Answer:
Let's solve for the radius.
r = C / 2π = 88 / (2 * 22/7) = 14
Volume of a cone = 1/3 * πr²h
= 1/3 * 22/7 * 14² * 15
= 3080 cm³
Nash's Trading Post, LLC took a physical inventory on December 31 and determined that goods costing $208,000 were on hand. Not included in the physical count were $30,000 of goods purchased from Swifty Corporation, FOB, shipping point, and $23,500 of goods sold to Marigold Corp. For $30,000, FOB destination. Both the Swifty purchase and the Marigold sale were in transit at year-end.
Answer:
$261,500
Step-by-step explanation:
What amount should Nash report as its December 31 inventory?
Item Amount
Goods on hand as per physical count $208,000
(+) Goods purchased from Swifty $30,000
Corporation FOB shipping point
(+) Goods sold to Marigold Corp $23,500
FOB destination (at cost value)
Ending inventory $261,500
Notes:
1) In case of FOB shipping point, the ownership of goods is transferred to the buyer when the goods are shipped and hence in the case of purchases from Swifty corporation, the goods should be included in the inventory of Nash's Trading Post as the goods are shipped and are in transit.
2) In case of FOB destination, the ownership of goods is transferred to the buyer when the goods reaches to the buyer, hence in the case of sales made to Marigold Corp, the goods are still in transit and the ownership is not transferred to Marigold Corp, hence Nash's Trading Post should included that goods in its inventory.
Use the given degree of confidence and sample data to construct interval for the population proportion. Of 369 randomly selected medical students, 23 said that they planned to work in a rural community. Construct a 95% confidence interval for the percentage of all medical students who plan to work in a rural community. (4.16%, 8.30%) (3.77%, 9.47%) (3.30%, 9.17%) (2.99%, 9.47%) (3.77%, 8.70%) In a poll of registered voters nationwide, 43% of those polled blamed of companies the most for the recent increase in gasoline prices. The margin of error at the 96% confidence level for this point estimate is 2.4%. Construct a 95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices. (0.382, 0.478) (0.368, 0.492) (0.406, 0.477) (0.383, 0.477) Cannot be determined from the information given.
Answer:
e) (3.77%, 8.70%)
95% confidence interval for the percentage of all medical students who plan to work in a rural community
(3.83% , 8.69%)
95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices
(0.406 , 0.454)
Step-by-step explanation:
Step(i):-
Given random sample size 'n' = 369
Sample proportion
[tex]p = \frac{x}{n} = \frac{23}{369} = 0.0623[/tex]
95% confidence intervals are determined by
[tex](p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} })[/tex]
[tex](0.0623 - 1.96 \sqrt{\frac{0.0623(1-0.0623)}{369} } , 0.0623 + 1.96\sqrt{\frac{0.0623(1-0.0623)}{369} })[/tex]
(0.0623 - 0.0246 , 0.0623 + 0.0246)
(0.0383 , 0.0869)
(3.83% , 8.69%)
95% confidence interval for the percentage of all medical students who plan to work in a rural community
(3.83% , 8.69%)
Step(ii):-
Given 43% of those polled blamed of companies the most for the recent increase in gasoline prices
sample proportion 'p' = 0.43
Given Margin of error (M.E) = 0.024
95% confidence intervals are determined by
[tex](p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} })[/tex]
[tex](0.43 - 0.024 } , 0.43 +0.024 )[/tex]
(0.406 , 0.454)
Final answer:-
95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices
(0.406 , 0.454)
PLEASE. NEED HELP. Find the sum.
Distribute the sum:
[tex]\displaystyle\sum_{i=1}^{24}(3i-2)=3\sum_{i=1}^{24}i-2\sum_{i=1}^{24}1[/tex]
Use the following formulas:
[tex]\displaystyle\sum_{i=1}^n1=n[/tex]
[tex]\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2[/tex]
[tex]\implies\displaystyle\sum_{i=1}^{24}(3i-2)=3\cdot\frac{24\cdot25}2-2\cdot24=\boxed{852}[/tex]
In case you don't know where those formulas came from:
The first one is obvious; you're just adding n copies of 1, so 1 + 1 + ... + 1 = n.
