Someone help please!!!!

Answer:

E. 54cm ^2

Step-by-step explanation:

when finding the area just multiply length over width .for example 9 is the length times it to the width 6 you get 54 so the area will be 54 cm

Answer:

E

Step-by-step explanation:

length times width

6 x 9 = 54

Answer:

Taking 45 degree as reference angle

Then using sine rule

sin 45=

p/h

replacing the value of sin 45 degree by 1/root 2.so

1/root 2=9/c

doing cross multiplication

9*root 2=1*c

9 root 2 =c

therefore the value of c is 9 root 2

Step-by-step explanation:

Answer:

There is a 1/3 chance it lands on each section

Step-by-step explanation:

Answer:

∠ G ≈ 8.3°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan G = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{HI}{GI}[/tex] = [tex]\frac{1.1}{7.5}[/tex] , then

∠ G = [tex]tan^{-1}[/tex] ([tex]\frac{1.1}{7.5}[/tex] ) ≈ 8.3° ( to the nearest tenth )

Answer:

Hi, there the answer is Graph A because the y-intercept and I did rise over run

Step-by-step explanation:

Hope this helps :)

Answer:

i don't know that language sorry

Step-by-step explanation:

Answer:

There is a little over 1 gallon

Step-by-step explanation:

Answer:

[tex] \frac{4}{5} [/tex]

Step-by-step explanation:

[tex] ( \cos \theta) ^{2} + ( \sin \theta) ^{2} = 1 \\ \\ \therefore \: { \bigg( \frac{{6} }{10} \bigg)}^{2} + ( \sin \theta) ^{2} = 1 \\ \\ \frac{36}{100} + ( \sin \theta) ^{2} = 1 \\ \\ ( \sin \theta) ^{2} = 1 - \frac{36}{100} \\ \\ ( \sin \theta) ^{2} = \frac{100 - 36}{100} \\ \\ ( \sin \theta) ^{2} = \frac{64}{100} \\ \\ \sin \theta = \sqrt{\frac{64}{100} } \\ \\ \sin \theta = \frac{8}{10} \\ \\ \sin \theta = \frac{4}{5} [/tex]

Answer: Angles ∠4 and∠2 are not alternate interior angles and neither are ∠1 and ∠5

Step-by-step explanation: Khan Academy

Joe made the mistake by guessing Angles ∠4 and∠2 are not alternate interior angles and neither are ∠1 and ∠5.

The correct option is (b).

The fundamental characteristics listed below make it simple to recognise parallel lines.

Given:

WE have to  prove that the sum of a triangle's interior angle measures is 180°

According to the figure <1 and <4 are the alternate interior angle and <2 and <5 are  alternate interior angle.

So, Joe made the mistake by guessing Angles ∠4 and∠2  and ∠1 and ∠5 are alternate interior angles.

Learn more about parallel lines here:

https://brainly.com/question/16701300

#SPJ2

Answer:

Step-by-step explanation:

so we know that a triangle degrees have to add up to 180 in the inside right? So we know c is 90 and so you need to find A and B. The left over degrees you have is 90 so the sum of B and A would have to be 90, thats all i can help you with sorry.

Answer:

12

Step-by-step explanation:

Answer:

c≈5.2

Step-by-step explanation:

c=a2+b2=1.412+52≈5.19501

Answer:

hope this helps

Step-by-step explanation:

31 divided by 2 = 15.5 then do 15.5 x 15.5= 240.25 then you do 240.25 x 3.14 = 754.385

Answer:

1.870828693387

Step-by-step explanation:

Standard Deviation, σ: 1.870828693387

Count, N:4

Sum, Σx: 12

Mean, μ: 3

Variance, σ2:  3.5

Steps

σ2 = Σ(xi - μ)2

N  =   (6 - 3)2 + ... + (1 - 3)2

4 = 14

4  = 3.5

σ = √3.5

= 1.870828693387

Answer:

[tex] \rm\displaystyle \displaystyle \displaystyle θ= {60}^{ \circ} , {300}^{ \circ} [/tex]

[tex] \rm \displaystyle a = - \frac{ \sqrt{3} }{2} - 1, \frac{\sqrt{3}}{2} - 1[/tex]

Step-by-step explanation:

we are given two coincident points

[tex] \displaystyle P( \sin(θ)+2, \tan(θ)-2) \: \text{and } \\ \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)[/tex]

since they are coincident points

[tex] \rm \displaystyle P( \sin(θ)+2, \tan(θ)-2) = \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ )\cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)[/tex]

By order pair we obtain:

[tex] \begin{cases} \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ) = \sin( \theta) + 2 \\ \\ \displaystyle 3 \sin( \theta) - 2 \cos( \theta) + a = \tan( \theta) - 2\end{cases}[/tex]

now we end up with a simultaneous equation as we have two variables

to figure out the simultaneous equation we can consider using substitution method

to do so, make a the subject of the equation.therefore from the second equation we acquire:

[tex] \begin{cases} \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sinθ \cos(θ)+2a \cos(θ )= \sin( \theta) + 2 \\ \\ \boxed{\displaystyle a = \tan( \theta) - 2 - 3 \sin( \theta) + 2 \cos( \theta) } \end{cases}[/tex]

now substitute:

[tex] \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2 \cos(θ) \{\tan( \theta) - 2 - 3 \sin( \theta) + 2 \cos( \theta) \}= \sin( \theta) + 2 [/tex]

distribute:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ)+4 \sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) - 6 \sin( \theta) \cos( \theta) + 4 \cos ^{2} ( \theta) = \sin( \theta) + 2 [/tex]

collect like terms:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + 4 \cos ^{2} ( \theta) = \sin( \theta) + 2 [/tex]

rearrange:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) + 4 \cos ^{2} ( \theta) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + = \sin( \theta) + 2 [/tex]

by Pythagorean theorem we obtain:

