SOMEONE PLS HELP ME WITH THIS ASAP

The diagram shows a circle with a
circunference of 88 cm and a sector of a circle.

Khairul uses the circle and the sector
to form a right cone with the height of 15 cm Calculate the volume, in cm of the cone formed.
[tex]use \: \pi = \frac{22}{7} [/tex]

SOMEONE PLS HELP ME WITH THIS ASAP The Diagram Shows A Circle With Acircunference Of 88 Cm And A Sector

Answers

Answer 1

Answer:

Let's solve for the radius.

r = C / 2π = 88 / (2 * 22/7) = 14

Volume of a cone = 1/3 * πr²h

= 1/3 * 22/7 * 14² * 15

= 3080 cm³


Related Questions

Nash's Trading Post, LLC took a physical inventory on December 31 and determined that goods costing $208,000 were on hand. Not included in the physical count were $30,000 of goods purchased from Swifty Corporation, FOB, shipping point, and $23,500 of goods sold to Marigold Corp. For $30,000, FOB destination. Both the Swifty purchase and the Marigold sale were in transit at year-end.

Answers

Answer:

$261,500

Step-by-step explanation:

What amount should Nash report as its December 31 inventory?

Item                                                             Amount

Goods on hand as per physical count    $208,000

(+) Goods purchased from Swifty             $30,000

Corporation FOB shipping point    

(+) Goods sold to Marigold Corp               $23,500

FOB destination (at cost value)

Ending inventory                                        $261,500

Notes:

1) In case of FOB shipping point, the ownership of goods is transferred to the buyer when the goods are shipped and hence in the case of purchases from Swifty corporation, the goods should be included in the inventory of Nash's Trading Post as the goods are shipped and are in transit.

2) In case of FOB destination, the ownership of goods is transferred to the buyer when the goods reaches to the buyer, hence in the case of sales made to Marigold Corp, the goods are still in transit and the ownership is not transferred to Marigold Corp, hence Nash's Trading Post should included that goods in its inventory.

Use the given degree of confidence and sample data to construct interval for the population proportion. Of 369 randomly selected medical students, 23 said that they planned to work in a rural community. Construct a 95% confidence interval for the percentage of all medical students who plan to work in a rural community. (4.16%, 8.30%) (3.77%, 9.47%) (3.30%, 9.17%) (2.99%, 9.47%) (3.77%, 8.70%) In a poll of registered voters nationwide, 43% of those polled blamed of companies the most for the recent increase in gasoline prices. The margin of error at the 96% confidence level for this point estimate is 2.4%. Construct a 95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices. (0.382, 0.478) (0.368, 0.492) (0.406, 0.477) (0.383, 0.477) Cannot be determined from the information given.

Answers

Answer:

e)  (3.77%, 8.70%)

95% confidence interval for the percentage of all medical students who plan to work in a rural community

(3.83% , 8.69%)

95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices

(0.406 , 0.454)

Step-by-step explanation:

Step(i):-

Given random sample size 'n' = 369

Sample proportion

                              [tex]p = \frac{x}{n} = \frac{23}{369} = 0.0623[/tex]

95% confidence intervals are determined by

[tex](p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} })[/tex]

[tex](0.0623 - 1.96 \sqrt{\frac{0.0623(1-0.0623)}{369} } , 0.0623 + 1.96\sqrt{\frac{0.0623(1-0.0623)}{369} })[/tex]

(0.0623 - 0.0246 , 0.0623 + 0.0246)

(0.0383 , 0.0869)

(3.83% , 8.69%)

95% confidence interval for the percentage of all medical students who plan to work in a rural community

(3.83% , 8.69%)

Step(ii):-

Given 43% of those polled blamed of companies the most for the recent increase in gasoline prices

sample proportion 'p' = 0.43

Given Margin of error (M.E) = 0.024

95% confidence intervals are determined by

[tex](p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} })[/tex]

[tex](0.43 - 0.024 } , 0.43 +0.024 )[/tex]

(0.406 , 0.454)

Final answer:-

95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices

(0.406 , 0.454)

PLEASE. NEED HELP. Find the sum.

