
V_r = i R
as they indicate that the wire is ideal, its resistance is zero R = 0, consequently
V_r = 0
the voltage is the same V = 0
D) circuit voltage
For this part we must write Ohm's law for this circuit
V₀ = V_L + V_r
where V₀ is the battery voltage, V_L and V_r are the voltage of the lamp and the wire, respectively.
The voltage of each element is
V_L = i R_L
V_r = i R
This is a series circuit so the current is also constant
V₀ = i (R_L + R)
therefore the voltage in the battery is the highest V₀
the voltage across the wire if it is ideal is zero V_r = 0, if it is ideal its resistance is zero
therefore the voltage on the lamp is equal to the voltage of the battery
V_{battery} = V_{Lamp} > V_{wire}
Is water a element or compound
Answer:
compound
Explanation:
water is made up of oxygen (O) and hydrogen (H) therefore making it a compound (H2O)
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A hot piece of copper is placed in water in an insulated cup. What is the final
temperature of the water and copper?
(Use
me AT: + copperfcoppe, Acoppe: = 0]
m = 0.50 kg water = 4.18 kJ/kg-'c,
m.copper = 0.50 kg, Cropper = 0.386 kJ/kg-°C, Ti copper = 115°C
Tower = 22°C
O A. 30°C
B. 45°C
O C. 39°C
O D. 52°C
Answer:
38.7 °C.
The final temperature (reached by both copper and water) is 38.7 °C.
So the answer is probably C.
The heat energy lost by the metal piece is equal to the heat gained by the water in the cup. From this concept using calorimetric equation, their final temperature is equal to 30°C.
What is calorimetric equation?Calorimetric equation states the relation between heat energy absorbed or released by a system with the mass, specific heat capacity and temperature difference of the matter as written below:
q = m c Δ
Given, mass of copper piece = 0.50 kg
mass of water = 0.50 kg
c for Cu = 0.386 KJ/Kg °C
c for water = 0.418 KJ/Kg °C
The heat energy lost by copper metal is equal to the heat energy gained by water. Let T be the final temperature.
then,
0.50 kg × 0.386 KJ/Kg °C × (115°C - T) = 0.50 kg × 0.418 KJ/Kg °C × (T - 22°C).
2.09 (115°C - T) = 0.193 (T - 22°C).
2.09 T - 45.98 + 0.193 = 22.195
T = 30°C
Therefore, the final temperature of water and copper piece is 30 °C.
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Two wires each carry 10.0 A of current (in opposite directions) and are 2.50 mm apart. What is the magnetic field 37.0 cm away at point P, in the plane of the wires
Answer:
see answer below
Explanation:
Before we do any kind of calculation, we need to convert the proper units of the exercise. All the units of distance must be in meters, so, let's change distance of the wire, and the magnetic field to meters:
Separation between the wires are 2.5 mm:
2.5 mm * (1 m / 1000 mm) = 0.0025 m
The distance of P from the bottom of the wires is 37 cm:
37 cm * (1 m/100 cm) = 0.37 m
The distance of P from the top of the wires is just the sum of the two distances:
R = 0.37 + 0.0025 = 0.3725 m
Now that we have the distance, we can determine the magnetic field, using the following expression:
B = B(bottom) - B(top) or just B₂ - B₁
And B = μ₀ I / 2πR
Replacing in the above expression we have:
B = μ₀ I / 2π ( 1/R₂ - 1/R₁)
Now we can determine the magnetic field:
B = (4πx10⁻⁷ * 10 / 2π) (1/0.37 - 1/0.3725)
B = 3.63x10⁻⁸ TWhich means that the magnetic field is out of the page.
Hope this helps
What is the frequency of a wave travelling at 45.45 m/s with a wavelength of 2 m?
Answer:
22.73 Hz
Explanation:
Frequency = 45.45/2 = 22.73 Hz
An object has a coefficient of static friction of 0.3 and a normal force of 30 N. Find the force of static friction.
Answer:
9N
Explanation:
static friction=normal force x coefficient of static friction
so static friction =30N x 0.3= 9N
Explanation:
9N is the static friction
Two protons in a molecule are 4.40 10-10 m apart. Find the electric force exerted by one proton on the other.