The second can be proved in this way: let S be the sum 1 + 2 + 3 + ... + n. Rearrange it as S = n + (n - 1) + (n - 2) + ... + 1. Then 2S = (n + 1) + (n + 1) + (n + 1) + ... + (n + 1), or n copies of n + 1. So 2S = n(n + 1). Divide both sides by 2 and we're done.
Two teaching methods, A and B, are implemented for learning Spanish. There is a 70% chance of successfully learning Spanish if method A is used, and a 85% chance of success if methodB is used. However, method B is substantially more 3. time consuming and is therefore used only 20% of the time (method A is used the other 80% of the time). The following notations are suggested:
A-Method A is used.
B-Method B is used.
L-Spanish was learned successfully Interpret each of the probabilities given in the original problem in probability
a) notation with their respective values (four of these).
b) Draw a Probability Tree representing each of the probabilities mentioned above.
c) What is the likelihood a person does not learn Spanish?
d) A student learned the spanish successfully. What is the probability that they were taught by method B?
Answer:
(a) Shown below.
(b) Shown below.
(c) The probability that a person does not learn Spanish is 0.18.
(d) The probability that method B was used given that a student learned the Spanish successfully is 0.83.
Step-by-step explanation:
(a)
Consider the provided data.
[tex]P(A)=0.20\\P(B)=0.80\\P(L|A)=0.70\\P(L|B)=0.85[/tex]
Then the probability of not learning Spanish using the respective methods are:
[tex]P(L'|A)=1-P(L|A)=1-0.70=0.30\\\\P(L'|B)=1-P(L|B)=1-0.70=0.15[/tex]
(b)
The Probability Tree representing each of the probabilities mentioned above is attached below.
(c)
Compute the probability that a person does not learn Spanish as follows:
[tex]P(L')=P(L'|A)P(A)+P(L'|B)P(B)[/tex]
[tex]=(0.30\times 0.20)+(0.15\times 0.80)\\\\=0.06+0.12\\\\=0.18[/tex]
Thus, the probability that a person does not learn Spanish is 0.18.
(d)
Compute the probability that method B was used given that a student learned the Spanish successfully as follows:
[tex]P(B|L)=\frac{P(L|B)P(B)}{P(L|A)P(A)+P(L|B)P(B)}[/tex]
[tex]=\frac{(0.85\times 0.80)}{(0.70\times 0.20)+(0.85\times 0.80)}\\\\=\frac{0.68}{0.14+0.68}\\\\=0.82927\\\\\approx 0.83[/tex]
Thus, the probability that method B was used given that a student learned the Spanish successfully is 0.83.
HELP IF YOU KNOW THIS PLEASEEEE
Answer:
63m
Step-by-step explanation:
HELP ASAP!!!
Identify the volume and surface area of a sphere with great circle area 9 pi m^2 in terms of pi. Give your answer in terms of pi.
Step-by-step explanation:
great circle = 9[tex]\pi[/tex] = r^2.[tex]\pi[/tex] --> r = 3 m
Surface area S = 4[tex]\pi[/tex].r^2 = 36[tex]\pi[/tex] m^2
Volume V = 4/3[tex]\pi[/tex].r^3 = 36[tex]\pi[/tex] m^3
The volume of a sphere is 36π m³ and the Surface area of sphere 36π m². Therefore, option A is the correct answer.
What is the volume of a sphere?The volume of sphere is the measure of space that can be occupied by a sphere. If the radius of the sphere formed is r and the volume of the sphere is V. Then, the volume of the sphere is given by: Volume of Sphere, V = (4/3)πr³
Given that, sphere with great circle area 9π m².
We know that, area of a circle = πr²
Now, πr²=9π m²
r=3 m
Here, volume of a sphere = 4/3 ×π×3³
= 36π m³
Surface area of sphere = A = 4πr²
= 4×π×3²
= 36π m²
Therefore, option A is the correct answer.
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A certain quantity decays exponentially over time. The initial quantity at t = 0 is 1,000. The quantity
decays at a rate of 2%. What is the quantity at t = 4?