Answers

Distribute the sum:

[tex]\displaystyle\sum_{i=1}^{24}(3i-2)=3\sum_{i=1}^{24}i-2\sum_{i=1}^{24}1[/tex]

Use the following formulas:

[tex]\displaystyle\sum_{i=1}^n1=n[/tex]

[tex]\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2[/tex]

[tex]\implies\displaystyle\sum_{i=1}^{24}(3i-2)=3\cdot\frac{24\cdot25}2-2\cdot24=\boxed{852}[/tex]

In case you don't know where those formulas came from:

The first one is obvious; you're just adding n copies of 1, so 1 + 1 + ... + 1 = n.

The second can be proved in this way: let S be the sum 1 + 2 + 3 + ... + n. Rearrange it as S = n + (n - 1) + (n - 2) + ... + 1. Then 2S = (n + 1) + (n + 1) + (n + 1) + ... + (n + 1), or n copies of n + 1. So 2S = n(n + 1). Divide both sides by 2 and we're done.

Two teaching methods, A and B, are implemented for learning Spanish. There is a 70% chance of successfully learning Spanish if method A is used, and a 85% chance of success if methodB is used. However, method B is substantially more 3. time consuming and is therefore used only 20% of the time (method A is used the other 80% of the time). The following notations are suggested:
A-Method A is used.
B-Method B is used.
L-Spanish was learned successfully Interpret each of the probabilities given in the original problem in probability
a) notation with their respective values (four of these).
b) Draw a Probability Tree representing each of the probabilities mentioned above.
c) What is the likelihood a person does not learn Spanish?
d) A student learned the spanish successfully. What is the probability that they were taught by method B?

Answers

Answer:

(a) Shown below.

(b) Shown below.

(c) The probability that a person does not learn Spanish is 0.18.

(d) The probability that method B was used given that a student learned the Spanish successfully is 0.83.

Step-by-step explanation:

(a)

Consider the provided data.

[tex]P(A)=0.20\\P(B)=0.80\\P(L|A)=0.70\\P(L|B)=0.85[/tex]

Then the probability of not learning Spanish using the respective methods are:

[tex]P(L'|A)=1-P(L|A)=1-0.70=0.30\\\\P(L'|B)=1-P(L|B)=1-0.70=0.15[/tex]

(b)

The Probability Tree representing each of the probabilities mentioned above is attached below.

(c)

Compute the probability that a person does not learn Spanish as follows:

[tex]P(L')=P(L'|A)P(A)+P(L'|B)P(B)[/tex]

         [tex]=(0.30\times 0.20)+(0.15\times 0.80)\\\\=0.06+0.12\\\\=0.18[/tex]

Thus, the probability that a person does not learn Spanish is 0.18.

(d)

Compute the probability that method B was used given that a student learned the Spanish successfully as follows:

[tex]P(B|L)=\frac{P(L|B)P(B)}{P(L|A)P(A)+P(L|B)P(B)}[/tex]

            [tex]=\frac{(0.85\times 0.80)}{(0.70\times 0.20)+(0.85\times 0.80)}\\\\=\frac{0.68}{0.14+0.68}\\\\=0.82927\\\\\approx 0.83[/tex]

Thus, the probability that method B was used given that a student learned the Spanish successfully is 0.83.

HELP IF YOU KNOW THIS PLEASEEEE

Answers

Answer:

63m

Step-by-step explanation:

HELP ASAP!!!
Identify the volume and surface area of a sphere with great circle area 9 pi m^2 in terms of pi. Give your answer in terms of pi.​

Answers

Step-by-step explanation:

great circle = 9[tex]\pi[/tex] = r^2.[tex]\pi[/tex] --> r = 3 m

Surface area S = 4[tex]\pi[/tex].r^2 = 36[tex]\pi[/tex] m^2

Volume V = 4/3[tex]\pi[/tex].r^3 = 36[tex]\pi[/tex] m^3

The volume of a sphere is 36π m³ and the Surface area of sphere 36π m². Therefore, option A is the correct answer.

What is the volume of a sphere?

The volume of sphere is the measure of space that can be occupied by a sphere.  If the radius of the sphere formed is r and the volume of the sphere is V. Then, the volume of the sphere is given by: Volume of Sphere, V = (4/3)πr³

Given that, sphere with great circle area 9π m².