Answer:
F = 1.19 x 10⁹ N
Explanation:
The electrostatic force between the charged particles is given by Colomb's Law as follows:
[tex]F = \frac{kq_{1}q_{2}}{r^{2}}[/tex]
where,
F = Electrostatic force = ?
k = Colomb's constant = 9 x 10⁹ N.m²/C²
q₁ = q₂ = charge on proton = 1.6 x 10⁻¹⁹ C
r = distance between protons = 4.4 x 10⁻¹⁰ m
Therefore,
[tex]F = \frac{(9\ x\ 10^{9}\ Nm^{2}/C^{2})(1.6\ x\ 10^{-19}\ C)(1.6\ x\ 10^{-19}\ C)}{(4.4\ x\ 10^{-10})^{2}} \\\\[/tex]
F = 1.19 x 10⁹ N
7. Consumers can be predators, prey, scavengers, herbivores omnivoree, or carnivore: What is the common characteristic of all consumer: A Create their own food B. Must eat to get energy C. Hunt for live animals D. Will eat anything
Answer:
B. Must eat to get energy
Explanation:
The common characteristics of all consumers is that they must eat to get energy. This way, they are termed heterotrophs.
Heterotrophs are organisms that cannot make their own food. They must eat other organisms to obtain nutrition for energy needs.
Plants do not do this. They are autotrophs in that they simply make their own food.
They use this food to obtain energy for their living activities.
Learning Task 5: Read each situation and encircle the letter of the best
answer. Do this activity on your notebook,
1. Our team is the champion because of our captain. No matter how fast his
Opponent shoot the ball he can do the same, he never misses it and hits it
right back. What emotion is shown in the situation?
A. Happiness
B. Anger
C. Sadness
D. Afraid
Answer:
I think the tone is happiness using the clues of "champion". But depending on who is saying it and background information it could be something different but based on the text here and the answer choices personally the best answer in my opinion is happiness.
If there was jealousy or optimism it would be a harder decision.
Explanation:
Hope this helped :)
Calculate the magnetic field at 2m from a straight wire carrying a current of 5 A. (K = 2 x 10 ^-7)
Answer:
[tex]B=5\times 10^{-7}\ T[/tex]
Explanation:
Given that,
Current in a wire, I = 5 A
We need to find the magnetic field at 2m from a straight wire carrying a current of 5 A.
The magnetic field due to a wire is given by :
[tex]B=\dfrac{\mu_0I}{2\pi r}\\\\B=\dfrac{4\pi \times 10^{-7}\times 5}{2\pi \times 2}\\\\B=5\times 10^{-7}\ T[/tex]
So, the required magnetic field is [tex]5\times 10^{-7}\ T[/tex].
if the mass of the object is doubled and the speed is halved then kinetic energy will change by a factor of:
2
4
1/2
1/4
Answer:
kinetic energy will change by a factor of 1/2
Option C) 1/2 is the correct answer
Explanation:
Given the data in the question;
we know that;
Kinetic energy = 1/2.mv²
given that mass of the object is doubled; m1 = 2m
speed is halved; v1 = V/2
Now, New kinetic energy will be; 1/2.m1v1²
we substitute
Kinetic Energy = 1/2 × 2m × (v/2)²
Kinetic Energy = 1/2 × 2m × (v²/4)
Kinetic Energy = 1/2 × m × (v²/2)
Kinetic Energy = 1/2 [ 1/2mv² ]
Kinetic Energy = 1/2 [ KE ]
Therefore; kinetic energy will change by a factor of 1/2
Option C) 1/2 is the correct answer
llustration 2: Aman can run a distance of 100 m in 20 seconds. Find the speed of Aman in m/s.
Answer:
[tex]\boxed {\boxed {\sf 5 \ meters/second}}[/tex]
Explanation:
Speed is equal to distance over time.
[tex]s=\frac{d}{t}[/tex]
The distance is 100 meters and the time is 20 seconds.
[tex]d= 100 \ m \\t= 20 \ s[/tex]
Substitute the values into the formula.
[tex]s=\frac{100 \ m }{20 \ s}[/tex]
Divide.
[tex]s= 5 \ m/s[/tex]
Aman's speed is 5 meters per second.
How/is climate change/human interaction affecting mutualism
1- If a skater travels 50 miles in one hour, what is the skaters speed?
2- A biker travels 10 miles in two hours, what is his speed?
3- A driver is going 42 miles in a 15 mph school zone and is pulled over by a police officer. The speed the driver was driver is known as what type of speed?
If the current in each wire is the same, which wire produces the strongest magnetic field?
-a wire that is 1 mm thick and not coiled
-a wire that is 2 mm thick and not coiled
-a 1-mm-thick coiled wire with ten loops
-a 2-mm-thick coiled wire with two loops
Answer:
C
Explanation:
I did this before
Answer:
it is c
Explanation:
cuz i know
PLEASE HELP ME, IT’S URGENT!!!
What is your hypothesis for, “what effect does parachute size have on the rate that the parachute drops?”
