someone help please !

Someone Help Please !

Answers

Answer 1

Each line between 0 and 1 is 1/10 ( there are 10 lines)

First arrow is on the 3rd line so would be 3/10

The next arrow is 3 away from that so would be 3/10

The 3rd arrow is 2 away from the 2nd so would be 2/10

3/10 + 3/10 + 2/10 = 8/10

The answer is b


Related Questions

what is -34/15 in decimal form

Answers

Answer:

2.26 repeating

Step-by-step explanation:

Convert the fraction to a decimal by dividing the numerator by the denominator.

hope this helpes

be sure to give brainliest

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that Rn(x) → 0.] f(x) = 10 x , a = −2

Answers

Answer:

[tex]\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n[/tex]

Step-by-step explanation:

Rn(x) →0

f(x) = 10/x

a = -2

Taylor series for the function f at the number a is:

[tex]f(x) = \sum^\infty_{n=0} \frac{f^{(n)}(a)}{n!} (x - a)^n[/tex]

[tex]f(x) = f(a) + \frac{f'(a)}{1!}(x-a)+\frac{f"(a)}{2!} (x-a)^2 + ...[/tex] ............ equation (1)

Now we will find the function f and all derivatives of the function f at a = -2

f(x) = 10/x            f(-2) = 10/-2

f'(x) = -10/x²         f'(-2) = -10/(-2)²

f"(x) = -10.2/x³      f"(-2) = -10.2/(-2)³

f"'(x) = -10.2.3/x⁴     f'"(-2) = -10.2.3/(-2)⁴

f""(x) = -10.2.3.4/x⁵    f""(-2) = -10.2.3.4/(-2)⁵

∴ The Taylor series for the function f at a = -4 means that we substitute the value of each function into equation (1)

So, we get [tex]\sum^\infty_{n=0} - \frac{10(x+2)^n}{2^{n+1}}[/tex] Or [tex]\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n[/tex]

Taylor series  is a power series that gives the expansion of a function f (x) in the neighborhood of a point.

Taylor series is,   [tex]f(x)=f(a)+\frac{f'(a)}{1!}(x-a)+\frac{f''(a)}{2!}(x-a)^{2}+........[/tex]

[tex]f(x)=\sum_{n=0}^{\infty }-\frac{10(x+2)^{n}}{2^{n+1}}[/tex]

Here,  f(x) = 1/x  and a = -2

Now find derivative,

 f(x) = 10/x            f(-2) = 10/-2

f'(x) = -10/x²         f'(-2) = -10/(-2)²

f"(x) = 10.2/x³      f"(-2) = 10.2/(-2)³

f"'(x) = -10.2.3/x⁴     f'"(-2) = -10.2.3/(-2)⁴

Substituting above values in Taylor series expansion.

We get,   [tex]f(x)=\sum_{n=0}^{\infty }-\frac{10(x+2)^{n}}{2^{n+1}}[/tex]

Learn more:

https://brainly.com/question/24237739

HELP ASAP!!!!!!!!!!!!!!!

Answers

Answer:

B) (x^2-2x)/(2x+6)

Step-by-step explanation:

When dividing fractions, it's just like multiplying the reciprocal of the second fraction : x/y divided by z/w = x/y * w/z.

We use that and we get (x-2)/(x+3) * x/2. we simplify and get x(x-2)/2(x+3). So Our answer is B

what is the slope of the line given by the equation?

Answers

Answer:

the slope is 8

Step-by-step explanation:

The coefficient of x,  "m"  is the slope in the slope-intercept form:

y = mx + b

write 26 as repeated multiplication​

Answers

Answer:

2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

2¹³

13 x 13

Step-by-step explanation:

We simply find numbers that can multiply to 26 and write out the multiplication to get our answer.