We know that, area of a circle = πr²

Now, πr²=9π m²

r=3 m

Here, volume of a sphere = 4/3 ×π×3³

= 36π m³

Surface area of sphere = A = 4πr²

= 4×π×3²

= 36π m²

Therefore, option A is the correct answer.

To learn more about the volume of a sphere visit:

https://brainly.com/question/9994313.

#SPJ2

A certain quantity decays exponentially over time. The initial quantity at t = 0 is 1,000. The quantity
decays at a rate of 2%. What is the quantity at t = 4?
A. 0.00016
B. 1.6000
C. 903.9208
D. 922.3682

Answers

Answer:

D: 922.3682

Step-by-step explanation:

First you take 1000 and subtract 20 from it.( 2% of 1000 = 1000x0.02x2=20).

You could do this on a calculator by entering 1000 and then subtracting 2% by clicking minus then, 2 then percent, then equals. you get 980. do the same to 980. (click minus, then 2, then percent, then equals). you get 960.4. do the same to 960.4. you get 941.192. do the same one more time since it says t=4  and you get 922.36816 which rounded to the nearest ten-thousandths is 922.3682.

hope this helped!

Can someone please help me I really need help

Answers

Answer:

choice c

Step-by-step explanation:

y axis shows value of computer

v-intercept; x axis = 0

show initial value of the computer

You have a prepaid bus pass that has $10 on it. Every time you ride the bus it costs you 50 cents. Assume that you cannot put anymore money on the card after it is used. Create an equation for the situation above.

Answers

Answer:

y = 10 - 0.5x for 0 ≤  x ≤ 20

Step-by-step explanation:

Initial value = (0,10)

final value = (20,0)

Cost per trip = debit of 0.50 = slope

equation : y = 10 - 0.5x for 0 <=  x <= 20

A train travels 600 km in one hour .what is the trains Velocity in meters /seconds?

Answers

Answer:

166.6666 metres/second

Step-by-step explanation:

1 km/hr = 5m/18s

600*5/18

which is the domain of the function in this table ?

Answers

Answer: 1,2,3,4

Step-by-step explanation:

The domain consists of every x value

Need help on this math problem!!!

Answers

Answer:

[tex](fof^{-1})(x)=x[/tex]

Step-by-step explanation:

Composition of two functions f(x) and g(x) is represented by,

(fog)(x) = f[g(x)]

If a function is,

f(x) = (-6x - 8)² [where x ≤ [tex]-\frac{8}{6}[/tex]]

Another function is the inverse of f(x),

[tex]f^{-1}(x)=-\frac{\sqrt{x}+8}{6}[/tex]

Now composite function of these functions will be,

[tex](fof^{-1})(x)=f[f^{-1}(x)][/tex]

                  = [tex][-6(\frac{\sqrt{x}+8}{6})-8]^{2}[/tex]

                  = [tex][-\sqrt{x}+8-8]^2[/tex]

                  = [tex](-\sqrt{x})^2[/tex]

                  = x

Therefore, [tex](fof^{-1})(x)=x[/tex]

13 points, please answer!

Which shows the dilation with a possible scale factor of 1/2?

Answers

Answer:

Option B

Step-by-step explanation:

With a scale factor of 1/2, the dilated shape should be smaller because of the scale factor, So in Option B the dilated shape is smaller than the real one.

1) Option A is an enlargement

2) Option B is reduction

3) Option C is equality

Which relationship in the triangle must be true?
A
c
b
C
B
а
sin(B) = sin(A)
sin(B) = cos(90 - B)
COS(B) = sin(180 - B)
cos(B) = (A)

Answers

Answer:

sin(B) = cos(90 - B).

Step-by-step explanation:

To answer this question, you must understand SOH CAH TOA.

SOH = Sine; Opposite divided by Hypotenuse

CAH = Cosine; Adjacent divided by Hypotenuse

TOA = Tangent; Opposite divided by Adjacent

I roughly drew a triangle for reference. Let's say we have a 3-4-5 triangle.

As you can see, sin(b) does not equal sin(a). To get the sine of an angle, you would do opposite over hypotenuse. For angle B, that would be 3/5, while for angle A, that would be 4/5.