A. 0.00016
B. 1.6000
C. 903.9208
D. 922.3682
Answer:
D: 922.3682
Step-by-step explanation:
First you take 1000 and subtract 20 from it.( 2% of 1000 = 1000x0.02x2=20).
You could do this on a calculator by entering 1000 and then subtracting 2% by clicking minus then, 2 then percent, then equals. you get 980. do the same to 980. (click minus, then 2, then percent, then equals). you get 960.4. do the same to 960.4. you get 941.192. do the same one more time since it says t=4 and you get 922.36816 which rounded to the nearest ten-thousandths is 922.3682.
hope this helped!
Can someone please help me I really need help
Answer:
choice c
Step-by-step explanation:
y axis shows value of computer
v-intercept; x axis = 0
show initial value of the computer
You have a prepaid bus pass that has $10 on it. Every time you ride the bus it costs you 50 cents. Assume that you cannot put anymore money on the card after it is used. Create an equation for the situation above.
Answer:
y = 10 - 0.5x for 0 ≤ x ≤ 20
Step-by-step explanation:
Initial value = (0,10)
final value = (20,0)
Cost per trip = debit of 0.50 = slope
equation : y = 10 - 0.5x for 0 <= x <= 20
A train travels 600 km in one hour .what is the trains Velocity in meters /seconds?
Answer:
166.6666 metres/second
Step-by-step explanation:
1 km/hr = 5m/18s
600*5/18
which is the domain of the function in this table ?
Answer: 1,2,3,4
Step-by-step explanation:
The domain consists of every x value
Need help on this math problem!!!
Answer:
[tex](fof^{-1})(x)=x[/tex]
Step-by-step explanation:
Composition of two functions f(x) and g(x) is represented by,
(fog)(x) = f[g(x)]
If a function is,
f(x) = (-6x - 8)² [where x ≤ [tex]-\frac{8}{6}[/tex]]
Another function is the inverse of f(x),
[tex]f^{-1}(x)=-\frac{\sqrt{x}+8}{6}[/tex]
Now composite function of these functions will be,
[tex](fof^{-1})(x)=f[f^{-1}(x)][/tex]
= [tex][-6(\frac{\sqrt{x}+8}{6})-8]^{2}[/tex]
= [tex][-\sqrt{x}+8-8]^2[/tex]
= [tex](-\sqrt{x})^2[/tex]
= x
Therefore, [tex](fof^{-1})(x)=x[/tex]
13 points, please answer!
Which shows the dilation with a possible scale factor of 1/2?
Answer:
Option B
Step-by-step explanation:
With a scale factor of 1/2, the dilated shape should be smaller because of the scale factor, So in Option B the dilated shape is smaller than the real one.
1) Option A is an enlargement
2) Option B is reduction
3) Option C is equality
Which relationship in the triangle must be true?
A
c
b
C
B
а
sin(B) = sin(A)
sin(B) = cos(90 - B)
COS(B) = sin(180 - B)
cos(B) = (A)
Answer:
sin(B) = cos(90 - B).
Step-by-step explanation:
To answer this question, you must understand SOH CAH TOA.
SOH = Sine; Opposite divided by Hypotenuse
CAH = Cosine; Adjacent divided by Hypotenuse
TOA = Tangent; Opposite divided by Adjacent
I roughly drew a triangle for reference. Let's say we have a 3-4-5 triangle.
As you can see, sin(b) does not equal sin(a). To get the sine of an angle, you would do opposite over hypotenuse. For angle B, that would be 3/5, while for angle A, that would be 4/5.
As stated above, sin(B) is 3/5. Now, if you did cos(90 - B), it would be the same thing as cos(A). This is because the triangle is a right triangle. Since a triangle has 180 degrees, and one angle is a right triangle, the other two angles will add up to be 90 degrees. So, 90 - B = A. cos(A) is the same thing as adjacent over hypotenuse, which is 3/5. So, sin(B) = cos(90 - B) must be true.
Let's just check the others to make sure they are false.
cos(B) = 4/5.
sin(180 - B) is basically the same thing as sin(A + C), which is definitely NOT 4/5.
cos(B) = 4/5, which is NOT the same as A.