Reliance on solid biomass fuel for cooking and heating exposes many children from developing countries to high levels of indoor air pollution. The article "Domestic Fuels, Indoor Air Pollution, and Children's Health" (Annals of the N.Y. Academy of Sciences, 2008: 209-217) pm-tented information on various pulmonary characteristics in samples of children whose households in India used either biomass fuel or liquefied petroleum gas (LPG). For the 755 children in biomass households, the sample mean peak expiratory flow (a person's maximum speed of expiration) was 3.30 Us, and the sample standard deviation was 1.20. For the 750 children whose households used liquefied petroleum gas, the sample mean PEF was 4.25 and the sample standard deviation was 1.75.

a. Calculate a confidence interval at the 95% confidence level for the population mean PEF for children in biomass households and then do likewise for children in LPG households. What is the simultaneous confidence level for the two intervals?

b. Carry out a test of hypotheses at significance level .01 to decide whether true average PEF is lower for children in biomass households than it is for children in LPG households (the cited article included a P-value for this test).

c. FEV1, the forced expiratory volume in 1 second, is another measure of pulmonary function. The cited article reported that for the biomass households the sample mean FEY, was 2.3 L/s and the sample standard deviation was .5 L/s. If this information is used to compute a 95% CI for population mean FEV1, would the simultaneous confidence level for this interval and the first interval calculated in (a) be the same as the simultaneous confidence level deter-mined there? Explain.

Answers

Answer:

A) 95% confidence interval for the population mean PEF for children in biomass households = (3.214, 3.386)

95% confidence interval for the population mean PEF for children in LPG households

= (4.125, 4.375)

Simultaneous confidence interval for both = (3.214, 4.375)

B) The result of the hypothesis test is significant, hence, the true average PEF is lower for children in biomass households than it is for children in LPG households.

C) 95% confidence interval for the population mean FEY for children in biomass households = (2.264, 2.336)

Simultaneous confidence interval for both = (2.264, 4.375)

This simultaneous interval cannot be the same as that calculated in (a) above because the sample mean obtained for children in biomass households here (using FEY) is much lower than that obtained using PEF in (a).

Step-by-step explanation:

A) Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the z-distribution. This is because although, there is no information provided for the population standard deviation, the sample sizes are large enough for the sample properties to approximate the population properties.

Finding the critical value from the z-tables,

Significance level for 95% confidence interval

= (100% - 95%)/2 = 2.5% = 0.025

z (0.025) = 1.960 (from the z-tables)

For the children in the biomass households

Sample mean = 3.30

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation of the sample = 1.20

N = sample size = 755

σₓ = (1.20/√755) = 0.0436724715 = 0.04367

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 3.30 ± (1.960 × 0.04367)

CI = 3.30 ± 0.085598

95% CI = (3.214402, 3.385598)

95% Confidence interval = (3.214, 3.386)

For the children in the LPG households

Sample mean = 4.25

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation of the sample = 1.75

N = sample size = 750

σₓ = (1.75/√750) = 0.063900965 = 0.063901

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 4.25 ± (1.960 × 0.063901)

CI = 4.25 ± 0.125246

95% CI = (4.12475404, 4.37524596)

95% Confidence interval = (4.125, 4.375)

Simultaneous confidence interval for both = (3.214, 4.375)

B) The null hypothesis usually goes against the claim we are trying to test and would be that the true average PEF for children in biomass households is not lower than that of children in LPG households.

The alternative hypothesis confirms the claim we are testing and is that the true average PEF is lower for children in biomass households than it is for children in LPG households.

Mathematically, if the true average PEF for children in biomass households is μ₁, the true average PEF for children in LPG households is μ₂ and the difference is μ = μ₁ - μ₂

The null hypothesis is

H₀: μ ≥ 0 or μ₁ ≥ μ₂

The alternative hypothesis is

Hₐ: μ < 0 or μ₁ < μ₂

Test statistic for 2 sample mean data is given as

Test statistic = (μ₂ - μ₁)/σ

σ = √[(s₂²/n₂) + (s₁²/n₁)]

μ₁ = 3.30

n₁ = 755

s₁ = 1.20

μ₂ = 4.25

n₂ = 750

s₂ = 1.75

σ = √[(1.20²/755) + (1.75²/750)] = 0.07740

z = (3.30 - 4.25) ÷ 0.07740 = -12.27

checking the tables for the p-value of this z-statistic

Significance level = 0.01

The hypothesis test uses a one-tailed condition because we're testing in only one direction.

p-value (for z = -12.27, at 0.01 significance level, with a one tailed condition) = < 0.000000001

The interpretation of p-values is that

When the p-value > significance level, we fail to reject the null hypothesis and when the p-value < significance level, we reject the null hypothesis and accept the alternative hypothesis.

Significance level = 0.01

p-value = 0.000000001

0.000000001 < 0.01

Hence,

p-value < significance level

This means that we reject the null hypothesis, accept the alternative hypothesis & say that true average PEF is lower for children in biomass households than it is for children in LPG households.

