Sonni added 23.79 mL of KOH to 20.00 mL of 0.393 M HF until the equivalence point was reached. What is the concentration of conjugate base at the equivalence point after the initial neutralization?

Answers

Answer 1

Answer:

0.1795 M

Explanation:

From the given information:

The equation is:

[tex]\mathbf{HF_{(aq)}+ KOH_{(aq)} \to KF _{(aq)} + H_2O}[/tex]

From the above equation, the reaction will go to completion due to the strong base:

At the equivalence point, moles of acid (HF) will be equal to moles of base (KOH)

[tex]\text{Number of moles = Volume} \times Molarity[/tex]

Thus. since moles of HF = moles of KOH

Then; 0.020 × 0.393 M = 0.02379 × (x) M

(x) M = [tex]\dfrac{0.02 \times 0.393 \ M}{0.02379}[/tex]

(x) = 0.3304 M

Thus, the molarity of KOH = 0.3304 M

Using the balanced neutralization reaction;

moles of HF = moles of KOH = moles of conjugate base = 0.00786 mol

Volume = 0.020 L + 0.02379 L

Volume = 0.04379 L

Volume of the solution =  0.04379 L

Therefore; Molarity = [tex]\dfrac{moles}{volume}[/tex]

Molarity = [tex]\dfrac{0.00786 \ mol}{0.04379 \ L}[/tex]

Molarity = 0.17949 mol/L

= 0.1795 M

Answer 2

After the initial neutralization, the molarity at the equivalence point will be:

"0.17949 mol/L"

Concentration of solution

According to the question,

→ HF (aq) + KOH (aq) [tex]\rightarrow[/tex] KF (aq) + H₂O

Since, moles of HF = moles of KOH

We know that,

Number of moles = Volume × Molarity

→ 0.020 × 0.393 = 0.02379 × M

By applying cross-multiplication,

The molarity of KOH be:

M = [tex]\frac{0.02\times 0.393}{0.02379}[/tex]

   = [tex]\frac{0.00786}{0.02379}[/tex]

   = 0.3304 M

By using balanced neutralization reaction,

Volume = 0.020 + 0.02379

             = 0.04379 L

hence,

The molarity will be:

= [tex]\frac{Moles}{Volume}[/tex]

By substituting the values,

= [tex]\frac{0.00786}{0.04379}[/tex]

= 0.17949 mol/L

Thus the response above is correct.

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This is ur answer.......

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Answers

Answer:

CaO < BaO < KCl <KI

Explanation:

Let us remember that the solubility of an ionic substance in water depends on the magnitude of the lattice energy and the hydration energy.  If the hydration energy is equal to or is greater than the lattice energy, the substance dissolves in water.

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Answers

Answer:

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Answer:

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Answers

Answer:

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