So, your answer is sin(B) = cos(90 - B).
Hope this helps!
. Write an example problem that includes a compound event. b. List all of the outcomes of the sample space of the compound event.
Answer:
living organism
Step-by-step explanation:
soil particals and decad crops living organism
a group of girls bought 72 rainbow hairbands ,144 brown and black hairbands and 216 bright colored hairbands .what is the largest possible number of girls in the group
Answer:
72
Step-by-step explanation:
We are assuming that all girls in the group bought the same number of items.
Therefore, we need to find the highest common factor of 72, 144 and 216.
HCF
72 = 2 * 2 * 2 * 3 * 3
144 = 2 * 2 * 2 * 2 * 3 * 3
216 = 2 * 2 * 2 * 3 * 3 * 3
The product of the emboldened numbers is the highest common factor.
That is:
2 * 2 * 2 * 3 * 3 = 72
Therefore, the largest possible number of girls in the group is 72.
In a road-paving process, asphalt mix is delivered to the hopper of the paver by trucks that haul the material from the batching plant. The article "Modeling of Simultaneously Continuous and Stochastic Construction Activities for Simulation" (J. of Construction Engr. and Mgmnt., 2013: 1037-1045) proposed a normal distribution with mean value 8.46 min and standard deviation .913 min for the rv X 5 truck haul time.a. What is the probability that haul time will be at least 10 min? Will exceed 10 min?b. What is the probability that haul time will exceed 15 min?c. What is the probability that haul time will be between 8 and 10 min?d. What value c is such that 98% of all haul times are in the interval from 8.46 2 c to 8.46 1 c?e. If four haul times are independently selected, what is the probability that at least one of them exceeds 10 min?
Answer:
a) Probability that haul time will be at least 10 min = P(X ≥ 10) ≈ P(X > 10) = 0.0455
b) Probability that haul time be exceed 15 min = P(X > 15) = 0.000
c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10) = 0.6460
d) The value of c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)
c = 2.12
e) If four haul times are independently selected, the probability that at least one of them exceeds 10 min = 0.1700
Step-by-step explanation:
This is a normal distribution problem with
Mean = μ = 8.46 min
Standard deviation = σ = 0.913 min
a) Probability that haul time will be at least 10 min = P(X ≥ 10)
We first normalize/standardize 10 minutes
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69
To determine the required probability
P(X ≥ 10) = P(z ≥ 1.69)
We'll use data from the normal distribution table for these probabilities
P(X ≥ 10) = P(z ≥ 1.69) = 1 - (z < 1.69)
= 1 - 0.95449 = 0.04551
The probability that the haul time will exceed 10 min is approximately the same as the probability that the haul time will be at least 10 mins = 0.0455
b) Probability that haul time will exceed 15 min = P(X > 15)
We first normalize 15 minutes.
z = (x - μ)/σ = (15 - 8.46)/0.913 = 7.16
To determine the required probability
P(X > 15) = P(z > 7.16)
We'll use data from the normal distribution table for these probabilities
P(X > 15) = P(z > 7.16) = 1 - (z ≤ 7.16)
= 1 - 1.000 = 0.000
c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10)
We normalize or standardize 8 and 10 minutes
For 8 minutes
z = (x - μ)/σ = (8 - 8.46)/0.913 = -0.50
For 10 minutes
z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69
The required probability
P(8 < X < 10) = P(-0.50 < z < 1.69)
We'll use data from the normal distribution table for these probabilities
P(8 < X < 10) = P(-0.50 < z < 1.69)
= P(z < 1.69) - P(z < -0.50)
= 0.95449 - 0.30854
= 0.64595 = 0.6460 to 4 d.p.
d) What value c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)?
98% of the haul times in the middle of the distribution will have a lower limit greater than only the bottom 1% of the distribution and the upper limit will be lesser than the top 1% of the distribution but greater than 99% of fhe distribution.