C) For FEY for biomass households,

Sample mean = 2.3 L/s

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation = 0.5

N = sample size = 755

σₓ = (0.5/√755) = 0.0182

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 2.30 ± (1.960 × 0.0182)

CI = 2.30 ± 0.03567

95% CI = (2.264, 2.336)

Simultaneous confidence interval for both = (2.264, 4.375)

This simultaneous interval cannot be the same as that calculated in (a) above because the sample mean obtained for children in biomass households here (using FEY) is much lower than that obtained using PEF in (a).

Hope this Helps!!!

Una persona se dirige a un edificio y observa lo alto del mismo con un ángulo de elevación “x”, después de caminar 10m observa al mismo punto anterior con ángulo de elevación “y”, si la altura del edificio es de 30m. Calcule: "3Tgx.Ctgy + Tgx"

Answers

Answer:

3

Step-by-step explanation:

To begin with notice that  

        [tex]\displaymode{ \tan(x) = \frac{30}{10 + 30\cot(y)} }[/tex]

From that equation you get that

10 tan(x)  +  30tan(x) cot(x) = 30

therefore

tan(x) + 3 tan(x) cot(x) = 3

             

6th grade math :) help me please !

Answers

Answer:

a1- 2 terms

a2- 6x, 9y

a3- 6,9

b1-2 terms

b2- 7x, 12x

b3- 7,12

c1- 3 terms

c2- 5x^2, 2y, 3

c3- 5,2,3

Step-by-step explanation:

Round off 3. 55 to one significant figure

Answers

Answer:

3.6

Step-by-step explanation:

We must first clarify how a number is rounded.

To round a number to unity we have to look at the first number after the comma.

If this number is less than 5 (1, 2, 3, 4) we should not do anything, but if that number is 5 or greater (5, 6, 7, 8, 9) we must add a unit to the number.

That is to say:

<5 do nothing

=> 5 round to the next number (+1)

So in the case of 3.55 it would be.

3.55 = 3.6

When we carry out a chi-square goodness-of-fit test for a normal distribution, the null hypothesis states that the population:________

a. Does not have a normal distribution
b. Has a normal distribution
c. Has a chi-square distribution
d. Does not have a chi-square distribution
e. Has k-3 degrees of freedom

Answers

Answer:

Option B

Step-by-step explanation:

The null hypothesis for a chi-square goodness of fit test states that the data are consistent with a specified distribution.

While the alternative hypothesis states that the data are not consistent with a specified distribution.

In this case study, the test is for a nose distribution. Thus the null hypothesis would be that the population has a normal distribution.

EXAMPLE 3 If f(x, y) = 4xy2 7x2 + y4 , does lim (x, y)→(0, 0) f(x, y) exist? SOLUTION Let's try to save some time by letting (x, y) → (0, 0) along any nonvertical line through the origin. Then y = mx, where m is the slope, and f(x, y) = f(x, mx) = 4x 2 7x2 + (mx)4 = 7x2 + m4x4 = 7 + m4x2 .

Answers

Answer:

Limit of the function exists.

Step-by-step explanation:

Given the function f(x,y) = [tex]\frac{4xy^{2} }{7x^{2} + y^{4} }[/tex], we are to show that lim (x, y)→(0, 0) f(x, y) exist. To show that, the following steps must be followed.

[tex]\lim_{(x,y) \to (0,0)} \frac{4xy^{2} }{7x^{2} + y^{4} }\\[/tex]

substituting the limit x = 0 and y = 0 into the function we have;

[tex]\frac{4(0)^{2} }{7(0)^{2} + (0)^{4} }\\= \frac{0}{0} (indeterminate)[/tex]

Since we got an indeterminate function, we will then substitute y = mx into the function as shown;

[tex]\lim_{(x,mx) \to (0,0)} \frac{4x(mx)^{2} }{7x^{2} + (mx)^{4} }\\\lim_{(x,mx) \to (0,0)} \frac{4m^{2} x^{3} }{7x^{2} + m^{4}x^{4} }\\\\\lim_{(x,mx) \to (0,0)} \frac{4m^{2} x^{3} }{x^{2}(7 + m^{4} x^{2}) }\\\lim_{(x,mx) \to (0,0)} \frac{4m^{2}x }{7 + m^{4} x^{2} }[/tex]

Substituting x = 0 , the limit of the function becomes;

[tex]\frac{4m^{2}(0) }{7 + m^{4} (0)^{2} }\\= \frac{0}{7}\\ = 0[/tex]

Since the limit of the function gives a finite value of 0 (the limit tends to 0). This shows that the limit exists.