[tex]\rm\displaystyle \displaystyle 4 - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) = \sin( \theta) + 2 [/tex]

cancel 4 from both sides:

[tex]\rm\displaystyle \displaystyle - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) = \sin( \theta) - 2[/tex]

move right hand side expression to left hand side and change its sign:

[tex]\rm\displaystyle \displaystyle - 2\sin(θ) \cos(θ)+\sin(θ ) - 4\cos( \theta) + 2 = 0[/tex]

factor out sin:

[tex]\rm\displaystyle \displaystyle \sin (θ) (- 2 \cos(θ)+1) - 4\cos( \theta) + 2 = 0[/tex]

factor out 2:

[tex]\rm\displaystyle \displaystyle \sin (θ) (- 2 \cos(θ)+1) + 2(- 2\cos( \theta) + 1 ) = 0[/tex]

group:

[tex]\rm\displaystyle \displaystyle ( \sin (θ) + 2)(- 2 \cos(θ)+1) = 0[/tex]

factor out -1:

[tex]\rm\displaystyle \displaystyle - ( \sin (θ) + 2)(2 \cos(θ) - 1) = 0[/tex]

divide both sides by -1:

[tex]\rm\displaystyle \displaystyle ( \sin (θ) + 2)(2 \cos(θ) - 1) = 0[/tex]

by Zero product property we acquire:

[tex] \begin{cases}\rm\displaystyle \displaystyle \sin (θ) + 2 = 0 \\ \displaystyle2 \cos(θ) - 1= 0 \end{cases}[/tex]

cancel 2 from the first equation and add 1 to the second equation since -1≤sinθ≤1 the first equation is false for any value of theta

[tex] \begin{cases}\rm\displaystyle \displaystyle \sin (θ) \neq - 2 \\ \displaystyle2 \cos(θ) = 1\end{cases}[/tex]

divide both sides by 2:

[tex] \rm\displaystyle \displaystyle \displaystyle \cos(θ) = \frac{1}{2}[/tex]

by unit circle we get:

[tex] \rm\displaystyle \displaystyle \displaystyle θ= {60}^{ \circ} , {300}^{ \circ} [/tex]

so when θ is 60° a is:

[tex] \rm \displaystyle a = \tan( {60}^{ \circ} ) - 2 - 3 \sin( {60}^{ \circ} ) + 2 \cos( {60}^{ \circ} ) [/tex]

recall unit circle:

[tex] \rm \displaystyle a = \sqrt{3} - 2 - \frac{ 3\sqrt{3} }{2} + 2 \cdot \frac{1}{2} [/tex]

simplify which yields:

[tex] \rm \displaystyle a = - \frac{ \sqrt{3} }{2} - 1[/tex]

when θ is 300°

[tex] \rm \displaystyle a = \tan( {300}^{ \circ} ) - 2 - 3 \sin( {300}^{ \circ} ) + 2 \cos( {300}^{ \circ} ) [/tex]

remember unit circle:

[tex] \rm \displaystyle a = - \sqrt{3} - 2 + \frac{3\sqrt{ 3} }{2} + 2 \cdot \frac{1}{2} [/tex]

simplify which yields:

[tex] \rm \displaystyle a = \frac{ \sqrt{3} }{2} - 1[/tex]

and we are done!

disclaimer: also refer the attachment I did it first before answering the question

Answer:

x=28

Step-by-step explanation:

4(x-5)=92

4x-20=92

add 20 to both sides

4x=112

divide 4 on both sides

x=28

Answer:

The value of x is 28

Step-by-step explanation:

4(x - 5) = 92

4x - 20 = 92

4x = 92 + 20

4x = 112

x = 112 ÷ 4

x = 28

Thus, The value of x is 28

-TheUnknownScientist

Answer: 5 is your answer hope this helped

plz make brainly

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

What?

Step-by-step explanation:

G8ve me more info and Ill answer again

Answer:

71

Step-by-step explanation:

ndndnrbrjen3n3nn3b2n2b2b

Answer:

The polar bear weighs 525kg

Step-by-step explanation:

C = Polar Bear

D = Baby Elephant

____________________________

(1)  C + D = 700 kg

(2)  C = 3D

________________________________

C = 700 - D

700 - D = 3D

700 = 4D

________________________________

525 + 175 = 700

Then we get our answer, the polar bear weighs 525kg, and the baby elephant weighs 175kg.

Hope this helps you :)

Answer:

1. D. Teorema.

2. A. Axioma.

Step-by-step explanation:

En matemáticas, un conjunto de proposiciones que deben estar respaldadas por una prueba adecuada basada en el razonamiento se denomina teorema. Se puede demostrar plenamente que todos los teoremas matemáticos son verdaderos mediante el razonamiento.

Sin embargo, un axión es evidente por sí mismo y no necesita ser probado. Es un hecho ya establecido.

Answer:

1. D. Teorema.

2. A. Axioma.

Step-by-step explanation:

Espero que esto ayude

Answer:

C.

Step-by-step explanation:

Answer:

B 18.79

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

37.82 year(s)

Step-by-step explanation:

double check tho, i might be using different method or my ans could be wrong since you gave literally no info on your specific task

Answer:

6 passengers got off at New Jersey

Step-by-step explanation:

let the number of passengers who got off be x and let the number of passengers who boarded the bus be y

y=2x

44 - x + y=50

y=50-44+x

y=6+x

subst y=2x

2x=6+x

2x-x=6

x=6