Let the lower limit be x'
Let the upper limit be x"
P(x' < X < x") = 0.98
P(X < x') = 0.01
P(X < x") = 0.99
Let the corresponding z-scores for the lower and upper limit be z' and z"
P(X < x') = P(z < z') = 0.01
P(X < x") = P(z < z") = 0.99
Using the normal distribution tables
z' = -2.326
z" = 2.326
z' = (x' - μ)/σ
-2.326 = (x' - 8.46)/0.913
x' = (-2.326×0.913) + 8.46 = -2.123638 + 8.46 = 6.336362 = 6.34
z" = (x" - μ)/σ
2.326 = (x" - 8.46)/0.913
x" = (2.326×0.913) + 8.46 = 2.123638 + 8.46 = 10.583638 = 10.58
Therefore, P(6.34 < X < 10.58) = 98%
8.46 - c = 6.34
8.46 + c = 10.58
c = 2.12
e) If four haul times are independently selected, what is the probability that at least one of them exceeds 10 min?
This is a binomial distribution problem because:
- A binomial experiment is one in which the probability of success doesn't change with every run or number of trials. (4 haul times are independently selected)
- It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (Only 4 haul times are selected)
- The outcome of each trial/run of a binomial experiment is independent of one another. (The probability that each haul time exceeds 10 minutes = 0.0455)
Probability that at least one of them exceeds 10 mins = P(X ≥ 1)
= P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)
= 1 - P(X = 0)
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = 4 haul times are independently selected
x = Number of successes required = 0
p = probability of success = probability that each haul time exceeds 10 minutes = 0.0455
q = probability of failure = probability that each haul time does NOT exceeds 10 minutes = 1 - p = 1 - 0.0455 = 0.9545
P(X = 0) = ⁴C₀ (0.0455)⁰ (0.9545)⁴⁻⁰ = 0.83004900044
P(X ≥ 1) = 1 - P(X = 0)
= 1 - 0.83004900044 = 0.16995099956 = 0.1700
Hope this Helps!!!
Estimate. 6.13/3 Choose 1 answer: a 2 b20 c200 d2000
Answer:
The answer is option A.
2.Hope this helps you
Rachel rides her bicycle due east at 12 kilometers per hour. Amos rides his
bicycle due north at 16 kilometers per hour. If they left from the same point at
the same time, how far apart will they be after 2 hours?
Answer:
40 km away.
Step-by-step explanation:
a^2 + b^2 = c^2
In this case, a = 16 * 2 = 32 km, since he travels 16 km per hour for 2 hours.
b = 12 * 2 = 24 km, since she travels 12 km per hour for 2 hours.
32^2 + 24^2 = c^2
1,024 + 576 = c^2
1600 = c^2
c^2 = 1600
c = plus or minus 40
Since distance cannot be negative, they will be 40 km away.
Hope this helps!
The required, after 2 hours, Rachel and Amos will be 40 kilometers apart.
What are Pythagorean triplets?In a right-angled triangle, its sides, such as hypotenuse, and perpendicular, and the base is Pythagorean triplets.
Here,
We can use the Pythagorean theorem to solve this problem. After 2 hours, Rachel will have traveled 24 kilometers (12 km/hour x 2 hours) due east, and Amos will have traveled 32 kilometers (16 km/hour x 2 hours) due north. Let's call the distance between them after 2 hours "d".
Using the Pythagorean theorem, we can write:
d² = (24 km)²+ (32 km)²
Simplifying this expression:
d² = 576 km² + 1024 km²
d² = 1600 km²
Taking the square root of both sides,
d = 40 km
Therefore, after 2 hours, Rachel and Amos will be 40 kilometers apart.
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What decimal represents the shaded part in the picture?
Answer:
40/100 = 0.4
your welcome
Helppp!!!! please!!!
Answer:
A. 336 ft²
Step-by-step explanation:
Add the sides: 6*8 + 6*12 + 12*8 + 10*12 = 336
One little trick: the area of the triangle sides is base times half height, i.e., 6*8/2, but since we have two of them you can just use 6*8!
Point S is located on RT so that RS/ST = 1/4. What are the coordinates of Point S? (4 , 4 ) (2.4, 2.4) (8 , 8 ) (4.4, 4.4)
Answer:
(4.4, 4.4)
Step-by-step explanation:
The point S can be found as the weighted average of the end points. The relative weights are the reverse of the distances to the end points:
RS : ST = 1 : 4
S = (4R +1T)/5
S = (4(2, 2) +(14, 14))/5 = (22, 22)/5
S = (4.4, 4.4)
Does the following table show a proportional relationship between the variables , g and h?