When would you need to arrange polynomials

Answers

When you’re simplifying after collecting like-terms or if the question asks to put each monomial in descending order

Not sure how I would solve this

Answers

Answer:

0

Step-by-step explanation:

Using the slope formula

m = (y2-y1)/(x2-x1)

  and the given points

m = ( 2-2)/ ( 3-4)

    = 0/ -1

    = 0

The slope is zero

Ava's bacteria population is modeled by an equation. Chase models his bacteria
population with a graph. Ava says that on day 14, she will have more bacteria than Chase
Is she right? Why or why not?

Answers

Answer:

P(Chase) > P(Ava)

700 > 587

Therefore, Ava's claim is wrong!

On day 14, Chase's bacteria population will be greater than Ava's bacteria population.

Step-by-step explanation:

Please refer to the attached image.

Ava's bacteria population is modeled by the following equation.

[tex]$ b(t) = 200(1+0.08)^t $[/tex]

Where t is time in days and b(t) is the population of the bacteria after t days.

The graph represents the population of Chase's bacteria.

Ava claims that on day 14, she will have more bacteria than Chase.

Let us compare the population of both bacteria.

Chase bacteria population when t = 14 days:

From the graph, the population is approximately 700 at t = 14 days

P(Chase) ≈ 700

Ava bacteria population when t = 14 days:

at t = 14 days

[tex]b(t) = 200(1+0.08)^t \\\\ b(14) = 200(1.08)^{14} \\\\ b(14) = 200 (2.93719)\\\\ b(14) = 587.44[/tex]

So, the population is approximately 587 at t = 14 days

P(Ava) ≈ 587

P(Chase) > P(Ava)

700 > 587

Therefore, Ava's claim is wrong!

On day 14, Chase's bacteria population will be greater than Ava's bacteria population.

Answer:

D

Step-by-step explanation:

Trust

PLEASE I NEED HELP!!! FIRST ANSWER IS BRANLIEST!!!

Apply the distributive property to create an equivalent expression. 6(5x-3)

Answers

Answer:

30x - 18

Step-by-step explanation:

6(5x - 3)

Apply the distributive property.

6(5x) + 6(-3)

30x + - 18

Answer:

30x - 18 is your final answer

Two ships leave a port at the same time.
Ship A sails 12 knots on a bearing of 035°
Ship B sails 16 knots on a bearing of 270°
Calculate the distance between the ships after 2 hours

(1 knot = 1 nautical mile per hour)

Answers

Answer:

49.8 nautical miles

Step-by-step explanation:

Recall that speed = distance/time

Time = 2hours

Speed = 12knots and 16 knots respectively

D = speed×time

D1 = 12×2 = 24

D2 = 16×2 = 32

Using the 'cosine rule' we have:

a^2 = b^2+c^2-2bc cos Θ

Where a =?

b =24

c = 32

Θ = 125°

a² = 24² + 32² - 2(24)(32)cos125°

a^2 = 576+1024 - 1536cos125°

a² = 1600 - 1536(-0.57357)

a² = 1600+881.0134

a² = 2481.0134

Then, a² = 2481.013406

a =√2481.013406

Hence, a = 49.8 nautical miles

In this exercise we must use the knowledge about triangles to calculate the distance that a ship will travel, in this way we find that:

49.8 nautical miles

First, remember the formula for distance, which is:

[tex]Speed = distance/time[/tex]

And knowing that the data reported in the exercise are:

Time = 2hours Speed = 12 knots and 16 knots respectively

So putting the values ​​informed in the distance formula, we have:

[tex]D = speed*time\\D_1 = 12*2 = 24\\D_2 = 16*2 = 32[/tex]

Using the 'cosine rule' we have:

[tex]a^2 = b^2+c^2-2bc cos \theta[/tex]

Find the a, will have:

[tex]b =24 \ \ \ c = 32 \ \ \ \theta = 125\\a^2 = 24^2 + 32^2 - 2(24)(32)cos125\\a^2 = 576+1024 - 1536cos125\\a^2 = 1600 - 1536(-0.57357)\\a^2 = 1600+881.0134\\a^2 = 2481.0134\\a=49.8[/tex]

See more about triangles at brainly.com/question/25813512

Which point is a reflection of T(-6.5, 1) across the x-axis and the y-axis? A. point U B. point V C. point W D. point X

Answers

Hey there! :)

Answer:

Point V.