As stated above, sin(B) is 3/5. Now, if you did cos(90 - B), it would be the same thing as cos(A). This is because the triangle is a right triangle. Since a triangle has 180 degrees, and one angle is a right triangle, the other two angles will add up to be 90 degrees. So, 90 - B = A. cos(A) is the same thing as adjacent over hypotenuse, which is 3/5. So, sin(B) = cos(90 - B) must be true.

Let's just check the others to make sure they are false.

cos(B) = 4/5.

sin(180 - B) is basically the same thing as sin(A + C), which is definitely NOT 4/5.

cos(B) = 4/5, which is NOT the same as A.

So, your answer is sin(B) = cos(90 - B).

Hope this helps!

. Write an example problem that includes a compound event. b. List all of the outcomes of the sample space of the compound event.

Answers

Answer:

living organism

Step-by-step explanation:

soil particals and decad crops living organism

a group of girls bought 72 rainbow hairbands ,144 brown and black hairbands and 216 bright colored hairbands .what is the largest possible number of girls in the group

Answers

Answer:

72

Step-by-step explanation:

We are assuming that all girls in the group bought the same number of items.

Therefore, we need to find the highest common factor of 72, 144 and 216.

HCF

72 = 2 * 2 * 2 * 3 * 3

144 = 2 * 2 * 2 * 2 * 3 * 3

216 = 2 * 2 * 2 * 3 * 3 * 3

The product of the emboldened numbers is the highest common factor.

That is:

2 * 2 * 2 * 3 * 3 = 72

Therefore, the largest possible number of girls in the group is 72.

In a road-paving process, asphalt mix is delivered to the hopper of the paver by trucks that haul the material from the batching plant. The article "Modeling of Simultaneously Continuous and Stochastic Construction Activities for Simulation" (J. of Construction Engr. and Mgmnt., 2013: 1037-1045) proposed a normal distribution with mean value 8.46 min and standard deviation .913 min for the rv X 5 truck haul time.a. What is the probability that haul time will be at least 10 min? Will exceed 10 min?b. What is the probability that haul time will exceed 15 min?c. What is the probability that haul time will be between 8 and 10 min?d. What value c is such that 98% of all haul times are in the interval from 8.46 2 c to 8.46 1 c?e. If four haul times are independently selected, what is the probability that at least one of them exceeds 10 min?

Answers

Answer:

a) Probability that haul time will be at least 10 min = P(X ≥ 10) ≈ P(X > 10) = 0.0455

b) Probability that haul time be exceed 15 min = P(X > 15) = 0.000

c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10) = 0.6460

d) The value of c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)

c = 2.12

e) If four haul times are independently selected, the probability that at least one of them exceeds 10 min = 0.1700

Step-by-step explanation:

This is a normal distribution problem with

Mean = μ = 8.46 min

Standard deviation = σ = 0.913 min

a) Probability that haul time will be at least 10 min = P(X ≥ 10)

We first normalize/standardize 10 minutes

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69

To determine the required probability

P(X ≥ 10) = P(z ≥ 1.69)

We'll use data from the normal distribution table for these probabilities

P(X ≥ 10) = P(z ≥ 1.69) = 1 - (z < 1.69)

= 1 - 0.95449 = 0.04551

The probability that the haul time will exceed 10 min is approximately the same as the probability that the haul time will be at least 10 mins = 0.0455

b) Probability that haul time will exceed 15 min = P(X > 15)

We first normalize 15 minutes.

z = (x - μ)/σ = (15 - 8.46)/0.913 = 7.16

To determine the required probability

P(X > 15) = P(z > 7.16)

We'll use data from the normal distribution table for these probabilities

P(X > 15) = P(z > 7.16) = 1 - (z ≤ 7.16)

= 1 - 1.000 = 0.000

c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10)

We normalize or standardize 8 and 10 minutes

For 8 minutes

z = (x - μ)/σ = (8 - 8.46)/0.913 = -0.50

For 10 minutes

z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69

The required probability

P(8 < X < 10) = P(-0.50 < z < 1.69)

We'll use data from the normal distribution table for these probabilities

P(8 < X < 10) = P(-0.50 < z < 1.69)

= P(z < 1.69) - P(z < -0.50)

= 0.95449 - 0.30854

= 0.64595 = 0.6460 to 4 d.p.

d) What value c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)?