9
3
6
9
h
9
36
81
Choose 1 answer:
А
Yes
No
Report a problem
Answer:
no
Step-by-step explanation:
Answer:
No is the answer you are welcome
solve this, please prove it with steps in detail
Answer:
2
Step-by-step explanation:
-(1-√2) -(2-√3) + 1/√3 + 2+1/2+√5-(√5-√6)-(√6-√7)+ 1/√7+2√2+1/2√2+3
-1+√2-√2+√3-(√3-2)-(2-√5)-√5+√6-√6+√7-(√7-2√2)-(2√2-3)
-1+√2-√2+√3-√3+2-2+√5-√5+√6-√6+√7-√7+2√2-2√2+3
2
A translation moves A(2,3) onto A′(4,8). If B(4,6), what is the image of B under the same translation?
A. (6,11)
B. (12,18)
C. (6,8)
D. (8,12)
Which of the following is the best definition of slope?
O A. The point where a line crosses the y-axis
B. The measure of the steepness of a line
O C. The value of a dependent variable
O D. The value of an independent variable
Answer: B
Step-by-step explanation: In algebra, we use the word slope to describe how steep a line is and slope can be found using the ratio rise/run between any two points that are on that line.
Please answer i will give thanks and 5 star
Answer:
A, B, and E are all less than 1/8
The mean length of 4 childrens' big finger is 14cm. The mean length of 9 adults' big finger is 16.1cm. What is the mean length (rounded to 2 DP) of these 13 people's big finger?
Answer:
The mean length of the 13 people's big finger is 15.45 cm
Step-by-step explanation:
Given;
mean length of 4 childrens' big finger, x' = 14cm
mean length of 9 adults' big finger is 16.1cm, x'' = 16.1cm
Let the total length of the 4 childrens' big finger = t
[tex]x' = \frac{t}{n} \\\\x' = \frac{t}{4}\\\\t = 4x'\\\\t = 4 *14\\\\t = 56 \ cm[/tex]
Let the total length of the 9 adults' big finger = T
[tex]x'' = \frac{T}{N} \\\\x'' = \frac{T}{9}\\\\T = 9x''\\\\T = 9*16.1\\\\T = 144.9 \ cm[/tex]
The total length of the 13 people's big finger = t + T
= 56 + 144.9
=200.9 cm
The mean length of these 13 people's big finger;
x''' = (200.9) / 13
x''' = 15.4539 cm
x''' = 15.45 cm (2 DP)
Therefore, the mean length of the 13 people's big finger is 15.45 cm
Please help! *grade 9 algebra work* :)
Answer:
9x-3 or 3(3x-1)
Step-by-step explanation:
A triangle has three sides. To find the perimeter, add those side lengths together.
3x-3+(4x-1)+(2x+1)
Add your common terms (xs and constants) together.
3x+4x+2x=9x
-1+-3+1=-3
9x-3
If you want to, you can factor the expression.
3(3x-1)
Answer:
9x - 3
Step-by-step explanation:
The perimeter is all the sides added together.
4x - 1 + 2x + 1 + 3x - 3
Rearrange.
4x + 2x + 3x - 1 + 1 - 3
Combine like terms.
9x - 3
Based on a recent poll, there is a 50-50 chance that randomly selected adut has pierced ears, Express the indicated degree of likelihood as a proabability value between 0 and 1.
Answer:
1/2 or 0.5
Step-by-step explanation:
Saying that there is a 50-50 chance of an event happening is equivalent to saying there is a 1 in 2 chance. Therefore, expressing that degree of likelihood as a value between 0 and 1:
[tex]\frac{1}{2}=0.50[/tex]
There is a 1/2 or 0.5 chance that a randomly selected adult has pierced ears.
Answer:
1/2 or 0.5
Step-by-step explanation:
50-50 chance between 0-1 means half of 0-1 which is 1/2 or 0.5
1/2 or 0.5!