Step-by-step explanation:

Given the coordinates of T at (-6.5, 1), U represents T before any reflections. (Helps to visualize this better)

Reflecting across the x-axis results in the sign of the y-coordinate changed. Point T after this reflection becomes (-6.5, -1).

Finally, reflecting across the y-axis will change the sign for the x-coordinate.

(-6.5, -1) becomes (6.5, 1). This is represented by point V.

If f(x) = the square root of X,
g(x) = x - 7. Then dom(fog) =

(a) [0, infinity)
(b) R
(c) (-7,infinity)
(d) [7,infinity)
(e) none​

Answers

Answer:

The answer is option D.

Hope this helps you

The rat population in major metropolitan city is given by the formula n(t)=89e^0.02t where t is measured in years since 1991 and n(t) is measured in millions. What does the model predict the rat population was in the year 2007?

Answers

Answer:

  122.6 million

Step-by-step explanation:

Figure the value of t, then put that into the formula and do the arithmetic.

  t = 2007 =1991 = 16

  n(16) = 89e^(0.02·16) = 89·e^0.32 ≈ 122.6

The model predicts a rat population of 122.6 million in 2007.

16. Find m<2.
a. 86°
b. 43°
C. 94°
d. 133

Answers

I think it’s A But I’m not sure
according to the sinx and tanx you should be able to find m by just the angles using most common functions
Answer : 86 degrees

I need help with this exercise please. What I need to know is the measure of one side of the square. Sorry for the language of the exercise

Answers

Answer:

[tex]\boxed{\sf \ \ x=6 \ \ }[/tex]

Step-by-step explanation:

Hello,

BMN and NPC are two similar triangles so

[tex]\dfrac{BM}{MN}=\dfrac{NP}{PC}\\\\ \dfrac{10-x}{x}=\dfrac{x}{15-x}\\\\<=>(15-x)(10-x)=x^2\\\\<=>150-25x+x^2=x^2\\\\<=>25x=150\\\\<=>x=6[/tex]

espero que esto ayude

Determining Key Aspects of a Quadratic Function
Use the drop-down menus to describe the key aspects of the function f(x) = -X2 - 2x - 1.
The vertex is the
The function is increasing
The function is decreasing
The domain of the function is hs
The range of the function is

Answers

Answer:

Step-by-step explanation:

The vertex can be located most easily by completing the square of

f(x) = -X^2 - 2x - 1 (which is equivalent to -(x^2 + 2x + 1).  The latter expression can be rewritten as -(x + 1)^2, which indicates that the x-coordinate of the vertex is -1.  The corresponding y-value is 0.  Vertex is at (-1, 0).

The function is increasing for x < -1 and decreasing for x > -1.

The domain of the function is "all real numbers."

The range is (-infinity, 0)

Find the hypotenuse of a right triangle (in cm) if one leg measures 7 cm and the other leg measures 11 cm. Round to the nearest thousandth. ____________ cm

Answers

Using the Pythagorean theorem

Hypotenuse = sqrt( 11^2 + 7^2)

= sqrt( 121 + 39)

= sqrt( 160)

= 12.694

HELP ASAP PLEASE!!!! 1. Create a unique equation using the graphic above with the solution (answer) of 36. There are many possible equations you could create to equal 36 using the chart above. 2. Describe the process you used to create your equation in prompt 1.

Answers

Answer:

4(A)=36

Step-by-step explanation:

An equation is said to be unique if the equation has a valid solution. Several unique equations that equal 36 can be taken from the given values. Some of these equations are:

[tex]4G + M + 2B = 36[/tex]

[tex]10F- N -D = 36[/tex]

[tex]10D + G =36[/tex]

[tex]4M - E = 36[/tex]

[tex]4L = 36[/tex]

[tex]9E = 36[/tex]

To get a unique equation, we ensure that the right-hand side of the equation equals the left-hand side. There are no quick solution to this; so, we make use of trial by error method.