98% of the haul times in the middle of the distribution will have a lower limit greater than only the bottom 1% of the distribution and the upper limit will be lesser than the top 1% of the distribution but greater than 99% of fhe distribution.

Let the lower limit be x'

Let the upper limit be x"

P(x' < X < x") = 0.98

P(X < x') = 0.01

P(X < x") = 0.99

Let the corresponding z-scores for the lower and upper limit be z' and z"

P(X < x') = P(z < z') = 0.01

P(X < x") = P(z < z") = 0.99

Using the normal distribution tables

z' = -2.326

z" = 2.326

z' = (x' - μ)/σ

-2.326 = (x' - 8.46)/0.913

x' = (-2.326×0.913) + 8.46 = -2.123638 + 8.46 = 6.336362 = 6.34

z" = (x" - μ)/σ

2.326 = (x" - 8.46)/0.913

x" = (2.326×0.913) + 8.46 = 2.123638 + 8.46 = 10.583638 = 10.58

Therefore, P(6.34 < X < 10.58) = 98%

8.46 - c = 6.34

8.46 + c = 10.58

c = 2.12

e) If four haul times are independently selected, what is the probability that at least one of them exceeds 10 min?

This is a binomial distribution problem because:

- A binomial experiment is one in which the probability of success doesn't change with every run or number of trials. (4 haul times are independently selected)

- It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (Only 4 haul times are selected)

- The outcome of each trial/run of a binomial experiment is independent of one another. (The probability that each haul time exceeds 10 minutes = 0.0455)

Probability that at least one of them exceeds 10 mins = P(X ≥ 1)

= P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

= 1 - P(X = 0)

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 4 haul times are independently selected

x = Number of successes required = 0

p = probability of success = probability that each haul time exceeds 10 minutes = 0.0455

q = probability of failure = probability that each haul time does NOT exceeds 10 minutes = 1 - p = 1 - 0.0455 = 0.9545

P(X = 0) = ⁴C₀ (0.0455)⁰ (0.9545)⁴⁻⁰ = 0.83004900044

P(X ≥ 1) = 1 - P(X = 0)

= 1 - 0.83004900044 = 0.16995099956 = 0.1700

Hope this Helps!!!

Estimate. 6.13/3 Choose 1 answer: a 2 b20 c200 d2000

Answers

Answer:

The answer is option A.

2.

Hope this helps you

Rachel rides her bicycle due east at 12 kilometers per hour. Amos rides his
bicycle due north at 16 kilometers per hour. If they left from the same point at
the same time, how far apart will they be after 2 hours?

Answers

Answer:

40 km away.

Step-by-step explanation:

a^2 + b^2 = c^2

In this case, a = 16 * 2 = 32 km, since he travels 16 km per hour for 2 hours.

b = 12 * 2 = 24 km, since she travels 12 km per hour for 2 hours.

32^2 + 24^2 = c^2

1,024 + 576 = c^2

1600 = c^2

c^2 = 1600

c = plus or minus 40

Since distance cannot be negative, they will be 40 km away.

Hope this helps!

The required, after 2 hours, Rachel and Amos will be 40 kilometers apart.

What are Pythagorean triplets?

In a right-angled triangle, its sides, such as hypotenuse, and perpendicular, and the base is Pythagorean triplets.

Here,

We can use the Pythagorean theorem to solve this problem. After 2 hours, Rachel will have traveled 24 kilometers (12 km/hour x 2 hours) due east, and Amos will have traveled 32 kilometers (16 km/hour x 2 hours) due north. Let's call the distance between them after 2 hours "d".

Using the Pythagorean theorem, we can write:

d² = (24 km)²+ (32 km)²

Simplifying this expression:

d² = 576 km² + 1024 km²

d² = 1600 km²

Taking the square root of both sides,

d = 40 km

Therefore, after 2 hours, Rachel and Amos will be 40 kilometers apart.

Learn more about Pythagorean triplets here:

brainly.com/question/22160915

#SPJ5

What decimal represents the shaded part in the picture?