I would say that you may check in ..........g....o...o...g....l....e
fasttt plsss!!!!
Energy A car engine drives a generator, which produces and stores electric charge in the car's battery. The headlamps use the electric charge stored in the car battery. List the forms of energy in these three operations
Give 2 examples of situations in which environmental values could come into conflict with other values
Answer:
Example of situations in which environmental values could come into conflict with other values, such as economy values of family values, include deciding whether or not a businessman should fly across the country for a meeting or whether a family should buy a gas car or an electric car.
The water side of the wall of a 60-m-long dam is a quarter-circle with a radius of 7 m. Determine the hydrostatic force on the dam and its line of action when the dam is filled to the rim. Take the density of water to be 1000 kg/m3.
Answer:
[tex]26852726.19\ \text{N}[/tex]
[tex]57.52^{\circ}[/tex]
Explanation:
r = Radius of circle = 7 m
w = Width of dam = 60 m
h = Height of the dam will be half the radius = [tex]\dfrac{r}{2}[/tex]
A = Area = [tex]rw[/tex]
V = Volume = [tex]w\dfrac{\pi r^2}{4}[/tex]
Horizontal force is given by
[tex]F_x=\rho ghA\\\Rightarrow F_x=1000\times 9.81\times \dfrac{7}{2}\times 7\times 60\\\Rightarrow F_x=14420700\ \text{N}[/tex]
Vertical force is given by
[tex]F_y=\rho gV\\\Rightarrow F_y=1000\times 9.81\times 60\times \dfrac{\pi 7^2}{4}\\\Rightarrow F_y=22651982.59\ \text{N}[/tex]
Resultant force is
[tex]F=\sqrt{F_x^2+F_y^2}\\\Rightarrow F=\sqrt{14420700^2+22651982.59^2}\\\Rightarrow F=26852726.19\ \text{N}[/tex]
The hydrostatic force on the dam is [tex]26852726.19\ \text{N}[/tex].
The direction is given by
[tex]\theta=\tan^{-1}\dfrac{F_y}{F_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{22651982.59}{14420700}\\\Rightarrow \theta=57.52^{\circ}[/tex]
The line of action is [tex]57.52^{\circ}[/tex].
How does the size of a wind turbine affect its energy output?
A.)Smaller turbines spin slower.
B.) Larger turbines have a greater storage capacity.
C.) Larger turbines generate more electricity.
D.)Smaller turbines are better for capturing strong winds.
Answer:
Larger tubines generate more electricity.
Explanation:
Larger blades allow the turbine to capture more of the kinetic energy of the wind by moving more air through the rotors. However, larger blades require more space and higher wind speeds to operate. This distance is necessary to avoid interference between turbines, which decreases the power output.
Potential energy is
stored in a state of readiness.
conserved.
energy of motion.
not measurable.
Answer:
stored in a state of readiness.
Explanation:
Potential energy is stored in a state of readiness.
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
[tex] P.E = mgh[/tex]
Where, P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
The power in our homes and buildings cycles at a frequency of 60Hz. If someone accidentally dropped a power line into a holding tank for frogs their muscles would immediately become stiff. This is because the high frequency stimuli is causing
Answer:
The answer is "Rigor mortis".
Explanation:
When the very large volume will be that the progress of its postponed by calcium and magnesium. The causes brain intensification of a liver due to the change throughout the myofibrils within a week of dying of its organism. When anyone accidentally spilled a power cable into a rank for toads, one's tissue will be disrupted instantly by stringent deaths.
This is because the high frequency stimuli of the power line is causing rigor
mortis.
Rigor mortis is referred to as the stiffening of the body of animals when they
die and is usually caused by the body's glycogen and ATP concentration
diminishing.
Rigor mortis can also be caused by a high frequency stimuli such as
exposure to electric current which hastens the conditions that causes it to
occur.
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The three inclines have the same height and they are all frictionless, but they have different angles. Which object will have the highest speed at the bottom of the incline
Answer:
the speed of the body must be the same for the three hills regardless of their slope
v = [tex]\sqrt{2gy}[/tex]
Explanation:
To shorten the answer to this exercise, let's use the concept of conservation of energy
starting point. Highest point of the hill
Em₀ = U = m h y
final point. Lower part of the hill
Em_f = K = ½ m v²
as there is no friction the mechanical energy is conserved
Em₀ = Em_f
mg y = ½ m v²
v = [tex]\sqrt{2gy}[/tex]
Let's analyze this result, we see that the speed at the bottom of the hill depends only on the height of the hill, not on the slope, so the speed of the body must be the same for the three hills regardless of their slope
2. Fill in the blanks
a. Two bodies are rubbed against each other they acquire __________and _____________
charges.