After several trials, some possible equations with three variables are:

[tex]4G + M + 2B = 36[/tex] because  [tex]4 \times 6 + 10 + 2 \times 1 = 36[/tex]

[tex]10F- N -D = 36[/tex] because [tex]10 \times 5- 11 -3 = 36[/tex]

Some possible equations with two variables are:

[tex]10D + G =36[/tex] because [tex]10 \times 3 + 6 =36[/tex]

[tex]4M - E = 36[/tex] because [tex]4 \times 10 - 4 = 36[/tex]

Some possible equations with two variables are:

[tex]4L = 36[/tex] because [tex]4 \times 9 = 36[/tex]

[tex]9E = 36[/tex] because [tex]9 \times 4 = 36[/tex]

The following are some unique equations from the given values:

[tex]4G + M + 2B = 36[/tex]

[tex]10F- N -D = 36[/tex]

[tex]10D + G =36[/tex]

[tex]4M - E = 36[/tex]

[tex]4L = 36[/tex]

[tex]9E = 36[/tex]

Read more about unique equations at:

https://brainly.com/question/23843252

is this right one more i think lol

Answers

Answer:

Yup P is the right one having 62.26%

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

We can set it up as

P = 33/53

Q = 20/48

R = 54/90

S = 44/83

This is because we are calculating the percent of yellow birds in the total amt. of birds in a specified park.

Now we calculate =>

P = 33/53 = around 0.62

Q = 20/48 = around 0.416

R = 54/90 = 0.6

S = 44/83 = around 0.53

We find that Park P has the greatest percentage and -->

Thus, Park P is our answer and yes, you are correct.

The ratio of the number of counters that Amy is 5:6 Amy gives 3/5 of her counters to Audrey. Amy has 126 counters left how many more counters does Audrey now have than Amy?

Answers

Answer:

441

Step-by-step explanation:

Given

ratio of the number of counters that Amy is 5:6

let the no. of counter with Amy be 5x

and the no. of counter with Audrey be 6x

Amy gives 3/5 of her counters to Audrey.

3/5 of her counters to Audrey. = 3/5 * 5x = 3x

Thus,

amy gives 3x counters to audrey

No. of counters left with Amy = 5x-3x = 2x

given that  Amy has 126 counters left

2x = 126

x = 126/2 = 63

Thus,

no. of counter with Amy now  = 2x = 2*63 = 126

and now the no. of counter with Audrey = 6x+3x  = 9*63 = 567

Difference of counter between Audrey and Amy = 567 - 126 = 441.

Thus, Audrey has 441 counter more than Any has.

Kelly's first four test grades of the period were 80, 72, 96, and 88. Which inequality represents the grades she can
earn on the fifth test to have a test average of no less than 80?
V
O gs16
O 92 16
O g564
O 9264

Answers

The inequality that represents Kelly’s first four test grades of the period are g2 16 because the inequality’s all together with the math all completed ends out to equal my final answer of g2 16 thank you

Answer: option D on edge 2020

Step-by-step explanation:

if you reverse the formula for mean, then you just insert the numbers and you have your answer

As a young professional in the future, it is good to start saving money to have a
security for the future and have something to use when emergency cases happen
related to the need of cash. The Philippine Average Family income last 2015 was
around P276,000 per year. Lets say every year you earn the same amount and save
P76,000 yearly in your frusted bank giving 4% compounded interest annually. How much
will the account worth in the future after 40 years?
a. Solve for the future value of the account:
FV=PMT
( \frac{(1 + i) ^{n} - 1 }{i} )(i(1+i)n−1​)

Answers

Answer:

Step-by-step explanation:

We would apply the future value which is expressed as

FV = C × [{(1 + r)^n - 1}/r]

Where

C represents the yearly payments of the young professional.

FV represents the amount of money

in your account at the end of 40 years.

r represents the annual rate.

n represents number of years or period.

From the information given,

r = 4% = 4/100 = 0.04

C = $76000

n = 40 years

Therefore,

FV = 76000 × [{(1 + 0.04)^40 - 1}/0.04]

FV = 76000 × [{4.8 - 1}/0.04]

FV = 76000 × 95

FV = P7220000

There are 3 times as many novels as comic books in a bookstore.If there are 2480 books altogether, how many comic books are there in the bookstore.​

Answers

Answer:

620 comic books

2480 / 4 is 620.

620 x 3 is 1860.

1860 + 620 is 2480.

Done!

Find the lowest common denominator. 1/(x+2)^2, 1/(x-2)^2, 2/(x^2-4) A. (x+2)^2 (x-2)^2 B. (x^2+2) (x^2-2)

Answers

Answer:

(x + 2) ^2 (x - 2) ^ 2 so A is the answer.

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

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