Answers

Answer:

40/100 = 0.4

your welcome

Helppp!!!! please!!!

Answers

Answer:

A. 336 ft²

Step-by-step explanation:

Add the sides: 6*8 + 6*12 + 12*8 + 10*12 = 336

One little trick: the area of the triangle sides is base times half height, i.e., 6*8/2, but since we have two of them you can just use 6*8!

Point S is located on RT so that RS/ST = 1/4. What are the coordinates of Point S? (4 , 4 ) (2.4, 2.4) (8 , 8 ) (4.4, 4.4)

Answers

Answer:

  (4.4, 4.4)

Step-by-step explanation:

The point S can be found as the weighted average of the end points. The relative weights are the reverse of the distances to the end points:

  RS : ST = 1 : 4

  S = (4R +1T)/5

  S = (4(2, 2) +(14, 14))/5 = (22, 22)/5

  S = (4.4, 4.4)

Does the following table show a proportional relationship between the variables , g and h?
9
3
6
9
h
9
36
81
Choose 1 answer:
А
Yes
No
Report a problem

Answers

Answer:

no

Step-by-step explanation:

Answer:

No is the answer you are welcome

solve this, please prove it with steps in detail

Answers

Answer:

2

Step-by-step explanation:

-(1-√2) -(2-√3) + 1/√3 + 2+1/2+√5-(√5-√6)-(√6-√7)+ 1/√7+2√2+1/2√2+3

-1+√2-√2+√3-(√3-2)-(2-√5)-√5+√6-√6+√7-(√7-2√2)-(2√2-3)

-1+√2-√2+√3-√3+2-2+√5-√5+√6-√6+√7-√7+2√2-2√2+3

2

A translation moves A(2,3) onto A′(4,8). If B(4,6), what is the image of B under the same translation?
A. (6,11)
B. (12,18)
C. (6,8)
D. (8,12)

Answers

If i am right it should be A.

Which of the following is the best definition of slope?
O A. The point where a line crosses the y-axis
B. The measure of the steepness of a line
O C. The value of a dependent variable
O D. The value of an independent variable​

Answers

Answer: B

Step-by-step explanation: In algebra, we use the word slope to describe how steep a line is and slope can be found using the ratio rise/run between any two points that are on that line.

Please answer i will give thanks and 5 star

Answers

Answer:

A, B, and E are all less than 1/8

The mean length of 4 childrens' big finger is 14cm. The mean length of 9 adults' big finger is 16.1cm. What is the mean length (rounded to 2 DP) of these 13 people's big finger?

Answers

Answer:

The mean length of the 13 people's big finger is 15.45 cm

Step-by-step explanation:

Given;

mean length of 4 childrens' big finger, x' = 14cm

mean length of 9 adults' big finger is 16.1cm, x'' = 16.1cm

Let the total length of the 4 childrens' big finger = t

[tex]x' = \frac{t}{n} \\\\x' = \frac{t}{4}\\\\t = 4x'\\\\t = 4 *14\\\\t = 56 \ cm[/tex]

Let the total length of the 9 adults' big finger = T

[tex]x'' = \frac{T}{N} \\\\x'' = \frac{T}{9}\\\\T = 9x''\\\\T = 9*16.1\\\\T = 144.9 \ cm[/tex]

The total length of the 13 people's big finger = t + T

                                                                           = 56 + 144.9

                                                                            =200.9 cm

The mean length of these 13 people's big finger;

x''' = (200.9) / 13

x''' = 15.4539 cm

x''' = 15.45 cm (2 DP)

Therefore, the mean length of the 13 people's big finger is 15.45 cm

Please help! *grade 9 algebra work* :)

Answers

Answer:

9x-3 or 3(3x-1)

Step-by-step explanation:

A triangle has three sides. To find the perimeter, add those side lengths together.

3x-3+(4x-1)+(2x+1)

Add your common terms (xs and constants) together.

3x+4x+2x=9x

-1+-3+1=-3

9x-3

If you want to, you can factor the expression.

3(3x-1)

Answer:

9x - 3

Step-by-step explanation:

The perimeter is all the sides added together.

4x - 1 + 2x + 1 + 3x - 3

Rearrange.

4x + 2x + 3x - 1 + 1 - 3

Combine like terms.