b. ___________are transferred from one object to another when two objects are charged by
friction.
c. __________ is a device used to secure tall buildings from the effect of lightning
d. __________charge is obtained by plastic comb when rubbed with dry hair.
e. Lightning is __________ on huge scale
Answer:
a. Two bodies are rubbed against each other they acquire equal and Opposite charge.
b. Electron are transferred from one object to another when two objects are charged by friction.
c. Lightening rod is a device used to secure tall buildings from the effect of lightning
d. Negative charge is obtained by plastic comb when rubbed with dry hair.
e. Lightning is natural spark discharge on huge scale.
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student builds a simple circuit with a single resistor with resistance R and measures an electric potential difference ΔV across the resistor. Then, the student replaces the resistor with a new one of resistance 2R and keeps the electric potential difference the same. What is the current (I2) through the new circuit in terms of the original current(I1)? 6mks
Answer:
i₂ = ½ i₁
Explanation:
Let's write ohm's law for the first statement
V = i₁ R
i₁ = V / R
tells us that we change the resistance to R '= 2R
let's write ohm's law
V = i₂ R’
indicates that V remains constant
i₂ = V / R '
i₂ = V / 2R
i₂ = ½ V/R
we substitute
i₂ = ½ i₁
Mass of 23.94kg and volume 2.10 cubic centimeters. Calculate the density of the copper wire in si units (ų/mm cubic)
Answer:
Density = 1.14 kg/mm³
Explanation:
Given the following data;
Volume = 2.10 cm³ to mm = 2.10 * 10 = 21 mm³
Mass = 23.94kg
To find the density;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
[tex]Density = \frac{mass}{volume}[/tex]
Substituting into the equation, we have;
[tex]Density = \frac{23.94}{21}[/tex]
Density = 1.14 kg/mm³
Currents exist in the ocean without the need of electric fields.
True
False
Answer:
True
Explanation:
A(n)_____ planet is composed of rocky material, has no rings, and is closer to the sun.
Answer:
A terrestrial planet.
Explanation:
Terrestrial planets (Inner planets) are closer to the sun then outer planets. No inner planet has rings and they are all composed of rocky material.
A terrestrial planet planet is composed of rocky material, has no rings, and is closer to the sun.
What is terrestrial planet?Terrestrial planets are Earth-like planets having a hard surface consisting of rocks or metals. A molten heavy-metal core, few moons, and topographical features like valleys, volcanoes, and craters are also characteristics of terrestrial planets.
Mercury, Venus, Earth, and Mars are the four terrestrial planets in our solar system, and they also happen to be the four nearest to the sun.
There may have been more terrestrial planetoids during the solar system's formation, but they either combined or were obliterated.
The planets are not entirely terrestrial. Gas giants, also referred to as Jovian planets, include Jupiter, Saturn, Uranus, and Neptune in our solar system.
Hence, a terrestrial planet planet is composed of rocky material, has no rings, and is closer to the sun.
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Sam, whose mass is 78 kg , stands at the top of a 11-m-high, 110-m-long snow-covered slope. His skis have a coefficient of kinetic friction on snow of 0.07. If he uses his poles to get started, then glides down, what is his speed at the bottom
Answer:
v = 8.09 m/s
Explanation:
For this exercise we use that the work done by the friction force plus the potential energy equals the change in the body's energy.
Let's calculate the energy
starting point. Higher
Em₀ = U = m gh
final point. To go down the slope
Em_f = K = ½ m v²
The work of the friction force is
W = fr L cos 180
to find the friction force let's use Newton's second law
Axis y
N - W_y = 0
N = W_y
X axis
Wₓ - fr = ma
let's use trigonometry
sin θ = y / L
sin θ = 11/110 = 0.1
θ = sin⁻¹ 0.1
θ = 5.74º
sin 5.74 = Wₓ / W
cos 5.74 = W_y / W
Wₓ = W sin 5.74
W_y = W cos 5.74
the formula for the friction force is
fr = μ N
fr = μ W cos θ
Work is friction force is
W_fr = - μ W L cos θ
Let's use the relationship of work with energy
W + ΔU = ΔK
-μ mg L cos 5.74 + (mgh - 0) = 0 - ½ m v²
v² = - 2 μ g L cos 5.74 +2 (gh)
v² = 2gh - 2 μ gL cos 5.74
let's calculate
v² = 2 9.8 11 - 2 0.07 9.8 110 cos 5.74
v² = 215.6 -150.16
v = √65.44
v = 8.09 m/s