9x - 3

Based on a recent poll, there is a 50-50 chance that randomly selected adut has pierced ears, Express the indicated degree of likelihood as a proabability value between 0 and 1.

Answers

Answer:

1/2 or 0.5

Step-by-step explanation:

Saying that there is a 50-50 chance of an event happening is equivalent to saying there is a 1 in 2 chance. Therefore, expressing that degree of likelihood as a value between 0 and 1:

[tex]\frac{1}{2}=0.50[/tex]

There is a 1/2 or 0.5 chance that a randomly selected adult has pierced ears.

Answer:

1/2 or 0.5

Step-by-step explanation:

50-50 chance between 0-1 means half of 0-1 which is 1/2 or 0.5

1/2 or 0.5!

Other Questions
Use the Integral Test to determine whether the series is convergent or divergent. n =1 summation [infinity] n / n2 + 8 n = 1 Evaluate the following integral. 1 integral [infinity] x/x2 + 8 dx Economist Jones favors a constant-money-growth-rate rule. She says that if the annual money supply growth rate each year is equal to the average annual growth rate in Real GDP, price stability will exist over time. What would economist Smith, who favors activist monetary policy, say to economist Jones? The biceps femoris muscle's name gives us information about it. What does the word "femoris" in its name tell us? A. Its general location B. Its action C. Its overall shape D. The number of attachments it has E. Its general size (compared to other muscles) F. The direction of its muscle fibers Living conditions in American cities in the late nineteenth century were deplorable for the poor for all of the following reasons EXCEPT ___________. many were strangers to the city housing arrangements were crowded city services were inadequate ethnic neighborhoods had no sense of community toy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizontal surface, taken as the x-y plane. The 4.00 kg puck has a velocity of 3.00 i m/s at one instant. Eight seconds later, its velocity is (8.00 i 10.00 j) m/s. Assuming the rocket engine exerts a constant force, find (a) the components of the force and (b) its magnitude. in the play you are putting on you want the auddience to feel emotionally close to the actors and play. what could you do to achieve this? Can somebody please help me with this question? What will happen to the astronaut when the jets produce these four forces: 10N, 10N, 9N, 9N? which name best describes the group of shapes below???? Mandy and karissa swam laps in the pool to train for the upcoming swim meet. The ratio to the number of laps Mandy swam to the number of laps karissa swam was 2 to 3. If Mandy swam 12 laps, how many laps did karissa swim? What is the area of the triangle in the diagram? 2. What is the correct sequence of market structures from the most competitive to theleast competitive? Education and income both have a large impact on whether a person gets needed healthcare. Education affects income. Often, having more education means a person will earn more income later in life. Education also helps people make wise decisions when choosing between health products and services. Income often determines whether healthcare is affordable. Even if they have health insurance, people pay some amount for healthcare. When a person has little income, this amount can become difficult. People with less education can spend as much as 50 percent of their income on housing, leaving little for money for healthcare and other expenses. As a result of not getting needed healthcare, people can develop health conditions or leave health conditions untreated. In fact, studies have found that more than one-half of people in the US have delayed or chosen not to get treatment for a health condition because of cost. Using the information in this passage, write an essay about the relationship between education, income, and access to healthcare. How do these factors affect each other? How do interactions between these factors influence health? Which of the following aqueous solutions are good buffer systems? . a. 0.12 M calcium hydroxide + 0.29 M calcium bromide . b. 0.25 M perchloric acid + 0.16 M sodium perchlorate . c. 0.34 M hydrocyanic acid + 0.27 M sodium cyanide . A perfume bottle is dropped in the comer of a room. The odor of the perfume can be detected on the other side of the statement best describes this observation? Particles are moving from regions of high concentration to low concentration.Particles are moving from regions of low concentration to high concentration. Particles are moving through a small opening into a smaller volume. Particles are moving through a small opening into a larger volume. Te parece que se podra representar en una dramatizar ion las acciones que se presentan en el texto "las obras de cocinero"? find the value of x. m A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the speed of the satellite. Evaluate the limit, if it exists.lim (h - > 0) ((-7 + h)^2 - 49) / h When does crossing over occur in meiosis? prophase II metaphase I metaphase II prophase I